Answer:
\(\frac{-8}{27}\)
Step-by-step explanation:
\(\frac{-5}{9}\) - \(\frac{-7}{27}\) Subtracting a negative is the same as adding a positive. So I would change the form to addition.
\(\frac{-5}{9}\) + \(\frac{7}{27}\) Now to add, we need a common denominator. Let's us 27
\(\frac{-5}{9}\) = \(\frac{-15}{27}\) We multiple the numerator and denominator (top and bottom) by 3 to make an equivalent fraction.
\(\frac{-15}{27}\) + \(\frac{7}{27}\) the bottom number stays the same and we add the top numbers
-15 + 7 = -8
\(\frac{-8}{27}\)
Answer: -8/27
Step-by-step explanation:
\(\displaystyle\\-\frac{5}{9} -(-\frac{7}{27} )=\\\\-\frac{5*3}{9*3} +\frac{7}{27} =\\\\\frac{-15}{27}+\frac{7}{27}=\\\\ \frac{-15+7}{27}=\\\\ \frac{-8}{27} =\\\\-\frac{8}{27}\)
Give exact values, not decimal approximations. If the sum does not exist, click on "No sum". \((5) + (5) {}^{2} + (5) {}^{3} + ...\)
first
\(undefined\)A bag contains a total of 25 marbles for which the mean height is 16 grams. In the bag are yellow marbles, green marbles, and red marbles. Marbles of the same color are equal in weight. Each of the 12 yellow marbles weighs 10 grams ,and each of the 8 green marbles weighs 20 grams. What is the weight of each of the red marbles.
The weight of each red marble is 120/5= 24 grams.
The bag contains 25 marbles and the mean weight is 16 grams.
In the bag, there are yellow, green, and red marbles.
Let us suppose the number of red marbles is x, and let the weight of each red marble be y grams.
Hence the total weight of the bag is: y × x + 10 × 12 + 20 × 8 = 25 × 16
y × x = 25 × 16 - 10 × 12 - 20 × 8
y × x = 400 - 120 - 160
y × x = 120 grams
Therefore, the weight of each red marble is 120/x grams.
x is 25-12-8= 5
The weight of each red marble is 120/5= 24 grams.
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Find each product. All answers should be in simplest form.
The correct option for the given product is -7/15.
What are the rules for multiplying fraction?Multiplying fractions begins with the numerators being multiplied, followed by the denominators being multiplied.
When multiplying fractions, keep the following rules in mind:
Rule 1; It is to convert any mixed fractions to improper fractions. The numerators of a given fractions are then multiplied.Rule 2: Multiply this same denominators individually.Rule 3: Reduce the obtained value to its simplest term.The given expression is;
(-7/9) × (3/5)
First multiply the numerator part separately.
= (-7) × 3
= -21
Now, multiply the denominator part separately.
= 9 × 5
= 45
Now, write the obtained numerator and denominator in fraction;
= -21/ 45
As, this number is further divisible by 3.
Divide the numerator and denominator by 3.
= -7/15
Thus, the number obtained by the product as -7/15.
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Express the confidence interval 15.8% ± 5.4% in interval form.Answer using decimals rounded to three places, not as percentages
Okay, here we have this:
Considering the provided confidence interval we are going to express it in interval form, so we obtain the following:
So let's first convert the interval from percent to decimals:
Confidence interval=15.8% ± 5.4%
Confidence interval=0.158 ± 0.054
And the interval form will be obtained by leaving the result using the lesser on the left side, and the result using the more on the right side:
Confidence interval=[0.158-0.054, 0.158+0.054]
Confidence interval=[0.104, 0.212]
Finally we obtain that the confidence interval in interval form is equal to [0.104, 0.212].
Does anyone know the answer to this?
Answer:
\( \frac{a - 3}{a + 2} \)
Step-by-step explanation:
\( \frac{ {a}^{2} - 7a + 12 }{ {a}^{2} - 2a - 8} = \frac{(a - 3)(a - 4)}{(a + 2)(a - 4)} = \frac{a - 3}{a + 2} \)
use green's theorem to find the counterclockwise circulation and outward flux for the field f=(7x−4y)i (9y−4x)j and curve c: the square bounded by x=0, x=4, y=0, y=4.
