5. Scientists always develop a plan when they try to learn something about our natural world. Which
sequence correctly shows the steps scientists follow in their plan?
A. make observations, develop an idea, obtain evidence, suggest an explanation
B. obtain evidence, suggest an explanation, develop an idea, make observations
C. suggest an explanation, obtain evidence, make observations, develop an idea
D. develop an idea, suggest an explanation, obtain evidence, make observations

Answer:

I think this the asnwer a satellit

Sorry if it incorrect

Have a nice day

Answer:

The Answer is Satellite.

Explanation:

An orbit is a regular, repeating path that one object in space takes around another one. An object in an orbit is called a satellite. A satellite can be natural, like Earth or the moon.

Let's see

\(\\ \rm\dashrightarrow k=\dfrac{Concentration\:of\: products}{Concentration\:of\: reactants}\)

\(\\ \rm\dashrightarrow k=\dfrac{\left[A_2B_2\right]}{\left[A\right]^2\left[B\right]}\)

To synthesize 2-methylpentan-3-one efficiently, following process has to be followed:

Start with the synthesis of 2-methylpentan-3-ol, which can be prepared via a Grignard reaction. Firstly, prepare 2-methylpentan-3-ol by reacting ethyl magnesium bromide with 3-methylbutanal.

Afterward, hydrolysis of this Grignard reagent using HCl or dilute sulfuric acid provides the alcohol.2-methylpentan-3-ol.

( Grignard reaction -The Grignard reaction is an organometallic chemical reaction in which carbon alkyl, allyl, vinyl, or aryl magnesium halides (Grignard reagent) are added to the carbonyl groups of either an aldehyde or ketone. This reaction is important for the formation of carbon–carbon bonds.)

Now,the oxidation of 2-methylpentan-3-ol is carried out using oxidizing agents like PCC (pyridinium chlorochromate), PDC (pyridinium dichromate), or Jones reagent to synthesize 2-methylpentan-3-one.Oxidation of 2-methylpentan-3-ol to synthesize 2-methylpentan-3-one can be represented as follows: PCC or PDC or Jones Reagent2-methylpentan-3-one.

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Answer: C intermolecular force

Explanation:

The type of attractive force shown in the figure is intermolecular force. Option C is correct.

There are nonbonding forces of attraction between one individual molecule and another. These forces are referred to as intermolecular forces and are responsible for the physical behavior of the phases of matter, such as their ability to form solids, liquids, and gases.

The strength of the intermolecular forces varies depending on the type of substance and its molecular structure. For example, substances with strong intermolecular forces, such as water, have a higher boiling point and are more likely to exist as liquids or solids at room temperature, while substances with weak intermolecular forces, such as methane, have a lower boiling point and are more likely to exist as gases.

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The number of moles of O₂ used to produce 4 moles of NO is 2 moles

First, shall write the balanced equation. This is given below:

N₂ + O₂ -> 2NO

From the balanced equation above,

2 moles of NO were obtained from 1 mole of O₂

With the above information, we can determine the number of moles of O₂ used to produce 4 moles of NO. This can be obtained as follow:

From the balanced equation above,

2 moles of NO were obtained from 1 mole of O₂

Therefore,

4 moles of NO will be obtain from = (4 × 1) / 2 = 2 moles of O₂

Thus, number of mole of O₂ used is 2 moles

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The reactions that will occur for each activity series include:

Reactive metals are metals that easily undergo chemical reactions with other substances, particularly with acids and water, to form new compounds. These metals are usually found in the lower part of the activity series, which means they have a high tendency to lose electrons and form cations.

Examples of reactive metals include alkali metals (such as lithium, sodium, and potassium) and alkaline earth metals (such as calcium and magnesium).

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Image trancribed:

Based on the activity series, which of the reactions will occur?

Least Reactive

Most Reactive Li Na K Mg Al Zn Fe Ni Sn Pb H Cu Ag Pt F₂ Cl₂ Br₂ I₂

Hint: Is the metal element more reactive than the metal ion in the compound?

A. Mg + NaNO3 →

B. AI+NISO4→

C. Zn + NaNO3 -

D. Sn+ Zn(NO3)2 →

Answer:A. Mg + NaNO₃ →

Explanation:

will occur since Mg is more reactive than Na.

The coordination number for pb will be 12

Four atoms make up each unit cell of the face-centered cubic (fcc), which has a coordination number of 12. Two atoms make up each unit cell of the body-centered cubic (bcc), which has a coordination number of eight.

The number of atoms, ions, or molecules that a central atom or ion in a complex, coordination compound, or crystal holds as its closest neighbours.

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Answer:

Approximately \(3.6 \times 10^{-10}\; {\rm M}\), assuming that the solution is dilute and is at room temperature (such that \(K_\text{w} = 10^{-14}\).)

Explanation:

Look up the ion product constant of water:

\(K_{\text{w}} \approx 10^{-14}\).

