Answer:
\(752.1\; {\rm N}\) from support \(\texttt{1}\) (\(2.0\; {\rm m}\) from the student.)
\(1013.7\; {\rm N}\) from support \(\texttt{2}\) (\(1.0\; {\rm m}\) from the student.)
(Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\), the beam is level with negligible height, and that the density of the beam is uniform.)
Explanation:
Weight of the beam: \((100\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) = 981\; {\rm N}\).
Weight of the student: \((80\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) = 784.8\; {\rm N}\).
Assuming that the beam is uniform. The center of mass of the beam will be \((1/2)\, (3.0\; {\rm m}) = 1.5\; {\rm m}\) away from each support.
Consider support \(\texttt{1}\) as the fulcrum:
For support \(\texttt{2}\) (with an upward force of \(N_{\texttt{2}}\)), the lever arm is \(3.0\; {\rm m}\).For the center of mass of the beam (\(981\; {\rm N}\)), the lever arm is \(1.5\; {\rm m}\).For the weight of the student (\(784.8\; {\rm N}\)), the lever arm is \(2.0\; {\rm m}\).Hence:
\(\begin{aligned}N_{\texttt{2}}\, (3.0) = (981)\, (1.5) + (784.8) \, (2.0) \end{aligned}\).
\(\begin{aligned}N_{\texttt{2}} &= \frac{(981)\, (1.5) + (784.8) \, (2.0)}{3.0} \; {\rm N} = 1013.7\; {\rm N}\end{aligned}\).
In other words, support \(\texttt{2}\) would exert an upward force of \(1013.7\; {\rm N}\) on the beam.
Similarly, consider support \(\texttt{2}\) as the fulcrum:
For support \(\texttt{1}\) (with an upward force of \(N_{\texttt{1}}\)), the lever arm is \(3.0\; {\rm m}\).For the center of mass of the beam (\(981\; {\rm N}\)), the lever arm is \(1.5\; {\rm m}\).For the weight of the student (\(784.8\; {\rm N}\)), the lever arm is \((3.0 - 2.0)\; {\rm m} = 1.0\; {\rm m}\).Hence:
\(\begin{aligned}N_{\texttt{1}}\, (3.0) = (981)\, (1.5) + (784.8) \, (1.0) \end{aligned}\).
\(\begin{aligned}N_{\texttt{1}} &= \frac{(981)\, (1.5) + (784.8) \, (1.0)}{3.0} \; {\rm N} =752.1\; {\rm N}\end{aligned}\).
In other words, support \(\texttt{1}\) would exert an upward force of \(752.1\; {\rm N}\) on the beam.
describe the error that results from accidentally using your left rather than your right hand when determining the direction of a magnetic force on a straight current carrying conductor
The error that results from accidentally using your left hand rather than your right hand when determining the direction of a magnetic force on a straight current carrying conductor is due to the fact that the left and right hand rules have opposite directions. The right-hand rule is commonly used in physics to determine the direction of magnetic forces, whereas the left hand rule is less common.
By using the left hand rule instead of the right hand rule, the direction of the magnetic force will be incorrect. This can lead to incorrect calculations and predictions in the field of electromagnetism. It is important to ensure that the correct hand rule is used to accurately determine the direction of the magnetic force on a straight current carrying conductor.
In summary, using the wrong hand rule can result in an error in the direction of the magnetic force on a straight current carrying conductor. To avoid this error, it is important to use the correct hand rule for the given situation. When determining the direction of the magnetic force on a straight current-carrying conductor, using your left hand instead of your right hand will result in an incorrect force direction. This error occurs because the Right Hand Rule is specifically designed to help visualize the relationship between the current direction, magnetic field direction, and the resulting magnetic force direction.
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A toroidal solenoid of square cross-section is made with inner and outer radii of 3.0 and 4.0 cm. How many turns of wire are necessary to obtain a self-inductance of 1.15 H
To find the number of turns of wire necessary to obtain a self-inductance of 1.15 H for a toroidal solenoid of square cross-section with inner and outer radii of 3.0 and 4.0 cm, we can use the formula for the self-inductance of a toroidal solenoid:
L = μ₀N²πr² / (2πr + πd)
where L is the self-inductance, N is the number of turns of wire, r is the mean radius (the average of the inner and outer radii), d is the cross-sectional diameter (in this case, equal to the side length of the square cross-section), and μ₀ is the permeability of free space (4π x 10^-7 H/m).
