The power radiated by a square meter of the star's surface is 5.67 x 10^17 W/m².
What do you mean by Stefan-Boltzmann Law?
The Stefan-Boltzmann Law states that the total energy radiated per unit surface area of a black body in thermodynamic equilibrium is directly proportional to the fourth power of its absolute temperature. This law is a fundamental law of thermodynamics and was first derived by Austrian physicist Josef Stefan in 1879, and later extended by German physicist Ludwig Boltzmann in 1884.
This is calculated by plugging the temperature into the Stefan-Boltzmann Law, as follows:
E = oT^4 = (5.67 x 10^-8)(30,000)^4 = 5.67 x 10^17 W/m².
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Critical angle of glass is 42 .what does it mean?
Answer:
i think..its fraction that its have multiple fractions on it..if you minus the 397 000-355 it should be 381+ so i say if you get the 5 multiply it by 9!! so you will get it!
Explanation:
HOPE IT HELPS!!
Newton's law of gravitation is proportional to the inverse cube of the distance between the two objects.
True
False
Which object has the greatest kinetic energy?
A. a truck with a mass of 3,500 kg moving at 30 m/s
B. a fast pitched baseball with a mass of .5 kg moving at 46.9 m/s
C. a locomotive engine with a mass of 205,000 kg moving 5 m/s
D. a person with a mass of 73 kg running 6 m/s
The object with the greatest kinetic energy is the locomotive engine (option C)
How do I know which object has the greatest kinetic energy?To know the object with the greatest kinetic energy, we shall determine the kinetic energy of each objects. Details below:
For truck:
Mass (m) = 3500 KgVelocity (v) = 30 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 3500 × 30²
KE = 1575000 J
For baseball:
Mass (m) = 0.5 KgVelocity (v) = 46.9 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.5 × 46.9²
KE = 549.90 J
For locomotive:
Mass (m) = 205000 KgVelocity (v) = 5 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 205000 × 5²
KE = 2562500 J
For person:
Mass (m) = 73 KgVelocity (v) = 6 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 73 × 6²
KE = 1314 J
From the above calculations, we can see that the locomotive has the greatest kinetic energy. Thus, the correct answer is option C
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A 2.0-kilogram ball traveling north at 4.0 meters per second collides head on with a 1.0-kilogram ball traveling south at 8.0 meters per second. What is the magnitude of the total momentum of the two balls after collision?
Answer:
We know the momentum after the collision MUST be equal to the momentum BEFORE the collision.
Momentum is a VECTOR quantity having both magnitude and direction. The first ball has momentum P =m*v = 2*4 = 8 at 90degrees. The second ball has momentum P = 1*8 = 8 at -90 or 270 degrees. They sum to zero when you perform vector addition.
Explanation:
The mass on the spring in this diagram is in harmonic motion between x = -5
cm and x = 5 cm.
At which point does the mass have the most kinetic energy
Answer:
The mass will have the most KE at the midpoint of motion (velocity is a maximum)
Total Energy = KE + PE = constant
At zero displacement the potential energy equals zero and the kinetic energy is a maximum.
Answer:
I think it's point C but I'm not sure
Imagine you are a medical examiner who has to perform an autopsy. Research and list the steps you would follow to perform the autopsy.
Imagine you are a medical examiner who has to perform an autopsy. Research and list the steps you would follow to perform the autopsy.
Imagine you are a medical examiner who has to perform an autopsy. Research and list the steps you would follow to perform the autopsy.
Imagine you are a medical examiner who has to perform an autopsy. Research and list the steps you would follow to perform the autopsy.
Imagine you are a medical examiner who has to perform an autopsy. Research and list the steps you would follow to perform the autopsy.
Answer:
general steps of performing an autopsy:
1. The body is identified and the relevant information about the deceased is collected.
2. A visual examination of the body is performed to look for any abnormalities or signs of injury.
3. The external examination is followed by an internal examination. The body is opened up to examine the organs, including the brain, heart, lungs, liver, and kidneys, for any signs of disease or injury.
4. The organs are weighed, measured and dissected.
5. Tissue samples are taken and sent for laboratory analysis.
6. The cause of death is determined based on the autopsy findings, and a report is generated.
7. The body is then closed and prepared for release to the family for funeral arrangements.
It is important to note that the specific steps involved may vary depending on the type of autopsy being conducted and the circumstances surrounding the death.
