The energy dissipated by friction is approximately 105663 Joules when a 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 170 m from top to bottom.
A skier with a mass of 66 kg starts from rest at the top of a 1200 m trail that drops 170 m. At the bottom, the skier is moving at a speed of 11 m/s. To calculate the energy dissipated by friction, we need to determine the change in potential energy and the change in kinetic energy.
The change in potential energy (ΔPE) can be calculated using the formula ΔPE = mgh, where m is the mass of the skier, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the vertical distance (170 m). Substituting the given values, we get ΔPE = (66 kg) × (9.8 m/s²) × (170 m) = 109656 J.
The change in kinetic energy (ΔKE) can be calculated using the formula ΔKE = (1/2)mv², where m is the mass of the skier and v is the final velocity (11 m/s). Substituting the given values, we get ΔKE = (1/2) × (66 kg) × (11 m/s)² = 3993 J
The energy dissipated by friction is the difference between the change in potential energy and the change in kinetic energy: Energy dissipated = ΔPE - ΔKE = 109656 J - 3993 J = 105663 J.
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A negative charge of -2.5 C and a positive charge of 2.0 C are separated by 100 m. What is the force between the two charges?
Explanation:
F = k |q1| |q2| / r^2
k = 9 * 10^9
q1 = - 2.5 C
q2 = 2 C
r = 100
r^2 = (10^2)^2 = 10^4
F = (9*10^9) * ( 2.5 ) ( 2) / ( 100)^2
F = 45* 10^9 / 10^4
F = 45 * 10^9 * 10 ^ -4 = 45 * 10^5 N
F = 45 * 10 ^ 5 N
Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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PLEASE HELP! a parking lot is going to be 40m wide and 100m long. Which dimensions could be used for a scale model of the lot? A. 100cm x 300m B. 10cm x 25 cm C. 75in x 225cm D. 25 cm x 75 cm
Answer:10cm x 25cm
Explanation:
i got it wrong so you could get it right
Two cars - Car A and Car B - drive in the same direction down a street. Car B is traveling at 30 m/s. Car A is traveling 20 m/s. Imagine that you're sitting inside Car A and Car B passes you. What is the velocity of Car B relative to you? Don't forget UNITS.
Answer:derp
Explanation:
It takes 39.7 N to push a crate at a constant speed across flat ground where μk=0.438 what is the mass of the crate
Answer:
I don't know how to show the work but I just had this question and the answer is 9.24kg.
Explanation:
Using the Skygazer's Almanac for 2022 at 40 degrees.
What day will Venus and Saturn be in opposite parts of the sky
this year?
According to the Skygazer's Almanac for 2022 at 40 degrees, Venus and Saturn will be in opposite parts of the sky on December 17, 2022.
The Skygazer's Almanac provides astronomical information for a specific location and year. In this case, at a latitude of 40 degrees, the almanac indicates that Venus and Saturn will be in opposite parts of the sky on December 17, 2022. This means that Venus and Saturn will appear at opposite sides of the celestial sphere as observed from Earth. However, it's important to note that the almanac's predictions are approximate and can be influenced by various factors, including atmospheric conditions and the observer's specific location. To obtain the most accurate and up-to-date information, it is recommended to consult more recent astronomical sources or use specialized software that can provide precise positions and dates for celestial events.
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Two students measure the length of the same object. If the students reported measurements of 3 m and 3.01 m, do you think one of them has made a mistake? Explain your reasoning.
Answer:
Yes, one of them made a mistake
Explanation:
Even though, the two values obtained in the measurements are close, the student that reported 3.01 m made a mistake.
A meter rule that is calibrated in meters (m) will only have an accuracy of 0.1 m, hence can be read as 3.0 m, 3.1 m, 3.2 m, 3.3 m and so on. A meter rule that is calibrated in meters cannot provide accuracy of up to 0.01 m, hence the student that reported 3.01 m could not have been sure of the .01 added as it couldn't have been read on the meter rule.
NOTE: A meter rule (popularly known as ruler) is an instrument that is used in the measurement of the length of an object. It can be calibrated in centimeter, inch or meter.
Q1. Explain the conservation of energy in terms of the energy transformation(s) that occur when you strike (light) a match.
