5) what are the requirements for using time rather than temperature as the only method of control when holding ready to eat tcs food?

The lead block is moving at a speed of 1 m/s after the bullet rebounds off of it. The correct answer is (c) -5 m/s.  

First, we need to find the momentum of the bullet before it hits the block:

p_bullet = m_bullet * v_bullet = 50 * 500 = 25,000 g

We also need to find the momentum of the block before the bullet hits it:

p_block = m_block * v_block = 2 * 2000 = 4000 g

After the bullet hits the block, it rebounds with a speed of 300 m/s. The momentum of the bullet after the collision is:

p_bullet_after = m_bullet * v_bullet_after = 25,000 * 300 = 750,000 g

The momentum of the block after the collision is:

p_block_after = m_block * v_block_after = 4000 * 300 = 120,000 g

The momentum of the system (bullet + block) before the collision is:

p_system_before = p_bullet + p_block = 750,000 + 120,000 = 870,000 g

The momentum of the system after the collision is:

p_system_after = p_bullet_after + p_block_after = 750,000 + 120,000 = 870,000 g

We want to find the speed of the block after the collision, so we can set the total momentum of the system before and after the collision equal to each other:

p_system_before = p_system_after

870,000 g = 750,000 g + 120,000 g

870,000 g = 870,000 g

Dividing both sides by 870,000 g gives us:

v_after = 1

Therefore, the lead block is moving at a speed of 1 m/s after the bullet rebounds off of it. The correct answer is (c) -5 m/s.  

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Answer:

Displacement

Explanation:

Velocity is more like displacement because

Both have an arrow above their signs which indicates they are vectors.

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Answer:

d = 720 s

Explanation:

The question says, "A train initially traveling at 16m / s accelerates constantly at a rate of 2m / s2 in the same direction. How far will it travel in 20s?"

Initial speed, u = 16 m/s

Acceleration, a = 2m/s²

We need to find the distance covered by it in 20 seconds. Let the distance is d. Using the second equation of motion,

\(d=ut+\dfrac{1}{2}at^2\\\\d=16\times 20+\dfrac{1}{2}\times 2\times 20^2\\\\d=720\ m\)

So, it will cover 720 m in 20 seconds.

To determine the minimum speed that the motorcycle must have at the top of the loop to make it safely around, we need to consider the forces acting on the motorcycle at that point.

At the top of the loop, the motorcycle is experiencing two forces: the force of gravity pulling it downward and the normal force exerted by the track pushing it upward. The minimum speed required is when the normal force becomes zero, indicating that the motorcycle is just about to lose contact with the track.The net force acting on the motorcycle at the top of the loop is the centripetal force, which is given by:
F_net = m * (v^2 / r)
Where:F_net is the net force.m is the mass of the motorcycle (250 kg).v is the speed of the motorcycle.r is the radius of the circular track (12 m).At the top of the loop, the net force is the difference between the gravitational force and the normal force:
F_net = mg - N
Setting the net force equal to zero (N = 0), we can solve for the minimum speed:
mg = m * (v^2 / r)
Canceling out the mass:
g = v^2 / r
Solving for v:
v = √(g * r)
Plugging in the values:
v = √(9.8 m/s^2 * 12 m)
v ≈ √(117.6 m^2/s^2)
v ≈ 10.85 m/s
Therefore, the minimum speed that the motorcycle must have at the top of the loop to make it safely around is approximately 10.85 m/s.

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C

Let's see how

We know the rule

\(\\ \rm\rightarrowtail V=\dfrac{Kq}{r}\)

\(\\ \rm\rightarrowtail Kq=vr\)

\(\\ \rm\rightarrowtail q\propto r\)

As radius is same charge will be same in both

Hence they both have same charge

If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.

To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.

The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:

ds/dt = d/dt(2t + t²)

ds/dt = 2 + 2t

Now we can set the velocity function equal to 24 m/s and solve for t:

2 + 2t = 24

Subtracting 2 from both sides:

2t = 22

Dividing both sides by 2:

t = 11

Therefore, it takes 11 seconds for the velocity to reach 24 m/s.

The correct answer is (d) 11 seconds.

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According to the question The horizontal velocity of the body is greatest in value at mid-stance for running. the correct option is C

Walking and running are two different ways of travelling by foot, but there are some key differences between them. Running entails a period of time when both feet are in the air and a period of time when both feet are in contact with the ground. When one foot is in contact with the ground, walking always has at least one foot in contact with the ground, whereas running requires both feet to be off the ground for a portion of the stride cycle. These differences affect the way that force is applied to the body, particularly the legs and feet.