Plugging in the given values, we get:
1.15 = (4π x 10^-7)(N²π(0.035+0.04)²) / (2π(0.04) + π(0.01))
Simplifying, we get:
1.15 = 1.053 x 10^-6 N²
Solving for N, we get:
N = √(1.15 / 1.053 x 10^-6) ≈ 1093 turns
Therefore, approximately 1093 turns of wire are necessary to obtain a self-inductance of 1.15 H for the given toroidal solenoid.
To find the number of turns of wire necessary for a toroidal solenoid with a square cross-section, inner radius of 3.0 cm, outer radius of 4.0 cm, and a self-inductance of 1.15 H, we can use the formula for the self-inductance of a toroidal solenoid:
L = (μ₀ * N² * A * h) / (2 * π * R)
where:
L = self-inductance (1.15 H)
μ₀ = permeability of free space (4π × 10⁻⁷ H/m)
N = number of turns of wire (unknown)
A = cross-sectional area of the solenoid (square cross-section)
h = height of the solenoid (which is the difference between the outer and inner radii, 4.0 cm - 3.0 cm = 1.0 cm)
R = average radius of the solenoid (which is the average of the inner and outer radii, (3.0 cm + 4.0 cm) / 2 = 3.5 cm)
First, convert the measurements from cm to meters:
h = 1.0 cm * 0.01 m/cm = 0.01 m
R = 3.5 cm * 0.01 m/cm = 0.035 m
Rearrange the formula to solve for N:
N = sqrt((2 * π * R * L) / (μ₀ * A * h))
Since A is not provided, you will need the value of the square cross-sectional area to calculate the exact number of turns (N). Once you have that value, plug it into the formula, and solve for N.
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suppose that the internal energy of a system has been increased, resulting in an increase in the temperature of the system. which of the following is the cause of this change?
No, according to the first law, whether a certain amount of energy is added by doing work on the system or by adding heat, the internal energy will change in the same way.
A thermodynamic system's total internal energy is defined as the energy it possesses. It consists of both internal kinetic energy and potential energy contributions, and it is the energy required to develop or prepare the system in its current internal condition. The system's energy gains and losses resulting from modifications to its internal state are tracked by this mechanism. It excludes all external energies from surrounding force fields as well as the kinetic energy of the system's overall motion. The first law of thermodynamics, which is based on the idea that an isolated system's internal energy is constant, is stated as the law of conservation of energy. An vast quality is the internal energy.
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a flexible container holding 4.00 moles of gas contracts from 89.6 l to 44.8 l when some gas is release
Avogadro's law connects temperature, pressure, volume, and substance amount for a certain gas, which makes it closely related to the ideal gas equation. The moles of gas in the reduced container are 2.
According to Avogadro's hypothesis, a gas law, the volume occupied by a gas at constant temperature and pressure is directly proportional to the total number of atoms/molecules of a gas (i.e., the amount of gaseous substance).
The following formula can be used to represent Avogadro's law under constant pressure and temperature:
V/n = K
Where 'V' is volume and 'n' is number of moles.
V₁/n₁ = V₂/n₂
n₂ = n₁V₂ / V₁
n₂ = 4 × 44.8 / 89.6
n₂ = 2
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Your question is incomplete, most probably your full question was:
a flexible container holding 0.04 moles of a gas contract from 800ml to 200ml when some gas is released. how many moles of gas are in the reduced container
Complete the sentence to describe what a wave is and what it does.
A wave is a
that carries
from one place to another.
Answer:disturbance
A wave is a disturbance that carries energy from one place to another.
Explanation:
edg2020
Answer:
its disturbance and energy for short
Explanation:
A 2280 kg car, moving at 24.2 m/s, runs into a car that has a mass of 2180 kg
and is moving at 15.3 m/s in the same direction. The cars stick together after
the collision. Assuming momentum is conserved, what is their final velocity?
OA. 18.6 m/s
OB. 17.2 m/s
O C. 19.8 m/s
OD. 16.7 m/s
Answer:
The answer is C.19.8 m/s because it's their common velocity after the collision of the two cars.
Explanation:
Hello !
look at the attachment above ☝️ and if you have any questions you're welcome.
in a cathode-ray tube, particles are fired at the screen. What are these particles
The conductivity of water can be increased by adding .
