A 2 liter drink costs $0.15 per deciliter. How much will the drink cost? please i need the answer for a quiz thats due tommarow

Answer:

5

Step-by-step explanation:

\(8:5=15:x\\8*x=15\\(8*x)/8=15/8\\x=1.875\\\\\frac{8}{5} *1.875=\frac{15}{x} \\\frac{8}{5} *1.875=3\\3=\frac{15}{x}\\x=5\)

The absolute value of the error in the instructor's estimate is 0.644.

To find the absolute value of the error in the instructor's estimate, we need to calculate the difference between the sample mean and the population mean.

Given:

Population mean (μ) = 3.15

Sample mean (\(\bar{X}\)) = (3.89 + 4.00 + 3.85 + 3.77 + 3.81 + 3.43 + 3.28 + 3.27 + 3.56 + 3.92) / 10

= 36.78/10

= 3.678

Absolute value of the error = |\(\bar{X}\) - μ|

|\(\bar{X}\) - μ| = |3.678 - 3.15| = 0.528

Therefore, the absolute value of the error in the instructor's estimate is 0.644.

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The relationship between variables p and q is given by p = kq. Also, the value of the variable p when q = 16 is 6 and when p = 2.4, the variable q is 6.4.

Mathematically, a proportional relationship can be represented with the following mathematical expression:

p = kq

Where:

Next, we would determine the constant of proportionality (k) as follows:

Constant of proportionality (k) = p/q

Constant of proportionality (k) = 4.5/12

Constant of proportionality (k) = 0.375.

When q = 16, the variable p is given by:

p = kq

p = 0.375 × 16

p = 6.

When p = 2.4, the variable q is given by:

q = p/k

q = 2.4/0.375

q = 6.4

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The experimental probability of rolling a 1 or a 2 is 0.2.

Hence, Option A is correct.

We know that,

The experimental probability of an event is defined as the number of times the event occurred divided by the total number of trials.

In this case,

The event is rolling a 1 or a 3,

Which occurred ⇒  3 + 1

                           = 4 times.

Given that there are total number of trials = 20.

Therefore,

The experimental probability of rolling a 1 or a 3 = 4/20,

                                                                                = 1/5

                                                                                 = 0.2

Hence, the required probability is 0.2.

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The complete question is:

Sarah is playing a game in which she rolls a number cube 20 times. The results are recorded in the chart below. What is the experimental probability of rolling a 1 or a 3?

Number on cube:1,2,3,4,5,6

Number of times event occurs:3,6,1,5,3,2

A.0.2

B.0.3

C.0.6

D.0.83

Answer:

Step-by-step explanation:

its D, (8 x 4)-(5-6-8)

Answer:

the correct answer will be 88

Answer:

Area of the shaded region 45.76 cm².

Step-by-step explanation:

Firstly, finding the area of rectangle by substituting the values in the formula :

\({\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}}\)

\(\begin{gathered} \qquad{\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} = 12\times 8}}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} = 96}}}\\\\\qquad{\star{\boxed{\sf{\pink{A_{(Rectangle)} = 96 \: {cm}^{2}}}}}} \end{gathered}\)

Hence, the area of rectangle is 96 cm².

\(\rule{200}2\)

Secondly, finding the area of circle by substituting the values in the formula :

\({\longrightarrow{\pmb{\sf{A_{(Circle)} = \pi{r}^{2}}}}}\)

\(\begin{gathered} \qquad{\longrightarrow{\sf{A_{(Circle)} = \pi{r}^{2}}}} \\ \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14{(4)}^{2}}}} \\ \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14{(4\times 4)}}}} \\ \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14(16)}}} \\ \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14 \times 16}}} \\ \\ \qquad{\longrightarrow{\sf{A_{(Circle)} \approx 50.24}}} \\ \\ \qquad{\star{\boxed{\sf{\purple{A_{(Circle)} \approx 50.24 \: {cm}^{2}}}}}} \end{gathered}\)

Hence, the area of circle is 50.24 cm².

\(\rule{200}2\)

Now, finding the area of shaded region by substituting the values in the formula :

\(\longrightarrow{\pmb{\sf{A_{(Shaded)} = A_{(Rectangle)} - A_{(Circle)}}}}\)

\(\begin{gathered}{\quad{\longrightarrow{\sf{A_{(Shaded)} = A_{(Rectangle)} - A_{(Circle)}}}}}\\\\{\quad{\longrightarrow{\sf{A_{(Shaded)} = 96 - 50.24}}}}\\\\{\quad{\longrightarrow{\sf{A_{(Shaded)} \approx 45.76}}}}\\\\{\quad{\star{\boxed{\sf{\red{A_{(Shaded)} \approx 45.76 \: {cm}^{2}}}}}}} \end{gathered}\)

Hence, the area of shaded region is 45.76 cm².

