A 1599 kg car is traveling down the road at 83.4 km/h. While traveling at this rate of speed, what is the kinetic energy of this vehicle in kilojoules?

Ek=

A 56.87 g sample of a substance is initially at 30.0 °C. After absorbing 1475 J of heat, the temperature of the substance is 138.4 °C. What is the specific heat ( ) of the substance?

c=

Answer:

split 4 times 68, 34, 17, 8.5, 4.25.

Explanation:

pls mark brainlist tysm hope it helps

Answer:

i) 16.5g of ZnO

ii) 9.8 dm³ of NO2

Explanation:

The working is shown in the photo so kindly refer to it

Answer:

Explanation:

The number of atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.75 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

(a  ) Standard temperature and Pressure

(e) 0 C at 760 mmHg

(g)  273 K at 1 atm

Explanation:

The term STP is an abbreviation for STANDARD TEMPERATURE PRESSURE

STP is 0 degree 760mm Hg

            273 k at 1 atm( approximately)

so the correct options are

a, e, g

Answer:

In Fahrenheit it is 294.8°F and in Celsius it is 146°C.

Answer:

number of electrons, n

Gibbs free energy change, ΔG

temperature, T

coefficients from balanced redox equation (various)

Explanation:

The standard electrode potential of a cell can be obtained from;

∆G°= -nFE°cell

Also;

E°cell= RTlnK/nF

Where;

∆G°= standard free energy of the cell

n= number of electrons transferred

F= Faraday constant

E°cell= standard cell potential

R= universal gas constant

T= temperature

K= equilibrium constant

The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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Answer:

To calculate the [OH-] in the solution we must first find the pOH

That's

pH + pOH = 14

pOH = 14 - pH

First to find the pH we use the formula

From the question

[H3O+]= 2.6 × 10^-8 M

pH = - log 2.6 × 10^-8

pH = 7.6

pH = 8

So we pOH is

pOH = 14 - 8 = 6

To find the [OH-] we use the formula

6 = - log [OH-]

Find antilog of both sides

The solution is slightly basic since it's pH is in the basic region and slightly above the neutral point 7

Hope this helps you

The molar mass of the sugar is obtained as  1.43 g/mol.

We know that the boiling point of a substance is one of the properties of the substances that could be called the colligative properties since they can be affected by the number of particles present.

We are told that the mass concentration of the substances w/w of the solution is 17% thus we have 17 g of the compound and 83 g of water. We can now get the number of moles of the substance as;

Number of moles = ?

Mass of the solution = 1000 mL * 1.015 g/mL = 1015 g or 1.015 Kg

Given that;

ΔT = K m i

ΔT = Boiling point elevation

K = Boing constant of water

m = molality of the solution

i = Van't Hoff factor

ΔT = 106 °C - 100°C

= 6 °C

Then;

6 = 0.515 *  17/MM * 1/1.015 * 1

Where MM = molar mass of the sugar

6 = 0.515 * 17/1.015 MM * 1

6 = 0.515 * 17/1.015 MM

6 = 8.755/1.015 MM

6 * 1.015 MM =  8.755

MM =  8.755/6 * 1.015

MM = 1.43 g/mol

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Answer:

Explanation:We known that Earths energy machine is driven by sunlight which acts as fuel for this machine and to strike a balance between outgoing long wave radiation and short wave radiation there are many factors which are involved in this process.Sun emits this energy in the form of short wave radiation because of the huge energy it has and short wave radiation are higher in energy.Hence, they reach the earth surface mostly as visible and UV rays.After reaching the earths surface what happens with these rays is that they get absorbed by the clouds and other constituents of Earth.

Now, this energy needs to be emitted back in to space in order to balance out the energy budget of earth and that is why this energy is emitted back as long wave radiation which have less energy and also earth has less energy unlike the sun.Loss of this energy is essential as Earth looses most of its energy through this and results in cooling.But when this OLR decreases it should be a cause of concern for us.

This imbalance is caused by a wide range of different human induced activities which has a cumulative effect on the temperature of earth.These activities gives rise to a huge gain in the CO2 concentration which is why this word has gain so much popularity and a cause of widespread concern for us.At community level we contribute to this heating by increasing usage of personal automobiles rather than going for public transport , advancement in technology has greatly changed our lifestyles making it more simpler and easier but this demands more energy consumption.Landscape changes are one of the most important because its taking place at a faster rate.Most of the land being cleared off to built new houses which means clearing off the existing vegetation which leads to temperature rise.Setting up of Industry depending on its type can reduce the amount of OLR escaping the surface by introducing more amount of GHGs in to the atmosphere.

Its these small communities which add up to become the entire human population causing a massive damage and hence at community level if people realize and take necessary steps things will start to change.

Answer: the temperature would increase

Explanation:

because if one spot on the earth got the same amount of light through the summer and winter it would have a severe amount of drought and nothing to cool it down since all off it evaperated

Answer:

73.05g

Explanation:

1.25 mol NaCl * \(\frac{58.44g}{1 mol NaCl}\) = 73.05g

58.44g = molar mass of NaCl

The mean of the data set is approximately 4.0626, and the 90% confidence interval is [4.060925, 4.064275].

