Answer:
D. 0.5 m/s
Explanation:
From C to D:
displacement, d is (8 - 7) = 1 m
time, t is (7 - 5) = 2 s
\(velocity = \frac{displacement}{time} \\ \\ velocity = \frac{1}{2} \\ \\ velocity = 0.5 \: m {s}^{ - 1} \)
Mrs. Summerlin jogs around a 250 m track twice. What is her distance?
What is the displacement?
Your answer
Answer:
distance 0,5km
this is the answer
Is this answer correct?
Which expenses do you think will change based on how much you drive
Increased driving can lead to higher vehicle maintenance and repair expenses, increased fuel costs, potential increases in auto insurance premiums, and additional parking fees, all of which should be considered when estimating the overall impact on your expenses.
The expenses that are likely to change based on how much you drive can be broadly categorized into two main areas: vehicle-related expenses and fuel-related expenses.
1. Vehicle-related expenses: The more you drive, the more wear and tear your vehicle will experience, leading to increased maintenance and repair costs. Regular oil changes, tire replacements, brake pad replacements, and other routine maintenance tasks will be required more frequently.
2. Fuel-related expenses: It's intuitive that the more you drive, the more fuel you'll consume, resulting in higher fuel expenses. Fuel prices can vary, but regardless of fluctuations, increased mileage will directly impact your fuel budget. Fuel-efficient vehicles may mitigate some of these costs, but the overall impact on your expenses will still be noticeable.
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the fastest tennis service by a man is 246,2 km.hr-1 by Andy Roddick of the United States of America during a match in London in 2004. Calculate the ball's momentum if it has a mass of 58 g?
Answer:
Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).
Explanation:
Convert velocity to the standard units (meters per second):
\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).
Convert mass to standard units (kilograms):
\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).
When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:
\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).
Electrical equipment in an office takes a current of 13 A from a 240 V supply.
Estimate the cost per week of electricity if the equipment is used for 30 hours each
week and 1 kWh of energy costs Rm0.50
Answer:
The cost per week of electricity is Rm 46.8
Explanation:
Electrical Power and Energy
The electrical power consumed by an appliance connected to a voltage V and carrying a current I is given by:
P = V.I
The energy consumed by an electrical appliance of power P during a time t is:
E = P.t
The electrical equipment in an office takes I=13 A when connected to a V=240 V supply.
The power consumed is:
P = 240 V * 13 A
P = 3,120 Watt
Converting to Kilowatt:
P = 3,120/1,000 KW
P = 3,12 KW
If the equipment is used t=30 hours each week, the energy is:
E = 3.12 KW * 30 h
E = 93.6 KWh
Since the cost of each KWh is Rm 0.50, the weekly cost of electricity is:
C = 93.6 * 0.50 = 46.8
The cost per week of electricity is Rm 46.8
Three-point charges are arranged at the corner of a square of side l as shown in Fig. 17-39. what is the potential at the fourth corner (point A)?
The electric potential at the fourth corner (point A) is E4 = kQ.[ 2/a2 + 1/a√2 ]
What is electric potential?The electric potential is defined as the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field.
Number of point charges = 3
Using the superposition principle to calculate the net electric field at the fourth point, so
E4 = E1 + E2 + E3
E4 = kQ/a2 + kQ/√(2a2) + kQ/a2
E4 = kQ.[ 1/a2 + 1/√(2a2) + 1/a2 ]
E4 = kQ.[ 2/a2 + 1/a√2 ]
Therefore the electric field at the fourth corner is E4 = kQ.[ 2/a2 + 1/a√2 ].
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Complete question:
Three-point charges are arranged at the corner of a square of side l as shown in Fig. 17-39. what is the potential at the fourth corner (point A)?
base your answer to the following question on the cross section below, which shows the type of seismic waves recorded at various locations after an earthquake has occurred. point a is a location on earth's surface and x is the epicenter of the earthquake. syvum
The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer.