Explanation:
what consist of a body wave
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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According to Ohm's law, the current (I) is equal to the voltage divided by the resistance, or I = V / R. A portable fan uses 54 V and has a resistance of 3 Ω. How much current is running through the fan when it's in use?
3 A
18 A
51 A
162 A
Answer:
Using Ohm's law, we can calculate the current (I) by dividing the voltage (V) by the resistance (R):
I = V / R
Substituting the given values:
I = 54 V / 3 Ω
I = 18 A
Therefore, the current running through the fan when it's in use is 18 A.
Explanation:
A man pushing a crate of mass
m = 92.0 kg
at a speed of
v = 0.855 m/s
encounters a rough horizontal surface of length
ℓ = 0.65 m
as in the figure below. If the coefficient of kinetic friction between the crate and rough surface is 0.359 and he exerts a constant horizontal force of 289 N on the crate.
A man pushes a crate labeled m, which moves with a velocity vector v to the right, on a horizontal surface. The horizontal surface is textured from the right edge of the crate to a horizontal distance ℓ from the right edge of the crate.
(a) Find the magnitude and direction of the net force on the crate while it is on the rough surface.
magnitude
N
direction
Opposite Direction or Same Direction
(b) Find the net work done on the crate while it is on the rough surface.
J
(c) Find the speed of the crate when it reaches the end of the rough surface.
m/s
(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 34.7 N in opposite direction.
(b) The net work done on the crate while it is on the rough surface is -22.6 J.
(c) The speed of the crate when it reaches the end is 0.5 m/s.
What is the net force on the crate while it is on the rough surface?
The magnitude and direction of the net force on the crate while it is on the rough surface is calculated as follows;
F (net) = F - Ff
where;
F is the applied forceFf is the frictional force on the crateF (net) = F - μmg
where;
μ is the coefficient of frictionm is massg is gravityF (net) = 289 N - (0.359 x 92 X 9.8)
F (net) = -34.7 N
The negative sign indicates opposite direction to the applied force.
The net work done on the crate while it is on the rough surface is calculated as follows;
W = F(net) x L
where;
L is the distance travelled by the crateW = -34.7 x 0.65
W = -22.6 J
The speed of the crate when it reaches the end is calculated as follows;
acceleration of the crate = F(net) / m
a = -34.7 N / 92 kg
a = -0.377 m/s²
v² = u² + 2aL
v² = ( 0.855)² + ( 2 x -0.377 x 0.65)
v² = ( 0.855)² - ( 2 x 0.377 x 0.65)
v² = 0.24
v = √ 0.24
v = 0.5 m/s
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The tension in a ligament in the human knee is approximately proportional to the extension of the ligament, if the extension is not too large.If a particular ligament has an effective spring constant of 150 N/mm as it is stretched, what is the elastic energy stored in the ligament when stretched by 0.780 cm?
Given that the spring constant of the ligament is
\(\begin{gathered} K=150\text{ N/mm} \\ =\frac{150N}{10^{-3}\text{ m}} \\ =150\times10^3\text{ N/m} \end{gathered}\)The displacement of the ligament is
\(\begin{gathered} x=0.78\text{ cm} \\ =0.78\times10^{-2}\text{ }m \end{gathered}\)We have to find elastic energy.
Elastic energy is given by the formula
\(U=\frac{1}{2}kx^2\)Substituting the values, the elastic energy will be
\(\begin{gathered} U=\frac{1}{2}\times(150\times10^3)\text{ }\times(0.78\times10^{-2})^2 \\ =\text{ 5.85 J} \end{gathered}\)Thus, the elastic energy of the ligament is 5.85 J.
Vectors u = −2(cos 30°i + sin30°j), v = 6(cos 225°i + sin225°j), and w = 8(cos 120°i + sin120°j) are given. Use exact values when evaluating sine and cosine.Part A: Find −7u • v. Show your work. (4 points)Part B: Use the dot product to determine if u and w are parallel, orthogonal, or neither. Justify your answer. (6 points)
Explanation
let
\(\begin{gathered} u=-2\mleft(\cos 30\degree i+\sin 30\degree j\mright) \\ v=6\mleft(\cos 225\degree i+\sin 225\degree j\mright) \\ w=8\mleft(\cos 120\degree i+\sin 120\degree j\mright) \end{gathered}\)Step 1
Part A)Find −7u • v.
the dot product is the sum of the products of the corresponding entries of the two sequences of numbers,and to multiply a vector by a scalar, multiply each component by the scalar.
