a) A molecule of DNA contains 140 A bases, how many T bases will it contain?​ Plz help ❤️

Answer:

\(\Delta T=18.24\°C\)

Explanation:

Hello,

In this case, since the equation for computing the heat in terms of mass, specific heat and temperature change is:

\(Q=mCp\Delta T\)

For the given heat and mass, and considering the specific heat of iron to be 0.444 kJ/(kg°C), the resulting temperature change is:

\(\Delta T=\frac{Q}{mCp}=\frac{97.2kJ}{12.0kg*0.444\frac{kJ}{kg\°C}}\\ \\\Delta T=18.24\°C\)

Best regards.

Answer:

8

Explanation:

Answer:

Answer: 3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms . Explanation: The relationship between atoms and moles is:. 1 mole atom. =6.022

Answer:

\(\boxed {\sf 5.63 \times 10^{24} \ atoms \ Li}}\)

Explanation:

We are asked to find how many atoms are in 9.35 moles of lithium (Li)

Moles are converted to atoms using Avogadro's Number or 6.022×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of lithium.

We convert using dimensional analysis, so we set up a conversion factor using Avogadro's Number.

\(\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)

We are converting 9.35 moles of lithium to atoms, so we multiply the conversion factor by this value.

\(9.35 \ mol \ Li *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 \ mol \ Li}\)

The units of moles of lithium cancel.

\(9.35 *\frac {6.022 \times 10^{23} \ atoms \ Li}{1 }\)

\(9.35 *{6.022 \times 10^{23} \ atoms \ Li}\)

\(5.63057\times10^{24} \ atoms \ Li\)

The original value of moles (9.35) has 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 0 in the thousandth place tells us to leave the 3 in the hundredth place.

\(5.63 \times 10^[24} \ atoms \ Li\)

9.35 moles of lithium contains approximately 5.63×10²⁴ atoms of lithium.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

1.68 mol Ca(NO₃)₂

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

[Given] 275 g Ca(NO₃)₂

[Solve] mol Ca(NO₃)₂

Step 2: Identify Conversions

[PT] Molar Mass of Ca: 40.08 g/mol

[PT] Molar Mass of N: 14.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of Ca(NO₃)₂: 40.08 + 2[14.01 + 3(16.00)] = 164.10 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.67581 mol Ca(NO₃)₂ ≈ 1.68 mol Ca(NO₃)₂

Answer:

1.68 mol Ca(NO₃)₂

Explanation:

Using prefix conversions. 68.9 meters (m)  is equal to 68.9 × 10⁷ micrometer.

deci - 10

centi - 100

milli - 1000

micro - 1,000,000

A prefix conversions. is a phrase component brought to the start of a word that modifications the word's meaning A suffix is a word part added to the giving up of a phrase that adjusts the word's which means mastering the meanings of prefixes and suffixes will assist in enlarging .

One milligram is one-thousandth of a gram and 1000 micrograms. A milligram is typically abbreviated as mg. One microgram is one-millionth of a gram and 1000th of a milligram. it also includes abbreviated as mcg or ug.

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Answer:

a) 2,4-dinitrobenzoic acid: the most acidic compound, p-nitrobenzoic acid: _______, p-bromobenzoic acid: the least acidic compound

b) oxalic acid: the most acidic compound, acetic acid: the least acidic compound, formic acid: _______.

c) p-cyanobenzoic acid: the least acidic compound, benzoic acid: the most acidic compound, p-aminobenzoic acid: _______.

Explanation:

a) 2,4-dinitrobenzoic acid is the most acidic compound of this set because it has two strong electronegative substituents (nitrogen dioxide) which increases the acidity of benzoic acid, while p-bromobenzoic acid is the least acidic compound because bromine is a weaker electron withdrawing group than nitrogen dioxide.

b) The presence of 2 -COOH group makes Oxalic acid the most acidic compound of this set, while decrease in acidity of carboxylic acid due to the presence of methyl group on carbon of -COOH group makes acetic acid the least acidic compound of this set.  

(c) Benzoic acid has a higher acid dissociation constant value (4.45 Ka) therefor it is the most acidic compound of this set, while p-cyanobenzoic acid is the least acidic compound of this set as it has the least acid dissociation constant value (16 Ka).

Answer:

a is oxidation

b is reduction

c is reduction

d is oxidation

hope it helps you

When the precipitate is washed, dried and weighed, then the percent by mass of silver in the alloy is 100%.

First, we need to determine the mass of the silver in the precipitate. We can do this by subtracting the mass of the filter paper from the mass of the filter paper and dried precipitate:

mass of precipitate = (mass of filter paper and dried precipitate) - (mass of filter paper)

mass of precipitate = 1.9332 g - 0.50000 g = 1.4332 g

Since all the silver in the alloy was converted to silver ions and then precipitated as silver chloride, the mass of silver in the precipitate is equal to the mass of silver in the original alloy. Therefore, the percent by mass of silver in the alloy is:

percent by mass of silver = (mass of silver / mass of alloy) x 100%

We just need to solve for the mass of silver. We know that the mass of the alloy was 4.3148 g, so the mass of silver must be:

mass of silver = mass of alloy - mass of other elements

Since we're assuming the alloy is pure silver and other elements, we can simply subtract the mass of the other elements from the mass of the alloy to get the mass of silver. We don't have information about the mass of other elements, but we can assume it's small enough to be negligible.

