A 10.0 kg mass is lifted 5.0 m above the ground.
Find the change in gravitational energy.

Answers

Answer 1

Answer:

500 J

Explanation:

formula of Energy is: E=mass*height*g, where g≈10 (m/s²).

according to the formula above: E=10*5*10≈500 (J)


Related Questions

A particle has a charge of q = +4.7 μC and is located at the origin.

A particle has a charge of q = +4.7 C and is located at the origin.

Answers

(a) When the particle is stationary, it will only experience a force due to the electric field. The force is given by:

F = qE

where q is the particle's charge as well as E is the electric field.

Substituting the given values, we have:

F = (4.9 × 10⁻⁶ C)(242 N/C) = 1.19 × 10⁻³N

The net force is directed in the +x direction.

What is magnetic force?

Magnetic force is the force that arises between two magnetic objects or between a magnetic object and a moving charged particle. It is one of the four fundamental forces of nature, the others being the strong nuclear force, the weak nuclear force, and gravity.

The magnetic force is caused by the interaction between magnetic fields. When two magnetic objects are brought near each other, their magnetic fields interact and exert a force on each other.

(b) When the particle is moving along the +x axis at a speed of 345 m/s, it will experience both electric and magnetic forces. The electric force will be the same as in part (a). The Lorentz force equation may be utilized to calculate magnetic force:

F = q(v x B)

where v is the particle's velocity and B is the magnetic field.

Substituting the given values, we have:

F = (4.9 × 10⁻⁶ C)(345 m/s)(1.9 T) = 3.28 × 10⁻³ N

The right-hand rule can be used to determine the direction of the magnetic force.  If you point your thumb in the direction of the velocity vector (+x axis) and your fingers in the direction of the magnetic field vector (+x and +y axes), your palm will face in the direction of the magnetic force vector, which is in the +z direction.

Therefore, the net force on the particle is given by the vector sum of the electric and magnetic forces:

Fnet = (1.19 × 10⁻³ N) + (3.28 × 10⁻³ N) = 4.47 × 10⁻³ N

The net force is directed in the +z direction.

(c) When the particle is moving along the +z axis at a speed of 345 m/s, it will only experience a magnetic force. The magnetic force can be calculated using the same equation as in part (b):

F = q(v x B)

where v is the particle's velocity and B is the magnetic field.

Substituting the given values, we have:

F = (4.9 × 10⁻⁶ C)(345 m/s)(1.9 T) = 3.28 × 10⁻³ N

The right-hand rule can be used to determine the direction of the magnetic force.  If you point your thumb in the direction of the velocity vector (+z axis) and your fingers in the direction of the magnetic field vector (+x and +y axes), your palm will face in the direction of the magnetic force vector, which is in the -y direction.

Therefore, the net force on the particle is given by the magnetic force:

Fnet = 3.28 × 10⁻³ N

The net force is directed in the +y direction.

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6. In an integrated circuit, each wafer is cut into sections, which
ООО
A. have multiple circuits and are placed in individual cases.
B. carry a single circuit and are placed in individual cases.
C. carry a single circuit and are placed all together in one case.
D. have multiple circuits and are placed all together in one case.
o

Answers

Answer:

B. carry a single circuit and are placed in individual cases.

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

Similarly, an integrated circuit (IC) also referred to as microchip can be defined as a semiconductor-based electronic component that comprises of many other tiny electronic components such as capacitors, resistors, transistors, and inductors.

Integrated circuits (ICs) are often used in virtually all modern electronic devices to carry out specific tasks or functions such as amplification, timer, oscillation, computer memory, microprocessor, etc.

A wafer can be defined as a thin slice of crystalline semiconductor such as silicon and germanium used typically for the construction of an integrated circuit.

In an integrated circuit, each wafer is cut into sections, which generally comprises of a single circuit that are placed in individual cases.

