A 4.5 L sample of a gas was collected over water on a day when the temperature was 24◦C and the barometric pressure was 706 torr. The dry sample of gas had a mass of 5.6 grams. What is the mass of three moles of the dry gas? At 24◦C the vapor pressure of water is 22 torr. Answer in units of g

Answer: 2.96 × 10-4 this is the scientific noatation of 0.000296

Explanation:

Answer:

Basically a muscle is tissue but sometimes they are also called organ

So the answer should be D...a tissue

The muscle in Lane's arm would best be described as a tissue. Option D is correct.

The tissues in the body of an organism are made up of a group of cells that work as a building block for tissues to build up and after that these tissues make a group of them to develop the organs in the body.

Muscles are the form of tissues only which can be of different types too. These can be tears which can cause major injuries in the body as they help the body for the movement of the body.

A collection of cells with similar structures and functions is referred to as a tissue. The intercellular matrix, a nonliving substance, fills the spaces between the cells. There might be a lot of this in some tissues and not much in others.

Therefore, Option D is correct. The muscle in Lane's arm would best be described as a tissue.

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Answer:

1.53 * 10^-3 moles of H20

Explanation:

I see that you're using the factor-label method, so if you want to convert a number into another number, let's start with the first number.

We have 9.20 * 10^20 molecules of water.

6.02 * 10^23 particles or molecules of water is 1 mole

If we want moles, we can write it like this

9.20 * 10^20 molecules of H20 | 1 mole of H20                            

                                                    | 6.02 * 10^23 molecules of H20

= 1.53 * 10^-3 moles of H20

The two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

A chemical compound is a substance made of numerous similar molecules (or molecular entities) joined by chemical bonds and comprising atoms from various chemical elements. Therefore, a molecule made up of only one type of atom is not a compound. Chemical reactions, which may entail interactions with other molecules, can change a compound into a distinct substance. Atomic bonds may be broken or new ones created during this process.

sample 1 = mass of lead / mass of oxygen = 12.92g/2g = 6.46 .

sample 2 = mass of lead/ mass of oxygen = 34.27 - 14.39/14.39 = 1.38 .

so, the ratios are not the same.

Hence, the two chemical compounds are not the same, because their ratio is not equal. In both samples the composition of lead and oxygen is different.

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Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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Answer:

D.) NaOH

Explanation:

Sodium always forms the cation, Na⁺.

Hydroxide is always written as OH⁻.

The compound should have an overall charge of 0 (be neutral). As you can see, the charges perfectly balance out (+1 + (-1) = 0). Therefore, there only needs to be one atom of each ion. The ionic compound is thus NaOH.

Answer:

\(Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)\)

Explanation:

Hello!

In this case, since writing the net ionic equation implies the complete molecular equation, we should start by:

\(Zn(s)+2HBr(aq)\rightarrow ZnBr_2(aq)+H_2(g)\)

Next, we represent the ionization of the aqueous species:

\(Zn(s)+2H^+(aq)+2Br^-(aq)\rightarrow Zn^{2+}(aq)+2Br^-(aq)+H_2(g)\)

Whereas the spectator ions, those at both reactants and products are cancelled out so the net ionic equation is obtained:

\(Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)\)

Best regards!

Based on the information, we can infer that the red line is about 3.9 cm.

To identify the measure of the red line we must look at the metric rule at the bottom. As we can see, this demarcates the centimeters and the millimeters. Based on the information, we can infer that the answer is 3.9 cm since the line extends to the line that delimits this value.

Based on the above, we can infer that the red line measures about 3.9 cm, taking the ruler as a reference.

Note: This question is incomplete. Here is the complete information:

Attached image

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The half-reaction is; H₂ → 2H⁺ + 2e⁻, the oxidizing agent is chlorine , and the reducing agent is hydrogen. The oxidation half-reaction is where a species loses electrons, the reduction half-reaction is where a species gains electrons, the oxidizing agent is the species that causes another species to be oxidized by accepting electrons itself, and the reducing agent is the species that causes another species to be reduced by donating electrons itself.

The oxidation half-reaction is the half-reaction where a species loses electrons. In this reaction, hydrogen (H₂) is oxidized to form hydrogen ions (H⁺). The half-reaction can be written as;

H₂ → 2H⁺ + 2e⁻

The reduction half-reaction is the half-reaction where a species gains electrons. In this reaction, chlorine (Cl₂) is reduced to form chloride ions (Cl⁻). The half-reaction can be written as follows;

Cl₂ + 2e⁻ → 2Cl⁻

The oxidizing agent is the species that causes another species to be oxidized by accepting electrons itself. In this reaction, chlorine (Cl₂) is the oxidizing agent because it accepts electrons from hydrogen (H₂), causing it to be oxidized.

The reducing agent is the species that causes another species to be reduced by donating electrons itself. In this reaction, hydrogen (H₂) is the reducing agent because it donates electrons to chlorine (Cl₂), causing it to be reduced.

Therefore, chlorine is the oxidizing agent, and hydrogen is the reducing agent.

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Answer:

81.59%

Explanation:

First we convert 107.50 g of NH₃ into moles, using its molar mass:

Now we calculate how many moles of NO would have been formed by the complete reaction of 6.32 moles of NH₃:

Then we convert 6.32 moles of NO to grams, using its molar mass:

Finally we calculate the percent yield:

Answer:

CH3CH2CH2COOH<CH2(F)CH2CH2COOH<CH3CH(F)CH2COOH<CH2(F)CH(F)CH2COOH

Explanation:

We know that the presence of highly electronegative elements in carboxylic acid molecules lead to -I inductive effect. This implies that electrons are withdrawn along the chain towards the electronegative element. As electrons are withdrawn towards the electronegative element, the electron cloud of the carbonyl- hydrogen bond in the acid weakens and the hydrogen can now be easily lost as a proton, that is , the molecule becomes more acidic.