So, we have:

mass of silver = 4.3148 g - 0 g (assumed negligible) = 4.3148 g

Now we can calculate the percent by mass of silver:

percent by mass of silver = (mass of silver / mass of alloy) x 100%

percent by mass of silver = (4.3148 g / 4.3148 g) x 100%

percent by mass of silver = 100.00%

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Answer:

50 Seconds

Explanation:

400 Divided By 8 Is 50

Answer:

50

Explanation:

Its 50 because 400/8=50

Answer:

so I can do it tomorrow

Explanation:

3(+7-(#679''78()

wag nyo na po pansinin yung nasa taas bwahahahaha

The mass of 0.550 mol of methanol, CH3OH, is 17.6 g

To find the mass of 0.550 mol of methanol, CH3OH, we need to use the molar mass of CH3OH. The molar mass is the sum of the atomic masses of each element in the molecule, which can be found on the periodic table.
For CH3OH, we have:

- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol (there are 4 hydrogen atoms in CH3OH)
- Oxygen (O): 16.00 g/mol

So the molar mass of CH3OH is:

12.01 g/mol + (1.01 g/mol x 4) + 16.00 g/mol = 32.04 g/mol

This means that one mole of CH3OH weighs 32.04 grams.

To find the mass of 0.550 mol of CH3OH, we can use the following formula:

mass = number of moles x molar mass

So the mass of 0.550 mol of CH3OH is:

0.550 mol x 32.04 g/mol = 17.62 g

Rounding this to three significant figures gives us:
17.6 g

Therefore, the mass of 0.550 mol of methanol, CH3OH, is 17.6 g (rounded to three significant figures).

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Bromine has larger ionic radius and atomic radius than fluorine.

Fluorine has larger ionisation energy and electronegativity than bromine.

Halogen are those elements that are found in group 7 of the periodic table.

Fluorine is in period two of the periodic table, meaning that it contains electrons in only the first two energy levels at ground state. It has a higher ionization energy and electronegativity than bromine.

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Indicate whether fluorine or bromine has a larger value for each of the following properties. a. electronegativity b. ionic radius c. atomic radius d. ionization energy

Answer:

I havent the foggiest.

Explanation:

Answer:

Explanation:

I havent the foggies

Explanation:

Cameron Herrin has killed a mother and her baby on a highway in Tampa, Florida

on 2018 on a illegal race

The volume of the metal bar should be reported in two significant figures and the density of the metal bar should be reported in two significant figures.

Significant figures are used to create numbers that can be written in the form of digits. We can find the number of significant digits by counting the values from the first non-zero digit placed on the left.

In the case of division or multiplication, the number of the significant digit should be the same as the value with the fewest significant digits figures.

Given the sides of the metal bar, a = 2.5 cm , b = 1.25 cm and c = 5.30 cm

The volume of the metal bar = 2.5 ×1.25 × 5.30 = 16.5625 cm³

The fewest significant figures in the dimension are two. Therefore, the volume of the metal bar will be written in 2 significant figures.

The volume in the metal bar = 17 cm³

Given the mass of the bar is equal to 104.72 g.

The density of the metal bar = 17 cm³

The density of bar = mass/volume = 104.72/17 = 6.16 g/cm³

The density of metal bar  = 6.2 g/cm³   (2 significant figures)

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In studying the influence of environmental pH on peroxidase activity, researchers can repeat the experiment without guaiacol, which will reveal the effect of guaiacol on reaction rates.

One of the investigators' proposal to use oxygen gas production to measure reaction rates leads to a change in the dependent variable.

In the first experiment the dependent variable was the volume of guaiacol and in the second experiment the dependent variable will be oxygen production.

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Answer:

E. More people from African American ethnic group is affected by AIDS than other groups.

Explanation:

because it is supported by the data provided in the circle graph. The graph shows that 48% of new AIDS cases in 2000 were in the African American population, while only 31% were in the white population and 20% were in the Hispanic population. This indicates that a disproportionate number of African Americans were affected by the AIDS epidemic in 2000. While option D "Many people are still misinformed about the severity of AIDS" is a possible conclusion, but it is not directly stated or implied by the data provided in the graph.

Answer:

(a) \(Cu^{2+}S^{2-}\): copper (II) sulfide or cupric sulfide.

(b)  \(Ag^+_2(SO_4)^{2-}\): silver sulfate.

(c) \(Al^{3+}(ClO_3)_3^-\): aluminum chlorate.

(d) \(Co^{2+}(OH)^-_2\): cobalt (II) hydroxide.

(e) \(Pb^{2+}(CO_3)^{2-}\): lead (II) carbonate.

