The original velocity is \(5.71 m/s\)
What do you know about momentum?
The conservation of momentum principle states that, in a closed system, the overall momentum before and after a collision is equal.
We know of momentum conservation,
\(MU+mu=MV +mv\)
where \(M\) is the mass of the bowling ball, \(m\) is the mass of the pin, \(U\) is the bowling ball's starting velocity, \(u\) is the pin's initial velocity, \(V\) is the bowling ball's final velocity, and \(v\) is the pin's final velocity
Given
\(M= 7 kg, m=2kg, u = 0 m/s, v = 6 m/s, V= 4 m/s\)
\(MU+mu=MV +mv\)
\(7(U) + 2(0) = 7(4) +2(6)\\7U = 28 +12\\7U = 40\\U = 5.71 m/s\)
Hence the velocity will be \(5.71 m/s\)
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A 0.0780 kg lemming runs off a
5.36 m high cliff at 4.84 m/s. What
is its potential energy (PE) when it
lands?
The potential energy of the lemming when it lands is 0.9108672 J.
To determine the potential energy (PE) of the lemming when it lands, we need to consider the conservation of energy. The potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the lemming (m) = 0.0780 kg
Height of the cliff (h) = 5.36 m
First, let's calculate the potential energy when the lemming is on the cliff. Using the given formula, we have:
PE = mgh
PE = 0.0780 kg * 9.8 m/s² * 5.36 m
PE = 0.413616 J
Next, we need to determine the final kinetic energy of the lemming just before it lands. We can use the equation for kinetic energy (KE) given by KE = (1/2)mv², where v is the velocity of the lemming.
Given:
Velocity of the lemming (v) = 4.84 m/s
Calculating the kinetic energy, we have:
KE = (1/2) * 0.0780 kg * (4.84 m/s)²
KE = 0.9108672 J
According to the conservation of energy, the potential energy at the top of the cliff is equal to the kinetic energy just before landing.
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How many nitrogen atoms are there in 4 molecules of NH3?
Answer:
There is one atom of N and three atoms of H
in total 4 atoms
Tonya is modeling the discovery of electromagnetic induction. Which procedure should she use? moving a magnet into a coil of wire in a closed circuit moving a magnet into a coil of wire in an open circuit bringing a compass near a wire that has no electric current bringing a compass near a wire that has an electric current
To model the discovery of electromagnetic induction, Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.
Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.
Electromagnetic induction refers to the phenomenon of generating an electric current in a conductor by varying the magnetic field passing through it. This concept was discovered by Michael Faraday in the early 19th century. To model this discovery, Tonya needs to recreate the conditions that led to this breakthrough.
In Faraday's experiment, he observed that when a magnet is moved into or out of a coil of wire, it induces an electric current in the wire. This occurs when the magnetic field passing through the coil changes. Therefore, Tonya should use a similar setup to replicate this process.
Out of the given options, the most appropriate procedure for Tonya would be to move a magnet into a coil of wire in a closed circuit. By having a closed circuit, it means that the ends of the wire are connected to form a complete loop. When the magnet is moved into the coil, the changing magnetic field induces an electric current to flow through the wire.
This procedure demonstrates the principle of electromagnetic induction and shows how a changing magnetic field can produce an electric current. It allows Tonya to visually observe the effects of the induced current, which is essential in modeling the discovery of electromagnetic induction.
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The energy an object possesses due to its motion
A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H
(a) The direction of wave propagation is along the negative z-axis.
(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m
Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.
Hence, the direction of wave propagation for the given wave is along the negative z-axis.
To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:
E = c * H,
where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.
(a) Direction of wave propagation: Along the positive z-axis.
(b) Calculating λ, f, and Er:
Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.
The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.
Using the relation c = ω/k, we can solve for λ and f:
λ = 2π/k = 2π/2 = π m (meters)
f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)
To find the wave impedance (Er), we can use the equation Er = E/H:
Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) can be calculated using the relationship H = E/c:
H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
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List the 6 questions you may apply to formulating a logical, reasonable perspective to any situation.
Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust
What are the 6 questions that may be applied to formulate logical, reasonable perspective to any situation?Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:
What are the issues that should be addressed?
What are the relevant facts and data related to this problem or issue?
What assumptions am I making about the problem or issue?
What are the possible solutions or outcomes, and what are the pros and cons of each?
What are my values and priorities related to this problem or issue?
What additional information do I need to make an informed decision or come to a reasonable conclusion?
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A brick is resting on a smooth wooden board that is at a 30° angle. What is one way to overcome the static friction that is holding the brick in place?
