The weight of the toluene alone is 17.08 g.
In this experiment, a solid is added to a flask along with toluene, which is insoluble with the solid. The total volume of the solid and liquid combined is measured to be 46.00 mL.
The combined weight of the solid and toluene is 58.88 g. By subtracting the weight of the toluene (58.88 g) from the total weight, we can determine the weight of the solid alone, which is 58.88 g - 32.65 g = 26.23 g.
To find the volume of the toluene, we can subtract the volume of the solid from the total volume. So, 46.00 mL - 26.23 g = 19.77 mL is the volume of the toluene.
Now, using the density of toluene (0.864 g/mL), we can calculate the mass of the toluene. The mass is equal to the density multiplied by the volume: 0.864 g/mL * 19.77 mL = 17.08 g.
Therefore, the weight of the toluene alone is 17.08 g.
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N2(g) + 3H2 (g)→2NH3(g) The reaction rate is measured as 0.032 M NH3/s. Determine the rate of disappearance of N2 and the rate of disappearance H2. Explain how you arrived at your answers.
The rate at which N\(_{2}\) disappears is 0.016 M/s, while the rate at which H\(_{2}\) disappears is 0.0213 M/s.
In the balanced chemical equation N\(_{2}\)(g) + 3 H\(_{2}\) (g) → 2NH\(_{3}\)(g), the stoichiometric coefficients represent the mole ratios between the reactants and products.
Since the reaction rate is given for NH\(_{3}\), we can determine the rates of disappearance of N\(_{2}\) and H\(_{2}\) by comparing their stoichiometric ratios in the reaction.
The stoichiometric ratio between N\(_{2}\) and NH\(_{3}\) is 1:2, meaning for every mole of N\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of N\(_{2}\) is half of the rate of formation of NH\(_{3}\).
Similarly, the stoichiometric ratio between H\(_{2}\) and NH\(_{3}\) is 3:2. This means that for every 3 moles of H\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of H\(_{2}\) is (2/3) times the rate of formation of NH\(_{3}\).
Given the rate of formation of NH\(_{3}\) as 0.032 M/s, the rate of disappearance of N\(_{2}\) would be 0.016 M/s (0.032 M/s ÷ 2), and the rate of disappearance of H\(_{2}\) would be approximately 0.0213 M/s (0.032 M/s × 2/3).
Therefore, the rate of disappearance of N\(_{2}\) is 0.016 M/s, and the rate of disappearance of H\(_{2}\) is 0.0213 M/s.
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what is the
difference between ice
and water vapour.
Answer:
Nothing. I guess ice vapor is a solid and water vapor is a liquid if nothing isn't an option, but that makes no sense.
Explanation:
Count the atoms of each element in this chemical formula: 2NaHCO3
Sodium (Na)=
Hydrogen (H)=
Carbon (C)=
Oxygen (O)=
Answer:
na:2
h:2
c:2
0:6
coefficient and structure of atom helps to identity it.
why are mass and volume not properties of substances
Answer:
Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present. Physical properties can be measured without changing a substance's chemical identity
Explanation:
Answer:
yes this above answer is right
A 1. 00 m long beam of stainless steel with a square 2. 00 cm x 2. 00 cm cross section has a mass of 3. 02 kg. What is it’s density in grams per cubic centimeter?
The density of the given stainless steel is 7.55 g/cm³.
Density is defined as the measure of how much “stuff” is in a given amount of space.
Determine the volume first to get the density , and the volume formula is,
Volume = Area × Thickness
Given,
Area = 2 cm × 2 cm = 4 cm²
Thickness = 100 cm
Substitute the values to get the volume,
Volume = 4 × 100 = 400 cm³
Where,
Density = mass / volume
Let's convert mass from kg to g = 3020 g
Substitute the values to get density,
Density = 3020 g / 400 cm^3
= 7.55 g/cm³
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Good scientists have what characteristics in common?
Answer:
determination or brains
Explanation:
how many moles of gas are contained in 22.41L at 99.85 kpa and 0 degrees c
The number of moles of gas contained in 22.41L at 99.85 kPa and 0 degrees Celsius is (99.85 ˣ 1000 ˣ 22.41 ˣ 0.001) / (8.314 ˣ 273.15) moles.