Additionally, a semiconductor can be defined as a crystalline solid substance that has its conductivity lying between that of a metal and an insulator, due to the effects of temperature or an addition of an impurity.

Answer: B got it right on the test just now

Explanation:

Four objects labeled W, X, Y, and Z have different forces applied to them. All of the horizontal forces acting on each object are shown in the diagrams. Identify the example(s) that demonstrate(s) a change in motion.

Four objects labeled W, X, Y, and Z have different forces applied to them. All of the horizontal forces

Answers

The horizontal forces acting on each object are shown in the diagrams would only cause a change in motion in diagram A

When does force cause a change in motion?

A force causes a change in motion when it is unbalanced, meaning there is a net force acting on an object. According to Newton's first law of motion, an object at rest will remain at rest, and an object in motion will continue to move in a straight line at a constant speed, unless acted upon by an unbalanced force.

When an unbalanced force acts on an object, it will accelerate, meaning its velocity will change.

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A moving object of mass 0.01 kg experiences a drag force proportional to its speed square. The proportionality constant is C. If the object has an initial speed v = 10 m/s and after time T has energy 1/8 m v^2, then find C.

Answers

The proportionality constant of the moving object experiencing a drag force is 0.01875 Ns²/m².

How to calculate proportionality constant?

The work-energy principle states that the work done on an object is equal to its change in kinetic energy. So, the work done by the drag force can be found as follows:

W = (1/8)mv² - (1/2)mv₀²

where m = mass of the object, v = final speed, and v₀ = initial speed.

The work done by the drag force is also given by the formula:

W = ∫F(x)dx

where F(x) = force function and x = position of the object.

In this case, the force function is F(x) = -Cv², since the drag force is in the opposite direction of motion. So:

W = ∫-Cv²dx

Since the force is proportional to v², rewrite this as:

W = -C∫v²dx

Integrating both sides with respect to x:

W = -(1/3)Cv³

So, equating the two expressions for W:

(1/8)mv² - (1/2)mv₀² = -(1/3)Cv³

Substituting m = 0.01 kg, v₀ = 10 m/s, and solving for C:

C = -(3/8) × (m/v₀³) × (v² - v₀²) = -(3/8) × (0.01/10³) × (1/8 × 10² - 10²) = 0.01875 Ns²/m²

Therefore, the proportionality constant is C = 0.01875 Ns²/m².

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Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed

Answers

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

A plate of iron at 20 °C has shown in the figure below. If the temperature
raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7 o
1, then what is the final area of the plate?
(5
2 m
2 m

Answers

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.​

Answers

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Identify a scenario from
gym class that has an action-reaction force. Describe the situation

Answers

Answer:

A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).

Explanation:

You have a weight of W on earth. Find your new weight, in terms of W, if you go to a planet with a radius 3 times more a than Earth and a mass 2 times more than Earth.
A 6W
B 2W/3
C 2W/9
D 18W​

Answers

Hi there!

We know that the acceleration due to gravity is given by:

\(g = \frac{Gm_o}{r^2}\)

We can plug in the given values assuming that the above equation represents the earth's gravitational acceleration:

\(g_{planet} = \frac{G(2m)}{(3r)^2} = \frac{2}{9}(\frac{Gm}{r})\)

Since the acceleration due to gravity of this other planet is 2/9th of the acceleration due to gravity on earth, the weight:

W = mg, will also be 2/9ths of that of earth. The correct answer is C.

What does gravitational potential energy depend on?; What three things does gravitational potential depend on?; Does the gravitational potential energy of an object depends on the path?

Answers

The Gravitational potential energy depends on mass , acceleration and path and potential also as G=V/m.

a).  As you can imagine, gravitational energy is the energy associated with gravity. This is the potential energy stored due to an object being in a higher position compared to a lower position. (e.g. far from the ground or close to the ground).

Gravitational energy is the energy associated with gravity.

b). Systems can increase their gravitational energy as their mass moves away from the center of the Earth and away from other bodies (such as the sun, planets, and stars) large enough to generate a large amount of gravity. there is.

