Answer:
the answer is
(D) HI
Explanation:
985 grams converted to kilometers
Answer:
?
Explanation:
did you mean kilograms?
the vostok ice core curve shows co2 concentrations over the last __________.
The Vostok ice core curve shows CO2 concentrations over the last 800,000 years.
The Vostok ice core, drilled in Antarctica at the Vostok Station, has provided valuable data on past climate conditions. By analyzing the ice layers, scientists can determine various parameters, including CO2 concentrations. The ice core data has allowed the reconstruction of CO2 levels in the atmosphere dating back hundreds of thousands of years, providing insights into long-term climate trends and the relationship between CO2 and global temperatures.
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Typically, nitrogen atoms are composed of electrons, protons, and neutrons. an isotope of nitrogen could?
Typically, nitrogen atoms are composed of electrons, protons, and neutrons. an isotope of nitrogen could have more number of neutrons than usual nitrogen atom.
What is proton ?
Protons include the H+ ion or the hydrogen atom's nucleus. Regardless of the isotope, each hydrogen atom has one proton, each helium atom has two, each lithium atom has three, and so on.
What is electron ?
It is possible for an electron to be free or linked to an atom. An electron is a negatively charged subatomic particle (not bound). There are three main types of particles in an atom: protons, neutrons, and an electron that is bonded to an atom. The nucleus of an atom is composed of protons, neutrons, and electrons.
Therefore, nitrogen atoms are composed of electrons, protons, and neutrons. an isotope of nitrogen could have more number of neutrons than usual nitrogen atom.
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Answer nb 1 and 2 to be marked as Brainliest
Answer:
Nb 1= mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
The molar mass of gallium (
G
a
GaG, a) is
69.72
g
/
m
o
l
69.72 g/mol69, point, 72, space, g, slash, m, o, l.
Calculate the number of atoms in a
27.2
m
g
27.2 mg27, point, 2, space, m, g sample of
G
a
GaG, a.
2.35 x 10²⁰ atoms are present in a 27.2 mg sample of Gallium.
What kinds of molecules have different masses?The total atomic mass of all the atoms that make up a molecule is calculated using a scale where the atomic masses of hydrogen, carbon, nitrogen, and oxygen are 1, 12, 14, and 16, respectively. For instance, the molecular mass of water, which consists of two hydrogen atoms and one oxygen atom, is 18 (2 + 16).
moles of Gallium = mass of sample / molar mass of Gallium
moles of Gallium = 27.2 mg / 69.72 g/mol
moles of Gallium = 0.0003906 mol
The number of atoms can be determined using Avogadro's number:
number of atoms = moles of Ga x Avogadro's number
number of atoms = 0.0003906 mol x 6.022 x 10²³ atoms/mol
number of atoms = 2.35 x 10²⁰ atoms
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In the Diels Alder reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride, what was the %recovery using the information below?
Weight of maleic anhydride used: 1 85 mg = 0.1 85g Volume of diene used: 0.215mL Weight of cyclic anhydride crystals recovered: 0.251g % Recovery:
Recovery = (Weight of product recovered ÷ Theoretical yield) × 100% Recovery = (0.251 g ÷ 0.27594 g) × 100% Recovery = 91.08%Therefore, the % recovery of the reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride was 91.08%.
