A 1 kg apple and a 2 kg baseball are 2 m apart. What is the force of gravity between each fruit?

Answers

Answer 1

The force of gravity between the apple and the baseball is 3.335×10¯¹¹ N

The following data were obtained from the question given above:

Mass of apple (M₁) = 1 Kg

Mass of baseball (M₂) = 2 Kg

Distance apart (r) = 2 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force (F) =?

The force of gravity between them can be obtained as follow:

\(F = \frac{GM_1M_2}{ {r}^{2}} \\ \\ F = \frac{6.67 \times {10}^{ - 11} \times 1 \times 2 }{ {2}^{2}} \\ \\ F = 3.335 \times {10}^{ - 11} N \\ \)

Therefore, the force of gravity between them is 3.335×10¯¹¹ N

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Related Questions

Light of wavelength 600 nm in air goes into a medium where the index of refraction is 1.73. What is the frequency of this light in the medium?
I need it with the given,unknowns ans equation and solution
ASAP

Answers

Answer:

5.00 × 10^14 Hz

Explanation:

The wavelength of the light in the medium can be calculated by using the formula:

λ = v / f

Where;

λ = wavelength (m)

v = speed of light

f = frequency (Hz)

From the provided information, λ = 600 nm (600 × 10^-9m), v = 3 × 10^8m/s.

λ = v / f

λ = 3 × 10^8/600 × 10^-9

λ = 0.005 × 10^(8+9)

λ = 0.005 × 10^17

λ = 5.00 × 10^14 Hz

The frequency of the light in the medium is 5.00 × 10^14 Hz

A closed vertical pipe contains layers of fluids mainly gas of thickness 1m, under pressure of 60 kpa, Ethyl alcohol of thickness of 60m and density 780 kg/m3, oil of thickness 10m and density 840 kg/m^3. Water of thickness 2m and density 990 kg/m^3 glycerine of thickness 3m and density 1,236 kg/m^3 and the remaining is molars is of thickness 10m and density 1,500 kg/m^3.Assume the fluids are separated and do not mix. a) In which fluid is pressure of 610 kpa first achieved. b) If the bottom of the pipe is at zero elevation what is the pressure at the bottom in kpa. c) At what elevation is the pressure of 640 kpa. d) If an open manometer is attached to the side of the pipe anywhere on the oily portion determine the height of the liquid level in the manometer.​

Answers

Answer:

pls mrk me brainliest

Explanation:

Hydrostatic pressure is the pressure exerted by a fluid at equilibrium at any point of time due to the force of gravity. Hydrostatic pressure is proportional to the depth measured from the surface as the weight of the fluid increases when a downward force is applied. The hydrostatic pressure at any point in a fluid can be calculated by using the formula:

P = P0 + ρgh

where P is the hydrostatic pressure, P0 is the atmospheric pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the point from the surface.

a) In which fluid is pressure of 610 kPa first achieved?

It can be found out by adding up the hydrostatic pressures of each layer of fluid until we reach 610 kPa. Starting from gas layer:

Pgas = 60 kPa + (1 kg/m3)(9.81 m/s2)(1 m) = 60.00981 kPa

Palcohol = Pgas + (780 kg/m3)(9.81 m/s2)(60 m) = 460.00981 kPa

Poil = Palcohol + (840 kg/m3)(9.81 m/s2)(10 m) = 542.40981 kPa

Pwater = Poil + (990 kg/m3)(9.81 m/s2)(2 m) = 561.60981 kPa

Pglycerine = Pwater + (1236 kg/m3)(9.81 m/s2)(3 m) = 605.46981 kPa

Pmolasses = Pglycerine + (1500 kg/m3)(9.81 m/s2)(10 m) = 752.96981 kPa

The pressure of 610 kPa is first achieved in glycerine layer.

b) If the bottom of the pipe is at zero elevation what is

b) If the bottom of the pipe is at zero elevation what isthe pressure at bottom in kpa?

The bottom of pipe corresponds to molasses layer so use it to calculate hydrostatic pressure as calculated above:

Pbottom = Pmolasses = 752.96981 kPa

c) At what elevation is pressure of 640kpa?

It can be found out by subtracting hydrostatic pressures from each layer until it reach below 640kpa and then use interpolation to find exact elevation.

Starting from molasses layer:

Pmolasses - Pglycerine= (752.96981 - 605.46981)kpa=147.5kpa

This means that somewhere between glycerine and molasses layers there is a point with pressure of 640kpa.