Potential energy can be defined as the amount of work expended to lift an object from the ground to its current height. In another sense, this is the amount of work the body does before returning to ground level (the position of maximum stability) when translated from its current level. Therefore, potential energy can be related to work.

c). A negative sign indicates that gravity is doing positive work as the mass approaches. A negative potential indicates a bonding state. That is, when mass is placed under its influence, it becomes trapped in its potential, and if something can provide the energy to escape the clutches of gravity, it must not escape.

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Compare the empirical equation from y=9.8x to V= gT + V0 to determine g and V0

Answers

Answer:

Explanation:

The empirical equation y = 9.8x represents the relationship between the displacement y of an object and the time x it has been falling under the influence of gravity.

On the other hand, the equation V = gT + V0 represents the relationship between the velocity V of an object, the time T, the initial velocity V0, and the acceleration due to gravity g.

To compare the two equations, we can equate the displacement y in the first equation with the expression for displacement in terms of velocity and time, which is y = (1/2)gt^2 + V0t, where t is the time.

Substituting this into the empirical equation, we get:

9.8x = (1/2)gt^2 + V0t

We can see that this equation has three variables: g, V0, and t. We can't determine all three variables from this equation alone.

However, if we know the time it takes for an object to fall a certain distance, we can use this equation to solve for g and V0. For example, if we know that an object falls 1 meter in 0.45 seconds, we can substitute x=1 and t=0.45 into the equation:

9.8(1) = (1/2)g(0.45)^2 + V0(0.45)

Simplifying this equation, we get:

g = 19.62 m/s^2

V0 = 0.45(9.8) = 4.41 m/s

So the acceleration due to gravity is 19.62 m/s^2 and the initial velocity is 4.41 m/s. Note that these values may not be exactly equal to the true values, as the empirical equation y=9.8x is only an approximation and there may be other factors affecting the motion of the object.

Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of uniform height
. The mass of each object is a multiple of the base mass
: object 1 has mass 4.60
, object 2 has mass 2.21
, and object 3 has mass
. When the objects are at the bottom of the steps, define the total gravitational potential energy of the three-object system to be zero.

Each answer requires the numerical coefficient to an algebraic expression that uses some combination of the variables , , and , where is the acceleration due to gravity. Enter only the numerical coefficient. (Example: If the answer is 1.23 , just enter 1.23)

Image showing three masses, 1, 2, and 3, and three steps, each of height D. The three masses are shown at the base of the steps. Arrows indicate that mass 1 is placed on the top step at height 3 D, mass 2 is placed on the middle step at height 2 D, and mass 3 is placed on the bottom step at height D.

If the objects are positioned on the steps as shown, what is gravitational potential energy ,system of the system?

If you redefine the reference height such that the total potential energy of the system is zero, how high ℎ0 above the bottom of the stairs is the new reference height?

Now, find a new reference height ℎ′0 (measured from the base of the stairs) such that the highest two objects have the exact same gravitational potential energy.

Three different objects, all with different masses, are initially at rest at the bottom of a set of steps.

Answers

a) The gravitational potential energy of the system of three masses at the given positions is 188.36md.

(b) The redefined reference height is h₀ = 0.55d.

(c) The new reference height measured from the base is h₀' = 0.96d.

What is the gravitational potential energy of the system?