Diels-Alder Reaction Diels-Alder reaction is a chemical process that joins a conjugated diene with a dienophile (a compound containing a double bond) to form a six-membered ring called a cyclohexene ring. It is a chemical reaction that can be used to make new carbon–carbon bonds. The reaction was discovered by two German scientists, Otto Diels and Kurt Alder, in 1928.In the Diels-Alder reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride, the % recovery was calculated using the following data:Weight of maleic anhydride used: 185 mg = 0.185 gVolume of diene used: 0.215 mLWeight of cyclic anhydride crystals recovered: 0.251 g% Recovery:We can calculate the percent recovery using the following formula:% Recovery = (Weight of product recovered ÷ Theoretical yield) × 100The theoretical yield of the product can be calculated from the balanced chemical equation as follows:2,3-dimethyl-1,3-butadiene + Maleic Anhydride → Cyclohexene-1,2-dicarboxylic AnhydrideThe molar mass of 2,3-dimethyl-1,3-butadiene is 68 g/mol. The molar mass of Maleic Anhydride is 98 g/mol. The molar mass of Cyclohexene-1,2-dicarboxylic Anhydride is 146 g/mol.Using these values, we can calculate the number of moles of each reactant: moles of diene used = (0.215 mL)(0.788 g/mL)/(68 g/mol) = 0.00248 mol moles of maleic anhydride used = 0.185 g/98 g/mol = 0.00189 mol The theoretical yield of cyclohexene-1,2-dicarboxylic anhydride = 0.00189 mol × 1 mol/1 mol = 0.00189 molThe theoretical yield of cyclohexene-1,2-dicarboxylic anhydride = 0.00189 mol × 146 g/mol = 0.27594 gNow, we can substitute these values into the percent recovery equation:% Recovery = (Weight of product recovered ÷ Theoretical yield) × 100% Recovery = (0.251 g ÷ 0.27594 g) × 100% Recovery = 91.08%Therefore, the % recovery of the reaction between 2,3-dimethyl-1,3-butadiene and maleic anhydride to form cyclic anhydride was 91.08%.
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the types of isomers
There are two main types of isomers:
Structural isomers: Structural isomers have the same molecular formula, but different arrangements of atoms within the molecule. These isomers may have different physical and chemical properties due to the different ways in which the atoms are bonded together. For example, n-pentane and isopentane are structural isomers with the same molecular formula (C5H12), but different structures.Stereoisomers: Stereoisomers have the same molecular formula and the same atom-to-atom connections, but differ in the spatial arrangement of the atoms. Stereoisomers can be further divided into two subtypes:a) Geometric isomers (also known as cis-trans isomers): Geometric isomers have the same atom-to-atom connections, but differ in the orientation of functional groups around a double bond or a ring structure. For example, cis-2-butene and trans-2-butene are geometric isomers with the same molecular formula and the same atom-to-atom connections, but different spatial arrangements.
b) Optical isomers (also known as enantiomers): Optical isomers are mirror images of each other and cannot be superimposed on each other. They have the same molecular formula, the same atom-to-atom connections, but differ in the spatial arrangement of atoms or functional groups around a chiral center. Optical isomers may have different physical and chemical properties and interact differently with other molecules. An example of optical isomers is L- and D-glucose.
What mass of iron should be produced if 11.0g of aluminum react with 30.0g of iron (III) oxide?
The mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.
To determine the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide, we need to balance the chemical equation and perform stoichiometric calculations.
The balanced chemical equation for the reaction between aluminum and iron (III) oxide can be written as follows:
2 Al + Fe₂O₃ → 2 Fe + Al₂O₃
From the balanced equation, we can see that 2 moles of aluminum react with 1 mole of iron (III) oxide to produce 2 moles of iron and 1 mole of aluminum oxide.
Convert the given masses of aluminum and iron (III) oxide into moles.
Using the molar mass of aluminum (26.98 g/mol) and iron (III) oxide (159.69 g/mol), we can calculate the number of moles for each substance.
Number of moles of aluminum = mass of aluminum / molar mass of aluminum
= 11.0 g / 26.98 g/mol
= 0.408 moles
Number of moles of iron (III) oxide = mass of iron (III) oxide / molar mass of iron (III) oxide
= 30.0 g / 159.69 g/mol
= 0.188 moles
Determine the limiting reactant.
To determine the limiting reactant, we compare the stoichiometric ratio of aluminum to iron (III) oxide. From the balanced equation, we see that 2 moles of aluminum react with 1 mole of iron (III) oxide.
Given that we have 0.408 moles of aluminum and 0.188 moles of iron (III) oxide, we can calculate the moles of iron that can be produced from each reactant.
Moles of iron from aluminum = 2 * 0.408 moles = 0.816 moles
Moles of iron from iron (III) oxide = 0.188 moles
Since the moles of iron from aluminum (0.816 moles) is greater than the moles of iron from iron (III) oxide (0.188 moles), we can conclude that iron (III) oxide is the limiting reactant.
