A 1900 kg car accelerates from 12 m/s to 20 m/s in 9 s. The net force acting on the car is:

The lower limit of position determination for the electron is zero, and for the bullet, it is 0.0001 seconds

To determine the lower limit of position determination for each object, we need to calculate the uncertainty in their positions. The uncertainty in position is given by the product of the uncertainty in velocity and the time taken to measure the position.

For the electron:
Uncertainty in velocity = 0.0100% of 500 m/s = 0.0001 * 500 m/s = 0.05 m/s
Since electrons are very light, we can assume they can be measured instantaneously. Thus, the time taken to measure the position is negligible.
Therefore, the lower limit of position determination for the electron is zero.

For the bullet:
Uncertainty in velocity = 0.0100% of 500 m/s = 0.0001 * 500 m/s = 0.05 m/s
To determine the lower limit of position determination, we need to find the time taken to measure the position. Assuming the bullet is moving with constant velocity, we can use the equation s = vt, where s is the position, v is the velocity, and t is the time.
0.05 m/s = 500 m/s * t
t = 0.05 m/s / 500 m/s = 0.0001 s
Therefore, the lower limit of position determination for the bullet is 0.0001 s.

In conclusion, the lower limit of position determination for the electron is zero, and for the bullet, it is 0.0001 seconds.

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In Young's experiment, the pattern that appears on the screen is a result of interference between two sets of waves that are diffracted through two slits.

The location of the bright fringes in the pattern depends on the wavelength of the light used. This means that the path difference between the waves that interfere to produce this fringe is an integer multiple of the red light's wavelength (700 nm).

ΔL = mλ_red = nλ_other

where ΔL is the path difference between the waves, m and n are integers, λ_red is the wavelength of the red light, and λ_other is the wavelength of the second type of visible light.

Solving for λ_other, we get:

λ_other = (m/n) λ_red.

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Answer:

1.5x10^-4C

C=Couloumb's

Explanation:

Expression for the electric force between the two charges is given by -

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

F=25N

q1 = 1.9x10^-6 x 10^-6 C

q2 = ?

r = 0.32m

Substitute the given values in the above expression -

25N= 9x10^9 *1.9x10^-6 *q2 / 0.32m^2

25N= 17,100*q2 / 0.1024m

Next part is algebra     multiply both sides by 0.1024 to remove denominator

2.56=17,100*q2  

Divide both sides to isolate q2

q2= 1.5x10^-4C

Explanation:

Formula:

F*255.92778=K

83 F *255.92778=301.48k

therefore the answer is:

301.48K

An experiment that involves using a Landsat satellite is given below;

Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in  cape town, South Africa.

Rice is known to be one of the most vital  food staples in a lot of countries, especially South Africa . Due to the irrigated rice production that tend to  differs from other kinds of  agricultural fields, this study was said to have created a paddy field mapping model via the use of  phenological aspects, a lot of  satellite sensor data, and also the use of object-based approach.

This study  uses the phonological features of rice plants and also the use of an annual data regarding surface temperature (LST) to make the paddy map.

The core remote sensing data is made up of the yearly LST that is obtained from MODIS and multi-temporal Landsat-8 satellite imagery.

Based on the study, the total  accuracy and kappa coefficient for the pixel-based classification method is seen to be  92% and 0.89.

Hence, An experiment that involves using a Landsat satellite is Paddy lands detection through the use of Landsat-8 satellite images and object-based classification in  cape town, South Africa.

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\( \sf• \: Battery \: Voltage \: (V) = 9 \: v\)

\( \sf• \: Current \: (I) = 18 \: Amps.\)

\( \\ \)

\( \sf• \: The \: Resistance. \)

\( \\ \)

\( \huge\bf{ \underline{Solution :- }}\)

\( \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}\)

\( \rightarrow \sf R = \frac{9}{18} \)

\( \rightarrow \sf R = \frac{1}{2}\)

\( \rightarrow \sf R = 0.5\)

\( \\ \)

Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.

The position vector of the particle is given by:

r_(t) = ((5/3)t³× (1 - cos(t)) + t)× i + ((5/6)t³× (1 - sin(2t)) + 1)× j

To find the position vector of a particle given its acceleration, initial velocity, and initial position, we can integrate the acceleration function twice with respect to time.

