9.3+b=−42 , you would subtract 9.3 to isolate the variable.

Given the function:

You can rewrite it as follows:

You need to remember that the y-value is zero when the function intersects the x-axis. Then, you need to make it equal to zero, in order to find the x-intercepts:

Solving for "x", you get these two values:

In order to find the vertex, you can follow these steps:

1. Find the x-coordinate of the vertex with this formula:

To find the value of "a" and "b", you need to multiply the binomials of the equation using the FOIL Method. This states that:

Then, in this case, you get:

Add the like terms:

Notice that, in this case:

Then, you can substitute values into the formula and find the x-coordinate of the vertex of the parabola:

2. Substitute that value of "x" into the function and then evaluate, in order to find the y-coordinate of the vertex:

Therefore, the vertex of the parabola is:

Knowing the x-intercepts and the vertex of the parabola, you can graph it.

Hence, the answer is:

Answer:

The correct answer is: he ate 6 sweets.

Step-by-step explanation:

24 / 4 = 6

Answer:

it's 200

Step-by-step explanation:

that's it's thats the anwrt

Answer:

200

Step-by-step explanation:

\(300 - 100\)

\(subtract ~the~ hundreds~ digit, 3 ~minus ~1, ~which ~ is ~ 2\)\(subtract ~the~ tens~ digit, 0 ~minus ~0, ~which ~ is ~ 0\)

\(subtract ~the~ units~ digit, 0 ~minus ~0, ~which ~ is ~ 0\)

\(put~it~back~into~its~place~value\)

\(300~minus~100~is~ 2 ~0~ 0, 200\)

The probability of landing on the dark blue target is 2/5.

Probability is the ratio of required to the total possible outcomes of an event.

P(dark blue ) = 40/100

divide through by 20

P(dark blue ) = 2/5

Therefore, the probability of landing on target is 2/5

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Answer:

un montón de gente

Step-by-step explanation:

The total pay for last week that Nelly earned was £180

From the information given, we have that;

For Monday - Friday

For Saturday

Double the normal rate of £8 per hour

The total hour She worked from Monday to Friday is;

= 3. 5 + 5 + 2.5 + 4 + 2

= 17 hours

From Monday to Friday

£8 × 15 = £120

£10 × 2 = £20

For Saturday

£8 × 2 = £16

£8 × 5 = £40

Total amount = £120 +  £20 + £40

Total amount = £180

Thus, the total pay for last week that Nelly earned was £180

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Answer:

sln

s=kt

60=k6

k=10

a)10

The absolute increase in population is 2200, and the relative increase is approximately 59.46%.

To find the absolute and relative increase in population, we can use the following formulas:

Absolute increase = Final value - Initial value

Relative increase = (Absolute increase / Initial value) * 100%

Given the population in 2005 is 3700 and the population in 2009 is 5900, we can calculate the absolute and relative increase as follows:

Absolute increase = 5900 - 3700 = 2200

To calculate the relative increase, we need to divide the absolute increase by the initial value and then multiply by 100:

Relative increase = (2200 / 3700) * 100% ≈ 59.46%

Therefore, the absolute increase in population is 2200, and the relative increase is approximately 59.46%.

The absolute increase represents the actual difference in population count between the two years, while the relative increase gives us the percentage change relative to the initial value. In this case, the population increased by 2200 individuals, and the relative increase indicates that the population grew by approximately 59.46% over the given period.

Note that the relative increase is expressed as a percentage, which makes it easier to compare changes across different populations or time periods.

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From the sampling distribution, the correct answer is: Both the center will remain the same, but the spread will decrease.

The center of the sampling distribution will remain the same, which is the expected proportion of even numbers showing on a single roll of the die, which is 1/2 or 0.5. This is because the probability of getting an even number on a single roll of the die does not change with the number of rolls in the experiment.

However, the spread of the sampling distribution will decrease as the number of rolls increases. This is because the larger the sample size, the more precise our estimate of the proportion of even numbers showing on each roll of the die will be. With more rolls, we will have a better idea of the true proportion of even numbers that the die produces.

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The cost of one hosta is approximately $7 and the cost of one geranium is approximately $4.

To find the cost of one hosta and one geranium, we can set up a system of equations based on the given information.

Let's assume the cost of one hosta is represented by 'h' and the cost of one geranium is represented by 'g'.

From the information given, we can set up the following equations:

Eugene's spending:

18h + 6g = $150

Jessica's spending:

7h + 16g = $113

We can now solve this system of equations to find the values of 'h' and 'g'.

Multiplying the first equation by 2 and the second equation by 3 to eliminate 'g', we get:

36h + 12g = $300

21h + 48g = $339

Now, we can subtract the second equation from the first to eliminate 'h':

(36h + 12g) - (21h + 48g) = $300 - $339

36h - 21h + 12g - 48g = -$39

15h - 36g = -$39

Simplifying further, we have:

15h - 36g = -$39

Now we can solve this equation for 'h' and substitute the value back into any of the original equations to find 'g'.