Explanation:

Hello,

In this case, we proceed by exchanging the subscripts between the cation and anion for each case as follows:

(a) CuS: cation is cupper (II) and anion is sulfide, thus the name is copper (II) sulfide or cupric sulfide.

\(Cu^{2+}S^{2-}\)

(b) Ag₂SO₄: cation is silver ion and anion is sulfate, thus the name is silver sulfate.

\(Ag^+_2(SO_4)^{2-}\)

(c) Al(ClO₃)₃: cation is aluminum ion and anion is chlorate, thus the name is aluminum chlorate.

\(Al^{3+}(ClO_3)_3^-\)

(d) Co(OH)₂: cation is cobalt (II) and anion is hydroxide, thus the name is cobalt (II) hydroxide.

\(Co^{2+}(OH)^-_2\)

(e) PbCO₃: cation is lead (II) and anion is carbonate, thus the name is lead (II) carbonate.

\(Pb^{2+}(CO_3)^{2-}\)

Regards.

Answer:

B

Explanation:

information about elavation and slope! i am correct

Answer:

True

Explanation:

The S-P difference (sec) is used to calculate the distance (km) between an earthquake epicenter and a seismic station, while the magnitude (M) is a measure of the energy released during the earthquake.

These parameters are important for understanding the severity and impact of an earthquake, as well as for predicting future seismic activity.

The S-P difference (sec) refers to the time difference between the arrival of the primary (P) waves and the secondary (S) waves at a seismic station. This time difference is used to calculate the distance (km) between the earthquake epicenter and the seismic station, using the equation: distance (km) = S-P difference (sec) x 8 km/sec. This calculation assumes that the waves travel at a constant speed through the Earth's interior.
The magnitude (M) of an earthquake is a measure of the energy released during the earthquake, and is usually determined using a seismometer. The magnitude scale is logarithmic, meaning that each increase of one unit represents a tenfold increase in seismic energy. For example, an earthquake with a magnitude of 5.0 is ten times more powerful than one with a magnitude of 4.0, and 100 times more powerful than one with a magnitude of 3.0.

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The correct order of the five steps of the scientific method is as follows:

State problem

Form hypothesis

Conduct experiment

Interpret data

Draw conclusion.

The scientific method is a systematic approach used by scientists to investigate and understand the natural world. The five steps of the scientific method, in their logical order, are as follows:

State problem: In this step, the scientist identifies and defines a specific question or problem to be investigated. The problem should be clear and well-defined to guide the rest of the scientific process.

Form hypothesis: A hypothesis is a proposed explanation or prediction for the problem stated in step one. It is an educated guess that can be tested through experiments and observations. The hypothesis should be based on prior knowledge and observations.

Conduct experiment: In this step, the scientist designs and performs experiments to test the hypothesis. The experiment is carefully planned and executed, and data is collected through observations and measurements.

Interpret data: Once the experiment is completed, the scientist analyzes the collected data. This involves organizing, graphing, and statistically analyzing the data to identify patterns and trends.

Draw conclusion: Based on the interpretation of the data, the scientist draws conclusions about whether the hypothesis is supported or not. The conclusions should be objective and supported by evidence obtained from the experiment.

It's important to note that while these steps are presented in a linear order, the scientific process is often iterative, with scientists revisiting and refining hypotheses, conducting further experiments, and building upon existing knowledge.

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At 2861 degree Celsius the iron begins to boil. At 1,538 °C the substance begins to melt.

The melting point is the point at which the liquid and solid forms of a solid can exist in equilibrium. It can also be defined as the point at which a solid changes into a liquid under normal atmospheric pressure.

The equilibrium point at which water vapor, liquid water, and solid ice can exist in equilibrium is the only point at which the pressure and temperature of water vapor are the same. The equilibrium point of water vapor is the point at which the partial vapor pressure is the same as that of liquid water at the exact temperature of 273.1600 K.

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Answer:

  -172.6 °C

Explanation:

You want to know the Celsius equivalent of the temperature 100.6 K.

The relation is ...

  C = K - 273.15

  C = 100.6 -273.15 = -172.55

The temperature is -172.55 °C, about -172.6 °C.

__

Additional comment

We have rounded to tenths, because that is precision of the temperature given. If you use 273 as the conversion constant, you will get -172.4.

Metallic bonds occur amid metal atoms. Whereas ionic bonds combine metals with non-metals, metallic bonding fixes several metal atoms.

An ionic bond is formed by joining a metal and a nonmetal, while a covalent bond is formed by allying two nonmetals. So we check the periodic table to see if our compound is made up of metals or nonmetals, or of two nonmetals.

Covalent compounds are built when two nonmetals react with each other. Since hydrogen is a nonmetal, binary compounds that carry hydrogen are also usually covalent compounds. Metallic elements produced compounds with non-metallic elements with the help of ionic bonds.

So we can conclude that In metals, the electrons leave the outer shells of metal atoms, devise positive metal ions and a 'sea' of delocalized electrons.

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The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.

The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.

Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:

moles = mass / molar mass

Substituting the values:

moles = 27.5 g / 63.55 g/mol

moles ≈ 0.433 mol

Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.

To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.

The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.

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