Q2. When you turn on a lamp at home you are using electricity generated by a power company or public utility. Assume the electricity powering the lamp was generated at a coal burning power plant and explain the conservation of energy in terms of the energy transformations that occur when you turn on the lamp.
Q3. Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), will it ever swing higher than it's starting point? Explain your answer in terms of kinetic and potential energy.
Q4. Does a pendulum swing forever? Why or why not?
Q5. Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), will it ever swing higher than it's starting point? Explain your answer in terms of kinetic and potential energy.
Q6. Describe the transformations between potential and kinetic energy when you drop a 15000 gram television from a height of 0.8 meters.
Q7. A car with a mass of 860 kg sits at the top of a 32 meter high hill. Describe the transformations between potential and kinetic energy that occur when the car rolls to the bottom of the hill and continues rolling.
Q8. How is the previous problem different from ones where the object comes to a stop at the end of moving/falling? Discuss what happens to the energy in each case and how they are different.
Q9. Describe the transformations between potential and kinetic energy that occur when a 1000 kg rock falls from the top of a 18 meter cliff.
Q10. How much kinetic energy does a 2000 gram ball have the instant before it hits the ground after falling from a height of 6 meters?
Q11. Assume the collision in problem 10 is perfectly elastic (no energy is lost) and there is no air friction. How high should the ball bounce? Describe the transformations between potential and kinetic energy that will occur from when the ball is dropped till it reaches the top of it's first bounce.
1) when we light a matchstick,the energy which got consumed in while rubbing the matchstick against the surface,turns into heat and hence ,it lights , therefore,the energy gets transferred from one type to another which proves the law of conservation of energy.
2) The coal gets burn and generate into electricity which further used by us for various purposes like lighting lamp and since the energy gets transferred from one source to another instead of ceasing, it proves the statement of conservation of energy.
3) As the pendulum swings in air , it continues to move from one point to another, changing potential energy to kinetic energy due to the motion that's taking place and unless an external force interferes, it's speed won't increase as at some point due to the friction by air will resist the movement resulting in decresement of kinetic energy and increased potential energy, thus ,at some point it will come to rest .
4) No ,it doesn't , because due to the force of friction,the disturbance in the movement of it ,takes place, making it stop at a specific point after some time.
5) As the pendulum swings in air , it continues to move from one point to another, changing potential energy to kinetic energy due to the motion that's taking place and unless an external force interferes, it's speed won't increase as at some point due to the friction by air will resist the movement resulting in decresement of kinetic energy and increased potential energy, thus ,at some point it will eventually come to rest .
6)
Mass (m)⇢15000 gram = 15 kgHeight(h)⇢0.8 metersAcceleration due to gravity(g)⇢9.8m/s²Potential energy ⇢mghPotential energy ⇢(15 x 9.8 x 0.8 )JPotential energy ⇢117.6 J7)
Mass (m)⇢15000 gram = 860 kgHeight(h)⇢32metersAcceleration due to gravity(g)⇢9.8m/s²kinetic energy ⇢mghkinetic energy ⇢(860 x 9.8 x 32 )Jkinetic energy ⇢269,696 J8) In the previous problem ,the kinetic energy increases as continues rolling and the potential energy decreases in this process of prolongation of the movement ,while ,when an object comes to rest after the process of moving or falling, it's potential energy is at the highest while the kinetic energy is just the opposite .
9)
Mass (m)⇢ 1000kgHeight(h)⇢18 metersAcceleration due to gravity(g)⇢9.8m/s²Kinetic energy ⇢mghKinetic energy ⇢(1000x 9.8 x 18 )JKinetic energy ⇢176,400 J10)
Mass (m)⇢ 2000 gm = 2kgHeight(h)⇢6metersAcceleration due to gravity(g)⇢9.8m/s²Kinetic energy ⇢mghKinetic energy ⇢(2x 9.8 x 6 )JKinetic energy ⇢117.6 J11)
In perfectly elastic collision, there's no loss of energy, hence ,the energy that got used up in the starting to bounce the ball ,will remain the same throughout the whole collision and the height would be the same 6 meters and kinteic energy would be 117.6J
the wind is blowing southward at 75.0 km/hour . in what frame of reference is this speed measured?
Answer:
The frame of reference is the user (or ground) frame.
