A 2000 kg car is rolling at 2.0 m per s. You would like to stop the car by firing a 12 kg blob of sticky clay at it. How fast should you fire the clay?

Answers

Answer 1

The correct answer is you should fire the clay at a velocity of approximately 1.99 m/s to stop the 2000 kg car rolling at 2.0 m/s.

To determine how fast you should fire the clay to stop the 2000 kg car rolling at 2.0 m/s, you can use the principle of conservation of momentum.

The total momentum of the car and clay before the collision is equal to the total momentum after the collision.


Initial momentum = final momentum



The initial momentum is the momentum of the car, which is:



Initial momentum = mass x velocity


Initial momentum = 2000 kg x 2.0 m/s


Initial momentum = 4000 kg m/s


The final momentum is the momentum of the car and clay combined, which is:



Final momentum = (2000 kg + 12 kg) x 0 m/s


Final momentum = 0 kg m/s



Since the momentum must be conserved, we can set the initial momentum equal to the final momentum and solve for the velocity of the clay:

Initial momentum = final momentum


4000 kg m/s = (2000 kg + 12 kg) x velocity


4000 kg m/s = 2012 kg x velocity


velocity = 4000 kg m/s ÷ 2012 kg


velocity = 1.99 m/s



Therefore, you should fire the clay at a velocity of approximately 1.99 m/s to stop the 2000 kg car rolling at 2.0 m/s.

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Related Questions

A force F~ = Fxˆı + Fyˆ acts on an object with Fx = 4 N and Fy = 6 N. The angle between F~ and the displacement vector ~s is 18◦ , and 106 J of work is done by F~. Find the magnitude of ~s. Answer in units of m

Answers

The magnitude of the vector displacement is 15.65 m.

Resultant force

The resultant force acting on the object is calculated as follows;

\(F = \sqrt{F_x^2 + F_y^2} \\\\F = \sqrt{4^2 + 6^2} \\\\F = 7.21 \ N\)

Displacement of the vector

The displacement of the vector is calculated as follows;

W = Fs cosθ

\(s = \frac{W}{Fcos(\theta)} \\\\s = \frac{106}{7.12 \times cos(18)} \\\\s = 15.65 \ m\)

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It is a hot summer day at the beach. From your understanding of specific heat capacity, what can you expect to be the difference between the sand and the water?
The water will gain more thermal energy than the sand
The water will heat up faster then the sand
The sand will heat up faster than the water
The sand will lose its energy more slowly than the water​

Answers

Answer:

the sand will heat up faster than the water

Explanation:

water has slow heat conduction

and sand had high heat conduction

In ptolemy’s earth-centered model for the solar system, venus always stays close to the sun in the sky and, because it always stays between earth and the sun, its phases range only between new and crescent. The following statements are all true and were all observed by galileo. Which one provides evidence that venus orbits the sun and not earth?.

Answers

hey, can you state your question a little more clearly

a thin flat ring with inner radius r1 and outer radius r2 has a uniform surface charge density σ. calculate the electric field at the point ""p"" which is centered on the ring

Answers

To calculate the electric field at point "P" centered on a thin flat ring with inner radius r1 and outer radius r2, we need to consider the contribution from each infinitesimal charge element on the ring.

By using the principle of superposition, we can integrate the contributions of all charge elements on the ring to determine the electric field at point "P." The electric field due to a charge element depends on its magnitude and distance from point "P." The magnitude of the electric field at point "P" can be calculated using the formula E = (k * Q * dl) / r^2, where k is the electrostatic constant, Q is the charge element, dl is the length element on the ring, and r is the distance between the charge element and point "P." By integrating all these contributions, we can find the total electric field at point "P" from the entire ring.

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12) Driving home from school one day, you spot a ball rolling out into the street (FIGURE 5-27). You brake for 1.20 s, slowing your 950-kg car from 16.0 m>s to 9.50 m>s. What was the average forceexerted on your car during braking and How far did you travel while braking?

12) Driving home from school one day, you spot a ball rolling out into the street (FIGURE 5-27). You

Answers

We are given the following information

Mass of car = 950 kg

Initial speed of car = 16.0 m/s

Final speed of car = 9.50 m/s

Time = 1.20 s

The average force exerted on the car during braking can be found using Newton's 2nd law of motion

\(F=m\cdot a\)

Where m is the mass of the car and a is the acceleration of the car.