\((ai+bj)\cdot(ci+dj)=ac+bd\)so
\(\begin{gathered} -7u\cdot v \\ \text{hence} \\ -7u=-7(-2\mleft(\cos 30\degree i+\sin 30\degree j\mright))=14(\cos 30\degree i+\sin 30\degree j)=12.12i+7j \end{gathered}\)therefore, replacing
\(\begin{gathered} -7u\cdot v \\ (12.12i+7j)\cdot6\mleft(\cos 225\degree i+\sin 225\degree j\mright) \\ (12.12i+7j)\cdot(-4.24i-4.24j) \\ (12.12i+7j)\cdot(-4.24i-4.24j)=(12.12\cdot-4.24)+(7\cdot-4.24)= \\ (12.12i+7j)\cdot(-4.24i-4.24j)=-51.43-29.690=-81.12 \end{gathered}\)So,Part A
\(-7u\cdot v=-81.12\)Step 2
Part B ,Use the dot product to determine if u and w are parallel, orthogonal, or neither
the dot product is also given by:
\(\begin{gathered} a\cdot b=\lvert a\rvert\lvert b\rvert\cos \theta \\ so \\ \cos \theta=\frac{a\cdot b}{\lvert a\rvert\lvert b\rvert} \end{gathered}\)a) find the magnitude of the vectors
\(\begin{gathered} \text{ }u=-2\mleft(\cos 30\degree i+\sin 30\degree j\mright), \\ u=(-2\cos 30\degree i-2\sin 30\degree j) \\ \text{hence} \\ \lvert u\rvert=\sqrt[]{(-2\cos30)^2+(-2\sin30\degree)}^2 \\ \lvert u\rvert=\sqrt[]{3^{}+1\text{ }} \\ \lvert u\rvert=\sqrt[]{4}=2 \\ \lvert u\rvert=2 \end{gathered}\)and
\(\begin{gathered} \text{ w}=8\mleft(\cos 120\degree i+\sin 120\degree j\mright) \\ w=8(\cos 120\degree i+\sin 120\degree j)=-4i+6.92j \\ \text{hence} \\ \lvert w\rvert=\sqrt[]{(-4)^2+(6.92)^2} \\ \lvert w\rvert=\sqrt[]{16^{}+48} \\ \lvert w\rvert=\sqrt[]{64} \\ \lvert w\rvert=8 \end{gathered}\)c) dot product
\(\begin{gathered} u\cdot w=-2(\cos 30\degree i+\sin 30\degree j)\cdot8(\cos 120\degree i+\sin 120\degree j) \\ u\cdot w=-5.73+5.92 \\ u\cdot w=0.19 \end{gathered}\)finally, replace in the formula and find the angle
\(\begin{gathered} \cos \theta=\frac{a\cdot b}{\lvert a\rvert\lvert b\rvert} \\ \cos \theta=\frac{0.19}{2\cdot8} \\ \cos \theta=0.011875 \\ \theta=\cos ^{-1}(0.011875) \\ \theta=90 \end{gathered}\)so
the vectors are orthogonal ( make a 90° angle)
I hope this helps you
Which notation is commonly used on force diagrams to show forces acting on an object.
Answer: is F^D
The notation that is commonly used on force diagrams to show forces acting on an object is FD.
What is free body diagram ?A free body diagram is a diagram that contains all the forces acting on an object.
These forces acting on an object include the following :
Upward force (normal reaction due to weight of the object)Downward force (downward force due to weight of the object)Frictional force (force resisting the motion)Thus, the notation that is commonly used on force diagrams to show forces acting on an object is FD.
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A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
F. O 0.00120 m/s
G.O 351 m/s
H
345 m/s
J.
841 m/s
Answer:351
Explanation:trust
A musical note has a frequency and the wavelength of the note. The speed of the sound of that note will be 351m/s. The correct option is G.
What is frequency?The frequency is the number of cycle per second.
The wavelength is related to frequency and speed as
f = v/λ
Given is the frequency f = 512Hz and wavelength λ= 0.685m, then the speed of note will be
v =512 Hz x 0.685m
v =350.72 m/s
Speed is approximately 35 m/s.
