A 30.00-ml sample of 0.125 M HCOOH is being titrated with 0.175 M NaOH. What is the pH after 5.00 mL of Naol has been added? K of HCOOH 1,810^-4 o 9.74 o 4.26 o 10.78 o 3.22 o I DON'T KNOW YET
Answers
Once 5.00 mL of 0.175 M NaOH is added, the pH of the mixture is 0.0105 mol
How to find the solution?NaOH is a powerful base while HCOOH is a mild acid. The HCOOH solution is diluted with NaOH in this titration, and the process is repeated until all of the HCOOH has reacted with the NaOH to produce the \(\rm HCOO^-\) ion and water.
For this reaction, the chemical equation is balanced as follows:
\(\rm HCOOH + NaOH \rightarrow NaCOOH + H_2O\)
The sole components of the solution before the addition of NaOH are HCOOH and its conjugate base, HCOO-. Now that the solution has become a buffer, we can determine its pH using the Henderson-Hasselbalch equation:
\($ \rm pH = pKa + log\frac{[HCOO^-]}{[HCOOH]}\)
Now let's calculate the number of moles of HCOOH present in the initial 30.00 ml of 0.125 M HCOOH:
moles of HCOOH = volume (in liters) × concentration
moles of HCOOH = 0.030 L × 0.125 mol/L
moles of HCOOH = 0.00375 mol
When we add 5.00 ml of 0.175 M NaOH, the reaction will proceed until all the HCOOH has been neutralized. The number of moles of NaOH added is:
moles of NaOH = volume (in liters) × concentration
moles of NaOH = 0.005 L × 0.175 mol/L
moles of NaOH = 0.000875 mol
moles NaOH = M × V = 0.175 mol/L × 0.005 L = 0.000875 mol
moles of HCOOH remaining = initial moles of HCOOH - moles of NaOH added
moles of HCOOH remaining = 0.00375 mol - 0.000875 mol
moles of HCOOH remaining = 0.002875 mol
moles HCOOH = initial moles HCOOH - moles NaOH added = 0.00375 mol - 0.000875 mol = 0.002875 mol
We can use the remaining moles of HCOOH to calculate the concentration of HCOOH at this point:
the concentration of HCOOH = moles of HCOOH remaining / volume (in litres)
concentration of HCOOH = 0.002875 mol / 0.030 L
concentration of HCOOH = 0.0958 mol/L
The Ka expression for this reaction is:
\($ \rm Ka =\frac { [H3O+][HCOO-] }{ [HCOOH]}\)
\(\rm [H3O^+]\) = concentration of NaOH added
\(\rm [H3O^+]\) = 0.000875 mol / 0.035 L
\(\rm [H3O^+] = 0.025 mol/L\)
Substituting this into the Ka expression, we get:
\($ \rm 1.81 \times 10^{-4} = \frac{(0.025 \times [HCOO^-]) }{0.0958}\)
Solving for \(\rm [HCOO^-]\), we get:
\(\rm [HCOO^-] = 0.0105 mol\)
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Related Questions
observe how scientists reconstructed the breakup of pangea compare this to a picture of the Pangea record similarites and differences
Answers
Answer: Your answer needs to be more clear
Explanation:
40 POINTS!! AND IF YOU DONT GET IT RIGHT IMMA REPORT YOU AND PLEASE HELP ME
Once upon a time, a mother duckling sat on her eggs with great impatience. How long would it be before they hatched? Finally, one summer day, the mother duckling watched as the eggs cracked, and her cute, yellow ducklings waddled into the world. She was filled with joy until she noticed that one egg, which was larger than all of the others, remained. After many hours, the egg cracked. A large, gray duckling emerged. The mother duck was horrified at the duckling's appearance. The mother duck's only comfort was that the ugly duckling could swim and dive under the water.
As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him.
One day, the ugly duckling decided to run far away and find a place where the animals would look past his appearance and be kind and friendly. He came to a pond and sighted three beautiful swans. Their white feathers, long necks, and kind eyes made them look like royalty. The ugly duckling sighed in disappointment. He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged.