One must be careful about the direction of the wind because the problem indicates the wind is blowing "toward" the South whereas a South wind on the weather channel would indicate a wind coming from the South or a wind blowing northward.
The speed of the wind blowing southward at 75.0 km/hour is measured in a stationary frame of reference, as this allows for an accurate and consistent measurement of the wind speed. the speed is measured relative to a fixed point that is not moving.
The choice of frame of reference can affect the measurements of speed and other physical quantities.
In the case of the wind speed, if the frame of reference is moving, such as a person walking or a car driving, the measured speed would be different due to the combined motion of the observer and the wind. Therefore, to obtain an accurate measurement of the wind speed, it is necessary to use a stationary frame of reference.
Hence, the speed of the wind blowing southward at 75.0 km/hour is measured in a stationary frame of reference, as this allows for an accurate and consistent measurement of the wind speed.
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A 1.2-kg spring-activated toy bomb slides on a smooth surface along the x-axis with a speed of 0.50 m/s. At the origin 0, the bomb explodes into two fragments. Fragment 1 has a mass of 0.40 kg and a speed of 0.90 m/s along the negative y-axis. In the figure, the energy released by the explosion is closest to?
The velocity of fragment 2 is equal to 0.88 m/s at 31°.
What is law of conservation of linear momentum?From the law of conservation of momentum, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂.u₂ = m₁ v₁ + m₂.v₂
where m₁ & m₂ is the mass of the collided objects, u₁ & u₂ are their initial speed while v₁ & v₂ is their final speed.
Given, the mass of the spring, m = 1.2 kg
The speed of the spring, v = 0.50 m/s
The mass of the first fragment, m₁ = 0.4 kg
The initial speed of fragment 1, u₁ = 0.9 m/s
The mass of the fragment, m₂ = 1.2 - 0.4 = 0.8 kg
In x-direction: \(mucos\theta = m_1v_1 cos\theta + m_2 v_2 cos\theta\)
1.2 ×0.5 ×cos(0) = 0 + 0.8× v₂ cosθ
v₂ cosθ = 0.75
In y-direction: 12 (0) = -0.4(0.9) + 0.8 v₂ sinθ
v₂ sinθ = 0.45
Now, \(\displaystyle \frac{v_2sin\theta}{v_2cos\theta} =\frac{0.45}{0.75}\)
tanθ = 0.6
θ = 31°
The value of the velocity of the fragment can be calculated as;
v₂ sinθ = 0.45
v₂ sin31 = 0.45
v₂ = 0.88 m/s
Thus, the magnitude of the velocity of fragment 2 is 0.88 m/s at 31⁰.
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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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A kilogram is a measure of an object's
O Gravity
O Weight
O length
O Mass
Answer:(d) mass
Explanation: The kilogram is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogram weighs 9.8 Newtons under normal conditions on the surface of the Earth, and Newton is the corresponding SI unit of force and weight.
In which three ways does the pattern seen on the screen during a double-slit
experiment support the wave model of light?
o a. all of the light that enters the slits passes through them.
o b. the light bends around the edges of the slit.
o c. there are bands of dimmer light.
o d. there are bands of brighter light.
Option B,C and D shows the three ways does the pattern seen on the screen during a double-slit experiment.
The double-slit experiment shows that light and matter are with properties that are both of waves and particles, as well as it has the essentially probabilistic nature of quantum mechanical processes.
Huygens' Wave Model of Light considers light behaving as a longitudinal wave. Huygens stated light's propagation as a wave's direction of travel. He proposed that the nature of light is similar to observing the motion of water surfaces.
The three ways does the pattern seen on the screen during a double-slit experiment support the wave model of light;
B. The light bends around the edges of the slit.
C. There are bands of dimmer light.
D. There are bands of brighter light.
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what is the weight of a 63.7 kg person? ?N
Answer:
624.26
Explanation:
63.7 kg x 9.8 (force of gravity) = 624.26N
The weight of a person is the normal fore acting on it by gravitation. It is the product of mass and acceleration due to gravity. The weight of the person with 63.7 kg person is 624.96 N.
What is gravitational force?Gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts every objects on its surface and that is why we are all standing on the ground.
The gravitational force depends on the mass of the object and distance from the source of force. Thus when we go to space we experience no gravitational force and thus no weight.
