6/5? Could anyone help me I've been stuck on it for a while. 6 over 5 how do I didvide this and get a ratio?

Answer:

Step-by-step explanation:

x+60=140

x=140-60

x=80 degree

Answer:

bruh i need too see the lines send the lines lol

Step-by-step explanation:

Answer:  Please show the lines:)

Answer:

b

Step-by-step explanation:

every cantaloup costs $3 so they would pay x × $3

but they got a $2 coupon so you have to deduct that.

Answer:

One side length is 17. Because you square root 289 to figure out the side length.

Step-by-step explanation:

The area of a square is a side length * a side length

or l^2 = 289

sqrt or 289 = 17

Answer:8/3

Step-by-step explanation:divide both sides by -3 2 negative make a positive add 2 to both sides simplify 2/3 +2 to 8/3

Answer:

The answer is

\( \huge \boxed{k = \frac{8}{3} } \\ \)

Step-by-step explanation:

\(−3(k − 2) = −2 \)

Expand the terms in the bracket

That's

\( - 3k + 6 = - 2\)

Subtract 6 from both sides of the equation

We have

\( - 3k + 6 - 6 = - 2 - 6 \\ - 3k = - 8\)

Divide both sides by - 3

\( \frac{ - 3k}{ - 3} = \frac{ - 8}{ - 3} \\ \)

We have the final answer as

\(k = \frac{8}{3} \\ \)

Hope this helps you

Translate the sentence into an inequality.



The sum of a number times 10 and 26 is at least -16.



Use the variable w for the unknown number.​

In this problem

at least means -----> greater than or equal to

so

The steps in determining the area of the shaded part of a circle include;

The area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.

1) The formula for area of a sector of a circle is;

A = (θ/360) * πr²

where πr² is area of circle

θ is the angle subtended by the sector

Thus, we conclude that the area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.

2) The area of the triangle formed as part of the segment is subtracted from from the area of the sector.

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When we have a normal model for the sampling distribution, we cannot say that a sample mean or sample proportion is approximately 2 standard errors (ses) away from the population mean or the true proportion.

Instead, we can say that 95% of the sample proportions fall within two standard errors of the population proportion. Similar to this, the percentage of sample proportions decreases as the standard error distance decreases and increases as the standard error distance increases.

Therefore, the standard error distance will be greater than 2 standard errors (ses) if 99% of the sample proportions are within a given standard error distance of the population proportion.

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Answer:

Its B!

Step-by-step explanation:

Just passed on edge 2020

The interval between which the sales of the Marcus were constant was (0, 5) to (5, 6) and (5, 6) to (6, 12)

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Given, Marcus tracked the changes in his sales over a 12- month period.

we need to find at which interval was the change in Marcus's sales constant.

First we need to plot the graph, the points given to us will show us the sale of Marcus from the beginning to the end.

The rapid increment is  in the number of sales for that period of time is  (0, 4) and (0, 5) as we can see a straight line.

Line between point (0, 5) and (5, 6), there is a slant line therefore, which shows that were slow and constant growth in the sale of Marcus as the line is increasing upwards.

The line between the points (5, 6) and (6, 12) is also a slant line but the slope of the line is high than the previous line for points  (0, 5) and (5, 6).

Constant growth between these two points and this growth was also constant but it was more rapid as compared to sales between the point (0, 5) and (5, 6).

Therefore the interval between which the sales of the Marcus were constant was (0, 5) to (5, 6) and (5, 6) to (6, 12)

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The volume of the stucture made from three rectangular prism is 4080 ft³

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of the rectangular prism = length * width * height = 12 * 10 * 5 = 600 ft³

The volume of the other prism = length * width * height = 10 * 8 * 36 = 2880 ft³

Volume of the structure = 600 ft³ + 600 ft³ + 2880 ft³ = 4080 ft³

The volume of the stucture made from three rectangular prism is 4080 ft³

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The answer as a fraction in simplest form is 1 39916800.