Read the fairy tale The Princess and the Pea.
Once upon a time, there was a handsome prince. The prince lived with his mother and father in a luxurious castle that overlooked a valley of wildflowers and a distant forest. As the prince grew up, he began to long for a princess. However, the prince wanted to be sure that the princess was a real princess. The queen and king searched far and wide for a real princess, but the prince always found something wrong with the princesses they found.
One evening, there was a terrible storm. The wind howled, thunder shook the stone walls, and lightning filled the dark night sky. Through the pelting of the rain, there came a knock at the door. When the king opened the door, he saw a bedraggled girl, soaked to the skin and covered in mud. He ushered her into the castle so that she could warm herself by the fire.
"Why is a young servant girl like you wandering about on such a ferocious night?" queried the king.
The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering.
The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion.
Bright and early the next morning, the king and queen arrived at the girl's bedchamber. The queen asked the girl how she had slept the night before.
"Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue."
The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit.
How do the authors use similar and different events in each fairy tale to illustrate the theme that people should not be judged based on their appearances? Use complete sentences and evidence from the text to support your answer.
Answers
Answer:
MAIN IDEA
What the authors meant is not to judge people by their looks.
_____________________________________________________________
THE UGLY DUCKLING
The ugly duckling doesn't fit with the other ducklings and grows up, to be a fabulous bird. In the beginning, he is teased because of his looks, in a quote, "As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him."
Near the end, however, it states, "He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged." Throughout the course of the story, the other birds' views change since now they realize how awful they felt for mistreating the ugly duckling.
_____________________________________________________________
THE PRINCESS AND THE PEA
The king and queen didn't believe that she was a princess, so they had her endure the trial of sleeping on twenty mattresses with a pea under the very bottom one. Near the beginning of the story, it states, "The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering. The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion." This is when the king and queen were in doubt that she was a princess.
However later on it stated, "Bright and early the next morning, the king and queen arrived at the girl's bed-chamber. The queen asked the girl how she had slept the night before. "Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue." The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit." As you can see the king and queen believed that she was a princess now because they stated, "Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses."
_____________________________________________________________
CONCLUSION
Both stories focus on how the main character is doubted or mistreated because of how they look, but throughout the stories, the main character proves them wrong.
Explanation:
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Which best describes a neutralization
reaction?
A) a reaction between an acid and a base
B) a reaction between two acids
C) a reaction between a base and a salt
D) a reaction between two salts
Answers
Explanation:
The Answer is a reaction between two acids
write a short notes on solubility product principle and its application?
Answers
the general formula for the alkane series is:
Answers
Answer:
The alkanes comprise a series of compounds that are composed of carbon and hydrogen atoms with single covalent bonds. This group of compounds comprises a homologous series with a general molecular formula of C n H 2 n+2 , where equals any integer.
Explanation:
The general formula for the alkane series is CnH2n+2
General formula for the alkane series:In this formula:
"Cn" shows how many carbon atoms are in the alkane molecule.
"H2n+2" shows the amount of hydrogen atoms in the alkane compound, with "n" being the number of carbon atoms.
Alkanes are a group of hydrocarbons that only have single bonds between their carbon atoms. The formula says that each carbon atom is connected to two hydrogen atoms. And the total number of hydrogen atoms in an alkane molecule is two more than double the number of carbon atoms.
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Why is mtDNA so useful in forensic investigations?
Answers
What Determines a atoms reactivity.
A) How many protons the atom contains
B) How many energy levels the atom contains
C) Whether the atom is metal or nonmetal
D) How many valence electrons the atom contains
Answers
Answer:
The number of electrons in the outermost shell of an atom determines its reactivity. Noble gases have low reactivity because they have full electron shells. Halogens are highly reactive because they readily gain an electron to fill their outermost shell
Explanation:
does that help
a homogeneous mixture with very small particles that do not settle out of the solution; composed of a solute and a solvent, called
Answers
A homogeneous mixture with very small particles that do not settle out of the solution, composed of a solute and a solvent is called a solution.