(a) The gravitational potential energy of the system of three masses at the given positions is calculated as;

total gravitational potential energy = P.E(mass 1) + P.E(mass 2) + P.E(mass 3)

T.G.P.E = m₁gh₁ + m₂gh₂ + m₃gh₃

where;

mass of object 1, m₁ = 4.6mmass of object 2, m₂ = 2.21mmass of object 3, m₃ = mh₁ = 3dh₂ = 2dh₃ = d

T.G.P.E = (4.6m x 9.8 x 3d) + (2.21m x 9.8 x 2d) + (m x 9.8 x d)

T.G.P.E = 135.24md  +   43.32md  + 9.8md

T.G.P.E = 188.36md

(b) The redefined reference height is calculated as follows;

0 =  (4.6m x 9.8 x h₀) + (2.21m x 9.8 x (h₀ - d) + (m x 9.8 x (h₀ - 2d)

0 = 45.08mh₀ + 21.66mh₀ - 21.66md  +  9.8mh₀ - 19.6md

0 = 45.08h₀ + 21.66h₀ - 21.66d  +  9.8h₀ - 19.6d

0 = 76.54h₀ - 41.26d

76.54h₀ = 41.26d

h₀ = 41.26d/75.54

h₀ = 0.55d

(c) The new reference height measured from the base such that the highest two objects have the exact same gravitational potential energy is calculated as follows;

m₂gh₂ = m₁gh₁

2.21m x 9.8 x h₂ = 4.6m x 9.8 x h₁

21.66mh₂  =  45.08mh₃

21.66h₂  =  45.08h₁

h₁ = 21.66h₂/45.08

h₁ = 0.48h₂

h₀' = 0.48 x (2d)

h₀' = 0.96d

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What is the rotational kinetic energy (in J) of Jupiter in its orbit around the Sun? (Assume its distance from the sun to be 7.78 ✕ 108 km and its period about the sun to be 4340 days.)

Answers

The rotational kinetic energy (in J) of Jupiter in its orbit around the Sun is 1.613 × 10³⁵ J

What is rotational kinetic energy?

Rotational kinetic energy is kinetic energy due to rotation about an axis.

What is the rotational kinetic energy (in J) of Jupiter in its orbit around the Sun?

The rotational kinetic energy is given by K = 1/2Iω² where

I = rotational inertia of juptier around sun = MR² where M = mass of Jupiter = 1.898 × 10²⁷ kg and R = distance of jupiter from sun = 7.78 × 10⁸ km = 7.78 × 10¹¹ m, ω = angular speed of Jupiter around sun = 2π/T where T = period of Juptier around sun = 4340 days = 4340 × 24 h/day × 60 min/h × 60 s/min = 374976000 s = 3.74976 × 10⁸ s

So, We have that the rotational kinetic energy of Jupiter is

K = 1/2Iω²

K = 1/2(MR²)(2π/T)²

K = 1/2(MR²)(4π²/T²)

K = 2π²MR²/T²

Substituting the values of the variables into the equation, we have that

K = 2π²MR²/T²

K = 2π² × 1.898 × 10²⁷ kg × (7.78 × 10¹¹ m)²/(3.74976 × 10⁸ s)²

K = 2π² × 1.898 × 10²⁷ kg × 60.5284 × 10²² m²/14.0607 × 10¹⁶ s²

K = 2π² × 114.8829 × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²

K = 229.7658π² × 10⁴⁹ kgm²/14.0607 × 10¹⁶ s²

K = 16.3410π² × 10³³ kgm²/s²

K = 161.2791 × 10³³ kgm²/s²

K = 1.612791 × 10³⁵ kgm²/s²

K ≅ 1.613 × 10³⁵ J

So, the  rotational kinetic energy is 1.613 × 10³⁵ J

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The nature of light is difficult to grasp because light acts differently in different situations. For example, when light shines through narrow slits, the light behaves as only ________ can. However, when light shines onto a metal and the spray of electrons that comes off is examined, the light behaves as only _________ can.

Answers

Answer:

what do you need us to answer?

Explanation:

Example (2):
Convert the flow rate of 5L/min to
cm³/s.

Answers

5L into cm³

=5000 cm³ (since 1cm³=1mL)

1 minute into seconds

=60 s (basic knowledge of universal quantities)

So, 5L/min =

\( \frac{5000}{60} {cm}^{3}/s = \boxed{ 83.33{cm}^{3} /s} \)

what is the formula of sound??​

Answers

Answer:

The speed of sound can be computed as, speed of sound = the square root of (the coefficient ratio of specific heats × the pressure of the gas / the density of the medium).

