5 [By hand] A unity feedback system comprises a process subsystem, P(s) = and a controller subsystem, s(s+5)' 74 C(s) = K (14 + 4 + s). S Sketch the root locus for this system. Include calculations for all relevant steps. If a step is irrelevant, explain why.

The primary objective of this project is to design a building in accordance with the structural requirements for LRFD for steel as defined in ASCE 7/IBC. The building's materials are defined in the following terms:

Light-weight concrete flooring over deck with a thickness of 5 inches.
ASTM A992 (Gr.50) for all W shape Beams, Girders, and Columns.
HSS Braces (ASTM A500) or W shapes (ASTM A992, Gr.50).

Dead Loads: The building's dead load will be made up of a variety of elements, including:

Roof: Roofing Materials (Water Proofing, etc.) = 4 psf.

18" Gage deck = 3 psf.
Light-weight concrete 5 in thick.
Framing & Fire proofing = 8 psf.
Suspended ceiling = 4 psf.
Mechanical & Electrical = 4 psf.
Solar panels & assembly = 9 psf.

Floor: Tile including assembly = 9.5 psf.
18" Gage deck.
Light-weight concrete 6 1/4 "= 3 psf.
Framing & Fire proofing = 15 psf.
Suspended ceiling = 5 psf.
Mechanical & Electrical = 5 psf.

Wall: Parapets on roof (outer boundary only) = 25 psf (3.5 ft high).
Glazed walls (outer boundary only) = 18 psf (ground to roof level).

The live load of partitions is taken into consideration as appropriate. Flooring requires a two-hour fire rating. The following deflection requirements are in effect:
L/360 due to live load deflection in all interior Beams and Girders.

L/180 due to total load for all spandrel Beams and Girders.
the building's seismic design should consider the values of spectral response acceleration parameters for the given location, which can be found using the USGS website.

To know more about structural requirements visit:-

https://brainly.com/question/31029799

#SPJ11

Answer:

a) 0.489

b) 54.42 kg/s

c) 247.36 kW/s

Explanation:

Note that all the initial enthalpy and entropy values were gotten from the tables.

See the attachment for calculations

A window is a fundamental element of modern computer interfaces that allows users to interact with software applications and programs. So the correct option is d) window

A rectangular area that can contain a document, program, or message is called a window. A window is a graphical user interface element that displays the contents of an application or program. It can be moved, resized, minimized, and closed using various buttons and controls. The contents of a window can vary depending on the application or program running in it. For example, a text editor program would display a blank document in a window, while a web browser would display a webpage. The purpose of a window is to allow users to interact with the contents of an application or program in a visual and intuitive way.

To know more about interfaces visit:

brainly.com/question/14154472

#SPJ11

The easiest way for the hotel to control for potential bias in their statistics would be to survey visitors at various periods throughout the year.

The hotel can make sure that the data in its survey of visitors is representative of those who stay there during various seasons, for various periods of time, and through various booking channels by conducting surveys of guests at random times throughout the year.

By solely surveying specific visitor subsets, any potential bias that might result will be reduced.

The most popular kind of guest satisfaction survey is the post-stay survey, which is given to guests after they have left the property and asks them about various elements of their stay.

Therefore, The easiest way for the hotel to control for potential bias in their statistics would be to survey visitors at various periods throughout the year.

To learn more about Guests, refer to the link:

https://brainly.com/question/16001808

#SPJ2

To calculate the ultimate shear strength of the soil at a depth of 3 ft using the Mohr-Coulomb failure criteria, we need to use the following equation:

τ = c' + σtan(φ)

Where:

τ is the shear stress (ultimate shear strength)

c' is the effective cohesion intercept

σ is the effective normal stress

φ is the angle of internal friction

Given:

φ = 25° (angle of internal friction)

γ_sat = 125.4 lb/ft^3 (saturated unit weight of the soil)

Depth = 3 ft

First, we need to calculate the effective normal stress (σ) at the given depth:

σ = γ_sat * Depth

σ = 125.4 lb/ft^3 * 3 ft

σ = 376.2 lb/ft^2

Next, we can calculate the ultimate shear strength (τ) using the equation:

τ = c' + σtan(φ)

Since the effective cohesion intercept (c') is not provided in the given information, we cannot determine the exact value of τ without it. The cohesion intercept is a material-specific property and needs to be determined through laboratory or field tests.