How many moles of gas are contained in 22.41L at 99.85 kPa and 0°C?To calculate the number of moles of gas contained in 22.41L at 99.85 kPa and 0 degrees Celsius, we can use the ideal gas law equation:
PV = nRTP = pressure (in Pa)V = volume (in m³)n = number of molesR = ideal gas constant (8.314 J/(mol·K))T = temperature (in Kelvin)First, we need to convert the given pressure from kPa to Pa and the temperature from degrees Celsius to Kelvin:
Pressure: 99.85 kPa = 99.85 ˣ 1000 Pa (since 1 kPa = 1000 Pa)
Temperature: 0 degrees Celsius = 0 + 273.15 K
Now we can rearrange the ideal gas law equation to solve for the number of moles (n):
n = (PV) / (RT)Substituting the given values:
n = (99.85 ˣ 1000 Pa ˣ 22.41 L) / (8.314 J/(mol·K) ˣ (0 + 273.15) K)Next, we need to convert the volume from liters to cubic meters:
Volume: 22.41 L = 22.41 ˣ 0.001 m³ (since 1 L = 0.001 m³)Finally, we can calculate the number of moles of gas:
moles of gas = (99.85 ˣ 1000 Pa ˣ 22.41 ˣ 0.001 m³) / (8.314 J/(mol·K) ˣ 273.15 K)Performing the calculation will give you the number of moles of gas contained in 22.41L at 99.85 kPa and 0 degrees Celsius.
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how many moles are in 3.4 x 10^23 molecules of carbon dioxide CO2
In the formula XS04, the symbol X could represent the element*
O (1) AI
O (2) Ar
O (3) Mg
0 (4) Na
The positively charged center in an atom is called as:A. NucleusB. NeutronsC. ProtonsD. Electrons
The positively charged center in an atom is called as Nucleus. It is made up of positively charged protons and neutral sub-atomic particle called as neutrons.
What is meant by protons ?
Every atom has a proton, a subatomic particle, in its nucleus.The particle possesses an electrical charge that is positive and opposite to the electron's.A subatomic particle with a negative charge is an electron. A subatomic particle having a positive charge is called a proton.The strong nuclear force holds protons together in the nucleus of an atom. A particular subatomic particle with no charge is the neutron.Although protons were once thought of as elementary particles, the Standard Model of particle physics now recognizes them as composite particles made up of three valence quarks, and they are grouped alongside neutrons as hadrons.To learn more about protons refer to
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The final electron acceptor in aerobic respiration is....... NAD water oxygen pyruvate O hydrogen . Answer al Question 16 Which of the following processes generate carbon dioxide? Hint There are more than one. Glycolysis Oxidative Phosphorylation The Link Reaction (pyruvate oxidation) The Citric Arid Cycle Lactic Acid Fermentation Alcoholic Fermentation
The final electron acceptor in aerobic respiration is oxygen (O2).The electron transport chain (ETC) in cellular respiration relies on a final electron acceptor to help oxygen get reduced into water. This is why oxygen is considered the final electron acceptor in cellular respiration.
During cellular respiration, glucose is broken down into pyruvate. Pyruvate is then transformed into acetyl CoA and enters the citric acid cycle, where it is oxidized and generates ATP, NADH, and FADH2. The final stage of aerobic respiration involves the electron transport chain, in which electrons from NADH and FADH2 are passed through a series of proteins and coenzymes in the inner mitochondrial membrane, ultimately reducing oxygen to form water.
This process is known as oxidative phosphorylation.In conclusion, the final electron acceptor in aerobic respiration is oxygen (O2), and carbon dioxide is generated in the link reaction (pyruvate oxidation) and the citric acid cycle.
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4.6 x 105
How many significant figures?
Answer:
2
Explanation:
4.6 has two figures. The 10^5 tells us only that it is a very large number, but adds nothing that tells us the number was any more accurately measured than what was provided in the 4.6
Chemists can identify the composition of some unknown salts by conducting a flame test. When potassium salts are heated in a flame, a purple color is observed.
