A baker made 15 loaves of bread from 3 pounds of flour. Each loaf had the same amount of flour. How many pounds of flour were used to make each loaf?

Answer:

I need more to the question so I can answer it

Step-by-step explanation:

The probability distribution of all possible values of the sample mean is called the sampling distribution of the mean.

What is meant by the sampling distribution of the mean?

Why is sampling essential and what does it mean?

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Answer:

This is what I think it is but im no good at this so sorry if it is wrong. XP

Step-by-step explanation:

y=4/7x

y*7= 4/7*7x

y*7=4x

7y/4x = 4x/4x

7y/4x=0

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Given:

Trisha uses 3 cups of sugar for every 2 teaspoons of baking soda to make a batch of cookies.

To find:

The equation that she should use to find the number of teaspoons of baking soda, x, needed if she uses 9 cups of sugar.

Solution:

Let the number of teaspoons of baking soda be x, that is needed if she uses 9 cups of sugar.

For every 2 teaspoons of baking soda Trisha uses 3 cups of sugar.

For every 1 teaspoons of baking soda Trisha uses \(\dfrac{3}{2}\) cups of sugar.

For every x teaspoons of baking soda Trisha uses \(\dfrac{3}{2}x\) cups of sugar.

Since she uses 9 cups of sugar for every x teaspoons of baking soda, therefore,

\(\dfrac{3}{2}x=9\)

Multiply both sides by 2.

\(3x=18\)

Divide both sides by 3.

\(x=6\)

Therefore, the required equation is \(\dfrac{3}{2}x=9\) and the number of required teaspoons of baking soda is 6.

Answer:

can u plz put a picture

Step-by-step explanation:

Answer:

I think it’s D not sure tho

Step-by-step explanation:

Answer:

90 more minutes

Step-by-step explanation:

108÷12=9

9x13=117

9x9=81

117-108=9

81+9=90 more minutes

Answer:

90

Step-by-step explanation:

Using an average credit card amount of $500 and an annual percentage rate of 18%, the monthly interest payment is $7.5.

It is possible to calculate the monthly interest payment as follows:

I = \(\frac{PNR}{100}\)

Given P = 500, N = 1, R = 18%

\(I = \frac{500*1*18}{100}\)

\(I = \frac{9000}{100}\)

\(I = 90\)

Yearly Interest is $\(90\)

Monthly interest :

\(M.I = \frac{18}{12}\)

\(M.I = 1.5%\)

Monthly interest payment = $\(500*1.5\)= $\(7.5\)

Monthly interest payment:

The percentage of the monthly payment earmarked for paying off the loan charge is referred to as the monthly interest payment.

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Now, According to the question:

The function of F5 is:

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Answer:

-1 and -2

Step-by-step explanation:

The function 2 represented by the equation f(x) = -(x - 2)² + 5 has the larger maximum.

Function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable.

The functions are given as:

Function 1

f(x) = -(x - 4)² + 1

Function 2:

f(x) = -(x - 2)² + 5

A quadratic function is represented as a (x - h)² + k, when a is negative then, the vertex of the function is a maximum. In both functions, the value of a is -1. This means that both functions are at a maximum

The values of k in both functions are k = 1 and k = 5. By comparison, 5 is greater than 1. Therefore, function 2 has larger maximum.

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complete question;

The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater maximum value, and provide the ordered pair. Function 1 graph of function f of x equals negative x squared plus 8 multiplied by x minus 15 Function 2 f(x) = −x2 + 2x − 15 Function 1 has the larger maximum at (4, 1). Function 1 has the larger maximum at (1, 4). Function 2 has the larger maximum at (−14, 1).

Answer:

x=7

y=0

Step-by-step explanation:

you can solve by using subsitution.

(2*7)-(9*0)=14

7=(-6*0)+7

Pls mark brainliest. thx have a nice day.

The expression \(m^{2}\) * \(m^{(3/2)}\) * \(m^{2}\) simplifies to \(m^{(3/2)}\).

What is an algebraic expression?

An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations. It may also include exponents and/or roots. Algebraic expressions are used to represent quantities and relationships between quantities in mathematical situations, often in the context of problem-solving.