Therefore, without knowing the value of the effective cohesion intercept (c'), we cannot calculate the ultimate shear strength of the soil at a depth of 3 ft using the given information.

Learn more about Mohr-Coulomb from

https://brainly.com/question/32785605

#SPJ11

The frequency of the AC supply is 0.036 Hz.

We know that an alternating current circuit is the kind of circuit in which we do have the resistor in addition to the to the capacitor or the inductor or both as the case may be.

Here we are told that; A 32x10^-6 F capacitor is connected to a 60V AC supply in series with a 56 ohm resistor. The current flowing in the circuit is 0.16 A.

We can tell that the impedance of the circuit can be obtained by the use of the formula;

V = IZ

V = voltage

I = current

Z = impedance

Z = V/I

Z = 60 V/0.16 A

Z = 375 ohms

Then we have;

Z = √R^2 - XC^2

375 = √(56)^2 - (1/2 * 3.142 * f *  32x10^-6)^ 2

140625 = 3136 - (1/2 * 3.142 * f *  32x10^-6)^ 2

140625 -  3136  =  (1/2 * 3.142 * f *  32x10^-6)^ 2

137489 = 1/2 * 10^-4 f

137489 * 2 * 10^-4 f = 1

f = 1/137489 * 2 * 10^-4

f = 0.036 Hz

Learn more about AC supply:https://brainly.com/question/28566820

#SPJ1

The pressure drop in a 50 m run of a 400 mm diameter pipeline with a wall shear stress of 7.0 Pa is 8.75 kPa.

To calculate the pressure drop, first, we need to find the friction factor (f) for fully developed flow.

Using the Darcy-Weisbach equation, we can relate wall shear stress (τ) to friction factor as follows:

τ = (1/2)ρv²f, where ρ is fluid density and v is fluid velocity.

Next, we can use the pressure drop equation: ΔP = f(L/D)(ρv²/2), where L is the pipeline length and D is the pipeline diameter.

Rearrange the equation for ΔP and substitute the known values, ΔP = (τ/ρ)(2L/D).

For simplicity, we'll assume a fluid density (ρ) of 1000 kg/m³.

Convert the diameter to meters (0.4 m) and calculate,

ΔP: (7.0 Pa / 1000 kg/m³)(2 * 50 m / 0.4 m) = 8.75 kPa.

To know more about friction factor visit:

brainly.com/question/17072003

#SPJ11

a = 0 and b = 0. The lead compensator becomes: C(s) = s / s This completes the design of the lead compensator.

To find the damping ratio and natural frequency of the closed-loop system, we need to determine the characteristic equation of the closed-loop system.

In a unity feedback system, the closed-loop transfer function is given by:

T(s) = G(s) / (1 + G(s)H(s))

where G(s) is the open-loop transfer function and H(s) is the transfer function of the feedback element (which is 1 in this case).

Given G(s) = K s(s+2), the closed-loop transfer function becomes:

T(s) = K s(s+2) / (1 + K s(s+2))

The characteristic equation is obtained by setting the denominator of the closed-loop transfer function to zero:

1 + K s(s+2) = 0

Simplifying the equation:

K s^2 + 2K s + 1 = 0

Now, we can determine the coefficients of the characteristic equation:

a = K

b = 2K

c = 1

The damping ratio (ζ) and natural frequency (ωn) of the closed-loop system can be calculated using the following formulas:

ζ = b / (2√(ac))

ωn = √(c / a)

Substituting the values:

ζ = (2K) / (2√(K * 1))

= √K

ωn = √(1 / K)

Therefore, the damping ratio (ζ) is √K and the natural frequency (ωn) is √(1 / K).

Now, let's plot the root locus of the system:

The root locus represents the possible locations of the closed-loop poles as the gain K varies from 0 to infinity. To plot the root locus, we need to determine the poles and zeros of the transfer function G(s)H(s).

In this case, the transfer function G(s)H(s) is:

G(s)H(s) = K s(s+2) / (1 + K s(s+2))

The poles of G(s)H(s) are the values of s that make the denominator of the transfer function zero:

1 + K s(s+2) = 0

Solving for s, we find the poles as:

s = -2 or s = -1/K

To plot the root locus, we start with the poles and move along the loci as the gain K changes. The root locus represents the values of s where the poles of the system lie.

Finally, we need to design a lead compensator to achieve the desired pole location of -o + j2. To do this, we can add a lead compensator of the form:

C(s) = (s + a) / (s + b)

where a and b are chosen to move the pole to the desired location. In this case, the desired pole location is -o + j2, so we need to choose a and b accordingly.

Since o = 0.5, the desired pole location becomes -0.5 + j2. By comparing this with the form of the lead compensator, we can equate the real and imaginary parts to find a and b:

-0.5 + a = -0.5

2 + b = 2

Learn more about open-loop transfer function here:

https://brainly.com/question/33228954

#SPJ11

Answer:

try to 36v power and take 1a and intersect to 3

The energy absorbed from the solar collector is approximately 3.16 w/m

The approximate solar energy absorbed by the collector can be calculated using the following equation:

Solar Energy Absorbed (W/m) = (Aperture Area x Solar Irradiance x Efficiency) / Hose Length

Aperture Area = π x (0.05 m)² = 0.0079 m2

Solar Irradiance = 1000 W/m²

Efficiency = (65°C - 25°C) / (100°C - 25°C) = 0.4

Hose Length = 1 m

Therefore, the approximate solar energy absorbed by the collector is:

Solar Energy Absorbed (W/m) = (0.0079 m² x 1000 W/m² x 0.4) / 1 m = 3.16 W/m

The energy absorbed is 3.16 watt per meter.

Learn more on energy absorbed here;

https://brainly.com/question/2463824

#SPJ1

complete question:

A simple solar collector is built by placing a 5-cm- diameter clear plastic tube around a garden hose whose outer diameter is 1.6 cm. The hose is painted black to maximize solar absorption, and some plastic rings are used to keep the spacing between the hose and the clear plastic cover constant. During a clear day, the temperature of the hose is measured to be 65°C, while the ambient temperature is 25°C. What is the approximate solar energy absorbed by the collector, in watts per meter of length of the hose?

Answer:

letter B

Explanation:

basta yan anwer

In an experiment, the variable that is manipulated by the researcher is called the independent variable.

The independent variable is the factor or condition that the researcher deliberately changes or controls to observe its effect on the dependent variable. The independent variable is often denoted as "X" and is the presumed cause or predictor variable in the experiment. The researcher selects the values or levels of the independent variable and manipulates it systematically across different experimental conditions or groups.

For example, in a study investigating the effect of different fertilizer types on plant growth, the researcher may manipulate the independent variable, which is the type of fertilizer applied to the plants. The researcher may have different groups of plants, each receiving a different fertilizer type (e.g., Group A: Fertilizer X, Group B: Fertilizer Y, etc.). By manipulating the independent variable, the researcher can observe and measure how the different fertilizer types impact the dependent variable, which in this case would be the plant growth.

