a ball is thrown upward at an angle what causes the change in the balls velocity?

The speed of the river is 0.5 Km/hr

Let X be the speed of the boat.

Let Y be the speed of the river.

Downstream speed

X - Y = 4

Upstream speed

X + Y = 5

By solving, we get

2X = 9

X =  4.5 Km/hr

Y =  0.5Km/hr

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Answer:

4500 joules

Explanation:

since work(joules) = force(newtons) x distance(meters),

150N x 30M = 4500 Joules

Answer:

4500 joules

Explanation:

150 N x 30 M = 4500 joules

The critical angle of the transparent material is 35.3 degrees.

The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:

sin(critical angle) = sin(90 degrees) / sin(angle of refraction)

sin(critical angle) = 1 / sin(32 degrees)

sin(critical angle) = 0.574

critical angle = arcsin(0.574)

critical angle = 35.3 degrees

Therefore, the critical angle of the transparent material is 35.3 degrees.

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Answer:

25.506J

Explanation:

Ep = mgh

given that ,

m = 2kg

h =1.3m

g = 9.81 m/s^2

Ep= 2 × 1.3 × 9.81

Ep= 25.506J

Answer:

answer a

Explanation:

while any machine is working, there are some forces (f.e. friction) that are still calculating.

Good luck

Answer:

Q = N e     total charge passing point

Q = 2.0E20 * 1.6E-19 coul = 32 coulombs

2)    I = Q / t = 32 C / 60 s = .53 amps

3)   R = V / i = 12 volts / .53 amps = 23 ohms

Answer:

4 kilograms

Explanation:

The minimum deadband setting is the point that causes the least sensing bulb temperature change while the system is running.

The minimum setpoint is the specific value that results in the smallest change in the temperature of the sensing bulb when the system is in operation. It is a critical parameter that determines the stability and efficiency of the system. The deadband refers to the range of temperatures within which no action is taken by the system. By setting a minimum deadband, the system minimizes unnecessary temperature adjustments, reducing the frequency and magnitude of temperature fluctuations. This ensures stable and efficient operation by avoiding constant switching on and off of heating or cooling mechanisms. The minimum deadband setting is crucial in achieving a balance between maintaining temperature stability and minimizing energy consumption, ultimately optimizing the performance of the system.

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Answer:

The strength of drag can be found by using the drag equation:

Drag = 1/2 * air density * velocity^2 * drag coefficient * reference area

where air density is the density of the fluid (air, water, etc.), velocity is the speed of the object moving through the fluid, drag coefficient is a dimensionless number that depends on the shape and roughness of the object, and reference area is the area that is normal to the direction of the fluid flow. To find the strength of the drag, you need to know these values and plug them into the equation.

Explanation:

A) The elastic potential energy stored in the spring is 25 J. B) The speed of the mass as it passes through the equilibrium point is 2.58 m/s.

A) To find the elastic potential energy stored in the spring, use the formula:
Elastic potential energy (PE) = (1/2)kx^2
Where k is the spring constant (500 N/m) and x is the displacement from the equilibrium length (0.1 m).
PE = (1/2)(500)(0.1)^2
PE = 25 J
B) The elastic potential energy will be converted to kinetic energy when the spring is released. Use the formula:
Kinetic energy (KE) = (1/2)mv^2
Where m is the mass (0.75 kg) and v is the velocity.
Since PE = KE, we can find the velocity:
25 J = (1/2)(0.75 kg)v^2
Solve for v:
v = 2.58 m/s

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The region of the ultraviolet spectrum absorbed least by the atmosphere is UVC.

UVC radiation, with wavelengths between 100 and 280 nanometers, is mostly absorbed by the Earth's atmosphere, specifically by the ozone layer. This absorption prevents UVC radiation from reaching the Earth's surface in significant amounts. On the other hand, UVA and UVB radiation are partially absorbed by the atmosphere, but they still reach the Earth's surface to varying degrees. UVA has longer wavelengths (315-400 nm) and is less absorbed than UVB, which has shorter wavelengths (280-315 nm). However, it's important to note that excessive exposure to both UVA and UVB radiation can have harmful effects on human health, such as skin damage and an increased risk of skin cancer. Therefore, it's crucial to protect oneself from UV radiation by using sunscreen, wearing protective clothing, and seeking shade when necessary.

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The capacitance between the two metal plates separated by a 0.21-mm-thick piece of Teflon is approximately 8.85 pF.

To provide an explanation, capacitance is the ability of a system to store electric charge.

It is directly proportional to the surface area of the plates and inversely proportional to the distance between them.

In this case, the surface area of each metal plate is 4.2 cm × 4.2 cm, which gives a total area of 35.28 cm².

The distance between the plates is given as 0.21 mm, or 0.021 cm.

Using the formula for capacitance, C = ε₀A/d, where ε₀ is the permittivity of free space, we can calculate the capacitance to be approximately 8.85 pF.

In summary, the capacitance between the two metal plates separated by a 0.21-mm-thick piece of Teflon is approximately 8.85 pF. This is determined by the surface area of the plates and the distance between them, using the formula C = ε₀A/d.

