5. Maximum velocity of a boat in still d = 500 m Vw=3 m/s water is v=5m/s. This boat sets off from one side of a river 500m in width, and travels directly across the river. Find the passage time for t
Answers
The boat will take approximately 86 seconds to cross the river, considering rounding to the nearest whole number. This calculation takes into account the boat's maximum velocity in still water and the velocity of the river.
To determine the passage time, we need to consider the relative velocities of the boat and the river.
The boat's maximum velocity in still water is given as Vb = 5 m/s, and the velocity of the river is Vw = 3 m/s.
When the boat is moving across the river, it experiences a resultant velocity due to the combination of its velocity relative to the water and the water's velocity itself. This can be calculated using vector addition.
Let's denote the passage time as t. The distance the boat needs to travel is equal to the width of the river, which is given as d = 500 m.
We can set up the following equation:
d = (Vb² + Vw²)^0.5 * t
we use the Pythagorean theorem to calculate the resultant velocity of the boat relative to the river. The velocity of the boat in still water (Vb) represents its speed without any influence from the river. The velocity of the river (Vw) represents the speed at which the water is flowing.
When the boat moves across the river, its velocity relative to the water combines with the water's velocity itself. This combination of velocities can be thought of as the hypotenuse of a right triangle, with Vb as one side and Vw as the other side.
Therefore, the resultant velocity can be calculated using the Pythagorean theorem: resultant velocity = (Vb² + Vw²)^0.5
Since the distance the boat needs to travel is equal to the resultant velocity multiplied by the passage time, we can write:
d = (Vb² + Vw²)^0.5 * t
Substituting the given values:
500 = (5²+ 3²)^0.5 * t
Simplifying the equation:
500 = (25 + 9)^0.5 * t
500 = (34)^0.5 * t
500 = 5.83 * t
Dividing both sides by 5.83:
t = 500/ 5.83
t ≈ 85.74 seconds
Therefore, the passage time for the boat to cross the river is approximately 85.74 seconds or approximately 86 seconds.
The boat will take approximately 86 seconds to cross the river, considering rounding to the nearest whole number. This calculation takes into account the boat's maximum velocity in still water and the velocity of the river.
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Related Questions
How did people fly before Isaac Newton invented gravity?
Answers
Answer:
Isaac Newton did not invent gravity. Gravity is a fundamental force of nature that has always existed. Newton's contribution was to formulate the laws of motion and universal gravitation, which helped to explain the behavior of objects under the influence of gravity.
As for how people flew before the development of powered flight, they relied on a variety of methods, such as gliding, using hot air balloons, and being lifted by the wind in kites. For example, in China, people have been flying kites for more than 2,000 years. In the late 18th century, the Montgolfier brothers developed hot air balloons, which allowed humans to ascend into the air for short periods of time. And in the late 19th and early 20th centuries, pioneers of aviation such as the Wright brothers and their contemporaries developed powered aircraft, which eventually led to modern air travel.
A satellite with a mass of 110 kg and a kinetic energy of 3.0 ´ 109 J must be moving at a speed of
Answers
Answer: A satellite with a mass of 110 kg and a kinetic energy of 3.08×10^9 J must be moving at a speed of 7483 m/s.
Explanation: To find the answer we need to know about the kinetic energy of a body.
How to solve the problem the equation of kinetic energy?We have the expression for kinetic energy of a body as,\(KE=\frac{1}{2}mv^2\)
Given that,\(m=110kg\\KE=3.08*10^9J\\\)
We have to find the speed of the satellite,\(v=\sqrt{\frac{2KE}{m} } =\sqrt{\frac{2*3.08*10^9}{110} } =7.483*10^3 m/s\)
Thus, we can conclude that, the velocity of the satellite will be 7438m/s.
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In order to move at a speed of 7483 m/s, a satellite with a mass of 110 kg and a kinetic energy of 3.08× 10^-9 J must be travelling.
Understanding a body's kinetic energy is necessary in order to determine the solution.
How can the kinetic energy equation be solved?The phrase "kinetic energy of a body" might be used as,\(KE=\frac{1}{2}mV^2\)
Given that,\(m=110kg\\KE=3.08*10^9J\)
We must determine the satellite's speed.\(V=\sqrt{\frac{2KE}{m} }=7.48km/s\)
Thus, we can infer that the satellite will move at a speed of 7438 m/s.
