The vectors v2,v3 must lie on the plane that is perpendicular to the vector v1. So consider the subspace. W={[xyz]∈R3|[xyz]⋅[2/32/31/3]=0}.
We can use the point (0, 0, 0) in this case as the point on the plane that makes the equation easy to solve. Therefore, we have:[2x + 3y + z = 0]as the equation of the plane.
The vectors v2 and v3 are expected to lie on the plane that is perpendicular to the vector v1 and so, it follows that the subspace of:
W={[xyz]∈R3|[xyz]⋅[2/32/31/3]=0} can be determined.
In the subspace of
W={[xyz]∈R3|[xyz]⋅[2/32/31/3]=0}
where vectors v2 and v3 are expected to lie, the dot product is zero, meaning that v2 and v3 are perpendicular to the vector [2,3,1]. We know that the vector [2,3,1] lies on the plane perpendicular to the subspace of W. Thus, the vector [2,3,1] is the normal vector of the plane.
To find the equation of the plane, we use the general equation given as:[ax + by + cz = d]
Where (a, b, c) represents the normal vector and the point (x, y, z) represents any point on the plane. We can use the point (0, 0, 0) in this case as the point on the plane that makes the equation easy to solve. Therefore, we have:[2x + 3y + z = 0]as the equation of the plane. Answer: [2x + 3y + z = 0].
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Point A is the incenter of triangle DEF. What is the length of NA?
A. 2 units
B. 9 units
C. 11 units
D. 14 units
Answer: B
Step-by-step explanation: Got a 100 on the test
AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extented intersect at a point E. Prove that angle AEB = 60°
proof:
CD= radius r
OC=OD= radius
OCD is equilateral triangle
∠DCO=∠COD=∠ODC=60 degrees
∠ACB=90 degrees
(Angle in semicircle)
∠DOC=2∠DBC (half angle)
∠DBC=30 degrees
∠ECB+∠BCA=180 degrees
(linear pair)
∠ECB=180−90=90 degrees
In △ECB
∠CEB+∠ECB+∠CBE=180 degrees
∠CEB+90+30=180
∠CEB=60 degrees
*This is the full proof and ask me questions in comments if you have anything you don't understand! Also I would appreciate if you give me brainlliest!!
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Completely factor the following expressions.
Answer:
assuming that the equations are equal to zero the answers would be
3 , -3 , 5
Step-by-step explanation:
please help!!! i just need this one
Answer:
\(p = x \\ r = 6\% \\ t = 2yrs\)
\(p = 1600\)
please see the attachment
Answer:
P = $1600
Step-by-step explanation:
We have to use the equation:
\(\boxed{I = Prt}\) .
We know that:
• I = $192
• P = ?
• r = 6% = 0.06
• t = 2 years
Substituting these values into the equation:
\(192 = P \times 0.06 \times 2\)
Solving for P:
\(P = \frac{192}{0.06 \times 2}\)
\(P = \bf \$1600\)
The function s(t) describes the motion of a particle along a line s(t) = t3-9t2 + 8t (a) Find the velocity function of the particle at any time t2 0 v(t) = (b) Identify the time intervals on which the particle is moving in a positive direction. (Enter your answer using interval notation.) (c) Identify the time intervals on which the particle is moving in a negative direction. (Enter your answer using interval notation.) (d) Identify the time(s) at which the particle changes direction.
(a) The velocity function of the particle is v(t) = \(3t^2 - 18t + 8.\) (b) The particle is moving in a positive direction on the intervals (0, 2) and (6, ∞). (c) The particle is moving in a negative direction on the intervals (-∞, 0) and (2, 6). (d) The particle changes direction at the time(s) t = 0, t = 2, and t = 6.
(a) To find the velocity function, we differentiate the position function s(t) with respect to time. Taking the derivative of s(t) =\(t^3 - 9t^2 + 8t\) gives us the velocity function v(t) = \(3t^2 - 18t + 8.\)
(b) To determine when the particle is moving in a positive direction, we look for the intervals where the velocity function v(t) is greater than zero. Solving the inequality \(3t^2 - 18t + 8\) > 0, we find that the particle is moving in a positive direction on the intervals (0, 2) and (6, ∞).
(c) Similarly, to identify when the particle is moving in a negative direction, we examine the intervals where v(t) is less than zero. Solving \(3t^2 - 18t + 8\)< 0, we determine that the particle is moving in a negative direction on the intervals (-∞, 0) and (2, 6).