Calculate the mass of iron produced.
To calculate the mass of iron produced, we use the molar mass of iron (55.85 g/mol) and the number of moles of iron from the limiting reactant.
Mass of iron = moles of iron from iron (III) oxide * molar mass of iron
= 0.188 moles * 55.85 g/mol
= 10.48 g
Therefore, the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.
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6) What is the pH of a solution with [H3O+] = 1 × 10-9 M?
A) 1.0 × 10-5
B) -9.0
C) 5.0
D) -5.0
E) 9.0
Answer:
E) 9.0
Explanation:
pH = -log [1×10^-9] = 9
How is thermal energy transferred by convection, conduction, and radiation?
Answer:
Radiation is responsible for most of the heat transferred into the room. Heat transfer also occurs through conduction into the room, but at a much slower rate. Heat transfer by convection also occurs through cold air entering the room around windows and hot air leaving the room by rising up the chimney.
When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along. This type of heat transfer is called convection. The fluid above a hot surface expands, becomes less dense, and rises. ... A space heater is a classic convection example.
How many grams of rubber stoppers would be needed to contain the same number of stoppers as there are corks in 1.0 kg of corks?
The weight of each stopper can vary based on the material, size, and manufacturing process used, so it is not possible to determine the number of rubber stoppers needed without more information.
What is weight and average weight?Weight is a measure of the force of gravity on an object and is typically measured in units of Newtons (N), pounds (lb), or kilograms (kg).
Average weight, on the other hand, refers to the sum of the weights of a group of objects divided by the number of objects in the group. It provides an estimate of the typical or central value of the weights in the group. The units of average weight are the same as the units used to measure weight.
The number of rubber stoppers needed to contain the same number of stoppers as there are corks in 1.0 kg of corks would depend on the average weight of each type of stopper.
The weight of each stopper can vary based on the material, size, and manufacturing process used, so it is not possible to determine the number of rubber stoppers needed without more information.
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A student is investigating the percentage purity of ibuprofen in a sample of tablets. 6.00 g of a sample of impure ibuprofen tablets was crushed and dissolved in 200 cm³ of 0.200 mol dm-³ aqueous sodium hydroxide.
25.0 cm³ of this solution was withdrawn and titrated against hydrochloric acid. The unreacted NaOH in this solution required 24.40 cm³ of 0.120 mol dm of hydrochloric acid for complete neutralisation.
i) Calculate the amount of sodium hydroxide that has reacted with hydrochloric acid. (ans: 0.002928mol)
ii) Calculate the amount of sodium hydroxide unreacted in 200 cm³ solution.
(ans: 0.002928 x (200/25.0) = 0.0234mol)
I KNOW HOW TO DO PART i. PLEASE EXPLAIN HOW TO GET THE ANSWER FOR PART ii WITH THE GIVEN SOLUTION thank you
Based on the mole ratio of the reaction and the volume of the reactants used;
Amount in moles of hydroxide that has reacted with hydrochloric acid is 0.002928 molesAmount in moles of sodium hydroxide unreacted in 200 cm³ solution is 0.0234 moles.What is the amount of sodium hydroxide that reacted with hydrochloric acid?The amount of sodium hydroxide that reacted with hydrochloric acid is calculated from the mole ratio of the reaction between hydrochloric acid and sodium hydroxide.
The equation of the reaction is given as follows:
HCl (aq) + NaOH (aq) ---> NaCl + H₂O
The mole ratio of HCl and NaOH is 1 : 1
Moles of HCl in 24.40 cm³ of 0.120 mol dm of hydrochloric acid solution will be determined as follows:
Moles = molarity * volume in LitersMoles of HCl = 0.120 * 24.40 / 1000
Moles of HCl = 0.002928 moles
Thus moles of NaOH reacted = 0.002928 moles
The amount of sodium hydroxide unreacted in 200 cm³ solution is determined as follows:
Moles of sodium hydroxide unreacted in 25 cm³ solution = 0.002928 moles
Moles of sodium hydroxide unreacted in 200 cm³ solution = 0.002928 moles * 250 / 25
Moles of sodium hydroxide unreacted in 200 cm³ solution = 0.0234 moles.
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So I have an F in science, and everything is due today. Am I going to fail 9th grade because I didn't pass that class?
Answer:
i dk how ur school works, but you'll most likely have to take that science again to get the credits u need to graduate
Explanation:
What would you expect for the magnitude and direction of the bond dipoles in this series? a) BâH>CâH>NâH b) NâH>CâH>BâH c) NâH>BâH>CâH d) CâH>BâH>NâH
The electronegativity of an atom determines how strongly it attracts electrons in a bond. When atoms with different electronegativities are bonded together, the shared electrons are not equally shared, leading to the formation of a bond dipole.
The direction of the bond dipole is from the less electronegative atom towards the more electronegative atom.
In this series, the electronegativity of the central atom increases from B to C to N, while the electronegativity of the bonded hydrogen atom remains relatively constant. Therefore, the bond dipoles are expected to increase in magnitude from a) BâH > CâH > NâH, since the difference in electronegativity between the central atom and the hydrogen atom becomes larger as we move from N to C to B. The direction of the bond dipoles is from the hydrogen atom towards the central atom.
Therefore, the correct answer is a) BâH > CâH > NâH.
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What is the primary function of phosphoglycerides mentioned in this module?
Answer:
which one is isn't the one that is wrong
Explanation:
bang bang chocho train
47.9 ml hrdrogen is collected at 26° Celsius and 718 torr. Find the volume occupied at STP
Answer:
41.45 mL
Explanation:
Applying the general gas equation,
PV/T = P'V'/T'............... Equation 1
Where P = Initial pressure of hydrogen, V = Initial volume of hydrogen, T= Initial Temperature of hydrogen, P' = Final pressure of hydrogen, V' = Final Volume of Hydrogen, T' = Final Temperature.
make V' the subject of the equation
V' = PVT'/TP'................ Equation 2
Given: P = 718 torr = (718×133.322) N/m² = 95725.196 N/m², V = 47.9 mL = 0.0479 dm³, T = 26 °C = (26+273) = 299 K, T' = 273 K, P' = 101000 N/m²
Substitute these values into equation 2
V' = ( 95725.196×0.0479×273)/(299×101000)
V' = 0.04145 dm³
V' = 41.45 mL
How many grams of calcium chloride should be dissolved in 500. 0mL of water to make a 0. 20m solution of calcium chloride?
11.1 grams of calcium chloride should be dissolved in 500. 0mL of water to make a 0. 20 M solution of calcium chloride.
Molarity of a solution is defined as the number of moles of solute present in 1 litre of a solution. 1 mole of any substance is equal to 6.022× 10²³ atoms, ions or molecules present in it.
0.2M means 0.2mol CaCl₂/1L solution.
This question didn't give us a density of the solution so needs an assumption that the solution has equal volume to water.
x mol/0.5L=0.2M
x = 0.1
0.1 mol of CaCl₂ is needed. Ca=40g/mol, Cl=35.5g/mol.
CaCl₂ 0.1mol = (40+35.5×2)×0.1=11.1g
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Mg(s) + CuSO4(aq) → Cus) + MgSO4(aq)
What are the products?
Answer:
Products are copper and magnesium sulphate
Explanation:
\({ \bf{A+B→C+D}}\)
A and B are reactants
C and D are products
if the acid dissociation constant, ka, for an acid ha is at 25°c, what percent of the acid is dissociated in a 0.50 m solution of ha at 25°c?
Approximately x% of the acid is dissociated in a 0.50 M solution of HA at 25°C.
What is the mathematical expression for the percent dissociation of an acid?The percent dissociation of an acid can be determined using the acid dissociation constant (Ka) and the initial concentration of the acid (HA). The mathematical expression for percent dissociation is:
Percent Dissociation = (Dissociated HA concentration / Initial HA concentration) * 100
In this case, we are given that the acid dissociation constant (Ka) for acid HA is known at 25°C, and we have a 0.50 M solution of HA. However, the value of Ka and specific acid are not provided, so we cannot calculate the exact percent dissociation.
