A 0.200 H inductor is connected in series with a 96.0 Ω resistor and an ac source. The voltage across the inductor is vL=−(12.5V)sin[(483rad/s)t] Part A Derive an expression for the voltage vR across the resistor. Express your answer in terms of the variables L, R, VL (amplitude of the voltage across the inductor), ω, and t Part B What is vR at 2.15 ms ?

Kinetic energy = 29.912 J

Given

mass = 0.155 kg

vo=initial velocity = 31.4 m/s

h/d=30 m

Required

KE=kinetic energy

Solution

vt²=vo²-2ad⇒vt=final velocity

vt²=31.4²-2.10.30⇒g=10 m/s²

vt²=985.96-600

vt²=385.96 m/s

Kinetic  energy (KE)

\(\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 0.155.\times 385.96\\\\KE=29.912~J\)

Answer:

The answer is 30.8 (J)

Explanation:

You're welcome

Answer:

C. balancing the amount of energy that is taken in with the amount of energy that is released by the body

Explanation:

Edge 2021

Answer:

Larva and pupa is present in complete metamorphosis while nymph is present instead of larva and pupa in incomplete metamorphosis.

Explanation:

Complete metamorphosis has four stages i. e. egg, larva, pupa, and adult while the incomplete metamorphosis has three stages i. e. egg, nymph, and adult. Grasshopper, dragonfly, cicada and cockroach have incomplete metamorphosis while ladybug , housefly, butterfly  and honeybee have complete metamorphosis. Both type of insects lay eggs and after hatching a baby insect comes out called larva. After sometime this larva transforms from immature to mature, this stage is known as pupa. After pupa, the insect converts into an adult which is ready for reproduction. Nymph is a stage that comes in place of larva and pupa in incomplete metamorphosis. in this stage, the insect is small in size and lack of wings but in adult stage the wings appear.

In Chapter 2 section 2.21, it is stated that in a cathode ray tube, electrons pass from the cathode to the anode. This is because the cathode is negatively charged, while the anode is positively charged.

The flow of electrons is controlled by an electric field between the cathode and anode, which causes the electrons to move towards the anode. Therefore, the correct answer to the question is option B) electrons pass from the cathode to the anode.

In Chapter 2, Section 2.21, regarding a cathode ray tube, the correct answer is B) electrons pass from the cathode to the anode. The cathode emits electrons, which are attracted to the positively charged anode, resulting in the flow of electrons in the tube.

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When a quality control test is performed to ensure that the penetrating ability of the x-ray beam is accurate, the result must be within what amount of the control panel setting will be ±4 kVp.

Quality control entails testing units to see if they meet the standards for the final product.

The goal of the testing is to evaluate whether any corrective measures are required in the production process. Good quality control assists businesses in meeting customer needs for improved products.

When a quality control test is performed to ensure that the penetrating ability of the x-ray beam is accurate. The results must be under some limits.

Hence the result must be within what amount of the control panel setting will be ±4 kVp.

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The power of a laser beam, measured in watts, gives us information about the rate at which energy is delivered by the beam. However, to compare the number of photons per second delivered by different beams, we need to consider the energy of each individual photon.

The energy of a photon can be calculated using Planck's equation:

E = hf

where E is the energy, h is Planck's constant (approximately 6.626 × 10^-34 J·s), and f is the frequency of the light.

Since both lasers emit light beams with the same power of 1 mW, their energies per second are equal. However, the energy of each individual photon depends on the frequency of the light.

Green light has a higher frequency than red light, which means that each green photon carries more energy than each red photon. Therefore, the green laser pointer delivers fewer photons per second compared to the red laser pointer to maintain the same energy output.

In conclusion, the red laser pointer delivers more photons per second than the green laser pointer, even though both have the same power output of 1 mW.

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To determine the change that will speed up the rate of erosion in the student's simulation, we need to consider the factors that influence erosion. Without specific details about the default conditions or the simulation, we can provide a general answer based on common factors affecting erosion.

To speed up the rate of erosion, the student could consider increasing one or more of the following factors:  Increase the water flow, Increase the slope gradient, Increase the sediment load, Increase the duration of the simulation.

1. Increase the water flow: If the simulation includes water as a factor, increasing the flow rate or volume of water can intensify erosion. Higher water flow can lead to greater sediment transport and erosion of the landscape.

2. Increase the slope gradient: Steeper slopes increase the potential for erosion. If the simulation allows for modifying the terrain's incline, increasing the slope gradient can accelerate erosion processes.

3. Increase the sediment load: If the simulation involves the presence of sediment, increasing the amount of sediment or its size can enhance erosion. Greater sediment load contributes to more abrasive action and faster erosion.