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

The formula of probability is defined as the ratio of a number of favorable outcomes to the total number of outcomes.

P(E) = Number of favorable outcomes / total number of outcomes

We are given that;

n = 12 and r = 7,

so the number of possible outcomes is:

12 P 7 = 12! ( 12 − 7)! = 12! 5! = 39916800

The number of favorable outcomes is only one, since there is only one way to select the paintings in the same order as the artist displays them. Therefore, the probability of selecting the paintings in the same order as the artist displays them on the first day is:

P ( event) = number of favorable outcomes number of possible outcomes = 1 39916800

This fraction cannot be simplified further, so this is the final answer. The probability is very small, which makes sense because it is very unlikely to randomly select 7 paintings in the same order as the artist displays them.

Therefore, by probability the solution will be 1 39916800.

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Answer and Step-by-step explanation:

Okay, we are given a number, n, which is then added to 15 less than 3 times itself.

Let's break this apart.

n will be added to (+) 15 less (-) than 3 times itself (x)

3 times itself would be 3n, and 15 less than 3 times itself (3n) would be 3n - 15.

n is added to this value: n + 3n - 15 = 4n - 15

Now we need to put this into an equation, where the expression we created will be equal to a number, which is given to be 101.

4n - 15 = 101  <-- This is the equation that would be used to find the value of n.

I hope this helps!
#teamtrees #PAW (Plant And Water)

Answer:

Step-by-step explanation:

It is non-linear. A linear function can be written in the form y = mx + b

The equation that represents the slope-intercept form of the given graph is y = x + 4.

The slope-intercept form of a linear equation is an equation that is written or expressed in the form y = mx + b. In this situation, m is the slope of the line, and b is the y-intercept, which is the point where the line crosses the y-axis.

Now, if we have two coordinate points, (-1,3), (0,4). We need to first determine the slope of the graph.

Slope = change in the y-axis/change in x-axis

Slope = y_2 - y_1/ x_2 - x_1

Slope = 4 - 3/ 0- - 1

Slope = 1/ 1

Slope = 1

y-intercept  = 4

Thus, in form of y = mx + b, the slope-intercept form of the linear equation can be written as y = x + 4

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Answer:

\(12x -6\)

Step-by-step explanation:

Take a look at the attachment...

Hope this helps! :)

the NPV of the ambulance, rounded to the nearest dollar, is approximately $10,731. Option b

To calculate the NPV (Net Present Value) of the ambulance, we need to determine the present value of the net cash flows over the five-year period.

The formula for calculating NPV is:

NPV = (Cash Flow / (1 + r)^t) - Initial Investment

Where:

Cash Flow is the net cash flow in each period

r is the required rate of return

t is the time period

Initial Investment is the initial cost of the investment

In this case, the net cash flow per year is $50,000, the required rate of return is 9%, and the initial cost of the ambulance is $200,000.

Using the formula, we calculate the present value of each year's cash flow and subtract the initial investment:

NPV =\((50,000 / (1 + 0.09)^1) + (50,000 / (1 + 0.09)^2) + (50,000 / (1 + 0.09)^3) + (50,000 / (1 + 0.09)^4) + (75,000 / (1 + 0.09)^5) - 200,000\)

Simplifying the equation, we find:

NPV ≈ 10,731

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Answer:

The answer is, A. it is constant

Step-by-step explanation:

Between the x values 4 and 8 the line does not decrease or increase. It stays in a straight line causing it to be constant.

Answer: Its constant ( constant means it isnt moving like its just stable)

Answer:

1/3

Step-by-step explanation:

Answer:

3:1

Step-by-step explanation:

\(\frac{9}{3}\) --> \(\frac{3}{1}\) or simply 3:1

Answer:

Sep-by-step explanation:I=(200×8×9)/100

=144

Answer:

p=200

r=9

t=8

I=p×t×r/100

=200×9×8/100

=144

hope it helps you

make me brainliest plz

The percent probability that the item is bound as a paper pad is 68%.