Let x be distance from top surface of molasses layer to this point then:

640kpa=605.4698+1500(9.8)x

x=0.023m

Therefore elevation from bottom surface of pipe to this point is:

10-0-0-023=9-977m

d) If an open manometer attached to side pipe anywhere on oily portion determine height liquid level manometer.

An open manometer measures difference between atmospheric pressure and fluid pressure inside pipe.

Let y be height liquid level manometer above oil level then:

Patm-Poil=yρg

y=(Poil-Patm)/ρg

y=(542-4098-101325)/(1000*9-8)

y=-44-6m

This means that liquid level manometer will be below oil level by -44-6m or oil level will be above liquid level manometer by +44-6m.

****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)

****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)
****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)

Answers

but I think it's a and f

and

b and e

PLEASE HELP!!

A student fires a cannonball diagonally with a speed of 34.om/s from a height of 66.0m as shown. Neglect drag. Determine all unknowns and answer the following questions.


How long did the ball rise?

What was the ball's maximum height above the ground?

How long did the ball remain in the air?

How far from the base of the building did the ball land?

How fast was the ball moving as it struck the ground?

PLEASE HELP!!A student fires a cannonball diagonally with a speed of 34.om/s from a height of 66.0m as

Answers

The ball rises for approximately 3.6 seconds.The ball reaches a maximum height of approximately 117 meters above the ground.The ball lands approximately 241 meters from the base of the building.The ball was moving at approximately 29.1 m/s when it struck the ground.Projectile motion problem

We can use the equations of projectile motion to determine the unknowns and answer the following questions:

The time it takes for the ball to reach its maximum height can be found using the following equation:

Vy = Voy - gt

where Voy is the initial vertical velocity and g is the acceleration due to gravity. At the maximum height, the vertical velocity of the ball is zero, so we have:

0 = Voy - gt

t = Voy/g

t = (34.0 m/s)sin(73°)/9.81 m/s^2 ≈ 3.6 s

The maximum height reached by the ball can be found using the following equation:

         y = Voyt - 1/2 gt^2

where y is the vertical displacement of the ball. At the maximum height, the vertical displacement is equal to the initial height of the ball, so we have:

66.0 m = (34.0 m/s)sin(73°)t - 1/2 (9.81 m/s^2)t^2

t ≈ 3.6 s

y = (34.0 m/s)sin(73°)(3.6 s) - 1/2 (9.81 m/s^2)(3.6 s)^2 ≈ 117 m

The total time of flight can be found using the following equation:

         t_total = 2t

where t is the time it takes for the ball to reach its maximum height. Substituting the value of t from above, we get:

t_total = 2(3.6 s) ≈ 7.2 s

The horizontal distance traveled by the ball can be found using the following equation:

        x = Vx t

where Vx is the initial horizontal velocity of the ball. Substituting the given values, we get:

x = (34.0 m/s)cos(73°)(7.2 s) ≈ 241 m

The final velocity of the ball can be found using the following equation:

        Vf = sqrt(Vx^2 + Vy^2 - 2gy)

where Vx and Vy are the horizontal and vertical components of the velocity, respectively, and y is the vertical displacement of the ball. At the instant of impact, the vertical displacement is equal to the initial height of the ball, so we have:

y = 66.0 m

Substituting the given values, we get:

Vf = sqrt[(8.9 m/s)^2 + (32.7 m/s)^2 - 2(9.81 m/s^2)(66.0 m)] ≈ 29.1 m/s

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The process of beta emission can be envisioned as the.

Answers

Answer:

conversion or a neutron to a proton and electron. the electronic is emitted

define the word prism

Answers

Answer:

a polyhedron with two polygonal faces lying in parallel planes and with the other faces parallelograms

Calculate both the relative and absolute VO2 for an 85 kg man walking on a treadmill at a speed of 2.8mph with an 6% grade. 1. Calculate both the relative and absolute VO, for a 65 kg woman running on a treadmill at a speed of 6.0mph with a 2% grade.

Answers

For an 85 kg man walking on a treadmill at a speed of 2.8 mph with a 6% grade, we can calculate both the relative and absolute VO2 values. Similarly, for a 65 kg woman running on a treadmill at a speed of 6.0 mph with a 2% grade.

