8. A man with an open parachute falls to Earth at constant speed. The following forces act: 9 P the upward force of the parachute on the man Q the upward force of the man on the Earth R the downward force of the Earth on the parachute S the downward force of the man on the parachute. Which two forces are a Newton's third law pair? A. P and Q 9 ● B. P and R C. P and S D. Q and R​

Answers

Answer 1

Answer:

Explanation:

According to Newton's third law, for every action, there is an equal and opposite reaction. This means that if force A acts on object B, then there must be a force that object B exerts on object A that is equal in magnitude but opposite in direction. Therefore, the two forces that are a Newton's third law pair are P and Q, as they are the forces that the parachute and the man exert on each other in opposite directions.

R and S are not a Newton's third law pair because they are not acting on the same objects. R is the force of the Earth on the parachute, while S is the force of the man on the parachute. These forces are not equal and opposite, as they are acting on different objects.


Related Questions

the resistance of a wire the resistance of a wire of length 100 cm and a diameter of 0.3 mm is found to be 3.0 ohms calculate the resistivity and conduct conductivity ​

Answers

Answer:

The resistivity of this wire is approximately \(2.1\times 10^{-7}\; \rm \Omega \cdot m\).

The conductivity of this wire is approximately \(4.7\times 10^6\; \rm (\Omega \cdot m)^{-1}\).

Assumption: the perpendicular cross-section of this wire is circular.

Explanation:

Convert all unit to standard ones:

Length of this wire: \(l = 100\; \rm cm = 1.00\; \rm m\).Diameter of this wire: \(0.3\; \rm mm = 3\times 10^{-4}\; \rm m\).

Assume that a wire has a resistivity of \(\rho\), a length of \(l\), and a cross-section area of \(A\). The formula for the resistance of this wire would be:

\(R = \displaystyle \frac{\rho \cdot l}{A}\).

Rearrange this equation to find an expression for \(\rho\), the resistivity of this wire:

\(\displaystyle \rho = \frac{R\cdot A}{l}\).

For the wire in this question, both length \(l\) and resistance \(R\) are already given. However, the cross-section area \(A\) of this wire needs to be calculated from its diameter, \(d\):

\(A = \displaystyle \pi\, \left(\frac{d}{2}\right)^2 \approx 7.08\times 10^{-8}\; \rm m^2\).

Calculate the resistivity of this wire:

\(\displaystyle \rho = \frac{R\cdot A}{l} \approx \frac{3.0\; \Omega\times 7.08\times 10^{-8}\; \rm m^2}{1.00\; \rm m} \approx 2.1\times 10^{-7}\; \rm \Omega\cdot m\).

The conductivity of a material is the reciprocal of its resistivity:

\(\displaystyle C = \frac{1}{\rho} \approx \frac{1}{2.1\times 10^{-7}\; \Omega\cdot m}\approx 4.7\times 10^{6}\; \rm (\Omega \cdot m)^{-1}\).

a double-decker london bus (figure 1) might be in danger of rolling over in a highway accident, but at the low speeds of its urban environment, it's plenty stable. the track width is 2.05 m. with no passengers, the height of the center of gravity is 1.45 m, rising to 1.73 m when the bus is loaded to capacity. What are the critical angles for both the unloaded and loaded bus?

Answers

When the bus is fully loaded, the center of gravity rises to 1.73 m, and the critical angles are 35.3 degrees for the unloaded bus and 30.6 degrees for the loaded bus, respectively.

Center of gravity: What is it?

Theoretically, the body's total weight is concentrated at a location called the center of gravity.

What distinguishes the center of mass from the center of gravity?

The main distinction between the centers of mass and gravity is that the center of gravity refers to the location where the total weight of the body is balanced, whereas the center of mass refers to the location where the body's complete mass is directed.

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You spit a wad of paper horizontally
from a height of 1.8 m. The wad
leaves your mouth with a velocity of
6 m/s. How long does it take the
wad to hit the ground?