The acceleration of the car is given by

\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ a=\frac{9.50-16.0}{1.20} \\ a=-5.4167\; \; \frac{m}{s^2} \end{gathered}\)

The negative sign indicates deacceleration since the car is stopping.

So, the force is

\(\begin{gathered} F=m\cdot a \\ F=950\cdot5.4167 \\ F=5145.865\; \; N \end{gathered}\)

Therefore, an average force of 5145.865 N was exerted on your car during braking.

The distance traveled by the car while braking can be found as

\(s=v_i\cdot t+\frac{1}{2}\cdot a\cdot t^2\)

Let us substitute the given values

\(\begin{gathered} s=16.0\cdot1.20+\frac{1}{2}\cdot(-5.4167)\cdot(1.20)^2 \\ s=19.20-3.90 \\ s=15.3\; m \end{gathered}\)

Therefore, the car traveled a distance of 15.3 m while braking.

You accidentally drop an eraser out of the window of an apartment 15 m above the ground

Answers

Answer:

hello, yes or nou sorry jaja

How is the heat affecting the appearance of the road and the people?

Answers

Answer:

I dont know what you mena by road and the people

It doesn’t it may burn the road a little but nothing much other than that I can think ok

a meter stick balances horizontally on a knife-edge at the 50.0 cm mark. with two 3.78 g coins stacked over the 33.4 cm mark, the stick is found to balance at the 48.8 cm mark. what is the mass of the meter stick?

Answers

The meter stick weighs 204.11cm. A meter stick is a measurement tool that measures one meter (hundred centimeters) and is used to measure things in meters and centimeters.

What is the mass trying to say?

In physics, mass is a way to measure inertia, a fundamental property of all matter. It essentially refers to a body of matter's resistance to changing its speed or position in response to the application of a force. The change produced by an applied force is smaller the more mass a body has.

Calculation:The computation of the mass of the meter stick is shown below:

Let us assume the following items

x1 = 50 cm;

m2 = m3 =  3.78 g;

x2 = x3 = 33.4 cm;

xcm = 48.8 cm

Now, using the aforementioned presumption, we must use the center mass equation, which is provided below:

Xcm = m₁x₁ + m₂x₂ + m₃x₃ / m₁ + m₂ + m₃

48.8cm = m₁ ₓ50 + 3.78 ₓ 33.4 + 3.78 ₓ 33.4 / m₁ + 3.78 + 3.78

48.8m₁ + 7.56 = 50m₁ + 126.25 + 126.25

48.8m₁ - 50m₁ = 244.94

₋1.2m₁ = 244.94

m₁ = ₋244.94/₍1.2

m₁ = 204.11cm.

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What steps are always part of both the process of technological design and the process of scientific investigation?
Check all that apply.
building a prototype
conducting tests or trials
analyzing results
determining affordability and availability researching related information​

Answers

Here, we are asked to identify steps which are common to both the process of technological design and the process of scientific investigation.

1. Researching related information

2. Determining affordability and availability.

3. Building a prototype.

4. Conducting tests or trials.

5. Analyzing results.

The list above is orderly.

The first iteration involves researching related information about the technological design or scientific investigation as the case may be. This is the first step after the idea-birth process.

The second iteration involves Determining the affordability and availability of the initiative. It is at this point that the process requires conducting a feasibility study.

Also, a prototype is needed because, a large scale effort cannot be wasted without first trying on a small scale and analyzing results obtained from the tests conducted.

Conducting tests or trials is next on the list as the prototype needs to be tested and the results analyzed accordingly.

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Answer:

Here, we are asked to identify steps which are common to both the process of technological design and the process of scientific investigation.

1. Researching related information

2. Determining affordability and availability.

3. Building a prototype.

4. Conducting tests or trials.

5. Analyzing results.

The list above is orderly.

The first iteration involves researching related information about the technological design or scientific investigation as the case may be. This is the first step after the idea-birth process.

The second iteration involves Determining the affordability and availability of the initiative. It is at this point that the process requires conducting a feasibility study.

Also, a prototype is needed because, a large scale effort cannot be wasted without first trying on a small scale and analyzing results obtained from the tests conducted.

Conducting tests or trials is next on the list as the prototype needs to be tested and the results analyzed accordingly.

