Tangent of the angle that the 26 foot bridge crosses a stream at an incline is 5/13.
The tangent is defined as the ratio of the length of the opposite side to the length of the adjacent side of a right triangle. we need to find the tangent of the angle of the bridge crossing the stream.The height of the bank on one side is 2 feet above the height of the water and the other bank is 12 feet above the water level. So, the height difference is 12 - 2 = 10 feet. Thus, the bridge's length is the hypotenuse of the right-angled triangle which has height 10 feet and base 26 feet.Using Pythagoras' theorem, hypotenuse = √(height² + base²)= √(10² + 26²)= √736= 26.832 feetTherefore, the tangent of the angle = height/base = 10/26 = 5/13. Thus, the tangent of the angle that the bridge crosses a stream at an incline is 5/13.
The trigonometric ratio between the adjacent side and the opposite side of a right triangle that contains an angle is called its tangent.
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A triathlete on the swimming leg of a triathlon is 120.0 m from the shore (a). The triathlete's bike is 50.0 m from the shore on the land (b). The component of her distance from the bicycle along the
A) The triathlete's bike is 50.0 m from the shore on the land B) the component of her distance from the bicycle along the shore is 70.0 m.
In a triathlon, a triathlete starts with swimming, then biking, and ends with running. Here, we have been given that a triathlete on the swimming leg of a triathlon is 120.0 m from the shore (a). The triathlete's bike is 50.0 m from the shore on land (b).
We need to find the component of her distance from the bicycle along the shore. Component of her distance from the bicycle along the shore In the above set, we can see that the triathlete is swimming in a straight line towards the shore, while the bike is on the land. We need to find the component of her distance from the bicycle along the shore. T
his component is represented by the horizontal distance (d) between the point where the swimmer hits the shore and the bike (50.0 m from the shore).Therefore, the component of her distance from the bicycle along the shore is d = 120.0 m - 50.0 m = 70.0 m. Therefore, the component of her distance from the bicycle along the shore is 70.0 m.
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Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with the three and couples to make a fourcar train. A moment later the train cars hit a fifth car that was at rest on the tracks, and it couples to make a five car train. What is the speed of the five car train? Answer in m/s.
The train moves with common Velocity, then the velocity of 5 Car train is 2m/s
There are in total 5 identical train cars which collide with each other after some interval of time
Let the Train Cars be: A,B,C,D and E
So, Velocity of A,B and C = 2 m/s
Velocity of D = 4 m/s
Velocity of E = 0 m/s
Let's Assume that the mass of all the carts is 'x', as all are identical Coaches
The common Velocity of the 5 Car train (A+B+C+D+E) if they collide with each. other we have to find
We will use the law of conservation of momentum, which states that the initial momenta of objects = Final momenta of objects
m1u1 + m2u2 = m1V1 + m2v2
Given, Mass of Train Cars = x (Assumed)
Velocity of A,B,C = 2m/s
So, they are travelling on the track, so if they collide with D, their Initial momenta will be the same as final momenta.
As Given, their final velocity are equal. So,
a(ip) + b(ip) + C(ip) + d(ip) = a(vp) + b(vp) + C(vj)
Where, IP = Initial momentum
VP = final momentum
(2*x) + (2*x) + (2*x) + (4*x)
2x + 2x + 2x + 4x = v (x+x+x+x)
10x = 4xv
v = 10x/4x =
v = 2.5mps
Hence, The final velocity of (A,B,C,D) or Four Car train = 2.5 m/s
Now, After sometime travelling with same velocity, they collide with a stationary train car of same mass and it also start moving with same velocity.
aip + bip + Cip + dip + eip = avp + bvp
(10x) + (0*x) = (v*x) + (v*x) + (v*x) + (v*x)
(10x) + 0 = v(x+x+x+x+x)
10x = 5xv
v = 10x/5x
v = 2 mps
Hence, The speed of 5 Car train (A+B+C+D+E) = 2m/s
If the train moves with common Velocity, then the velocity of 5 Car train is 2m/s
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1.5 x 10^3 standard notation
Answer:
1500
Explanation:
What is the maximum weight of a luminaire (lighting fixture) permitted to be hung directly from an outlet box in a ceiling?