Answers

Approximately 0.606 seconds (I rounded)

Since the wad was projected in the horizontal direction, it’s velocity will have no impact on the change in the y axis.
You spit a wad of paper horizontallyfrom a height of 1.8 m. The wadleaves your mouth with a velocity

A person is driving down a country lane at 25 m/s, when a deer suddenly jumps in front of the car. The deer is 75 m ahead and when the driver hits the brakes, the car slows at a rate of 4.20 m/s each second. Does the car hit the deer?

Answers

Answer:

The car does not hit the deer.

Explanation:

In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

s = distance covered by car before stopping = ?

a = deceleration of car = - 4.2 m/s²

Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity of the Car = 25 m/s

Therefore,

2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²

s = (- 625 m²/s²)/(-8.4 m/s²)

s = 74.4 m

So, the car stops in 74.4 m, while the deer is at a distance of 75 m.

Hence, the car does not hit the deer.

Initial velocity=25m/s=uFinal velocity=0m/s(As it stopped)=vDeacceleration=a=-4.2m/s^2Distance of deer=75mDistance at where car stops=s

Using third equation of kinematics

\(\boxed{\sf v^2-u^2=2as}\)

\(\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s\)

\(\\ \sf\longmapsto -625=-8.4s\)

\(\\ \sf\longmapsto 8.4s=625\)

\(\\ \sf\longmapsto s=\dfrac{625}{8.4}\)

\(\\ \sf\longmapsto s=74.4m\)

AS IT IS LESS THAN 75M HENCE CAR DOESNOT HIT THE DEAR.

A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures

Answers

Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

What will be the nature of the image formed from both a convex lens and a concave
lens of 20 centimeter focus distance, when the object is placed at a distance of
10 centimeters?​

Answers

Answer:

Explanation:

Using the lens formula

1//f = 1/u+1/v

f is the focal length of the lens

u is the object distance

v is the image distance

For convex lens

The focal length of a convex lens is positive and the image distance can either be negative or positive.

Given f = 20cm and u = 10cm

1/v = 1/f - 1/u

1/v = 1/20-1/10

1/v = (1-2)/20

1/V = -1/20

v = -20/1

v = -20 cm

Since the image distance is negative, this shows that the nature of the image formed by the convex lens is a virtual image

For concave lens

The focal length of a concave lens is negative and the image distance is negative.

Given f = -20cm and u = 10cm

1/v = 1/f - 1/u

1/v = -1/20-1/10

1/v = (-1-2)/20

1/V = -3/20

v = -20/3

v = -6.67 cm

Since the image distance is negative, this shows that the nature of the image formed by the concave lens is a virtual image

Question 1

Describe the path light takes as it travels through air and into glass

Question 2

Explain the brightness of light using the wave model of light

Answers

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Question 1 :
The path light bends as it travels through air and into glass.
What is light?
The light is the ray form of energy obtained from the Sun.
The path of light will look like bended when it has crossed the interface of two medium.
As. the light ray falls on the surface of glass travelling through air, the ray appears to bend after refraction.
Thus, the path of light bends as it travels through air and into glass.
———————
Question 2 :
According to the wave theory of light, the energy of radiation depends only on the intensity or wave amplitude (brightness), not the frequency (what type of light; e.g red light or green light; visible light or gamma) According to the particle theory of light states the energy of radiation depend only on the frequency

The current source has an EMF of 14 V and an internal resistance of 1Ω. Two resistors with resistances of 3Ω are connected to the current source. How much current flows in the circuit?

Answers

Answer:

Explanation:

To find the current flowing in the circuit, we can use Ohm's Law and Kirchhoff's circuit laws.