...

c = \sqrt(\frac{\gamma \times P}{\rho})

c Speed of sound

\rho Density

\gamma Specific heat ratio

A force of 250 N is exerted on a cable wrapped around a drum with a diameter of 20 cm. What is the torque produced about the centre of the drum?​

Answers

The torque that is produced at the center of the drum is 50 Nm.

What is a torque?

The term torque has to do with a force that leads to a turning effect. I can use the example of a tap to show you what is meant by a torque. The force that is exerted on a tap causes the tap to turn and this is what we mean by saying that a torque would produce a turning effect.

We have the following;

Force = 250 N

Distance = 20 cm or 0.2 m

Torque = 250 N  *  0.2 m

= 50 Nm

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A small Keplerian telescope has an objective with a 1.33 m focal length. Its eyepiece is a 2.82 cm focal length lens. It is used to look at a 25000 km diameter sunspot on the sun, a distance 1.5*108 km from Earth.

Required:
What angle is subtended by the sunspot's telescopic image in degree?

Answers

Answer:

The angle is  \(\phi = 0.45 0 ^o\)

Explanation:

From the question we are told that  

     The objective  focal length   \(f = 1.33 \ m\)

     The  eyepiece focal length is  \(f_o = 2.82 \ cm = 0.0282 \ m\)

      The diameter of the sunlight is  \(d = 25000km = 2.5 *10^{7} \ m\)

       The distance of the sun from from the earth is  \(D = 1.5 *10^8 km = 1.5 *10^{11} \ m\)

  Generally the magnification of the object is mathematically evaluated as

        \(m = -\frac{f_o }{f_e }\)

The negative  sign is because the lens of the telescope is  diverging light

 substituting values  

      \(m = -\frac{1.33 }{0.0282 }\)

      \(m = - 47.16 3\)

Now we can obtain the angle made by the object (sunlight ) with respect to the telescope  as follows  

        \(tan \theta = \frac{d}{D}\)

substituting values

      \(tan \theta = \frac{2.5 *10^{7}}{1.5*10^{11}}\)

      \(tan \theta = 0.0001667\)

      \(\theta= tan^{-1}[0.0001667]\)

     \(\theta= 0.00955^o\)

The  magnification can  also be mathematically represented as

      \(m = \frac{\phi }{\theta }\)

Where \(\phi\) is the angle the image made with telescope

Since the negative sign indicate direction of light movement we will remove it from the calculation below

      =>   \(47.163 = \frac{\phi}{0.00955}\)

     =>    \(\phi = 0.45 0 ^o\)

Download the attached Word Document and follow the instructions to complete the lab. Please be sure to to answer all questions.

Copy and paste your answer in the box below or attach a Word Document (.doc or .docx) or PDF (.pdf).

Download the attached Word Document and follow the instructions to complete the lab. Please be sure to

Answers

Topic: The Effect of Temperature on Enzyme Activity in Plants
Hypothesis: I predict that as the temperature increases, the rate of enzyme activity in plants will also increase. As the temperature decreases, the rate of enzyme activity in plants will decrease.

What is temperature?

Temperature is the measure of the average kinetic energy of the particles in a substance. It is measured in degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K). Temperature is determined by the amount of heat present in a substance, which is a measure of the average kinetic energy of its particles. Heat is the energy transferred from a hotter object to a cooler one. When two objects of different temperatures come into contact, heat will flow from the hotter object to the cooler one until both objects reach the same temperature. Temperature can be affected by many factors, such as the weather, the amount of sunlight, and the activity of the particles in a substance.

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An adventurous dog strays from home, runs a distance L at an angle θ north
of East, then walk a distance D directly south
a.) How far from home is the dog? Express your answer in terms of L, D, and θ
b.)In what direction is the dog?Express your angle with respect to east.