It is important to carefully control and manipulate the independent variable to ensure that any observed effects on the dependent variable can be attributed to the changes in the independent variable rather than other factors. This allows researchers to establish cause-and-effect relationships and draw valid conclusions from their experiments.

learn more about independent variable

https://brainly.com/question/32711473

#SPJ11

Answer:

up up down down

Explanation:

left right left right b a select start

Answer:

Already drawn without counterions or byproducts

Answer:

Explanation:

Given that:

From process 1 → 2

\(P_1 = 10 bar \\ \\ V_1 = 1 m^3 \\ \\ V_2 = 4 m^3\)

\(PV^{1.5} = \ constant\)

\(\gamma = 1.5\)

Process 2 → 3

The volume is constant i.e \(V_2 =V_3 = 4m^3\)

\(P_3 = 10 \ bar\)

Process 3 → 1

P = constant  i.e the compression from state 1

Now, to start with 1 → 2

\(P_1V_1^{1.5} = P_2V_2^{1.5}\)

\(P_2 = P_1 (\dfrac{V_1}{V_2})^{1.5}\)

\(P_2 = 10 \times (\dfrac{1}{4})^{1.5}\)

\(P_2 =1.25\)

The work-done for the process  1 → 2 through adiabatic expansion is:

\(W = \dfrac{1}{1-\gamma}[P_2V_2-P_1V_1]\)

We know that 1 bar = \(10^5 \ N/m^2\)

∴

\(W = \dfrac{1}{1-1.5}[1.25 \times 10^5 \times 4- 10 \times 10^5 \times 1]\)

\(W =1000000 \ J\)

\(W_{1 \to 2} = 1000 kJ\)

For process 2 → 3

Since V is constant

Thus:

W = PΔV = 0

\(W_{2 \to 3} = 0\)

For process 3 → 1

W = PΔV

\(W _{3 \to 1} = P_3(V_1-V_3)\)

\(W _{3 \to 1} = 10 \times 10^5 (1-4)\)

\(W _{3 \to 1} = 10 \times 10^5 (-3)\)

\(W _{3 \to 1} = -3 \times 10^6 \ J\)

\(W _{3 \to 1} = -3000 \ kJ\)

The net work-done now  for the entire system is :

\(W_{net} = W_{1 \to 2} + W_{2 \to 3 } + W_{ 3 \to 1 }\)

\(W_{net} = (1000 + 0 + (-3000)) \ kJ\)

\(W_{net} =-2000 \ kJ\)

The sketch of the processes on p -V coordinates can be found in the image attached below.

A) The work done for each process are :

B) The net work for the cycle = -2000 kJ

Given Data :

For process (1 -2)      For process ( 2 - 3 )       process ( 3 - 1 )

P₁ = 10 bar                   P₃ = 10 bar                  constant pressure compression

V₁ = 1 m³                  constant volume heating

V₂ = 4 m³

PV\(^{1.5}\) = constant

A) Determine work done for each process

Calculate work done for process (1 - 2)

W₁ ₋ ₂ = \(\frac{P_{1}V_{1} - P_{2}V_{2} }{n -1 }\) * 100

         = [ ( 10*1 ) - ( 1.25 * 4 ) ] / 1.5 - 1

         = [ 10 - 5 ] / 0.5

         = 10 * 100 = 1000 kJ

Calculate work done for process ( 2-3 )

given that there is constant volume heating

W₂₋₃ = 0 kJ

Calculate work done for process ( 3-1)

W₃₋₁ = P ( Δ V )     given that p = constant

       = 10 * 100 ( -3 )

       = - 3000 kJ

B) The net work for the cycle

W₁ ₋ ₂  +  W₂₋₃  + W₃₋₁

= 1000 kJ  + 0 kJ  +  - 3000 kJ

= - 2000 kJ

Hence we can conclude that the ) The work done for each process are :

and The net work for the cycle = -2000 kJ

Learn more about piston-cylinder assembly : https://brainly.com/question/13739421

Attached below is the P-V sketch of the process

Answer: Why is even here then.

Explanation:

The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

The thickness of the aluminum can be determined using from distance of closest approach of the particle.

\(K.E = \frac{2KZe^2}{r}\)

where;

\(r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m\)

Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.