Ohm's Law states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):

I = V / R

In this case, the voltage (V) is the electromotive force (EMF) of the current source, which is 14 V. The total resistance (R) in the circuit is the sum of the internal resistance (r) and the resistances of the two resistors (R1 and R2):

R = r + R1 + R2

Given that the internal resistance (r) is 1Ω and each resistor (R1 and R2) has a resistance of 3Ω, we can substitute these values into the equation:

R = 1Ω + 3Ω + 3Ω = 7Ω

Now we can calculate the current (I):

I = V / R = 14 V / 7Ω = 2 A

Therefore, the current flowing in the circuit is 2 Amperes.

Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?

Answers

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Why can’t human males be carriers for sex linked (x-linked) disorders?

Answers

Answer:

This is because the X chromosome is large and contains many more genes than the smaller Y chromosome. In a sex-linked disease, it is usually males who are affected because they have a single copy of X chromosome that carries the mutation.

Explanation:

Which of objects above is the furthest away from earth?

Group of answer choices

The Andromeda Galaxy.

The cluster of galaxies.

Saturn.

the Voyager spacecraft.

Answers

The object that is furthest away from earth is the cluster of galaxies. Option B

What is the solar system?

The solar system is arrangement of arrangement of the sun and the planets. The sun lies at the center of the solar system. This is known as the heliocentric model. The planets surround the sun in orbits.

Now as we move across the earth going far deeper into the outer space, we would find out that the object that is furthest away from earth is the cluster of galaxies. Option B

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7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -​

Answers

According to the question the tension in each wire is 1.96 N.

What is tension?

Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.

The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.

The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.

Therefore, the tension in each wire is:

T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)

= 1.96 N

Therefore, the tension in each wire is 1.96 N.

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Which is an SI base unit that makes up part of the unit of energy?

candela

ampere

kelvin

kilogram

Answers

The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

What is a unit of measurement?

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole

The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²

Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

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Gas in a container is at a pressure of 1.6 x 10^5 Pa and a volume of 4.0 m^3. What is the work done by the gas if it expands at a constant pressure to twice its initial volume?

Answers

Answer: W = 6.4 x 10^5

Explanation: W = P x AV +(1.6x10^5 PA)(4M)

                                                        W = 6.4 x 10^5

Gas in a container is at a pressure of 1.6 x 10^5 Pa and a volume of 4.0 m^3. What is the work done by

5. What occurs when an enzyme and a substrate interact at an
active site?
a. Activation energy is reduced.
b. The products are bound irreversibly.
c. The enzyme is changed by the reaction.
d. Activation energy is increased.

Answers

Answer:

B

Explanation:

The enzime's active site bindes to the substrate.... when an enzime binds to a substrate it forms a enzime-substrate complex

When an enzyme and a substrate interact at an active site, the products are bound irreversibly. Therefore, option B is correct.

What are enzymes?

Enzymes can be described as proteins that act as biological catalysts by accelerating reactions. The enzymes may act on the molecules called substrates, and the enzyme changes the substrates into different molecules known as products.

All metabolic processes require enzyme catalysis to occur at rates fast enough to sustain life. Metabolic pathways will depend upon enzymes to catalyze each step.

Enzymes catalyze more than 5,000 biochemical reaction types. Enzymes enhance reaction rates by lowering their activation energy. Some enzymes make their conversion of substrate to product occurs.

Enzymes are much larger than substrates, they can have 62 amino acid residues to over 2,500 residues in the animal fatty acid synthase. The catalytic site is located next to binding sites where residues are oriented to the substrates. The catalytic site and binding site compose the active site.

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Find a function that models the simple harmonic motion having the given properties. Assume that the displacement is at its maximum at time t = 0.
amplitude 6.45 in., frequency 30 Hz

Answers

The function for the simple harmonic motion having the given properties. Assume that the displacement is at its maximum at time t = 0 is y = 6.45 cos(60π*t).

Moving an object back and forth along a line is known as simple harmonic motion.

See a pendulum, for instance. It follows the same path when we swing it back and forth. Oppositions are what these motions are. A simple harmonic motion example is the oscillations of a pendulum.