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

When a person with normal vision looks at an object 10m away, the image is formed clearly on the retina. The reason is that the eye has an optical power of 60 diopters. Therefore, a person with normal vision can see an object 10 meters away clearly.

Optical power refers to the ability of a lens to bend light. It is measured in diopters (D). The greater the diopter, the greater the lens's ability to bend light. The human eye's lens and cornea both contribute to its optical power.The cornea contributes around 43 diopters, while the lens contributes the remaining 17 diopters. The human eye's total optical power is usually about 60 diopters.A person with normal vision has an optical power of 60 diopters. When they look at an object 10m away, the image is formed clearly on the retina. The reason is that the eye has an optical power of 60 diopters.

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Answer:

What I put- This will affect animals, the earth, and could affect future generations. Plastic also gets into the oceans causing sea creaters die by eating it.

Sample Answer- Problems that arise from the unavailability of natural resources and from environmental hazards will affect the generations that follow us.

Explanation:

Answer:

This will affect animals, the earth, and could affect future generations. Plastic also gets into the oceans causing sea creaters die by eating it.

Explanation:

Explanation:

tan ● = opposite / adjacent

tan 31.5 = 19 / F

0.613 = 19 / F

0.613F = 19

F = 31

sin ● = opposite / hypotenuse

sin 31.5 = 19 / a

0.52 = 19 / a

0.52a = 19

a = 36. 36

Using trigonometry, the base of the triangle is approximately 33.476, and the hypotenuse of the triangle is approximately 38.118.

To find the base and hypotenuse of a right triangle with one angle of 31.5 degrees and a given height of 19:

Here,

Opposite side = height = 19 (given)

Adjacent side = base (unknown)

Hypotenuse = hypotenuse (unknown)

First, let's find the base (adjacent side):

tan(θ) = opposite ÷ adjacent

tan(31.5 degrees) = 19/base

To find the base, we can rearrange the equation:

base = opposite ÷ tan(θ)

base = 19 ÷ tan(31.5 degrees)

Calculating the value:

base ≈ 33.476

So, the base of the triangle is approximately 33.476.

Now, using the Pythagorean theorem, we can write:

hypotenuse² = base² + opposite²

hypotenuse² = (33.476)² + 19²

hypotenuse ≈ 38.118

Therefore, the hypotenuse of the triangle is approximately 38.118.

Thus, base is 33.476, and hypotenuse is 38.118.

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a. Two conditions that can affect friction and traction are the type of surface and the presence of contaminants.

b. Loss of friction and traction can cause a car to slide, skid, or lose control.

Friction and traction are crucial for vehicle handling and control. Two conditions that can affect friction and traction are the surface condition and the tire condition.

Wet, icy, or uneven road surfaces can decrease friction and traction, while worn or improperly inflated tires can also reduce the ability to maintain traction.

Loss of friction and traction can result in a variety of handling issues, such as difficulty steering, reduced braking ability, and increased risk of skidding or sliding.

This can be particularly dangerous in adverse weather conditions or during sudden stops or turns, making it important for drivers to maintain their vehicles properly and adjust their driving habits to match the current road conditions.

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Answer:This could be in the form of using fewer energy services or using devices that require less energy.

Explanation:

The value of the diameter of the washer so that 45% of the diameters are greater is approximately 0.0161. The problem states that the diameter of a washer is normally distributed with a mean (μ) of 0.012 and a standard deviation (σ) of 0.0024.

We want to find the value of the diameter that corresponds to the top 45% of the distribution.

To find this value, we need to calculate the z-score corresponding to the top 45% of the distribution. The z-score represents the number of standard deviations a value is from the mean. We can use the z-table or a statistical calculator to find the z-score associated with a cumulative probability of 0.45.

In this case, the z-score is approximately 1.645. Using the formula z = (x - μ) / σ, we can rearrange it to solve for x (the diameter we are looking for).

x = μ + (z * σ)
x = 0.012 + (1.645 * 0.0024)
x ≈ 0.0161

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Answer:

C. An article written by a scientist

Explanation:

Research-based original articles written by a scientist can act as a primary source of information. Textbooks, dictionaries and encyclopedias are generally classified as secondary sources and are rarely primary sources.

Answer:

Minimum uniform acceleration in Km/hr² is 20,505.05 km/hr²

Explanation:

In other to determine the acceleration, we can use the formula below

acceleration = velocity/time

Time wasn't given in the question, hence we calculate for time using the parameters given and the formula below

Velocity= distance/time

time = distance/velocity

distance = 2000m ⇔ 2km

time = 2/203

time = 0.0099

Hence, we look for acceleration

which is

acceleration = 203/0.0099

= 20,505.05 km/hr² ⇔ 2.0 × 10⁴

Answer:

A

Explanation:

Wavelength is represented by lambda

a. The proper time (τ) is the time you observe, which is the time the searchlight blinks on for, given as 0.150 s.

b. The speed of the spacecraft relative to Earth is approximately 0.9999922 times the speed of light c

To determine the proper time and the speed of the spacecraft relative to Earth, we can use the concept of time dilation from special relativity. Let's denote the proper time as τ and the measured time on the spacecraft as t.