Answer:
We apply force to move the brick.
Explanation:
Let me first of define a force .
A force is something applied to an object or thing to change it's internal or external state.
Now if a brick is resting on smooth wood inclined at 30° to the horizontal for us to overcome the friction which is also a force we have to apply a force greater than the gravity force acting on the body and then depending on the direction of the applied force the angle to apply it also.
A 6.35 kg bowling ball moving 8.49 m/s strikes
a 1.59 kg bowling pin at rest. After, the pin moves 20.1 m/s at a -77.0° angle. What is
the x and y component of the ball's final velocity?
The x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Mass of the ball: M = 6.35 kg.
Initial velocity of ball: U = 8.49 m/s.
Mass of the pin at rest: m = 1.59 kg.
Final velocity of pin: v = 20.1 m/s at a -77.0° angle.
Let the x and y component of the ball's final velocity are respectively V₁ m/s and V₂ m/s.
Appling conservation of momentum along x axis:
MU + m.0 = MV₁ + mvcos(-77.0°)
⇒ V₁ = u - (m/M) v cos(-77.0°)
After putting the values we get:
V₁ = 7.35 m/s.
Appling conservation of momentum along y-axis:
M.0 + m.0 = MV₂ + mvsin(-77.0°)
⇒ V₂ = - (m/M) vsin(-77.0°)
After putting the values we get:
V₂ = 4.90 m/s.
Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
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Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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Sammy Sosa swings at a 0.15 kg baseball and accelerates it at a rate of3.0 x 10^4 m/s2. How much force does Sosa exert on the ball?
Given:
The mass of the ball is m = 0.15 kg
The acceleration of the ball is
\(a=3\times10^4\text{ m/s}^2\)To find the force.
Explanation:
The force can be calculated by the formula
\(F=\text{ ma}\)On substituting the values, the force will be
\(\begin{gathered} F=0.15\times3\times10^4 \\ =4500\text{ N} \end{gathered}\)Thus, the Sosa exerts 4500 N of force on the ball.
Given the temperature data shown, which of these ecosystems is definitely in the northern hemisphere
answer choices
Daly Waters
Iquitos
Tindouf
These are all in the southern hemisphere
The ecosystem that is present in the northern hemisphere is Tindouf
Tindouf is the capital of Algeria's Tindouf province, a city close to the borders of Mauritania, Western Sahara, and Morocco which is located in the northern hemisphere. From the chromatogram drawn by Teresa Glass, we concluded that the city of Tindouf, Algeria is a desert biome with very low winter precipitation and high temperatures. This region is of strategic importance. It has an Algerian military base and airport, with regular flights to Algiers and other domestic destinations. Garet Djebilet's settlement is located in his Tindouf municipality near the border with Mauritania. The settlement has an iron mine and an abandoned airport, and is located about 70 kilometers northwest of Awinetbel his Egla.
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The filament of a 75-W light bulb is at a temperature of 3300 K. Assuming the filament has an emissivity e = 0.9, find its surface area. (Use s = 5.6696 10-8 W/m2 · K4 for the Stefan-Boltzmann constant.)
Surface area is 1.10 × 10^-5 .
Stefan-Boltzmann law, statement that the total radiant heat power emitted from a surface is proportional to the fourth power of its absolute temperature.All bodies radiate energy W depending on temperature T, according to the Stefan-Boltzmann law W = ε σT4 where emissivity ε is equal to 1 for black bodies and less than 1 for grey bodies, σ being the Stefan constant.
From Stefan's law, the power radiated by an object at absolute
temperature T and surface area A is POAT, where a=5.6696 × 10
W/m²K and e is the emissivity. Thus, the surface area of the filament
must be
A =75 W / (5.6696x10 )(1.0 )(3300) = 1.10 * 10^-5
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Chadwick now needs to push the piano up a ramp and into a moving van. (Figure 2) The ramp is frictionless. Is Chadwick strong enough to push the piano up the ramp alone or must he get help? To solve this problem you should start by drawing a free-body diagram.
Determine the object of interest for this situation.
The object of interest for this situation is the piano. The forces acting on the piano are: (1) gravitational force acting on the piano (piano's weight). (2) force of the floor on the piano (normal force). (3) force of Chadwick on the piano
In this situation, the object of interest is the piano. The forces acting on the piano are the gravitational force (weight) pulling the piano down, the normal force of the floor pushing up on the piano, and the force of Chadwick pushing on the piano to move it up the ramp. Since the ramp is frictionless, the only force acting to stop the piano from sliding back down the ramp is the normal force of the floor, which is perpendicular to the ramp surface. Therefore, Chadwick must push the piano with a force greater than its weight to overcome gravity and move it up the ramp.