Explanation:
The conductivity of water can be increased by adding any solute that increases the number of ions in solution.
Hope this helps you.. Good luck
The conductivity of water can be incrased by adding to it anything that disolves and ionizes in it.
Examples:
-- sugar
-- coffee
-- tea
-- artificial sweetener
-- baking soda
-- orange juice
-- corn starch
-- salt
PLEASE HELP 30 POINTS
1.
Determine the kinetic energy of 1500 kg Tow-Mater Truck traveling at 31.0 m/sec.
Show your work.
2.
A base jumper of mass 68.0 kg stands on the edge of a cliff and possesses 16,800 J of potential energy. How high up is this Mountain Dew Man from the base of the cliff?
Show your work
Answer:1. Using the following formula, we can calculate the kinetic energy of a 1500 kg tow-mapping truck moving at a speed of 31.0 m/s: KE is equal to 0.5 * m * v2, where m is the object's mass and v is its speed.
By entering the data, we obtain the following equation: KE = 0.5 * 1500 kg * (31.0 m/sec) * 2 = 0.5 * 1500 kg * 961 m2/sec * 2 = 723,500 J
Therefore, the 1500 kg Tow-Mater Truck's kinetic energy at 31.0 m/sec is 723,500 J.
2. To determine the height of the cliff, we use the formula: PE = mgh, where m is the mass of the base jumper, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the cliff.
Given that the base jumper has 16,800 J of potential energy, we can rearrange the formula to find h: h = PE / (m * g) = 16,800 J / (68.0 kg * 9.8 m/s^2) = 20.6 m
So, the base jumper is 20.6 meters above the base of the cliff.
Explanation:
Answer:
1.
energy : KE = units J
mass: m = 1500m unit
velocity: v = 31v unit m/s
Answer:
KE = 720750 J
2.
energy: KE = 16800 KE unit
mass: m = 68.0m unit
= V
Answer:
v = 22.228757209048 m/s
A skier of weight 700 N is pointed down a ski hill that has a slope angle of 25° above horizontal.
What is the component of his weight pulling him down the slope.
O 634N
O 326N
O 296N
O 700N
Answer:
O 296N
Explanation:
F_y = F*sin(x)
F_y = 700N*sin(25°)
F_y = 295.83N or 296N
A double-concave lens has equal radii of curvature of 15.1 cm. An object placed 14.2 cm from the lens forms a virtual image 5.29 cm from the lens. What is the index of refraction of the lens material?
a) 1.77
b) 1.90
c) 1.82
d) 1.98
A double-concave lens has equal radii of curvature of 15.1 cm. An object placed 14.2 cm from the lens forms a virtual image 5.29 cm from the lens. 1.90 is the index of refraction of the lens. Therefore, the correct option is option B.
A lens's index of refraction is a measurement of how much light passing through it may be bent relative to the speed of light in a vacuum. It is a crucial component of a lens since it affects how well it can concentrate light and produce images. A lens's index of refraction might change based on the kind of material that was used to make it. Glass, plastic, and crystal are examples of frequently encountered materials with high indexes of refraction. A lens can be made narrower while yet having the same optical power the higher its index of refraction. Typically, a lens's index of refraction is indicated by the letter "n."
\($\frac{1}{f} = (n-1)\left(\frac{1}{R_1}-\frac{1}{R_2}+\frac{(n-1)d}{nR_1 R_2}\right)$\)
\($\frac{1}{f} = (n-1)\left(-\frac{2}{|R|}\right)$\)
\($n-1 = -\frac{1}{2}\left(\frac{1}{f}\right)\left(\frac{|R|}{15.1\text{ cm}}\right)$\)
\($\frac{1}{f} = \frac{1}{d_o}+\frac{1}{d_i}$\)
\($\frac{1}{f} = \frac{1}{14.2\text{ cm}}-\frac{1}{5.29\text{ cm}}\)
\(= -0.0983\text{ cm}^{-1}$\)
\($n-1 = \frac{1}{2}(0.0983\text{ cm}^{-1})(1.00)\)
\(= 1.90\)
n = 1.90
Therefore, the correct option is option B.
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What energy transformation takes place when you push a pencil off your desk? A. Mechanical energy transforms into kinetic energy. B. Potential energy transforms into nuclear energy. C. Potential energy transforms into kinetic energy. D. Kinetic energy transforms into potential energy.