1. For an 85 kg man walking on a treadmill at a speed of 2.8 mph with a 6% grade:

Relative VO2:

\(\[\text{{VO}}2_{\text{{relative}}} = 3.5 + 0.1 \times \text{{speed}} + 1.8 \times \text{{speed}} \times \text{{grade}}\]\[\text{{VO}}2_{\text{{relative}}} = 3.5 + 0.1 \times 2.8 + 1.8 \times 2.8 \times 0.06\]\[\text{{VO}}2_{\text{{relative}}} \approx 7.33 \, \text{{ml/kg/min}}\]\)

Absolute VO2:

\(\[\text{{VO}}2_{\text{{absolute}}} = \text{{VO}}2_{\text{{relative}}} \times \text{{body weight}}\]\[\text{{VO}}2_{\text{{absolute}}} = 7.33 \times 85\]\[\text{{VO}}2_{\text{{absolute}}} \approx 622.05 \, \text{{ml/min}}\)

2. For a 65 kg woman running on a treadmill at a speed of 6.0 mph with a 2% grade:

Relative VO2:

\(\[\text{{VO}}2_{\text{{relative}}} = 3.5 + 0.1 \times \text{{speed}} + 1.8 \times \text{{speed}} \times \text{{grade}}\]\[\text{{VO}}2_{\text{{relative}}} = 3.5 + 0.1 \times 6.0 + 1.8 \times 6.0 \times 0.02\]\[\text{{VO}}2_{\text{{relative}}} \approx 12.37 \, \text{{ml/kg/min}}\]\)

Absolute VO2:

\(\[\text{{VO}}2_{\text{{absolute}}} = \text{{VO}}2_{\text{{relative}}} \times \text{{body weight}}\]\[\text{{VO}}2_{\text{{absolute}}} = 12.37 \times 65\]\[\text{{VO}}2_{\text{{absolute}}} \approx 803.05 \, \text{{ml/min}}\]\)

These calculations provide the values for both the relative and absolute VO2 for the given scenarios. The relative VO2 is expressed in milliliters per kilogram per minute (ml/kg/min), and the absolute VO2 is given in milliliters per minute (ml/min).

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Which of these consumers is an herbivore? *

1. lion

2. deer

3. spider

4. snake

Answers

Answer:

2. deer

Explanation:

The lion, spider, and snake eat meat or to an extent.

Deer don't eat meat

Answer:

deer :)

Explanation:

The rest are basically carnivores

A 40-kg crate is being pulled along a frictionless surface by a force of magnitude 140 N that makes an angle of 30° with the horizontal. The acceleration of the crate is?

Answers

ETo determine the acceleration of the crate, we need to resolve the applied force into its horizontal and vertical components. The horizontal component of the force will contribute to the acceleration, while the vertical component will not affect the motion of the crate on a frictionless surface.
Given:
Mass of the crate (m) = 40 kg
Magnitude of the applied force (F) = 140 N
Angle of the force with the horizontal (θ) = 30°

To find the horizontal component of the force (F_horizontal), we can use trigonometry:
F_horizontal = F * cos(θ)
F_horizontal = 140 N * cos(30°)
F_horizontal = 140 N * √3/2
F_horizontal = 140 N * 0.866
F_horizontal ≈ 121.24 N
Since there is no friction or vertical forces acting on the crate, the horizontal component of the applied force will be responsible for the acceleration.
Using Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration (F = m * a), we can calculate the acceleration (a).
a = F_horizontal / m
a = 121.24 N / 40 kg
a ≈ 3.03 m/s²
Therefore, the acceleration of the crate is approximately 3.03 m/s².

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the amount of gravitational force that acts on a space vehicle while in earth orbit is

Answers

The amount of gravitational force that acts on a space vehicle while in earth orbit is almost zero but not absolute zero.

There is no ground force or opposing natural force to gravity.

Because the earth is not a perfect sphere, the value of "g" is lowest at the equator. At the equator, its radius is at its largest. Thus, the equator is the location where g will be smallest according to the equation

g = GM/R2.

All items in the planet's gravitational field will be lost in space if gravity abruptly vanishes. We would experience levity. Essentially, if gravity is equal to zero, then there will be no acceleration caused by gravity.

Astronauts can float within their spaceship or outside during a spacewalk in microgravity. Moving heavy stuff is simple. Astronauts, for instance, can merely use their fingertips to manipulate machinery weighing hundreds of pounds.

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Linus builds an electrical circuit with a battery and with wires that carry the current. As the battery weakens, the current also weakens. How does this affect the magnetic field around the wires

Answers

Answer:

When electric current weakens then the magnetic field around the wire also weaken

Explanation:

The magnetic field produced by electrical wire is directly proportional to the electricity flowing through it.