(a) To determine which of the measured times is the proper time, we need to find the time that would be measured by an observer at rest relative to the event. In this case, we assume that you, standing in your backyard, are at rest relative to the event.

Therefore, the proper time (τ) is the time you observe, which is the time the searchlight blinks on for, given as 0.150 s.

(b) To calculate the speed of the spacecraft relative to Earth, expressed as a fraction of the speed of light (c), we can use the time dilation formula,

t = γτ

where γ (gamma) is the Lorentz factor given by:

γ = 1 / √(1 - v²/c²)

Here, v represents the velocity of the spacecraft, and c is the speed of light.

We have t = 12.0 ms (converted to seconds) and τ = 0.150 s.

12.0 ms = γ * 0.150 s

γ = (12.0 ms) / (0.150 s)

= 80

To find the velocity v of the spacecraft relative to Earth, we rearrange the Lorentz factor equation,

γ = 1 / √(1 - v²/c²)

Squaring both sides of the equation, we have,

γ² = 1 / (1 - v²/c²)

Rearranging the equation to solve for v²/c², we get,

v²/c² = 1 - 1/γ²

= 1 - 1/80²

= 1 - 1/6400

= 6399/6400

To find v/c, we take the square root of both side,

v/c = √(6399/6400)

≈ 0.9999922

Therefore, the speed of the spacecraft relative to Earth is approximately 0.9999922 times the speed of light c.

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The momentum of a 3.81 μg particle moving at 1.83×108 m/s can be calculated using the formula p=mv, where p is the momentum, m is the mass, and v is the velocity. First, we need to convert the mass from micrograms to kilograms by dividing it by 10^9. So, the mass is 3.81x10^-9 kg. Then, we can substitute the mass and velocity values in the formula to get the momentum as follows: p = (3.81x10^-9 kg) x (1.83x10^8 m/s) = 6.97x10^-1 kg*m/s. Therefore, the momentum of the particle is 6.97x10^-1 kg*m/s.
Your question is: What is the momentum of a 3.81 μg particle moving at 1.83×10^8 m/s?

To calculate the momentum, we use the formula: momentum = mass × velocity. First, convert the mass from micrograms (μg) to kilograms (kg) by dividing by 1,000,000,000. So, 3.81 μg = 3.81 × 10^-9 kg. Now, multiply the mass (3.81 × 10^-9 kg) by the velocity (1.83 × 10^8 m/s) to find the momentum.

Momentum = (3.81 × 10^-9 kg) × (1.83 × 10^8 m/s) = 6.9773 × 10^-1 kg·m/s.
Therefore, the momentum of the particle is approximately 6.98 × 10^-1 kg·m/s.

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When the plane flies from the initial position to the final position, the given parameter show's the average velocity of the plane.

Average velocity of an object is defined as the change in position or displacement of the object with the given time period in which it is in motion.

Mathematically, the average velocity of an object is given as;

v = Δx / Δt

where;

The average velocity of an object increases with increase in the displacement of the object for a short period of time.

For a plane that flies from the given initial position to the final position at a speed of 925 km/hr, the given average velocity can be converted into meter per seconds

v = 925 km/hr

In meters per second the average velocity is determined as ;

v = 925 km/hr/3.6  = 256.94 m/s

Thus, when the plane flies the given initial position to the final position at a speed of 925 km/hr. The information provided is showing the plane's average velocity.

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Answer:

A wave would be absorbed continuously

A particle would be absorbed in a discrete amount

The photoelectric effect demonstrates the particle nature of the energy absorbed.

Option E is correct. The line spectra of elements may be utilized to identify the elements required to produce a line spectrum for each given element.

Each element has a distinct line spectrum that may be used as a fingerprint to identify the one that is present.

The following other claims made in the choices are false:

a. Components having a place with a similar family have different line spectra, though they really do have two specific shared characteristics.

b. The line spectra of the components are irrelevant to how they consolidate with oxygen.

c. An element's line spectra are unaffected by its physical condition.

d. Other techniques, including chromatography, are utilized to separate components from mixtures instead of using line spectra for that purpose.

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The question is -

Which of these characteristics is necessary to achieve a line spectra for any given element?

a. The line spectra of elements are the same provided they belong to the same family.

b. The line spectra of elements are the same provided they belong to the same family and are combined with oxygen.

c. The line spectra of elements are the same provided they belong to the same family and are in the same physical state.

d. The line spectra of elements can be used for the separation of elements from mixtures.

e. The line spectra of elements can be used to identify the elements.

Answer:

true

Explanation:

Answer:

yes

Explanation:

you don't learn it until high school

Answer: Refraction

Explanation:

Apparent brightness is a scale used primarily by ancient astronomers to determine how bright a star is as it appears from Earth.

The apparent brightness is how much energy is coming from the star per square meter per second as measured on Earth. Apparent  brightness depends on the location of the observer. Different observers will come up with a different measurement depending on their locations and distance from the star.

Therefore, Apparent brightness scale of 1-6 was used by astronomers to categorize observable stars in the night sky, with 1 being the brightest and 6 being the dimmest.

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