A 400 kg mass is moving in a circular path with a constant angularspeed of 5.00 rad/sec and with a linear speed of 5.00 m/sec. Themagnitude of the radial force on the mass is?

Answer:

time

Explanation:

First would be the yellow thing to go up next will be the spoons hanging or whatever that is then will be the ball and the car and the thing that’s next to the dog and last will be the thing that throws to treat. Sorry I don’t know what they’re called. You just have to do an obstacle for the dog to receive the treat.

The value of the angle for which the value of the resultant force is parallel to b-b is 6.35°. Therefore, the correct option is A.

An angle can be defined as the figure that is formed when two rays or lines shares a common endpoint.

Let the x and y-axis be shown here. If the resultant is directed along the x-axis, then its component in the y direction is zero.

0 = ΣFy = 300 sin θ + 300 sin (40 + θ) – 500 sin 30°

Therefore,  sin θ+ sin (40+ θ)= 500 sin 30°÷ 300

⇒ sin θ + sin (40 + θ) = 0.833

⇒ 2 sin (40 + θ + θ)÷ 2 × cos 40 + θ—θ) ÷ 2 = 0.833

⇒ 2 sin (20 + θ) × cos (20) = 0.833

⇒ θ = 6.35°

Hence, the value of angle is 6.35°. Therefore, the correct option is A.

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The question is incomplete, but most probably the complete question is,

Three forces acting at a point are shown in Fig. The direction of the 300 N forces may vary, but the angle between them is always 40°. Determine the value of θ for which the resultant of the three forces is directed parallel to b-b.

A. 6.35°

B. 6.00°

C. 7.40°

D. 4.81°

Answer:

a spring scale

Explanation:

i think it is correct

If a 5kg mass starts from rest at xo = -1 and moves under the action of a variable force F(x) = √1-x² to point xf = 1. Then the total work done by the force is equal to π/2 + 1.

To calculate the total work done by the force in this scenario, we can use the formula for work:

Work = ∫F(x) dx

where F(x) is the force as a function of position and dx represents an infinitesimal displacement.

In this case, the force is given by F(x) = √(1 - x²), and we need to find the total work done as the object moves from xo = -1 to xf = 1.

Let's break down the calculation step by step:

Write the integral for work:

Work = ∫F(x) dx

Substitute the given force:

Work = ∫√(1 - x²) dx

Integrate with respect to x:

To integrate the square root of (1 - x²), we use the trigonometric substitution. Let's substitute x = sin(θ) and dx = cos(θ) dθ.

Work = ∫√(1 - sin²(θ)) cos(θ) dθ

Simplify the integrand:

Using the trigonometric identity sin²(θ) + cos²(θ) = 1, we can rewrite the integrand as cos²(θ).

Work = ∫cos²(θ) dθ

Apply the power-reducing formula:

The power-reducing formula states that cos²(θ) = (1 + cos(2θ)) / 2. We can use this formula to simplify the integrand further.

Work = ∫(1 + cos(2θ))/2 dθ

Integrate the terms separately:

Work = (1/2) ∫dθ + (1/2) ∫cos(2θ) dθ

The first integral, ∫dθ, is simply θ, and the second integral, ∫cos(2θ) dθ, can be calculated as sin(2θ)/2.

Work = (1/2) θ + (1/2) (sin(2θ)/2) + C

Evaluate the integral limits:

To find the total work done, we need to evaluate the integral at the upper and lower limits of integration.

At xf = 1, the angle θ is π/2, and at xo = -1, the angle θ is -π/2.

Work = (1/2) (π/2) + (1/2) (sin(2(π/2))/2) - [(1/2) (-π/2) + (1/2) (sin(2(-π/2))/2)]

Simplifying further:

Work = π/4 + (1/2) - (-π/4 + (1/2))

Work = π/4 + 1/2 + π/4 + 1/2

Work = π/2 + 1

Therefore, the total work done by the force is equal to π/2 + 1.

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Answer:

The speed of the mouse is 10 m/s

Explanation:

Given;

speed of the cat, u = 8 m/s

let the mass of the cat = m

then, mass of the mouse, = m / 10

let the speed of the mouse = v

Let the kinetic energy of the mouse = K.E

When the cat speeds up by 2 m/s, its new speed = 10 m/s,

then its kinetic energy is given as;

¹/₂m(10)² = 10K.E

\(50 m = 10[\frac{1}{2} *\frac{m}{10}.v^2]\)

50 = ¹/₂v²

v² = 100

v = √100

v = 10 m/s

Therefore, the speed of the mouse is 10 m/s

Answer:

.....when there is a continuous path for electricity....