\(\rule{300}{2.5}\)

Approximately 0.357 or 35.7% of customers require more than 12 minutes to check out.

Since the checkout times are exponentially distributed with a mean of 5.5 minutes, we can use the exponential distribution formula to find the probability that a customer will take more than 12 minutes to check out:

P(X > 12) = 1 - P(X ≤ 12)

where X is the checkout time.

To find P(X ≤ 12), we can use the cumulative distribution function (CDF) of the exponential distribution, which is:

F(x) = 1 - e^(-λx)

where λ is the rate parameter of the distribution. For an exponential distribution with mean μ, the rate parameter λ is equal to 1/μ.

So, in our case, λ = 1/5.5 = 0.1818, and we can calculate P(X ≤ 12) as:

P(X ≤ 12) = F(12) = 1 - e^(-0.1818 × 12) ≈ 0.643

Therefore, the probability that a customer will take more than 12 minutes to check out is:

P(X > 12) = 1 - P(X ≤ 12) ≈ 1 - 0.643 ≈ 0.357

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The total number of possible 7-place license plates are 67600000.

Given: A 7-plate license plate. 2 places are for letters and 5 places are for numbers. To find how many different 7-plate license plates are possible

Let's solve the given problem:

The license plate has 7 places. 2 places are for letters and the remaining 5 places are for numbers.

Therefore, the total number of ways in which the 7-place license plate can fill are: Total possible ways in which the two letters can be filled × Total possible ways in which the 5 number places can be filled

= 676 × 100000

= 67600000 ways

Hence the total number of possible 7-place license plates are 67600000.

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Answer:

43.35 years

why?

From the above question, we are to find Time t for compound interest

The formula is given as :

t = ln(A/P) / n[ln(1 + r/n)]

A = $2500

P = Principal = $200

R = 6%

n = Compounding frequency = 1

First, convert R as a percent to r as a decimal

r = R/100

r = 6/100

r = 0.06 per year,

Then, solve the equation for t

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06/1)] )

t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06)] )

t = 43.346 years

(credit to VmariaS)

The equation that Nathan can use to find w, the number of comic books Nathan originally had in his collection is w - 42 = 1752.

From the information, Susan will buy 42 comic books from Nathan for $0.75 per comic book. After the purchase, Nathan will have 1,752 comic books left in his collection.

Let the the number of comic books Nathan originally had in his collection be w.

This will be illustrated as:

w - 42 = 1752

w = 1752 + 42.

w = 1794

He originally had 1794 books.

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To find the median of two sorted arrays of sizes m and n, we need to merge the two arrays into one sorted array and then find the median of that array. However, we can't simply merge the two arrays using a linear approach as it would take O(m+n) time, which doesn't meet the requirement of O(log(m+n)) time. Instead, we can use a binary search algorithm to find the median in O(log(m+n)) time.

The basic idea is to compare the medians of the two arrays and eliminate half of the elements from one or both of the arrays based on their comparison with the median. We keep doing this until we are left with only one or two elements, and then we can easily calculate the median.

Here's how the algorithm works:

1. Initialize two pointers, one for each array, and set their values to the beginning and end of the respective arrays.
2. Calculate the midpoints of the two arrays and compare their values.
3. If the median of the first array is greater than the median of the second array, then we know that the median of the combined array will be in the first half of the first array and the second half of the second array. So we can eliminate the second half of the second array and the first half of the first array by adjusting the pointers accordingly.
4. If the median of the second array is greater than the median of the first array, then we know that the median of the combined array will be in the second half of the first array and the first half of the second array. So we can eliminate the first half of the second array and the second half of the first array by adjusting the pointers accordingly.
5. Repeat steps 2-4 until we are left with only one or two elements.
6. If we are left with one element, then that element is the median. If we are left with two elements, then the median is the average of the two elements.

This algorithm runs in O(log(m+n)) time because we are eliminating half of the elements in each iteration, which results in a logarithmic time complexity.

