a ball player catches a ball 3.4 s after throwing it vertically upward. with what speed did he throw it, and what height did it reach?

Answer:

400 J

Explanation:

work done = force x distance

First convert 4000 m into metres = 4m

Then do 100N x 4m = 400

The net charge is 600 Coulombs. Q = I * t. Q is the charge and I is current and t is time period.

Thus, Where Q represents the total charge going through any point in the circuit, I represents the current flowing through it, and t represents the passage of time. Q = I * t

The time interval is 1 minute, which is equal to 60 seconds, and the current is specified as 10 A (amperes). Q = 10 A * 60 s. Q equals 600 Coulombs.

As a result, 600 coulombs of charge total flow through any location in the circuit within a 1-minute period.

Thus, The net charge is 600 Coulombs. Q = I * t. Q is the charge and I is current and t is time period.

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Answer:

0.2 hours

Explanation:

Answer:

10s to reverse velocity in opposite direction

Explanation:

Momentum = mass * velocity

The objects initial momentum therefore is 0.4*30=12Ns

Time = momentum / force

In order to stop the object's momentum, a force of 2N would thereforehave to be applied for 12/2=5s

In order to reverse the velocity of the object in the opposite direction, it would take twice this: 10s

Answer:

La fuerza que se ejerce entre las dos cargas es 2880 N.

Explanation:

La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

\(F=k*\frac{Q*q}{r^{2} }\)

donde:

En este caso:

Reemplazando:

\(F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{4*10^{-5} C*2*10^{-5}C }{(0.05 m)^{2} }\)

F= 2880 N

La fuerza que se ejerce entre las dos cargas es 2880 N.

We will determine the work as follows:

So:

So, the work done by the force of gravity is of 78.4 J.

The speedboat momentum is 19,500 kg.m/s.

We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by

P = m . v

where P is momentum (kgm/s), m is mass (kg) and v is velocity (m/s).

From the question above, we know that:

m = 1500 kg

v = 13 m / s

By substituting the given parameters, we can calculate the momentum

P = m . v

P = 1500 . 13

P = 19,500 kg . m / s

Hence, the speedboat momentum is 19,500 kg.m/s.

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Answer:19,500 kg

Explanation:your welcome!:)

Explanation:

electric current is the answer

Answer:

Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.

Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).

Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).

Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:

\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).

With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:

\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).

Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).

All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.

It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:

\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).

Solve for the displacement of the spring, \(x\):

\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).

Answer:

In chaos theory , the butterfly effect is the sensetive dependence on initial conditions in which a small change in one state of a deterministic nonlinear can result in large difference in a letter state.

If a person gets into the rowboat, the water level at the edge of the pool will rise slightly. This is because the weight of the person adds to the weight of the boat and displaces more water, causing the water level to rise.

The amount of the rise in water level will depend on the weight of the person and the size of the boat. Similarly, if objects are added to the boat, the water level at the edge of the pool will also rise. However, if the boat is empty and just floating in the pool, it will displace a certain amount of water and the water level at the edge of the pool will be at the marked level.

Overall, the water level in the pool is determined by the amount of water displaced by the rowboat and any additional weight that is added to it.

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Answer:

1.78 m/s

Explanation:

We again have to use the inelastic collision formula, which is m1*v1 + m2*v2 = (m1+m2)*vf. The question gives us m1 = 80kg, v1 = 4 m/s, and m2 = 100kg. Plugging this into the equation gets us: 80 * 4 = (80 + 100) * vf. Solving for vf, we get: vf = 320/180 = 1.78 m/s.

Answer:

v = 1.78 m/s

Explanation:

Momentum of the fisherman before = mass of the fisherman x velocity of the fisherman

= 80 kg x 4 m/s

= 320 kg·m/s

Momentum of the boat before = mass of the boat x velocity of the boat

= 100 kg x 0 m/s

= 0 kg·m/s

Total momentum before = Momentum of the fisherman before + Momentum of the boat before

= 320 kg·m/s + 0 kg·m/s

= 320 kg·m/s

Total mass after = mass of the fisherman + mass of the boat

= 80 kg + 100 kg

= 180 kg

Total momentum before = Total momentum after

320 kg·m/s = 180 kg x v

v = 320 kg·m/s / 180 kg

v = 1.78 m/s

The time lapse between when the bat emits the sound and when it hears the echo is 0.05 s.