The expression can be simplified using the laws of exponents. According to the law of exponents, when we multiply two powers with the same base, we can add their exponents:

m² * \(m^{3/2}\) * \(m^{-2}\)

= \(m^{(2 + 3/2 - 2)}\) (using the law of exponents for multiplication)

= \(m^{3/2}\)

Therefore, the expression \(m^{2}\) * \(m^{(3/2)}\) * \(m^{2}\) simplifies to \(m^{(3/2)}\).

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Answer:

your answer should 1\3x

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

attached

Answer:

X=-4 Y= 5

Step-by-step explanation:

solving the equation simultaneously

4X+7Y = 19-------------(1)

Y- X = 9-------------(2)

from equation (2),

Y = 9+X ----------------(3)

substituting equation (3) into equation (2)

4X+7(9+X)=19

removing bracket

4X+63+7X= 19

11x = 19-63

11X = -44

X= -44/11

X= -4

put X equal- 4 into equation (3)

Y= 9+-4

Y= 5

therefore, X= -4 Y = 5

therefore,

Answer:

D not possible.........

Answer:

9

Step-by-step explanation:

27:

1,3,9, 27

18:

1,2,3,6,9, 18

Answer:

9

Step-by-step explanation:

3 27 2 18

3 9 3 9

3 3 3 3

1 1

27=3×3×3×1

18=2×3×3×1

H.C.F= 3×3×1

=9. ans.

The difference in volume between the two pyramids is 12,371,740 cubic feet.

To find the volume of a square pyramid, you use the formula :

V = (1/3)Bh, where B is the area of the base and h is the height.

Using the dimensions given in the table, we can calculate the volumes of the two pyramids:

- Volume of Bent Pyramid = (1/3)(619 feet * 619 feet)(332 feet) = 26,384,053.33 cubic feet
- Volume of Red Pyramid = (1/3)(722 feet * 722 feet)(341 feet) = 38,755,793.33 cubic feet

To find the difference in volume between the two pyramids, we subtract the smaller volume from the larger volume:

38,755,793.33 - 26,384,053.33 = 12,371,740 cubic feet.

Rounding to the nearest cubic foot, the difference in volume between the two pyramids is 12,371,740 cubic feet.

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Answer:

x<7

Step-by-step explanation:

x+5<12

x<12-5

x<7

Answer:

We conclude that:

\(x+5<12\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<7\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:7\right)\end{bmatrix}\)

Please check the attached graph below.

Step-by-step explanation:

Given

The inequality expression is

\(x + 5 < 12\)

To determine

To solve the  inequality expression

Solving the inequality expression

\(x + 5 < 12\)

Subtract 5 from both sides

\(x+5-5<12-5\)

Simplify

\(x<7\)

Therefore, we conclude that:

\(x+5<12\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x<7\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:7\right)\end{bmatrix}\)

Please check the attached graph below.

The probability of an employee randomly selecting three white chocolates out of ten is 0.25028228759765625 or approximately 0.25. Probability is the possibility that an event will occur.

The formula for calculating probability is as follows: P(A) = n(A) / n(S), where n(A) represents the number of favorable outcomes and n(S) represents the number of possible outcomes.

In the case where an employee randomly selects a chocolate, records their selection, and returns the chocolate to the display, selecting 10 chocolates in this way, the possible number of outcomes is 4 * 10 = 40, where the 4 represents the total number of chocolate types and the 10 represents the total number of chocolate selected.

The formula for the binomial distribution is as follows: P(X = x) = \((nCx) p^x (1 - p)^(n - x)\), where n is the total number of trials, x is the total number of successes, p is the probability of success, 1 - p is the probability of failure, and nCx is the binomial coefficient of x in n.

Using the binomial distribution formula, the probability of selecting three white chocolates is:

P(X = 3) = (10C₃) (1/4)^3 \((3/4)^(10 - 3)\) P(X = 3)

= (120) (1/64) (27/64)P(X = 3)

= 0.25028228759765625

Therefore, the probability of an employee randomly selecting three white chocolates out of ten is 0.25028228759765625 or approximately 0.25.