Thus, the correct option is G.
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A mass of (200 g) of hot water at (75.0°C) is mixed with cold water of mass M at (5.0°C). The final temperature of the mixture is (25.0°C). What is the mass of the cold water (M)?
The mass of the cold water, given the data from the question is 500 g
Data obtained from the questionMass of warm water (Mᵥᵥ) = 200 gTemperature warm water (Tᵥᵥ) = 75 °CTemperature of cold water (T꜀) = 5 °C Equilibrium temperature (Tₑ) = 25 °CSpecific heat capacity of the water = 4.184 J/gºC Mass of cold water (M꜀) =?How to determine the mass of the cold waterHeat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – T꜀)
200 × 4.184 (75 – 25) = M꜀ × 4.184(25 – 5)
41840 = M꜀ × 83.68
Divide both side 83.68
M꜀ = 41840 / 83.68
M꜀ = 500 g
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What is picture ..........
Answer:
In its most general sense, a picture is a visual representation of something, especially in the form of a painting, drawing, photograph, or the like. A picture can also refer to a mental image, among other senses.
An applied frictional force on this wheel (not shown) causes it to slow down until it comes to a complete stop after a time interval Δt, where: |ωo| = 34.28 rad/s, R = 0.29 m, |α| = 1.77 rad/s2.
a) Solve for the time interval needed for the wheel to come to a complete stop.
19.37s
b) Solve for total angular distance traveled (in radians, not meters) by the wheel during this time interval.
We can use the formula for angular deceleration to find the time interval needed for the wheel to come to a complete stop:
α = (ωf - ωo) / Δt
where ωf is the final angular velocity, ωo is the initial angular velocity, and Δt is the time interval. Rearranging the formula, we get:
Δt = (ωf - ωo) / α
Since the wheel comes to a complete stop, the final angular velocity is zero:
ωf = 0
Substituting the given values, we get:
Δt = (0 - 34.28) / (-1.77) ≈ 19.37 s
What is the r total angular distance traveled?The formula for angular displacement is:
θ = ωo t + (1/2) α t^2
where θ is the angular displacement, ωo is the initial angular velocity, α is the angular acceleration, and t is the time interval. When the wheel comes to a complete stop, the final angular velocity is zero, so the formula simplifies to:
θ = ωo t + (1/2) α t^2
Substituting the given values, we get:
θ = (34.28 rad/s)(19.37 s) + (1/2)(-1.77 rad/s^2)(19.37 s)^2 ≈ -2003.9 rad
The negative sign indicates that the wheel has rotated in the opposite direction of its initial motion.
To get the total angular distance traveled by the wheel during this time interval, we take the absolute value of θ:
|θ| = |-2003.9 rad| = 2003.9 rad
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A 39.4 kg beam is attached to a wall with a link and its far end is supported by a cable such that the angle between the beam and the cable is 90 degrees. If the beam is inclined at an angle of theta = 33.1 degrees with respect to horizontal, what is the magnitude of the horizontal component of the force exerted by the link on the beam?
Answer:
192.6N
Explanation:
Let's consider the forces acting on the beam:
Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.
Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.
Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.
Let's break down the forces acting on the beam:
Vertical forces:
W (weight of the beam) - T (vertical component of tension) = 0
T = W
Horizontal forces:
F_link (horizontal component of the force exerted by the link) = ?
To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.
Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:
F_link = W * sin(θ)
Let's substitute the given values:
W = 39.4 kg * 9.8 m/s^2
θ = 33.1 degrees
F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)
Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.
What does it indicate if an ion has a charge of -1
An Ion carrying a charge of -1 indicates the presence of an extra electron.
Atoms are formed by the combination of protons, neutrons, and electrons. Protons and Neutrons together form the Nucleus, and the Electrons move around the Nucleus of the atoms in a shell and can vary in number.
The number of protons and electrons is the same in an atom. As the protons have a charge of +1 and electrons carry a negative charge of -1, thus the total charge of an atom is zero means an atom is electrically neutral.
But when an atom gains an extra electron from its nearby atoms or surroundings, it gains a negative charge of -1. An atom that has a positive or negative electrical charge is an Ion. Thus an ion with a -1 charge is an atom with an extra electron in its shell.
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12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. What is the beaver’s mass?