Given:

Acceleration: a(t) = 10t×i×sin×(t)× j× cos×(2t)× k

Initial velocity: v(0) = i

Initial position: r(0) = j

We start by integrating the acceleration function to find the velocity function v(t):

v(t) = integration of [0 to t]× a_(t)× dt

Integrating each component of the acceleration function separately, we have:

v_(t) = integration of [0 to t]× (10t× i sin(t)× j cos(2t) ×k) dt

= integration of [0 to t]× (10t× i× sin(t)) dt + integration of [0 to t]× (10t j cos(2t)) dt

Integrating each term, we get:

v_(t) = [5t²× i ×(1 - cos(t))] + [5t²× j× (1 - sin(2t))] + C_(1)

Applying the initial condition v_(0) = i, we can find the constant C_(1):

v_(0) = [5(0)² ×i× (1 - cos(0))] + [5(0)² ×j ×(1 - sin(2(0)))] + C_(1)

i = C_(1)

Therefore, the velocity function becomes:

v_(t) = 5t²× i ×(1 - cos(t)) + 5t²× j (1 - sin(2t)) + i

Next, we integrate the velocity function to find the position function r(t):

r_(t) = integration of [0 to t] ×v_(t) ×dt

Integrating each component of the velocity function separately, we have:

r_(t) = integration of [0 to t]× (5t²× i ×(1 - cos(t)) + 5t² ×j (1 - sin(2×t)) + i)× dt

Integrating each term, we get:

r_(t) = [(5/3)t³× i× (1 - cos(t))] + [(5/6)t³× j ×(1 - sin(2t))] + (t× i) + C_(2)

Applying the initial condition r_(0) = j, we can find the constant C_(2):

r_(0) = [(5/3)(0)³× i× (1 - cos(0))] + [(5/6)(0)³× j× (1 - sin(2(0)))] + (0× i) + C_(2)

j = (0× i) + C(2)

j = C(2)

Therefore, the position function becomes:

r_(t) = (5/3)t³× i× (1 - cos(t)) + (5/6)t³× j× (1 - sin(2t)) + t× i + j

So, the position vector of the particle is given by:

r(t) = ((5/3)t³× (1 - cos(t)) + t)× i + ((5/6)t³× (1 - sin(2t)) + 1)× j

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The matching strand for the genetic code CGA would be D. GCT.

In DNA, the base pairs are formed between complementary nucleotides. Adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G).

Given the genetic code CGA, we need to determine the matching strand.

The complementary strand is formed by pairing each base with its complementary base.

For CGA, we have:

C pairs with G

G pairs with C

A pairs with T

So, the matching strand for the genetic code CGA would be GCT.

Thus, in the given example, the matching strand for the genetic code CGA is GCT. This means that on the opposite strand of the DNA double helix, the sequence would be TGC. The complete sequence given TGC GGG TAT GCT represents one side of the DNA double helix, with its complementary strand having the sequence CGA CCC ATA CGA. Therefore, Option D is correct.

The question was incomplete. find the full content below:

The base T pairs with A, and C pairs with G. If the genetic code is CGA, what would be the matching strand?

A. TGC

B. GGG

C. TAT

D. GCT

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The car will appear to be 10% lighter than its normal weight when traveling at a speed of about 16.7 m/s.

When the car is going over the top of the hill, the apparent weight of the occupants will be less than their actual weight due to the centrifugal force acting on them.

The centrifugal force acting on the occupants is given by:

Fc = ma

where Fc is the centrifugal force, m is the mass of the occupants, and a is the centripetal acceleration.

The centripetal acceleration is given by:

a = v^2 / r

where v is the velocity of the car and r is the radius of the hill.

The apparent weight of the occupants can be found using:

Wapp = Wactual - Fc

where Wactual is the actual weight of the occupants and Wapp is the apparent weight.

If the occupants appear to weigh 10% less than their average weight, then:

Wapp = 0.9 * Wactual

Substituting the equations for F and a we get:

0.9 * Wactual = Wactual - m * v^2 / r

Simplifying, we get:

m * v^2 / r = 0.1 * Wactual

v^2 = 0.1 * Wactual * r / m

We can express the weight in terms of mass using the formula:

W = m * g

where W is the weight, m is the mass, and g is the acceleration due to gravity.

Substituting, we get:

v^2 = 0.1 * m * g * r / m

v^2 = 0.1 * g * r

Solving for v, we get:

v = √(0.1 * g * r)

Plugging in the values, we get:

v = √(0.1 * 9.81 m/s^2 * 350 m)

v = 16.7 m/s

Therefore, the velocity of the car at which the occupants will appear to weigh 10% less than their average weight is approximately 16.7 m/s.

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When the rate of the forward reaction equals the rate of the backward reaction, the system is said to be dynamic equilibrium. Hence option B is correct.

A dynamic equilibrium exists in chemistry when a reversible reaction occurs. Substances transition at equal rates between reactants and products, implying that there is no net change. Reactants and products are generated at such a rapid rate that neither's concentration changes. It's an example of a system in a steady state.

A closed system is in thermodynamic equilibrium in physics when reactions occur at such rates that the composition of the mixture does not vary with time. Reactions do occur, sometimes violently, but not to the point that changes in composition may be recognised. Equilibrium constants can be stated in terms of reversible reaction rate constants.