Thus, in case when electric current weakens then the magnetic field around the wire also weaken.

Answer:

The field gets weaker

Explanation:

took the quiz!

1. What is the claim made by the Big Bang theory regarding the creation of the universe?

Answers

Answer:

Explanation:

The big bang theory explained that the universe started as a single entity which was created by massive explosion and it create most of the matter i.e galaxies were moving away from the universe in all directions with great speed which then cause massive explosion and bring about cosmos creation.

a 6 amp light bulb dissipates 24j per seconds

calculat the amount of charge passing through the 6 amp light bulb per second

Answers

The  charge passing through the circuit in one second is 8 C.

What is charge?

Charge is property of matter that causes experience of force when kept in electric or magnetic field.

Electric charge exists as the physical property of matter that causes charged matter to experience a force when positioned in an electromagnetic field. Electric charges can be positive or negative. Like charges repulse each other and unlike charges attract each other.

Charge, also understood as electric charge, electrical charge, or electrostatic charge and symbolized by q, exists as a characteristic of a unit of matter that represents the extent to which it has more or fewer electrons than protons.

As we know

I =Q/t

where I is current and Q is charge ,t is time

so put the value in formula

8 = Q/

Q  =  8 coulomb.

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I need help! Picture is the sheet. ​

I need help! Picture is the sheet.

Answers

Answer:

The answers to the questions are

1. Sound energy

2. Conductor

3. Flow

4. Thermal energy (g underlined)

5. Electric current

6. Insulator

7. Light energy

8. Electric circuit

The underlined letters are, e, n, g, r, y, e which can be rearranged to spell energy

Explanation:

1. Sound energy is the wave form of mechanical energy that is transferred by the vibration of the of the medium through which it propagates

2. An electrical conductor is used to conduct electricity from one point to another

3. An object or material flows when it has a smooth motion towards a given direction, such as a river

4. Thermal energy is the form of energy that is given off by a body as sensible heat that can be measured as a temperature by a thermometer

5. Electric current is the electricity in a circuit

6. An insulator is a material that limits the flow of electricity or heat

7. Light energy is the form electromagnetic energy which the eye can sense

8. An electric current flows an electric circuit which consist of a source of electricity and an path through which the electric current can easily flow.

A race begins from rest and r and reaches 250 miles/hour in 7.5 seconds what is the final velocity of the race in meters per second

Answers

The final velocity of the race is 111.75 m/s

As per the question,

Initial velocity, u = 0 miles/hour

Final velocity, v = 250 miles/hour

Time, t = 7.5 sec

Now, converting the units of final velocity from miles per hour to meters per second:

1 mile = 1609.34 meter

1 hour = 3600 seconds

So, 250 mi/hr = 250 × 1609.34 m/3600s

                      = 111.75 m/s

Alternatively,

1 mile per hour = 0.447 meters per second

250 miles per hour ⇒250 × 0.447

                                   = 111.75 m/s

The final velocity of the race is 111.75 m/s.

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My grass is dying and I believe that it is not getting enough water so I decided to conduct a experiment

Answers

NO WUESTION NO ANSWER
That’s a smart Idea !!!

3) A photon is emitted as the electron in a hydrogen
atom drops from the n = 5 energy level directly to
the n = 3 energy level. What is the energy of the
emitted photon?
(1) 0.85 eV
(2) 0.97 eV
(3) 1.51 eV
(4) 2.05 eV

Answers

From the information provided and the calculations, the energy of the drop is 1.51 eV

What is the Rydberg formula?

The Rydberg formula is used to obtain the energy of a photon or the wavelength of a photon.

Thus;

1/λ = 1.097 * 10^7 (1/3^2 - 1/5^2)

1/λ = 1.097 * 10^7(0.11 - 0.04)

λ = 1.3 * 10^-6 m

Since;

E = hc/λ

E = 6.6 * 10^-34 * 3 * 10^8/1.3 * 10^-6

E = 1.51 * 10^-19 J or 1.51 eV

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Answer:

0.97eV

Explanation:

The energy emitted during n=5 is 0.54 eV

The energy emitted during n=3 is 1.51 eV
(This information is on the Physics Reference Table 2006 edition)

We find the change in the energy level which is:  

1.51eV-0.54eV = 0.97eV

Therefore the energy emitted by the photon is 0.97eV.