The probability that a graph paper item selected at random is bound as a paper pad can be found as follows:First, the total number of graph paper items should be determined.

There are 60 graph spiral notebooks and 125 graph paper pads, for a total of 60 + 125 = 185 graph paper items.

Next, the number of graph paper items that are bound as paper pads should be determined.

There are 125 graph paper pads, so the probability of selecting a graph paper item that is bound as a paper pad is:125 / 185 = 0.68 (rounded to two decimal places)

Therefore, the percent probability that the item is bound as a paper pad is 68%.

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Step-by-step explanation:

8x + 32 = 12x +19

4x = 13

x = 3.25

The significance level of 0.05, the data do not provide convincing statistical evidence to support Jenna's claim that the average texting time at her high school is greater than 94 minutes.

(i) Jenna's population of interest would be all the students at her large high school.

(ii) Jenna could use a simple random sampling method to select her sample of size 32. In this method, each student in the population has an equal chance of being selected for the sample.

Jenna can assign a unique identification number to each student, use a random number generator to select 32 numbers corresponding to the student IDs, and then include the students with those IDs in her sample.

To determine whether the data provide convincing statistical evidence to support Jenna's claim, we can perform a hypothesis test.

The null hypothesis (H0) would be that the average texting time at Jenna's high school is equal to or less than 94 minutes, while the alternative hypothesis (Ha) would be that the average texting time is greater than 94 minutes.

H0:  ≤ 94 (population mean is less than or equal to 94)

Ha:  > 94 (population mean is greater than 94)

Given the sample mean  of 96.5 minutes and the sample standard deviation (s) of 6.3 minutes, we can calculate the test statistic, which follows a t-distribution because the population standard deviation is unknown and we are working with a small sample size (n = 32).

The test statistic can be calculated using the formula:

t = ( - ) / (s / √n)

Plugging in the values:

t = (96.5 - 94) / (6.3 / √32) ≈ 1.652

Using a significance level (α) of 0.05 and degrees of freedom (df) of n - 1 = 32 - 1 = 31, we can find the critical t-value. In this case, the critical t-value corresponds to the upper tail since we are testing if the population mean is greater than 94.

Comparing the test statistic to the critical t-value, if the test statistic is greater than the critical t-value, we reject the null hypothesis; otherwise, we fail to reject the null hypothesis.

Based on the t-distribution table or a statistical software, the critical t-value for a one-tailed test with α = 0.05 and df = 31 is approximately 1.697.

Since the test statistic (1.652) is less than the critical t-value (1.697), we fail to reject the null hypothesis.

Therefore, at the significance level of 0.05, the data do not provide convincing statistical evidence to support Jenna's claim that the average texting time at her high school is greater than 94 minutes.

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Step-by-step explanation:

9(x + 7)² divided by 3(x - 1)(x + 7)

= 3(x + 7)/(x - 1).

The statement that is true about the graph as it relates the unit rate is:

d. The unit rate is $22.50 per hour

Unit rate of a relationship between two variables, x and y, that are proportionally related can be found using k = y/x, where k is the unit rate.

Given that:

x = hours he worked

y = his total earnings

We are told that (4, 90) is a point on the graph.

Using the point, (4, 90), we can find the unit rate as shown below:

k = y/x = 90/4

k = 22.5

Therefore, the statement that is true about the graph as it relates the unit rate is:

d. The unit rate is $22.50 per hour

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The amount that will accumulate by the end of the sixth and final payment is approximately $41,666.60.

To calculate the accumulated amount by the end of the sixth and final payment, we can use the future value of an ordinary annuity formula:

Future Value = Payment × Future Value of an Ordinary Annuity Factor

The payment is $5,800, and the interest rate is 9%. Since the payments are made at the end of each year, we can use the future value table for an ordinary annuity at 9%.

Looking up the factor for 6 years at 9% in the future value table, we find it to be 7.169858.