\(y=Acos(Bt)\)

has amplitude |A| and period 2π/B, and reaches its maximum at t=0.

So we choose A = 6.45

Period = 1/frequency

Period = 2π/B = 1/30

2π/B = 1/30

B = 60π

y = A.cos(Bt)

y = 6.45 cos(60π*t)

Therefore, The function for the simple harmonic motion is y = 6.45 cos(60π*t).

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An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of â3.45Ã10^â3 V .The charge and the mass of an alpha particle are qα = 3.20Ã10^â19 C and mα = 6.68Ã10â27 kg , respectively.

Mechanical energy is conserved in the presence of which of the following types of forces?

a. electrostatic
b. frictional
c. magnetic
d. gravitational

Answers

Answer:

Speed = 575 m/s

Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.

Explanation:

Given :

Potential difference, U = \($-3.45 \times 10^{-3} \ V$\)

Mass of the alpha particle, \($m_{\alpha} = 6.68 \times 10^{-27} \ kg$\)

Charge of the alpha particle is, \($q_{\alpha} = 3.20 \times 10^{-19} \ C$\)

So the potential difference for the alpha particle when it is accelerated through the potential difference is

\($U=\Delta Vq_{\alpha}$\)

And the kinetic energy gained by the alpha particle is

\($K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2 $\)

From the law of conservation of energy, we get

\($K.E. = U$\)

\($\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$\)

\($v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$\)

\($v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$\)

\($v_{\alpha} \approx 575 \ m/s$\)

The mechanical energy is conserved in the presence of the following conservative forces :

-- electrostatic forces

-- magnetic forces

-- gravitational forces

What is the wavelength of this wave

What is the wavelength of this wave

Answers

\(\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the Concept of the Waves.

Wavelength is the distance between two consecutive crest or trough.

hence, here the distance is 10cm

So the wavelength is 10cm

===> 10 cm

A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground

Answers

Answer:

14.68m/s

Explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

\(F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )\)

\(M g h = (\frac{1}{2} ) M ( V^2 - U^2 )\)

\(g h = (\frac{1}{2} ) ( V^2 - U^2 )\)

\(V^2 - U^2 = 2gh\)

\(V^2 - 0 = 2gh\)

\(V = \sqrt{2 g h}\)

\(= \sqrt{2\times9.8\times11}\)

= 14.68m/s

A cars mass is 950kg and it travels at a speed of 35 m/s when it rounds a flat curve of radius 215 m.
a. Determine the value of the frictional force exerted on the car.

b. Determine the value of the coefficient of friction between the tires and the road.

Answers

(a) It's the force of (static) friction that keeps the car on the road and prevents it from skidding, and this friction is directed toward the center of the curve.

Recall that centripetal acceleration has a magnitude a of

a = v ² / R

where

v = tangential speed

R = radius of the curve

so that

a = (35 m/s)² / (215 m) ≈ 5.69767 m/s² ≈ 5.7 m/s²

Parallel to the road, the only force acting on the car is friction. So by Newton's second law, we have

F = Fs = m a

where

Fs = magnitude of static friction

m = mass of the car

Then

Fs = (950 kg) (5.7 m/s²) ≈ 5412.79 N ≈ 5400 N

(b) Perpendicular to the road, the car is in equilbrium, so its weight and the normal force of the road on the car are equal in magnitude. By Newton's second law,

N - W = 0

where

N = magnitude of normal force

W = weight

so that

N = W = m g = (950 kg) (9.8 m/s²) = 9310 N

Friction is proportional to the normal force by a factor of µ, the coefficient of static friction:

Fs = µ N

Assuming 35 m/s is the maximum speed the car can travel without skidding, we find

µ = Fs / N = (5400 N) / (9310 N) ≈ 0.581395 ≈ 0.58

A uniform metal bar of length 6m and mass 100kg rest with its upper end against a smooth vertical wall and with its lower end on a rough surface of coefficient of friction 0.32.what is the maximum angle made with the horizontal to which the bar can be enclined without sliding?