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the kinetic energy (KE) of an object that is KE = (1/2) ×m × \(v^2\).
KE = (1/2) ×m × \(v^2\).
where m= mass of the object, v=its velocity.
The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation
45 J = (1/2) ×m × \((2.0 m/s)^2\)
Simplifying this equation:
45 J = (1/2) × m × 4.0\(m^2/s^2\)
45 J = 2 m × 2 \(m^2/s^2\)
45 J = 4 \(m^3/s^2\)
\(m^3\) = 45 J / 4 \(s^2\)
\(m^3\) = 11.25 kg×\(m^2/s^2\)
Taking the cube root of both sides to solve for mass,
m = (11.25 kg×\(m^2/s^2)^(^1^/^3^)\)
m = 1.74 kg (rounded to two decimal places)
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If you can run 10.43 m in 14.22 s. How fast are you running?
Answer:
I am 15th in my state for 55m hurdles with a time of 10.4 seconds
Explanation:
BAM
Answer: 44 m per minute
Explanation:
a car traveled at 100 km h for 3 hours how far did it travel
100 km
300 km/h
300 km
3 km/h
Answer:
300km
Explanation:
Given parameters:
Speed of the car = 100km/h
Time taken for the travel = 3hrs
Unknown:
How far did it travel = ?
Solution:
To solve this problem, we must understand that;
Speed = \(\frac{distance}{time}\)
Distance = speed x time
Distance = 100km/hr x 3hr = 300km
In order to train astronauts to get used to the accelerations they experience during space shuttle launches, they must ride around in a centrifuge to experience accelerations of up to 100 m/s2. If a centrifuge measures 20 m in radius, what is the rotational velocity of a centrifuge during testing?
The rotational velocity of the centrifuge is \(\sqrt{5}\) rad/s.
What is Centripetal force ?
Centripetal force is defined as the force that acts on a body moving in circular path which is directed towards the centre of the circular path.
Here,
The rotational acceleration attained by the astronauts, a' = 100 m/s²
The radius of the centrifuge, r = 20 m
From the equation of circular motion,
a' = rω²
So, ω² = a'/r
ω² = 100/20
ω² = 5
Rotational velocity, ω = \(\sqrt{5}\) rad/s
Hence,
The rotational velocity of the centrifuge, ω is \(\sqrt{5}\) rad/s
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describe the difference between particle motion in solids and liquids.
Answer:
Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.
i hope this helps your answer
Answer:
liquids vibrate, move about, and slide past each other. solids vibrate but generally do not move from place to place.
What is the direction of the electric field at a point a distance d = 34.00 cm directly to the right of the positive charge?
Answer:
s the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.
Explanation:
The electric field around the cagases oisitvi, field leaving this means that the field lines move away from
If the charge is negative the lines of the field are directed towards the charge
Let's apply this to our case, as the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.
A light wave will *Blank* if it enters a new medium perpendicular to the surface.
Answer:
A light wave will not stop if it enters a new medium perpendicular to the surface.
Explanation:
A light wave will not have any deviation if it enters a new medium perpendicular to the surface.
What is meant by refraction ?Refraction is defined as an optical phenomenon by which the direction of a light wave gets changed when it travels from one medium to another. This is because of the change in speed.
Here,
The light wave is entering a new medium such that it enters perpendicular to the surface. Angle of incidence is the angle between the incident ray and the line perpendicular to the surface at the point of incidence. Since, here the light ray is incident normal to the surface that means the angle of incidence is 0.
According to Snell's law,
sin i = μ sin r
where i is the angle of incidence, r is the angle of refraction and μ is the constant called refractive index.
As i = 0, sin i = 0
So, μ sin r = 0
Since μ is a constant, we can say that sin r = 0 or the angle of refraction,
r = 0
This means that there is no refraction and hence the light wave won't get deviated when it enters the medium normally.
Hence,
A light wave will not have any deviation if it enters a new medium perpendicular to the surface.
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A 75 kg skier travels downhill 1200 meters in 56 seconds. What is the velocity of the skier?
when is an object considered to be in motion
Answer:
An object is considered to be in motion only when its position changes over time with reference to a point which will be known as orgin
A car achieves a velocity 50 meters per second after 5 seconds. What is the Car's acceleration?
Answer: 10 m/s
Explanation: Velocity/Time
50/5= 10
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