The weight of an object is the product of its mass and acceleration due to gravity g of earth.
g of earth = 9.8 m/s²
Then, the weight of a 63.7 kg person = 63.7 kg × 9.8 m/s² = 624.96 N.
Therefore, the weight of the 63.7 kg person is 624.96 N .
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An object is thrown from the ground with an initial velocity of 30 m/s. What is the velocity at the point 25 m above the ground?
Answer:
It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.
V^2=U^2+2*a*x
V=0 (as it is at max height)
U=30ms^-1 (initial speed)
a=-g /-9.8ms^-2 (as it is moving against gravity)
x is the variable you want to calculate (height)
0=30^2+2*(-9.8)*x
x=-30^2/2*-9.8
x=45.92m
Answer:
35
Explanation:
dfddffffffffffffdddfr
Describe the three methods of thermal energy transfer and provide a sketch that depicts each:
Conduction:
Convection:
Radiation:
Answer:
a)the process by which heat or electricity is directly transmitted through the material of a substance when there is a difference of temperature
b)the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat
c)radiation is the emission or transmission of energy in the form of waves or particles through space or through a material medium.
Lizette works in her school’s vegetable garden. Every Tuesday, she pulls weeds for 15 minutes. Weeding seems like a never-ending task. Each time Lizette goes to the garden, there are just as many weeds as the week before!
Lizette’s teacher suggests that she use a strong solution of vinegar to kill the weeds. Vinegar is acidic and prevents plants from maintaining homeostasis. Lizette sets up a controlled experiment to test her hypothesis that the solution will kill the weeds without harming nearby vegetables. She plans to spray one group of weeds with the solution and another group of weeds with water as a control.
What variables should Lizette keep the same between the control group of weeds and the sprayed weeds?
The variables that Lizette should keep the same between the control group of weeds and the sprayed weeds include : type of weed, age and size of the weeds, amount of sunlight and water , location of the weeds and amount and frequency of spraying.
What variables should Lizette keep the same between control group of weeds and sprayed weeds?The variables that Lizette should keep the same between the control group of weeds and the sprayed weeds include:
The type of weed: To ensure that the control group of weeds and the sprayed weeds are comparable, Lizette should use the same type of weed in both groups.
The age and size of the weeds: Lizette should select weeds of similar age and size for both groups, as larger or older weeds may be more resistant to the vinegar solution.
The amount of sunlight and water: The amount of sunlight and water that the control group of weeds and sprayed weeds receive should be same, as these factors can affect plant growth and health.
The location of the weeds: The control group of weeds and the sprayed weeds should be located in same area of the garden, as differences in soil composition or other environmental factors could affect the results.
The amount and frequency of spraying: Lizette should apply the same amount of water to the control group of weeds as she applies vinegar solution to the sprayed weeds, and frequency of spraying should also be same.
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a 40 kg boy dives horizontally off a 600 kg raft. if the boy's speed at the moment he is leaving the raft is 4.0 m/s, what is the raft's speed? group of answer choices 0.56 m/s 0.60 m/s 0.26 m/s 4.0 m/s
The speed of the raft when the 40 kg boy dives horizontally off it at a speed of 4.0 m/s is 0.60 m/s.
According to the law of conservation of momentum, the total momentum before the boy jumps off the raft is equal to the total momentum after he jumps off. The momentum of an object is given by the product of its mass and velocity.
Let the initial velocity of the raft be v (which is what we need to find), and the final velocity of the boy be v_boy = 4.0 m/s. The mass of the boy is 40 kg, and the mass of the raft is 600 kg.
Before the boy jumps off, the total momentum is the sum of the momentum of the boy and the momentum of the raft. After the boy jumps off, the momentum of the boy becomes zero, and only the momentum of the raft remains.
The initial momentum is given by the product of the mass and velocity of the boy: momentum_initial = 40 kg * 4.0 m/s.
The final momentum is the product of the mass and velocity of the raft: momentum_final = 600 kg * v.
Since momentum is conserved, we can equate the initial momentum to the final momentum: momentum_initial = momentum_final.
40 kg * 4.0 m/s = 600 kg * v.
Simplifying the equation, we find: v = (40 kg * 4.0 m/s) / 600 kg.