The maximum weight of a luminaire (lighting fixture) permitted to be hung directly from an outlet box in a ceiling 50 pound.
A luminaire that weighs more than 23 kg (50 lb) shall be supported independently of the outlet box, unless the outlet box is listed for not less than the weight to be supported.
Luminaire, or light fixture, complete lighting unit, consisting of one or more lamps (bulbs or tubes that emit light), along with the socket and other parts that hold the lamp in place and protect it, wiring that connects the lamp to a power source, and a reflector that helps direct and distribute the light.
Fluorescent fixtures usually have lenses or louvers to shield the lamp (thus reducing glare) and redirect the light emitted. Luminaires include both portable and ceiling- or wall-mounted fixtures.
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PLEASE HELP 50 POINTS!!
An unknown material bolt with a mass of .43 kg is heated to a temperature of 100 oC, then it is placed in 1 kg of water at a temperature of 20oC, a simple calorimeter and the top is sealed. Time is allowed to go by and the equilibrium temperature is 23.059oC. What is the energy gained by the water during this process?
4186 J
96523.80 J
It doesn't gain any energy
12804.974 J
Answer:
Explanation:
The energy gained by the water can be calculated using the formula for the heat capacity of water, which is: q = mc * Delta T, where q is the energy gained by the water, m is the mass of the water, c is the heat capacity of water, and Delta T is the change in temperature of the water. In this case, m = 1 kg, c = 4.184 J/g * oC, and Delta T = 23.059 - 20 = 3.059 oC. Substituting these values into the formula, we find that the energy gained by the water is approximately 52.3 J.
The heat gained by water will be equal to the heat lost by the material bolt and it can be calculated using calorimetric equation. The heat energy gained by water is equal to 12800 J.
What is calorimetry?Calorimetry is an analytical technique used to determine the heat energy absorbed or released by a reaction system. The calorimetric equation connecting the heat energy q with the mass m, temperature difference ΔT and specific heat capacity c is written as:
q = m c ΔT.
The specific heat capacity of water = 4.18 J/ g °C
mass = 1 kg = 1000 g
temperature difference from 20 to 23. 059 °C.
The heat energy gained by water from the material bolt is then calculated as follows:
q = 4.18 J/ g °C × 1000 g × (23. 059 0 - 20 °C )
= 12800 J.
Therefore, the energy gained by water during the process is 12800 J.
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If the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27o, find the refractive index of the material
The refractive index of the material is 0.
When the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27°, the refractive index of the material can be determined. The formula for Snell’s law is used to calculate refractive index. It states that: `sin i / sin r = n where i is the angle of incidence, r is the angle of refraction and n is the refractive index`.Snell’s law can be re-arranged to make n the subject of the formula to be: `n = sin i / sin r`Hence, we can calculate the refractive index as follows:
For the incident ray, i = 360° and the angle of refraction within the material, r = 27°.n = sin i / sin r= sin 360°/ sin 27°= 0/1 (since sin 360° = 0)= 0Therefore, the refractive index of the material is 0. T
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how to calculate density
density(ρ) = mass (m) : volume (V)
A ball dropped from a height. Find (a) Acceleration (b) Distance after 3 seconds (c) Time in air if final velocity is 20 m/s.
Answer:
a)10m/s^2
b)90m/s
c)2seconds
Explanation:
a)because the ball is falling, acceleration=gravitational acceleration i.e 10m/s^2
b)distance=velocity x time
velocity= acceleration x time
velocity= 10x3=30m/s
distance= 30x3=90m/s
c)velocity=accelerationxtime
20=10 x t
20=10t
t=20/10
t= 2seconds
Answer:
Explanation:
Given:
t = 3 s
V = 20 m/s
__________
a - ?
D(t) - ?
t* - ?