In a uniform motion
- Acceleration is non zero constant
- Direction of velocity may vary
- Speed is not constant
- Velocity and speed are constant

Answers

Answer:

pls mark as brainliest

Explanation:

Velocity and speed is constant

Why do we weigh less in the equator rather than in poles ?
Give all the reasons for this situation ​

Answers

Answer:

There are a few reasons why we weigh slightly less at the equator compared to the poles. Here are the main factors contributing to this phenomenon:

1. Centrifugal force: The Earth rotates on its axis, causing a centrifugal force at the equator due to the circular motion. This force acts opposite to gravity and reduces the effective gravitational pull at the equator. As a result, we experience slightly less weight at the equator compared to the poles.

2. Earth's shape: The Earth is not a perfect sphere but rather an oblate spheroid, meaning it is slightly flattened at the poles and bulges at the equator. This shape is due to the rotation of the Earth. As a result of this oblate shape, the distance between the center of the Earth and any object is greater at the equator compared to the poles. Since gravitational force decreases with distance, the gravitational pull is slightly weaker at the equator.

3. Altitude variation: The Earth's surface is not perfectly uniform, and there are variations in elevation and altitude across different locations. The force of gravity decreases as we move farther away from the Earth's center. At the poles, we are closer to the center of the Earth compared to the equator, resulting in a slightly stronger gravitational pull at the poles. Hence, our weight is slightly higher at the poles due to the smaller distance from the center of the Earth.

It's important to note that these differences in weight are extremely small and difficult to perceive with regular scales. The variation is typically on the order of a few tenths of a percent, so it has a negligible impact on our daily lives.

Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.

According to your data, was your hypothesis correct? (Be sure to refer to your data when answering this question.)
Summarize the conclusions that you can draw from this experiment. Use the questions above to guide your ideas.
Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Give at least three examples from everyday life where an inclined plane is used to reduce the effort force needed to accomplish a task.


In this experiment, you will determine the IMA, AMA, and efficiency.
The materials for this experiment are:
a smooth board
smooth block or other object to drag up a plane
a spring scale (calibrated in newtons)
string
books or blocks to support the inclined plane
and a meter stick.

Your job is to observe the experiment and collect your own data from this demonstration.
Be ready to record your observations and data.

You will be pulling an object up an inclined plane at different inclines.
Make and record a hypothesis about how changine the slope of inclined plane will affect the efficiency.
Measure the height and length of the plane, record the measurements.
Measure the mass of the object, and record. Convert the mass from grams to newtons by dividing by 102, and record.

Now slowly and steadily pull the object up the incline with the spring scale and string kept parallel to the incline.
Record the readout on the scale.
This will be the effort force.

Now increase the slope of the incline by increasing the height.
Measure the height of the new incline.
The length of the incline remains constant.
Slowly and steadily pull the object up the incline, record the readout from the scale.
You are now ready to complete the rest of this assignment.

Answers

Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right bcs i got it lol, yw btw! hahaha! good luck also, subscribe to my channel!

Explanation:

are you more likely to be able to walk at constant velocity

Answers

When you walk, you are more likely to be able to walk at a constant velocity. Your walking speed varies as you walk in real-life scenarios, but you aim to maintain a steady pace or velocity. This is how you can keep track of time and distance traveled.

When you walk at a constant velocity, you move forward with a steady speed and direction. The velocity is defined as the rate at which an object's position changes with respect to time. When you walk, you typically aim to move forward with a constant velocity, which is the speed at which you walk and the direction you walk. In certain situations, a constant velocity is ideal, such as when you are traveling long distances and want to arrive at your destination at a certain time. To ensure that you walk at a constant velocity, you need to maintain a steady pace by keeping your stride consistent and avoiding unnecessary stops or changes in direction. Walking with a constant velocity involves maintaining a steady speed and direction. It is possible to achieve this by maintaining a constant pace, keeping your stride consistent, and avoiding any unnecessary stops or changes in direction.

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a force of 5.4 n acts on a 28 kg body initially at rest. compute the work done by the force in (a) the first, (b) the second, and (c) the third seconds and (d) the instantaneous power due to the force at the end of the third second.

Answers

A) Work done in the first second =0.524 J

B) Work done in the 2nd second =1.042 Joules

C) Work done in the third second = 0.524 Joules

D) The instantaneous power due to the force at the end of the third second is = 0.524 Watts

To solve this problem, we need to use the equations for work and power:

Work = force x distance x cos(theta)

Power = work / time

Where theta is the angle between the direction of the force and the direction of motion.