Answers

Answer:

Explanation:

To solve this problem, we will use vector addition. We can represent the dog's displacement as two vectors: one that points north of east, and another that points directly south. Let's call the first vector A and the second vector B.

a.) The distance from home is the magnitude of the total displacement vector, which we can find by adding vectors A and B using the Pythagorean theorem:

|A + B| = sqrt[(L cosθ + (-D))^2 + (L sinθ)^2]

Simplifying this expression gives:

|A + B| = sqrt[L^2 + D^2 - 2LD cosθ]

Therefore, the distance from home is sqrt[L^2 + D^2 - 2LD cosθ].

b.) To find the direction of the displacement, we need to find the angle between the displacement vector and the eastward direction. We can use trigonometry to do this:

tanθ = opposite/adjacent = L sinθ / (L cosθ - D)

Simplifying this expression gives:

tanθ = (sinθ)/(cosθ - D/L)

Taking the inverse tangent of both sides gives:

θ = tan^-1[(L sinθ)/(L cosθ - D)]

We can express this angle with respect to east by subtracting 90 degrees if θ is acute (i.e., θ < 90 degrees) or adding 90 degrees if θ is obtuse (i.e., θ > 90 degrees).

Select the correct answer.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
O A.
B.
100 kilometers/hour south
200 kilometers/hour
200 kilometers/hour north
O C.
O D. 100 kilometers/hour

Answers

The average velocity of the car is 100 kilometers/hour south. This means that, on average, the car is traveling 100 kilometers per hour in the south direction relative to its starting point.

To determine the average velocity of the car, we need to calculate the displacement and divide it by the time taken. Velocity is defined as the rate of change of displacement with respect to time.

In this case, the car is traveling south, and its displacement is 200 kilometers from its starting point after 2 hours.

The average velocity is given by the formula:

Average velocity = Displacement / Time

The displacement is 200 kilometers south, and the time is 2 hours. Therefore, we have:

Average velocity = 200 kilometers south / 2 hours

Simplifying the calculation:

Average velocity = 100 kilometers/hour south

Hence, the correct answer is B. 100 kilometers/hour south. This indicates that the car's average velocity is 100 kilometers per hour towards the south direction.

It's important to note that velocity is a vector quantity and includes both magnitude (speed) and direction. In this case, the direction is specified as south, which indicates that the car is moving towards the south relative to its starting point.

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If an electromagnetic wave has a frequency of 6×10^5 hz, what is its wavelength? ​ what is its wavelength? A. 2 x 10^12m, B. 5 x 10^14m, C. 5 x 10^2m, 2 x 10^-3m

Answers

Answer:

5*10^2

Explanation:

A p e x

Why are rocks made of limestone usually an indication that an area was previously covered by ocean water

Answers

Answer:

what's the question? I don't understand

Answer:

Limestone can from form shell fragments of sea creatures

Explanation:

Compute the speed of sound waves in air at room temperature (T=200C) and find the range of wavelengths in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive. The mean molar mass of air (a mixture of principally nitrogen and oxygen) is 28.8 x 10-3kg/mol and the ratio of heat capacity is ϒ = 1.40.

Answers

The speed of sound waves in air at room temperature T=20° is 344.035 m/s.

The range of wavelength in air to which the human ear (which can hear frequencies in the range of 20 – 20,000Hz) is sensitive is  17.20 m to  0.0172 m.

What is wavelength?

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = c/f

where c is the speed of sound wave.

Given the room temperature T = 20 +273 = 293K

The velocity of sound wave is given by

v = √(γRT/m)

​where γ =1.4 , m = 28.8×10⁻³ kg/mol  R = 8.31 J/K.mol

Substituting the values, we get

v = 344.035 m/s

Thus, the speed of sound wave is 344.035 m/s

The human ear can hear frequencies in the range of 20 – 20,000Hz.

