a 20.16 ml sample of 0.68 m hcl is titrated with 0.68 m naoh.

According to ideal gas equation, volume must change by 0.5 factor to keep the pressure and temperature the same.

The ideal gas equation is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

Since there are two conditions before addition and after addition  which is 0.1×RT/V=0.2×RT/V thus volume changes by factor of 0.5 which is pressure.

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Answer:

Explanation:An age-structure diagram provides a snapshot of the current population and can represent information about the past and give potential clues about future problems. When you are interpreting age-structure diagrams, it is important to compare the width of the base to the rest of the population

This molecule has the condensed formula CH3CH2CH2COCH3, and the oxygen atom forms a double bond with the carbon atom. To determine its systematic (IUPAC) name, follow these steps:

1. Identify the main carbon chain: In this case, it's a 5-carbon chain (including the carbon atom double-bonded to oxygen). The prefix for a 5-carbon chain is "pent-".
2. Identify the functional group: The molecule contains a carbonyl group (C=O) bonded to one of the carbon atoms within the chain. This functional group is called a ketone.
3. Combine the prefix and functional group: Since it's a ketone with a 5-carbon chain, the base name is "pentanone".
4. Determine the position of the functional group: The carbonyl group is bonded to the third carbon atom in the chain, so it is numbered as 3. 5. Combine the base name, position, and functional group: The full IUPAC name is "3-pentanone". In summary, the systematic (IUPAC) name for the molecule with the condensed formula CH3CH2CH2COCH3 is 3-pentanone.

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Answer:

Different

Explanation:

Chlorobenzene can be converted into benzoic acid using Grignard reagent. Thus, treating with Mg metal in dry ether followed by carboxylation and then hydrolyising the product gives benzoic acid.

Grignard reagents are alkyl magnesium halides with the general formula RMgX. They can be prepared by treating alkyl halides with Mg metal in presence of dry ether.

Chlorobenzene when treated with Mg gives MgCl substituted benzene ring which upon carboxylation using carbon dioxide followed by hydrolysis gives benzoic acid.

Therefore, the reagents needed for the conversion of chlorobenzene to benzoic acid are Mg, CO₂ and water.

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Answer:

elements from group four to eight

Answer:

The Ordovician-Silurian extinction as well as many new species

Explanation:

Answer:

sliding friction

Explanation:

Answer:

D. solid friction

Explanation:

Its not a fluid, Its not sliding, and its not rolling, so therefor is solid friction

Answer:is a trace metal of severe toxicity. Its health concerns via consumption of contaminated vegetables have often been overlooked or underestimated

Explanation: Read it carefully and it explains

Answer:

theres gonna be more energy and some of the particles with a lot of energy will become vapor and evaporate

Explanation:

"If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. The most energetic particles at the surface escape from the surface of the liquid as a vapor as it gets warmer. Liquids evaporate faster as they heat up and more particles have enough energy to break away."

Answer:Wave frequency is related to wave energy. Since all that waves really are is traveling energy, the more energy in a wave, the higher its frequency. The lower the frequency is, the less energy in the wave. ... When it comes to light waves, violet is the highest energy color and red is the lowest energy color.

Explanation:

Answer:

A bee sting has a ph of 5, and is therefore an acid. Litmus paper goes red (or stays red) in acidic solutions.

Answer:

The Blue Litmus Paper should turn red

Explanation:

Bee venom has a pH of 5.5, which means it is mildly acidic which in turn should make the Litmus paper turn Red. Hope this helps!

Answer:

1.92

Explanation:

Answer:

Surface tension is an important factor in the phenomenon of capillarity . Surface tension has the dimension of force per unit length, or of energy per unit area.

Explanation:

A solution with a pH of 6.52 has a hydronium ion concentration of 3.02x10-7 mol/L and a hydroxide ion concentration of 3.31x10-8 mol/L.

The hydronium ion concentration of a solution can be calculated from pH by using \(10^{-pH}\). For a pH of 6.52, hydronium ion concentration is 3.02x10-7 mol/L.