Seismic waves, which are vibrations caused by the movement of the Earth's crust, are recorded at various locations after an earthquake has occurred. The type of seismic waves recorded at a particular location depends on its distance from the epicenter (point X) of the earthquake.
There are two main types of seismic waves: body waves and surface waves. Body waves, such as P-waves and S-waves, travel through the Earth's interior and can be recorded at any location. Surface waves, such as Love waves and Rayleigh waves, travel along the Earth's surface and are typically recorded closer to the epicenter.
The P-waves are the primary waves that are the fastest and the first to arrive at the seismometer. The S-waves are the secondary waves that are slower and arrive later than P-waves.
In general, the closer a location is to the epicenter, the stronger and more frequent the seismic waves will be.
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A SOLID OF MASS 1.3KG Suspended by a spring Is Completely Immersed in H₂0. If the tension in the spring is 6N. Calculate: a. upthrust on the solid b. the volume of the solid c. Density (take g=10m/s², density of H₂0= 1000kg/m³)
a. Upthrust on the solid:
\(Upthrust = volume of solid * density of fluid * g = 1000 kg/m^3 * volume of solid * 10 m/s^2\)
b. Volume of the solid:
\(volume = mass/density = 1.3 kg / (1000 kg/m^3) = 1.3 x 10^-3 m^3\)
c. Density of the solid:
So,\(density = mass/volume = 1.3 kg / (1.3 x 10^-3 m^3) = 1000 kg/m^3\)
What is upthrust?Upthrust is the upward force exerted on an object immersed in a fluid. It is equal to the weight of the fluid displaced by the object and acts in the opposite direction to gravity. Upthrust helps to counteract the weight of the object and keep it afloat.
a. The upthrust on an object immersed in a fluid is equal to the weight of fluid displaced by the object. The weight of fluid displaced can be calculated using the formula:
Weight of fluid = volume of fluid * density of fluid * g
Since the solid is completely immersed in water, the volume of the fluid displaced is equal to the volume of the solid. The density of water is given as 1000 kg/m^3, and the acceleration due to gravity is given as\(10 m/s^2.\)
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Which heart rate zones are generally anaerobic in nature?
Answer:
Below
Explanation:
Not sure what numbers you have been taught to use, but heart rates (BPM) above 80% of your maximum heart rate is anaerobic
your approximate Max heart rate = ( 220 - age in years)
so if you are 20 y/o max = 220 - 20 = 200 bpm
80% of this is 160 beats per min <===above this is anaerobic
Which kind of wave interaction is shown?
Answer:
where?
Explanation:
ill edit my answer when see it
A copper atom has an atomic number of 29 and an atomic mass of 64. What is the structure of this atom?
A. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
B. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
C. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.
D. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
Answer:
Explanation:
Atomic mass is nuetrons + protons.
Basically it's
? nuetrons + protons = 64
I did process of elimination:
b) It cannot be "b" because 29 + 64 doesn't equal 64.
c) It cannot be "c" because in a regular molecule the amount of protons equals to amount of electron(s).
d) 29 + 29 doesn't = 64.
Therefore, the answer is "A"
Answer: A
Explanation: Just took the test on a.pex
A radar installation operates at 9000 MHz with an antenna (dish) that is 15 meters across. Determine the maximum distance (in kilometers) for which this system can distinguish two aircraft 100 meters apart.