^_^ Pls mark my answer as brainliest ^_^

Answer:

Table C:

Fan Speed Observations of Position vs. Time Graphs

Low:

The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.

Medium:

The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.

High:

The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.

Explanation:

hope it helps

Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.

Materials:

Smooth, inclined plane

Cart or tiny wheeled object

Stopwatches and timers

Measuring tape or meterstick

Procedure:

Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.

Place the cart or small wheeled object at the bottom of the inclined plane.

Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.

Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.

As soon as the cart is freed and begins to move, start the stopwatch or timer.

Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.

Determine the time intervals (Δt) between each position for velocity analysis

Data:

Position (m) Time (s) Time Interval (Δt) (s)

0.0                   0.00           -

0.5                   0.50        0.50

1.0                   0.75        0.25

1.5                    1.10              0.35

2.0                    1.50        0.40

Analysis:

Calculate the average velocity between each position by dividing the position change by the time interval (x/t).

Create a graph that plots average velocity (V_avg) versus time (t).

Results:

A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.

Conclusion:

The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.

Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.

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Answer:

inonic bond has greatest difference in electronegativiru

The type of bond that has elements with the greatest difference in electronegativity ionic bond. The correct option is is B.

Electronegativity is a chemical property that describes an atom's or functional group's tendency to attract electrons toward itself.

An atom's electronegativity is affected by both its atomic number and the distance between its valence electrons and the charged nuclei.

Electronegativity is a measurement of an atom's proclivity to attract electrons (or electron density) towards itself.

It governs the distribution of shared electrons between two atoms in a bond. The greater an atom's electronegativity, the more strongly it attracts electrons in its bonds.

Ionic bonds are formed by elements with large differences in electronegativity. Covalent bonds are formed between atoms of elements with similar electronegativity.

Thus, the correct option is B.

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Answer:

Below

Explanation:

0-1 sec descends at constant rate from 10 to 6 m

1-2 sec stops at 6m

2-3 sec descends at constant rate to 2 m

3-4 sec stops at 2 m

4-5 sec descends at another constant rate to 0 m

Answer:

Q = 636.48 J

Explanation:

Given that,

The mass of gold, m = 0.052 kg

The temperature increase from 30°C to 120°C.

The specific heat of gold is 136  J/kg °C.

We need to find the heat needed to warm the gold. The formula for heat needed is given by :

\(Q=mc\Delta T\\\\Q=0.052\times 136\times (120-30)\\\\Q=636.48\ J\)

So, 636.48 J of heat is needed to warm gold.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 50 × 0.85

We have the final answer as

Hope this helps you

a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while  b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.

a. Isothermal compression:

For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Since the process is isothermal, we can write:

\(P_1V_1 = P_2V_2\)

where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.

We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:

\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)

To find the final temperature, we can use the ideal gas law again:

PV = nRT

Rearranging, we get:

T = PV/(nR)

Substituting the values we know, we get:

T = (\(1.5*10^5\)Pa)(V1)/(nR)

Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:

T2 = T1 = 293 K

b. Adiabatic compression:

For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:

PV^γ = constant

where γ = Cp/Cv is the ratio of specific heats.

Since the process is adiabatic and reversible, we can write:

\(P_1V_1\)^γ = \(P_2V_2\)^γ

We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:

\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)

To find the final temperature, we can use the adiabatic equation again:

\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K

Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.

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Answer:

Time, t = 4.08 secs

Explanation:

Given the following data;

Initial velocity, U = 40m/s

To find the time, we would use the first equation of motion;

\( V = U + at\)

Where;

Making time, t the subject of formula, we have;

\( t = \frac{V - U}{a}\)

We know that acceleration due to gravity, g is 9.8m/s².

a = g = - 9.8m/s² because the ball is thrown in the opposite direction.  

Also, the final velocity is equal to zero (0) because the ball reached its maximum height.

Substituting into the equation, we have;

\( t = \frac{0 - 40}{-9.8}\)

\( t = \frac{-40}{-9.8}\)

Time, t = 4.08 secs

Therefore, it will take the ball 4.08 seconds to reach the top.

The glycerin index predicts the way certain foods affect​ the blood glucose.

The glycemic index is a numerical scale that ranks carbohydrates in foods based on how they affect blood glucose levels compared to a reference food, typically pure glucose  or white bread. Foods with a high glycerin index cause rapid increase in blood sugar levels, while foods with a low glycerin index result in a slower and more gradual increase.