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Answer: 926

Step-by-step explanation:

1. 920- 444= 476

2. 476+450= 926

3. 926

Answer:926

Step-by-step explanation:because 920 - 444 = 476 + 450 = 926

The inverse function of f(x) = 7x + 6 is f −1(x) = (x - 6) / 7. This inverse function allows us to obtain the original input value (x) when given the output value (f −1(x)).

To find the inverse function, we need to swap the roles of x and y and solve for y. Let's start with the equation f(x) = 7x + 6:

Step 1: Swap x and y:

x = 7y + 6

Step 2: Solve for y:

x - 6 = 7y

Divide both sides by 7:

(x - 6) / 7 = y

Step 3: Replace y with f −1(x):

f −1(x) = (x - 6) / 7

The resulting equation, f −1(x) = (x - 6) / 7, is the inverse function of f(x) = 7x + 6. It allows us to retrieve the original input value (x) when given the output value (f −1(x)). The inverse function "undoes" the actions of the original function, reversing the calculations performed by f(x).

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The expected value of the continuous random variable V is 5. The expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

To calculate the expected value of a continuous random variable V with a given probability density function (PDF), we integrate the product of V and the PDF over its entire range.

The PDF of V is defined as:

f(v) = 6/24 = 0.25 for 3 ≤ v ≤ 7, and 0 otherwise.

The expected value of V, denoted as E(V), can be calculated as:

E(V) = ∫v * f(v) dv

To find the expected value, we integrate v * f(v) over the range where the PDF is non-zero, which is 3 to 7.

E(V) = ∫v * (0.25) dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * ∫v dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * [(v^2) / 2] evaluated from 3 to 7.

E(V) = (0.25) * [(7^2 / 2) - (3^2 / 2)].

E(V) = (0.25) * [(49 / 2) - (9 / 2)].

E(V) = (0.25) * (40 / 2).

E(V) = (0.25) * 20.

E(V) = 5.

Therefore, the expected value of the continuous random variable V is 5.

The expected value represents the average value or mean of the random variable V. It is the weighted average of all possible values of V, with each value weighted by its corresponding probability. In this case, the expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

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Answer:

Step-by-step explanation:

y=10

The Total surface area of each given figure are:

g) 165 in²

h) 869 in²

i) 1146.57 ft²

j) 400 m²

g) The area of a triangle is given by the formula:

Area = ¹/₂ * base * height

Area of left triangle = ¹/₂ * 10 * 8 = 40 in²

Area of right triangle = ¹/₂ * 10 * 25 = 125 in²

Total surface area = 40 in² + 125 in²

Total surface area = 165 in²

h) This will be a total of the trapezium area and triangle area to get:

Total surface area = (¹/₂ * 22 * 19) + (¹/₂(22 + 38) * 22)

Total surface area = 209 + 660

Total surface area = 869 in²

i) Total surface area is:

T.S.A = (50 * 30) - ¹/₂(π * 15²)

T.S.A = 1146.57 ft²

j) Total surface area is:

TSA = 20 * 20 (This is because the removed semi circle is equal to the additional one and when we add it back to the square, it becomes a complete square)

TSA = 400 m²

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By the demand equation for a certain commodity, the price at which there is unitary elasticity is approximately $78.18 per unit

To find the price at which there is unitary elasticity, we need to determine the price (p) when the elasticity of demand is equal to 1.

The elasticity of demand can be calculated using the formula:

E = (dq/dp) x (p/q)

Given the demand equation: 550p + q = 86,000, we can solve for q in terms of p:

q = 86,000 - 550p

Now, we differentiate q with respect to p to find dq/dp:

dq/dp = -550

Substituting these values into the elasticity formula:

1 = (-550) x (p / (86,000 - 550p))

Simplifying the equation:

p = (86,000 - 550p) / 550

Multiplying both sides by 550 to eliminate the denominator:

550p = 86,000 - 550p

Combining like terms:

1100p = 86,000

Dividing both sides by 1100:

p = 78.18

Therefore, the price at which there is unitary elasticity is approximately $78.18 per unit (rounded to two decimal places).

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we can expect that approximately 815 employees owned a petrol car in 2019 (rounded to the nearest integer).

We can model the number of employees owning petrol cars in the years 2010 and 2013 using the exponential decay formula:

\($$N(t) = N_0 e^{-kt}$$\)

where N(t) is the number of employees owning petrol cars at time t, \($N_0$\) is the initial number of employees owning petrol cars (in 2010), k is the decay constant, and t is the time elapsed since 2010 (in years).