Let's solve for 'h':

15h = 36g - $39

h = (36g - $39) / 15

Substituting this value of 'h' into Eugene's equation:

18[(36g - $39) / 15] + 6g = $150

(648g - $702) / 15 + 6g = $150

648g - $702 + 90g = $150 * 15

738g - $702 = $2250

738g = $2250 + $702

738g = $2952

g = $2952 / 738

g ≈ $4

Now, substituting the value of 'g' back into Eugene's equation:

18h + 6($4) = $150

18h + $24 = $150

18h = $150 - $24

18h = $126

h = $126 / 18

h ≈ $7

Therefore, the cost of one hosta is approximately $7 and the cost of one geranium is approximately $4.

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Answer :

32b + 63

Hope this help!

Answer:

yyy

Step-by-step explanation:

Answer:Canst see

Step-by-step explanation:

sorry my guy

The linear equation of the total cost is y = 1.5x + 3.5 and the number of candy bars for $29 will be 17.

The equation in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the cost for each candy bar is $1.50 and the store charges a $3.50 shopping fee.

The linear equation can be written as:-

y = 1.5x + 3.5

Here, y = total cost and x = Number of candy bar

The number of candy bars for $29 will be:-

y = 1.5x + 3.5

29 = 1.5x + 3.5

1.5x = 25.5

x = 25.5 / 1.5

x = 17

Therefore, the linear equation of the total cost is y = 1.5x + 3.5 and the number of candy bars for $29 will be 17.

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Answer:

Option (a)

Step-by-step explanation:

\(\sqrt[6]{1000m^{3} n^{12} } = \sqrt[6]{10^{3} } \sqrt[6]{m^{3} } \sqrt[6]{n^{12} } =\\\sqrt{10} \sqrt{m} n^{2} = n^{2} \sqrt{10m}\)

There is a 60% probability that a randomly selected student from the class scored either an A or B in Biostatistics.

To calculate the probability that a randomly selected student scored either an A or B in Biostatistics, we need to consider the number of students who scored A and B and divide it by the total number of students in the class.

Given that there are 25 students in the class, 5 of them scored an A and 10 scored a B. To calculate the probability, we add the number of students who scored A (5) to the number of students who scored B (10):

Number of students who scored A or B = Number of students who scored A + Number of students who scored B = 5 + 10 = 15.

Therefore, the probability that a randomly selected student scored A or B

in Biostatistics is:

Probability = Number of students who scored A or B / Total number of students = 15 / 25 = 0.6 or 60%.

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Answer:

The sequence is:

\(\:\left\{a_{1,\:}a_2,\:a_3,\:a_4\right\}\:=\:\left\{-10,\:-23,\:-62,\:-179\right\}\)

Step-by-step explanation:

Given the recursive function

\(a_n=3a_{n-1}+7\)

As the first term is -10.

i.e.

\(a_1=-10\)

Putting n = 2 to determine the 2nd term

\(a_n=3a_{n-1}+7\)

\(a_2=3a_{2-1}+7\)

\(a_2=3a_1+7\)

    \(= 3(-10)+7\)    ∵ \(a_1=-10\)

     \(= -23\)

Putting n = 3 to determine the 3rd term

\(a_n=3a_{n-1}+7\)

\(a_3=3a_{3-1}+7\:\:\)

\(a_3=3a_2+7\:\:\:\:\:\)      

    \(= 3(-23)+7\)       ∵ \(a_2=-23\)

    \(= -62\)

Putting n = 4 to determine the 4th term

\(a_n=3a_{n-1}+7\)

\(a_4=3a_{4-1}+7\)

\(a_4=3a_3+7\:\:\:\:\:\)      

    \(= 3(-62)+7\)       ∵ \(a_3=-62\)

    \(=-179\)

Therefore, the sequence is:

\(\:\left\{a_{1,\:}a_2,\:a_3,\:a_4\right\}\:=\:\left\{-10,\:-23,\:-62,\:-179\right\}\)

In mathematics, every integer in a number has a place value. Therefore, the place value of a number is the value represented by a digit in a number based on its position in the number.

For example, consider the number 30.

3 is in the tens place while,

0 is in the ones place.

Going by the above explanation:

The digit in the ones place in each of the products (10,20,30,40,50,...90) is 0

For every product obtained, it will always have a ones place value of 0

The total area of the three triangles is square units is 36 and the area of the figure is square units is 60.

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

From the figure, the area of triangles can be calculated using the:

Area = (1/2)height×base length

Area of three triangle = 1/2(4×6) + 1/2(6×4) + 1/2(4×6)

Area of three triangle = 1/2(24×3) = 36 square units

Area of the figure = area of three triangle + area of the rectangle

= 36 + 6×4

= 60 square units

Thus, the total area of the three triangles is square units is 36 and the area of the figure is square units is 60.

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Answer:

-4/5

Step-by-step explanation: When you multiply anything by one it is always itself but in this case the one has a negative in front of it so when you multiply a positive number by a negative it makes the number negative.