4. Increase the duration of the simulation: Extending the simulation time can allow erosion processes to occur for a longer period, potentially resulting in more erosion.

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The density of the coin is 263.8 kg/m³.

The density of the given coin can be determined using the formula for density which states that density is equal to mass divided by volume. The given coin has a diameter of 21.21 mm, a thickness of 1.95 mm, and weighs 0.04905 N. We can find the volume of the coin using the formula for the volume of a cylinder which is given by:

V = πr²h, where
r = radius of the cylinder = diameter/2
h = height of the cylinder

Substituting the values of the diameter and height in the above formula we get:

V = π(21.21/2)²(1.95)
 = 1.862 × 10⁻⁴ m³

The mass of the coin is given to be 0.04905 N.

So, density is given by:

Density = Mass / Volume
Density = 0.04905 N / 1.862 × 10⁻⁴ m³
Density = 263.8 kg/m³

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A 7.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping the initial velocity of the bullet was 958 m/s.

First, let's calculate the momentum of the bullet before the collision. Momentum is defined as mass times velocity, so we need to find the velocity of the bullet. We can use the fact that the bullet remains embedded in the block to determine the final velocity of the bullet-block system. The momentum of the system is equal to the mass of the system times its velocity.
Let's call the initial velocity of the bullet "v". The mass of the system is the mass of the bullet plus the mass of the block, which is 7.00 g + 1.20 kg = 1.207 kg. After the collision, the block and bullet move together at a final velocity of "vf". We can use the fact that the block slides 0.390 m along the surface before stopping to determine vf. The work done by friction is equal to the force of friction times the distance over which it acts. This work is equal to the change in kinetic energy of the system, which we know is equal to the initial kinetic energy of the bullet. We can write:
frictional force x distance = 1/2 x m x v^2
The frictional force is equal to the coefficient of kinetic friction times the normal force, which is equal to the weight of the block. We can write:
0.20 x 1.20 x 9.81 x 0.390 = 1/2 x 1.207 x vf^2
Solving for vf, we get:
vf = 2.62 m/s
Now we can use the conservation of momentum to find the initial velocity of the bullet:
m_bullet x v = (m_bullet + m_block) x vf
7.00 g x v = 1.207 kg x 2.62 m/s
v = 958 m/s
So the initial velocity of the bullet was 958 m/s.

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Answer:

B. A well-tested explanation for a widely accepted hypothesis

Explanation:

This is true about a scientific theory going by the fact of it being a well tested explanation. For example, in one of the Newtons law of motion which he stated to be "To every action, there is equal and opposite reaction", the hypothesis has been known till he was able to offer a well tested explanations with calculations showing that, it was actually true.

Biker 1's acceleration:

(25 mph) / (3 s) = ((25 mi/h) • (1/3600 h/s)) / (3 s) ≈ 0.00231 mi/s²

Biker 2's acceleration:

(85 mph) / (8 s) = ((85 mi/h) • (1/3600 h/s)) / (8 s) ≈ 0.00295 mi/s²

Biker 2 has the greater acceleration.

Answer:

Volume = 112cm^2

Density = 0.45 g/cm^2 (2.s.f)

Explanation:

Volume of a cube is found by multiplying its height by its length by its width.

We are given the values: l = 7cm, w = 8cm, h = 2cm, so to find the volume we just need to multiply them all together:

V=lwh

V = (7)(8)(2)

The volume of the cube = 112cm^2

Density is found by dividing mass by volume.

We are given the mass (50 grams) and we have just found the Volume (112cm^2), so we can just divide them to find the density:

p (symbol for density) = m/v

p = (50)(112)

The density of the cube is 0.45 g/cm^2 (2.s.f.)

Hope this helped!

Answer:

Dimitri Mendeleev

In 1869 Russian chemist Dimitri Mendeleev started the development of the periodic table, arranging chemical elements by atomic mass. He predicted the discovery of other elements, and left spaces open in his periodic table for them.

Engineering design has to do with the overall process of the design and the production of new products.

Engineering design has to do with the overall process of the design and the production of new products. Now the process of engineering design involves many components and all these are taken into account when a new product is being designed.

As such, the stage of technological design in which each action would occur is;

Define a need and research related information- identify a problem

Establish criteria and prepare the initial design -  Design a solution

Build and test a prototype - implement a solution

Redesign and retest as necessary - Evaluate a solution

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answer: 1 design a solution 2 evaluate a solution 3 identify a problem 4 implement a solution

Explanation: i know

A person would be 30 feet (y) 8 seconds (x) after the experiment begins.

The scatterplot shows a linear relationship between the distance (in feet) from the motion sensor and the time (in seconds) since the start of the experiment.