(d) The particle changes direction when the velocity function v(t) changes sign. By finding the roots or zeros of v(t) = \(3t^2 - 18t + 8,\) we discover that the particle changes direction at t = 0, t = 2, and t = 6.
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A truck can be rented from Company A for $90 a day plus $0.70 per mile. Company B charges $20 a day plus $0.90 per mile to rent the same truck. Find the
number of miles in a day at which the rental costs for Company A and Company B are the same.
Answer:
335 miles
Step-by-step explanation:
y = 20 + .9 x 350
y = 90 + .7 x 350
Both equations equal 335
Solve for x 5(x + 3) = 4(x-3)
0-18
0-27
O-3
O-6
I need help ASAP
in the 3rd century bc the egyptians used their body parts to measure things.Why do you think peoplebinvented measurement system if body parts can be used to measure?
PLEASE ANSWER IT I REALLY NEED THANKYOU
A 3-gallon bottle of fabric softener costs $33.24. What is the price per quart?
Answer:
$2.77 per quart.
Step-by-step explanation:
There are four quarts in a gallon.
4 * 3 = 12
There are 12 quarts in 3 gallons.
\(\frac{price}{quart} =\frac{33.24}{12}=\frac{33.14/12}{12/12}=\frac{2.77}{1}=\boxed{2.77}\)
The price per quart should be $2.77.
Hope this helps.
please help wth my mathsssssssss
Answer:
A = 1
B = 5
Step-by-step explanation:
What are the coordinates of the vertex of the graph of f (x)=2x - 3|?
Answer:
\((\frac 32, 0)\)
Step-by-step explanation:
I'm assuming that there was a | at the beginning so it's \(f(x) = |2x-3|\). With this kind of plots you get angular points where the graph of the "original" function - ie the one without the absolute value - would cross the x-axis. In this case, when \(2x-3 = 0 \rightarrow x= \frac32\)
At the instant shown, the shaft and plate rotates with an angular velocity of 19 rad/s and angular acceleration of 9 rad/s2 0.6 m 0.2 m 0.4m 0.3 m 0.3 m 0.4 m Part A eterminethe wocl a n D sea c Enter the ", y, and Z components of the velocity separated by commas vec m/s Submit Request Answer Part B Determine the acceleration of point D located on the corner of the plate at this instant. Enter the , y, and Z components of the velocity separated by commas vec m/s Submit Request Answer
The acceleration components of point D are, ax = 3.6 m/s², ay = 6.4 m/s², az = -1.14 m/s²
At the instant shown, the shaft and plate rotates with an angular velocity of 19 rad/s and angular acceleration of 9 rad/s2. The given diagram is shown below. Angular velocity (w) = 19 rad/sAngular acceleration (α) = 9 rad/s²Plate dimension AB = 0.6 m, BC = 0.2 m, CD = 0.4 m, DA = 0.3 m, AE = 0.3 m and EF = 0.4 m.
Determine the wocl and Dsea of Enter the ", y, and Z components of the velocity separated by commas vec m/sThe velocity components for point D can be calculated using the following formula.Vd = R x wWhere R is the position vector of D relative to the origin.
According to the given diagram, the position vector of point D relative to the origin is, R = 0.2i + 0.4j + 0.3kThe velocity of point D can be calculated as follows.Vd = R x w = 0.2i + 0.4j + 0.3k x 19The cross product of R and w can be calculated as follows.i j k 0.2 0.4 0.3 0 19 0 = [(0.4 × 0) - (0.3 × 19)] i - [(0.2 × 0) - (0.3 × 0)] j + [(0.2 × 19) - (0.4 × 0)] kVd = -5.7i + 6.8kThus, the velocity components of point D are, Vx = -5.7 m/s, Vy = 0 m/s, Vz = 6.8 m/s
Determine the acceleration of point D located on the corner of the plate at this instant. Enter the, y, and Z components of the velocity separated by commas vec m/sThe acceleration components of point D can be calculated using the following formula.aD = R x α + w x (w x R)Where R is the position vector of D relative to the origin.
According to the given diagram, the position vector of point D relative to the origin is, R = 0.2i + 0.4j + 0.3kThe acceleration of point D can be calculated as follows.aD = R x α + w x (w x R) = (0.2i + 0.4j + 0.3k) x 9 + 19 x (19 x (0.2i + 0.4j + 0.3k)) = (0.4k - 0.3j) x 9 + 19 x (0.4 x (0.4j - 0.3k))aD = 3.6i + 6.4j - 1.14k.