The concentration of hydroxide ions can be determined by identifying the value of pOH. The sum of pOH and pH is equal to 14, which is based on the negative logarithm of the ion-product constant of water. At a pH of 6.52, pOH is equal to 7.48.

The relationship between pOH and hydroxide ion concentration is the same as the relationship between pH and hydronium ion concentration. With this, the hydroxide ion concentration at pOH of 7.48 is \(10^{-7.48}\) or 3.31x10-8 mol/L.

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The two unique common elementary steps in the above mechanism are nucleophilic elimination and nucleophilic addition.

As we can see in the first step of the reaction (reaction attached) iodine (I) is attached to the compound. As we know that iodine is a good leaving group so it leaves easily with electrons. As it takes the bond electrons and becomes I⁻ so it is a nucleophilic elimination reaction.

In the second step of the reaction, the lone pair of electrons of nitrogen are attacking the carbocation, so we can call it a nucleophilic addition reaction. So the first step is nucleophilic elimination and the second step is nucleophilic addition.

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the temperature change produced when 800 calories are absorbed by 100 g of water is 8°C.

When 800 calories of heat are absorbed by 100 g of water, the temperature change that occurs can be calculated using the specific heat capacity of water.

The specific heat capacity of water is the amount of heat energy required to raise the temperature of 1 gram of water by 1 degree Celsius. It is 1 calorie/gram°C.

Therefore, to calculate the temperature change in Celsius produced when 800 calories of heat are absorbed by 100 g of water, we can use the following formula:Q = m × c × ΔTwhere Q = heat energy absorbed, m = mass of water, c = specific heat capacity of water, and ΔT = change in temperature.

Substituting the values, we get:800 = 100 × 1 × ΔTΔT = 800/100ΔT = 8°CTherefore, the temperature change produced when 800 calories are absorbed by 100 g of water is 8°C.

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When 15.5 g of iron (Fe) is reacted with an excess of chlorine gas, it will produce approximately 44.97 g of iron(III) chloride (FeCl₃) based on the balanced equation.

To balance the equation, we need to ensure that the number of atoms of each element is equal on both sides. In the unbalanced equation:

Fe(s) + Cl₂ (g) → FeCl₃ (s)

We have one iron atom on the left side and one iron atom on the right side. So, the iron is already balanced. However, we have two chlorine atoms on the left side and three chlorine atoms on the right side. To balance the chlorine, we need to place a coefficient of 3 in front of the Cl₂ on the left side:

Fe(s) + 3Cl₂ (g) → FeCl₃ (s)

Now that the equation is balanced, we can calculate the number of grams of iron(III) chloride (FeCl₃) formed when 15.5 g of iron (Fe) reacts. From the balanced equation, we can see that the molar ratio between iron and iron(III) chloride is 1:1. Therefore, the molar mass of iron(III) chloride is relevant for this calculation.

The molar mass of Fe is approximately 55.845 g/mol, and the molar mass of FeCl₃ is approximately 162.204 g/mol (55.845 g/mol for Fe + 3 * 35.453 g/mol for Cl). We can use these molar masses to convert the mass of iron to moles and then calculate the mass of iron(III) chloride produced.

Number of moles of Fe = 15.5 g / 55.845 g/mol = 0.2776 mol

Since the molar ratio between Fe and FeCl₃ is 1:1, the number of moles of FeCl₃ produced is also 0.2776 mol.

Mass of FeCl₃ = 0.2776 mol * 162.204 g/mol = 44.97 g

Therefore, 15.5 g of iron will result in approximately 44.97 g of iron(III) chloride when reacted with an excess of chlorine gas.

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The required volume flow rate of liquid ethyl alcohol to supply at a rate of 2000 kJ/s is approximately 164.9 L/min.

To determine the required volume flow rate of liquid ethyl alcohol, we need to calculate the fuel flow rate first. Then, we can convert it to volume flow rate.