The sample mean (x) is calculated as follows:

x = (4.0620 + 4.0550 + 4.0650 + 4.0740 + 4.0550 + 4.0660) / 6

x ≈ 4.0626 (rounded to four decimal places)

The 90% confidence interval is calculated as follows;

Standard deviation (s):

(4.0620 - 4.0626)² = 0.00000036

(4.0550 - 4.0626)² = 0.00000576

(4.0650 - 4.0626)² = 0.00000006

(4.0740 - 4.0626)² = 0.00001328

(4.0550 - 4.0626)² = 0.00000576

(4.0660 - 4.0626)² = 0.00000012

average of the squared differences:

(0.00000036 + 0.00000576 + 0.00000006 + 0.00001328 + 0.00000576 + 0.00000012) / 6 ≈ 0.00000624

s = √(0.00000624)

s ≈ 0.002496

the standard error of the mean (SEM):

SEM = 0.002496 / √6

SEM ≈ 0.001018

For a 90% confidence interval, the z value is approximately 1.645.

ME = 1.645 * 0.001018 ≈ 0.001675

CI = x ± ME

CI = 4.0626 ± 0.001675

CI ≈ [4.060925, 4.064275]

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Answer:

C: They can freely bond with any other atom.

Explanation:

It is said that Because each carbon is identical, they all have four valence electrons, so they can easily bond with other carbon atoms to form long chains or rings

Answer:

P.S

Explanation:

Because sulphur has low electronegative magnitude, hence low polarity potential.

The sulphur atom doesn't not get distorted hence increase in ionic degree character.

Answer: A mass of 0.518 g of phenol must be dissolved in 25.0 g of naphthalene to produce a solution that is 0.22 m in phenol.

Explanation:

Given: Mass of naphthalene = 25.0 g

Molality = 0.22 m

This means that 0.22 moles of solute is present per kg of solvent.

As 25.0 g  of naphthalene is there that will be 25.0 g per 1000 g (1 kg) is equal to 0.025 kg.

Hence, moles of phenol are calculated as follows.

\(Molality = \frac{moles}{mass (in kg)}\\0.22 m = \frac{moles}{0.025 kg}\\moles = 0.0055 mol\)

Also, molar mass of phenol is 94.11 g/mol. This means that 1 mole of phenol contains 94.11 g.

Therefore, mass contained by 0.0055 moles of phenol is as follows.

\(0.0055 mol \times 94.11 g/mol \\= 0.518 g\)

Thus, we can conclude that a mass of 0.518 g of phenol must be dissolved in 25.0 g of naphthalene to produce a solution that is 0.22 m in phenol.

Answer:

48.4%

Explanation:

Mass percent is calculated by the equation:

mass of element / total mass * 100%

Plugging in the figures of the problem: 242g / 500g * 100% = 48.4% (grams are in the numerator and denominator, so they cancel out)

The mass percent of iron in the ore sample is 48.4 %.

The percentage of an element in a compound can be described as the number of parts by mass of that element present in 100 parts by mass of that compound.

The mass percentage of an element can be evaluated in two steps: First, determine the molecular mass of the given compound by the addition of the atomic masses of the elements. Then, the percentage of the elements can be determined by dividing the total mass of the element present in that compound by the molar mass of the given compound multiplied by 100.

Given, the mass of the iron in sample = 242 g

The total mass of the iron ore sample = 500 g

The mass percentage of the iron = (242/500) × 100 = 48.4 %

Therefore, the mass percentage of the iron in the iron ore sample is equal to 48.4%.

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The ph value of human saliva is between 6.2-7.6 with 6.7 being the average pH

ph value of human saliva is 7 and 6

The correct categorization of the solutions is:a. KCl - Neutral

b. ZnCl2 - Acidic

c. Ba(C2H3O2)2 - Basic

d. NH4I - Acidic

e. NaNO3 - Neutral

To determine whether a 0.5M solution of each salt is acidic, basic, or neutral, we need to analyze the nature of the ions present in the solution.

a. KCl: When KCl is dissolved in water, it dissociates into K+ and Cl- ions. Both K+ and Cl- are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.

b. ZnCl2: When ZnCl2 is dissolved in water, it dissociates into Zn2+ and 2Cl- ions. The presence of Zn2+ ions in the solution can hydrolyze water molecules, resulting in the formation of H+ ions. Therefore, the solution is acidic.

c. Ba(C2H3O2)2: When Ba(C2H3O2)2 is dissolved in water, it dissociates into Ba2+ and 2C2H3O2- ions. The acetate ions (C2H3O2-) can hydrolyze water, leading to the formation of OH- ions. Therefore, the solution is basic.

d. NH4I: When NH4I is dissolved in water, it dissociates into NH4+ and I- ions. The presence of NH4+ ions in the solution can undergo a weak hydrolysis, resulting in the formation of H+ ions. Therefore, the solution is acidic.

e. NaNO3: When NaNO3 is dissolved in water, it dissociates into Na+ and NO3- ions. Both Na+ and NO3- ions are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.

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Answer:

industrialization and rapid human population growth.