When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.
The correct answer to the given question is option C.
Potential energy is the energy stored within an object because of its position or configuration.
In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.
As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.
Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.
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Consider a beaker with two holes X and Y near the base, such that hole X is ABOVE hole Y. The holes are closed with water-resistant tape and the beaker is filled with water.
Both the holes are then uncovered at the same time. If water from hole X comes out in a stream that touches the ground at a distance of 5 cm away from the beaker, how far from the beaker will the stream from hole Y touch the ground?
1. exactly 5 cm
2. less than 5 cm
3. more than 5 cm
4. (It will be more or less than 5 cm depending on the distance between the two holes.)
As the height of the hole increases, the velocity of the stream increases, results in a higher distance from the beaker. Therefore, the distance of the stream from the hole Y will be less than that from X thus, less than 5 cm is correct.
What is stream speed ?The speed of stream can be determined using the height and acceleration due to gravity g. We can use the equation for velocity using the parameters g and h.
v = √2gh
Therefore, as the height h increases, v increases.
Similarly the distance s = vt
therefore, the distance increases with v.
Here, the hole x is above the hole Y. Then the stream from X will have the greater speed and it covers greater distance (5 cm )from the beaker. Stream from Y slow compared to that in X hence covers a distance less than 5 cm. Hence, option 2 is correct.
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what are noble gases ? Explain each example.
Answer:
18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og)
Explanation:
problem b2: the soil test report recommended 5 lb per 1000 ft2 n and 4 lb per 1000 ft2 p2o5 for your lawn. you have no fertilizer, so you head to the store. you realize that there is an organic option (milorganite) or you could buy inorganic fertilizer (urea tsp). determine the cost per pound of nutrient. determine what you will need to apply for each option. determine the cost of both options. assume your lawn is 5000 ft2 and that you are only concerned with the total cost to apply not the cost of materials (you can use remaining fertilizer later).
The cost of the organic option (Milorganite) is approximately $578.50, and the cost of the inorganic option (Urea TSP) is approximately $407.50
To determine the cost per pound of nutrient and the amount needed to apply for each option (organic and inorganic), we'll need the cost and nutrient composition of the fertilizers. Let's assume the following:
Organic Option - Milorganite:
Cost: $20 for a 36 lb bag
Nutrient Composition: Nitrogen (N) - 6%, Phosphorus (P2O5) - 4%, Potassium (K2O) - 0%
Inorganic Option - Urea TSP (Triple Superphosphate):
Cost: $15 for a 20 lb bag
Nutrient Composition: Nitrogen (N) - 46%, Phosphorus (P2O5) - 0%, Potassium (K2O) - 0%
Now, let's calculate the cost per pound of nutrient for each option:
Organic Option - Milorganite:
Cost per pound of Nitrogen (N): $20 / (36 lb * 0.06) = $9.26/lb
Cost per pound of Phosphorus (P2O5): $20 / (36 lb * 0.04) = $13.89/lb
Inorganic Option - Urea TSP:
Cost per pound of Nitrogen (N): $15 / (20 lb * 0.46) = $16.30/lb
Cost per pound of Phosphorus (P2O5): Not applicable (since it doesn't contain P2O5)
Next, let's determine the amount of each nutrient needed to apply for the given lawn area:
Nitrogen (N):
For the organic option - Milorganite:
5 lb per 1000 ft^2 * (5000 ft^2 / 1000 ft^2) = 25 lb
For the inorganic option - Urea TSP:
5 lb per 1000 ft^2 * (5000 ft^2 / 1000 ft^2) = 25 lb
Phosphorus (P2O5):
For the organic option - Milorganite:
4 lb per 1000 ft^2 * (5000 ft^2 / 1000 ft^2) = 20 lb
For the inorganic option - Urea TSP:
No phosphorus is provided by this fertilizer.
Finally, let's calculate the total cost of both options:
For the organic option - Milorganite:
Total cost = (Cost per pound of Nitrogen * Amount needed) + (Cost per pound of Phosphorus * Amount needed)
= ($9.26/lb * 25 lb) + ($13.89/lb * 20 lb)
≈ $578.50
For the inorganic option - Urea TSP:
Total cost = (Cost per pound of Nitrogen * Amount needed)
= ($16.30/lb * 25 lb)
≈ $407.50
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Explain it pleaseTwo particles of charge Q are located inside a box. One is at the box center while the other is halfway to one of the corners. Determine the electric flux through the box.