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Which one of the following is the graph of:
Answer:
B
Step-by-step explanation:
Correct if wrong
Which expression is NOT equivalent to 27− r?
r −27r −27
(27 −r)+0(27 −r)+0
(27 −r)×1(27 −r)×1
−r+27
Answer:
A. and C.
Step-by-step explanation:
Identify carefully!
What is 100-293?
I WILL GIVE BRAINLIEST
Answer: the answer is -193
suppose you toss 3 coins at one time. what is the probability that exactly two land with heads facing up?
The probability of getting heads is 3/8.
Probability:
Probability is a branch of mathematics that quantifies the likelihood of an event occurring or the likelihood of a statement being true. Probability is a number between 0 and 1, with 0 generally indicating impossibility and 1 indicating certainty. that an event will occur. A simple example is tossing a fair (unbiased) coin. Since the coin is fair, the two outcomes (heads and tails) are equally likely. The probability of heads is the same as the probability of tails. Since no other outcome is possible, the probability of heads or tails is 1/2 (also written as 0.5 or 50%).
Since 3 is a small number, let's list out all possible combinations.
H represents a head while T represents a tail.
3 Heads
HHH
2 Heads
HHT
HTH
THH
1 Head
HTT
THT
TTH
0 Head
TTT
The answer is
3/1+3+3+1=3/8
OR
In general, we will find that the list resembles a particular row of the pascal's triangle.
If you want to know the probability of getting r heads (or tails) from n flips, it is the sum of the rth elements in the n + 1 line. All elements of the series n+1.
\(\left[\begin{array}{ccc}N\\\\R\end{array}\right]\)/ 2ⁿ = \(\frac{n!}{r! * (n - r)!* 2^{n} }\)
n this case,
N =3andR= 2
3!/ 2!×1! × 2³
= 6/ 2× 1 × 8
= 3/8
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Solve for x. -17=-5x+3(x-7) Simplify your answer as much as possible. x=?
Answer:
ANother filthy£50
Step-by-step explanation:
PLEASE HELP I NEED A GOOD GRADE ON THIS
Answer:
B = 1/243
Step-by-step explanation:
1/2, y-intercept 4
Determine the equation of each line
Answer:
\(8x + y = 4\)
Step - by - step explanation:
Standard form of a line X-intercept as a Y-intercept as b is
\( \frac{x}{a} + \frac{y}{b} = 1\)
As X-intercept is \( \frac{1}{2}\) and Y-intercept is 4.
The equation is:
\( \frac{x}{ \frac{1}{2} } + \frac{y}{4} = 1 \\ or \\ 8x + y = 4\)
Graph {8x+y=4[-5.42, 5.83, -0.65, 4.977]}
Hope it helps..
Mark as brainliest..
Match the following items by evaluating the other expressions for x=-2
HELP!
X0= 1
X-2= 1/4
X-1= -1/2
X1= -2
X2= 4
This manufacturing specification is for a metal part that comes in a shelving kit. Part SH-C0524 comes in two sizes, and the acceptable size for each measurement is shown on the diagram and in the table. The inspection log shows the measurement of six parts the manufacturer has produced. Which measurement for SH-C0524-B 250 is out of range?
please help
The measurement for SH-C0524-B 250 that is out of range is given as follows:
A. V.
How to obtain the out of range measurement?From the table given by the third image at the end of the answer, the measurements of SH-C0524-B 250 are given by:
V = 1.07.W = 0.89X = 0.81.Y = 1.48.Z = 2.The ranges for each variable, from the second image, are given as follows:
V: Between 0.95 and 1.05 -> V = 1.07 is out of range.W: Between 0.89 and 0.91 -> 0.89 is in the range.X: Between 0.79 and 0.81 -> 0.79 is in the range.Y: Between 1.45 and 1.55 -> 1.48 is in the range.Z: Between 1.95 and 2.05 -> 2 is in the range.Hence measurement V is out of range, as the range of acceptable values is between 0.95 and 1.05, and option A is correct.
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What is the solution of the equation 3 and minus 2 is equal to 46?
The solution of the equation 3z minus 2 is equal to 46 is 16.
