\(\boxed{x=\frac{4}{15},~0.2667}\)
Solution Steps:______________________________
1.) Combine 6x and 1.5x:\(6x+1.5x=7.5x\)- You combine since these are like terms.
Equation at the end of Step 1:
\(7.5x=2\)2.) Divide both sides by 7.5:\(7.5x\) ÷ \(7.5=x\)\(2\) ÷ \(7.5=\)- We divide because we want to get x alone.
Equation at the end of Step 2:
\(x=\frac{2}{7.5}\)3.) Expand the fraction by multiplying both numerator and the denominator by 10:\(2\) × \(10=20\)\(7.5\) × \(10=75\)- We turned this into a fraction because we couldn't divide properly.
4.) Reduce the fraction to lowest terms by extracting and canceling out 5:\(20\) ÷ \(5=4\) \(75\) ÷ \(5=15\)- This step just means divide the lowest amount possible, which in this case is 5.
______________________________
What is the quotient of (x3 + 3x2 + 5x + 3) ÷ (x + 1)?
x2 + 4x + 9
x2 + 2x
x2 + 2x + 3
x2 + 3x + 8
Answer:
C
Step-by-step explanation:
C
using the taylor remainder estimation theorem, what is the maximum possible error of using the first three nonzero terms from the maclaurin series for cos x to approximate cos 2?
The maximum possible error is 2/3.
The Maclaurin series for cosine function is given by:
\(cos(x) = 1 - x^2/2! + x^4/4! - x^6/6! + ...\)
Using the first three nonzero terms, we get:
\(cos(x) ≈ 1 - x^2/2! + x^4/4!\)
To estimate the error, we can use the Taylor remainder formula:
\(Rn(x) = f(n+1)(c) * (x-a)^(n+1) / (n+1)!\)
where f(n+1)(c) is the (n+1)th derivative of f evaluated at some value c between a and x.
In this case, we have:
f(x) = cos(x)
a = 0
n = 2
x = 2
To find an upper bound for the error, we need to find the maximum value of the absolute value of the third derivative of cosine function over the interval [0,2]. Since the third derivative of cosine is -cos(x), the maximum value of its absolute value is 1.
Therefore, we have:
\(|R2(2)| ≤ 1 * (2-0)^(2+1) / (2+1)!\)
≤ 4/3!
≤ 2/3
So the maximum possible error is 2/3.
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The following are the amounts of time, in minutes, that it took a random sample of 20 technicians to perform a certain task: 18.1, 20.3, 18.3, 15.6, 22.5, 16.8, 17.6, 16.9, 18.2, 17.0, 19.3, 16.5, 19.5, 18.6, 20.0, 18.8, 19.1, 17.5, 18.5, and 18.0. Assuming that this sample came from a symmetrical continuous population, use the sign test at the 0.05 level of significance to test the null hypothesis that the mean of this population is 19.4 minutes against the alternative hypothesis that it is not 19.4 minutes. Perform the test using(a) Table I;(b) the normal approximation to the binomial distribution.Rework Exercise 16.16 using the signed-rank test based on Table X.
Since the test statistic (-2.24) falls outside the range of the critical values (-1.96 to 1.96), we reject the null hypothesis.
What is sign test?
The sign test is a non-parametric statistical test used to determine whether the median of a distribution is equal to a specified value. It is a simple and robust method that is applicable when the data do not meet the assumptions of parametric tests, such as when the data
The given problem can be solved using the one-sample sign test to test the null hypothesis that the mean of the population is 19.4 minutes against the alternative hypothesis that it is not 19.4 minutes.
(a) Using Table I:
Step 1: Set up the hypotheses:
Null hypothesis (H0): The mean of the population is 19.4 minutes.
Alternative hypothesis (H1): The mean of the population is not 19.4 minutes.
Step 2: Determine the test statistic:
We will use the sign test statistic, which is the number of positive or negative signs in the sample.
Step 3: Set the significance level:
The significance level is given as 0.05.
Step 4: Perform the sign test:
Count the number of observations in the sample that are greater than 19.4 and the number of observations that are less than 19.4. Let's denote the count of observations greater than 19.4 as "+" and the count of observations less than 19.4 as "-".