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Complete question:
Chadwick now needs to push the piano up a ramp and into a moving van. The ramp is frictionless. Is Chadwick strong enough to push the piano up the ramp alone or must he get help? To solve this problem you should start by drawing a free-body diagram.
Determine the object of interest for this situation.
Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.
(1) gravitational force acting on the piano (piano's weight)
(2) force of the floor on the piano (normal force)
(3) force of Chadwick on the piano
A compound microscope has a barrel length of =159.0 mm and an objective with a 4.070 mm focal length. The total angular magnification of the microscope is −411.0. Using the approximation that the barrel length is large relative to the focal lengths, determine the angular magnification of the eyepiece.
A microscope's objective lens has a focal length of 4 cm, whereas the eye lens's focal length is 8 cm. if 24 cm is the minimum distance at which a person can see clearly,
How does a microscope use magnification?When an object is magnified, it appears in a microscope image at a scale bigger than its true size. Only when it is able to see more specifics of an item in the photograph than when studying the thing without the use of a magnifying glass does magnification serve a beneficial purpose.
What magnification do 10x and 4x represent?Scanning objective lenses typically have a magnification of 4x, and when paired with a 10x eyepiece lens, they have a total magnification of 40x.
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SuperPointParticleDog is playing tug of war with two other dogs, Isaac and Newton. Isaac is pulling with a force of 255 N, 13 degrees North of East on one rope attached to a ball. Newton is pulling with a force of 156 N, 34 degrees South of East on another rope attached to the ball. If the ball is moving with constant momentum toward SuperPointParticleDog, what is the East/West component of her force on the ball?
The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
How to explain tje informationIsaac's force:
Magnitude: 255 N
Angle: 13 degrees North of East
x-component: 255*cos(13) = 245.1 N (Eastward)
y-component: 255*sin(13) = 58.1 N (Northward)
Newton's force:
Magnitude: 156 N
Angle: 34 degrees South of East
x-component: 156*cos(34) = 129.4 N (Westward)
y-component: 156*sin(34) = 86.5 N (Southward)
Now we can add the x- and y-components of the forces to find the net force:
Net force:
x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)
y-component: 58.1 N - 86.5 N = -28.4 N (Southward)
The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).
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A golfer hits the ball across a 40 meter golf course, the ball reaches the other side in 0.30 seconds. What is the average speed that the golfer hit the ball at?
a. 0.0075 m/sec
b. 40 m/sec
c. 0.30 m/sec
d. 133.33 m/sec
A 10 kg piano is hoisted on a crane and delivered through the window of a six story apartment 20 m above the ground what is the potential energy of the piano?
Answer:
1962 J
Explanation:
potential energy= mgh
m=10 kg
h=20 m
g=9.81 (always unless otherwise stated)
PE= 10(20)(9.81)=1962 J
A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block
difference between fuse wire and MCB
Answer:
Explanation:
"fuse wire" typically refers to a thin, single-use wire that is used to protect an electrical circuit from overloading or short circuiting. The wire is designed to melt and break the circuit if the current flowing through it exceeds a certain level, which helps to prevent damage to the electrical equipment or a potential fire hazard. Once the fuse wire has melted, it must be replaced with a new one.
an "MCB" (miniature circuit breaker) is a type of switch that automatically trips and breaks the circuit when there is an overcurrent or short circuit.
Unlike a fuse wire, an MCB can be reset after it has tripped, making it more convenient for protecting electrical circuits. MCBs are typically more expensive than fuse wires, but they offer greater protection and are often used in modern electrical systems.
You are on the Pirates of the Caribbean attraction in the Magic Kingdom at Disney World. Your boat rides through a pirate battle, in which cannons on a ship and in a fort are firing at each other. While you are aware that the splashes in the water do not represent actual cannonballs, you begin to wonder about such battles in the days of the pirates. Sup-pose the fort and the ship are separated by 75.0 m. You see that the cannons in the fort are aimed so that their cannon-balls would be fired horizontally from a height of 7.00 m above the water.
(a) You wonder at what speed they must be fired in order to hit the ship before falling in the water.
(b) Then, you think about the sludge that must build up inside the barrel of a cannon. This sludge should slow down the cannonballs. A question occurs in your mind: if the can-nonballs can be fired at only 50.0% of the speed found ear-lier, is it possible to fire them upward at some angle to the horizontal so that they would reach the ship?