A solution is a homogeneous mixture where the solute (the substance being dissolved) is evenly distributed throughout the solvent (the substance that dissolves the solute). The particles of the solute are very small and do not settle out, making the solution uniform in composition.
Type of mixture in which the components are evenly distributed throughout the mixture, resulting in a uniform composition is known as homogeneous mixture. This implies that mixture has the same properties and composition throughout and there are also no visible difference between the components.
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PLEASE HELP Will give brainliest and 50 points!! Please give honest answers
Answers
Balance the equation:
For the following reaction, 10,5L. of C,H. reacts with 36.5 g of Cly.
C.H.
+
CI,
a. Which reactant is the limiting reactant?
+
HCI
-)
C.H CI
(C.H.)
b. How much of the excess reagent will remain at the end of the reaction?
Answers
The amount of excess reagent remaining at the end of the reaction is 0.429 mol.
The balanced chemical equation for the given reaction is:
\(C2H_10\) + \(6Cl_2\) → \(2C2H_5Cl\) + 6HCl
The molar mass of
\(C2H_10\) is (2 × 12.01) + (10 × 1.01) = 30.12 g/mol.
The molar mass of Cl2 is
(2 × 35.45) = 70.90 g/mol.
Therefore,10.5 L of \(C_2H_10\) will be equal to = (10.5 × 2.5) = 26.25 mol of \(C_2H_10\).36.5 g of \(C_l_2\) will be equal to = (36.5/70.90) = 0.515 mol of \(C_l_2.\)Now, let's find the limiting reactant.
The stoichiometric ratio between \(C_2H_10\) and \(C_l_2\) is 1:
6.Thus, 1 mol of\(C_2H_10\) will require 6 mol of \(C_l_2\).
As per the given information, there are only 0.515 mol of \(C_l_2\) present, which is not enough to react with 26.25 mol of\(C_2H_10\). Hence, Cl2 is the limiting reactant.
Using the stoichiometric ratio, the amount of\(C_2H_10\) required to react with
0.515 mol of\(C_l_2\) = (1/6) × 0.515 = 0.08583 mol. Thus, the amount of excess \(C_2H_10\) present = (26.25 - 0.08583) = 26.16 mol.
Now, let's calculate the amount of excess \(C_l_2\) that will remain at the end of the reaction. Using the stoichiometric ratio, 1 mol of Cl2 will react with 1/6 mol of \(C_2H_10\). Thus, 0.515 mol of Cl2 will react with
(1/6) × 0.515 = 0.08583 mol of\(C_2H_10\). Hence, 0.515 - 0.08583 = 0.429 mol of\(C_l_2\) will remain at the end of the reaction.
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how many grams of glucose (c6h12o6) are in 4.9 moles of glucose? report your answer to the nearest 1 g.
Answers
The answer is 0.0055 grams of glucose (c6h12o6) are in 4.9 moles of glucose
The formula weight is a quantity calculated in chemistry by multiplying each element's atomic weight (measured in atomic mass units) by the number of atoms it has in the formula, and then adding up the results. Sometimes referred to as equation weights, these relative weights computed from the chemical equation. This is how isotropically weighted averages are used to get the molar mass(of glucose) (average molecular weight). This differs from molecular mass, which is the weight of a single molecule made up of distinct isotopes.
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at what height the acceleration due to gravity of the earth become half ?
Answers
Answer:
Acceleration due to gravity is reduced to half its value on the earth's surface at an altitude of 2.65×106 m
a container contains 5L of nitrogen gas at 25°C. what will be it's volume if the temperature increases by 35°C keeping the pressure constant
Answers
Answer:
5.168 L
Explanation:
Applying Charles Law,
V/T = V'/T'..................... Equation 1
Where V = Initial Volume, T = Initial Temperature in Kelvin, V' = Final Volume, T' = Final Temperature in Kelvin,
Make V' the subject of the equation,
V' = VT'/T................. Equation 2
From the question,
Given: V = 5L, T = 25°C = (25+273) = 298K, T' = 35°C = (35+273) = 308K
Substitute these values into equation 2
V' = (5×308)/298
V' = 5.168 L
Chemistry help needed please
Answers
It should be noted that 8.0 grams of ammonium nitrite must have reacted to produce 2.58 L of nitrogen gas.