1)
The acceleration is equal to the free fall acceleration:
a = g = 9.8 m/s²
2)
Distance after 3 seconds (c) :
D(t) = g·t² / 2
D(3) = 9.8·3² / 2 ≈ 44 m
3)
Time:
V = a·t*
t* = V / a = 20 / 9.8 ≈ 2 s
1. Gravity depends on two things. What two things does gravity depend on? 10pts
SCI
Gravity depends on the mass of objects and distance.
The more mass the more gravitational force, the more distance between two objects the less gravitational force.
9 Two wells are located at points A and B respectively. Point C is the middle point between A and B. When water is pumped out from Well A only, the drawdown at C is 7 in. if water is pumped out from well A whle water is poured in from well B at the same rate, what is the drawdown(ft) at point C?
Answer:
0
Explanation:
When water is pumped out of well A, it causes a drop of 7 inches at point C; if water is pumped from well B into well A (at the same rate the water is pumped out of well A), then it will give a rise of 7 inches at well C. Therefore the net drawdown at well C is:
S = 7-7 = 0
Normally, whem I shut my door, it takes quite a bit of effort to shut it, but when my window is open, even if I just pull it slightly then let go, it slams automatically. It isn't an issue, I just want to know the physics behind it. Is it something to do with difference in pressure?
Answer:
gravity
Explanation:
gravity pulls anything with with weight towards the earth.
Answer
The reason why this occurs is because if there is any apparent wind being pushed towards the direction of the door, there will be an attempt of equalizing pressure and thus it will slam, or close very loudly when you even just push it shut with some effort.
Explanation
This has happened to me a variety of times, I would have the garage open, and it would be a little bit windy, and when I tried to close it, it would slam shut.
Airflow is a significant factor in the pressure appliance.
Your question at the end is correct (Differences in air pressure.)
Apologies for the late response, but I was interested in this as well.
The potential difference across the terminals of a battery is 8. 4v when there is a current of 1. 50 a in the ba
Answer:
The potential difference across the terminals of a battery is 8. 4v when there is a current of 1. 50 a in the ba
Explanation:
The potential difference across the terminals of a battery is `8.4 V` when there is a current of `1.50 A` in the battery from the negative to the positive terminal. When the current is `3.50 Air`, the reverse direction, the potential difference becomes `9.4 V`. <br>(a) What is the internal resistance of the battery? <br>(b) What is the emf of the battery?
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
\(dl'=3.621*10^{-4}m\)
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
\(dl=\frac{Flo}{yA}\)
\(dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}\)
\(dl=1.19064778*10^-^4\)
Generally the equation for brass cylinder is mathematically given as
\(dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}\)
\(dl=2.43*10^{-4}\)
Therefore Total change in length
\(dl'=1.191*10^-^4+(2.43*10^{-4})\)
\(dl'=3.621*10^{-4}m\)
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Which is the correct equation for calculating the kinetic energy of an object?
COM
1
1
KE = mgh
KE = mu?
KE = at
KE =
492
O
) Intro
✓ Done
DO
Answer:
KE = 1/2(m)(v^2)
Explanation:
Answer:
I hope this helps
Explanation:
Find the distance a rocket will travel in orbit during a 17 second burn that will provide 300 m/s2 acceleration. assume the initial velocity is zero (relative to earth). the answer needs to be to the nearest whole number.
The distance the rocket will travel in orbit during a 17-second burn with a 300 m/s² acceleration is approximately 130050 meters, rounded to the nearest whole number.
To find the distance a rocket will travel in orbit during a 17-second burn with a constant acceleration of 300 m/s², we can use the kinematic equation: d = v₀t + (1/2)at²
where: d is the distance traveled
v₀ is the initial velocity
t is the time
a is the acceleration
Given that the initial velocity v₀ is zero, we can simplify the equation to:
d = (1/2)at²
Plugging in the values:
d = (1/2)(300 m/s²)(17 s)²
d = (1/2)(300 m/s²)(289 s²)
d = 130050 m
Therefore, the distance the rocket will travel in orbit during a 17-second burn with a 300 m/s² acceleration is approximately 130050 meters, rounded to the nearest whole number.