Hence option B is correct.

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The downward force of the atmosphere on the book is equal to the pressure of the atmosphere multiplied by the surface area of the book's cover and it is calculated to be 5 N.

Atmospheric pressure is the pressure exerted by the weight of the Earth's atmosphere on objects on or near the surface of the Earth. It is caused by the gravitational attraction of the Earth on the gases in the atmosphere. The atmospheric pressure varies with altitude, temperature, and weather conditions, and is typically measured in units of pressure such as pascals (Pa) or kilopascals (kPa).

Force = Pressure x Area

Where:

Pressure = 100 kPa (given)

Area = 0.05 m² (given)

Substituting the given values, we get:

Force = 100 kPa x 0.05 m²

Force = 5 N

Therefore, the downward force of the atmosphere on the book is 5 N.

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The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Distance from spot shines =  12 m away

Height of man,h=2 m tall

Speed of man +1.6 m/s,

Distance from the building = 4 m

Let the height of shadow= y,

CD=x

Height of man=2 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

As the triangle ABD and ECD are similar. The property of the similarity is found as;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)

Differentiate the above question with respect to x;

\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)

From the given conditions the man is 4 m from  the building the value of the remaining distance x is;

x=12-4

x=8 m

Speed of man:

\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)

On putting all the values we get;

\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)

The speed of man when the  length of his shadow on the building decreases when he is 4 m from the building;

\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)

Hence the value of the speed for the given conditions willl be 0.6 m/sec.

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Answer:

Electron affinity is the energy change that results from adding an electron to a gaseous atom. For example, when a fluorine atom in the gaseous state gains an electron to form F⁻(g), the associated energy change is -328 kJ/mol.

Give brainliest please.

Answer:

Electron affinity is the energy change that results from adding an electron to a gaseous atom.

Sorry I don't know about the second one.

Answer:

Formula = D = m/v

Given value of D = 19.3 and m = 13g

19.3 = 13/v

V × 19.3 = 13

v = 13/19.3

v = 0.67

The amount of work required to stretch the spring to 40 cm beyond its original length is 5333 J.

Spring is defined as an elastic object which gets deformed from its original shape when an external force is applied to it and again reverts back to its original shape when the external force is removed. When a force is placed on a material, the material stretches or compresses in response to the force. The length of the extension is directly proportional to the amount of force applied to it. Hence more the extension more the force is applied. Force and stretch are proportional to one another such that if you double the force applied, the amount of stretching of the spring will also be double. F 1 =kx 1, 3=k×20. This spring constant  k= 20/3 N/m. Now, W= ½ k x^2 =1/2×20/3×40×40= 5333 J.

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A reference frame is a perspective from which you observe and measure things. Used to define the movement and position of objects. Two people can have different frames of reference for the same situation. In this case, they observe the movement and position of objects differently.

A reference frame is a perspective from which you observe and measure things. Used to define the movement and position of objects.

Two people can have different frames of reference for the same situation. In this case, they observe the movement and position of objects differently.

Units are a way of expressing measurements. It can consistently describe object velocity, mass, position, etc.

Scientists need to communicate their data clearly. They do this by sharing the units and frame of reference they use to measure.

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Answer:

11. A door accelerating when pushing it.

12. A person sliding along the floor.

13. Water dropping from the faucet.

14. Courtains descending when loosening them.

Explanation:

For kinetic energy, any example that does not move horizontally will do. Something accelerating or decelerating is a good example (Ek=1/2mv^2, where v is velocity).

For potential energy try to think of things moving vertically. Potential energy comes from the height of an object (Ep=mgh, where h is height).

Notice that example 13 and 14 represent potential energy turning into kinetic energy, height becomes lower, so velocity increases.

Answer:

54,000 J

Explanation:

Given,

Power ( P ) = 75 W

Time ( t ) = 12 minutes

To find : Electrical energy ( E ) = ?

t = 12 minutes

= 12 x 60

t = 720 seconds

Formula : -

E = Pt

E = 75 x 720

E = 54,000 J

Therefore,

54,000 J is the electrical energy is used by a 75 W laptop that is operating for 12 minutes.

The eccentricity of the object's orbit can be determined by using the ratio of its maximum angular speed to its minimum angular speed.