This is due to the movement of electrons between energy levels. What is the electron configuration of a potassium atom at ground state?
answer choices
1s2; 2s2; 2p6; 3s2; 3p6; 4d1
1s2; 2s2; 2p6; 3s2;3p6; 3d1
1s2; 2s2; 2d6; 3s2; 3d6; 4s1
1s2; 2s2; 2p6; 3s2; 3p6; 4s1
A potassium atom's ground state electron configuration is 1s2, 2s2, 2p6, 3s2, 3p6, 4s1.
What substance is electronic configuration 1s2 2s2 2p6 3s2 3p6 4s1?An atom's electron configuration is a picture of how electrons are arranged in relation to orbital shells and subshells. Consequently, this is potassium's electron configuration.
How can you express a whole electron configuration in writing?Making Electron Configurations in Writing. Write the energy level (the period) first, then the subshell that needs to be filled, and finally the superscript, which indicates how many electrons are in that subshell. The atomic number, Z, is the sum of all the electrons.
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What is the molecularity of step 1 in the proposed mechanism?Step 1 CI + O3 → CIO + O2 Step 2 CIO + O3 + CI+ 202 A) unimolecularB) bimolecularC) termolecularD) tetramolecularE) Cannot be determined with the given information
The proposed mechanism for this reaction involves two steps:
Step 1: CI + O3 → CIO + O2
Step 2: CIO + O3 + CI+ 202
The molecularity of a step in a reaction mechanism is the number of reactant particles involved in the step.
In step 1, one CI molecule and one O3 molecule collide to form one CIO molecule and one O2 molecule. Therefore, the molecularity of step 1 is (B) bimolecular.
In step 2, three reactant particles (CIO, O3, and CI+) collide to form two product molecules (202). Therefore, the molecularity of step 2 is (C) termolecular.
Overall, the proposed mechanism involves a bimolecular step followed by a termolecular step.
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what is the volume (in l) of a scuba tank if it takes 2000l of air collected at 1.00 atm to fill the tank to a pressure of 150 atm? assume n and t are constant
The volume of the air collected at the pressure of 150 atm is 13.33 litres.
The ideal gas equation says,
The pressure P, the volume V, the number of moles n, the gas constant R and the temperature t of the gas are related with each other as,
PV = nRT
If the number of moles and the temperature are constant,
PV = Constant
So, we can write,
P₁V₁ = P₂V₂
P₁ is the pressure of the scuba tank is 1 atm and the volume V₁ of the scuba tank is 2000L while P₂ is pressure of the other tank is 150 atm. Hence we can write,
2000 x 1 = V₂ x 150
V₂ = 13.33 Liters.
So, the volume of the air is 13.33 litres
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I need help with energy
Answer:
Explanation:
The correct answer is
energy resulting from the flow of charged particles , such as electrons or ions.
hope it helps :)
the property of a star that relates to the amount of energy per unit time it is producing is its a. luminosity. b. volume. c. mass. d. apparent brightness. e. color.
The property of a star that relates to the amount of energy per unit time it is producing is its luminosity. Option a is correct.
Luminosity is the total amount of energy emitted by a star per unit time. It is a measure of the star's intrinsic brightness and is independent of its distance from us. Luminosity is usually expressed in units of watts (or solar luminosities), and is determined by the star's temperature, size, and composition.
Apparent brightness, on the other hand, is the amount of light received per unit area per unit time from a star and is dependent on both the star's luminosity and its distance from us. Apparent brightness is usually expressed in units of watts per square meter (or magnitude), and is determined by the star's luminosity and its distance from us.
Therefore, the property of a star that relates to the amount of energy per unit time it is producing is its luminosity. Hence Option a is correct.
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calculate the volume of a 3.0 mol of oxygen, b 50.0g of hydrogen cloride gas at STP(molar volume of gas is 22.4dm³,molar mass of Hcl=36.5g)
Answer:
98L is the volume of the gas
Explanation:
To solve this question we need to find the moles of O2 + moles HCl. With these moles and PV = nRT we can find the volume as follows:
Moles O2: 3.0mol
Moles HCl:
50.0g * (1mol/36.5g) = 1.37 moles HCl
Total moles:
3.0mol O2 + 1.37 mol HCl = 4.37 moles
PV = nRT
V = nRT/P
Where V is volume in L, n are moles = 4.37mol, R is gas constant = 0.082atmL/molK, T is absolute temperature = 273.15K at STP, P = 1atm at STP
V = 4.37mol*0.082atmL/molK*273.15K / 1atm
V = 98L is the volume of the gas
100.0 kmoles/day of a feed that is 10 mole % ethane, 35 mole % n-pentane and 55 mole % n-heptane is fed to a flash drum. The drum pressure is 1,000 kPa and the drum temperature is 120 °C. Find V/F, x, and y. Use De Priester chart.