The wavelength corresponding to 20Hz is

λ = c/f

λ =  344.035 /20

λ  = 17.20 m

The wavelength corresponding to 20,000Hz is

λ =  344.035 /20000

λ  = 0.0172 m

Thus, the range of wavelength is 17.20 m to  0.0172 m sensitive to human ear.

Learn more about wavelength.

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Two objects are dropped from a bridge, an interval of 1.0 s apart, and experience no appreciable air resistance. As time progresses, the DIFFERENCE in their speeds


a.
increases.



b.
remains constant.


c.
decreases.



d.
increases at first, but then stays constant.



e.
decreases at first, but then stays constant.

Answers

Answer: a

Explanation:

A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood

Answers

The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:

k = Q / (A * ΔT * L) = Rth * (A * ΔT)

Reorganizing this equation gives:

Rth = k / (A * ΔT)

The given information in the problem is:

Rate of heat flow (Q) = 14.0 watts

Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C

Temperature difference (ΔT) = 28°C

Substituting these values into the equation, we have:

k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK

So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.

need help with these 4 ASAP. if u can answer even 1 of them that would be amazing! formula sheet provided

1. a) a mass of 5.0kg is at rest at the top of an inclined plane, 5.0m above the ground. if the inclined plane is frictionless, calculate the final velocity of the mass as it reaches the bottom of the inclined plane?

b) if the mass slides down the plane and encounters a spring with a force constant of 8000.00 N/m by how much will the spring be compressed when the mass comes to a stop?

c) if the mass is found to move down the inclined plane at a constant velocity what is the force of friction between the ramp and the mass? (the angle of incline is 30°)

2. a 12 m long ramp has its high end 4.0m above the low end. a crate of mass 10kg is given a sharp push so that it begins to slide down the ramp from the top of the ramp with an initial speed of 4.0m/s. the force of friction along the ramp is 20N. determine the speed of the crate at the bottom of the ramp.

3. a 7.0 kg crate is dropped from a window 8.0m above the ground. if the average air resistance on the crate is 20.0N, what is the crates kinetic energy and velocity upon reaching the ground?

4. a 0.25 kg puck moving with a constant speed across a 2.0m stretch of horizontal frictionless ice. how much work is done?

need help with these 4 ASAP. if u can answer even 1 of them that would be amazing! formula sheet provided1.

Answers

you may want to google the answers cuz that is a lot

What do Earth scientists do?

Answers

Answer:

Study Earth as a whole

Explanation:

ex. oxygen around Earth, layers, formations, temperature, mountains and how they form etc.

Answer:

Geologists study rocks and help to locate useful minerals. Earth scientists often work in the field—perhaps climbing mountains, exploring the seabed, crawling through caves, or wading in swamps. They measure and collect samples (such as rocks or river water), then they record their findings on charts and maps.

a single conservative force Fx= (2x+7) N acts on a particle of mass 6 kg as the particle moves along the X-axis from X1 = 1 m to X 2 = 5m. calculate the work done by this force​

Answers

Answer:

To calculate the work done by a force, we can use the formula:

Work = ∫F dx

In this case, the force is given by Fx = (2x + 7) N, and the particle moves along the X-axis from X1 = 1 m to X2 = 5 m. Let's calculate the work done.

Work = ∫(2x + 7) dx

Integrating the function (2x + 7) with respect to x, we get:

Work = (x^2 + 7x) evaluated from X1 to X2

Plugging in the values X2 = 5 and X1 = 1 into the expression, we have:

Work = (5^2 + 7 * 5) - (1^2 + 7 * 1)

= (25 + 35) - (1 + 7)

= 60 - 8

= 52

Therefore, the work done by the force is 52 Joules (J).

Explanation:

is thermoproteota a unicellular organism

Answers

Answer:

Yeah

Explanation:

Thermoproteota is a prokaryote.

Prokaryotes are unicellular

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