Answer:
R = 36.885 km
Explanation:
In order to distinguish the two planes we must use the Rayleigh criterion that establishes two distinguishable objects if in their diffraction the central maximum of one coincides with the first minimum of the other
The diffraction equation for slits is
a sin θ = m λ
the first minimum occurs for m = 1
sin θ = λ a
as the diffraction experiments the angles are very small, we approximate
sin θ = θ
θ = λ / a
This expression is for a slit, in the case of circular objects, when solving the system in polar coordinates, a numerical constant appears, leaving the expression of the form
θ = 1.22 λ / a
In this problem they give us the frequency, let's find the wavelength with the relation
c = λ f
λ = c / f
θ = 1.22 c/ f a
since they ask us for the distance between the planes, we can use the definition of radians
θ = s / R
if we assume that the distance is large, we can approximate the arc to the horizontal distance
s = x
we substitute
x / R = 1.22 c / fa
R = x f a / 1.22c
Let's reduce the magnitudes to the SI system
f = 9000 MHz = 9 109 Hz
a = 15 m
x = 100 m
let's calculate
R = 100 10⁹ 15 / (1.22 3 108)
R = 3.6885 10⁴ m
let's reduce to km
R = 3.6885 10¹ km
R = 36.885 km
Two small charged spheres are 7.59 cmcm apart. They are moved, and the force on each of them is found to have been tripled. How far apart are they now?
Answer:
The two small charged spheres are now 4.382 cm apart
Explanation:
Given;
distance between the two small charged sphere, r = 7.59 cm
The force on each of the charged sphere can be calculated by applying Coulomb's law;
\(F = \frac{kq_1q_2}{r^2}\)
where;
F is the force on each sphere
q₁ and q₂ are the charges of the spheres
r is the distance between the spheres
\(F = \frac{kq_1q_2}{r^2} \\\\kq_1q_2 = Fr^2 \ \ (keep \ kq_1q_2 \ constant)\\\\F_1r_1^2 = F_2r_2^2\\\\r_2^2 = \frac{F_1r_1^2}{F_2} \\\\r_2 = \sqrt{\frac{F_1r_1^2}{F_2}} \\\\r_2 = r_1\sqrt{\frac{F_1}{F_2}}\\\\(r_1 = 7.59 \ cm, \ F_2 = 3F_1)\\\\r_2 = 7.59cm\sqrt{\frac{F_1}{3F_1}}\\\\r_2 = 7.59cm\sqrt{\frac{1}{3}}\\\\r_2 = 7.59cm *0.5773\\\\r_2 = 4.382 \ cm\)
Therefore, the two small charged spheres are now 4.382 cm apart.
Explore Suppose you are in a partially darkened room holding a flat piece of white cardboard in one hand and a converging lens of focal distance Convex lens 6.3 x 10 m in your other hand. You want to form an image of the window in front of you, which is at a distance of 1.74 m in front of the lens. (A) Find how far behind the lens the cardboard should be held to form as sharp an image as possible. (B) If the height of the window is 1.00 m, find the height of its image Object height 0.05 m Image height -0.05 m
Object distance 0.40 m Image distance 0.40 m Conceptualize The rays of light from any given point on the window refract as they pass through the lens to meet at a point behind the lens A ray that is parallel to the optical axis on either side of the convex lens passes through the focal point on the opposite side, and a ray through the center of the lens is undeflected. If the cardboard is held at the location where the rays traced in this way meet, an image focused as well as possible would be seen on the cardboard Categorize We apply the thin lens formula to calculate the image distance from the object distance and focal length. (A) Find how far behind the lens the cardboard should be held to form as sharp an image as possible Analyze The image distance q can be calculated from the thin lens formula: which can be rearranged as: (B) If the height of the window is h = 1.00 m, find the height of its image. Analyze The ratio of the image height h' to the object height h is the magnification M given by: h' 9 Then: C 9 1.74 m (1.00 m) =- h' Finalize The minus sign in the height corresponds to an inverted image. Finalize Notice also what happens if the sign of the focal length is changed, corresponding to a diverging lens (in the simplest case a concave lens) as illustrated in the Active Figure for concave lens. The rays from a given point on the object meet to form an image only when the rays are imagined to extend back towards the object, where they converge (as seen in the Active Figure). This is where the rays would appear to come from if you were holding the diverging lens in front of you while looking at the window. Would the image of the window be smaller or larger than the window in this case? What sign would q have?