Since the body is initially at rest, its initial velocity is zero. We can use the equation of motion:

Final velocity = Initial velocity + acceleration x time

Where acceleration = force / mass

(a) For the first second:

Acceleration = force / mass = 5.4 N / 28 kg = 0.193 m/s^2

Final velocity = 0 + 0.193 m/s^2 x 1 s = 0.193 m/s

Distance traveled in the first second = 1/2 x acceleration x time^2 = 1/2 x 0.193 m/s^2 x (1 s)^2 = 0.097 m

Work done in the first second = force x distance x cos(theta) = 5.4 N x 0.097 m x cos(0) = 0.524 Joules

(b) For the second case:

Since the body is moving with a constant velocity of 0.193 m/s, the distance traveled in the second is:

Distance traveled in the second second = velocity x time = 0.193 m/s x 1 s = 0.193 m

Work done in the second second = force x distance x cos(theta) = 5.4 N x 0.193 m x cos(0) = 1.042 Joules

(c) For the third second:

The final velocity at the end of the second second is the initial velocity for the third second:

Final velocity = 0.193 m/s

Distance traveled in the third second = 1/2 x acceleration x time^2 = 1/2 x 0.193 m/s^2 x (1 s)^2 = 0.097 m

Work done in the third second = force x distance x cos(theta) = 5.4 N x 0.097 m x cos(0) = 0.524 Joules

(d) The instantaneous power due to the force at the end of the third second is:

Power = work / time

= (work done in the third second) / (time taken for the third second)

= 0.524 Joules / 1 s

= 0.524 Watts

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(c) Life testing was made on six non-replaceable) electrical lamps and the following results were obtained. Calculate MTTF. (5 Marks)

Answers

MTTF or Mean Time to Failure can be calculated using the given data. The term MTTF is often used to describe the expected lifetime of electronic devices and other items.

Here is how to calculate MTTF when given data:(c) Life testing was made on six non-replaceable) electrical lamps and the following results were obtained.

Calculate MTTF.The following data has been given:Number of lamps, n = 6Total time, T = 10000 hoursFailures, f = 2MTTF formula is given as:MTTF = T / n * fWhere, T = total time during which the test was conducted.n = the number of items tested.f = the number of items failed.Using the given data, we can calculate the value of MTTF as follows:MTTF = T / n * f = 10000 / 6 * 2= 1666.67 hoursTherefore, the MTTF of the six non-replaceable electrical lamps is 1666.67 hours.

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The pitch of a sound you hear depends on the------------------ of the sound wave.The pitch of a sound you hear depends on the------------------ of the sound wave.

Answers

Answer:

Frequency.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.

Mathematically, the speed of a sound is given by the formula:

Speed = wavelength * frequency

The pitch of a sound you hear depends on the frequency of the sound wave.

Answer:Frequency. 

 Explanation:Sound are mechanical waves that are highly dependent on matter for their propagation and transmission. Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.Mathematically, the speed of a sound is given by the formula:Speed = wavelength * frequency

which principle is used in mass spectrograph to estimate the mass of a charged particle​

Answers

magnetic field
The basic principle on which mass spectrometry operates is that a stream of charged particles is deflected by a magnetic field. The amount of the deflection depends on the mass and the charge on the particles in the stream.

a child is sledding down a hill. the child has 200 j of potential energy and 500 j of kinetic energy at one point on the hill. how much more kinetic energy does the child gain for the remainder of the motion to the bottom of the hill?

Answers

The additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule. The result is obtained by using the principle of Conservation of Mechanical Energy.

What is Conservation of Mechanical Energy?

The principle of conservation of energy states that "The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and transferred from one object to another, but the total amount remains constant."

In the same way, the Conservation of Mechanical Energy states that the total mechanical energy of a system is conserved. It can be expressed as

\(E_{1} = E_{2}\)

\(K_{1} + U_{1} = K_{2} + U_{2}\)

\(\frac{1}{2} mv_{1} ^{2} + mgh_{1} = \frac{1}{2} mv_{2} ^{2} + mgh_{2}\)

Where

E₁ = mechanical energy at point 1E₂ = mechanical energy at point 2K₁ = kinetic energy at point 1K₂ = kinetic energy at point 2U₁ = potential energy at point 1U₂ = potential energy at point 2m = mass of an objectv₁ = velocity of object at point 1v₂ = velocity of object at point 2h₁ = height of object at point 1h₂ = height of object at point 2

At one point, a child has:

U₁ = 200 JK₁ = 500 J

How much more kinetic energy does the child gain at the bottom of the hill?