Charge of alpah particle = 2e

\(r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m\)

Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

Learn more about closest distance of approach here: https://brainly.com/question/6426420

Answer:

2D CAD Software Application

Explanation:

Two Dimensional Computer-Aided Design Software Application is otherwise known as 2D CAD software application such as AutoCAD or MicroStation is used to change physical objects and 3-D ideas into a 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.

The utilization of a 2D CAD software application saves time and revision to construction drawings can quickly be made without having to redesign the whole drawings from the scratch.

Using the knowledge in computational language in JAVA it is possible to write a code that the vending machine will collect cash and credit card for purchase.

public class vendingMachine {

  private static final int[] prices = {100, 75, 50, 25};

  private static final String[] drinks = {"Coke", "Pepsi", "Sprite", "Water"};

  public static void main(String[] args) {

      Scanner scanner = new Scanner(System.in);

      boolean running = true;

      while (running) {

          System.out.println("Welcome to the vending machine! Please make a selection:");

          for (int i = 0; i < prices.length; i++) {

              System.out.println(i + ") " + drinks[i] + " - $" + prices[i] / 100.0);

          }

          System.out.println("4) Quit");

          int selection = scanner.nextInt();

          if (selection == 4) {

              running = false;

          } else {

              System.out.println("You selected " + drinks[selection] + ". Please insert $" + prices[selection] / 100.0);

              int moneyInserted = scanner.nextInt();

              if (moneyInserted < prices[selection]) {

                  System.out.println("Not enough money for purchase. Please insert additional $" + (prices[selection] - moneyInserted) / 100.0);

              } else {

                  System.out.println("Vending " + drinks[selection] + "...");

                  System.out.println("Your change is $" + (moneyInserted - prices[selection]) / 100.0);

              }

          }

      }

      scanner.close();

  }

}

See more about JAVA at brainly.com/question/12975450

#SPJ1

Answer:

True

Explanation:

Those are the exact uses of a resistor

Answer:

Given, diameter of pin head d = 1 mm = 1/25.4 = 0.0394 in Surface area of a pinhead, A = 4pr^2 =

Explanation:

eesh

Explanation:

The Release Train Engineer (RTE) has the main work of supporting as well as coaching the Agile Release Train (ART). They are capable of steering ART successfully and to navigate the complexity in delivering  the software in large and inter-functional environments.  

They serve the scrum master and coach teams to improve on the results.

The two actions or behaviors of the RTE are :

1. They try to create an environment of the mutual influence.  

2. Listens and also supports the teams in problem identification as well as decision-making.

The behaviors or actions that the release train engineer does include:

The release train engineer refers to a servant leader who is responsible for facilitating program-level processes and executes them.

The release train engineer is also responsible for driving continuous development, managing risks, and escalating impediments. Some of their actions include operating within the lean budget and facilitating demos.

Read related link on:

https://brainly.com/question/25254146

Answer:

B

Explanation:

Answer:

The electric ceiling fan was invented in 1882 by engineer and inventor, Philip Diehl. He had earlier invented an electric sewing machine and adapted the motor from this invention to create the ceiling fan. He called his invention the “Diehl Electric Fan” and it was such a success that he soon had many other people competing with him.

Explanation:

Answer:

A rectifier is an electrical device used to convert alternating current to direct current.

Explanation:

Hope this helps! Shalom

Answer:

a. True

Explanation:

Answer:

d

Explanation:

yea

Answer:

D

Explanation:

Estimating the size and type of the "standard" and "advanced" network circuits is called capacity planning.

Capacity planning involves evaluating the network requirements, traffic patterns, and projected growth to determine the appropriate size and type of network circuits. It aims to ensure that the network infrastructure can adequately handle the anticipated workload and meet performance expectations. By considering factors such as bandwidth requirements, network utilization, data transfer rates, and potential bottlenecks, capacity planning helps organizations optimize their network resources and make informed decisions regarding circuit sizing and provisioning. This process assists in avoiding network congestion, optimizing network performance, and ensuring that the network circuits are sufficient to meet the organization's present and future needs.

Learn more about capacity planning here:

brainly.com/question/13484626

#SPJ11