In the given sample, there are 5 observations greater than 19.4 (18.1, 20.3, 19.3, 19.5, and 20.0), and 15 observations less than 19.4 (18.3, 15.6, 16.8, 17.6, 16.9, 17.0, 16.5, 18.6, 18.8, 19.1, 17.5, 18.5, and 18.0).
Step 5: Calculate the test statistic:
The test statistic is the smaller of the counts "+" or "-". In this case, the test statistic is 5.
Step 6: Determine the critical value:
Using Table I, for a significance level of 0.05 and a two-tailed test, the critical value is 3.
Step 7: Make a decision:
Since the test statistic (5) is greater than the critical value (3), we reject the null hypothesis.
(b) Using the normal approximation to the binomial distribution:
Alternatively, we can use the normal approximation to the binomial distribution when the sample size is large. Since the sample size is 20 in this case, we can apply this approximation.
Step 1: Set up the hypotheses (same as in (a)).
Step 2: Determine the test statistic:
We will use the z-test statistic, which is calculated as (x - μ) / (σ / √n), where x is the observed number of successes, μ is the hypothesized value (19.4), σ is the standard deviation of the binomial distribution (calculated as √(n/4), where n is the sample size), and √n is the standard error.
Step 3: Set the significance level (same as in (a)).
Step 4: Calculate the test statistic:
Using the formula for the z-test statistic, we get z = (5 - 10) / (√(20/4)) ≈ -2.24.
Step 5: Determine the critical value:
For a significance level of 0.05 and a two-tailed test, the critical value is approximately ±1.96.
Step 6: Make a decision:
Since the test statistic (-2.24) falls outside the range of the critical values (-1.96 to 1.96), we reject the null hypothesis.
Rework Exercise 16.16 using the signed-rank test based on Table X:
To provide a more accurate solution, I would need additional information about Exercise 16.16 and Table X.
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What is the length of NP to the nearest hundredth centimeter?
please do all of these :)
Jackie has two new puppies. One weights 5 9/16 pounds, and the other weighs 6 1/4 pounds. Find the difference in their weights.
Answer:big brrrrrrd
Step-by-step explanation:
yes
Answer:
11/16 pounds
Step-by-step explanation:
The difference between their weights can be found by subtracting 6 1/4 pounds from 5 9/16 pounds to find the difference. To do this we must transfer it from 1/4 to sixteenths which is 4 sixteenths. Then we subtract.
6 4/16
- 5 9/16
11/16
brainliest please . . . uwu
Helppppppppppppppppppppppppppppppppppppppp
Answer:
B
Step-by-step explanation:
Answer:
the answer B
Step-by-step explanation:
1. Reflect Rectangle ABCD across the y-axis, then
translate it using the following rule:
(x,y) → (x-4, y - 3).
A B
D
с
-4 -2
4
2
ТУ
O
-2-
-4-
2
4
X
√x
A' (
B'(
C'(
D'(
A"(
B"(
C"(
D"(
)
)
)
)
PLS HELP ME WITH THIS
Answer:
See attached image
Step-by-step explanation:
PLSSSSSSSS HELP ME WITH THIS CORRECT ANSWER GETS BRAINLIEST
Answer:
6
Step-by-step explanation:
he hypotenuse of a right triangle measures 13 cm and one of its legs measures 10 cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
hypotenuse =13cm
base=10cm
perpendicular =?
Step-by-step explanation:
by using Pythagoras law
hypotenuse=perpendicular²+base²
13²=perpendicular²+10²
perpendicular =√(13²-10²)=√69=8.3cm
the measure of the other leg is 8.3cm
The measure of the other leg is 8.3 cm .
What is Pythagoras theorem?The Pythagoras theorem states that if a triangle is right-angled (90 degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Formula of Pythagoras theorem :
(Hypotenuse)² = (Base)² + (Perpendicular)²
According to the question
Hypotenuse of a right triangle = 13 cm
Perpendicular of a right triangle = 10 cm
Now,
Base of a right triangle
By using formula of Pythagoras theorem :
(Hypotenuse)² = (Base)² + (Perpendicular)²
Substituting the values
(13)² = (Base)² + (10)²
169 = (Base)² + 100
69 = (Base)²
Base = \(\sqrt{69}\)
Base = 8.3 cm
Hence, the measure of the other leg is 8.3 cm .