The counterclockwise circulation around c is 12 and the outward flux through c is zero.
Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.
In this case,
we have a field f=(7x−4y)i+(9y−4x)j and
a square curve c bounded by x=0, x=4, y=0, y=4.
To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.
The curl of f is given by (0,0,3), so the line integral evaluates to 12.
To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.
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a rope passing through a capstan on a dock is attached to a boat offshore. the rope is pulled in at a constant rate of 6 ft/s and the capstan is 5 ft vertically above the water. how fast is the boat traveling when it is 12 ft from the dock?
Answer:The boat is traveling at a rate of 3 ft/s.
Step-by-step explanation:
Help plzz. Timeddd. Only right answers.
using the following integers in the order given, we can create a binary search tree. 4, 10, 12, 54, 19, 27, 7, 2 what is the value in the leftmost node in the right subtree of the root?
The value in the leftmost node in the right subtree of the root is 10.
To determine the value in the leftmost node in the right subtree of the root in the given binary search tree, we need to construct the tree using the given integers: 4, 10, 12, 54, 19, 27, 7, 2.
The binary search tree is constructed based on the property that all values in the left subtree of a node are less than the node's value, and all values in the right subtree are greater than the node's value.
Starting with the root node, which is 4, we construct the tree as follows:
4
/ \
2 10
\
12
\
19
\
27
\
54
The right subtree of the root contains the values 10, 12, 19, 27, and 54. The leftmost node in this subtree is 10.
Therefore, the value in the leftmost node in the right subtree of the root is 10.
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i neeeeeeeeeeeeeeeeeeed help
HEEEEELLLPPPPPPP!!!!!!!!!!!!!
Answer:
E. b + u = 21
Step-by-step explanation:
b = (bicycles)
u = (unicycles)
The Question gives you the answer.
" the number of bicycles plus the number of unicycles is 21"
*put as an equation*
b + u = 21
<3 Enjoy,
Dea
how many distinguishable ways are there to write $9$ as the sum of $1\text{'s},$ $2\text{'s},$ and $4\text{'s},$ where the order of the addends matters? for example, $4 4 1$ and $1 4 4$ are two different ways.
The required number of ways to write 9 as sum of 1, 2, 4 is 96 ways.
What is permutation?An arrangement of items in a specific order is referred to as a permutation. Here, the components of sets are arranged in a linear or sequential order. For instance, the set A=1,6 has a permutation of 2, which is 1,6,1.
According to question:Two fours and one one Three numbers must be added up. Any one of the three spaces will accept a one before fours are used to fill the remaining slots. There are thus 3 possible arrangements for these. Thus, there are
1 + 8 + 21 + 6 + 20 + 20 + 5 + 12 + 3 = 96 ways
Thus, there are 96 ways to write 9 as sum of 1, 2, 4.
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The intersection of plane R and plane P is
Point is not on plane P.
CE and De intersect at point
Answer:
The intersection of plane R and plane P is line DB.
Point H is not on plane P
CE and DB intersect at point D
Step-by-step explanation:
PLS, PLS, PLS HELP SO NEED IT PLEASE GUYS HELP, ANYONE!!!!!!!!!!!!!!!!!!!!!
Mean and median values for February are higher. This is because the data is skewed to the right and more flights arrive ahead of schedule. The values for February are more clustered on the right side of the graph, indicating late flight arrivals compared to January.
What are the responses to other questions?2) February appears to have a larger standard deviation and a larger interquartile range. February's data points are wider than February's, and the range of values is wider. This is reflected in the larger standard deviation and interquartile range.
3) As an airline owner, I am proud to share the January data with my customers. While January has slightly better average arrival times, February has better average arrival times and flights arrive late. Also, January data is less volatile than January, has a smaller standard deviation and narrower interquartile range. This shows that flights in January were consistently on time compared to February, which should be credited to the company.
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A map scale reads: 2 inches = 25 miles. Which distance does 6 inchos represent?
Answer:
75 miles.
Step-by-step explanation:
You can calculate this by calculating the number of times 2 fits into 6:
6 ÷ 2 = 3
3 x 25 = 75
So 75 miles.
Hope his helps!