In a dilute solution where water is the solvent, the product of \([{\rm {H_{3}O}^{+}}]\) and \([{\rm {OH}^{-}}]\) (concentration of \(\rm {H_{3}O}^{+}}\) ions and \({\rm {OH}^{-}}\) ions) is constantly equal to \(K_{\text{w}}\). (The unit of both \([{\rm {H_{3}O}^{+}}]\!\) and \([{\rm {OH}^{-}}]\!\) need to be \({\rm M}\).) In other words:

\([{\rm {H_{3}O}^{+}}]\, [{\rm {OH}^{-}}] = K_{\text{w}}\).

Rearrange this equation to find \([{\rm {OH}^{-}}]\) in terms of \(K_{\text{w}}\) and \([{\rm {H_{3}O}^{+}}]\):

\(\begin{aligned}[] [ {\rm OH^{-}} ] &= \frac{K_{\text{w}}}{[{\rm {H_{3}O}^{+}}]} \\ &= \frac{10^{-14}}{2.8 \times 10^{-5}} \\ &\approx 3.6 \times 10^{-10}\end{aligned}\).

When both parents shared different traits either it will be heterogeneous or homogenous traits,in that case offspring traits neither belongs to parents.However,chances are very that traits of children neither belongs to parents.

Unaffected parents can create impacted offsprings assuming that the two guardians are transporters (heterozygous) for the attribute being followed in the family. Latent traits are normally not communicated in each age. Finally, guys and females are similarly prone to communicate a latently acquired characteristic.

In the event that the latent characteristic is more than prevailing, the recessive traits will really become predominant and the predominant attribute will become recessive.Recessive alleles are meant by a lowercase letter (a versus A). Just people with an aa genotype will communicate a latent characteristic; consequently, posterity should get one passive allele from each parent to display a latent traits.

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Answer:

We'd all freaking freeze to death and be standing there like the black beetles trend.

Explanation:

This is a joke, please don't take this seriously.

The amount of acetic acid (CH₃COOH) in grams needed to prepare the solution is 90

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Molarity = mole / Volume

Cross multiply

Mole = Molarity × Volume

Mole of CH₃COOH = 1.5 × 1

Mole of CH₃COOH = 1.5 mole

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of CH₃COOH = 1.5 × 60

Mass of CH₃COOH = 90 g

Thus, 90 g of CH₃COOH is needed to prepare the solution

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Answer:

1. 2Ca + N\(_{2}\) → 2CaN

2. 4Li + O\(_{2}\) → 2Li\(_{2}\)O

3. 2KCl + BaF\(_2\) → 2KF + BaCl\(_2\)

4. CH\(_4\) + 2O\(_2\) → CO\(_2\) + 2H\(_2\)O

Be sure to balance the number of atoms on both sides of each equation only by adding coefficients to the compounds!!!! Those without a coefficient are meant to have a coefficient of 1.

Answer:  0.428%

Explanation:  % Error = [(measured - Actual)/Actual]*100%

    (93.9g - 93.5 g)/93.5g = 0.428%

Answer:

+0.4

Explanation:

For all those Acellus kids XD

Answer:

Units are used to show if a certain calculation is on track.

Explanation:

For example, 5.1 inches is way shorter than 5.9 inches.

In terms of the energy change in the reaction, the negative value indicates that the reaction is exothermic as the reaction releases 1560.74 kJ of energy for every mole of C2H6 that reacts with 7/2 moles of O2.

The model of chemical energy changes is given below:

Balanced chemical equation:

C2H6 + 7/2 O2 → 2CO2 + 3H2O

Now, to calculate the energy change in the reaction, we will use a table of enthalpy values. The enthalpy change for each of the reactants and products is given in the table below:

Reactants:

C2H6: -84.68 kJ/mol

O2: 0 kJ/mol

Products:

CO2: -393.51 kJ/mol

H2O: -285.83 kJ/mol

The energy change in the reaction can be calculated using the formula:

ΔH = ∑(products) - ∑(reactants)

ΔH = [2(-393.51 kJ/mol) + 3(-285.83 kJ/mol)] - [-84.68 kJ/mol + 7/2(0 kJ/mol)]

ΔH = -1560.74 kJ/mol

Therefore, the energy change in the reaction is -1560.74 kJ/mol.

To create a model of the energy change in the reaction, we can use an energy level diagram. In this diagram, the energy of the reactants is shown on the left, the energy of the products is shown on the right, and the activation energy is shown as a barrier between them.

The energy level diagram for this reaction is shown below:

Reactants (C2H6 + 7/2 O2)

                |

                |

       Activation energy

                |

                |

Products (2CO2 + 3H2O)

As shown in the diagram, the reactants have a higher energy level than the products, and the activation energy is required to get the reaction started.

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Answer:

I hate to not answer and have you repost this if you could repost it with the choices by clicking the arrow I can figure it out a lot faster and I'll copy and paste to show you that it's right

Explanation:

I'm good with history biology sum math so if you want to do what I asked and reposted I can give you the answers and I will show that they are correct I won't just guess like some people do just to get points cuz I don't care about points I just get on here to help people

Answer: The answer for the blanks is initial appearance and than final appearance.