Answer: charge enclosed over epsilon not gives
The electric flux through the box is determined by the charge enclosed within the box divided by the permittivity of free space (ε₀). In this scenario, we have two particles of charge Q, with one located at the center of the box and the other halfway to one of the corners.
Since the charge at the center of the box is equidistant from all sides, it will produce an equal flux through each face of the box. On the other hand, the charge halfway to one of the corners will only contribute to the flux through one face of the box.
Therefore, the total electric flux through the box is given by the charge enclosed, which is the sum of the charges of both particles (2Q), divided by the permittivity of free space (ε₀). Mathematically, it can be expressed as:
Electric Flux = (2Q) / ε₀.
This equation signifies that the electric flux through the box is directly proportional to the total charge enclosed within it. The permittivity of free space (ε₀) is a constant that relates to the ability of the electric field to propagate through a vacuum.
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What is meant by net force?
the lift piston base and the input piston base are at the same height. what input force, , is required to maintain this system in equilibrium?
Input force = (Output force/Output area) × Input area
By Pascal Law,
Input force / input area = Output force / output area
By re-arranging,
Input force = (Output force/Output area) × Input area
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tarzan swings over a small gap in the land. it takes him two seconds to swing over. what is the length of the vine
To calculate the length of the vine that Tarzan swings on, we need to use the formula: Length of vine = distance swung / time taken. Length of vine = distance swung / time taken, Length of vine = length of gap / 2 seconds. Without knowing the length of the gap, we cannot calculate the length of the vine that Tarzan swings on.
We know that Tarzan swings over a small gap in the land in two seconds. So, the time taken is 2 seconds. We also know that he swings over the gap, which means the distance swung is equal to the length of the gap.
Therefore, the length of the vine can be calculated by dividing the length of the gap by the time taken:
Length of vine = distance swung / time taken
Length of vine = length of gap / 2 seconds
To calculate the length of the vine Tarzan is using, we would need additional information such as Tarzan's speed while swinging. However, based on the given information:
1. Tarzan swings over a small gap in the land.
2. It takes him 2 seconds to swing over the gap.
Without knowing the length of the gap, we cannot calculate the length of the vine that Tarzan swings on.
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I need some help
a golfer can hit a golf ball 300 m horizontally. what maximum height would a 301.5 meter drive reach if it was launched at a 25 degree angle above the ground
This question involves the concepts of projectile motion, horizontal range, and height.
The maximum height reached by the ball is "35.15 m".
First, we will find out the launch velocity of the projectile motion of the ball, by using the formula of the horizontal range:
\(R= \frac{u^2Sin\ 2\theta}{g}\\\\\)
where,
R = horizontal range = 301.5 m
u = launch speed = ?
θ = launch angle = 25°
g = acceleration due to gravity = 9.81 m/s²
Therefore,
\(301.5\ m = \frac{u^2Sin\ 50^o}{9.81\ m/s^2}\\\\u = \sqrt{\frac{(301.5\ m)(9.81\ m/s^2)}{Sin\ 50^o}}\)
u = 62.14 m/s
Now, we will find out the maximum height (H) of the projectile motion, using the following formula:
\(H = \frac{u^2Sin^2\theta}{2g}\\\\H =\frac{(62.14\ m/s)^2Sin^2(25^o)}{2(9.81\ m/s^2)}\)
H = 35.15 m
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The attached picture shows the projectile motion.
1. A 50 kg carton slides at 4 m/s across an icy surface.
The sliding carton skids onto a rough surface and
stops in 3 seconds. Calculate the force of friction it
encounters.
Answer:
A carton of mass 50-kg slides across an icy surface at a speed of 4 m/s. Conclusion : The momentum of a carton of given mass moving with a particular velocity is 200 kg−m/s .
A diffraction grating has 45,000 slits/cm. What is the distance between adjacent slits?.
If A diffraction grating has 45,000 slits/cm then The distance between adjacent slits on this diffraction grating is approximately 2.22 micrometers.
To determine the distance between adjacent slits on a diffraction grating, we need to use the formula:
d = 1/n * dλ/a
where d is the distance between adjacent slits, n is the number of slits per unit length (in this case, 45,000 slits/cm), dλ is the wavelength of the incident light, and a is the angle between the incident light and the diffracted light.