Answer:
a) v₀ₓ = 62.76 m / s, b) θ₁ = 17.6º, θ₂ = 67.0º
Explanation:
We can solve this exercise using the projectile launch ratios
a) Let's find the time it takes for the bullet to reach the water level
y = y₀ + v_{oy} t - ½ g t²
when it reaches the water its height is zero y = 0, as the bullet is fired horizontally its initial vertical velocity is zero
0 = y₀ + 0 - ½ g t²
t =\(\sqrt{2y_o/g}\)
t = \(\sqrt{2 \ 7 /9.8}\)
t = 1,195 s
now we can calculate the speed with the horizontal movement
x = v₀ₓ t
v₀ₓ = x / t
v₀ₓ = 75.0 / 1.195
v₀ₓ = 62.76 m / s
b) if the speed of the bullets is half of that found
v₀ = 62.76 / 2 = 31.38 m / s
let's write the expressions for the distance
x = v₀ cos θ t
y = y₀ + v_{oy} sin θ t - ½ g t²
t = \(\frac{x}{v_o \ cos \theta}\)
we substitute
\(0 = y_o + v_o sin \theta \ \frac{x}{v_o \cos \thetay} - 1/2 g \ (\frac{x}{v_o \ cos \theta})^2\)
\(0 = y_o + x tan \theta - \frac{1}{2} g \ \frac{x^2}{ v_o^2 \ cos^2 \theta}\)
let's use the identified trigonometry
sec² θ = 1 + tan² θ
sec θ = 1 / cos θ
we substitute
\(0 = y_o + x tan \theta - \frac{g x^2}{2 v_o^2} ( 1 + tan^2 \theta)\)
\(\frac{g x^2}{2v_o^2} tan^2 \theta - x tan \theta + \frac{gx^2}{2v_o^2} - y_o = 0\)
we change variable
tan θ = H
\(\frac{gx^2}{2 v_o^2 } H^2 - x H + \frac{gx^2}{2v_o^2}-y_o =0\)
we subtitle the values
\(\frac{9.8 \ 75^2}{2 \ 31.38^2} H^2 - 75 H + \frac{9.8 \ 75^2}{2 \ 31.38^2}-7 =0\)
27.99 H² - 75 H + 20.99 = 0
H² - 2.679 H + 0.75 = 0
we solve the quadratic equation
H = [2.679 ± \(\sqrt{2.679^2 - 4 0.75}\)] / 2
H = [2,679 ± 2,044] / 2
H₁ = 0.3175
H₂ = 2.3615
now we can find the angles
H₁ = tan θ₁
θ₁ = tan⁻¹ H₁
θ₁ = tan⁻¹ 0.3175
θ₁ = 17.6º
θ₂ = 67.0º
for these two angles the bullet hits the boat
To move a large crate across a rough floor, you push on it with a force at an angle of 15 degrees below the horizontal. Find the force necessary to start the crate moving, given that the mass of the crate is 32 kg and the coefficient of static friction between the crate and the floor is 0.49.
Answer:
663N
Explanation:
We need to find the force that will overcome the frictional force.
The angle of the normal force is 15°.
The mass of the crate is 32 kg
The coefficient of static friction is 0.49
Frictional force is given in terms of Normal force as:
F = μNcosθ
where μ = coefficient of static friction
N = normal force
θ = angle of normal force
Frictional force is given as:
F = mg
=>mg = μNcosθ
=> N = mg/(μcosθ)
N = (32 * 9.8) / (0.49 * cos15)
N= 313.6 / 0.473
N = 663 N
The force needed to cause the box to move must be 663N or greater.
) The graph in the figure shows the position of a particle as a function of time as it travels along the x-axis.
What is the average velocity of the particle between t = 2.0 s and t = 4.0 s?
The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
What is average velocity?Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.
The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.
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A ball, starting from rest at Position 1, rolls along a curved track toward Position 5. The ball speeds up as it rolls from Position 1 to Position 3, and it slows down as it rolls from Position 3 toward Position 5. Just before it reaches Position 5, it stops and rolls back down the track. As the ball rolls back and forth along the curved track, the ball and the track get a little warmer.When does the Thermal energy of the ball and track increase and why?
From the law of conservation of energy, the energy can neither be created nor be destroyed. But it can be converted from one form to another.
At position 3, the ball will have maximum kinetic energy and at 1 and 3 the ball has the energy only in the form of gravitational potential energy.