Answers

Answer:

Let F1x = force of wall on ladder

F1x = F2x    the force of friction  (balances horizontal forces)

F2y = W      balance weight of ladder

F2x = μ F2y       force of friction on ladder

F1x L sin θ = W L / 2 cos θ     balance torque about point F2

tan θ  = W / (2 F1x)     previous equation

Now     μ W = μ F2y = F2x = F1x   from above

So tan θ  = W / (2 μ W) = 1 / (2 μ ) = 1 / .64

tan θ = 1.56

θ = 57.4 deg

Rachel and Sarah are on a bus travelling at 5 mph past John who is standing on the sidewalk. Rachel then throws a ball
forward to Sarah at a speed of 20 mph in the frame of reference of the bus. From the point of view of John, the ball is traveling
with a speed of
x
Select one:
a. 20 mph
b. 25 mph
c. 15 mph
d. 5 mph

Answers

Answer:

I think C

Explanation:

Since the bus is moving away from John.

{C - V}.

Select the correct answer.
Why are the requirements to become a congressional representative and a senator different?
A.
The framers didn’t want senators to worry about their constituents as often as representatives do.
B.
The framers gave senators more lawmaking powers and responsibilities than representatives.
C.
The framers wanted senators to be more mature and more experienced than representatives.
D.
The framers thought senators and representatives should have reasons to argue with each other.

Answers

The framers wanted senators to be more mature and more experienced than representatives. (C)

Answer:

C -> The framers wanted senators to be more mature and more experienced than representatives.

find the electric field strength 58 cm from the sphere's center. express your answer in meganewtons per coulomb.

Answers

The electric field strength is 58 cm from the sphere's center. express your answer in meganewtons per coulomb is \({E_{19cm}} = 1.0517 \times {10^6}N/C\end{array}$$\)

The formula for the electric field inside a solid sphere is:

\($$\begin{array}{l}{E_{19cm}} = \frac{{kQr}}{{{R^3}}}\\{E_{19cm}} = \frac{{\left( {9 \times {{10}^9}N{m^2}/{C^2}} \right)\left( {15\mu C \times \frac{{{{10}^{ - 6}}C}}{{1\mu C}}} \right)\left( {19cm \times \frac{{{{10}^{ - 2}}m}}{{1cm}}} \right)}}{{{{\left( {29cm \times \frac{{{{10}^{ - 2}}m}}{{1cm}}} \right)}^3}}}\\{E_{19cm}} = 1.0517 \times {10^6}N/C\end{array}$$\)

An electric-powered subject (occasionally E-discipline) is the bodily discipline that surrounds electrically charged particles and exerts a force on all differently charged particles in the field, either attracting or repelling them. It additionally refers to the bodily discipline of a device of charged debris. electric powered fields originate from electric charges and time-varying electric-powered currents. electric powered fields and magnetic fields are each manifestation of the electromagnetic subject, one of the 4 fundamental interactions (additionally referred to as forces) of nature.

Electric fields are vital in lots of areas of physics and are exploited in electrical generation. In atomic physics and chemistry, for example, the electrical field is the appealing force maintaining the atomic nucleus and electrons collectively in atoms. it's also the force answerable for chemical bonding among atoms that bring about molecules.

The electrical field is described as a vector discipline that pals to each factor in the area the electrostatic (Coulomb) force per unit of fee exerted on an infinitesimal advantageous test fee at relaxation at that factor. The derived SI unit for the electrical discipline is the volt in line with the meter (V/m), which is equal to the newton per coulomb (N/C).

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a book weighing 1.0 newton is lifted 2m. how much work was done?