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analyze how carbohydrate gets digested in the mouth
( answer this question)
Answers
In 1980, over San Francisco Bay, a large yo-yo was released from a crane. Suppose the yo-yo was 107 kg, and it consisted of two uniform disks of radius 27.7 cm connected by an axle of radius 2.77 cm. What was the magnitude of the acceleration of the yo-yo during (a) its fall and (b) its rise
Answers
The magnitude of acceleration of the yo-yo during its fall and rise can be determined using the principles of rotational motion and torque.
(a) During the yo-yo's fall, it is subject to two forces: its weight (mg) and the tension in the string. The net torque acting on the yo-yo causes it to rotate and accelerate. The torque due to the weight can be calculated as the weight multiplied by the radius of the axle (2.77 cm). The torque due to the tension in the string can be calculated as the tension multiplied by the radius of the disks (27.7 cm).
To calculate the magnitude of acceleration during the fall, we need to sum up the torques and divide by the moment of inertia of the yo-yo. The moment of inertia for two uniform disks connected by an axle can be calculated as (1/2) * mass * (radius^2).
Once we have the moment of inertia and the net torque, we can use the equation τ = I * α, where τ is the net torque, I is the moment of inertia, and α is the angular acceleration. The angular acceleration is related to the linear acceleration by the equation α = a / r, where a is the linear acceleration and r is the radius of the axle.
(b) During the yo-yo's rise, the forces acting on it are the same as during the fall: its weight (mg) and the tension in the string. However, the direction of the net torque is opposite to that during the fall. Thus, the magnitude of acceleration during the rise can be calculated using the same principles as in part (a), but with the signs of the torques reversed.
It's important to note that the tension in the string changes during the yo-yo's motion, which affects the magnitude of acceleration. To accurately determine the tension, more information about the yo-yo's motion, such as the angular velocity or the length of the string, would be needed.
In summary, the magnitude of the acceleration of the yo-yo during its fall and rise can be calculated using principles of rotational motion, torque, and moment of inertia. The specific calculations require more information about the yo-yo's motion and the tension in the string.
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A positive point charge is placed at 5 cm from a negatively charged plate.
it is then pulled away from the plate, so it is 10 cm from the plate. Describe
what happened to the potential energy of the charge. (Hint what
happened to the force on the charge more force means more potential
energy) *
Answers
Answer: I'm not sure about this one, but you can go to this link to understand it better https://youtu.be/wEQxtUwiV1E.Its a Khan Academy Video Hope This Helps
Explanation:
1. Cite the primary differences between elastic, anelastic, and plastic deformation behaviors.
2. Of those metals listed in table 6.3. (provided in the image)
a) Which will experience the greatest percent reduction in area? Why?
b) Which is the strongest? Why?
c) Which is the stiffest? Why?
d) Of those metals listed in Table 1. Which is the hardest, why?
Material Yield. Tensile. Strain. Fracture. Elastic
Strength Strength. at. Strength. Modulus
(MPa). (MPa). Fracture (MPa). (GPa)
A. 310. 340. 0.23. 265. 210
B. 100. 120. 0.40. 105. 150
C. 415. 550. 0.15. 500. 310
D. 700. 850. 0.14. 720. 210
E Fractures before yielding. 650. 350
Answers
1. Elastic deformation is a reversible deformation where the material can return to its original shape and size once the applied load is removed.
Anelastic deformation is a time-dependent deformation where the material undergoes some permanent deformation upon loading and unloading but still can recover its original shape over a long time.
2. a) Material B will experience the greatest percent reduction in area because it has the highest elongation (strain) value, which means it can undergo more deformation before failure.
b) Material D is the strongest because it has the highest yield strength and tensile strength values, which means it can withstand higher loads before deformation and failure.
c) Material C is the stiffest because it has the highest elastic modulus value, which means it requires higher stress to produce a certain amount of deformation.
Deformation refers to a change in the shape or size of a material or object due to the application of external forces. This can occur in response to tension, compression, shear, or a combination of these forces. Deformation can be either elastic or plastic.
Elastic deformation is temporary, meaning that the material will return to its original shape once the forces are removed. On the other hand, plastic deformation is permanent, meaning that the material retains its deformed shape even after the forces are removed. Deformation is an important concept in materials science, engineering, and physics, as it plays a crucial role in determining the behavior and properties of materials.
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a yo-yo is made of two uniform disks, each of mass m and radius r, which are glued to a smaller central axle of negligible mass and radius 0.5r (see figure). a string is wrapped tightly around the axle. the yo-yo is then released from rest and allowed to drop downwards, as the string unwinds without slipping from the central axle.