The glycerin index is often used as a tool for managing blood sugar levels, particularly in individuals with diabetes. Foods with a lower glycerin index are generally considered healthier as they provide more sustained energy and have a lesser impact on blood sugar levels.

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

where u put it last time or retrace ur steps to where u last put it

Answer:

200 meters per second

Explanation:

wave speed = wavelength x frequency

2 meters x 100 hertz = 200 meters per second

The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

The acceleration of the box is calculated as follows;

vf² = vi² + 2as

a = (vf² - vi²)/2s

a = (11.5² - 13²) / (2 x 8.5)

a = -2.16 m/s²

The time taken for the box to travel is calculated as follows;

a = (vf - vi)/t

t = (vf - vi) / a

t = (11.5 - 13) / (-2.16)

t = 0.69 s

P = Fv

P = (ma)(vf - vi)

P = (1 x -2.16) x (11.5 - 13)

P = 3.24 W

Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

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The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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The work done by gravity on the sliding crate is 176.6 J.

The work done by gravity on the sliding crate is calculated by applying the following formula.

W = Fd cosθ

W = mg x d cosθ

where;

W = ( 14 kg x 9.8 m/s² ) x ( 1.61 m ) x cos ( 36.9 )

W = 176.6 J

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Explanation:

Free Solutions to GR BATHLA & SONS BIOLOGY (HINGLISH) Class 12 book Chapters, Questions, Answers and Solutions 2022

Given

An object that has balanced forces acting upon it has zero acceleration.

To find

Is the statement true or false

Explanation

When a balanced force is acting on a object its net force is zero.

So there is no acceleration of the object.

Conclusion

The statement is True

Answer:10.0001 km/hr

Explanation:v=s/t

15km =15000ms

1.5hr =5400s

V=15000m/5400s

V =2.778m/s

2.778m/s =10.0001 km/hr

His speed was 10 km/hr

From the question, we are to determine Antonio's speed,

From the formula,

\(Speed = \frac{Distance}{Time}\)

From the given information,

Distance = 15 km

Time = 1.5 hours

\(Speed = \frac{15}{1.5}\)

Speed = 10 km/hr

Hence, his speed was 10 km/hr

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Answer:

The apple fell at a distance of 4.17 m.

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

When a net force is applied to the body or a system and this produces displacement, then that force is said to perform mechanical work.

In the International System of Units, work is measured in Joule. Joule is equivalent to Newton per meter.  

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves.  

Work=Force*distance* cosine(angle)

On the other hand, Newton's second law says that the acceleration of a body is proportional to the resultant of forces on it acting and inversely proportional to its mass. This is represented by:

F=m*a

where F is Force [N], m is Mass [kg] and a Acceleration [m / s²]

In this case, the acceleration corresponds to the acceleration of gravity, whose value is 9.81 m / s². So you have:

Replacing:

9 J= 2.1582 N* distante* 1

Solving:

\(distance=\frac{9J}{2.1582 N*1}\)

distance= 4.17 m

The apple fell at a distance of 4.17 m.

Answer:

A.The tortoise is moving at a constant speed

Explanation:

The chart shows the tortoise covering a distance of 0.5 meters every 60.0 seconds. Since this rate of motion is not changing, the tortoise is moving at a constant speed.

The diagram shows the tortoise moving at a constant speed. Thus the correct option is option A.

Speed is defined as how far the object travels. It is also defined as the rate of change of distance per unit of time. Speed is the scalar quantity and the unit of speed is m/s.

Speed is denoted by the letter v. v = s/t, where s is the distance traveled along the path and t is the time taken by the object to move along the path.   The SI unit of distance is meter and the unit of time is seconds.

When the object covers an equal distance at equal intervals of time is called uniform speed. When the object covers unequal distance with equal intervals of time or equal distance with unequal intervals of time is called Non-uniform speed.

The graph shows the Tortoise covers 0.5 m in 60 seconds is called uniform speed. Thus, option A is correct.

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Answer:

A. 1.

B. 5.

C. 3.

D. 4.

E. 6.

F. 4.

Explanation:

Answer: \(1.64 m/s^{2}\) (3 sig figs)

              \(1.6 m/s^{2}\) (2 sig figs)

Explanation:

First we need to find the weight of the cat using F=ma (117.72 = 12 * 9.81)

Using 117.72 we can find the force of friction by doing F = μ * N (35.316 = 0.3 * 117.72)

After we find the friction force we simply subtract the friction force from the applied force (19.684 = 55 - 35.316)

Using 19.684 we can find the acceleration using F / m = a (19.684 / 12 = 1.64)

From there you reduce your answer to the number of sig figs, which I think is 2 unless otherwise specified.