At the bottom of the hill, the height of the child is zero, h₂ = 0. So, the potential energy is

\(U_{2} = mgh_{2}\)

\(U_{2} = mg(0)\)

\(U_{2} = 0\)

The kinetic energy at the bottom of the hill is

\(K_{1} + U_{1} = K_{2} + U_{2}\)

\(500 + 200 = K_{2} + 0\)

\(K_{2} = 700 J\)

The kinetic energy added for the remainder of the motion is

\(K = K_{2} - K_{1}\)

\(K = 700 - 500\)

\(K = 200 J\)

Hence, the additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule.

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. Which of the following depends greatly on effective stress? (a) Strength (b) Gradation (c) Plastic Limit Liquid Limit 2. Select the correct range of capillary rise in fine sands (a) 7.5 - 23 m (b) 0.75 - 7.5 m - 0.2 m (c) 0.3 - 1.2 m (a) 1.0 the above (d) 3. For most soils, the critical hydraulic gradient that causes quick condition (i.e., piping) is approximately (b) 0.75 (c) 0.5 (d) 0.1 (d) none of 4. If water is seeping through a soil layer in the vertically upward direction, the effective stress at any point within the soil (a) will be lower than its static case without seepage. (b) will be higher than its static case without seepage. (c) may decrease to zero for a specific hydraulic gradient. (d) both (a) and (c).

Answers

The factors that depend greatly on effective stress are (a) Strength, which is influenced by the difference between total stress and pore water pressure, and (c) Plastic Limit and Liquid Limit, which are soil properties affected by the effective stress. The correct range of capillary rise in fine sands is (c) 0.3 - 1.2 m. For most soils, the critical hydraulic gradient that causes quick conditions (piping) is approximately (d) 0.1. If water seeps vertically upward through a soil layer, the effective stress at any point within the soil will be lower than its static case.

Effective stress is a crucial parameter in soil mechanics and influences various factors. One such factor is (a) Strength, which is determined by the difference between total stress (the weight of the soil) and pore water pressure. The effective stress directly affects the soil's shear strength and its ability to bear loads. Additionally, the plasticity characteristics of soil, specifically the Plastic Limit and Liquid Limit, are also greatly influenced by effective stress. These limits represent the water content at which soil transitions from solid to plastic and from plastic to liquid states, respectively.

The correct range of capillary rise in fine sands is (c) 0.3 - 1.2 m. Capillary rise occurs in soils due to the cohesive and adhesive forces between water and soil particles. In fine sands, the capillary rise is relatively limited compared to other soil types.

For most soils, the critical hydraulic gradient that causes quick conditions or piping is approximately (d) 0.1. Piping refers to the erosion or washing away of soil particles due to seepage flow, leading to the formation of pipes or channels. A hydraulic gradient of approximately 0.1 is generally considered critical for initiating piping in most soils.

When water seeps through a soil layer in the vertically upward direction, the effective stress at any point within the soil is lower than its static case without seepage. This is because the seepage increases the pore water pressure, reducing the effective stress. Under certain conditions, the effective stress may decrease to zero for a specific hydraulic gradient. Hence, the correct answer is (d) both (a) and (c).

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A car of weight 300N moved through a distance of 10m when pushed by 3 students
a. Calculate the work done by the three students
b. Explain the energy transfer involved

Answers

The work done by the three students is 3,000 J.

The energy transferred in the process is 3,000 J.

What is work done?Work done is the product of force and distance moved by the object.

W = Fd

The work done by the three students is calculated as follows;

W = 300 x 10

W = 3,000 J

What is energy transfer?This is means by which energy is converted from one form to another.

The energy transferred in the process is determined by work energy theorem.

E = W

E = 3,000 J

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PLEASE HELP WILL MARK BRAINLIEST !! Which documentation is a car insurance company unlikely to ask for when a person is applying for coverage?