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Answer:its D

Explanation: but i think u meant to put not in the question but if u did mean to put not then its A

To further stretch the spring from l m to L m, the work done is given by W = 0.5k (L² - l²), where k is the spring constant and l and L are the initial and final lengths respectively.

Given, it requires a force of 18 N to hold a spring stretched l m beyond its natural length.Since the work done is equal to the change in potential energy, therefore, the work required to further stretch the spring from l m to L m is given by:

W = Uf - Ui

= 0.5 k L² - 0.5 k l²

Now, we have k = F / x where F is the force required to stretch the spring by a distance x.So,

k = 18 / l

Also, the force required to stretch the spring to length L is given by:

F' = k (L - l) = 18 (L - l) / l

Therefore, the work done is given by:

W = 0.5 k (L² - l²) = 0.5 x 18 / l x (L² - l²) = 9 (L² - l²) / l

Hence, the work done to further stretch the spring from l m to L m is 9 (L² - l²) / l J.

Therefore, the work required to stretch the spring from l m to L m is given by the equation: W = 9 (L² - l²) / l.

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Answer:

The speed of the comet at the surface of the star is approximately 1,208,694.7 m/s

Explanation:

Question parameter obtained online; The mass of the star, M = 5 × 10³¹ kg

Explanation;

The given mass of the comet, m = 2 × 10⁸ kg

The initial velocity of the comet, v → 0

The distance of the comet from the star, d = 700,000,000 km

The gravitational potential at d = G·M·m/d

The kinetic energy of the comet, K.E. = m·v²/2

The kinetic energy of the comet at d = m·(0)²/2 = 0

The gravitational potential at the surface of the star, R = G·M·m/R

The kinetic energy of the comet at the surface of the star, R = m·(v)²/2 = 0

Where;

M = The mass of the star = 5 × 10³¹ kg

\(M_{Sun}\) = The mass of the Sun = 1.989 × 10³⁰ kg

M/\(M_{Sun}\) = 5 × 10³¹/(1.989 × 10³⁰) ≈ 25

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

R = The radius of the star

Therefore, we have;

m·(0)²/2 - G·M·m/d = m·v²/2 - G·M·m/R

∴ v = √((G·M·m/R - G·M·m/d)×2/m) = √(2·G·M(1/R - 1/d))

Therefore; v = (2 × 6.67430 × 10⁻¹¹ × 5 × 10³¹ × (1/R - 1/700,000,000,000))

v = 81696389149.1×√(1/R - 1/700,000,000,000).

The speed of the comet at the surface of the star, v = 81696389149.1×√(1/R - 1/700,000,000,000)

The mass radius relationship is given as follows;

\(\dfrac{R}{R_{Sun}} = 1.30 \times \left(\dfrac{M}{M_{Sun}} \right)^{\dfrac{1}{2} }\)

\(R = R_{Sun} \times 1.30 \times \left(\dfrac{M}{M_{Sun}} \right)^{\dfrac{1}{2} }\)

The radius of the Sun = 696,340,000 M

∴ R ≈ 696,340,000 × 1.3 × √(25.14) = 4538865694.76

R = 4538865694.76 m

v = 81696389149.1×√(1/4538865694.76 - 1/700,000,000,000) ≈ 1208694.7  m/s

The solid cylinder reaches the bottom first.

A (solid) cylinder is a solid that has two parallel planes and a cylindrical surface surrounding it. An element of the cylinder is a line segment that is determined by an element of the cylindrical surface between two parallel planes. A cylinder's components are all the same length. The material's velocity would be higher if the moment of inertia was lower and the radius of gyration k was smaller. In comparison to a hollow cylinder with k as 1, a solid cylinder with k as 1/2 will move at a faster speed. Their energies at both levels, including potential energy and energy lost through friction, would stay the same because they had the same mass and radius.

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A solid cylinder and a hollow cylinder of the same mass and radius, both initially at rest, roll down the same inclined plane without slipping. Choose the correct options.

The solid cylinder reaches the bottom first.

A solid object will always roll down the ramp faster than a hollow object of the same shape regardless of their exact mass or diameter.

The solid cylinder has a lower moment of inertia than the hollow one does. Although they have the same mass, all the hollow cylinder's mass is concentrated around its outer edge so its moment of inertia is higher.

The velocity would be greater for the material with radius of gyration k is lower of for which the moment of inertia is lower. Solid cylinder with k as 1/2 will have greater velocity as compared to hollow cylinder which has k as 1. As they have same mass and radius their energies at both the levels would remains same including the potential energy and energy lost due to friction.