For a converging lens, the focal point is the point at which converging light rays cross; for a diverging lens, the focal point is the point from which diverging light rays appear to originate.
Where do diverging rays come from?The focal length f is the measurement from the lens's centre to its focal point. Diverging light will come from a point on a far-off object. Diverging light rays will emanate from a point at a very far object. Parallel light beams spread out when they pass through a diverging lens. These light rays appear to the spectator to originate from the focal point on the opposite side of the lens. Together, these beams create a virtual image. A ray that is parallel to the axis and approaching a convex diverging mirror appears to be coming from the focal point F behind the mirror due to reflection. Convex mirrors are also known as diverging mirrors because they diverge the light rays that strike their surfaces.To learn more about diverging rays refer to:
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Somebody tell me what the answer is please
Answer:
The acceleration of the ball is 200 m/s^2
Answer:
A
Explanation:
200 m/s squared
Lenders are prohibited from
using borrowers' information in a responsible manner.
explaining to borrowers why their application was rejected.
considering borrowers' sources of income other than salary.
considering borrowers 'race, sex and national origin.
Answer:
Considering borrowers race sex and national origin
Explanation:
Edge
Lenders are prohibited from considering borrowers' race, sex and national origin.
What is borrowing?Receiving something that will eventually be returned is the act of borrowing. In finance and economics, obtaining money is typically referred to as borrowing.
Simply put, borrowing is the act of obtaining money with the understanding that it will be required of the recipient to repay the same amount after a predetermined period of time. Most often, people or even various financial institutions may lend money.
The most dependable place to get financial aid is from banks. Apart from banks, consumers also frequently borrow money from consumer financing companies and other businesses.
Lenders are allowed to use borrowers' information in a responsible manner; explain to borrowers why their application was rejected, consider borrowers' sources of income other than salary. But lenders are prohibited from considering borrowers 'race, sex and national origin.
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Fred the fisherman has been told that, because
of refraction, a fish in water will
appear
nearer the water's surface than it really is.
to be
He draws a diagram to try to work this out.
I think it will look lower, not higher.' he says.
Explain what Fred has done wrong.
Due to light refraction, any fish in the water can see a fisherman on the bank a little more clearly than one might anticipate. When the light hits the water's surface, it “bends” down by around 13 degrees, leaving the image. Thus option A is correct.
What refraction affect the fisherman?When it reaches the surface, light emanating from the fish refracts (changes direction). When viewed from above the water, a fish appears to be closer to the surface than it actually is.
Therefore, Fred the fisherman has been told that, because of refraction, a fish in water will appear.
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What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 550 nm
Answer:
The expression for destructive interference in thin films allows to find the result for the smallest thickness of the films is:
t = 2.03 10⁻⁸ mm
Explanation:
Given parameters
Incident wavelength lamo = 535 nm
Refractive index of the film n = 1.32
To find
The minimum thickness for destructive interference
The interference phenomenon occurs when the path of two rays scattered by an obstacle have different optical paths. In the case of thin films we must take into account:
The reflected wave has a phase change of 180º when it goes from a medium with a lower refractive index to a medium with a higher index.
Inside the film medium the wavelength is modulated by the refractive index.
In the attachment we see an outline of these events and the expression for destructive interference remains.
2 n t = m λ₀
Where n is the refractive index, t the thickness of the film, λ₀ the wavelength in the vacuum and m an integer indicating the order of interference.
t =
The first destructive interference occurs for m = 1, let's calculate.
t =
t = 202.65 nm
Let's reduce this amount to millimeters.
t = 202.65 nm
t = 2,027 10⁻⁸ mm
In conclusion, using the expression for destructive interference in thin films we can find the result for the smallest thickness of the films is:
t = 2.03 10⁻⁸ mm
1. In wavelength y = cos 2πX/ 60 sin(100pi t) where x & y are in cm and t is in seconds then distance between node & antinode is
The distance between the node and antinode is 15 cm.