A. the type of car and when it was made

B. the number of accidents the driver had in the past

C. proof that the driver has life insurance

D. proof of how many miles the car has driven

Answers

Answer:

C, proof that the driver has life insurance.

Explanation:

what is the wavelength of a beam of light having a frequency of 6 × 1017 hz?

Answers

The wavelength of the light beam having a frequency of 6 × 1017 hz is 0.05 nm.

To calculate the wavelength of a light beam, we can use the formula:

λ = c/f

Where λ is the wavelength, c is the speed of light and f is the frequency of the light.

The speed of light is approximately 3 x 10^8 m/s, we can use this value to find the wavelength.

λ = c/f

λ = (3 x 10^8 m/s) / (6 x 10^17 Hz)

λ = 0.05 nm

So the wavelength of the light beam is 0.05 nm.

It's important to mention that the wavelength is inversely proportional to the frequency, meaning if the frequency is high the wavelength is short and if the frequency is low the wavelength is long.

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A man is inside an airplane and walking toward the back of the plane at 7 m/s. The plane is flying West at 245 m/s. What is the speed and direction of the plane relative to the man?



7 m/s East

238 m/s, East

252 m/s West

238 m/s, West

Answers

Answer:

7 m/s East

Explanation:

The speed of the man relative to the plane is given as 7 m/s. Given that he's walking in the corridor of the plane, this is his speed relative to the plane. Since he's moving to the back of the plane, and the aircraft is headed to west, the man's direction relative to the plane is East.

The amount of water, w, in litres, remaining in a cooking pot after it is placed onto a hot stove is given by the function W(t) = 4000.75). + 20 where is the time in hours after the pot is placed on the stove. Find 0 the initial amount of water in the pot. the percentage of water that leaves the pot in the form of steam each hour. (b) Calculate the amount of water remaining in the pot after 5 hours.

Answers

The percentage of water that leaves the pot in the form of steam each hour is approximately 20003.75%. b) The amount of water remaining in the pot after 5 hours is approximately 20023.75 liters.

To find the initial amount of water in the pot, we can substitute t = 0 into the function W(t) and solve for W(0).

W(0) = 4000.75(0) + 20 = 20 liters

Therefore, the initial amount of water in the pot is 20 liters.

To calculate the percentage of water that leaves the pot in the form of steam each hour, we need to calculate the rate of water loss per hour and express it as a percentage of the initial amount.

The rate of water loss per hour can be found by taking the derivative of the function W(t) with respect to t:

W'(t) = 4000.75

Since the derivative is constant, it represents the rate of water loss per hour. So the percentage of water loss per hour is:

(4000.75/20) × 100% = 20003.75%

(b) To calculate the amount of water remaining in the pot after 5 hours, we can substitute t = 5 into the function W(t).

W(5) = 4000.75(5) + 20 = 20003.75 + 20 = 20023.75 liters

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the microwave radiation left over from the big bang explosion of the universe has an average energy density of 4.19 × 10–14 j/m3. what is the rms value of the electric field of this radiation?

Answers

The rms value of the electric field of the microwave radiation left over from the big bang explosion is approximately 6.68 x 10⁻³ V/m.



To find the rms value of the electric field, we can follow these steps:

1. Understand the relationship between energy density (u) and the electric field (E) for electromagnetic radiation. The energy density can be given by the formula:

u = (1/2) * ε₀ * E², where ε₀ is the vacuum permittivity, which is approximately 8.85 × 10⁻¹² F/m.


2. Rearrange the formula to solve for the electric field E:

E = √(2u/ε₀)


3. Plug in the given energy density (u = 4.19 × 10⁻¹⁴ J/m³) and the vacuum permittivity (ε₀ = 8.85 × 10⁻¹² F/m) into the formula:

E = √(2 * 4.19 ×  10⁻¹⁴ J/m³ / 8.85 × 10⁻¹² F/m) = 9.46 x 10⁻³ V/m


4. Calculate the rms value of the electric field:

E = 9.46 x 10⁻³/ √2 ≈ 6.68 x 10⁻³ V/m

So, the rms value of the electric field is approximately 6.68 x 10⁻³ V/m.

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HELP PLEASE
Find the net force necessary for a 15 kg object to accelerate at 20 m/s/s.