Given:

Rate of energy release (Q) = 2000 kJ/s

Excess air = 40% (or 0.4)

First, let's calculate the fuel flow rate (m f):

Q = m f × Lower Heating Value (LHV)

The Lower Heating Value (LHV) for ethyl alcohol can be calculated using the enthalpy of vaporization:

LHV = enthalpy of vaporization / molecular weight of fuel

LHV = 42,340 kJ/k mol / 46.07 kg/k mol = 920.11 kJ/kg

Now, we can calculate the fuel flow rate:

m f = Q / LHV

m f = 2000 kJ/s / 920.11 kJ/kg ≈ 2.173 kg/s

Next, let's convert the fuel flow rate to volume flow rate:

Volume flow rate (V f) = m f / density

V f = 2.173 kg/s / 790 kg/m³ = 0.002749 m³/s

Finally, we can convert the volume flow rate to L/min:

V f = 0.002749 m³/s × (1000 L/1 m³) × (60 s/1 min) ≈ 164.9 L/min

Therefore, the required volume flow rate of liquid ethyl alcohol to supply at a rate of 2000 kJ/s is approximately 164.9 L/min.

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Answer:

V = 25.7 L.  

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the volume of hydrogen, by firstly calculating the moles of this gas produced by 37.6 g of magnesium, according to the 1:1 mole ratio between them:

\(n_{H_2}=37.6gMg*\frac{1molMg}{24.305gMg}*\frac{1molH_2}{1molMg}=1.55molH_2\)

Now, we use the ideal gas equation:

\(PV=nRT\)

To solve for the volume, and obtain:

\(V=\frac{nRT}{P}\\\\V=\frac{1.55mol*0.08206\frac{atm*L}{mol*K}*293.15K}{1.45atm}\\\\V=25.7L\)

Regards!

The average atomic mass of the Mc in the sample, given the that the hypothetical mass spectrum of Mc, is 289.1 amu

First, we shall determine the atomic mass of each isotope as shown from the spectrum. Details below:

For 1st isotope

Atomic mass of 1st isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 1st isotope = (3 / 10) × 288.2

Atomic mass of 1st isotope = 86.46 amu

For 2nd isotope

Atomic mass of 2nd isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 2nd isotope = (5 / 10) × 289.2

Atomic mass of 2nd isotope = 144.6 amu

For 3rd isotope

Atomic mass of 3rd isotope = (Number of atom /total atom) × atomic mass

Atomic mass of 3rd isotope = (2 / 10) × 290.2

Atomic mass of 3rd isotope = 58.04 amu

Finally, we shall determine the average atomic mass of Mc. Details below:

Average atomic mass of Mc = sum atomic masses of isotopes

Average atomic mass of Mc = 86.46 + 144.6 + 58.04

Average atomic mass of Mc = 289.1 amu

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Proton a couples to proton b. proton a possesses a j-value of 3.0 Hz. the j-value proton b possesses to be 3.0hz.

A proton contains two up quarks and one down quark. A neutron contains one up quark and two down quarks. The core is held together by one of four fundamental forces, the "strong nuclear force" (gravitational and electromagnetic forces are the other two). Heavy atoms tend to have more neutrons than protons, but the number of electrons in the atom is always equal to the number of protons. Therefore, the atom as a whole is electrically neutral.

There are two types of protons and neutrons: up quarks and down quarks. Each up quark has a +2/3 charge. Each down quark has a charge of -1/3. The sum of the charges of the quarks that make up the nuclear particle determines its charge.

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(a) The pH of a 0.095 M propionic acid solution is 4.89. (b) The pH of a 0.100 M hydrogen Chromate ion solution is 2.20. (c) The pH of a 0.120 M pyridine solution is 9.29.