The potential energy and kinetic energy of the ball will be lost due to the friction between the ball and the track. This lost energy will be converted into thermal energy. The friction will act on the ball throughout its motion on the track.
Thus, the thermal energy increases the entire time the ball rolls on the track. And both gravitational potential energy and kinetic energy are converted into thermal energy.
Therefore, the correct answer is option C.
19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.
The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula
W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.
Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.
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pathogens grow best at which temperature
Pathogens grow best at temperatures between 5°C and 60°C.
The ideal temperature range for food-poisoning bacteria to develop is between 5°C and 60°C. The temperature danger zone is the name given to this temperature zone.
The bacteria can't thrive if potentially dangerous items are kept heated (above 60°C) or cold (below 5°C). Bacteria can double in number in as little as 20 minutes at temperatures between 40 °F and 140 °F, where they proliferate the fastest.
FATTOM, an acronym for food, acidity, time, temperature, oxygen, and moisture, stands for the elements necessary for bacterial growth.
Due to their availability of nutrition, energy, and other elements that the bacteria require for growth, foods offer the ideal conditions for bacterial growth.
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A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 5.50×10−5T and points into the Earth at an angle of 58.0 below a line pointing due north. A 6.90-A clockwise current passes through the coil.
The Earth's magnetic field at the location has a magnitude of 5.50×10^−5 T and points into the Earth at an angle of 58.0 degrees below a line pointing due north.
What is Magnetic Field?
A magnetic field is a region of space surrounding a magnet or a current-carrying conductor in which magnetic forces are exerted on other magnetic objects or moving charged particles. Magnetic fields are characterized by their direction, magnitude, and polarity. The direction of a magnetic field is defined as the direction in which a magnetic north pole would be pulled or aligned, and is conventionally represented by magnetic field lines that form closed loops.
Based on the information provided, it seems like you have described a situation where a circular coil with a diameter of 14.0 cm and containing nine loops is lying flat on the ground.
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A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 5.00×10−5T and points into the Earth at an angle of 58.0 ∘ below a line pointing due north. A 6.90-A clockwise current passes through the coil. Determine the torque on the coil, and which edge of the coil rises up: north, east, south, or west?
A teammate starts taking an all-natural supplement to improve strength and body shape and recommends you take it, too. This is an example of
Answer:
Explanation:
online personal fittness
Determine the speed of B when A and B pass each other. The speed of B is ___ mi/h
To determine the speed of B when A and B pass each other, we need to first gather information about their initial velocities, relative speeds, and direction of motion.
The speed of A is given and we need to find the speed of B. The formula for relative speed can be used, which states that the relative speed of two objects is equal to the sum of their individual speeds when they are moving in the same direction, and the difference of their speeds when they are moving in opposite directions. In this case, if A and B are moving in opposite directions, then their relative speed is equal to the speed of A plus the speed of B.
It is important to note that the speed of B must be expressed in the same unit as the speed of A (e.g. miles per hour) to allow for accurate comparison and calculation. Once the relative speed is known, it can be used to determine the speed of B by solving for it algebraically. The answer should be a numerical value in miles per hour.
It is also important to take into consideration any external factors that may affect the motion of the objects such as friction, air resistance, and changes in direction or speed. These factors can impact the accuracy of the calculation and should be accounted for if possible.
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The density of a solid or liquid material divided by the density of water is called
Answer:
I believe the answer is specific gravity
Explanation:Hope this helps :)
Observe the picture of the various components and processes that contribute to the activation energy required to light a match
Which of the statements about these components and processes are true? Select all that apply.
Breaking the adhesion between the match head and the striking surface causes particle vibration.
The thermal energy of the vibrating particles on the head of the match is transferred from hot regions to cool regions.
The energy of vibration provides the activation energy required to light the match.
The thermal energy of the vibrating particles on the head of the match is transferred from cool regions to hot regions.
As the match head moves across the striking surface, its particles repel the surface.
The repulsive forces between the match head and the striking surface cause particle vibration.
As the match head moves across the striking surface, its particles adhere to the surface for a short period of time.
The activation energy required to light a match is obtained by the chemical energy transferred into the thermal energy. When the match stick and head are rubbed together, the friction force is developed and hence, lightning occurs.
Activation energy is the minimum amount of energy available for the chemical reaction to occur. It involves the Breaking of adhesion between the match head and the striking surface causing the particle to vibrate.
The energy of vibration provides the activation energy required to light the match. The thermal energy of the vibrating particles on the head of the match is transferred from cool to hot regions.
As the head moves across the striking surface, its particles adhere to the surface for a short period of time and produce heat and light energy.
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