A 46 g domino slides down a 30 degrees incline at a constant speed. What is the coefficient of friction?

Answer:

A) Sue is lifting the bucket by a force of 49.035 newtons.

B) The bucket has an acceleration of 8.207 meters per square second on the Moon.

Explanation:

A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:

\(\Sigma F = F - m\cdot g = 0\) (1)

Where:

\(F\) - Lifting force, measured in newtons.

\(m\) - Mass of the bucket, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:

\(F = m\cdot g\)

\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)

\(F = 49.035\,N\)

Sue is lifting the bucket by a force of 49.035 newtons.

B) By the Second Newton's Law, we have the following model:

\(\Sigma F = F-m\cdot g = m\cdot a\) (2)

Where \(a\) is the net acceleration of the bucket, measured in meters per square second.

If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:

\(a = \frac{F}{m} -g\)

\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)

\(a = 8.207\,\frac{m}{s^{2}}\)

The bucket has an acceleration of 8.207 meters per square second on the Moon.

(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.

(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².

The given parameters;

The force applied by Sue in lifting the bucket at a constant velocity is calculated as;

\(F = m(a + g)\)

\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)

The acceleration of the bucket when lifted on the moon with the calculated force is;

\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)

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Answer:

2.08 m  (2 d.p.)

Explanation:

Constant Acceleration Equations (SUVAT)

\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

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When a body is projected through the air with initial speed (u), at an angle of θ to the horizontal, it will move along a curved path.

Therefore, trigonometry can be used to resolve the body's initial velocity into its vertical and horizontal components:

Since the projectile is modeled as moving only under the influence of gravity, the only acceleration the projectile will experience will be acceleration due to gravity.

If the ball is kicked at an initial velocity of 20 m/s from flat ground at an angle of 45.9° then:

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

\(s=35 \quad u=20 \cos 45.9^{\circ} \quad v = 20 \cos 45.9^{\circ} \quad a=0\)

\(\begin{aligned}\textsf{Using} \quad s&=\left(\dfrac{u+v}{2}\right)t\\\\35&=\left(\dfrac{20 \cos 45.9^{\circ}+20 \cos 45.9^{\circ}}{2}\right)t\\35&=(20 \cos 45.9^{\circ})t\\t&=\dfrac{35}{20 \cos 45.9^{\circ}}\\\implies t&=2.51468288...\; \sf s\end{aligned}\)

Therefore, the time is takes for the ball to reach the crossbar is 2.51 s.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↑ as positive:

\(u=20 \sin 45.9^{\circ} \quad a=-9.8 \quad t=2.51468288...\)

\(\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(20 \sin 45.9^{\circ})(2.51468288...)+\dfrac{1}{2}(-9.8)(2.51468288...)^2\\s&=36.1171982...-30.9857870...\\\implies s&=5.131411132...\; \sf m\end{aligned}\)

To find by how much the ball clears the crossbar, subtract the height of the crossbar (3.05 m) from found the vertical height of the ball at 2.51 s:

\(\implies 5.13141132...-3.05=2.08\; \sf m\;(2 \: d.p.)\)

Therefore, the ball clears the crossbar by 2.08 m (2 d.p.).

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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The tension in the wire is the force exerted by the wire to support the woman's weight and maintain her balance.

It is directed vertically upwards and equal in magnitude to the gravitational force acting on the woman. This tension force is necessary to counteract the force of gravity and prevent the woman from falling. The exact value of the tension depends on the woman's weight and the specific conditions of the wire, such as its elasticity and length.

When a person stands on a wire or cable, the wire must exert an upward force to support the weight of the person and keep them from falling. This upward force is known as tension.

Tension is a force that is transmitted through a medium, such as a cable or wire, when it is pulled taut by two opposing forces. In this case, the opposing forces are the woman's weight pulling down on the wire and the wire itself resisting that downward force by pulling up on the woman.

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Answer:

450 ML

Explanation:

Given:

Volume of gas sample: 550 mL Pressure: 1.8 atm plus 2.2 atm

To find:

The new volume of the gas after the pressure increases to 2.2 atm.