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Answer:

F = 0.414 N

Explanation:

Given that,

Magnetic flux density,\(B=3.6\times 10^{-2}\ T\)

The length of the wire, l = 24 m

Current, I = 0.48 A

We need to find the force acting on the wire. The formula for the force is given by:

\(F=ILB\)

Put all the values,

\(F=0.48\times 24\times 3.6\times 10^{-2}\\\\F=0.414\ N\)

So, the force acting on the copper wire is equal to 0.414 N.

The magnetic force of the copper wire is  41.472 N.

The magnetic force of the copper wire is calculated by applying the following equation.

F = BIL x sinθ

Where;

F = (3.6 x 10⁻²) x (48) x 24 x sin(90)

F = 41.472 N

Thus, the magnetic force of the copper wire is  41.472 N.

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The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Given data :

Tension in the ropes ( T ) = 2.28 N

Angle made by ropes = 13° vertical

F ( combined force ) = T + T

                                  = 2.28 + 2.28 = 4.56 N

from the question  13° vertical is approximately equal to 77° above the positive X-axis.

Therefore the  combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.

Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

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Answer:

Explanation:

The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Given data :

Tension in the ropes ( T ) = 2.28 N

Angle made by ropes = 13° vertical

Determine the combined force of the two ropes

F ( combined force ) = T + T

                                 = 2.28 + 2.28 = 4.56 N

from the question  13° vertical is approximately equal to 77° above the positive X-axis.

Therefore the  combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.

Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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During summer, the constellation Gemini is not visible in the night sky because it is obscured by the glare of the Sun.

Constellations are groups of stars that have been identified and named by humans based on their pattern in the night sky. The Zodiacal constellations are a group of 13 constellations that lie along the ecliptic, which is the path that the Sun appears to follow across the sky over the course of a year.

One of these Zodiacal constellations is Gemini, which is known for its distinctive twin-star pattern. In the northern hemisphere, Gemini is visible in the winter, but not in the summer. This is because the visibility of constellations is determined by the position of the Earth in its orbit around the Sun.

During the winter months, the Earth is on one side of the Sun and the Sun appears to be in the opposite direction in the sky. This means that the portion of the sky containing the Gemini constellation is visible at night. However, during the summer months, the Earth has moved to the other side of the Sun and the Sun appears to be in the same direction as the Gemini constellation. As a result, the constellation is not visible in the night sky because it is obscured by the glare of the Sun.

In summary, the visibility of constellations such as Gemini is determined by the position of the Earth in its orbit around the Sun. The changing position of the Earth relative to the Sun affects the portion of the sky that is visible at night and thus the visibility of particular constellations at different times of the year.

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Answer:That only applies to highly polished surfaces, eg mirrors.

If you take a high quality laser (ie with low divergence) and aim it at a wall, you can see the spot where the laser beam reaches the wall from anywhere with a direct line-of-sight to the spot where the laser beam reaches the wall. This due to micro imperfections on the surface of the wall. At a microscopic level, the wall surface is very rough and pointing in all directions.

As to why, a beam of light bounces of a highly polished surface, I can only surmise that it is essentially due to kinematics, ie the only force opposing the light beam is normal to the surface, hence there no forces along the reflective surface. Since there are no forces along the reflective surface, the speed component of light along the reflective surface remains unchanged. However, on the plane perpendicular to the reflective surface the, the light photons bounce off at the same speed at which the hit the reflective surface because the mass of the reflective surface is much much much larger than the mass of the photons, which means that the reflective surface won’t move at all. Since conservation of momentum requires that momentum after the collision be the same as the momentum before the collision then the only way for that to happen is if the velocity of the photon perpendicular to the reflective surface is of exactly the same magnitude but in the opposite direction. Vector resolution of the speed component of the reflected beam means that the angle of reflection must be the same as the angle of incidence.

Explanation:

\(

{\huge{\red{\boxed{\mathfrak{\blue{\underline{\blue{A}{\red{N}{\pink{S}{\orange{W}{\red{E}{\purple{R}}}}}}}}}}}}}\)

Levon Ter-Petrosyan won the majority of the votes and became the first president of independent Armenia.

Answer:

227 seconds.

Explanation:

Speed is equal to distance divided by time. s = d/t

We can rearrange this algebraically to solve for the time it will take to cover a certain distance at a certain speed. Time is equal to distance divided by speed.  t = d/s

Then we substiture our known values for the variables and solve for our unknown.

t = 454m / 2m/s = 227s

Answer:

If the lady is traveling 2 meters per second and she travels 454 meters then you will have to divide 454 by 2 to get the amount of time she walked.

454 divided by 2 = 227

This means that the lady traveled for 227 seconds or about 3.78 minutes.

Kickball, also known as soccer baseball or kick baseball, is a popular recreational game with origins dating back to the early 20th century. The invention of kickball is attributed to two individuals: Nicholas C. Seuss and Charles M. Strobel.

