5One end of a wire is attached to a ceiling, and a solid brass ball is tied to the lower end. The tension in the wire is 120 N. What is the radius of the brass ball?​

Answer:

Explanation:

Unfortunately, as an AI text-based model, I cannot directly view or interpret images. However, I can still provide you with the information you need to identify Polaris and its position in the night sky.

To locate Polaris using the stars of the Big Dipper (also known as the Great Dipper or Ursa Major), you can follow these steps:

1. Locate the Big Dipper: The Big Dipper is a prominent asterism, or a recognizable pattern of stars, within the constellation Ursa Major (the Great Bear). It is visible in the northern hemisphere during most of the year.

2. Identify the pointer stars: The two stars on the outer edge of the Big Dipper's bowl, farthest from the handle, are called the pointer stars. These stars are named Dubhe and Merak.

3. Extend the line between the pointer stars: Mentally extend an imaginary line that passes through Dubhe and Merak, extending it for approximately five times the distance between the pointer stars.

4. Locate Polaris: The extended line will lead you to Polaris, also known as the North Star. Polaris is relatively bright and appears as the last star in the handle of the Little Dipper (Ursa Minor constellation). It lies almost directly above the North Pole of the Earth and remains nearly fixed in the sky while other stars appear to rotate around it as the Earth rotates.

By following these steps, you should be able to identify Polaris and its position in the night sky, even without an image.

Polaris is positioned directly above the celestial North Pole in the sky, making it a useful navigation tool. The easiest way to locate it is by identifying the Great Dipper constellation and using its two pointer stars, Dubhe and Merak, to lead to the North Star.

The star Polaris, also known as the North Star, is beneficial for navigation due to its fixed position in the sky above the celestial North Pole. The best way to locate it is by first finding the Great Dipper constellation. Two stars in the bowl of this Dipper, named Dubhe and Merak, form a line that leads directly to Polaris.

In the given image, without the benefit of visual reference, it is difficult to identify the specific position of Polaris. However, remember that in actual practice, you would find the two pointer stars of the Great Dipper and follow a line from these stars to locate Polaris.

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Answer:

which items are matter?

battery , mobile phone

Answer:

Unit of precision for force is the Newton.

Explanation:

It is the official unit used to describe force in science and mostly abbreviated with the symbol N.

Answer:

dvhd

Explanation:

xhxjjdvcbxhjddvifidid

Answer:

The units of frequency are called hertz (Hz). Humans with normal hearing can hear sounds between 20 Hz and 20,000 Hz. Frequencies above 20,000 Hz are known as ultrasound

Answer:

\(\huge\boxed{\sf Average\ speed = 16\ km/hr}\)

Explanation:

Given:

Distance = S = 8 km

Time = t = 30 minutes = 30/60 = 0.5 hours

Required:

Average Speed = ?

Formula:

Average speed = total distance covered / total time taken

Solution:

Average Speed = 8 / 0.5

Average speed = 16 km/hr

\(\rule[225]{225}{2}\)

Hope this helped!

Harry cycles 8 kilometers in 30 minutes and the Harry's average speed obtained is 6 kilometers per hour.

Given:

Total distance covered by the Harry= 8 kilometers

Total time is taken by the Harry= 30 minutes

Convert total time to hours, the total time taken is obtained as:

Total time (hours) = 30 minutes / 60 minutes/hour = 0.5 hours

The average speed of the Harry is given by:

Average speed = Total distance / Total time

Average speed = 8 km / 0.5 hours

Average speed = 16 km/h

Therefore, Harry's average speed is 16 kilometers per hour when Harry cycles 8 kilometers in 30 minutes.

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Just before the collision, the ball has a velocity of 9.3 m/s, downward. After the collision, the ball has a velocity of 6.2 m/s, upward.

To solve this problem, we can analyze the motion of the ball and block before and after the collision using the principles of conservation of energy and momentum. Since the collision is elastic, the total kinetic energy of the system is conserved. The ball has gravitational potential energy before the collision, which is converted to kinetic energy as it falls.

The block has no kinetic energy before the collision, but gains some after the collision due to the transfer of momentum from the ball. By equating the total kinetic energy before and after the collision and using the principle of conservation of momentum, we can solve for the velocities of the ball and block.