The -I inductive effect increases with increase in the number of electronegative elements present in the molecule and the proximity of the electronegative element to the carbonyl group. The closer the electronegative element is to the carbonyl group, the greater the acidity of the molecule since the -I inductive effect dies out with increasing distance from the carbonyl group. Also, the more the number of electronegative elements in the molecule, the greater the - I inductive effect and the greater the acidity of the molecule, hence the answer.

To determine the volume of water, we need to account for the density of water, which changes with temperature. However, at 25.4°C, the density of water is close enough to 1 g/mL for practical purposes. Therefore, we can approximate the volume of water to be the same as its mass.

Given:

Mass of water = 19.5487 g

Volume of water = Mass of water

Therefore, the volume of water is approximately 19.5487 mL.

A Plate Boundaries and Movement Lab Report is a report that shows the records of all the data relating to the movement of Plate Boundaries and their movements.

A tectonic plate is also described or referred to as a Lithosperic Plate. In Geography, it is described as a slab of rock that is not shaped regularly.

In most cases, it comprises continental and oceanic lithosphere.

Plate Boundaries and their movement are largely linked to volcanic activities and earthquakes. This means that they can be used to predict when any of the above-mentioned events may happen.

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Hi there!

Let me know if you have questions about my answer:

6.15 × 10²⁴

Explanation:

To find the number of atoms, divide the mass of calcium (m) by its molar mass (MM). This will give you the number of moles of calcium (n).

\(n = m/MM\)            Start with a formula

\(=\frac{41.0g}{40.08g/mol}\)             Substitute values from the question

\(= \frac{41.0g*1mol}{40.08g}\)             Simplify

\(= \frac{41.0mol}{40.08}\)                 Cancel out the units "g"

\(= 1.022...mol\)          Number of moles of calcium, with 4 significant figures

Then, multiply the number of moles of calcium (n) by Avogadro's number (\(N_{A}\)) to find the number of calcium atoms.

\(Number.of.Ca=n*N_{A}\)      Start with a formula

\(= 1.022mol*\frac{6.022*10^{23}Ca}{1mol}\)      Substitute values from the question

\(= \frac{1.022mol*6.022*10^{23}Ca}{1mol}\)           Simplify

\(= 1.022*(6.022*10^{23}Ca)\)     Cancel out the units "mol"

\(= 6.154*10^{24} Ca\)                   Multiply, leave one extra digit to help round. "4" tells you to round down.

\(= 6.15*10^{24} Ca\)                     Final answer to 3 significant figures*

*When multiplying and dividing numbers, your final answer will have the same number of significant figures as the number with the least number of significant figures in the question.

40.08 has 4 significant figures. 41.0 has 3 significant figures. So, you want 3 significant figures in your final answer.

I hope this helps!

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Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles\)  

\(2K+2H_2O\rightarrow 2KOH+H_2\)  

According to stoichiometry :

2 moles of \(K\) produce = 2 moles of \(KOH\)

Thus 0.57 moles of \(K\) will produce=\(\frac{2}{2}\times 0.57=0.57moles\)  of \(KOH\)

Mass of \(KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g\)

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

Answer:

The person above me is correct  

Explanation:

It's D

The following are categorized into polar or nonpolar molecules:

a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.

b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.

d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.

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Strong electrolyte: lead(II) chloride weak electrolyte trimethylamine Strong electrolyte: cesium hydroxide sulphide of hydrogen: a weak electrolyte, strong electrolyte chromium chloride Weak electrolyte: nickel(II) acetate

Response and justification The fact that acetic acid has a low dissociation constant suggests that it is a weak acid. Acetic acid's restricted ability to ionise in an aqueous solution is a result of its low dissociation constant. With this in mind, acetic acid can be regarded as a weak electrolyte.

Phosphoric acid is a useful electrolyte because of its low volatility, strong ionic conductivity, stability at high temperatures, carbon dioxide and carbon monoxide tolerance, and low flammability.

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Answer: D. Intensity

Explanation: Intensity is correct, because if you originally were working on a treadmill with a speed of 8, that is how much intensity your putting your body on. And if you put the speed for a treadmill at 11 to increase your exercise, you are increasing the speed you have to run, making it more intense. The more intense you make your workout or training, the more stressful exercise you are doing.

Hope this helps,

:)

Answer:

Exothermic Reaction

Product  = Calcium hydroxide + hydrogen

Explanation:

Answer:

BBBBBBBB ITS B

Explanation:

Answer:

What is the question?

Explanation:

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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Answer:

1.03

Explanation:

18.4 × 10^(24) water molecules are contained in a 0.50L bottle of water.

Given,

Density of water = 1.00 g/mL

Volume of water = 0.50L = 500 ml

We can calculate the mass of water.

As we know that,

Density = mass/ volume

By substituting the values, we get

1 = Mass / 500

Mass = 500 g.

Now, we know

Molar mass of water = 18 g

Mass of water = 500g

We will calculate the moles of water

Mole = given mass / molar mass

= 500/18 = 27.7 moles

As we know that,

1 mole = 6.673 × 10^(23) molecules

So, 27.7 moles contain = 6.673 × 27.7 × 10^(23)

= 18.4 × 10^(24) molecules

Thus, we concluded that 18.4 × 10^(24) water molecules are contained in a 0.50L bottle of water.

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Answer:

866.142 inches

Explanation:

By formula