How to calculate the valueWe can use the ideal gas law to calculate the number of moles of nitrogen gas produced:
PV = nRT
Solving for n, we get:
n = PV/RT = (97.8 kPa)(2.58 L)/(8.314 J/mol K)(294.15 K)
= 0.125 mol
Since 1 mole of ammonium nitrite produces 1 mole of nitrogen gas, the mass of ammonium nitrite that reacted is:
mass = moles * molar mass = 0.125 mol * 64.01 g/mol
= 8.0 g
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What is the best alternative to safely cooling foods without a blast chiller?
Answers
Moving hot food in a covered pan to a cooler space, such as a storage room, or submerging it in ice water, is another option. Ice can also be used to hasten the cooling process.
Soups can be chilled by submerging them in cold water. This technique aids in a swift and secure drop in food temperature. To make a slush, put some ice in a big container or sink and add some water. After that, put the plate of food to be chilled into the ice bath. bathing in ice water and stirring the food often.Food is stirred with ice paddles, which are plastic containers that have been frozen after being filled with water.using ice as a component (if water is an ingredient).chiller that jars or tumbles.
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Convert 220 grams of CO2 into Moles.
Answers
Answer:
. 44.0 g/mol.
Explanation:
Determine the amount of Boron that is required to make a 10 kg p-type
silicon with majority carrier concentration of 5x018 /cm3. Density of Boron
is 2.46 g/cm3, an atomic mass unit of boron is 10 grams/mol. Distribution
coefficient of born in solid vs. melt in silicon is kd = 0.3.
Answers
Given the mass of silicon (Ms) as 10 kg, the atomic mass unit of boron (Mboron) as 10 g/mol, the density of boron (ρboron) as 2.46 g/cm³, and the majority carrier concentration of silicon (Np) as 5 × 10¹⁸/cm³, we are tasked with finding the boron concentration in silicon (Nb).
To calculate Nb, we can utilize the formula: Nb = (ρboron/Mboron) × (kd/Ms) × Np.
By substituting the given values into the equation, we obtain:
Nb = (2.46 g/cm³ ÷ 10 g/mol) × (0.3 ÷ 10 kg) × 5 × 10¹⁸/cm³.
Simplifying the expression, we find:
Nb = 3.69 × 10¹³/cm³.
Hence, the boron concentration required to produce a 10 kg p-type silicon with a majority carrier concentration of 5 × 10¹⁸/cm³ is 3.69 × 10¹³/cm³.
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What is Cd2+ and F1- together as a formula
Answers
Answer:
i am not sure tho
Explanation:
Cd ²+ + F¹- = CdF2
F fluor is a non metal so he takes the electons that Cd gives so if Vd has to give 2 electrons and F can take only 1, there has to be 2 F atoms so all the electrona can be neutral and in ionisation
How many moles are in 234.4 grams of oxygen
Answers
Answer:
7.325 mol.
Explanation:
use the formula n=m/mr
so that makes:
234.4/16*2
which is 7.325 mol.
a 100.0 ml solution of naoh reaches the equivalence point when 30.22 ml of a 0.0750 m solution of hcl is added from the burette.
Answers
The answer is 0.0026.
Solution:
(V₁) Volume of NaOH = 100 mL
(V₂) Volume of HCl = 30.22 mL
(M₂) molarity of HC = 0.0750 m
(m₁) molarity of NaOH =
By using relation
M₁V₁ = M₂V₂
M₁ = M₂ V₂/V₁
M₁ = 0.0750ML*30.22mL/100 mL
M₁ = 0.0226
Now
molarity of NaOH = mole of NaOH/Volume of NaOH (in L)
mole of NaOH = molarity x volume
= 0.0226 mol/L X 100 X 10⁻³ L
= 0.0026 mol So the mole of NaOH is 0.0026.