Let's denote the maximum angular speed as ω_max and the minimum angular speed as ω_min. We are given that the ratio of these two speeds is n:

n = ω_max / ω_min

The angular speed (ω) is related to the angular momentum (L) and the moment of inertia (I) of the object by the equation:

L = Iω

Since the object moves in an inverse square centripetal force field, the angular momentum (L) is conserved. Therefore, we can write:

L_max = L_min

Iω_max = Iω_min

The moment of inertia (I) can be expressed as the product of the mass (m) and the square of the distance (r) from the object to the axis of rotation:

I = mr^2

Substituting this into the equation above, we get:

m(r^2)ω_max = m(r^2)ω_min

Canceling out the mass (m) and the square of the distance (r^2), we obtain:

ω_max = ω_min

This implies that the maximum and minimum angular speeds are equal, contradicting the given ratio n = ω_max / ω_min. Therefore, there must be an error in the question or the provided information.

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Answer:

P = 200 W

Explanation:

The expression for the power is

        P = W / t

the job

       W = F d

we substitute

      P = F d / t

      P = F. v

We apply this equation to our case where the velocity is

 v = (5 i + 3j + 6k) m / s

and the force is

 F = (10i + 10j +20 k) N

we substitute in the power equation, remember that the scalar product of the unit vectors is

i.i = j.j = k.k = 1 and the other products are zero

    P = 10 5 + 10 3 + 20 6

    P = 200 W

When we pump air into a bicycle tire, we are increasing the amount of air molecules inside the tire. The air molecules inside the tire move around randomly and collide with the tire walls. As we pump in more air, the number of air molecules increases, and they collide with the tire walls more frequently.

The increased collisions exert a force on the tire walls, and this force is what we feel as the tire pressure. The tire pressure is directly proportional to the number of air molecules inside the tire. As we pump in more air, the tire pressure increases.

The pressure inside the tire is measured in pounds per square inch (PSI). A typical bicycle tire requires around 60 PSI of pressure for optimal performance.

It's essential to maintain the correct tire pressure because it affects the bike's handling, speed, and overall safety. Too little pressure makes the bike sluggish and harder to ride, while too much pressure increases the risk of the tire bursting.

In summary, pumping air into a bicycle tire increases the number of air molecules inside, which leads to increased collisions with the tire walls and an increase in pressure inside the tire.

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Answer:

The suitcase weighs 225N

Explanation:

Weight can be defined as the force of gravity acting on an object. The unit of the weight of an object is Newton because it is a force.

Given that mass = 22.5

Weight = ?

Weight = mass × acceleration due to gravity.

Acceleration due to gravity = 10m/s2

W = mg

W = 22.5 × 10

W = 225N.

Hence, the suitcase weighs 225N.

The convex spherical mirror is the diverging mirror. The image distance is 20.4 cm. The magnification is 0.417. The image is virtual and upright.

Magnification is the ratio of image distance to the object distance.

Object distance is 49 cm and the focal length of convex mirror is 35 cm, then image distance is calculated by the lens maker formula.

1/f = 1/v +1/u

1/-35 = 1`/v +1/49

v= -20.4 cm

Thus, the image distance is 20.4 cm.

The magnification is given by

m = v/u

m = -20.4 / 49

m = 0.417

Thus, the magnification is 0.417.

The image formed is by virtual meeting of light rays and above the principle axis. Thus the image is virtual and upright.

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Answer:

7 feet because 2 feet and 5 feet make seven.

In series: The combined resistance is equal to the sum of the individual resistances (R_total = R1 + R2 + R3).

In parallel: The combined resistance is the reciprocal of the sum of the reciprocals of the individual resistances (1/R_total = 1/R1 + 1/R2 + 1/R3).

When resistors are connected in series, their resistances add up to give the total resistance. In this case, the combined resistance in series would be the sum of the individual resistances: R_total = R1 + R2 + R3.

On the other hand, when resistors are connected in parallel, their reciprocals sum up to give the inverse of the total resistance. In this case, the formula for calculating the combined resistance in parallel is: 1/R_total = 1/R1 + 1/R2 + 1/R3.

Let's assume the resistance values are R1 = 1 ohm, R2 = 2 ohms, and R3 = 3 ohms.

For the series connection: R_total = R1 + R2 + R3 = 1 + 2 + 3 = 6 ohms.

For the parallel connection: 1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/1 + 1/2 + 1/3 = (6 + 3 + 2) / 6 = 11 / 6. Taking the reciprocal of both sides, we get R_total = 6 / 11 ohms.

Therefore, the combined resistance in the series connection is 6 ohms, while in the parallel connection, it is 6/11 ohms.

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As per the given data of velocity of sound wave through different gas medium, sound wave travels through methane gas more fastly than through ammonia.

Sound waves are longitudinal mechanical waves passing through a medium. In sound waves,, the oscillation of particles is in the same direction of wave propagation. Such waves are called longitudinal waves.

Sound waves travels through air with a speed of 340 m/s. The speed of the wave through different medium depends on  the density of the medium as well as frequency.

The speed of sound wave through ammonia gas is 415 m/s. Speed through methane gas is 450 m/s. Thus, sound waves travels fastly through methane than through ammonia.

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