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A flash of light caused by a dishcharge of static electricity.
Answer:
Lightning is a flash of light created by electric discharge between clouds or between cloud and the ground or any object on the ground.
A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 254 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.0 m3 to 16.2 ms. Part A Calculate the work done by the gas. Express your answer with the appropriate units. μΑ ? W = Value Units Part B Calculate the change in internal energy of the gas. Express your answer with the appropriate units. НА O ? AU = Value Units
the change in internal energy of the gas is 1,061,830.54 J.
Part A: To calculate the work done by the gas, we use the equation:
W = PΔV
where W is the work done, P is the pressure, and ΔV is the change in volume.
Since the gas is maintained at atmospheric pressure, P = 1 atm. The change in volume is:
ΔV = 16.2 m3 - 12.0 m3 = 4.2 m3
Therefore, the work done by the gas is:
W = (1 atm)(4.2 m3) = 4.2 atm·m3
We can convert atm·m3 to joules (J) using the conversion factor:
1 atm·m3 = 101.3 J
So, the work done by the gas is:
W = (4.2 atm·m3)(101.3 J/atm·m3) = 425.46 J
Therefore, the work done by the gas is 425.46 J.
Part B: To calculate the change in internal energy of the gas, we use the first law of thermodynamics:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the gas, and W is the work done by the gas.
We are given that Q = 254 kcal. We need to convert kcal to joules:
1 kcal = 4,184 J
So, Q = (254 kcal)(4,184 J/kcal) = 1,062,256 J
We calculated in Part A that W = 425.46 J. Therefore, the change in internal energy of the gas is:
ΔU = 1,062,256 J - 425.46 J = 1,061,830.54 J
Therefore, the change in internal energy of the gas is 1,061,830.54 J.
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what happens to a circuit if the potential difference (voltage) is increased (by adding batteries) and the resistance is the same? sps10.a what happens to a circuit if the potential difference (voltage) is increased (by adding batteries) and the resistance is the same? the current is decreased the current stays the same the current increases impossible to tell
As the total resistance increases, the potential difference increases and the total current in the circuit decreases.
If you increase the voltage (or electrical pressure) in a circuit, the current (flow of electrons) will increase in direct proportion. In other words, doubling the voltage doubles the current flow. As the potential difference Δ V \Delta V ΔV increases for a given current I, the resistance R also increases, and vice versa. As the potential difference across an incandescent lamp increases, the current through the lamp also increases due to Ohm's law. As the current flow increases, the lamp also heats up, increasing the resistance of the lamp.
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The average US house uses 10,972 kilowatt hours (kWh) in a year, an average of about 914 kWh per month. 1) hoover dammm produces about 4 billion kilowatt hours per year. How many houses can it power? 2) If the average (not hoover) dammm is 15 meters in height, how much water would have to drop out of the dam to power a house for a year?
Answer:
1) 364,564 houses
2) Approximately 2.7 × 10⁸ litres of water annually
Explanation:
The power consumption of the average household = 10,972 kWh/year
The power consumption, \(P_{(consumed/house)}\) of the average household = 914 kWh/month
The amount of power produced, \(P_{produced}\), by the Hoover Dam = 4×10⁹ kW/year
1) The number of houses, n, the Hoover Dam can power is given by the relation;
\(n = \dfrac{P_{produced}}{P_{(consumed/house)}} = \dfrac{4 \times 10^9}{10972} = 364,564.35 \ houses\)
Which is approximately 364,564 houses
2) Given the height, h = 15 m
We have at 100% efficiency,
The potential energy of the water per year = 10,972 kWh
The potential energy of the water = m×g×h
Where:
g = Acceleration due to gravity = 9.81 m/s²
∴ The potential energy of the water = m×9.81×15
Therefore, we have;
m×9.81×15 = 10,972 kWh = 10972×60 min/hour ×60 seconds/minute Joules
m×9.81×15 = 39,499,200 kJ = 39,499,200,000 J
m = 39,499,200,000/(9.81 × 15) = 268,428,134.6 kg
The volume, V, of water that would have to drop out of the dam to power a house for a year is given by the relation;
Volume = (Mass of water)/(Density of water)
V = (268,428,134.6 kg)/(1000 kg/m³)
V = 268,428.135 m³ ≈ 2.7 × 10⁸ litres of water annually.