The equation for the displacement of the wave is given as,
y = cos(2πx/60) sin(100πt)
Comparing the given equation with the standard wave equation,
y = A cos(2πx/λ) sin (ωt)
So,
The amplitude of the wave,
A = 1
2πx/λ = 2πx/60
Therefore, wavelength of the wave,
λ = 60 cm
Therefore, the distance between the node and antinode = λ/4
d = 60/4
d = 15 cm
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similarities and differences between a lunar eclipse and the disappearing sun. HELP FAST
Answer: A solar eclipse results when the moon passes in between the earth and the sun hiding the sun fully or partly for some time. A lunar eclipse occurs when the earth passes in between the moon and the sun casting its shadow on the moon and thus hiding it fully or partly for some time.
What is the independent variable if a scientist is turning bulb on and off to check behaviour of the earthworm?
The independent variable in this experiment is the act of turning the bulb on and off, while the dependent variable is the behavior of the earthworm in response to changes in light. The scientist can analyze the data collected to determine the impact of light on the earthworm's behavior.
In the experiment where a scientist is turning a bulb on and off to check the behavior of an earthworm, the independent variable is the manipulation performed by the scientist, which is the act of turning the bulb on and off.
The independent variable is the variable that the scientist deliberately changes or controls in order to observe its effect on the dependent variable. In this case, the scientist is interested in investigating how the earthworm responds to changes in light. By turning the bulb on and off, the scientist is manipulating the presence or absence of light in the environment of the earthworm.
The behavior of the earthworm, which is the dependent variable, will be observed and measured in response to the changes in light. The scientist may record various behaviors such as movement, burrowing, or changes in activity level exhibited by the earthworm when the light is turned on and off.
By systematically controlling the independent variable (turning the bulb on and off) and observing the dependent variable (behavior of the earthworm), the scientist can analyze the relationship between light exposure and the earthworm's behavior. This allows for drawing conclusions about how the earthworm responds to light stimuli.
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What does longitudinal and transverse mean when your talking about waves
We will have the following:
*Longitudinal waves: Waves in which the particles are displaced parallel to the direction the wave travels.
*Transversal waves: Waves in which the particles are displaced perpendicular to the direction the wave travels.
For a specific gas, how does its emission spectrum relate to its absorption spectrum?
a) Bright lines in its emission spectrum have different wavelengths than the dark lines of its absorption spectrum.
b) They do not relate directly.
c) Dark lines in its emission spectrum have the same wavelengths as the bright lines of its absorption spectrum.
d) Bright lines in its emission spectrum have the same wavelengths as the dark lines of its absorption spectrum.
Bright lines in its emission spectrum have the same wavelengths as the dark lines of its absorption spectrum. Hence, option (d) is correct.
What are emission spectrum and absorption spectrum?The electromagnetic radiation spectrum that is emitted when an atom or molecule changes from a high energy state to a lower energy state is known as the emission spectrum of a chemical element or chemical compound.
Absorption spectrum: An electromagnetic spectrum where a drop in radiation strength at particular wavelengths or ranges of wavelengths indicative of an absorbing substance (such as chlorophyll) is particularly visible as a pattern of dark lines or bands, in contrast to emission spectrum.
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does the mass of a parachute affect terminal velocity?
Answer:
The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.
Sharon and Kaylyn are playing air hockey. Sharon hits the hockey puck sending it at a velocity of 6 m/s and it hits Kaylyn's puck Both hockey pucks have a mass of 0.3 kg Sharon's puck stops after it hits Kaylyn's puck According to the law of conservation of momentum, what should the resulting velocity of Kaylyn's puck be if it. was at rest before colliding with Sharon's puck?