Using the two labeled points (8 seconds, 21 feet) and (15 seconds, 57 feet), we can use the line equation y = mx + b to create a linear model. The slope (m) equals (57 feet - 21 feet)/(15 seconds - 8 seconds) = 36 feet/7 seconds, and the y-intercept (b) equals 21 feet.

Using the linear model, we can estimate that a person would be 30 feet (y) 8 seconds (x) after the experiment begins.

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The magnitude of the electric force acting on the electron is equal to Fel = keqe2/r2

Thus, Electric fields can also be created by electric charges. A charged particle projects an electric field into its immediate surroundings. Standard electric fields are produced by a single charge, while ''net'' electric fields are produced by the combination of multiple charge fields.

Positive charges are pointed away from by electric fields, whereas negative charges are pointed in the other direction.

A little test charge would move along the field lines if it were inserted into the electric field from our hypothetical situation. Positive test charges would flow in the direction of the net electric field, while negative test charges would move in the opposite direction.

Thus, The magnitude of the electric force acting on the electron is equal to Fel = keqe2/r2.

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Answer: 98000 N/m.

Explanation:

To determine the spring constant of the spring, we can use Hooke's Law, which states that the force exerted by a spring is proportional to its displacement.

Hooke's Law can be written as:

F = -k * x

Where:

F is the force applied to the spring,

k is the spring constant, and

x is the displacement of the spring from its equilibrium position.

In this case, we can assume that the displacement of the spring is the change in length from 1 m to 50 cm, which is 0.5 m (or 0.5 m - 1 m = -0.5 m if we consider compression as a negative displacement).

We can also assume that the force exerted by the spring is the weight of the elephant, which is given as 5000 kg.

Plugging these values into Hooke's Law:

5000 kg * 9.8 m/s^2 = -k * 0.5 m

Simplifying the equation:

49000 N = -k * 0.5 m

Dividing both sides by -0.5 m:

k = -49000 N / -0.5 m

k = 98000 N/m

Therefore, the spring constant of the spring is 98000 N/m.

Answer:

Explanation:

Durante as aulas, os estudantes da 3ª série deveriam escolher uma entre as três atividades físicas possíveis, sendo elas: natação, futsal e dança. Na turma, 25% escolheram dança, 15% escolheram natação, e os outros 24 estudantes escolheram futsal. Podemos afirmar que, nessa turma, existe um total de:

A) 64 alunos

B) 55 alunos

C) 48 alunos

D) 45 alunos

E) 40 alunos

Answer:

W = 1074.88 J = 1.07 KJ

Explanation:

The work done on an object by a force is given as the dot product of the force, with the displacement. So, the formula for work done in this case will be:

W = F.d

W = F d Cos θ

where,

W = Work done by tension force = ?

F = Magnitude of tension force = 95 N

d = displacement covered = 13.2 m

θ = Angle of force with horizontal = 31°

Therefore, using the values in equation, we get:

W = (95 N)(13.2 m)(Cos 31°)

W = 1074.88 J = 1.07 KJ

Answer:

conduction is the correct answer

Answer:

yes it is

Explanation:

The simplified expression for Q using De Morgan's laws is Q = A . (A' . C')'.

a) Truth tables for the NAND gate and NOR gate with two inputs:

NAND gate:

| A | B | Q |

|---|---|---|

| 0 | 0 | 1 |

| 0 | 1 | 1 |

| 1 | 0 | 1 |

| 1 | 1 | 0 |

NOR gate:

| A | B | Q |

|---|---|---|

| 0 | 0 | 1 |

| 0 | 1 | 0 |

| 1 | 0 | 0 |

| 1 | 1 | 0 |

b) Truth table and logic expression for Z in terms of inputs A, B, and C:

| A | B | C | Z |

|---|---|---|---|

| 0 | 0 | 0 | 1 |

| 0 | 0 | 1 | 0 |

| 0 | 1 | 0 | 1 |

| 0 | 1 | 1 | 0 |

| 1 | 0 | 0 | 1 |

| 1 | 0 | 1 | 0 |

| 1 | 1 | 0 | 0 |

| 1 | 1 | 1 | 0 |

Logic expression for Z: Z = (A' AND B' AND C) OR (A' AND B AND C')

c) Simplification of the Boolean expression Q = (A. (A + C))' using De Morgan's laws:

Q = (A. (A + C))'

Apply De Morgan's law: (AB)' = A' + B'

Q = (A' + (A + C)')'

Apply De Morgan's law again: (A + B)' = A' . B'

Q = ((A')' . (A + C)')'

Simplifying the double negations: (A')' = A and (A + C)' = A' . C'

Q = (A . (A' . C'))'

Final simplified expression: Q = A . (A' . C')'

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A series of reactions occur when 4-bromo-3-methyloctane is treated with NaOCH3 followed by O3.