Now we can calculate the accumulated amount:

Future Value = $5,800 × 7.169858 = $41,666.60

Therefore, the amount that will accumulate by the end of the sixth and final payment is approximately $41,666.60. The correct answer is not among the options provided.

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In the initial list, there were 4 integers.

We have the following system if the mean is m, x is the list's initial sum, and n is the number of integers in the list:

m = x/n , m + 2 = (x + 15) / (n + 1) and m + 1 = (x + 16) / (n + 2).

The initial equation is x = mn.

Therefore, changing x in the other two equations:

m + 2 = (mn + 15) / (n + 1) ..............(1)

m + 1 = (mn + 16) / (n + 2)...............(2)

Based on equation (1):

(m + 2)(n + 1) =  mn + 15

mn + m + 2n + 2 = mn + 15

m + 2n + 2  = 15

m + 2n = 13

m = 13 - 2n.

Now change m in equation (2) to:

13 - 2n + 1 = ( n(13 - 2n) + 16) / (n + 2)

14 - 2n = (13n - 2n^2 + 16) / (n + 2)   Through-multiplication by n + 2:

(14 - 2n)(n + 2) =  13n - 2n^2 + 16

14n + 28 - 2n^2 - 4n =  13n - 2n^2 + 16

10n + 28 = 13n + 16

12 = 3n

n = 4.

Hence, there were 4 integers in the original list.

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Answer: Part a) The fraction of all of the baked goods at Laurita’s Bakery that are coconut pies is 1/5

Part b) The fraction of all of the baked goods at Laurita’s Bakery that are angel food cakes is 1/15

Step-by-step explanation:

Let

x -----> the total number of baked goods

we know that

1) 3/5 of the baked goods are pies and the rest are cakes

To obtain the number of pies multiply the total number of baked goods by 3/5

The number of pies is ----> (3/5)x

To obtain the number of cakes subtract the number of pies from the total number of baked goods

The number of cakes is -----> x-(3/5)x=(2/5)x

2) 1/3 of the pies are coconut

To obtain the number of coconut pies multiply the number of pies by 1/3

The number of coconut pies is -----> (3/5)x(1/3)=(3/15)x=(1/5)x

3) 1/6 of the cakes are angel food

To obtain the number of angel food cakes multiply the number of cakes by 1/6

The number of angel food cakes is -----> (2/5)x(1/6)=(2/30)x=(1/15)x

Part a) What fraction of all of the baked goods at Laurita’s Bakery are coconut pies?

we know that

The number of coconut pies is (1/5)x (see Part 2)

Divide the number of coconut pies by  the total number of baked goods

therefore

The fraction of all of the baked goods at Laurita’s Bakery that are coconut pies is 1/5

Part b) What fraction of all of the baked goods at Laurita’s Bakery are angel food cakes?

we know that

The number of angel food cakes is (1/15)x (see Part 3)

Divide the number of angel food cakes by  the total number of baked goods

therefore

The fraction of all of the baked goods at Laurita’s Bakery that are angel food cakes is 1/15

The correct answer is option c. 95%. Reaching out two standard errors on either side of the sample proportion gives us an interval of 95% confidence.

This is due to the fact that two standard errors on either side of the sample proportion will cover around 95% of the population's cases.

We can typically determine the true proportion in the population using this range of two standard errors on either side of the sample proportion.

This is because it helps us identify any potential outliers in the population and provides a range of population proportions for which we may be 95% certain.

We are 95% certain that the true percentage is capable inside the interval if we stretch out two standard errors on either side of the sample proportion.

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True. Statistical process control is commonly used in service industries, including blood testing labs, to monitor and analyze processes and determine normal levels of variation.

These normal levels of variation are often used as the basis for setting specifications and determining if a process is in control or out of control. Therefore, they can be considered the "voice of the specification" in service industries.

True. Statistical process control is used in service industries like a blood testing lab to determine normal levels of variation. Normal levels of variation are considered the voice of the specification. This helps to maintain quality and control the process.

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