Answers

Answer:

The answer is 300 N

Explanation:

The force acting on an object given the mass and acceleration we use the formula

force = mass × acceleration

We have

force = 15 × 20

We have the final answer as

300 N

Hope this helps you

a golf ball of mass 0.045 kg is hit off the tee at a speed of 37 m/s . the golf club was in contact with the ball for 3.90×10−3 s .find the impulse imparted to the golf ball.

Answers

Impulse  = change in momentum = 0.045 * 36 = 1.62 kg m/sec and Average Force = Impulse / time  = 1.62 / 3.9 x 10^-3    = 415.3 Newton

Impulse forces are those that have a relatively brief duration of action. The term "impulse" refers to the result of the impulsive force and the time at which it acts. I = F dt = dM is the formula for the impulse, which is the change in momentum brought on by the impulsive force.

The momentum of an object will change when a force acts for a predetermined period of time. In other words, an uneven force always accelerates an object, either by making it go faster or slower. When a force opposes an object's motion, the object slows down. When a force is applied in the same direction as an object's motion, the object is accelerated by the force. In either case, a force will alter an object's velocity.

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Space questions

Please help

Space questionsPlease help

Answers

Answer:

(1) The relationship between the altitude height, 'h', and the orbital speed, \(v_{orbit}\), of the satellite is an inverse relationship

\(v_{orbit}\) = 1/(h + R)

(2) The height of the satellite, is approximately 24,442 meters

(3) Please find attached the drawing showing the two lines that indicate the direction of the gravitational force on the satellites created with Microsoft Visio

Explanation:

(1) From the given data table, as the altitude increases, the orbital velocity decreases, therefore, the relationship between altitude, 'h', and orbital velocity, '\(v_{orbit}\)', is an inverse relationship which can be expressed as follows;

\(v_{orbit} = \sqrt{\dfrac{G \cdot M}{r} }\)

Where;

G = The universal gravitational constant

M = The mass of the Earth, or planet about which the satellite orbits

r = The distance between the center of the planet and the satellite = h + R

R = The radius of the planet

When \(v_{orbit}\) = 27,500, h = r - R = 1000

We have;

\(v_{orbit}\)² ∝ 1/r

\(v_{orbit}\)² = k/r = k/(R+ h)

When, \(v_{orbit}\)² = 27,500² = 756,250,000

r = h + R = 1000 + R

∴ 756,250,000 = k/(1000 + R)

(1,000 + R) × 756,250,000  = k

When, \(v_{orbit}\)² = 18,000² = 324,000,000

r = h + R = 10,000 + R

∴ 324,000,000 = k/(10,000 + R)

324,000,000 = ((1,000 + R) × 756,250,000)/(10,000 + R)

∴ 324,000,000×(10,000 + R) = (1,000 + R) × 756,250,000

R × (756,250,000 - 324,000,000) = 324,000,000×10,000 - 1,000 × 756,250,000

R = (324,000,000×10,000 - 1,000 × 756,250,000)/(756,250,000 - 324,000,000) = 5746.09600925

R = 5,746.09600925

k = (1,000 + R) × 756,250,000  = (1,000 + 5,746.09600925) × 756,250,000 = 5.1017351 × 10¹²

k = 5.1017351 × 10¹²

(2) When, \(v_{orbit}\) = 13,000 m/s, we have;

13,000² = 5.1017351 × 10¹²/(5,746.09600925 + h)

∴ 5,746.09600925 + h = 5.1017351 × 10^(12)/(13,000²) = 30187.7816568

h = 30187.7816568 - 5,746.09600925 = 24,441.6856476

The height of the satellite, h ≈ 24,442 meters

(3) Please find attached the drawing showing the two lines indicating the direction of the force of gravity exerts on the satellites created with Microsoft Visio.

Space questionsPlease help
Space questionsPlease help

What behavior of light is evidence for a wave model of light.

Answers

Explanation:

the intersection behavior

Under which of the following circumstances would a person be shocked?

Answers

The person would suffer a shock in becomes part of an electrical circuit.

When a person becomes part of an electrical circuit, they can suffer a shock if the voltage of the circuit is high enough to cause injury. This occurs when the electrical current passes through the person's body, causing disruption of their normal body functions.

The severity of the shock depends on the amount of current passing through their body and its duration. In some cases, the person may experience temporary or long-term memory loss due to the shock.

When a person becomes part of an electrical circuit, it is important to take proper safety precautions to prevent injury.

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