We can use the given information to find the value of k:

In 2013 (3 years after 2010), the number of employees owning petrol cars decreased from 2187 to 1536:

\($$1536 = 2187 e^{-3k}$$\)

Dividing both sides by 2187 gives:

\($$e^{-3k} = \frac{1536}{2187}$$\)

Taking the natural logarithm of both sides gives:

\($$-3k = \ln\left(\frac{1536}{2187}\right)$$\)

Solving for k gives:

\($k = -\frac{1}{3} \ln\left(\frac{1536}{2187}\right) \approx 0.1565$$\)

Now we can use the exponential decay formula to find the number of employees owning petrol cars in 2019 (9 years after 2010):

\($$N(9) = 2187 e^{-0.1565 \cdot 9} \approx 815$$\)

Therefore, we can expect that approximately 815 employees owned a petrol car in 2019 (rounded to the nearest integer).

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The answer is approximately 68% of the scores in a normally distributed set of data will fall within one standard deviation (-1 to +1) of the mean, according to the empirical rule.

According to the empirical rule, approximately 68% of the scores in a normally distributed set of data will fall within one standard deviation (i.e., within -1 to +1 standard deviation) of the mean. This is also known as the 68-95-99.7 rule or the three-sigma rule, which states that:

Approximately 68% of the data falls within one standard deviation of the mean. Approximately 95% of the data falls within two standard deviations of the mean. Approximately 99.7% of the data falls within three standard deviations of the mean.

Therefore, the answer to the question is 68%.

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The main difference between everyday logic and mathematical logic is that everyday logic is based on general observations and opinions, while mathematical logic is based on precise statements and facts.

Differences:
- Everyday logic is based on common sense and intuition, while mathematical logic is based on strict rules and formulas.
- Everyday logic is often used to make decisions or solve problems in daily life, while mathematical logic is used to solve complex mathematical problems.
- Everyday logic can be subjective and influenced by personal beliefs or experiences, while mathematical logic is objective and follows a set of universally accepted principles.

Similarities:
- Both everyday logic and mathematical logic use reasoning to draw conclusions.
- Both everyday logic and mathematical logic rely on evidence and facts to support their conclusions.
- Both everyday logic and mathematical logic can be used to solve problems and make decisions.

In conclusion, while everyday logic and mathematical logic have some similarities in terms of their use of reasoning and evidence, they differ in their approach and application. Everyday logic is based on common sense and intuition, while mathematical logic is based on strict rules and formulas.

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Answer:

No

Step-by-step explanation:

4 x 2 = 14

BUT

3 x 2 ≠ 9

they are not equal because if is simplify 3/7 you will not get 9/14 you will get 6/14

like this

3|7

6|14

Answer:

1st and 3rd options

Step-by-step explanation:

substitute the coordinates of each point into the left side and compare answer to right side.

(0, 2 )

2(2) - 0 = 4 - 0 = 4 > 1 ← solution

(8, \(\frac{1}{2}\) )

2(\(\frac{1}{2}\) ) - 8 = 1 - 8 = - 7 < 1 ← not a solution

(- 6, 3 )

2(3) - (- 6) = 6 + 6 = 12 > 1 ← solution

(- 7, - 3 )

2(- 3) - (- 7) = - 6 + 7 = 1 ← not a solution

Answer:

24 will be your answer.

Step-by-step explanation:

Answer:

No, is the answer. :)

Step-by-step explanation:

The complete proof of the parallel lines k and l is:

The complete question is added as an attachment

With the given information and the image attached below, we can state that the two lines are parallel

Then go ahead to use the angle theorems and transitive properties to complete the proof

So, the complete proof is:

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Answer:

Top one is A, then false, then C

Step-by-step explanation:

Ez

The numbers arranged in order from least to greatest is: √146, 12.39, 12.62, 12⅝, and 12¾. The third option is correct.

The ordering of numbers refers to arranging numbers in a specific sequence based on their magnitude or value. The ordering of numbers is determined by their relative values. Comparisons are made between numbers to determine their position in the order.

12⅝ = 101/8 = 12.645

12.62 = 12.62

√146 = 12.0830

12.39 = 12.39

12¾ = 51/4 = 12.75

Therefore, the numbers arranged in order from least to greatest is: √146, 12.39, 12.62, 12⅝, and 12¾.

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Answer:

1 solution: x = 1 and y = 4