Answers
The axle is tightly cinched with a string. The yo-yo is then allowed to sink downward after being removed from rest.
What is uniform?
This kind of motion is described as the movement of an object that travels in a straight line and maintains a constant speed along that path while traversing equal distances in equal amounts of time, regardless of the length of the time.
Moment of inertia is calculated using the formula 1 on top of 2 m r square + 1 on top of 2 m r square. We can calculate moment of inertia from this. M is that. We must determine the equation for speed in part b since I is now equal to m r square in order to determine the expression for speed when the energy conservation law applies. It will yield 2 mg. H equals 1 multiplied by 22 mv square plus 1. I omega square after number 2. The answer to the equation is 2 m g h = m v square + 1 on 2.
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How can the intensity of a sound be changed without changing the pitch
Answers
Answer:
Sound waves are greatly affected by the medium in which they travel, not just in terms of speed, but also in terms of loudness and tonal quality. Just think of the variation in loudness and sound quality of different acoustic guitars which may use the same strings, but the sound is greatly affected by the different media in which it travels, including the wood, sound cavities, even the varnish on the instrument.
Explanation:
can anyone help me???
Answers
Answer:
yes
Explanation:
1.98×10 m/s
you can use a physics text
I remember but am not sure
3.00 × 10 m/s
I think you do 10 ×10 in 8 places for both them you do the rest
Sort the types of energy according to the order in which they move through this system:
Water stored in dams falls freely with the force to make a turbine move. The turbine moves and produces electricity. This electric energy is supplied to homes. At home, we use electricity for heating, cooling, and lighting.
Answers
The types of energy that move through the system are as follows: potential energy, kinetic energy, mechanical energy, and electrical energy.The water stored in the dams contains potential energy.
This energy is stored as the water is located at a higher altitude compared to the point where it falls. The potential energy of the water is converted into kinetic energy as it falls through the force of gravity with a speed proportional to its mass and the height from which it fell. The moving water can be used to make a turbine move, which converts the kinetic energy of the moving water into mechanical energy. The mechanical energy of the turbine is used to generate electricity through a generator, which converts the mechanical energy into electrical energy. The electricity generated is then supplied to homes for heating, cooling, and lighting. Hence, the energy moves through the system in the following order: potential energy, kinetic energy, mechanical energy, and electrical energy.For such more question on potential energy
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A string is wrapped around a pulley of radius 0.10 m and moment of inertia 0.15 kg·m^2. The string is pulled with a force of 12 N. What is the magnitude of the resulting angular acceleration of the pulley?
Answers
The magnitude of the resulting angular acceleration of the pulley is 8.0 rad/s².
To find the magnitude of the resulting angular acceleration of the pulley, we can use the formula:
α = τ / I
Where α is the angular acceleration, τ is the torque applied to the pulley, and I is the moment of inertia of the pulley.
First, we need to find the torque applied to the pulley. The force applied to the string (12 N) creates a torque by pulling on the pulley, which can be calculated using the formula:
τ = rF
Where τ is the torque, r is the radius of the pulley (0.10 m), and F is the force applied to the string (12 N).
τ = (0.10 m)(12 N) = 1.2 N·m
Now we can use this torque and the moment of inertia of the pulley (0.15 kg·m²) in the formula for angular acceleration:
α = τ / I
α = (1.2 N·m) / (0.15 kg·m²)
α = 8.0 rad/s²
Therefore, the pulley will have an angular acceleration of 8.0 rad/s².
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The graph above shows Marie's trip to work as a distance/time graph.
Match the range from the graph with the correct description of the type of motion.
At Rest __
Moving the Fastest __
Moving back to home __
Moving the Slowest ___
options:
E to F
B to C
A to B
C to D
Answers
Fastest= EF
Back to home= BC
Slowest= CD
From the graph it is clear that Marie is at rest from A to B. From B to C she is back to home. From C to D the motion gets slows down. From E to F, moving the fastest.
What is distance -time graph?A distance - time graph is really helpful to determine the position of an object with respect to time. Thus, we can clearly calculate how much distance is covered within a given time.
From the given graph, from A to B , the girl was at rest and just started her trip. From B to C, the position changes to 0 m which means she is back to home.
At the position C to D she is moving with slowly, the change in position is very less with the time change. D to E she is in rest. From E to F the girls moves fastly and the distance changes from 5 m to 20 m within 10 minutes.
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pls somebody help there is a blank space between this and the question its screenshotted just look down
Answers
Answer:
This relationship is from Newtons Second Law of Motion
Newton's second law shows that there is a direct relationship between force and acceleration. The greater the force that is applied to an object of a given mass, the more the object will accelerate.