___

steps

⇒ \(V_1P_1=V_2P_2\)

⇒ \((550\text{ml})(1.8\text{atm})\)

⇒ \(=(x)(2.2\text{atm})\)

⇒ \(x=\frac{(550)(1.8)}{2.2}\)

⇒ \(x=450\text{ml}\)

Answer:

V₂ = 450 mL

Explanation:

Because you are dealing solely with pressure and volume, you can use Boyle's Law to find the missing value. The equation looks like this:

P₁V₁ = P₂V₂

In this formula, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You have been given values for all of the variables except for "V₂". Thus, you can substitute the given values into the equation and simplify to find the answer. The final answer should have 2 sig figs to match the given values.

P₁ = 1.8 atm                      V₁ = 550 mL

P₂ = 2.2 atm                     V₂ = ?

P₁V₁ = P₂V₂                                               <----- Boyle's Law equation

(1.8 atm)(550 mL) = (2.2 atm)V₂              <----- Plug given values in

990 = (2.2 atm)V₂                                    <----- Multiply 1.8 and 550

450 = V₂                                                  <----- Divide both sides by 2.2

The operational amplifier circuit that will give an output that is proportional to the integral of the input voltage is the circuit with Input 1 and Output, as this is an integrator circuit.

An integrator circuit uses an operational amplifier and a feedback resistor to generate an output voltage that is proportional to the integral of the input voltage. The integral of a signal represents the area under the curve, and the feedback resistor in an integrator circuit causes the output voltage to increase or decrease in proportion to the area under the input voltage curve. Therefore, the Output of the integrator circuit will be proportional to the integral of the Input 1 voltage.

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To determine the force that needs to be applied to the smaller piston, we can use Pascal's law, which states that the pressure in a fluid is transmitted equally in all directions.

Given:

Force on the larger piston (F1) = 13,000 N

Diameter of the larger piston (D1) = 25 cm

Diameter of the smaller piston (D2) = 5.0 cm

The ratio of the areas of the pistons is equal to the ratio of the forces applied. The formula to calculate the force on the smaller piston (F2) is:

F2 = (A2 / A1) * F1

where A1 is the area of the larger piston and A2 is the area of the smaller piston.

To calculate the area of a piston, we use the formula:

Area = π * (radius)²

First, let's calculate the areas of the pistons:

A1 = π * (D1/2)²

A2 = π * (D2/2)²

Now, we can substitute the values and calculate F2:

F2 = (A2 / A1) * F1

Finally, we can find the correct answer from the given options by calculating F2.

Let's go through the calculations:

A1 = π * (25 cm / 2)² = 4.91 cm²

A2 = π * (5.0 cm / 2)² = 0.79 cm²

F2 = (0.79 cm² / 4.91 cm²) * 13,000 N

F2 ≈ 209.58 N

The closest option to this value is 260 N. Therefore, the force that needs to be applied to the 5.0 cm diameter piston to lift the 13,000 N vehicle is approximately 260 N.

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Option a. 8 is the correct answer because Four or fewer luminaire conductors, smaller than AWG size, and small EGCs.

It's essential to guarantee that crates or nooks that contain electrical associations have sufficient space to oblige the transmitters and hardware establishing conveyors (EGCs) without surpassing the case fill limits determined by the Public Electrical Code (NEC).

As per the NEC, four or less luminaire channels, less than American Wire Check (AWG) size, and additionally little EGCs that start in the luminaire and end in the container need not be counted while computing box fill.

This standard is intended to give a specific level of adaptability and diminish the intricacy of box fill estimations, particularly in lighting establishments where luminaire guides and little EGCs are usually utilized. Notwithstanding, it's vital to take note of that this avoidance just applies to the guides and EGCs referenced, and different guides and fittings that consume space inside the container actually should be thought about while computing box fill.

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The number of turns per centimeter for a 2.0 A current must be 4.

In order to produce a magnetic field within a solenoid, there must be a certain number of turns per centimeter of winding. The exact number of turns depends on the current running through the solenoid: the higher the current, the more turns are needed.

If the current running through the solenoid is 2.0 A, then the appropriate number of turns per centimeter is calculated by Ohm’s law by dividing the current by the magnetic field, expressed in Tesla. Assuming an average magnetic field value of 0.5 Tesla, the number of turns per centimeter for a 2.0 A current must be 4.

This means that, for a solenoid of 10 cm length, 40 turns must be wound in order to produce an average magnetic field within the solenoid. This number can be adjusted according to the desired magnetic field, and more turns can be added if a higher magnetic field is desired.

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The frequency of the G allele in the population is 0.4, the correct option is B. 0.4.

The frequency of beetles with glabrous elytra in a population of ground beetles is 0.36. The frequency of the G allele is to be calculated, assuming that the population is in Hardy-Weinberg equilibrium.

What is Hardy-Weinberg equilibrium? The Hardy-Weinberg equilibrium is a model that describes the genetic makeup of a non-evolving population.

This model postulates that the genetic variation in a population remains constant from generation to generation in the absence of disturbing influences such as mutation, migration, or natural selection.

According to the Hardy-Weinberg equilibrium, the frequency of alleles and genotypes remains constant if certain conditions are met.

The Hardy-Weinberg equilibrium is represented by the following equation:p2 + 2pq + q2 = 1 Where:p2 = frequency of homozygous individuals (GG)2pq = frequency of heterozygous individuals (Gg)q2 = frequency of homozygous recessive individuals (gg)p + q = 1Now let's move on to the calculation of the frequency of the G allele.

The frequency of individuals with the gg genotype can be obtained from the following equation:q2 = 0.36q2 = 0.36^(1/2)q = 0.6

The sum of the frequency of all genotypes must be equal to 1, which can be used to calculate the frequency of the G allele:p + q = 1p = 1 - qp = 1 - 0.6p = 0.4The frequency of the G allele in the population is 0.4.Therefore, the correct option is B. 0.4.

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The basketball player must leave the ground with a velocity of 3.50 m/s in order to rise 1.25 m above the floor in an attempt to get the ball.

vf = final velocity, vi = initial velocity, a = acceleration, and d = displacement.

Assuming the initial velocity is zero and the acceleration due to gravity is -9.8 m/s^2 (downwards),

we can solve for the final velocity as follows:vf^2 = 2(-9.8)(1.25)vf = sqrt(2(-9.8)(1.25))vf = 3.50 m/s.

Therefore, the basketball player must leave the ground with a velocity of 3.50 m/s in order to rise 1.25 m above the floor in an attempt to get the ball.

we can use the kinematic equation: vf^2 = vi^2 + 2ad, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and d is the displacement.

We can assume that the initial velocity is zero and that the acceleration due to gravity is -9.8 m/s^2 (downwards).

We can then solve for the final velocity as follows:vf^2 = 2(-9.8)(1.25)vf = sqrt(2(-9.8)(1.25))vf = 3.50 m/s

The basketball player must leave the ground with a velocity of 3.50 m/s in order to rise 1.25 m above the floor in an attempt to get the ball.

In conclusion, the velocity required for the basketball player to rise 1.25 m above the floor can be found using the kinematic equation vf^2 = vi^2 + 2ad, and is calculated to be 3.50 m/s.

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Explanation:

an electrical load is the part of an electrical circuit in which current is transformed into something useful. examples include a lightbulb, a resistor and a motor. a load converts electricity into heat, light or motion. put another way, the part of a circuit that connects to a well-defined output terminal is considered an electrical load.

Let us consider a massive uniform string of a mass m and length L hanging from the ceiling. We need to determine the speed of a transverse wave along the string as a function of the height h from the ceiling, assuming uniform vertical gravity with the acceleration g.

The tension in the string is given by:T = mg (at the bottom of the string)As we move up to a height h, the tension in the string is reduced by the weight of the string below the point, that is:T' = m(g - h/L g)The mass of the string below the point is:ml = m(L - h)

Therefore:T' = m(g - h/L g) = m(Lg/L - hg/L) = mLg/L - mh/L

The speed of the transverse wave is given by:v = √(T' / μ)

where μ is the mass per unit length of the string and can be given as:μ = m / LThus:v = √((mLg/L - mh/L) / (m / L)) = √(gL - h)

Therefore, the speed of a transverse wave along the string as a function of the height h from the ceiling, assuming uniform vertical gravity with acceleration g is given by:v = √(gL - h)

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To find the speed with which a wave travels on a piano string under a certain tension and with a specific mass per unit length,

we can use the formula v = sqrt(T/μ), where T is the tension in newtons and μ is the mass per unit length in kilograms per meter.

Plugging in the given values, we get:

v = sqrt(1200 N / 4.70 x 10^-3 kg/m)

v = sqrt(255319.15 m^2/s^2)

v ≈ 505.28 m/s

Therefore, the speed with which a wave travels on a piano string with a mass per unit length equal to 4.70 x 10^-3 kg/m under a tension of 1200 N is approximately 505.28 m/s.

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Yes, you would hear the tone, but it would be slightly distorted due to interference.

The sound waves from each speaker would travel a slightly different distance to reach you, causing them to be slightly out of phase with each other. This interference would result in areas where the sound waves cancel each other out, creating "nodes" of quiet sound, and areas where they reinforce each other, creating "antinodes" of loud sound. The exact pattern of interference would depend on the relative phase and amplitude of the waves from each speaker, which in turn depend on the exact frequency and amplitude of the tone and the distance between the speakers and your location.

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Almost every font has four common stylistic sets, besides its regular display. These stylistic sets are alternate characters, ligatures, swashes, and small caps.

Alternate characters are different versions of the same letter, number, or symbol, which can give a font a unique and personalized look. Ligatures are two or more characters that are combined into one glyph to improve the font's legibility and aesthetics. Swashes are decorative elements that extend from letters, adding elegance and flair to a font. Lastly, small caps are lowercase letters that are designed to be the same height as uppercase letters, creating a more consistent and professional look. These stylistic sets can be accessed in many design software programs, allowing designers to customize their typography and create unique and visually appealing designs. Besides its regular display, almost every font has four common stylistic sets. These sets typically include regular, bold, italic, and bold italic styles. This allows for versatility in design and text formatting.

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The total work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

The work done by the force of friction on the block as it moves a distance L up the incline is equal to the product of the force of friction and the distance moved. Work is the measure of the amount of energy transferred by a force when an object is moved a certain distance. If a force acts on an object and the object moves, work is done by the force. Therefore, work can be defined as the product of force and displacement.

Mathematically, it can be expressed as follows:

W = F × S

where W is work, F is force, and S is displacement. The SI unit of work is joules (J). When a block moves on an inclined plane, friction is one of the forces acting on the block. As the block moves up the plane, the force of friction acts opposite to the direction of motion of the block. Hence, the work done by the force of friction is negative. This means that the force of friction acts to decrease the energy of the block.

The work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

where Wfric is the work done by the force of friction, f is the force of friction, and L is the distance moved by the block up the incline. Therefore, the total work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

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The work done by the cable on the car is 67500 J.  

To calculate the work done by the cable on the car, we need to use the formula for work, which is:

W = F * d

here W is the work done, So, F is the force applied, and here d is the displacement of the object being moved.

In this case, the force applied by the cable is given by the tension in the cable, which is 1350 N. The displacement of the car is given by the distance it is pulled along the roadway, which is 5.00 km.

We can use the formula for distance to calculate this displacement, which is:

d = 5.00 km

Substituting this value into the formula for work, we get:

W = 1350 N * 5.00 km

W = 67500 J

Therefore, the work done by the cable on the car is 67500 J.  

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The calculated instantaneous velocity is 65 m/s

Instantaneous velocity is a more concise term for an object's velocity at that precise moment in time. So, "The velocity of an object under motion at a specific point in time" is the definition provided. The instantaneous velocity of an object may be equal to its standard velocity if it possesses uniform velocity.

given- initial velocity=5 m/s

acceleration=6 m/s²

time taken=10 s

we can use the formula-

v = u + at

v = 5 + (6) (10)

v = 5 + 60

v = 65 m/s

Hence the velocity at instance is 65 m/s

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The total horizontal distance dm in meters traveled by the ball is approximately 28.6 m

The horizontal distance dm that the ball travels before it hits the ground is called the range. The angle is 49 degrees, and the time the ball is in the air is 1.2 seconds.

Therefore, we need to compute the horizontal velocity Vx, given that

Vy = 0 m/s.

Vy = V*sinθ

Vx = V*cosθ

Let's calculate V using the equation:

Δy = Vy*t + 1/2*a*t² = 0

Δy = 0

sinθ = Vy / V

V = 0/ sinθ = 0 m/s

Vx = V*cosθ

cos(49) = Vx / V

Vx = V*cos(49)

Now, using the formula for range:

R = Vx*tR = V*cos(49)*1.2R = 28.6 m

The total horizontal distance dm in meters traveled by the ball is approximately 28.6 m.

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The average velocity of the object, given the data is 1.25 m/s

Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:

Velocity = displacement / time

This is simply defined as total displacement travelled divide by the total time

Average velocity = Total displacement / total time

From the question given above, we were told that the object moved from x = 15 m to x = 165 m. Thus, the displacement at this point is

Displacement = 165 - 15 = 150 m

Also, we were told that the object moved back to x = 25 m.

Thus, the total displacement will be

Total displacement = 150 - 25 = 125 m

Average velocity = Total displacement / total time

Average velocity = 125 / 100

Average velocity = 1.25 m/s

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Answer:            The ice molecules expand and  become stuck since the water is frozen and start to vibrate

Explanation:

According to the concept of thermal energy, as the temperature rises thermal energy increases and molecules start vibrating faster and ice changes it's state to water  that is from solid to liquid.

Thermal energy is defined as a type of energy which is contained within a system and is responsible for rise in temperature.Heat is a type of thermal energy.It is concerned with the first law of thermodynamics.

Thermal energy arises from friction and drag.It includes the internal energy or enthalpy of a body of matter and radiation.It is related to internal energy and heat .It arises when a substance containing  molecules or atoms are vibrating faster.

These vibrating molecules and atoms collide and as a result of which heat is generated in a substance , more the  number of collision of particles , higher is the thermal energy.

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The total amount of energy a star radiates in one second is called its luminosity.

Luminosity is a fundamental property of a star radiates that measures the total amount of energy it radiates per unit of time. It is often described as the star's intrinsic brightness or power output. Luminosity is typically measured in units of watts (W) or solar luminosities (L☉), which represent the amount of energy emitted by the star relative to the Sun's luminosity.

The luminosity of a star is a result of the energy generated within its core through nuclear fusion processes. In stars like our Sun, hydrogen atoms are converted into helium through fusion reactions, releasing a tremendous amount of energy in the process. This energy radiates outward in the form of electromagnetic radiation, including visible light, infrared radiation, ultraviolet radiation, and other wavelengths.

Luminosity is an important characteristic of stars as it provides insights into their size, temperature, and overall energy output. By studying the luminosity of stars across different wavelengths, astronomers can classify them into various spectral types and determine their evolutionary stage.

Additionally, luminosity measurements allow astronomers to estimate the distance to stars, known as the luminosity distance, which is a crucial parameter in determining the scale of the universe.

Overall, the luminosity of a star provides valuable information about its energy production and plays a significant role in our understanding of stellar properties and the broader field of astrophysics.

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Answer: (d)

Explanation:

Given

Mass of the first ram \(m_1=49\ kg\)

The velocity of this ram is \(v_1=-7\ m/s\)

Mass of the second ram \(m_2=52\ kg\)

The velocity of this ram \(v_2=9\ m/s\)

They combined after the collision

Conserving the momentum

\(\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]\)

Momentum after the collision will be

\(\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}\)

Therefore, option (d) is correct

Answer:

10.21 m/s

Explanation:

∆x =( v ^2 sin(2θ))/ g

rearrange this to get

v=√Δx·(g÷ sin(2θ))

Plug it in

v=√10·(-9.8÷sin(2·35))

Solve

v=10.21

The mass of the car that was at rest is 4800kg.

What is mass?

Measurement of inertia, a fundamental characteristic of all matter. The resistance a body of matter offers to a change in its speed or location as a result of the application of a force is what it is in essence.

What is momentum?

As a measure of an object's kinetic energy, momentum is easily defined. Simply put, momentum is the result of mass times velocity. full response Simply said, momentum is concerned with the quantity of motion. The conserved quantity is another definition for it.

m= 3600kg

Vi= 21.0m/s

Vf = 9.0m/s

conservation of momentum

mVi= (m+M) Vf

mass of rest car M = (Vi-Vf )m/Vf

M = (21.0 m/s - 9.0m/s)* 3600 kg/ 9.0m/s

M= 4800kg

Therefore, the mass of the car that was at rest is 4800kg.

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