Explanation:

Hope this helps

Answer:

Water Pollution

Explanation:

Dumping industrial waste in ocean

Accidental oil leakages

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

When waves travel from one medium to another, they interact. When waves hit a new medium, they may bend or spread out instead of bouncing back like an echo. These three interactions of waves with matter are known as reflection, refraction, and diffraction.

Interactions include reflection, refraction, and diffraction. An example of wave reflection is an echo. Refraction occurs when waves bend at an angle as they enter a new medium. When waves spread out as they travel through an opening in an obstacle, this is referred to as diffraction.

When two or more waves collide, they interact with one another. Wave interference is the interaction of waves with other waves. When two waves traveling in opposite directions collide, wave interference occurs.

Thus, the interactions of waves with matter are known as reflection, refraction, and diffraction.

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Answer:

P2 = 1125 mmHg

Explanation:

Gas Pressure Calculation

To solve this problem, we need to use the combined gas law, which relates the pressure, volume, and temperature of a gas under different conditions. The combined gas law is given by:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature.

Let's start by calculating the initial conditions:

P1 = 750 mmHg

V1 = 120 cm^3

T1 = 25°C + 273.15 = 298.15 K (temperature in Kelvin)

Now we can plug in these values and solve for P2:

(P1V1)/T1 = (P2V2)/T2

(750 mmHg x 120 cm^3) / 298.15 K = (P2 x 150 cm^3) / (40°C + 273.15)

Simplifying this equation, we get:

P2 = (750 mmHg x 120 cm^3 x (40°C + 273.15)) / (298.15 K x 150 cm^3)

P2 = 1125 mmHg

Therefore, the pressure of the gas would increase to 1125 mmHg if its volume increased to 150 cm^3 at 40°C.

ChatGPT

As a result, 2.75 moles of KCLO3 are needed.

Divide the mass by the molar mass (122.6g/mole) of KClO3 to get the moles, which is 0.626. To determine the amount of O2 produced, multiply that by the molar ratio: (0.062) x (3/2) = 0.939 moles of oxygen.

The balanced chemical equation for KClO3's breakdown is:

2 KClO3(s) → 2 KCl(s) + 3 O2(g)

The equation states that 3 moles of O2 are created for every 2 moles of KClO3 that break down. Thus, we can apply a ratio to determine how much O2 is generated from 2.75 moles of KClO3:

(3 mol O2 / 2 mol KClO3) x 2.75 mol KClO3

= 4.125 mol O2

Now, we may convert moles to grammes using the molar mass of oxygen:

4.125 mol O2 x 32.00 g/mol

= 132 g O2

Therefore, 2.75 moles of KClO3 will produce 132 grams of O2.

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Answer:

There are 2 Hydrogen molecules in H2O

Explanation:

if you look at the symbol for Hydrogen (H) you see that there is a number beside it, to the right. That number shows how many molecules there are of that element.

(Sidenote: If there is no number there is only one molecule)

Hope this helped :)

We can see that an atom with 14 protons, 14 neutrons, and 16 electrons is unstable, and has a -2 charge.

So the correct option is the third one.

An atom with 14 protons, 14 neutrons, and 16 electrons is not stable. The number of protons in an atom, also known as its atomic number, determines its element and its chemical properties. In this case, the atom has 14 protons, which corresponds to the element silicon (Si) on the periodic table.

For an atom to be stable, it should have a balanced number of protons and electrons. Electrons are negatively charged particles that orbit the nucleus of an atom in energy levels or electron shells. The number of electrons in a stable atom should be equal to the number of protons, resulting in a neutral charge overall.

In this case, the atom has 14 protons and 16 electrons, which means it has two more electrons than protons, resulting in a net charge of -2. This is an example of an ion.

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Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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Answer:

\(m_{MgCO_3}=0.0202molMgCO_3\)

Explanation:

Hello,

In this case, for this purpose we first have to write the undergoing chemical reaction:

\(Na_2CO_3+Mg(NO_3)_2\rightarrow MgCO_3+2NaNO_3\)

Thus, since the mole ratio between the reactants is 1:1, we next identify the limiting reactant by computing the available moles of sodium carbonate and those moles of the same reactant consumed by the magnesium nitrate considering the given solutions:

\(n_{Na_2CO_3}=0.010L*0.300\frac{molNa_2CO_3}{1L}=0.003molNa_2CO_3 \\\\n_{Na_2CO_3}^{consumed}=0.006L*0.0400\frac{molMg(NO_3)_2}{1L}*\frac{1molNa_2CO_3}{1molMg(NO_3)_2} =0.00024molNa_2CO_3\)

In such a way, since less moles are consumed, we can say that the sodium carbonate is excess whereas the magnesium nitrate is the limiting one, therefore, the yielded mass of magnesium carbonate turns out:

\(m_{MgCO_3}=0.00024molMg(NO_3)_2*\frac{1molMgCO_3}{1molMg(NO_3)_2}*\frac{84.31gMgCO_3}{1molMgCO_3} \\\\m_{MgCO_3}=0.0202molMgCO_3\)

Regards.

The result of the computation when you follow the steps is 1.699.

A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"

What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.

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