The NaOCH3 reacts with the 4-bromo-3-methyloctane to form an intermediate that is electrophilically substituted with ozone (O3) to form an alkoxy radical, which is then unimolecularly degraded to form a ketone and an aldehyde.

The reaction is completed by treating the products with dimethyl sulfide (DMS). As a nucleophile, dimethyl sulfide reacts with the carbonyl groups of the ketone and aldehyde to form hemiacetal and dimethyl sulfoxide. This is a common method for converting carbonyl groups into alcohols and is known as nucleophilic addition.

Thus, the products formed when 4-bromo-3-methyloctane is treated with NaOCH3, then O3, , and then with dimethyl sulfide, are a ketone and an alcohol. The exact identity of the products will depend on the specific conditions of the reaction, including the reaction temperature, solvent, and reactant ratios.

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There are 12 more squares than triangles on a poster that has a mixture of 36 squares and triangles. The task is to determine the number of triangles on the poster.

To solve this problem, we can set up an equation. Let's represent the number of squares as "x" and the number of triangles as "y". Given that there are 12 more squares than triangles, we can write the equation: x = y + 12. We also know that the total number of squares and triangles on the poster is 36, so we can write another equation: x + y = 36.

Now, we can substitute the value of x from the first equation into the second equation: y + 12 + y = 36.
Simplifying the equation, we get: 2y + 12 = 36.
Subtracting 12 from both sides, we have: 2y = 24.
Dividing both sides by 2, we find: y = 12.
Therefore, there are 12 triangles on the poster.
In conclusion, the number of triangles on the poster is 12.

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Write each force in component form:

v ₁ : 50 N due east   →   (50 N) i

v ₂ : 80 N at N 45° E   →   (80 N) (cos(45°) i + sin(45°) j ) ≈ (56.5 N) (i + j )

The resultant force is the sum of these two vectors:

r = v ₁ + v ₂ ≈ (106.5 N) i + (56.5 N) j

Its magnitude is

|| r || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N

and has direction θ such that

tan(θ) = (56.5 N) / (106.5 N)   →   θ ≈ 28.0°

i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive x-axis.)

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

\(-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})\)

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

\(-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]\)

The velocity with which the astronaut must throw the tool kit is 9.62 m/s.

The given parameters:

Apply the principle of conservation of linear momentum to determine the velocity of the tool kit;

\(m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\-0.1(157) \ + 5u_2 = 0.2(157 + 5) \\\\-15.7 + 5u_2 = 32.4\\\\5u_2 = 32.4 + 15.7\\\\5u_2 = 48.1\\\\u_2 = \frac{48.1}{5} \\\\u_2 = 9.62 \ m/s\)

Thus, the velocity with which the astronaut must throw the tool kit is 9.62 m/s.

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Answer:

Explanation:

In a sonometer , expression for speed of wave produced can be given as follows .

v = \(\sqrt{\frac{T}{m} }\)

v is velocity , T is tension in wire , m is density per unit length .

Here v is inversely proportional to square root of m . So if m becomes m / 4

velocity changes as follows .

velocity = \(\sqrt{\frac{T}{\frac{m}{4} } }\)

= \(\sqrt{\frac{4T}{m} }\)

= 2v

velocity becomes two times . Hence to make velocity two times , mass per unit length  has to be changed to one fourth value , keeping tension constant .

In conclusion, to calculate the exact value of the instantaneous current at time t = 2.6 s, we need to know the resistance in the circuit. Without this information, we can only provide a general explanation of how the current behaves based on the given source voltage function.

The instantaneous current in the circuit can be determined by applying Ohm's law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). In this case, the source voltage (vsource) is given as v0cos(2πft), where v0 represents the peak voltage and f is the frequency.
To find the instantaneous current at time t = 2.6 s, we need to know the value of the resistance in the circuit. Without this information, we cannot determine the exact value of the current.
However, we can still provide a general explanation of how the current changes with time in this circuit. Since the source voltage is a cosine function, the current will also be a cosine function with the same frequency and a phase shift. The amplitude of the current will depend on the value of the resistance.
In conclusion, to calculate the exact value of the instantaneous current at time t = 2.6 s, we need to know the resistance in the circuit. Without this information, we can only provide a general explanation of how the current behaves based on the given source voltage function.

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Explanation:

MASS=2.22

VELOCITY=10m/s

KINETIC ENERGY=111

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Explanation:

potential energy = mass × gravity force × height

5000 = 50 ×10 ×h

5000= 500×h

h = 5000÷500

h = 10 m