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We will use Dirichlet's test to determine if the series converges. Let {an} and {bn} be the sequences defined as follows:

an = (-1)^(n+1) and bn = 1/n

Then, we can write the series as:

∑ (an * bn) = 1*(-1/1) - 1/2*(1/2) - 1*(-1/3) + 1/4*(1/4) + 1*(-1/5) - 1/6*(1/6) - ...

To apply Dirichlet's test, we need to show that:

The sequence {an} is bounded and monotonically decreasing.

The sequence of partial sums of {bn} is bounded.

For (1), note that |an| = 1 for all n and an is alternating in sign. Also, an+1 < an for all n, so {an} is monotonically decreasing.

For (2), note that the partial sums of {bn} are given by:

S_n = 1 + 1/2 + 1/3 + ... + 1/n

which is known as the harmonic series. It is well-known that the harmonic series diverges, but we can show that its partial sums are bounded as follows:

S_n = 1 + 1/2 + (1/3 + 1/4) + (1/5 + 1/6 + 1/7 + 1/8) + ... + (1/(2k-1) + 1/2k) + ... + 1/n

> 1 + 1/2 + 1/2 + 1/2 + ... + 1/2 + 1/n

= 1 + n/2n

= 3/2

Thus, the sequence of partial sums of {bn} is bounded by 3/2, and so Dirichlet's test implies that the series converges.

Therefore, the series 1 - 1/2 - 1/3 + 1/4 + 1/5 - 1/6 - 1/7 + ... converges.

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The canonical expression equivalent to sinusoidal model y(t) = 2 · sin (4π · t) + 5 · cos (4π · t) is y(t) = (√ 29) · sin (4π · t + 0.379π) .

Herein we have a simple harmonic motion model represented by a sinusoidal expression of the form y(t) = A · sin (C · t) + B · cos (C · t), which must be transformed into its canonical form, that is, y(t) = A' · sin (C · t + D). We proceed to perform the procedure by algebraic and trigonometric handling.

The amplitude of the canonical function is determined by the Pythagorean theorem:

A' = √(2² + 5²)

A' = √ 29

The angular frequency C  is the constant within the trigonometric functions from the non-canonical formula:

C = 4π

Then, we find the initial position of the weight in time: (t = 0)

y(0) = 2 · sin (4π · 0) + 5 · cos (4π · 0)

y(0) = 5

And now we calculate the angular phase below: (A' = √ 29, C = 4π, y = 5)

5 = √ 29 · sin (4π · 0 + D)

5 / √ 29 = sin D

D ≈ 0.379π rad

The canonical expression equivalent to sinusoidal model y(t) = 2 · sin (4π · t) + 5 · cos (4π · t) is y(t) = (√ 29) · sin (4π · t + 0.379π) .

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The function g(x) satisfies condition of the main statement on convergence of the FPI from the lecture notes on the closed interval [VA, A],

Given:

                     \(x^3 = A, \\x.x^2 = A \\x= A/x^2.\)

Adding 2x on both side.

                     \(3x=2x+\frac{A}{x^2} \\x= \frac{1}{3} (2x+\frac{A}{x^2} )\)

This is reduction of cube root of A to fixed point problem.

b).                  \(g(x)=\frac{1}{3} =(2x+\frac{A}{x^2} )\)

Given closed interval [A^1/3, A].

                      \(g(x)=\frac{1}{3} =(2-\frac{2A}{3x^3} )\\\)

g'(x) is also continuous in [A^1/3, A]

                      \(|g'(A^\frac{1}{3})|= \frac{1}{3} (2-\frac{2A}{A} )=0\)

                                   \(=|\frac{2}{3} -\frac{2}{3A^2} |\)

Given A > 1

                                   \(=|\frac{2}{3} -\frac{2}{3A^2}| < 1\)

Therefore, g(x) satisfies condition of the main statement on convergence of the FPI from the lecture notes on the closed interval [VA, A],

                                          \(x_{n+1} = g(x_{n )\)

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The graph of f(x) = x in a straight line passing through the origin (0,0) and  at an angle of 45 degrees to the x axis. It increases from left to right.