To find the values of V/F, x, and y for the given feed composition in the flash drum, we can use the De Priester chart. The De Priester chart is a graphical representation of the vapor-liquid equilibrium (VLE) for hydrocarbon mixtures.
Determine the critical properties of each component:
The critical properties required for using the De Priester chart are critical temperature (Tc) and critical pressure (Pc) for each component. The critical properties of ethane (C2), n-pentane (C5), and n-heptane (C7) can be obtained from appropriate references or data tables.
Calculate the reduced properties:
The reduced properties are calculated using the following equations:
Tr = T / Tc
Pr = P / Pc
where T is the temperature in Kelvin, P is the pressure in Pascal, and Tc and Pc are the critical temperature and pressure of the component, respectively.
Locate the reduced temperature (Tr) on the De Priester chart:
On the De Priester chart, locate the reduced temperature (Tr) along the x-axis.
Determine the vapor and liquid compositions:
Using the feed composition and the De Priester chart, find the corresponding points on the chart for each component. Interpolate between the nearest points if necessary.
Calculate V/F, x, and y:
V/F (vapor-to-liquid flow ratio) is the ratio of the vapor flow rate (V) to the liquid flow rate (F). It can be calculated as:
V/F = y / (1 - y)
where y is the mole fraction of the more volatile component in the vapor phase.
The liquid phase mole fraction (x) is the feed composition.
The vapor phase mole fraction (y) can be calculated using the following equation:
y = (V / F) * x
Substitute the values obtained from the De Priester chart into the equations to calculate V/F, x, and y for the given feed composition in the flash drum.
Note: Ensure that the pressures and temperatures are converted to the appropriate units (e.g., temperature in Kelvin and pressure in Pascal) before using the De Priester chart.
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HELP ASAP plz!:) I’ll give brainliest
Answer:
it is closer to the south pole
Explanation:
what type of reaction is Au2S+H2---> 2Au+H2S
Answer:
single replacement reaction is type of reaction is Au2S+H2---> 2Au+H2S.
determine the ph at the half-equivalent point during the titration of 100.0 ml of 0.295 m hf with 50.0 ml of 0.295 m naoh. ka = 6.8x10-4 enter ph to 2 decimal places.
The question asks to determine the pH at the half-equivalent point during the titration of 100.0 ml of 0.295 M HF with 50.0 ml of 0.295 M NaOH. The given Ka value is 6.8x10^-4. We need to find the pH at the point where half of the HF has reacted with NaOH.
To solve this problem, we need to use the Henderson-Hasselbalch equation, which is given by:
pH = pKa + log([A-]/[HA])
In this equation, [A-] represents the concentration of the conjugate base (F-) and [HA] represents the concentration of the acid (HF). At the half-equivalent point, the moles of HF reacted will be equal to the moles of NaOH added.
First, we need to calculate the moles of HF and NaOH. Moles can be calculated using the formula:
moles = concentration (M) * volume (L)
For HF:
moles of HF = 0.295 M * 0.100 L = 0.0295 mol
For NaOH:
moles of NaOH = 0.295 M * 0.050 L = 0.01475 mol
Since the reaction between HF and NaOH is 1:1, the moles of HF reacted at the half-equivalent point will be half of the initial moles of HF:
moles of HF reacted = 0.0295 mol / 2 = 0.01475 mol
Now, we can calculate the concentration of F- and HF at the half-equivalent point using the balanced chemical equation:
At the half-equivalent point, moles of F- will be equal to moles of HF reacted, which is 0.01475 mol.
Concentration of F- = moles of F- / total volume (L)
Concentration of F- = 0.01475 mol / (0.100 L + 0.050 L) = 0.0983 M
Concentration of HF at the half-equivalent point will be the initial concentration minus the concentration of F-:
Concentration of HF = 0.295 M - 0.0983 M = 0.1967 M
pH = -log(6.8x10^-4) + log(0.5)
pH = -(-3.17) + log(0.5)
pH = 3.17 + (-0.30)
pH = 2.87
Therefore, the pH at the half-equivalent point is 2.87 (rounded to 2 decimal places).