The given equation '3z minus 2 is equal to 46' can be written as
3z - 2 = 46
Now solving for z because the value of z will give the required solution of the given equation. So now finding the z from the equation:
3z = 46 + 2
3z = 48
z = 48/3
z = 16
The value of the z is 16 which represents the solution of the given equation i.e 3z minus 2 is equal to 46.
Therefore it is concluded that the solution of the equation 3z minus 2 is equal to 46 is 16.
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hey broskii's i need help because im d1mb Which of the following numbers is irrational? Select all that apply. √36 √25 √49 √15 √3
√36×25×49×15×3
2×3×5×3×7√5
630√5
verify that the vector xp is a particular solution of the given nonhomogeneous linear system.
x’ = (2 1 1 -1)x+(-5 2); x˅p = (1 3)
To verify that the vector xp is a particular solution of the given nonhomogeneous linear system, we need to substitute xp into the system and check if it satisfies the equation.
The given nonhomogeneous linear system can be written in the form x' = Ax + f, where A is the coefficient matrix (2 1 1 -1) and f is the constant vector (-5 2). The vector xp = (1 3) is a particular solution if it satisfies the equation x' = Ax + f.
Substituting xp into the equation, we get:
x' = (2 1 1 -1) (1 3) + (-5 2)
= (1 -1 2 -8)
Therefore, the left-hand side of the equation is:
x' = (1 -1 2 -8)
And the right-hand side is:
Ax + f = (2 1 1 -1) (1 3) + (-5 2)
= (1 -1 2 -8)
Since the left-hand side is equal to the right-hand side, we can conclude that the vector xp = (1 3) is indeed a particular solution of the given nonhomogeneous linear system.
We have verified that the vector xp = (1 3) is a particular solution of the given nonhomogeneous linear system by substituting it into the equation and checking if it satisfies the equation.
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I would really appreciate it if someone could help me with this, I will give 5 stars. Thank you so much I really appreciate it.
Answer:
Step-by-step explanation:
a:
21 49 70
46 34 80
67 83 150
b: 34+49=83
c:
total no. of students = 150
no of boys who disapproved = 46
probability = 150/46 = 75/23
hope that helps!
Can you please help me I am struggling I will mark brainliest and give 50 points please help me.
in the special case of two degrees of freedom, the chi-squared distribution coincides with the exponential distribution
In the special case of two degrees of freedom, the chi-squared distribution does not coincide with the exponential distribution. The chi-squared distribution is a continuous probability distribution that arises in statistics and is used in hypothesis testing and confidence interval construction. It is defined by its degrees of freedom parameter, which determines its shape.
On the other hand, the exponential distribution is also a continuous probability distribution commonly used to model the time between events in a Poisson process. It is characterized by a single parameter, the rate parameter, which determines the distribution's shape.
While both distributions are continuous and frequently used in statistical analysis, they have distinct properties and do not coincide, even in the case of two degrees of freedom. The chi-squared distribution is skewed to the right and can take on non-negative values, while the exponential distribution is skewed to the right and only takes on positive values.
The chi-squared distribution is typically used in contexts such as goodness-of-fit tests, while the exponential distribution is used to model waiting times or durations until an event occurs. It is important to understand the specific characteristics and applications of each distribution to appropriately utilize them in statistical analyses.
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For years, telephone area codes in the United States and Canada consisted of a sequence of three digits. The first digit was an integer between 2 and 9, the second digit was either 0 or 1, and the third digit was any integer from 1 to 9. How many area codes were possible
This format had 144 possible telephone area codes in the United States and Canada.
We can calculate the number of possible area codes based on the given information by multiplying the number of options for each digit.
There are 8 options for the first digit (2 through 9), 2 options for the second digit (0 or 1), and 9 options for the third digit (1 through 9).
So, the total number of possible area codes is:
8 x 2 x 9 = 144
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Solve each inequality.
||x+4|-7|<5
||3x-1|+5|<1
The solutions for x are x < 16 and x < 7/ 3 respectively
What is absolute value?The absolute value of a real number can be defined as the non-negative value of that number without regard or consideration to its sign.
It is also described as the modulus of a number.
Given the inequality;
||x+4|-7|<5
Take the absolute value
x + 4 + 7 < 5
collect like terms
x < 5 + 4 + 7
Add like terms
x < 16
||3x-1|+5|<1
Take the absolute value
3x + 1 + 5 < 1
collect like terms
3x < 1 + 5 + 1
3x < 7
Make 'x' the subject
x < 7/ 3
Thus, the solutions for x are x < 16 and x < 7/ 3 respectively.
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