Answer the photo below thanks
Answer: that is a rectangle
Step-by-step explanation:
Answer:
Rectangle , is correct answer of this question
The perimeter of a square field is 400 meters. How long is each side of the field?
Answer:
100m
Step-by-step explanation:
Perimeter of square = 4( sides ) = 400m
Let side = a
Therefore,
4a = 400
a = 400 / 4
a = 100m
Hope it helps!
The perimeter of a rectangle is 22cm. The area is 28cm squared, what are the length of the sides?
I just need to fill 20 characters, the answer is right there on the sheet
In a bag containing 4 yellow balls and 3 blue balls. 2 balls are drawn in a succession without replacement. Find The values of random variables. B where B represents the number of blue balls drawn
The above pic is your answer mate.
I need some help y'all hmu
Which equation matches y = 2x + 3
a) The cost of buying two shirts after a $3 discount
b) The total amount of money you make after spending $3 on
supplies and selling for $2 per item
c) The total height of a 3 inch tree after it grows 2 inches per
month.
d) The amount of money in your bank account if you started
with $2 and make $3 per day.
The equation y=2x+3 matches the total height of a 3-inch tree after it grows 2 inches per month.
We have given, y=2x+3
We have to determine whether the equation matches y=2x+3.
What is the slope-intercept form?
The slope-intercept form of the line is y=mx+c.
Where m is the slope
C=y-intercept
Therefore option c is correct.
because the height is three inches and the tree after it grows 2 inches per month.
The slope of a line is a measure of its steepness.
Here the slope is 2 and the y-intercept is 3.
Therefore option c is correct.
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determine the common factors and HCF for each of the following terms
1) Зw, 5w
2)5bc ,2c², 3cd
3)4a² b, 8b² c ,6bcd
PLS HELP
1) For the term 3w, 5w, the HCF is "w" since it is common for both terms
2) For the terms 5bc ,2c², 3cd, the only common term is "c" hence the HCF of the terms will be "c"
3) For the set 4a² b, 8b² c ,6bcd, the HCF of the term is 2 since that is the only common value of the terms.
Common factors and HCF of valuesThe HCF is the smallest value that can divide a set of values without leaving a remainder.
Given the following terms, we are to find their HCF's
1) For the term 3w, 5w, the HCF is "w" since it is common for both terms
2) For the terms 5bc ,2c², 3cd, the only common term is "c" hence the HCF of the terms will be "c"
3) For the set 4a² b, 8b² c ,6bcd, the HCF of the term is 2 since that is the only common value of the terms.
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Segment PQ has endpoints P(-3, 4) and
Q(1, 7). Find the midpoint and length of
the segment.
-2
Mid point of the length segment PQ has endpoints P(-3, 4) and
Q(1, 7) is (1,11/2).
Mid point = {(-3+1)/2, (4+7)/2}
Mid point = (1,11/2)
The midpoint of a line segment is known as the midpoint in geometry. It is the centroid of the segment and of the endpoints, and it is equally distant from both of them. It cuts the section in half.
A line is said to be a bisector when it divides another line into two identical segments. The line will be split at its midpoint by the bisector. A compass and straightedge can be used to determine the midpoint of a line segment. See creating a line segment's perpendicular bisector.
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Evaluate 11.5x + 10.9y when x = 6 and y =7
The value of the algebraic expression 11.5x + 10.9y at x = 6 and y = 7 is 145.3
What is an algebraic expression?
Algebraic expression consists of variables and numbers connected with addition, subtraction, multiplication and division
The given algebraic expression is 11.5x + 10.9y
We have to find the value of the algebraic expression at x = 6 and y = 7
Putting x = 6 and y = 7 in the algebraic expression,
\(11.5 \times 6 + 10.9 \times 7\)
69 + 76.3
145.3
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\( \frac{15}{100} \times 115\)
Answer:
3/5
Step-by-step explanation:
A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a.
The radial distances from the center (-3, -2), to the points on the circumference (0, -6), and (a, 0), found using the distance formula, indicates that a = -3 ± √21
What is the distance formula for finding the distance between locations on the coordinate plane?The distance between points (x₁, y₁), and (x₂, y₂), on the coordinate plane, can be found using the formula; d = √((x₂ - x₁)² + (y₂ - y₁)²).