When titrating NaOH with HCl using methyl orange as an indicator the endpoint color changes from yellow to red, so add HCl to the burette. This is just for ease of calculation. Put the hydrochloric acid in the burette and the soda solution in the Erlenmeyer flask. Methyl orange is used as an indicator.
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Can someone please help me with the page on the right please
Answers
Rocks, water, air, minerals, forests, wildlife, and soil are all examples of a natural resource. True or false ?
Answers
Answer:true
Explanation:
Answer:
it is definitely true.
Explanation:
water is natural, air is natural, minerals are natural, forests are natural, wildlife is natural and soil is natural, since it is now manmade it has to be natural
how many significant digits are in 38 students
Answers
Answer: 2
Explanation: Every non-zero digit is a significant digit.
Answer:
2 significant figures.
Explanation:
38 contains 2 significant figures.
How many moles are in 7.52 x 1025 atoms of magnesium?
Answers
In 7.52 x 10^25 atoms of magnesium there are approximately 124.92 moles
What is the number of moles in magnesium?To calculate the number of moles from the given number of atoms, you need to divide the number of atoms by Avogadro's number, which is approximately 6.022 × 10^23.
Given that you have 7.52 x 10^25 atoms of magnesium, we can calculate the number of moles as follows:
\(Number\ of\ moles = Number\ of\ atoms / Avogadro's\ number\\Number\ of\ moles = 7.52 * 10^2^5 atoms / 6.022 * 10^2^3 atoms/mol\\Number\ of\ moles = 124.92 moles\)
Therefore, there are approximately 124.92 moles in 7.52 x 10^25 atoms of magnesium.
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4. Why is it important to neutralize an acid spill
before attempting to clean it up?
Answers
Answer:
It the acid easier to handel
which element has high melting point, doesn't conduct electricity, is water soluble but the solution produced conducts electricity
Answers
Answer:
sodium chloride
Explanation:
Sodium chloride is an ionic compound having sodium and chloride ions in its structure. Ionic compounds do not conduct electricity in solid state but they conduct electricity in aqueous solution and in molten state.Hence this property is shown by sodium chloride.
Explanation:
sodium chloride is an ionic compound
Using prior knowledge to forecast what will happen next
Analyzing
Predicting
Inquiring
Communicating
Answers
There are 2 grams of sulfur and 0.45 grams of copper. What is the
percent composition of coppper in the sample.
A. 18.3 %
B. 5.44 %
C. 81.6 %
D. 1.25%
Answers
Answer:
18.3%
Explanation:
Add the numbers together, and then take the number of grams of the substance, in this case copper, not coppper lol. divide the .45 by 2.45 to get 18.3
Atoms contain nuclei with electrons orbiting
Answers
Answer:
please mark brainliest!
Explanation:
Atoms consist of a nucleus made of protons and neutrons orbited by electrons. Quarks came together to form protons and neutrons, and these particles combined into nuclei. This all took place within the first few minutes of the universe's existence, according to CERN.
calculate the mass of HNO3 obtained when 20.0g of KNO3 reacts completely with excess concentrated H2SO4
Answers
The mass of HNO3 obtained is 12.46 g from the given reaction.
The chemical reaction is :
Potassium Nitrate + Sulphuric acid ------> Potassium Bisulphate + Nitric acid.
The above reaction is basically used for the making of nitric acid.
Less than 200 degree celcius the Nitric acid if more than 200 degree celcius then it will form Potassium Sulphate.
Now,
1 mol of KNO3 reacts with1 mol of concentrated H2SO4 to give 1 mol HNO3
Molar Mass of KNO3 = 101.1 g
Molar mass of H2SO4 = 98.07 g
Mass of H2SO4 that can react with 20 g of KNO3 = (20 g* 98.07 g )/ 101.1 g
= 19.4 g
Molar mass of nitric acid= 63.01 g
Hence mass of nitric acid produced by 20 g of KNO3 = (20 g * 63.01 g ) / 101.1 g = 12.46 g
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