Assuming we are working with visible light (with a wavelength of approximately 500 nm) and a diffraction angle of 30 degrees, we can calculate the distance between adjacent slits as follows:
d = 1/(45,000/cm) * (500 nm)/(sin(30 degrees))
d = 1/(4.5 x 10^5 /m) * (500 x 10^-9 m)/(0.5)
d = 2.22 x 10^-6 m
Therefore, the distance between adjacent slits on this diffraction grating is approximately 2.22 micrometers.
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The formula for the spacing of a diffraction grating: d = 1/N * λ/sin(θ)
To answer this question, we need to use the formula for the spacing of a diffraction grating: d = 1/N * λ/sin(θ)
Where d is the distance between adjacent slits,
N is the number of slits per unit length (in this case, 45,000 slits/cm),
λ is the wavelength of the incident light, and θ is the angle between the incident light and the diffracted light.
Assuming we are using visible light with a wavelength of 500 nm (0.0005 cm), and that the diffraction angle is 30 degrees, we can calculate the spacing as follows:
d = 1/45000 * 0.0005 / sin(30) = 1.155 x 10^-6 cm
So the distance between adjacent slits in this diffraction grating is approximately 1.155 micrometers (or 1155 nanometers).
In conclusion, the distance between adjacent slits in a diffraction grating with 45,000 slits/cm is 1.155 x 10^-6 cm, or approximately 1.155 micrometers. This calculation is based on the formula for diffraction grating spacing, which takes into account the number of slits per unit length, the wavelength of the incident light, and the diffraction angle.
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The law of superposition states that in an undeformed sequence of sedimentary rocks the oldest rocks will be at the bottom while the youngest will be on top. Notice the word undeformed in the last sentence: that means the naturally occurring rock layers are somehow altered, causing confusion or gaps in the geologic record. Changes to the rock strata can occur due to a variety of geologic events. Which geologic event is INCORRECTLY identified?
A) D. Intrusion of magma at Earth's surface.
B) B. Folding of layers due to compression.
C) C. Unconformity showing erosion and deposition.
D) A. Faulting due to stress and fracture.
The geologic event that is incorrectly identified is option A) D. Intrusion of magma at Earth's surface.
What is the law of superposition about?According to the Law of Superposition, the oldest rocks will be at the bottom and the youngest at the top of a sequence of sedimentary strata that has not undergone any deformation.
If you were to imagine a river dumping sand into an ocean, the sand would eventually pour out onto the ocean floor and settle on top of the seafloor. After the seafloor's sand had already been laid down, this sand was added.
Note that the events are as follows:
Subsidence and deposit layer Folding of layers as a result of compression.Unconformity showing erosion as well as deposition.Faulting as a result of stress and fracture.Therefore, option A is incorrectly labeled because it is one that is supposed to be labeled as subsidence and deposit layer of geologic event.
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What is the difference between a distance time graph and a speed time graph?
Answer:
speed-time graph is the acceleration of the particle or straight lines acceleration is constant
a distance-time graph represents that a particle has constant speed.
Explanation:
The difference between Distance - Time graph and Speed - Time graph is explained below -
We have a distance - time graph and a speed - time graph.
We have to differentiate between them.
How is Speed of any body related to the distance covered by it?The speed of the body can be expressed as the ratio of total distance travelled by the body and the time taken by the body.
According to the question -
Distance - Time graph - The distance - time graph shows the total distance covered by the body with respect to time. In this graph, distance covered is plotted along the y - axis and the time is plotted along the x - axis.Speed - Time graph - The speed - time graph shows the variation of speed (or the rate of change of distance covered w.r.t time) with respect to time. In this graph, speed is plotted along the y - axis and the time is plotted along the x - axis.Hence, the difference between Distance - Time graph and Speed - Time graph is explained.
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a car travels at a constant speed around a circular track whose radius is 3.50 km. the car goes once around the track in 200 s. what is the magnitude of the centripetal acceleration of the car?