The coordinates of the center of the circle = (-3, -2)
The coordinates of the locations (on the circumference of the circle), through which the circle passes = (0, -6) and (a, 0)
Therefore the distances between points (0, -6) and (-3, -2) and (a, 0) and (-3, -2) are the same;
The distance from (0, -6) to (-3, -2) = The distance from (a, 0) to (-3, -2)
(-3 - 0)² + (-2 - (-6))² = (-3 - a)² + (-2 - 0)²
25 = a² + 6·a + 9 + 4 = a² + 6·a + 13
a² + 6·a + 13 = 25 (symmetric property)
a² + 6·a + 13 - 25 = 0
a² + 6·a - 12 = 0
a = (-6 ± √(6² - 4×1×(-12)))/(2×1) = (-6 ± √(84))/2
a = (-3 ± √(21))
a ≈ 1.58 and a ≈ -7.58
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NEED HELP ASAP!!! PLSSSSSSSSSSSSSSSSSSSS
Answer:
score(3)
Step-by-step explanation:
If the score is a function of the hours studied, it depends on the number of hours spent studying.
score(hours studying)
score(3)
Find the value of each trigonometric ratio. Express your answer as a fraction in lowest terms.
The value of the trigonometric ratios are
1. sin C = 21/29
2. sin C = 3/5
3. cos C = 12/13
4. cos C = 8/17
5. tan A = 12/35
6. tan X = 4/3
How to find the trigonometric ratiosThe trigonometry problem in a triangle is worked using an acronym SOH CAH TOA, this acronym means:
Sin = opposite / hypotenuse - SOH
Cos = adjacent / hypotenuse - CAH
Tan = opposite / adjacent - TOA
1. sin C
sin C = opposite / hypotenuse = 21/29
3. cos C = 12/13
cos C = adjacent / hypotenuse = 36/39 = 12/13 to the lowest term
6. tan X = 4/3
tan X = opposite / adjacent = 36/27 = 4/3 to the lowest term
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I need to find the value of s. Could you help me please?? At the end it says (s-1) it's just really blurry.
From the figure we notice that the two bottom angles are equal. We also know that the angle DXG is equal to 98, then we have that:
\((4s-2)+(s-1)+(s-1)=98\)solving for s we have:
\(\begin{gathered} (4s-2)+(s-1)+(s-1)=98 \\ 6s-4=98 \\ 6s=98+4 \\ 6s=102 \\ s=\frac{102}{6} \\ s=17 \end{gathered}\)Therefore s=17
diamond and trevor both have a six-sided dice. the sides of their dice are displayed below: assuming that their dice are both fair (equally likely to land on each side). find the theoretical probability of rolling each value. write your answers as percentage correct to two decimal places. % % % when diamond rolls her dice 1280 times, she rolls a one 217 times, a two 425 times, and a three 638 times. find the experimental probability of rolling each value. % % % based on the law of large numbers, could you reasonably assume that the dice diamond has is a fair dice (equally likely to land on each side)? no yes when trevor rolls his dice 1280 times, he rolls a one 888 times, a two 313 times, and a three 79 times. find the experimental probability of rolling each value. % % % based on the law of large numbers, could you reasonably assume that the dice trevor has is a fair dice (equally likely to land on each side)? no yes
A. Theoretical probability of rolling each value for both Diamond and Trevor is 16.67%.
The experimental probability of rolling each value for Diamond is 16.95% for one, 33.20% for two, and 49.84% for three.
The experimental probability of rolling each value for Trevor is 69.38% for one, 24.45% for two, and 6.17% for three. Based on the Law of Large Numbers, Diamond's dice can be assumed to be fair, but Trevor's dice cannot be assumed to be fair.
The theoretical probability of rolling each value for both Diamond and Trevor is 1/6 or 16.67%. To find the experimental probability for Diamond, we divide the number of times each value was rolled by the total number of rolls and multiply by 100%. For example, the experimental probability of rolling one is (217/1280) x 100% = 16.95%.
Based on the Law of Large Numbers, which states that the sample mean will approach the population mean as the sample size increases, we can reasonably assume that Diamond's dice is fair.
However, Trevor's dice cannot be assumed to be fair because the experimental probability of rolling each value is significantly different from the theoretical probability, indicating a potential bias in the dice.
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