-1 * 4/5

-4/5

Answer:

b

Step-by-step explanation:

b. There is 5% probability that a true null hypothesis will be rejected.

A p-value of 0.05 represents the probability of obtaining a test statistic as extreme or more extreme than the one observed under the assumption that the null hypothesis is true. In other words, it is the probability of observing the data or more extreme data assuming the null hypothesis is true. It is also the threshold level of significance beyond which the null hypothesis is rejected in favor of the alternative hypothesis. A p-value of 0.05 means that there is a 5% probability that the observed results occurred by chance under the null hypothesis and that there is a 95% probability that the observed results occurred due to a real effect.

Answer: 13

Step-by-step explanation: The number goes up by three each time, so it would be 13.

Answer:

The nᵗʰ term of the sequence is 3n - 2.

Step-by-step explanation:

\(\longrightarrow{\sf{a_n = a + (n - 1)d}}\)

where :

Here we can see that the difference between two terms is 3.

Thus, finding the nth term of the sequence by substituting all the given values in the formula :

\(\longrightarrow{\sf{a_n = a + (n - 1)d}}\)

\(\longrightarrow{\sf{a_n = 1 + (n - 1)3}}\)

\(\longrightarrow{\sf{a_n = 1 + (n \times 3 - 1 \times 3)}}\)

\(\longrightarrow{\sf{a_n = 1 +(3n - 3)}}\)

\(\longrightarrow{\sf{a_n = 1 +3n - 3}}\)

\(\longrightarrow{\sf{\underline{\underline{a_n = 3n - 2}}}}\)

Hence, the nth term of the sequence is 3n - 2.

Answer:

The frame needs a border of 35.75 inch² for a frame that is 5.5 inches by 6.5 inches.

Step-by-step explanation:

Given:

Given that the frame is 5.5 inches by 6.5 inches.

To Determine:

We need to determine the border needed for a frame that is 5.5 inches by 6.5 inches.

In order to determine the area of the border, all we need is to multiply 5.5 inches by 6.5 inches as it would give us the area of the frame.

Since the frame is rectangular, and the area of the rectangular object can be determined using the formula:

\(A = wl\)

substituting the values

\(A = 5.5 \times 6.5\)

\(A=35.75\) inch²

Therefore, the frame needs a border of 35.75 inch² for a frame that is 5.5 inches by 6.5 inches.

Answer:

7

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer: 6.6 meters a week

Step-by-step explanation:

This problem is quite simple

You take 80 and divide it by 12

80/12

which equals

6.6

Answer:

B

Step-by-step explanation:

a prime polynomial is one which does not factor into 2 binomials.

its only factors are 1 and itself

attempt to factorise the given polynomials

3x³ + 3x² - 2x - 2 ( factor the first/second and third/fourth terms )

= 3x²(x + 1) - 2(x + 1) ← factor out common factor (x + 1) from each term

= (x + 1)(3x² - 2) ← in factored form

--------------------------------------------------

3x³ - 2x² + 3x - 4 ( factor the first/second terms

= x²(3x - 2) + 3x - 4 ← 3x - 4 cannot be factored

thus this polynomial is prime

----------------------------------------------------

4x³ + 2x² + 6x + 3 ( factor first/second and third/fourth terms )

= 2x²(2x + 1) + 3(2x + 1) ← factor out common factor (2x + 1) from each term

= (2x + 1)(2x² + 3) ← in factored form

-------------------------------------------------

4x³ + 4x² - 3x - 3 ( factor first/second and third/fourth terms )

= 4x²(x + 1) - 3(x + 1) ← factor out common factor (x + 1) from each term

= (x + 1)(4x² - 3) ← in factored form

--------------------------------------------------

the only polynomial which does not factorise is

3x³ - 2x² + 3x - 4

Answer:

A = 1.5386

Step-by-step explanation:

Quarter circle area formula:

A = (πr²)/4

A= (π1.4²)/4

A = (3.14*1.96)/4

A = (6.1544)/4

A = 1.5386

Parameterize C by the two vector functions,

r(t) = (1 - t) (0, 0) + t (6, 0) = (6t, 0)

with 0 ≤ t ≤ 1, and

s(t) = (6 cos(t), 6 sin(t))

with 0 ≤ t ≤ π/2.

Then the line integral over C is equal to the sum of the line integrals over each path:

\(\displaystyle \int_C dS = \int_0^1 \|r'(t)\| \, dt + \int_0^{\frac{\pi}2} \|s'(t)\| \, dt\)

\(\displaystyle \int_C dS = \int_0^1 \sqrt{6^2 + 0^2} \, dt + \int_0^{\frac{\pi}2} \sqrt{(-6\sin(t))^2 + (6\cos(t))^2} \, dt\)

\(\displaystyle \int_C dS = 6 \int_0^1 dt + 6 \int_0^{\frac{\pi}2} dt\)

\(\displaystyle \int_C dS = 6 + \frac{6\pi}2 = \boxed{6+3\pi}\)