What is the net electric force on the charge located at the lower right-hand corner of the triangle.

Answers

Answer:

\(\sqrt{3}\frac{kq^{2}}{a^{2} }\)

Explanation:

none sadly

The net electric force on the charge is located at the lower right-hand corner of the triangle is \(Fr = \sqrt{3} \times\dfrac{q^2}{4 \times \pi \times 0 \times a^2 }\).

What is electric force?

Electric force is the attraction or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. One of the many forces that affect objects is the electric force.

The given electrostatic force is:

F = k  x Q1 x Q2 / R²

here, Q1 & Q2 = charges

R = distance between charges

The force between q and q

F1 = k x q x q / a² = F

The force between q and '-2q'

F2 = k x q x 2 x q / a²  = 2 x F (towards '-2q' charge)

From the diagram given below, angle between F1 & F2 = A = 120°

So, the resultant force will be:

\(Fr = \sqrt(F1^2 + F2^2 + 2 \times F1 \times F2 \times cosA)\\Fr = \sqrt(F^2 + (2 \times F)^2 + 2 \timesF \times2 \timesF \timescos(120)\\Fr = \sqrt(5 \times F^2 - 2 \timesF^2)\\Fr = F \times \sqrt(3)\)

Therefore, the net electric force on the charge is located at the lower right-hand corner of the triangle is \(Fr = \sqrt{3} \times\dfrac{q^2}{4 \times \pi \times 0 \times a^2 }\).

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The question is incomplete. Your most probably complete question is given below:

The image of the triangle is attached below:

What is the net electric force on the charge located at the lower right-hand corner of the triangle.

The charge of most alkaline earth metals.​

Answers

Answer:

2+ charge

Explanation:  The alkaline earth metals have two valence electrons in their highest-energy orbitals (ns2). They are smaller than the alkali metals of the same period, and therefore have higher ionization energies. In most cases, the alkaline earth metals are ionized to form a 2+ charge

Hope this helps, have a great day :)

if you were floating in the solar system at equal distances between mars (small mass) and jupiter (large mass) which planet would you be gravitational pulls to? Why

Answers

You would gravitate towards Jupiter because if it’s large mass it has a stronger gravitational pull

If you are floating in the solar system at equal distances between Mars which has a small and Jupiter which has a larger mass than Jupiter, the planet has the largest gravitational pull. So the planet which has a larger mass will have a more gravitational pull.

What is a Solar system?

The gravitationally bound system known as the Solar System is made up of the Sun and the asteroids that orbit it. It formed 4.6 billion years ago when a large interstellar molecular cloud gravitationally collapsed. Jupiter holds the lion's share of the system's remaining mass, with the Sun owning the vast majority of it.

Because Jupiter is the largest planet in our solar system, it has the strongest gravity. On Jupiter, you would weigh 2.5 times more than you would on Earth. Everything is drawn to the surface of the planet by the fundamental force of gravity.

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a canon mounted on the back of a ship fires a 50 kg canonball

Answers

A cannonball weighing 50 kg is fired from a cannon mounted on the back of a ship.

When the cannonball is fired from the cannon, it experiences an initial force propelling it forward. According to Newton's third law of motion, the cannonball exerts an equal and opposite force on the cannon. The magnitude of the cannonball's initial velocity can be determined based on factors such as the cannon's design, the amount of gunpowder used, and the angle at which the cannon is elevated.

However, since the cannon is mounted on the back of a ship, the ship's velocity must also be considered. When the cannonball is fired, it inherits the ship's initial velocity, both in terms of speed and direction. This means that the cannonball will not only move forward due to the force from the cannon but also continue moving with the ship's velocity.

The combined effect of the cannon's force and the ship's velocity results in the cannonball following a curved trajectory known as a projectile motion. Factors such as air resistance, gravity, and the ship's movement can influence the cannonball's path and distance traveled. To make precise calculations, additional information regarding the ship's speed and direction, as well as the angle of the cannon's elevation, would be necessary.

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A car travels 40 miles north in the first 40 minutes of a trip. The same car travels 30 miles west in the next 30 minutes of the trip. What can be said about the motion of the car?.

Answers

It can be said that the car which travels first at 40 miles in 40 minutes and then 30 miles in 30 minutes is traveling at a constant speed.

The formula and procedure we will use to solve this exercise is:

v = x /t

Where:

x = distancet = timev = velocity

Information about the problem:

t₁ = 40 minx₁= 40 milest₂ = 30 minx₂= 30 milesv₁ = ?v₂ = ?