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Answer and Explanation:

Your mass will always stay the same, the same as it is on Earth.

It is your weight that changes, which is why you would jump higher on the moon and on mars. You would have a decrease in weight, allowing you to jump higher and stay in the air longer.

#teamtrees #PAW (Plant And Water)

The number of turns determines the strength; whether the core is made of soft or hard magnetic material. Soft iron is more easily magnetized than steel. As a result, using a soft core increases the electromagnet's strength.

The magnetic field is mathematically described as a vector field. This vector field can be directly plotted as a grid of many vectors. Each vector points in the same direction as a compass and has a length proportional to the strength of the magnetic force. This technique is demonstrated by arranging many small compasses in a grid pattern and placing the grid in a magnetic field. The only difference is that a compass does not indicate field strength. Field lines are another way to represent the information contained within a vector field. We remove the grid pattern and connect the vectors with smooth lines. We are free to draw as many lines as we want.

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Answer:

B. Boats need to float.

Answer:

from

velocity= displacement/time

then

time=displacement/velocity

time= 4200/70

time=60s

time will take 60seconds

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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The correct answer is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.

The geocentric model, which placed Earth at the center of the universe with the Sun, Moon, and stars revolving around it, was widely accepted until the 16th century for several reasons. One of the primary reasons was that observations seemed to support this view. For example, it was observed that the stars appeared to move across the sky in a circular path, and it was assumed that this was due to their motion around Earth. Similarly, the Sun and Moon appeared to rise and set each day, which was consistent with their motion around Earth.

The geocentric model was consistent with the prevailing philosophical and religious beliefs of the time, which held that Earth was a special and unique place at the center of the universe. It was not until the development of the heliocentric model, which placed the Sun at the center of the solar system, and the refinement of astronomical observations, that the geocentric model was gradually abandoned.
The correct option is B. Observations had led to the belief that the Sun, Moon, and stars revolved around Earth.

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The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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Answer: Mass= 13.6 kg

Explanation:

F = m * a

34 = m (2.5)

m = 34 / 2.5

m = 13.6 kg

Let's see

\(\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)\)

Now we know the formula of acceleration

\(\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)\)

\(\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2\)

\(\\ \rm\Rrightarrow \alpha=-x\omega^2\)

Or

\(\\ \rm\Rrightarrow \alpha=-\omega^2x\)

Given that the position x of a particle along X-axis varies with time t by the equation:

\({:\implies \quad \sf x=A\sin (\omega t)}\)

As it defines the position, so x is just displacement here, and we need to find the acceleration first for telling with what if varies, so by definition, the second differential coefficient of displacement is acceleration, so differentiating both sides w.r.t.x of the above equation in accordance with chain rule we have:

\({:\implies \quad \sf \dfrac{dx}{dt}=A\cos (\omega t)\cdot \omega \cdot \dfrac{dt}{dt}}\)

\({:\implies \quad \sf \dfrac{dx}{dt}=A\omega \cos (\omega t)}\)

Differentiating both sides w.r.t.x by chain rule again to get the 2nd order derivative

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega \sin (\omega t)\cdot \omega \dfrac{dt}{dt}}\)

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega^{2}\sin (\omega t)}\)

Re-write as :

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-\omega^{2}\{A\sin (\omega t)\}}\)

Can be further written as

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-x\omega^{2}}\)

This is the Required answer

If they ask you the differential equation for the acceleration of a wave (as the given equation was general equation of a wave), you can simply write:

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}+x\omega^{2}=0}\)

We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.

The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.

The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.

The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.

The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.

The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.

The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.