Its expressed as
F=ma
a worker is standing on a wet concrete floor, holding an electric drill having a metallic case. the metallic case is connected through the ground wire of a three-terminal power outlet to power-system ground. the resistance of the ground wire is rg. the resistance of the worker's body is rw
Answers
The resistance of the ground wire is Rg is mathematically given as Rg=0.025Ф
This is further explained below.
What is resistance?Take into account that the amount of electricity flowing through the worker's body does not surpass 0.1 mA.
The value of the earth's resistors should be extremely low in order to ensure that the greatest possible current is carried by the earth wire and, as a result, that the worker is not shocked.
Determine the highest possible value for R g s o.
\($\begin{aligned}&0.1 \mathrm{~mA}=(2)\left(\frac{R_g}{R_g+500}\right) \\&\frac{R_g+500}{R_g}=20000 \\&R_g+500=20000 R_g \\&\begin{aligned}R_g &=\frac{500}{20000-1} \\&=0.025 \Omega\end{aligned}\end{aligned} \\\\ Rg=0.025Ф\)
The current that flows through the worker is less than or equal to 0.1mA.
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CQ
A worker is standing on a wet concrete floor, holding an electric drill having a metallic case. The metallic case is connected through the ground wire of a three-terminal power outlet to the power-system ground. The resistance of the ground wire is Rg. The resistance of the worker's body is Rw = 500 ?. Due to faulty insulation in the drill, a current of 2 A flows into its metallic case. The circuit diagram for this situation is shown in the figure.Find the maximum value of Rgso that the current through the worker does not exceed 0.1 mA.
As distance ________________ between two objects, gravitational force will _________________. *
1 point
a. increases, increase
b. increases, decrease
c. decreases. increase
Answers
Answer:
b. increases, decrease
Explanation:
Which force does not operate at a distance of 1 m?
A. Weak nuclear
O B. Electric
C. Gravitational
D. Magnetic
Answers
Answer:
A
Explanation:
What are the five elements of fitness?
Answers
Answer:
5 Components of Physical Fitness
Cardiovascular Endurance.
Muscular Strength.
Muscular endurance.
Flexibility.
Body Composition.
Which of the following waves in the electromagnetic spectrum do all objects emit?
Radio Waves
Infrared Waves
Visible Light waves
Ultraviolet Waves
please answer ASAP
Answers
Answer:
radio waves
Explanation:
Answer:
the answer is A radio waves
(b) A ball is thrown vertically upwards with
velocity of 20 m/s from the top of a tower of
height 25 m from ground. How long does it
remain in air? (g = 10 m/s²)
Answers
Answer:
5 seconds
Explanation:
The vertical position of the ball will be given by the equation
df = do + vo t + 1/2 a t^2 df = final position = 0 ( on the ground
do = original position ( 25 m )
vo = original velocity (+ 20 m/s)
a = - 10 m/s^2
So this becomes
0 = 25 + 20 t - 1/2 (10)t^2
= - 5 t^2 +20 t + 25 Use Quadratic Formula a = -5 b=20 c = 25
to find the positive value of t = 5 seconds
how large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 105 m m at a speed of 102 km/h k m / h ?
Answers
The car must have a static friction coefficient of 0.568 in order to safely round the bend.
What is a suitable friction coefficient?"The Occupational Safety and Health Administration advises that walking surfaces have a static coefficient of friction of 0.5," reads the appendix statement (at A4. 5). The allocation of a 0.5 COF to OSHA is most likely explained by the regulatory proposal from OSHA and the mention in ADAAG taken together.
To get the static friction coefficient required for a vehicle to travel at 102 km/h around a flat curve with a radius of 105 m,
F = mv²/r
F = μs * N
μs × N = mv²/r
N = mg
μs × mg = mv²/r
μs = v²/(gr)
μs = (102 km/h)² / (9.8 m/s² × 105 m)
μs = 0.568
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The fine horizontal scratches etched onto a bullet after it has been fired are called?
Answers
The fine horizontal scratches etched onto a bullet after it has been fired are called Striations.