What is graph?

In discrete mathematics, a graph is made up of vertices—a collection of points—and edges—the lines connecting those vertices. In addition to linked and disconnected graphs, weighted graphs, bipartite graphs, directed and undirected graphs, and simple graphs, there are many other forms of graphs.

A simple graph is one in which no two vertices are connected by more than one edge, and no edge begins or finishes at the same vertex. In other terms, a simple graph is one that doesn't have loops or many edges.

Reflection in the x axis  will convert all positive values of f(x) to negative values of f(x)  and vice versa.  

g(x)  = - x     and is a straight line passing through origin  at angle of 45 degrees but the slope descends from left to right.

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9514 1404 393

Answer:

  C

Step-by-step explanation:

The subscript (n-1) is used to indicate the term previous to term (n). In this sequence, each term is 0.5 more than the previous term, so the recursive relation ...

  \(a_n=a_{n-1}+0.5\)

is the appropriate one. This matches choice C.

__

Additional comment

Of course, if the next term is 0.5 more than the last, then the previous term is 0.5 less than the present one. The sequence can be described in this "backward" fashion by the recursive relation of choice A. While that does work to describe the sequence, it is usually not the form we desire for a recursive relation.

The maximum rectangular area that can be fenced can be

2499 sq meters.

We know the perimeter of any 2D figure is the sum of the lengths of all the sides except the circle and the area of a rectangle is the product of its length and width.

We know for a quadrilateral, A square has the maximum area.

We also know That the product of two numbers is maximum when the difference between them is minimum.

Given, A farmer has 2,000 meters of fencing and wants to use it to create a rectangular area for grazing.

So, 2(l + b) = 2000.

l + b = 1000.

For a square, it would be 500 and 500, But to be a rectangle it can be 49 and 51.

Therefore, The maximum area would be,

= (51×49) sq meters.

= 2499 sq meters.

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Answer:

down by 1 units

right/left by 4 units

Answer:

down by 1 units

right/left by 4 units

Step-by-step explanation:

The logistic differential equation for the hyena population is given by:

dP/dt = r * P * (1 - P/K)

where P(t) is the hyena population at time t, r is the growth rate, and K is the carrying capacity.

We are given that:

P(t) = 40 + k * e^(-0.57t)

K = 200

To determine the value of k, we can plug in these values into the logistic differential equation and solve for k:

dP/dt = r * P * (1 - P/K)

dP/dt = r * P * (1 - P/200)

dP/dt = r/200 * (200P - P^2)

dP/(200P - P^2) = r dt

Integrating both sides, we get:

-1/200 ln|200P - P^2| = rt + C

where C is a constant of integration.

Using the initial condition P(0) = 40 + k, we can solve for C:

-1/200 ln|200(40+k)-(40+k)^2| = 0 + C

C = -1/200 ln|8000-480k|

Plugging in this value of C and simplifying, we get:

-1/200 ln|200P - P^2| = rt - 1/200 ln|8000-480k|

ln|200P - P^2| = -200rt + ln|8000-480k|

|200P - P^2| = e^(-200rt) * |8000-480k|

200P - P^2 = ± e^(-200rt) * (8000-480k)

Since the population is increasing, we choose the positive sign:

200P - P^2 = e^(-200rt) * (8000-480k)

Using the initial condition P(0) = 40 + k, we get:

200(40+k) - (40+k)^2 = (8000-480k)

8000 + 160k - 2400 - 80k - k^2 = 8000 - 480k

k^2 + 560k - 2400 = 0

(k + 60)(k - 40) = 0

Thus, k = -60 or k = 40. Since k represents a growth rate, it should be positive, so we choose k = 40. Therefore, the value of the constant k is option (A) 4.

For the second part of the question, the logistic equation that could model the growth in the graph is option (B) dM/dt = (20-M)*(M-50). This is because the carrying capacity is between 20 and 50, and the population growth rate is zero at both of these values (i.e. the population does not increase or decrease when it is at the carrying capacity).

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Answer:

Myron would need 7.2 hours to cook 3 kilograms of meat.