Calculating this, we get v ≈ 0.2667 m/s, which can be rounded to 0.26 m/s.
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in the trapazoid below, x=?
A polygon with only one set of parallel sides is called a trapezoid. The parallel bases of a trapezoid are another name for these parallel sides. Trapezoids have two additional sides that are not parallel and are referred to as their legs. The value of x is 12.
What is a Trapezoid?A four-sided shape called a trapezoid has one pair of parallel sides. It fundamentally resembles a square, rectangle, or parallelogram in two dimensions. So, like other shapes, this one has a boundary and an area.
There are some Mid-segment characteristics :
Parallel to each boxHalf the sum of length of the basesAlso called the medianNow, according to the diagram, make an equation :
5x-20 = [(2x+6) + (4x+2)] / 2
5x-20 = (6x+8)/2
5x-20 = 3x+4
5x-3x = 20+4
2x = 24
x = 12
Hence, the value of x is 12.
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A steam power plant produces 50MW of net work while burning fuel to produce 150MW of heat energy at the high temperature. Determine the cycle thermal efficiency and the heat rejected by the cycle to the surroundings.
\(Nth\) =\(\frac{W net, out}{Qh}\)
50MW is our net output.
Then, we plug it in.
= \(\frac{50MW}{150MW}\) = 0.333 or 33.33%
W net, out = Qh - Ql
Ql = Qh - W net,out
Plug the values in.
Then, it becomes:
= 150MW - 50 MW
= 100MW
Thus, the cycle thermal efficiency is 33.33% and the heat rejected is 100MW.
100 MW of the cycle thermal efficiency and the heat is thermal energy rejected by the cycle to the surroundings.
What is thermal energy?The energy present in a system that determines its temperature is referred to as thermal energy. Thermal energy flows as heat. Thermodynamics is a whole field of physics that studies how heat is transmitted across various systems and how work is performed in the process.
N = W/Q
50 MW is our net output.
Then, we plug it in.
= 50/150 = 0.333 or 33.33%
W net, out = Qh - Ql
Ql = Qh - W net,out
Plug the values in.
Then, it becomes:
= 150 MW - 50 MW
= 100 MW
Thus, the cycle thermal efficiency is 33.33% and the heat rejected is 100 MW
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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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Find the gravitational force that Earth (mass = 5.97 × 10²⁴ kg) exerts on the moon (mass = 7.35 × 10²² kg) when the distance between them is 3.84 × 10⁸ m. The value of G is 6.67 x 10⁻¹¹ Nm²/kg².
Explanation:
mass of earth (m1)=5.97×10^24
mass of moon (m2)=7.35×10^22
distance between their center (d)= 3.84×10^8
G=6.67×10^-11
now,
gravitational force =(F)= G(m1×m2)/d²
6.67×10^-11(5.97×10^24×7.35×10^22)/(3.84×10^8)19.84×10^19stay safe healthy and happy...Alkaline earth metals have a low density
true
false
true
Explanation:
this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons
Do children under the age of 13 that have social media accounts have more behavior problems in school? What is the independent variable?
A). The number of behavior problems in school
B). Children under 13 with social media accounts
C). Use of electronics after 9 PM
D). Students over the age of 13
Answer:
A
Explanation:
if the crate has a mass of 10 kg and the coefficient of friction between the box and the surface is 0.5, what is the force of friction on the box?
The force of friction on the box is equal to 49 N.
What is frictional force?Frictional force can be described as the force produced by two surfaces that contact and slide against each other. These forces are affected by the surface texture, the angle, and the position of the object.
Friction can be described as the force that prevents motion when the surface of one object comes in contact with the surface of another. The mechanical advantage reduced by friction is the ratio of output to input is decreased because of friction.
The fractional force can be represented as:
F = μ mg
Given, the mass of the crate, m = 10 Kg
The coefficient of friction between the box and the surface = 0.5
The gravitational acceleration, g = 9.8 m/s²
The frictional force, F = 10 ×0.5× 9.8 = 49 N
Therefore, the frictional force on the box is 49 N.
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Sian wants to measure the number of seconds that it takes for the contents of a beaker to change from clear to purple. which of these tools should she use for this purpose? an electronic balance a stopwatch a barometer a graduated cylinder
Sian wants to count the number of seconds it takes for a beaker's contents to become purple from clear. She should utilize a stopwatch as her instrument for this job.