Explanation:

The atomic radius of Floridium atoms in the FCC unit cell is approximately 109.8 pm to one decimal place.

The face-centered cubic unit cell contains 4 atoms. The edge length of the unit cell can be calculated using the formula:
a = 2 * (radius of atom)
Therefore, the radius of each floridium atom can be calculated as:
radius of atom = a / (2 * sqrt(2))
radius of atom = 310.2 pm / (2 * sqrt(2))
radius of atom = 109.9 pm
Therefore, the atomic radius of floridium is 109.9 pm to one decimal place.
To find the atomic radius of Floridium atoms in a face-centered cubic (FCC) unit cell, we can follow these steps:
1. Recall the relationship between the edge length (a) and the atomic radius (r) in an FCC unit cell: a = √2 * 4r.
2. Solve for the atomic radius (r) using the given edge length (a = 310.2 pm).
Step 1: Relationship between edge length and atomic radius in an FCC unit cell
For an FCC unit cell, the relationship between the edge length (a) and the atomic radius (r) is given by the formula:
a = √2 * 4r
Step 2: Solve for the atomic radius (r)
We are given the edge length (a = 310.2 pm). We can plug this value into the formula and solve for r:
310.2 pm = √2 * 4r
Now, we need to isolate r by dividing both sides of the equation by 4√2:
r = (310.2 pm) / (4√2)
r ≈ 109.8 pm
Therefore, the atomic radius of Floridium atoms in the FCC unit cell is approximately 109.8 pm to one decimal place.

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Answer:

newtons law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of the distance between their centers

Answer:

an object at rest tends to stay at rest

Answer:

c

Explanation:

beacause Câu 1: Trình bày phương pháp hóa học nhận biết

Answer:

I think it is b

Explanation:

but I'm not for sure that the answer is right

Answer:

Unknown 4

Explanation:

Answer:

chemical hazard

Explanation:

Answer:

the pH solution is 4.9.

[\(H^{+}\)(aq)] = \(10^{-pH}\)

Explanation:

If salt A has a greater solubility in water than salt B we can say that the Ksp value of salt A is greater than the Ksp value of salt B.

Solubility product constant (Ksp) is a measure of the solubility of an ionic compound in water. The Ksp value is dependent on the nature of the compound and the conditions under which it is dissolved. A higher Ksp value indicates that the compound is more soluble in water.

If salt A has a greater solubility in water than salt B, it means that salt A has a higher concentration of dissolved ions in water compared to salt B. This implies that the Ksp value of salt A is greater than the Ksp value of salt B, as a higher concentration of ions in solution requires a higher Ksp value to maintain equilibrium.

Therefore, we can conclude that the solubility of salt A is greater than salt B, and that the Ksp value of salt A is greater than the Ksp value of salt B.f f s

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The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:

2 SO2(g) + O2(g) → 2 SO3(g)

To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.

To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:

S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol

Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:

2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1

Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:

2 SO2(g) + O2(g) → 2 SO3(g) ΔH2

Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:

ΔH2 = ΔHf° - ΔH1

Substituting the given values, we get:

ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol

Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.

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The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:

2 SO2(g) + O2(g) → 2 SO3(g)

To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.

To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:

S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol

Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:

2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1

Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:

2 SO2(g) + O2(g) → 2 SO3(g) ΔH2

Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:

ΔH2 = ΔHf° - ΔH1

Substituting the given values, we get:

ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol

Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.

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The balanced chemical reaction for the combustion of glucose (C6H12O6) can be represented as follows:
C6H12O6(s) + 6O2(g) -> 6CO2(g) + 6H2O(g)

In this reaction, glucose (C6H12O6) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).

To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. In this case, we have 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the left side (reactants). On the right side (products), we have 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms as well.

To balance the carbons, we place a coefficient of 6 in front of CO2. This gives us 6 carbon atoms on both sides. To balance the hydrogens, we place a coefficient of 6 in front of H2O. This gives us 12 hydrogen atoms on both sides. Finally, to balance the oxygens, we place a coefficient of 6 in front of O2. This gives us 18 oxygen atoms on both sides.

By balancing the equation, we ensure that the law of conservation of mass is obeyed. This means that the total number of atoms of each element remains the same before and after the reaction.

In summary, the balanced chemical equation for the combustion of glucose is:

C6H12O6(s) + 6O2(g) -> 6CO2(g) + 6H2O(g)

This equation shows that when glucose is combusted, it reacts with oxygen to produce carbon dioxide and water.

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The mass of iron sample will be 585 grams.

According to the question,

Density of iron sample = 7.80 g/cm³

Volume of water displaced = 75.0 ml

1 ml = 1 cm³

Therefore, 75 ml = 75 cm³

Density is defined as the mass (m) of a substance per unit volume (V). It can be generally denoted by ρ. Therefore, ρ = m/V.

Mass is the amount of matter present in a substance. Volume is the 3-D space occupied by a substance.

In the given question density and volume are provided and to find the value of mass, the formula can be rewritten as: m = ρ × V.

Hence, m = 7.80 g/cm³ × 75 cm³

            m = 585 grams.

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