Applying the velocity formula for the first data information of the travel, we get:

v₁ = x₁ /t₁

v₁ = 40 miles /40 min

v₁ = 1 mile/min

Applying the velocity formula for the second data information of the travel, we get:

v₂ = x₂ /t₂

v₂ = 30 miles /30 min

v₂ = 1 mile/min

As we notice v₁ = v₂ that means that the car is traveling with a constant speed during the trip

What is velocity?

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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The hydraulic tool holder is a type of what? A.port B. clamp C. Press D. Actuator​

Answers

Answer:

A

Explanation:

What is the speed of a kite that travels 120 meters in 4 seconds?

Answers

Answer:

30m/s

Explanation:

Use the formula

V= d /t

Answer:

30m/s

FORMULA

Use the formula
v d/t

In a photoelectric effect experiment, light with a wavelength of 4.12E-7 m is shone on a clean metal surface. The work function of the metal is 4.72 eV. What is the frequency of the incident ultraviolet light (in Hz)

Answers

The frequency of the incident Ultraviolet light is approximately 7.28 × 10^14 Hz

To find the frequency of the incident ultraviolet light, we can use the relationship between the speed of light, wavelength, and frequency:

c = λ * ν

where c is the speed of light (approximately 3.00 × 10^8 m/s), λ is the wavelength, and ν is the frequency.

Given:

λ = 4.12 × 10^(-7) m

First, we need to convert the work function from electron volts (eV) to joules (J). The conversion factor is 1 eV = 1.602 × 10^(-19) J.

Work function (Φ) = 4.72 eV * (1.602 × 10^(-19) J/eV)

≈ 7.56 × 10^(-19) J

Now, we can rearrange the equation to solve for frequency:

ν = c / λ

ν = (3.00 × 10^8 m/s) / (4.12 × 10^(-7) m)

≈ 7.28 × 10^14 Hz

Therefore, the frequency of the incident ultraviolet light is approximately 7.28 × 10^14 Hz.

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What kind of energy does an electromagnet use to pick up metallic objects?

Answers

Answer:

Magnetic energy is used by an electromagnet  to pick up metallic objects

Explanation:

An electromagnet generates its own magnetic field in presence of electric current.

As an electric current is induced in an electromagnet , it  magnetic dipole arrange themselves in order to behave as a magnet and hence generate magnetic field with a proper north and south. This leads to attraction of metallic object.

Hence, it can be said that Magnetic energy is used by an electromagnet  to pick up metallic objects

A mass of 15 X 10^5 kg is held at a position 9 m away from a mass of 20 X 10^6 kg. What is the gravitational attraction between the two masses?

Answers

Answer:

The gravitational attraction between the two masses is 24.7 N.

Explanation:

We have,

Mass of object 1, \(m_1=15\times 10^5\ kg\)            

Mass of object 2, \(m_2=20\times 10^6\ kg\)

Distance between masses is 9 m

We know that there exists a gravitational force between masses when they are placed at certain distance. The gravitational force between masses is given by :

\(F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{15\times 10^5\times 20\times 10^6}{(9)^2}\\\\F=24.7\ N\)

So, the gravitational attraction between the two masses is 24.7 N.

Which of the following is LEAST likely to be the result of a genetic mutation?
A
A horse with a particularly long neck
B
A man with a beard
С
An albino squirrel
D
A plant that produces fewer seeds than normal

Answers

Answer:

B. man with a beard

Explanation:

it is not a genetic mutation because it is completely natural and common unlike the other options.

how could you confirm the missing mass dissolved in the aqueous layer?

Answers

To confirm the missing mass dissolved in the aqueous layer, you can perform a process called evaporation followed by weighing the residue.

In this method, you would first collect the aqueous layer containing the dissolved substance.

Then, evaporate the water from the solution using an evaporating dish and a heat source.

Once all the water has evaporated, the dissolved substance will be left behind as a solid residue.

Weigh this residue using a precision balance to determine the missing mass.



Summary: By evaporating the water from the aqueous layer and weighing the remaining solid residue, you can confirm the missing mass that was dissolved in the aqueous layer.

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What energy transformation takes place when you push a pencil off your desk? A. Mechanical energy transforms into kinetic energy. B. Potential energy transforms into nuclear energy. C. Potential energy transforms into kinetic energy. D. Kinetic energy transforms into potential energy.​

Answers

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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