What is Striations?Striations are the minute differences in the curve of the bullet's surface. The bullet and the gun barrel are the harder and softer materials, respectively, in firearms evidence. The striations left on the fired bullet are used as a comparison by firearm examiners.When a gun is discharged, the bullet blasts down the barrel where it strikes ridges and grooves, spinning and improving shot accuracy. These ridges cause striations in the bullet's soft metal by digging into it.An examiner analyses these distinctive markings to verify whether a given bullet was shot from a specific firearm. A barrel will produce individual markings in addition to a bullet's land and groove impressions as the projectile passes through.Learn more about Bullet here:
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The mass of this astronaut on the moon is 84kg. If the astronaut is on the moon for 3 weeks then returns home, his mass will be (blank) kg ?
Answers
Answer:
84kg
Explanation:
If the mass of an astronaut in on the moon is 84kg on the moon. After the 3weeks in returning home, his weight will not change. The mass of the astronaut will remain the same which is 84kg. This is so because the acceleration due to gravity experienced by the body remains the same both in the earth and in moon.
The burning of a log releases the logs chemical_energy into other forms of energy
Answers
Answer:
When we burn wood we are releasing solar energy, in the form of heat, that has been stored in the wood as chemical energy. The process of photosynthesis converted solar energy, water and carbon dioxide into oxygen and the organic molecules that form the wood, half the weight of which is carbon.
Explanation:
ch 201 self study worksheet 7a 1. is the ph of a solution that is 0.25 m in hf and 0.15 m f1- ? the pka of hf is 3.14.
Answers
The pH of the solution is approximately 2.919.
To determine the pH of the solution, we need to consider the dissociation of HF (hydrofluoric acid) and the equilibrium between HF and its conjugate base, F^-.
HF can dissociate according to the equation: HF ⇌ H^+ + F^-
Given that the solution is 0.25 M in HF and 0.15 M in F^-, we can assume that HF is the predominant species and the concentration of F^- is relatively low. Therefore, we can consider HF as the acid and F^- as the conjugate base.
The pKa of HF is given as 3.14. The pKa is a measure of the acid's strength, and it is related to the equilibrium constant for the dissociation reaction. In this case, pKa = -log(Ka), where Ka is the acid dissociation constant.
Using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]), we can calculate the pH of the solution.
pH = 3.14 + log(0.15/0.25) ≈ 3.14 + (-0.221) ≈ 2.919
Therefore, the pH of the solution is approximately 2.919.
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How would you expect the results of your experiment to change if you used the same friction block on a different surface? How
would you expect your results to change if you set the friction block on a different side (so that the area of contact between the
two surfaces was different)?
Answers
Answer:
If the friction block was placed on a smoother, more slippery surface there would be less friction. If it was placed on a rougher surface there would be more fiction. If the block was placed on a different side the results would vary depending on factors such as surface area and texture of the block. This is why roads are made of asphalt because of its rough surface, which creates more fiction so vehicles don’t lose traction.
in a star nuclear fusion occurs in the
A. corona
b. photosphere
c. core
d. radiative zone
Answers
Answer:
C. Core
Explanation:
Can someone please help me it's urgent!
Answers
Answer:
6.8 x 10^6
Explanation:
Look up M A T H W A Y it will help you with all of your algebra needs
in longitudinal waves in a spring, the parts where the coils are close together are called
Answers
Answer:
compression
Explanation:
compression
A 5.0-m-wide swimming pool is filled to the top. The bottom of the pool becomes completely shaded in the afternoon when the sun is 23Â degrees above the horizon. How deep is the pool? (in meters)
Answers
the depth of the pool is 3.08 meters.
Given:
Width of the swimming pool = 5.0 mThe pool is filled to the top.
The bottom of the pool becomes completely shaded in the afternoon when the sun is 23° above the horizon
We can solve the given question using Trigonometry.
ABC,cot 23° = AB/BCEquation (1)
But, AB + BC = 5.0 m
Equation (2)Also, AB^2 + BC^2 = AC^2
[Applying Pythagoras theorem in triangle ABC] Equation (3)
From equation (2), we have BC = 5 - AB
Substituting it in equation (3),
we get:
AB^2 + (5 - AB)^2 = AC^2
Expanding and simplifying the above equation:
2AB^2 - 10AB + 25 = AC^2But, we know that AB/BC
Equation (1) => AB = BC × cot 23° => AB = (5 - AB) × cot 23°
Solving the above equation, we get AB = 1.92 m
Hence, the depth of the pool is BC = 5 - AB = 5 - 1.92 = 3.08 meters.
So, the depth of the pool is 3.08 meters.
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what are the three examples that show relation between pressure and area in daily life.
Answers
Answer: The area of the edge of a knife's blade is extremely small.
Syringes are used to take blood for blood tests.
When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.
Explanation: