79.2 L of a gas are contained at STP. How many moles are present in the container?

The greatest molar amount of metal product is obtained from silver (1) nitrate.

Let us determine the mass of metal obtained in each case.

For La^3+;

La^3+ + 3e ----> La

1 mole of La is deposited by 3F

x moles of La is deposited by 10 F

x = 1 × 10/3

x = 3.33 moles

For Zn^2+;

1 mole Zn^2+ is deposited by 2F

x moles of Zn^2+ is deposited by 10 F

x = 5 F

For Ag^+

1 mole of Ag^+ is deposited by 1 F

x moles of Ag^+ is deposited by 10 F

x = 10 moles

For Ba^2+;

1 mole of Ba^2+ is deposited by 2 F

x moles of Ba^2+ is deposited by 10 F

x = 5 moles

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0.6 is the equilibrium constant for the given reaction.

To calculate the equilibrium constant (K) for the given reaction, we need to use the molar concentrations of the reactants and products at equilibrium. The equilibrium constant expression is given by:

\(K= [H_{2}O]^{2} / ([H_{2}^{2} * [O_{2}])\)

Given the moles of H2, O2, and H2O in the 8.1 L container, we can convert them to molar concentrations by dividing the number of moles by the volume:

[H2] = 1.83 moles / 8.1 L

[O2] = 2.33 moles / 8.1 L

[H2O] = 3.95 moles / 8.1 L

Substituting these values into the equilibrium constant expression, we have:

K = \((3.95 / 8.1)^{2}\) / (\((1.83 / 8.1)^{2}\) * (2.33 / 8.1))

Evaluating this expression and rounding to one decimal place, we find the equilibrium constant to be:

K ≈ 0.6

Therefore, the equilibrium constant for the given reaction is approximately 0.6.

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Answer:0.400 gl

Explanation:

Answer:

Option C

Explanation:

The complete question is

What is the major organic product obtained from the reaction of

(R)-2-bromohexane with sodium cyanide/acetone?

A) ) trans-2-pentene

B) ( S)-2-Methylpentanenitrile

C) ( S)-2-Methylhexanenitrile

D) (plus or minus)-2-Methylpentanenitrile

Solution

This is an inversion reaction in which (R) 2 Bromohexane convert into (S) -2 – methyl hexane in the presence of Acetone and NaCN.  

The reaction occurs through the SN2 mechanism and  there is inversion of confiruration

Hence, option C is correct

Answer:

5l NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

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The heat energy q of water can be calculated using calorimetric equation. The heat energy of water in the given reaction is, 551.76 J.This reaction is endothermic where change in heat energy is positive.

Calorimetry is an analytical technique used to determine the heat energy absorbed or evolved in a reaction. The calorimetric equation connecting the mass  m of reactant, specific heat capacity q and the temperature difference Δ T is:

q = m c  Δ T.

It is given that temperature changes from 25 to 26.2 degree celsius and mass of water is 110 g. The specific heat capacity of water is 4.18 J/g °C.

The heat energy of water is then calculated as follows:

q = 110 g ×  4.18 J/g °C × (26.2 - 25 °C)

  = 551.76 J.

Hence, the heat energy change in this reaction is 551.76 J.

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Your question is incomplete, but, your complete question probably was:

The temperature of 110 g of water rises from 25.0 C to 26.2 C when 0.10 mol of H+ is reacted with 0.10 mol of OH-. Calculate q OF water ...

Answer : The concentration of the HCl in original bottle is 0.56 M.

Explanation :

According to neutralization law:

\(M_1V_1=M_2V_2\)

where,

\(M_1\) = concentration of  HCl

\(M_2\) = concentration of NaOH

\(V_1\) = volume of HCl

\(V_2\) = volume of NaOH

Given:

\(M_1\) = ?

\(M_2\) = 0.25 M

\(V_1\) = 10 mL

\(V_2\) = 22.4 mL

Now put all the given values in the above formula, we get:

\(M_1\times 10mL=0.25M\times 22.4mL\)

\(M_1=0.56M\)

Therefore, the concentration of the HCl in original bottle is 0.56 M.

Answer:

0.20 g/L

Explanation:

Step 1: Calculate the molar mass of the gas (M)

At T = 350 °C = 623 K and P = 1 atm (we will assume this data), the density (ρ) of the gas is 0.087 g/L. We can calculate the molar mass of the gas using the following expression.

ρ = P × M/R × T

M = ρ × R × T/P

M = 0.087 g/L × (0.0821 atm.L/mol.K) × 623 K/1 atm = 4.5 g/mol

Step 2: Calculate the density of the gas at STP

At standard temperature (T = 273.15 K) and standard pressure (P = 1 atm), the density of the gas is:

ρ = P × M/R × T

ρ = 1 atm × 4.5 g/mol /(0.0821 atm.L/mol.K) × 273.15 K = 0.20 g/L

In those portions, the heat supplied to the substance by the heater does not lead to a temperature rise as intermolecular forces are broken.

When a substance is heated, we normally expect that its temperature will rise as a consequence.

However, heat may be supplied to a substance but its temperature does not rise owing to the fact that the heat energy supplied is used to break intermolecular bonds.

This occurs during fusion and boiling. The heat supplied at these point does not result in temperature rise since it is used to break intermolecular bonds. The temperature remains steady during these processes as shown by the two flat portions on the graph in the image attached to the question. This heat supplied is known as the latent heat.

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Answer:

The answer for me was "These show where changes of state are occuring"

Explanation:

I got it right

Answer:

The pH of the buffer is 4.77

Explanation:

Using Henderson-Hasselbalch equation we can solve the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

Where pH is the pH of the buffer

pKa is -log Ka = 5.056

[A⁻] = [NaA] = 0.2M

[HA] = 0.39M

Replacing:

pH = 5.056+ log [0.2] / [0.39]

pH = 4.77

Answer:

MP hippopotamus

Explanation: I'm in the fifth grade so yeah I really don't know this so I'm just going to say some random stuff and white cheddar mac and cheese warm TV perfect back MD 11443 to 2885 eleven 12:20 to 11 132 0.24 answer

Answer:

mass no = 70 amu

mass no = neutrons+ protons

pls mark me as the brainliest

Explanation:

The statement that is true if the ΔEsys = -100 J is that the system looses 100J  of energy which is gained by the surroundings.

Note that the study of energy is what we call thermodynamics. We should note that according to the laws of thermodynamics, energy can not be created nor destroyed but can be converted from one form to another.

This implies that the energy that is lost by the system must be gained by the surroundings since there can never be energy that goes to waste in the system.

Recall that the universe is composed of the system and the surroundings and the energy that is lost by the system must be gained by the surroundings and vice versa. This would now be our guide in deciding which statement is right above from what we have in the question here.

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The preferred arrangement of electrons in a molecular structure can be determined by calculating the electronic configuration of each atom in the molecule.

What is electronic configuration?

The electronic configuration of an atom is determined by the number of protons in the nucleus and the specific rules governing the filling of energy levels and orbitals. The electronic configuration is usually represented using a notation that indicates the number of electrons in each energy level or orbital.

what is delocalized electron ?

Delocalized electrons are electrons that are not restricted to a specific location or region in a molecule or material, but instead are spread out over multiple atoms or molecules. In other words, delocalized electrons are free to move throughout a larger region instead of being confined to a single atom or bond.

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Answer:

D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Explanation:

Step 1: Given data

Molarity (M): 2.00 M

Volume (V): 500 mL = 0.500 L

Molar mass of NaCl: 58.44 g/mol

Step 2: Calculate the required moles of NaCl

We will use the following expression.

n = M × V

n = 2.00 mol/L × 0.500 L

n = 1.00 mol

Step 3: Calculate the mass corresponding to 1.00 moles of NaCl

1.00 mol × 58.44 g/mol = 58.44 g

Step 4: Describe the procedure to prepare the solution

Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Answer:

D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Explanation:

I got it right in class!

Hope  this helps!! :))

Answer:

1.5236414197340638

Answer:

Tings that effect weather is basically the following:

Answer:

the liquid becomes equal to the rate of condensation

Explanation:

ive come across this question before! and i think its right! :D

The vapor pressure of a liquid at a provided temperature is measured when the rate of evaporation of a liquid evolves equally to the rate of condensation.

Evaporation is the procedure by which water transforms from a liquid to a gas or vapor.

Evaporation is the primary route that water moves from the liquid circumstances around into the water cycle as atmospheric water vapor.

When a molecule around the surface absorbs adequate energy to overwhelm the vapor pressure, it will exit and join the surrounding air as a gas.

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Answer:

310K

Explanation:

Rearrange PV=nRT to get T=PV/nR

T=(2.0L)(0.75atm)/(0.5mol)(0.08206)

=36.5 or 37

add 273 for K to get

310

Answer:

The reaction N2 + 3H2 → 2NH3 is an exothermic reaction, which means that it releases heat. The amount of energy released is called the enthalpy of reaction, and it is typically measured in kilojoules per mole (kJ/mol). The enthalpy of reaction for the Haber-Bosch process, which is the industrial process used to produce ammonia, is -46.2 kJ/mol. This means that for every mole of ammonia produced, 46.2 kJ of heat is released.

The energy released during the Haber-Bosch process is used to heat the reactants and to drive the reaction forward. The reaction is exothermic because the bonds in the products (NH3) are stronger than the bonds in the reactants (N2 and H2). When the reactants are combined, the energy released when the bonds in the products form is greater than the energy required to break the bonds in the reactants. This excess energy is released as heat.

The Haber-Bosch process is a very important industrial process, and it is used to produce ammonia on a large scale. Ammonia is used in a variety of products, including fertilizers, explosives, and plastics. The exothermic nature of the Haber-Bosch process makes it a very efficient way to produce ammonia.

Explanation:

Answer:

C. AgNO3 + LICI - AgCl + LINO3

Explanation:

Here the chemical equation for double displacement reaction is

AgNO3 + LICI - AgCl + LINO3

The reaction in which two compounds react together to form two other compounds by mutual exchange of their ions is called double displacement reaction.

Hope it will help :)

A chemical equation is a symbolic representation of a chemical reaction in terms of the symbols and formulae. Among the given equations, AgNO₃ + LICI  → AgCl + LINO₃. The correct option is C.

A double displacement reaction is a kind of reaction in which one part of the reactant is replaced by another part of the reactant. In this reaction the positive and negative ions of two ionic compounds exchange places to form two new compounds.

The double displacement reaction is generally found between the substances in aqueous solution. A precipitate formation occurs in this reaction where the cations of one reactant combines with the anions of the other reactant to form insoluble compound.

The general form of the double displacement reaction is:

AB + CD → AD + CB

Here the double displacement reaction is:

AgNO₃ + LICI  → AgCl + LINO₃

Thus the correct option is C.

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CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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Answer: \(H_2\) < \(CO\) < \(O_2\) < \(CO_2\) < \(CL_2\)

Explanation:

According to avogadro's law, 1 mole of every substanceweighs equal to its molecular mass and contains avogadro's number \(6.023\times 10^{23}\) of particles.

To calculate the moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}\)

1. Mass of \(H_2=moles\times {\text {Molar mass}}=0.50moles\times 2g/mol=1g\)

2. Mass of \(O_2=moles\times {\text {Molar mass}}=0.50moles\times 32g/mol=16g\)

3. Mass of \(Cl_2=moles\times {\text {Molar mass}}=0.50moles\times 71g/mol=35.5g\)

4. Mass of \(CO_2=moles\times {\text {Molar mass}}=0.50moles\times 44g/mol=22g\)

5. Mass of \(CO=moles\times {\text {Molar mass}}=0.50moles\times 28g/mol=14g\)

Thus the flasks of gases in order of increasing grams of gas is:

\(H_2\) < \(CO\) < \(O_2\) < \(CO_2\) < \(CL_2\)

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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Answer:

the answer is C. Exothermic

Answer:

Option C: exothermic

Explanation:

Exothermic means to release heat out to surroundings.

Answer:

C.

Explanation:

They will need to know the influence of gravitational force on objects because gravity can affect an objects weight.

Answer:

121 K

Explanation:

Step 1: Given data

Step 2: Convert "-1.4°C" to Kelvin

We will use the following expression.

K = °C + 273.15 = -1.4°C + 273.15 = 271.8 K

Step 3: Calculate the final temperature of the gas (T₂)

Assuming ideal behavior and constant pressure, we can calculate the final temperature of the gas using Charles' law.

V₁/T₁ = V₂/T₂

T₂ = V₂ × T₁/V₁

T₂ = 35.3 mL × 271.8 K/79.5 mL = 121 K

Answer:

Liquid–liquid extraction

Explanation: