. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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1/(1/2+1/5) = 10/7 hours

Answer:

Since the object is floating, the buoyant force equals the weight of the water displaced:

W = d g v  where d is the density of water and v = V/2 where v is the volume of the water displaced   and v = V/2 where V is the volume of the object.

W = 1000 kg/m^3 * 9.8 m/s^2 * (3.5 /2 m^3)

W = 17150 kg m / s^2 = 17150 N

When an object floats with half its volume beneath the surface of the water. If the volume of the object is 3.5 m,then the weight of the object would be 17167.5 N if the density of water is 1000 kg/m3

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

The density is the reciprocal of the specific volume of any substance.

The mathematical formula for density is given below

ρ =m /V

where ρ is the density of the substance

m is the mass of the substance

V is the volume of the substance

As given in the problem an object floats with half its volume beneath the surface of the water. The volume of the object is 3.5 m

The density of water is 1000 kg/m3​

According to the Archimedes principle, the buoyancy force acting on  the floating object is equal to the weight of the fluid displaced by it

W =  ρ g V

Given the object floats with half its volume beneath the surface of the water means the volume of the water displaced is half of the volume of the object

V=3.5/2 m³

W = 1000×9.81×3.5/2

   = 17167.5 N

Thus, the weight of the object is 17167.5 N

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It will accelerate. A force of magnitude F exerted on an object of mass m applies an acceleration a according to

F = m a

Remember that force and accleration are vector quantities, so the object's acceleration would point in the same direction as the applied force. The other choices describe some possible outcomes, but

• it the object starts in motion, it can only stop moving if the force opposes the motion and acts in the opposite direction. The object would eventually stop, but only for an instant before changing direction and starting to move again. Consider a ball being thrown directly upward, reaching its highest point, then falling again.

• its speed (which is a scalar quantity) would only decrease if the object starts in motion and is slowed down. But if it starts at rest, its speed can only increase. Consider a ball being dropped from some height and gaining speed as it falls.

• its velocity will certainly change, but can only increase if the object is at rest, or if it's already in motion and the force points in the same direction.

Answer:

It will accelerate.

Explanation:

i go to K12

Answer:

According to Albert Einstein's equation, E = m·c², matter and energy are fundamentally related

Events that involve matter and energy that can be explained includes;

The boiling of water in a kettle

The rebound of objects including water after falling

The sound made by airplane and helicopters

Events involving matter and energy that are difficult to explain includes

The cause of the universe that manifest into about matter

The size of the universe

The fundamental object controlling gravity

Decipherable

1) The boiling of water in a kettle; Water boils by the addition of energy that raises the temperature of the particles which result in the forming of vapor as the bonds of the liquid state are broken by the fast moving molecules

2) The rebound of objects including water after falling from a height is proportional to the height from which the object is dropped, due to conservation of energy principle

3) The sound made by airplane and helicopters; This is due the interactions with the air to develop propulsion in the air

Difficult to decipher

1) The cause of the universe that manifest into about matter; The reason behind the formation of the universe is difficult to explain

2) The size of the universe; Will it be possible to know measure a universe

If the universe is measurable, how many universes do we have;

3) The fundamental object controlling gravity; What particle is responsible for gravity and the way if functions

Explanation:

Answer:

F_c = 519.32 N

Explanation:

We are given;

Mass of child; m = 27.1 kg

Angular velocity;ω = 31.6 rev/min

Radius;r = 1.75m

Since we want to find the force in Newton's, let's convert the angular velocity to Linear Velocity. The formula is :

v = r × RPM × 0.10472

v = 1.75 × 31.6 × 0.10472

v = 5.791 m/s

Formula for centripetal force is;

F_c = mv²/r

F_c = (27.1 × 5.791²)/1.75

F_c = 519.32 N

There are 54 turns in the coil.

The electromotive force produced by N turns is given as

                         ε=NBAω

From this, we can solve for the number of turns in the coil as

                        N = ε / BAω

Substituting the area of the coil, which is a rectangle, we get

                     N = ε / abBω

According to the question,

A bicycle generator rotates at 1,925 rad/s, producing a 20.0 v peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.640T field.

Solving numerically, we find

                  \(N =\frac{20}{0.01 * 0.03 * 0.64 * 1925}\) ( substitute the values )

                  \(N =\frac{20}{0.3696}\)

                    N = 54

So, there are 54 turns in the coil.

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​

The complete question is:

A bicycle generator rotates at 1925 rad/s, producing a 20.0 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.640 T field. How many turns are in the coil?

A series-connected light strand is most likely involved in this scenario. When lights are wired in series, the current passes sequentially through each light.

Considering that the indicator bulb is one of the bulbs in that half-strand. To identify the indicator, you must first replace each bulb with a standard bulb, one at a time.

When incandescent mini-lights first appeared, they were often wired in series, which meant that for the circuit to be complete, current had to pass through each bulb.

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Answer: 1.2 mm

Explanation:

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement=  0.5* (2.4/140) *140 = 1.2 mm

Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation:

A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant k is

43.8 N = k (0.155 m)   ==>   k = (43.8 N) / (0.155 m) ≈ 283 N/m

The total work done on the spring to stretch it to 15.5 cm from equilibrium is

1/2 (283 N/m) (0.155 m)² ≈ 3.39 J

The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be

1/2 (283 N/m) (0.259 m)² ≈ 9.48 J

Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.

Its mass is m and weight is w/9, making option D the right response. A mass m object has a weight w at the Earth's surface. If this object is moved to a height twice as far above the Earth's surface.

A body's mass is a fundamental characteristic. Before the discovery of the atom and the field of particle physics, it was generally thought to be tied to the amount of matter in a physical body. Different atoms and elementary particles were discovered to theoretically contain the same amount of substance. In terms of science and engineering, the force exerted by gravity on an object is its weight. Weight is sometimes described as a vector quantity in common textbooks, denoting the gravitational force acting on the item.

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Answer:

At point A the car has more height than at point B. This means there is more potential energy at point A than at point B.  As the car moves down the ramp from Point A, the potential energy that it starts with is converted into kinetic energy as it moves. The mechanical energy will remain the same because of the principle of conservation of mechanical energy

Explanation:

The Principle of Conservation of Mechanical Energy

In the absence of friction, the total mechanical energy is conserved. That means that

\(E_m=U+K\) is constant, being U the potential energy and K the kinetic energy

U=mgh

\(K=\frac{mv^2}{2}\)

The theory shown above will help us to complete the sentences to come:

At point A the car has more height than at point B. This means there is more potential energy at point A than at point B.  As the car moves down the ramp from Point A, the potential energy that it starts with is converted into kinetic energy as it moves. The mechanical energy will remain the same because of the principle of conservation of mechanical energy

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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Answer:

The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:

Brightness ratio = 2.512^(magnitude difference)

60 = 2.512^(magnitude of A - magnitude of B)

Taking the logarithm base 2.512 of both sides:

log base 2.512(60) = magnitude of A - magnitude of B

Solving for the magnitude of B:

magnitude of B = magnitude of A - log base 2.512(60)

magnitude of B = 1.0 - log base 2.512(60)

Calculating the value:

magnitude of B ≈ 1.0 - 2.799

magnitude of B ≈ -1.799

Therefore, the magnitude of Star B is approximately -1.799.

Explanation:

Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.

To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.

Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.

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Answer:

option A is correct because air friction is greater than gravity

Explanation:

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The distance traveled by the ball before hitting the ground is 7.2 m.

The given parameters:

The time of motion of the ball is calculated as follows;

\(h= v_y_i t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2 \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1}{9.8} }\\\\t =0.45 \ s\)

The horizontal distance traveled by the ball before hitting the ground is calculated as follows;

\(X = v_x \times t\\\\X = vcos\theta \times t\\\\X = 20 \times cos(37) \times 0.45\\\\X = 7.2 \ m\)

Thus, the distance traveled by the ball before hitting the ground is 7.2 m.

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Answer:

Their main disadvantage is that they are fairly easy to break and if they do, it results in small splinters of glass and the release of mercury which is quite toxic if absorbed into the body.

Answer:

direction of the net electric field will depend on the signs and locations of the charges. If the net electric field is positive, it means the field points away from the charges. If the net electric field is negative, it means the field points towards the charge

Explanation:

E = k * q / r^2

where E is the electric field, k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), q is the charge, and r is the distance from the charge to the point where we want to find the electric field.

Let's calculate the net electric field at the given points:

(a) x = 0 cm:

For the first charge, q1 = +6.27 μC, the distance r1 = 3.00 cm = 0.03 m.

The electric field due to q1 at x = 0 cm is:

E1 = k * q1 / r1^2

For the second charge, q2 = -20.4 μC, the distance r2 = 9.00 cm = 0.09 m.

The electric field due to q2 at x = 0 cm is:

E2 = k * q2 / r2^2

To find the net electric field, we need to add the electric fields vectorially:

E_net = E1 + E2

(b) x = +6.00 cm:

For the first charge, q1 = +6.27 μC, the distance r1 = 6.00 cm = 0.06 m.

The electric field due to q1 at x = +6.00 cm is:

E1 = k * q1 / r1^2

For the second charge, q2 = -20.4 μC, the distance r2 = 6.00 cm = 0.06 m.

The electric field due to q2 at x = +6.00 cm is:

E2 = k * q2 / r2^2

To find the net electric field, we need to add the electric fields vectorially:

E_net = E1 + E2

Answer:

Nucleus

Explanation:

Answer: Nucleolus

Explanation: The nucleolus is like the cells brain. It controls all the other organelles (cell parts).

                                                 Hope I helped!

Answer:

B or C

Explanation:

Answer-

a. iron - 60 grams and nickel 6 grams

b. \(14\) grams

Explanation

The complete question is given in the two attached images

Solution

As shown in the graph

Part A

The weight of iron is 60 gram

Weight of nickel is 6 grams

Part B

Weight of chromium is equal to

\(80-60-6\\= 14\)

\(14\) grams

The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

NASA uses centrifuges to simulate the forces astronauts' bodies feel during a launch, and it does this by placing them in a pod near the outer edge of the centrifuge, which spins around and can simulate the equivalent of several times the gravitational acceleration g via centripetal force.

To simulate 5g, assuming the radial distance from the centrifuge's axis of rotation to the pod is 8.00 m,The formula for the centripetal acceleration is:a = v^2/r where v is the tangential velocity, and r is the radial distance between the pod and the axis of rotation.

The tangential velocity is proportional to the angular velocity, ω.

Therefore, the tangential velocity is:v = ωrThe period of rotation, T, is related to the angular velocity by:ω = 2π/T

The centripetal acceleration can be rewritten as:

\(a =\frac{ (ωr)^2}{r} = ω^2r\)

Therefore,a

\(= (ω^2)r =\frac{ v^2}{rT^2}\)

= \(\frac{4π^2r}{v^2}\)

\(=\frac{ 4\pi^2r}{ω^2r}\)

\(= \frac{x4\pi^2}{ω^2T^2 }\)

= \(\frac{4\pi^2}{ω^2}\)

= \(\frac{4\pi^2r}{(ωr)^2}\)

= \(\frac{4\pi^2r}{v^2}\)

Substituting for ω and r,

\(T^2 = \frac{4\pi^2r}{(ωr)^2}\)

\(=\frac{ 4\pi^2r}{v^2}\)

\(= \frac{4\pi^2r}{(ωr)^2T^2}\)

= \(\frac{4\pi^2r}{(4\pi^2g)}\)

rT^2 = 1/gT = sqrt(1/g) * rT = sqrt(1/9.8) * 8.00mT = 0.45 seconds

Therefore, to simulate 5g, the time for one rotation required is 0.45 seconds.

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The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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Answer:

A TURNING CAR WITH CONSTANT SPEED......NON-EX OF INERTIA

Explanation:

Answer:

Explanation:

a)     Fx = F cos (θ)

           = (200) cos(60)

           = 100 N

b)     FR = ma

       Fx + Ff = ma

      100 + Ff = (50)(1,5)

       Ff     = 75 - 100

               =  -25 N

c)    Fy = F sin θ

           = (200) sin(60)

           = 173,2 N