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Context: There are two flat sheets, horizontal and parallel to the "xy" plane; one located in the z=1 plane and the other in z=-1 (see coordinate reference). Both sheets carry equal charge densities -σ. What is the E field produced by these sheets in the coordinate (x,y,z) = (1,1,0.5)?
Question: In the previous problem, what is the E field produced by these sheets in the coordinate (x,y,z) = (1,-1,1.5)?
The E field produced by the sheets at the coordinate (x, y, z) = (1, 1, 0.5) is zero.
The E field produced by the sheets at the coordinate (x, y, z) = (1, -1, 1.5) is also zero.
To calculate the electric field (E) produced by the charged sheets at the given coordinates, we need to consider the contributions from each sheet separately and then add them together.
For the coordinate (x, y, z) = (1, 1, 0.5):
The distance between the point and the sheet in the z=1 plane is 0.5 units, and the distance to the sheet in the z=-1 plane is 1.5 units. Since the sheets have equal charge densities and are parallel, their contributions to the electric field cancel each other out. Therefore, the net electric field at this coordinate is zero.
For the coordinate (x, y, z) = (1, -1, 1.5):
The distance to the sheet in the z=1 plane is 0.5 units, and the distance to the sheet in the z=-1 plane is 0.5 units. Again, due to the equal charge densities and parallel orientation, the contributions from both sheets cancel each other out, resulting in a net electric field of zero.
The electric field produced by the charged sheets at the coordinates (x, y, z) = (1, 1, 0.5) and (x, y, z) = (1, -1, 1.5) is zero. The cancellation of electric field contributions occurs because the sheets have equal charge densities and are parallel to each other.
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How many and what type of solutions does 5x2−2x+6 have?
1 rational solution
2 rational solutions
2 irrational solutions
2 nonreal solutions
Answer:
2 nonreal solutions
Step-by-step explanation:
given a quadratic equation in standard form
ax² + bx + c = 0 (a ≠ 0 )
then the nature of the roots are determined by the discriminant
b² - 4ac
• if b² - 4ac > 0 then 2 real and irrational solutions
• if b² - 4ac > 0 and a perfect square then 2 real and rational solutions
• if b² - 4ac = 0 then 2 real and equal solutions
• if b² - 4ac < 0 then no real solutions
5x² - 2x + 6 = 0 ← in standard form
with a = 5 , b = - 2 , c = 6
b² - 4ac
= (- 2)² - (4 × 5 × 6)
= 4 - 120
= - 116
since b² - 4ac < 0
then there are 2 nonreal solutions to the equation
Find angle 1
PLS ANSWER ASAP
Answer:
80 degrees
Step-by-step explanation:
What we see in this drawing is a triangle formed by three lines. In order to solve this problem, we need to know that when two lines intersect, the two angles formed are supplementary (meaning they add up to 180 degrees). For example, the 150-degree angle, and the angle right next to it (the angle on the left side of the triangle) add up to 180 degrees. This means that the left-most angle of the triangle is 180-150, which is 30 degrees
We can figure out the topmost angle of the triangle using the same method. We know that the angle outside the triangle is 130 degrees, so the angle right next to it (in this case, right below it), is 180-130, or 50 degrees.
Next, we use the fact that triangles are 180 degrees on the inside to figure out the third angle (the one on the right, right next to angle 1). We know that the other two angles are 30 and 50 degrees, and if you add that up, you get 80 degrees. The last angle, then, is 180-80, or 100 degrees.
Lastly, we know that the rightmost angle of the triangle and angle 1 add up to 180 degrees. In other words, 100+Angle1=180. Therefore, Angle 1 is 180-100 or 80 degrees.
Please help me with this math problem!! Will give brainliest!! :)
Answer:
\(2x^3-3x^2-10x+15\\\)
Step-by-step explanation:
To find (fg)(x), we have to look at f(x) and g(x) and multiply the two quantities together. We are already given the two quantities individually so all that is left is the multiplication:
\((fg)(x)=(-2x+3)(5-x^2)=-10x+2x^3+15-3x^2\\\)
If we reorder the terms to go from highest degree to lowest, we get our final answer to be the following:
\(2x^3-3x^2-10x+15\)
(1.02)
Evaluate the following expression using the values given:
Find 3r2 – 5s + 6t if r = 2, s=-4, t = -1
O 38
O 26
O -2
O -14
Answer:
-14
Step-by-step explanation:
3r2-5s+6t
3.2.2-5(-4)+6.(-1)
12-20-6
12-26
-14
Answer:
(3r2 -5s +6t if r=2 s= -4 t= -1 ) =-2
Does anyone know the answer to this equation?
Fill The Blank ?a function is a rule that assigns to each value of the_____
In essence, a function is a rule that assigns to each value of the input set (also known as the domain), a unique value of the output set (also known as the range).
A function is a fundamental mathematical concept that is used to describe the relationship between two sets of values.
To understand the idea of a function, imagine a machine that takes in an input and produces an output. The input values are the domain of the function, and the output values are the range. A function can be represented as an equation, a graph, or a table. For example, the equation f(x) = x + 3 represents a function that takes in an input value x and produces an output value that is 3 greater than the input value.
One of the key features of a function is that each input value must have a unique output value. This means that if you input the same value into the function twice, you should get the same output value both times. In mathematical terms, we say that a function is well-defined if it has a unique output value for each input value.
Functions are used in a wide range of mathematical applications, from algebra and calculus to statistics and data analysis. They provide a powerful tool for describing and analyzing relationships between different sets of values.
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a football team won 80% of the 150 games in a season. Wright the percent proportion that will help you solve the problem in that point
PLEASE HURRY
Let p: A student plays basketball.
Let q: A student plays tennis.
How many students play both basketball and tennis?
Answer:
4
Step-by-step explanation:
4 is the intersecting point which states p intersect q giving both tennis and basketball players
find the measure of the arc AC
What are the solutions of 4x2 - 16X = 16x - 39
Answer:
x = \(\frac{3}{2}\), x = \(\frac{13}{2}\)
Step-by-step explanation:
Given
4x² - 16x = 16x - 39 ( subtract 16x - 39 from both sides )
4x² - 32x + 39 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term, that is
product = 4 × 39 = 156 and sum = - 32
The factors are - 26 and - 6
Use these factors to split the x- term
4x² - 26x - 6x + 39 = 0 ( factor the first/second and third/fourth terms )
2x(2x - 13) - 3(2x - 13) = 0 ← factor out (2x - 13) from each term
(2x - 13)(2x - 3) = 0
Equate each factor to zero and solve for x
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \(\frac{3}{2}\)
2x - 13 = 0 ⇒ 2x = 13 ⇒ x = \(\frac{13}{2}\)
PLEASE HEPPPPPP MEEEEEE :))))
⇒ x² - 6x = -8
\(\sf add \ 9 \ on \ both \ sides\)
⇒ x² - 6x + 9 = -8 + 9
\(\sf simplify \ and \ complete \ square\)
⇒ x² - 3x - 3x + 9 = 1
\(\sf factor \ common \ term\)
⇒ x(x - 3) - 3(x - 3) = 1
\(\sf collect \ into \ groups\)
⇒ (x - 3)² = 1
\(\sf square \ root \ both \ sides\)
⇒ x - 3 = ±√1
\(\sf simplify\)
⇒ x - 3 = ±1
\(\sf change \ side\)
⇒ x = 1 + 3, -1 + 3
\(\sf simplify\)
⇒ x = 4, 2
2)\(\rightarrow \sf 4x^2 + 12x + 11 = 0\)
\(\rightarrow \sf 4\left(x^2+3x+\dfrac{11}{4}\right) = 0\)
\(\rightarrow \sf 4\left(x^2+3x+\dfrac{11}{4}+\left(\dfrac{3}{2}\right)^2-\left(\dfrac{3}{2}\right)^2\right) = 0\)
\(\rightarrow \sf 4\left(x+\dfrac{3}{2}\right)^2+2 = 0\)
\(\rightarrow \sf \left(x+\dfrac{3}{2}\right)^2 = -\dfrac{2}{4}\)
\(\rightarrow \sf \left(x+\dfrac{3}{2}\right)^2 = -\dfrac{1}{2}\)
\(\rightarrow \sf x+\dfrac{3}{2} = \pm \sqrt{-\dfrac{1}{2} }\)
\(\rightarrow \sf x+\dfrac{3}{2} = \pm i\sqrt{\dfrac{1}{2} }\)
\(\rightarrow \sf x= \pm i\sqrt{\dfrac{1}{2} }-\dfrac{3}{2}\)
If p varies directly as q and p = 9. 6 when q = 3, find the equation that relates p and q
P = 3.2qThis is the equation that relates p and q when p varies directly with q.