The gravitational force is 2336 N for an object that is 4.15 x 10^6 m above the surface of the Earth? The radius of the Earth is 6.378 x 10^6 m. (Earth's mass is 5.97 x 10^24 kg) What is the mass of the object above earth?
Answer:
34kg
Explanation:
determine the ratio of output force, fo , to input force, fi . ignore friction and the mass of the lever, and assume the work output equals the work input.
This means that fo/fi = di/do, which is equal to the mechanical advantage of the lever.
What is mechanical advantage?
The force amplified by using a device, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, this same device trades off input troops against movement. The law of the lever serves as a model for this. Mechanisms are machine parts made to control forces and motion in this way. An ideal transmission system does not increase or decrease power. Consequently, the ideal machine is devoid of a power source, frictionless, and built from rigid materials that do not flex or wear. Efficiency factors that account for deviations from the ideal are used to express how well a real system performs in comparison to the ideal.
The ratio of output force, fo , to input force, fi , is determined by the mechanical advantage of the lever.
The mechanical advantage is equal to the ratio of the distance from the fulcrum to the input force, di , divided by the distance from the fulcrum to the output force, do.
Therefore, the ratio of output force, fo , to input force, fi , is equal to di/do. Since work output equals work input, the product of fo and di is equal to the product of fi and do.
This means that fo/fi = di/do, which is equal to the mechanical advantage of the lever.
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If the potential energy of a roller coaster is 60,000 J at the highest point, what is its kinetic energy at the lowest point?
Answer:
60 000 J
Explanation:
The PE will be converted to KE entirely (if the lowest point is ground level)
Which other subatomic particle has the same mass as a neutron
Answer:
.................... protons :)
Answer:
protons
The two subatomic particles that have the same mass are protons and neutrons.
Calculate the amount of energy a 3 kg ball on top of 10 m hill will have. Show your work with the correct ending units.
Answer:
This question is hard I will edit my answer when I find the answer
Explanation:
Which best contrasts Newton's and Einstein's ideas?
Newton believed that mass tells objects how to move. Einstein believed that the curvature of space-time tells force how to
move objects.
Newton believed that force tells mass how to move. Einstein believed that the curvature of space-time tells velocity how to
change.
Newton believed that distance tells gravity how much force to exert. Einstein believed that distance tells space-time how to
curve.
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Answer:
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Explanation:
Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.
Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.
This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.
Answer:
first one is for the assignment second is for the quiz
Explanation:
Assignment - C.
Quiz - D.
A figure skater rotating at 5. 00 rad/s with arms extended has a moment of inertia of 2. 25 kg·m2. If the arms are pulled in so the moment of inertia decreases to 1. 80 kg·m2, what is the final angular speed?.
A figure skater rotating at an initial angular speed of 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg·m². When the skater pulls in their arms, reducing the moment of inertia to 1.80 kg·m², the final angular speed can be determined.
According to the principle of conservation of angular momentum, the total angular momentum of a system remains constant unless acted upon by an external torque. Mathematically, angular momentum (L) is given by the product of moment of inertia (I) and angular speed (ω), i.e., L = Iω.
Initially, the skater has an angular momentum of L =\(I * ω\) , where I_initial is the initial moment of inertia and ω_initial is the initial angular speed.
When the skater pulls in their arms, the moment of inertia decreases to I_final, and we need to find the final angular speed ω_final.
Since angular momentum is conserved, we have L_initial = L_final, which can be expressed as I_initial * ω_initial = I_final * ω_final.