To calculate the percent dissociation, you would need the value of Ka for the specific acid, which indicates the extent of dissociation at equilibrium. Based on this value and the initial concentration of HA, you can calculate the dissociated HA concentration and then use the mathematical expression mentioned above to determine the percent dissociation.
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The Universal Space Agency wants to know the results of your Sim investigation. Write your report to the lead chemist, explaining why there is liquid water on the outside of the can but no liquid nitrogen. Use evidence from your investigation in your explanation.
Answer:
Due to warm temperature.
Explanation:
There is water present in liquid form instead of liquid nitrogen on the outer side of the can because of the temperature present in the surrounding environment. The temperature around the can is little warm which is favourable for the water but not for the liquid nitrogen. The liquid nitrogen present in liquid state when the temperature of the surrounding is too cold. if it is warm, the liquid nitrogen starts boiling and converts into gaseous state so that's why the warmer temperature is responsible for the presence of water not the liquid nitrogen.
Which determines the reactivity of an alkali metal?
Answer:
Its ability to lose electrons
Explanation:
The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.
Answer:
When it's able to lose electrons when it bonds with another substance.
6. A diamond contains 5.0 ×10^21 atoms of carbon. What amount(moles) of carbon and what mass (grams) of carbon are in this diamond? *
a. 0.008303 and 0.0997
b. 0.008303g and 0.0997mol
c. 0.008303amu and 0.0997
d. 0.008303 and 0.0997amu
Answer:
0.008303 mol and 0.0997 g
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.
This implies that 1 mole of carbon also contains 6.022×10²³ atoms.
Next, we shall determine the mole of carbon that contains 5.0×10²¹ atoms. This can be obtained as follow:
1 mole of carbon contains 6.022×10²³ atoms.
Therefore, Xmol of carbon will contain 5.0×10²¹ atoms i.e
Xmol of carbon = 5.0×10²¹ / 6.022×10²³
Xmol of carbon = 0.008303 mole
Therefore, 0.008303 mole of carbon contains 5.0×10²¹ atoms.
Finally, we shall determine the mass of carbon. This can be obtained as follow:
Mole of carbon = 0.008303 mole
Molar mass of carbon = 12.01 g/mol
Mass of Carbon =.?
Mole = mass /Molar mass
0.008303 = mass of carbon/12.01
Cross multiply
Mass of Carbon = 0.008303 x 12.01
Mass of Carbon = 0.0997 g.
An old refrigerator is rated at 500 W how many kilowatt hours of electric energy what does refrigerator use in 30 days assume the refrigerator is running 12 hours per day
The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.
To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.
Given:
Power rating of the refrigerator = 500 W
Running time per day = 12 hours
Number of days = 30
First, we need to convert the power rating from watts to kilowatts:
Power rating = 500 W / 1000 = 0.5 kW
Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:
Energy used = Power rating × Running time × Number of days
Energy used = 0.5 kW × 12 hours/day × 30 days
Energy used = 180 kWh
Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.
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Predict whether each of the following would result in a higher, lower, or unaltered percent yield of product.
A. The product was washed with water instead of acetone
B. Not all of the acetone was removed in the drying step
C. The beaker was not rinsed with the additional 5 mL of ethanol
D. More than 10 mL of water was used to dissolve the anhydrous copper (II) sulfate.
A. Lower percent yield of product
B. Lower percent yield of product
C. Higher percent yield of product
D. Lower percent yield of product
A. Washing the product with water instead of acetone can lead to impurities remaining in the product, which can lower the percent yield.
B. Not removing all the acetone can lead to residual solvent in the product, which can lower the percent yield.
C. Rinsing the beaker with the additional ethanol can lead to more product being collected, which can increase the percent yield.
D. Dissolving the anhydrous copper (II) sulfate in more than 10 mL of water can lead to dilution of the reactants, which can lower the percent yield.
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What does it mean for something to be radioactive?
A. It has an emission spectrum.
B. It is in a stable condition.
C. It generates radio waves.
D. Its nuclei can split apart.
Answer:
D
Explanation:
Radioactivity means
the emission of ionizing radiation or particles caused by the spontaneous disintegration of atomic nuclei
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chemistry-mole calculations
Answer:
somebody answer this please>>>!!!
Explanation:
!!!
hydroxyl, ether, carbonyl, or amine?
It represents an amine group.
11 Jamila and Ahmed investigate displacement reactions
They put drops of different solutions into the dimples of a spotting tile.
They then add metals to each solution
The diagram shows their experiment.
zinc magnesium copper
metal metal metal
iron
metal
dimple
zinc nitrate
solution
♡
magnesium nitrate
solution
♡
» 2
Кеу
copper nitrate
solution
empty dimple
2
iron nitrate
solution
dimple with
metal and solution
spotting til
(a) Jamila and Ahmed look to see if a reaction takes place.
Suggest what they might see if a reaction takes place.
Based on the activity series of metals, it can be observed that Magnesium being most reactive is not dispalaced by any metal from it's solution whereas copper being the least reactive is displaced by all the metals from it's solution.
What is the activity series of metals?The activity series of metals is an arrangement of metals based on their reactivities, from the most reactive to the least reactive.
Based on the activity series of metals, the following will be observed:
Zinc nitrate solution + magnesium metal = Magnesium dissolves and zinc metal is obtained
Zinc nitrate solution + Copper metal = No reaction
Zinc nitrate solution + Iron metal = no reaction
Magnesium nitrate solution + Zinc metal = No reaction
Magnesium nitrate solution + copper metal = No reaction
Magnesium nitrate solution + Iron metal = No reaction
Copper nitrate solution + Zinc metal = Zinc metal dissolves and copper metal is produced
Copper nitrate solution + Magnesium metal = Magnesium dissolves and copper metal is produced
Copper nitrate solution + Iron metal = Iron metal dissolves and copper metal is produced
Iron nitrate solution + Zinc metal = Zinc metal dissolves and iron metal is obtained
Iron nitrate solution + Magnesium metal =Magnesium metal dissolves and iron metal is obtained
Iron nitrate solution + Copper metal = No reaction
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If 80mg of a radioactive element decays to 10 mg in 30 mins., what is the element's half-life in minutes?
a- 10 b- 20 c- 30 d- 40
Answer:
the answer is a.10
Explanation:
in(No/N) = kt
No = 80 mg
N = 10 mg
t = 30 min
solve for k, then
k = 0.693/t1/2
Substitute k from above and solve for t1/2
10 min is correct.
Radioactive element keeps on decaying over the time. Decay of radioactive element always comes under first order kinetics. The element's half-life of decay of 80mg of a radioactive element decays to 10 mg in 30 mins is 10.04 minutes. The correct option is option A.
What is half life?Half life tells about the time at which the radioactive material decays to half of its initial concentration.
Mathematically, the initial and final amount of radioactive material can be connected as
ln(No/N) = kt
No =initial amount of radioactive decay= 80 mg
N = final amount of radioactive decay=10 mg
t =time taken to decay= 30 min
K= rate constant
ln( 80 mg/10 mg) = k×30 min
0.069min⁻=k
k = 0.693/half life
half life=10.04min
Therefore the element's half-life of decay of 80mg of a radioactive element decays to 10 mg in 30 mins is 10.04 minutes. The correct option is option A.
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You have been assigned to prepare 50.0 mL of a 3.0 %(v/v) solution in a volumetric flask from a 20.0% (v/v) Red Food Coloring (RFC) stock solution provided. Use the equation below to calculate the amount in (mL) of the RFC stock solution to prepare your assigned % solution.
Answer:
7.5mL of the stock solution
Explanation:
A stock solution is a concentrated solution that is used to make another more diluted solution.
In the problem, the RFC solution is 20% (v/v). That means contains 20mL of RFC in 100mL of solution.
Yo need to prepare 50.0mL of a 3.0% (v/v), solution (3mL of RFC in 100mL of solution). That means you need:
50.0mL solution × (3mL RFC / 100mL solution) = 1.5mL of RFC. These RFC must come from the stock solution
As your stock solution contains 20mL of RFC per 100mL of solution, you will need:
1.5mL RFC × (100mL stock / 20mL RFC) =
7.5mL of the stock solution