Answers

Answer:

Work done, W = 2 J

Explanation:

Given that,

Weight of a book, W = F = 1 N

It is lifted to a height of 2 m

We need to find the work done. It can be calculated using the formula as follows :

W = F d

Put all the values,

W = 1 N × 2 m

W = 2 J

So, 2J of work was done.

person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?

person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and

Answers

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

consider a parallel plate capacitor with an electric field of 2500 N/C.
An electron is launched horizontally at a speed of 210000 m/m in the plates, exactly 3.6cm above the positive plate. calculate the horizontal distance ,x, at which the electron will collide with the plate.

consider a parallel plate capacitor with an electric field of 2500 N/C.An electron is launched horizontally

Answers

The electric field will cause the electron to experience a force of F = qE = -eE, where e is the electron charge and E is the electric field.

Which the electron will collide with the plate?

The force will cause the electron to accelerate in the direction of the negative plate, so the equation for its horizontal motion is:

x = x_0 + (v_0 * t) + (1/2 * a * t^2)

where x_0 is the initial distance from the plate, v_0 is the initial velocity, t is the time, and a is the acceleration due to the electric field.

We can substitute our known values:

x = 3.6 cm + (210000 m/s * t) - (1/2 * (2500 N/C) * t^2)

Since the electron will eventually collide with the plate, we can set the equation equal to 0 and solve for t:

0 = 3.6 cm + (210000 m/s * t) - (1/2 * (2500 N/C) * t^2)

t = 0.28 seconds

Then we can substitute this value for t back into the equation to find the distance x:

x = 3.6 cm + (210000 m/s * 0.28 s) - (1/2 * (2500 N/C) * 0.28^2 s^2)

x = 4.04 cm.

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A student builds an electromagnet using a battery, an iron nail, and some insulated wire. The wire is wrapped around the nail 50 times, then connected to the
battery. What changes could the student make to increase the strength of the electromagnet?
1. wrap more wire around the nail
2. increase the voltage of the battery
3. use a switch to turn the electromagnetic on and off
4. increase the size of the nail

A. 1 and 2
B. 2 and 4
C. 1,2 and 4
D. 1,2,and 3

Answers

Answer:

a

Explanation:

its right

To increase the electromagnet's strength, the student must enlarge the nail, wrap more wire around the nail, and increase the voltage of the battery. Option c is the correct answer.

How does an electromagnet work?The mechanics of an electromagnet are not overly complicated. It is accomplished by wrapping a length of conductive wire, usually copper, around a metal object.Until electricity is introduced, this appears to be nothing more than a jumbled collection of parts, similar to Frankenstein's monster. An electromagnet, on the other hand, does not require a storm to be activated. A current is introduced and flows through the wire, which can come from a battery or another source of power.As a result of the magnetic field created around the coiled wire, the metal is magnetized as if it were a permanent magnet. Electromagnets are useful because they can be activated and deactivated by closing and opening a circuit.

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Which of these changes will decrease the acceleration of an object? Select the two correct answers

increasing the applied net force

decreasing its mass

increasing its mass

decreasing the applied net force​

Answers

Answer:

✔️From Newton's second law of motion we know that

✔️acceleration is inversely proportional to the mass of the body

✔️Here in this question increasing the mass of body will decrease its acceleration.

Explanation:

Hope it will help you :)

A hydraulic press has a safety feature which consists of a hydraulic cylinder with a piston at one end and a safety valve at the other. The cylinder has a radius of 0.0200 m and the safety valve is simply a 0.00750-m radius circular opening at one end, sealed with a disk. The disk is held in place by a spring with a spring constant of 950 N/m that has been compressed 0.0085 m from its natural length. Determine the magnitude of the minimum force that must be exerted on the piston in order to open the safety valve.

Answers

Answer:

Explanation:

radius of cylinder r₁ = .02 m

radius of safety valve r₂ = .0075 m

force exerted by spring on safety valve = 950 x .0085 = 8.075 N .

Force required on piston of cylinder = F

Applying Pascal's law

8.075 / 3.14 x .0075²  =  F / 3.14 x .02²

F = 8.075 x .02² / .0075²

= 8.075 x 7.111

= 57.42 N .

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