Rearranging the equation to solve for ω_final, we get ω_final = (I_initial * ω_initial) / I_final.
Plugging in the values, we have ω_final = (\(2.25 kg·m² * 5.00 rad/s) / 1.80 kg·m².\)
Simplifying the expression, we find ω_final ≈ \(6.25 rad/s\\\).
Therefore, the final angular speed of the figure skater, after pulling in their arms and reducing the moment of inertia to 1.80 kg·m², is approximately 6.25 rad/s.
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.If you looked at a light through the lenses from two polarizing sunglasses that were overlapped at right angles to each other: a) all of the light would pass through b) most of the light would pass through c) little of the light would pass through d) none of the light would pass through
When two polarizing lenses are overlapped at right angles, the polarization axes are perpendicular to each other. In this configuration, option d) "none of the light would pass through" is correct.
When two polarizing sunglasses are overlapped at right angles to each other, the amount of light that passes through depends on the orientation of the polarization axes in each lens.
Polarizing sunglasses are designed to block light waves vibrating in certain orientations while allowing light waves vibrating in other orientations to pass through. The lenses have a built-in filter that transmits light waves with a specific polarization axis while absorbing or blocking light waves with perpendicular polarization axes.
Since the polarization axes of the two lenses are orthogonal, the first lens will block all the light waves that are not aligned with its polarization axis. The second lens, with its polarization axis at a right angle to the first lens, will also block all the remaining light waves that managed to pass through the first lens. As a result, no light would be able to pass through both lenses, and no light would be visible when looking at a light source through them.
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a change in which of the following will affect the buoyant force experienced by an object that is totally submerged in a liquid?
Density of the fluid and volume of the body immmerse in it will affect the buoyant force experienced by an object that is totally submerged in a liquid.
Hence, the correct option is D.
A change in the following factors will affect the buoyant force experienced by an object that is totally submerged in a liquid:
a) Weight of the fluid displaced: The buoyant force is equal to the weight of the fluid displaced by the submerged object. Therefore, the weight of the fluid displaced, which is determined by the volume of the object submerged and the density of the fluid, will affect the buoyant force.
b) Density of the fluid: The buoyant force is directly proportional to the density of the fluid. If the density of the fluid changes, it will affect the buoyant force acting on the object.
c) Volume of the object submerged: The buoyant force is directly proportional to the volume of the object submerged in the fluid. If the volume of the object changes, it will result in a change in the buoyant force.
d) Mass of the fluid displaced: The buoyant force is also equal to the mass of the fluid displaced. This is determined by the volume of the object submerged and the density of the fluid.
So, to summarize, changes in the weight of the fluid displaced, the density of the fluid, the volume of the object submerged, or the mass of the fluid displaced will affect the buoyant force experienced by an object that is totally submerged in a liquid.
Hence, the correct option is D.
The given question is incomplete and the complete question is '' a change in which of the following will affect the buoyant force experienced by an object that is totally submerged in a liquid?
a. weight of the immersed in it
b. shape of the body immersed in the fluid
c. density of the fluid ande mass of the body immmerse in it.
d. density of the fluid and volume of the body immmerse in it.
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Which scientist was involved in the War of Currents?
Help
Explanation:
thomas edison and Nikola tesla were involved in the war of currents
A white dwarf will become a supernova if Choose one: A. even a small amount of mass falls on it from a companion. B. it accretes an additional 1.38 MSun from a companion. C. the original star was more than 1.38 MSun. D. enough mass accretes from a companion to give the white dwarf a total mass of 1.38 MSun.
A white dwarf will become a supernova if it accretes an additional 1.38 MSun from a companion. White dwarf stars have used up all of the hydrogen that was once used as nuclear fuel. Heat and outward pressure are produced by fusion in a star's core, but these pressures are balanced by the star's mass's inward pull of gravity.
They are the stellar cores that remain after a star has depleted its fuel supply and ejected the majority of its gas and dust into space. The white dwarf is considered "dead" because the atoms inside it no longer fuse to provide energy to the star.
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