A. Equal to the velocity of Sharon's puck before they collided
B. Twice the velocity of Sharon's puck before they collided
C. Half the velocity of Sharon's puck before they collided
D. Equal to the velocity of Sharon's puck ball after they collided
Answer:
According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since Sharon's puck stops after the collision, all of its momentum is transferred to Kaylyn's puck. Therefore, the resulting momentum of Kaylyn's puck is equal to the initial momentum of Sharon's puck:
m1v1 = m2v2
where m1 and v1 are the mass and velocity of Sharon's puck before the collision, and m2 and v2 are the mass and velocity of Kaylyn's puck after the collision.
Substituting the given values:
0.3 kg × 6 m/s = 0.3 kg × v2
Simplifying:
1.8 kg m/s = 0.3 kg × v2
Dividing both sides by 0.3 kg:
v2 = 6 m/s
Therefore, the resulting velocity of Kaylyn's puck should be equal to the velocity of Sharon's puck before they collided, which is 6 m/s.
Answer: A. Equal to the velocity of Sharon's puck before they collided.
Look at the equation below. What does the u represent?
Answer:
but you didn't give the equation the question is incomplete
Answer:
Initial velocity
Explanation:
An object accelerates uniformly from rest. If the final velocity of the object after 6.0 s is
18 m/s east, how far did the object travel?
Answer:
54m
Explanation:
Given parameters:
Initial velocity = 0m/s
Time taken = 6s
Final velocity = 18m/s east
Unknow:
How far did the object travel = ?
Solution:
To solve this problem, we use one of the kinematics equation:
We first find the acceleration which is the change in velocity
So;
S = \((\frac{v - u}{2} ) t\)
S is the distance
v is the final velocity
u is the initial velocity
t is the time taken
Therefore;
S = \(\frac{18 - 0}{2}\) x 6 = 54m
A manufacturing company has a machine that can hold a maximum volume of 300 cm3 of liquid silver. This volume of liquid silver has a mass of approximately 2.8 kg. The company has a second machine that can only hold a maximum volume of 150 cm3 of liquid silver. What is the approximate mass of liquid silver that the second machine can hold?
Approximately 1.4 kg mass of liquid silver that the second machine can hold.
What is the approximate mass of liquid silver that the second machine can hold?The approximate mass of liquid silver that the second machine can hold is approximately 1.4 kg. To calculate this mass, one must understand the relationship between volume and mass, as the volume of a material can directly affect its mass.In this case, the first machine can hold a maximum volume of 300 cm3 of liquid silver, which has a mass of 2.8 kg. To calculate the mass of the second machine, one must divide the mass of the first machine by the volume of the first machine, and then multiply that number by the volume of the second machine.This equation looks like this: (2.8 kg/300 cm3) x 150 cm3 = 1.4 kg. Therefore, the approximate mass of liquid silver that the second machine can hold is approximately 1.4 kg. By understanding the relationship between volume and mass, one can accurately calculate the mass of a material that a machine can hold. In this case, the mass of the liquid silver that the second machine can hold can be calculated to be approximately 1.4 kg.This calculation can be useful for manufacturing companies, as it can help them to determine the amount of material their machines can hold in order to avoid any potential production issues.To learn more about The approximate mass of liquid silver refer to:
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A SONAR used in a ship sends ultrasound waves and receives the echo after 2.0 s.Find the depth of the shoal of fish if the speed of sound in water is 1250 m/s
Given :
A SONAR used in a ship sends ultrasound waves and receives the echo after 2.0 s.
To Find :
The depth of the shoal of fish if the speed of sound in water is 1250 m/s.
Solution :
Let, the depth of the shoal fish is d.
Now, it is given that it takes 2.0 s to receive the echo.
Also, distance covered by echo is 2d.
Now, 2d = s × t
2d = 1250 m/s × 2 s
d = 1250 m
Therefore, the depth of the shoal of fish is 1250 m.
a horse was at rest.what was the final velocity of the horse if it covered 200 meters in 16 seconds?
Answer:
12.5m/s
Explanation:
Simplify the proportion.
200/16 = 100/8 = 50/4 = 25/2 = 12.5