What is a stopwatch?Watch that, when turned on and off, measures the amount of time that has passed since a specific time.
Sian wants to measure the number of seconds that it takes for the contents of a beaker to change from clear to purple. Stopwatch is the tool she should utilize for this purpose.
Hence, option B is correct.
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Answer: Sian wants to count the number of seconds it takes for a beaker's contents to become purple from clear. She should utilize a stopwatch as her instrument for this job.
option b
Explanation:
a ball has a diameter of 3.87 cm and average density of 0.0845 g/cm3. what force is required to hold it completely submerged under water?
The amount of force required to hold the ball completely submerged under water is 0.025N.
The diameter of the ball is 3.87 cm.
So, the radius of the ball is 1.935cm. The density of the ball is 0.0845 g/cm³.
The force required to hold the ball completely submerged under water will be equal to the the buoyancy on the body,
The buoyancy on the body is given as,
B = pVg
B is the buoyancy,
p is the density of the body,
V is the volume of the ball,
g is the acceleration due to gravity.
So, putting values,
B = 4π(0.01935)³(84.5)(9.8)/3
B = 0.025N.
So, the amount of force required is 0.025N.
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The following figure is from a student’s experiment to find the centre of mass of an irregular shape.
a. Explain how the student used the following equipment to find the centre of mass:
• String
• A small mass (e.g. adhesive putty)
• A stand
• A pencil
• A straight-edge (e.g. ruler).
Include a diagram of the experimental set-up as part of your explanation.
To find the center of mass of an irregular shape using
String- for hanging at the center
• A small mass - hung from the string
• A stand-holding up the string
• A pencil pinpointing the center
• A straight-edge- Identify the middle
What is the center of mass?Generally, a point indicates the mean location of the matter in a body or system.
In conclusion, the center of mass also indicates a point at which the body is most balanced under gravity.
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a 83.0-kg person is riding in a car moving at 20.0 m/s when the car runs into a bridge abutment. calculate the average force on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm.
The average force applied to the person when he stopped by a padded dashboard is 166×10⁴ N.
An external force is an agent that has the power to alter the body in moving or resting conditions. It can also be described as a push or a pull. It is a vector quantity so it has both direction and magnitude.
The formula to calculate the force applied on an object is F=m×a. Where F is force, a is the acceleration, and m is the mass of an object,
Given mass (m) is 83 kg, initial velocity (u) is 20 m/s, and displacement (s) is 1 cm.
When the dashboard is compressed to stop a car, then the acceleration is calculated using the formula v²=u²+2as where v is final velocity, u is initial velocity, a is acceleration, and s is displacement. Initially, the final velocity is zero. Solving we get,
\(\begin{aligned}0&=u^2+2as\\u^2&=-2as\\20^2&=-2\times a\times0.01\\a&=\mathrm{-20000\;m/s^2}\end{aligned}\)
The negative sign indicates that the car is slowing down or decelerating.
The average force on the person riding the car is given by,
\(\begin{aligned}F&=83\times 20000\\&=\mathrm{166\times 10^4\;N}\end{aligned}\)
The answer is 166×10⁴ N.
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a commercially available solar cell module puts out 3 v and 0.1 a, and measures 5.0 cm and 8.0 cm. how large an array is necessary to provide an output of 40 w
To provide an output of 40 W, approximately 134 solar cell modules would be necessary.
To determine the size of the solar cell array necessary to provide an output of 40 W, we need to calculate the total power generated by a single solar cell module and then divide 40 W by that power.
In this case:
Voltage (V) = 3 V
Current (I) = 0.1 A
Dimensions: Length (L) = 5.0 cm and Width (W) = 8.0 cm
First, let's calculate the power generated by a single solar cell module using the formula:
Power (P) = Voltage (V) * Current (I)
P = 3 V * 0.1 A
P = 0.3 W
So, a single solar cell module generates 0.3 W of power.
Now, we can determine the number of modules required to provide 40 W of power by dividing the desired output power by the power of a single module:
Number of modules = Desired power / Power per module
Number of modules = 40 W / 0.3 W
Number of modules ≈ 133.33
Since we cannot have a fraction of a module, we would need to round up to the nearest whole number.
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