When two variables are directly proportional to each other, they are said to be varying directly. This suggests that when one variable is multiplied by a fixed value, the other variable will also be multiplied by the same fixed value to obtain the product.
Let's say p is directly proportional to q. Then, we can write: p = kq, where k is a constant of variation. We can obtain the equation that relates p and q by substituting the given values p = 9.6 and q = 3. p = kq ⇒ 9.6 = k(3)
Solving for k:k = 9.6/3k = 3.2Now that we know k, we can substitute it back into the equation p = kq:p = 3.2q
This is the equation that relates p and q when p varies directly with q.
To confirm, let's check that it works for other values of p and q. If q = 2,p = 3.2(2) = 6.4If q = 5,p = 3.2(5) = 16
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What is the answer? Please help, this is urgent. Thanks.
Evaluate the expression when g= 14 and h=63.
h
9+
Х
5
?
Answer:
\(23\)
Step-by-step explanation:
\(g+\frac{h}{7}\)
\(g=14\)\(h=63\)\(14+\frac{63}{7}\)First, divide 36 by 7:
\(\frac{63}{7}=9\)Add 14 and 9:
\(14+9=23\)________________________
10.
Find the area of the shaded
a)
b)
14 cm
14 cm
d)
e)
Answer:
14 cm
Step-by-step explanation:
Please help me . 8,10,11!
Solve this equation for the given domain.
cos(2x + 45°) = 0.8 for 0° ≤ x ≤ 180°
The solution to the equation cos(2x + 45°) = 0.8 in the domain of 0° to 180° is x = 15° and X=139° or X=176 °
How to find the solution?Because Cos (±37° +360k) = 0.8
0≤2X ≤ 360°
0+45°=2x+45° 360°+45° 45°≤ 2x+45°< 405°
50 2x+45° = 360°-37° or 2x+45° = 360° + 37°
{list the equation} 397° -45°=2X = 323-45°
2X = 323-45°. 2x=397° -45°
2x= 278°. 2x= 352°
X = 139°. X=176°
So , x = 139° or x = 176°
To discover the solution set of an equation with a particular domain, first insert each domain value into the equation to obtain the associated range values. Make ordered pairs out of these values and put them down as a set. That set is your solution!
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Let X₁, X2,... , Xn be a random sample from the probability density function fo (x) = { if 0 <0
Suppose we have a random sample X₁, X₂,..., Xn from a probability density function (PDF) f₀(x) defined as 1/x² if 0 < x < 1, and zero otherwise. In this case, we discuss its implications for the random sample.
The given PDF, f₀(x), is a continuous function defined over the interval (0, 1). It takes the value 1/x² for 0 < x < 1 and is zero elsewhere. This means that the PDF is unbounded as x approaches zero, and it approaches zero as x approaches infinity.
When we have a random sample X₁, X₂,..., Xn from this PDF, it means that each observation in the sample is independently and identically distributed according to f₀(x). The sample can consist of any positive values between 0 and 1, but cannot include values outside this range due to the zero density outside the interval.
To analyze this sample further, we can explore properties such as the sample mean, sample variance, or other statistical measures. However, it's important to note that the properties of this sample will depend on the specific values observed within the interval (0, 1) and the sample size, n. The behavior of the sample statistics will be influenced by the underlying distribution defined by the PDF f₀(x).
In summary, the given random sample X₁, X₂,..., Xn is generated from a probability density function that assigns a density of 1/x² for values within the interval (0, 1). Analyzing the properties and behavior of this sample will require examining specific observed values within the interval and considering the effects of the underlying PDF on the sample statistics.
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Joe measures a bug and finds out it is 3.5 centimeters long.
How many millimeters long is the bug?
1 cm = 10 mm
0.035 mm
0.35 mm
35 mm
350 mm
Answer:
35 mm
Step-by-step explanation:
Formula:multiply the length value by 10
Answer:
0.35
Step-by-step explanation:
3.5÷10=0.35