(a) Propionic acid (C₂H₅COOH) is a weak acid, with a Kₐ value of 1.3 × 10⁻⁵. To calculate the pH of a 0.095 M solution of propionic acid, we first use the Kₐ expression to calculate the concentration of H₃O⁺:

Kₐ = [H₃O⁺][C₂H₅COO⁻]/[C₂H₅COOH]

1.3 × 10⁻⁵ = x²/0.095

x = 2.78 × 10⁻³ M

Taking the negative logarithm of the H₃O⁺ concentration gives us the pH:

pH = -log[H₃O⁺] = -log(2.78 × 10⁻³) = 4.89

(b) Hydrogen Chromate ion (HCrO₄⁻) is a weak acid with a Kₐ value of 4.6 × 10⁻¹³. However, in this case we are dealing with the conjugate base of this acid, which is a strong base. Therefore, we can use the Kᵇ expression for the dissociation of the conjugate base:

Kᵇ = [OH⁻][HCrO₄⁻]/[CrO₄²⁻]

1.8 × 10⁻⁴ = [OH⁻][0.100]/[HCrO₄⁻]

[OH⁻] = 1.8 × 10⁻³ M

Taking the negative logarithm of the hydroxide concentration gives us the pOH:

pOH = -log[OH⁻] = -log(1.8 × 10⁻³) = 2.74

To calculate the pH, we use the fact that pH + pOH = 14:

pH = 14 - pOH = 14 - 2.74 = 11.26

(c) Pyridine (C₅H₅N) is a weak base, with a Kᵇ value of 1.7 × 10⁻⁹. To calculate the pH of a 0.120 M solution of pyridine, we first use the Kᵇ expression to calculate the concentration of hydroxide ions:

Kᵇ = [OH⁻][HC₅H₅N]/[C₅H₅N]

1.7 × 10⁻⁹ = [OH⁻][0.120]/[C₅H₅N]

[OH⁻] = 1.1 × 10⁻⁵ M

Taking the negative logarithm of the hydroxide concentration gives us the pOH:

pOH = -log[OH⁻] = -log(1.1 × 10⁻⁵) = 4.96

To calculate the pH, we use the fact that pH + pOH = 14:

pH = 14 - pOH = 14 - 4.96 = 9.29

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The two ways in which the physical state of matter can be changed are melting and freezing.

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Answer:

See below

Explanation:

The glycosidic bond forms between the carbon atom on the glucose molecule and the nitrogen atom present on the nitrogenous base. A diagram has been attached to show this particular bond. There is also a phosphate molecule bonded on the sugar molecule at the other end.

Molecular lines are more complex than elemental spectral lines because molecules have two or more atoms and can vibrate and rotate as well. This gives rise to many different energy levels that electrons can occupy, resulting in a more complex spectrum. Option A and B are the correct answers. Options C, D, and E are not correct as they are not relevant to the question.

The behavior of molecules, which are made up of two or more atoms, is more complex than that of single atoms. This behavior results in a wide range of energy levels, which results in a more complex spectrum of spectral lines. Individual atoms are not as complex as molecules and do not have the same range of energy levels as molecules. Therefore, they produce simpler spectra than molecules.

Hence, option A and B are the correct answers. Options C, D, and E are not correct as they are not relevant to the question.

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Explanation:

Electronic Configuration of First 30 Elements with Atomic Numbers

Atomic Number Name of the Element Electronic Configuration

18 Argon (Ar) [Ne] 3s2 3p6

19 Potassium (K) [Ar] 4s1

20 Calcium (Ca) [Ar] 4s2

21 Scandium (Sc) [Ar] 3d1 4s2

26 more rows

Explanation:

NUMBER ELEMENT ELECTRON CONFIGURATION

1 Hydrogen 1s1

2 Helium 1s2

3 Lithium [He]2s1

4 Beryllium [He]2s2

5 Boron [He]2s22p1

6 Carbon [He]2s22p2

7 Nitrogen [He]2s22p3

8 Oxygen [He]2s22p4

9 Fluorine [He]2s22p5

10 Neon [He]2s22p6

11 Sodium [Ne]3s1

12 Magnesium [Ne]3s2

13 Aluminum [Ne]3s23p1

14 Silicon [Ne]3s23p2

15 Phosphorus [Ne]3s23p3

16 Sulfur [Ne]3s23p4

17 Chlorine [Ne]3s23p5

18 Argon [Ne]3s23p6

19 Potassium [Ar]4s1

20 Calcium [Ar]4s2