The magnitude of the centripetal acceleration of the car is 0.0314 m/s².
centripetal acceleration
Centripetal acceleration is described because the assets of the motion of an item, traversing a circular path. Any object that is shifting in a circle and has an acceleration vector pointed in the direction of the center of that circle is referred to as Centripetal acceleration.
a = v²/ r
r = 3500 m (SI unit)
t = 200 s
circumference = C
C = 2 * π * r
C = 2 * 3.141 * (3500 m)
C = 21987 m
v = D / t
v = (21987 m) / (200 s)
v = 109.935 m/s
a = (109.935 m/s)² / (3500 m)
a = (109.935 m/s²) / (3500 m)
a = 0.0314 m/s²
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explain what the net effect of the sodium-potassium pump is.
The net effect of the sodium-potassium pump is to create a transmembrane electrical potential.
Sodium-potassium pump is a process in which sodium ions (Na+) are transported out of the cell while potassium ions (K+) are transported into the cell. The net effect of this process is that there is a greater concentration of K+ ions inside the cell and a greater concentration of Na+ ions outside the cell.
This creates an electrochemical gradient across the cell membrane. This gradient is what allows cells to carry out a variety of functions such as transmitting signals and carrying out metabolic processes. The electrochemical gradient is also what drives the movement of other molecules across the cell membrane.
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PLS ANSWER ASAP!!
A player punts a football at an angle of 30 degrees with an initial velocity of 20.0
m/s. What is the max range of the ball horizontally?
O 34.0 m
O24.0 m
8.30 m
0 20.0 m
Answer:
The closest choice to the answer is 34.0 m
Explanation:
Projectile Motion
It's the type of motion experienced by an object that is launched near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the Range or maximum horizontal distance traveled by the object is:
\(\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}\)
The football is kicked at an angle of 30° with an initial velocity of 20 m/s. Replacing those values:
\(\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ)}{9.8}}\)
\(\displaystyle d={\frac {400\sin(60^\circ)}{9.8}}=35.35\ m\)
The closest choice to the answer is 34.0 m
given the angular speed of ω = 1.00 radians/s , find the radius r(ω) at which the mass rotates without moving toward or away from the origin.
To find the radius at which the mass rotates without moving toward or away from the origin, we can use the concept of centripetal acceleration. Centripetal acceleration is given by the formula: a = ω^2 * r
F = -T
m * ω^2 * r = -T
r = -T / (m * ω^2)
Where:
a is the centripetal acceleration,
ω is the angular speed (in radians per second),
and r is the radius.
In this case, the angular speed ω is given as 1.00 radians/s. We want to find the radius r at which the mass rotates without moving toward or away from the origin, so the centripetal acceleration must be zero.
Setting a = 0 in the centripetal acceleration formula, we have:
0 = ω^2 * r
Since ω^2 is nonzero, we can divide both sides of the equation by ω^2:
0 / ω^2 = r
Therefore, the radius at which the mass rotates without moving toward or away from the origin is 0.
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Question 7 (1 point)
An air mass exists off the Pacific coast of California. What type of air mass is this and
what are its main characteristics?
Choose ALL that apply
Lesson 1.07
Maritime
Polar
Continental
Polar
Maritime
Polar
Maritime
Tropical
Maritime
Tropical
Continental
Tropical
Maritime
Tropical
forms over warm water
warm, humid air mass
its a polar air mass
brings rainy or muggy weather
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
The velocity – time graph of an object moving along a straight line is shown in
fig. Find (a) the distance covered and (b) the displacement of the object in time
interval between t = 0 s and t = 10 s
(a) The distance travelled by the object is 100 m.
(b) The displacement of the object in time interval between t = 0 s and t = 10 s is 60 m.
What is the distance covered by the object?(a) The distance travelled by the object is calculated from the total area of the curve.
total distance = area of triangle 1 + area of triangle 2 + area of rectangle.
total distance = (¹/₂ x base x height)₁ + (¹/₂ x base x height)₂ + length x width
total distance = (¹/₂ x 6 s x 20 m/s) + (¹/₂ (8 - 6) 20) + (10 - 0)(10 - 8)
total distance = 60 m + 20 m + 20 m
total distance = 100 m
(b) The displacement of the object in time interval between t = 0 s and t = 10 s is calculated as follows;
displacement = final position - initial position
displacement = (¹/₂ x base x height)₁ + (¹/₂ x base x height)₂ + length x width
displacement = (¹/₂ x 6 s x 20 m/s) + (¹/₂ (8 - 6) (-20)) + (10 - 0)(10 - 8)
displacement = 60 m - 20 m + 20 m = 60 m
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