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Answer:

The  time elapsed at the spacecraft’s frame is less that the time elapsed at earth's  frame

Explanation:

From the question we are told that

The distance between earth and Retah is  \(d = 20 \ light \ hours = 20 * 3600 * c = 72000c \ m\)

Here c is the peed of light with value \(c = 3.0*10^8 m/s\)

The time taken to reach Retah from earth is  \(t = 25 \ hours = 25 * 3600 =90000 \ sec\)

The velocity of the spacecraft is mathematically evaluated  as

     \(v_s = \frac{d }{t}\)

substituting values

   \(v_s = \frac{72000 * 3.0*10^{8} }{90000}\)

    \(v_s = 2.40*10^{8} \ m/s\)

The time elapsed in the spacecraft’s frame is mathematically evaluated as

      \(T = t * \sqrt{ 1 - \frac{v^2}{c^2} }\)

substituting value

       \(T = 90000 * \sqrt{ 1 - \frac{[2.4*10^{8}]^2}{[3.0*10^{8}]^2} }\)

        \(T = 54000 \ s\)

=>    \(T = 15 \ hours\)

So  The  time elapsed at the spacecraft’s frame is less that the time elapsed at earth's  frame

Answer:

-1.57 m/²

Explanation:

The equation is

v = u + at

where v = final velocity, u = initial velocity, a = acceleration, t = time

We can manipulate the final velocity equation to get

a = (v - u)/t

Final velocity v = 0, u = 17.3 m/s, t = 11s

a = (0 - 17.3)/11 = -17.3/11 = -1.57 m/²

Negative value means it is deceleration since speed is decreasing

The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:

Potential energy (PE) = mass (m) × gravity (g) × height (h)

Where:

m = 2.5 kg (mass of the object)

g = 9.8 m/s² (acceleration due to gravity on Earth)

h = ? (height)

First, let's find the height (h) by rearranging the formula:

h = PE / (m × g)

Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):

Energy (E) = power (P) × time (t)

E = 0.20 kW × 1 min × 3,600 J/kW

Now, we can substitute the values into the equation to find the height:

h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)

Calculating the expression on the right side:

h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)

Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

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The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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The additional information needed to calculate the acceleration of the motorcycle is the time taken to complete the distance.

Acceleration is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).

The acceleration of a moving body can be calculated by dividing the change in velocity of the motion (∆V) by the time taken to complete the motion as follows:

Acceleration (m/s²) = change in velocity (m/s)/time(s)

According to this question, a motorcyclist is traveling in the positive direction at a velocity of 7.0 meters per second. She then increases her velocity to 9.0 meters per second. This means that the change in velocity {∆V} is 2m/s.

However, the time taken to complete the distance is still required to compute the acceleration of the motorcycle.

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Since focal length cannot be negative for a converging lens, we take the positive value: f ≈ 41 cm Option C

To determine the focal length of the lens, we can use the lens formula, which relates the object distance (u), image distance (v), and focal length (f) of a lens. The lens formula is given by:

1/f = 1/v - 1/u

In this case, the object distance (u) is 25 cm and the image distance (v) is 64 cm. We can substitute these values into the lens formula to solve for the focal length:

1/f = 1/v - 1/u

1/f = 1/64 cm - 1/25 cm

To simplify the equation, we can find a common denominator:

1/f = (25 - 64) / (64 * 25)

1/f = -39 / (64 * 25)

Now, we can invert both sides of the equation to solve for the focal length:

f = (64 * 25) / -39

f ≈ -41.03 cm

Since focal length cannot be negative for a converging lens, we take the positive value:

f ≈ 41 cm

Therefore, the correct answer is option C) 41 cm.

It's important to note that in the lens formula, distances are measured with respect to the lens, with positive values indicating distances on the opposite side of the incident light. The negative value obtained for the focal length indicates that the lens is a converging lens, as expected. Option C

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Answer:

Acceleration

Explanation:

Answer: Acceleration

Explanation:

Answer:

C) The force experienced by the ball equals the force experienced by the club.

Explanation:

When the golfer strikes the ball with his club, the club exerts a force on the ball. Due to Newton's Third Law Of Motion [Every Action has an equal and opposite reaction], the ball also exerts an equal force on the club. However,

As the mass of the club is usually greater than the mass of the ball, it accelerates slower; While the ball way faster, following the equation : F=ma

Answer:

1) rate of motion

Explanation:

Speed is the rate of motion. Whereas velocity is the rate and direction of motion.

Answer:

rate of motion is the correct answer because the rate is the speed in wich you are moving

Answer:

wind orosion is the correct answer dkr this