Nicholas C. Seuss was a playground supervisor in Cincinnati, Ohio, who introduced the game as "Kick Baseball" in 1917. He aimed to create a simplified version of baseball that was more accessible to children and required less equipment. The game quickly gained popularity on school playgrounds and in physical education classes.

Charles M. Strobel, a physical education specialist, also contributed to the development of kickball. In 1922, he published a book called "The Playground Book," which included rules and guidelines for playing kickball. His work helped standardize the game and promote it as an enjoyable and healthy outdoor activity for children.

In summary, Nicholas C. Seuss and Charles M. Strobel are credited with the invention of kickball. Their efforts in creating and promoting the game have led to its widespread popularity as a fun and engaging activity for people of all ages.

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By applying Newton's second law of motion, it is possible to establish an equation of motion for a mass attached to a spring. The traditional form of the equation of motion of a spring–mass system is called the "Nielsen form" in this context.

Provides the following motion equation:

m * d²x/dt² + k * x = 0

Where:

m is the mass of the object connected to the spring

x is the displacement of the object from its equilibrium position

t is time

k is the spring constant, which represents the stiffness of the spring

The inertial force (m * d²x/dt²) and the spring force (k * x) acting on the mass are balanced by this equation. The spring force is said to be in the opposite direction to the displacement when its sign is negative, which acts as a restoring force to move the mass back to its equilibrium position.

We can calculate the momentum of the mass-spring system with time by solving this second-order ordinary differential equation. The initial conditions, such as the initial displacement and velocity of the mass, affect the solution.

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The correct answer is 5.7 N

Given,

Mass of the box = 0.824 kg

Force on the right = 8.3 N

Force on the left = 2.6 N

Here, the horizontal force will be the net force.

Force is the product of mass of an object and the acceleration applied to it.

There are different forces acting on an object which are acting on different directions.

This is given by F = ma where m is the mass and 'a' is the acceleration.

The net force is the total force applied on that object.

The forces in the same direction will add up to give net force while the difference in the forces in different directions will be the net force.

Here, the forces are applied on the opposite directions (right and left)

Net force = Force on the right - Force on the left

Net force = 8.3 - 2.6 = 5.7 N

Therefore, we conclude that the net horizontal force on the box is 5.7 N.

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Answer:Speed is the time rate at which an object is moving along a path

Velocity is the rate and direction of an object's movement.

Explanation:

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One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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She is probably suffering from a major depression. Depression results in emotional change and loss of interest in previously appreciated activities.

Depression is a frequent and significant medical ailment that has an adverse effect on how you feel, think, and act. It can cause a number of mental and physical difficulties, as well as a loss in your ability.

According to epidemiological research, a hereditary element is involved in 30% to 40% of instances of bipolar illness. As a result, environmental influences have a larger role in the development of depression.

Maria's mother was deported 6 months ago, and she is staying with a cousin. She has to share a room with 3 other children and is very discouraged.

She has little energy to do much of anything, and she cries a lot, she is probably suffering from a major depression.]

Hence, option A is correct.

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ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

Answer:

A, flat water

Explanation:

The astronaut would indeed find it difficult to keep from being torn apart by these gravitational forces. f the mass within the head is distributed unevenly, the center of gravity may be shifted away from the center of mass.

(a) The tension between the astronaut's ears can be calculated using the equation for gravitational force, F = G(m1m2/r^2), where G is the gravitational constant, m1 and m2 are the masses of the objects (in this case, the astronaut's ears and the black hole), and r is the distance between them. The difference in distance between the two ears and the center of mass of the spacecraft is 0.06 meters. The gravitational force acting on the ear closer to the black hole is greater than the force acting on the ear farther away, creating a tension of 5.4 N between them. The astronaut would indeed find it difficult to keep from being torn apart by these gravitational forces.

(b) The center of gravity of the astronaut's head may not be at the same point as the center of mass because the position of the head may be affected by the distribution of mass within the head. The center of mass takes into account the mass distribution of the entire body, whereas the center of gravity only considers the gravitational forces acting on the body. Therefore, if the mass within the head is distributed unevenly, the center of gravity may be shifted away from the center of mass.

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Answer:

15000000 m

Explanation:

From the question,

Speed (S) = Distance(d)/Time(t)

S = d/t....................... Equation 1

Make d the subject of the equation

d = St..................... Equation 2

Given: S = 50 km/s = 50000 m/s, t = 5 minutes = 5*60 seconds = 300 seconds

Substitute these values into equation 2

d = 50000(300)

d = 15000000 m

Hence the skier travels 15000000 m