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Ello fellers
A chemical change is also known as a:
1.endothermic reaction
2.exothermic reaction
3.solution
4.chemical reaction
Convert each of the following masses to the units requested
A. 500 liter to deciliters
B. 4200 km to hm
The diagram shows a cross section of a thermos the vacuum between the outer and inner bottles is a space containing no air of other matter
Answer:
which diagram are you talking about?
The answer is
It prevents particles from transferring thermal energy between the outer and inner bottles
Does anybody know how to find the theoretical yield? you can just do 1 equation
Answer:
its the first part in mass of sodium
Explanation:
:)
Which kind of thermal energy transfer warms your hand when you hold a hot
mug of tea?
A. Radiation
B. Convection
C. Conduction
D.Translation
\(\huge \boxed{\sf C}\)
Conduction: Heat transfers into hands when holding a hot cup of coffee. Heat energy is transferred between or inside substances by conduction. We can use any media for conduction, but physical media is required.
The kind of thermal energy transfer that warms your hand when you hold a hot mug of tea is called conduction. The correct option is C.
What is conduction?Direct contact between molecules inside a substance allows for the transfer of energy, typically in the form of heat and/or electricity. Conduction can occur in gases, liquids, and solids.
Conduction heat transfer primarily takes place in stationary mediums, including solids or fluids that are at rest.
When holding a hot cup of coffee, heat is transferred to the hands. Conduction is the method of transferring heat energy inside or between materials. Any medium can be used for conduction, although physical mediums are necessary.
Therefore, the correct option is C. Conduction is correct for the process mentioned above.
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Calculate the energy in joules of a wave particles with a wave length of 6.5×10^6 nm (infrared region)
Answer:
The energy of the wave particle is 3.058 x 10⁻²³ J.
Explanation:
Given;
wavelength of the wave particle, λ = 6.5 x 10⁶ nm = (6.5 x 10⁶) x 10⁻⁹ m
The energy of the wave particle is calculated as;
\(E = hf\\\\E = \frac{hc}{\lambda}\)
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/Hz
c is speed of light = 3 x 10⁸ m/s
\(E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{6.5 \times 10^6 \times 10^{-9}} \\\\E = 3.058 \times 10^{-23} \ J\)
Therefore, the energy of the wave particle is 3.058 x 10⁻²³ J.
What is the mass of an object accelerating at 10 m/s2 when a force of 10 N is applied?
a
100 kg
b
0 kg
c
20 kg
d
1 kg
Answer:
Mass of object = 1 kg
Explanation:
Given:
Acceleration = 10 m/s²
Force applied = 10 N
Find:
Mass of object
Computation:
Mass = Force / Acceleration
Mass of object = 10 / 10
Mass of object = 1 kg
when svante arrhenius first proposed his acid-base theory, he was a doctoral candidate. his professors thought his ideas were unfounded. within a decade, the arrhenius theory of acid-base was widely accepted and praised within the scientific world. arrhenius defined acids as compounds having ionizable hydrogen and bases as compounds with ionizable
Svante Arrhenius, as a doctoral candidate, proposed the acid-base theory, which initially faced skepticism from his professors who thought his ideas were unfounded. However, within a decade, the Arrhenius theory was widely accepted and praised in the scientific world. In his theory, Arrhenius defined acids as compounds having ionizable hydrogen, and bases as compounds with ionizable hydroxide ions (OH-).
Arrhenius proposed his theory of acids and bases in 1884 as part of his doctoral thesis. At the time, his ideas were met with skepticism and criticism from his professors and peers, who were more accustomed to the older, classical theories of acids and bases.
However, Arrhenius's theory was eventually accepted and became widely praised within the scientific community. This was in part due to the experimental evidence that supported his theory and the way that it could be used to explain a wide range of chemical phenomena.
In Arrhenius's theory, an acid is a substance that dissociates in water to produce hydrogen ions (H+), while a base is a substance that dissociates in water to produce hydroxide ions (OH-). This theory provided a new and more comprehensive understanding of the behavior of acids and bases and laid the foundation for further research in this area.
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