From the question given above, the following data were obtained:

Velocity of sound (v) = 343 m/s

Distance (x) = 8.42 m

Time (t) =?

We can obtain obtained the time as illustrated below:

v = 2x / t

343 = 2 × 8.42 / t

343 = 16.84 / t

Cross multiply

343 ×  t = 16.84

Divide both side by 343

t = 16.84/343

t = 0.05 s

Thus, the time between  when the bat emits the sound and when it hears the echo is 0.05 s.

A bat emits a sound wave and carefully listens to the echoes that return to it. The returning information is processed by the bat's brain in the same way that we processed our shouting sound with a stopwatch and calculator. The bat's brain determines the distance of an object by measuring how long it takes for a noise to return.

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Correction question:

A bat emits a sonar sound wave (343 m/s) that bounces off a mosquito 8.42 m away. How much time elapses between when the bat emits the sound and when it hears the echo? (Unit = s)

Answer:

False

Explanation:

There are 3 states of matter, and all states have molecules. These molecules vibrate in different speeds, depending on the mass, weight, and stae off matter of the object.

Answer is A 2.8 x 10^-8 N, to the right

The net gravitational force on mass A due to masses B and C is required.

The correct option is a. \(2.8\times 10^{-8}\ \text{N}\) to the right.

G = Gravitational constant = \(6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2\)

\(r_{AB}\) = Distance between A and B = 0.4+0.1 = 0.5 m

\(r_{AC}\) = Distance between A and C = 0.1 m

\(m_A=m_B=m_c\) = Mass of each particle = 2 kg

The required force is

\(F_A=F_{AB}+F_{AC}\\ =\dfrac{Gm_Am_B}{r_{AB}^2}+\dfrac{Gm_Am_C}{r_{AC}^2}\\ =Gm^2\left(\dfrac{1}{r_{AB}^2}+\dfrac{1}{r_{AC}^2}\right)\\ =6.674\times 10^{-11}\times 2^2\left(\dfrac{1}{0.5^2}+\dfrac{1}{0.1^2}\right)\\ =2.8\times 10^{-8}\ \text{N}\)

The magnitude of force will be \(2.8\times 10^{-8}\ \text{N}\)

The direction will be towards the right since C is closer to A.

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Answer:it would make it thicker

Explanation:

Answer:

"The equation shows that the current in a circuit is inversely proportional to the resistance of the circuit. An increase in resistance would result in a decrease in current. And the factor by which the resistance increases is the same factor by which the current decreases."

Explanation:

Because it's just like wearing a glove/mitten when getting something out of the oven, because of the insulation from the glove/mitten, it reduces the heat that gets through into your hand, and it protects it. Just like what the "answer" says, it said that the resistance would decrease current.

Answer:

PLEASE BE MORE SPECIFIC

Explanation:

The pathfinder is currently 3.4 m away from its initial position. Speed can be defined by the change in position of the object over time.

What is Speed?

It can be defined by the change in position of the object over time. The distance can be calculated by the formula,

\(d = s \times t\)

Where,

\(d\)- distance

\(s\) - speed

\(t\) - times -

Initially, Pathfinder moves,

\(d = 0.2 \times 20 \\\\d = 4 \rm \ m\)

Then he turns back and moves,

\(d' = 0.2 \times 3 = 0.6 \rm m\)

So the current position is:

\(D = d - d'\\\\D = 4 - 0.6 \\\\D = 3.4\rm m\)

Therefore, the pathfinder is currently 3.4 m away from its initial position.

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Answer: The Hall effect is the movement of charge carriers through a conductor towards a magnetic attraction. The Hall effect causes a measurable voltage differential across the conductor such that one side is positively charged and the other negatively.

Explanation:

The weather map shows some conditions in the atmosphere at noon on a particular day OB. In the northeast

The atmospheric pressure is strongest at sea level and lowers as you ascend into the atmosphere. At sea level, typical air pressure ranges from 800 to 1050 millibars.

High-pressure regions are often areas of fair, stable weather. Low-pressure zones have a thin atmosphere. Winds sweep inward towards these regions. This causes the air to ascend, resulting in clouds and condensation.

Since warm air rises, areas with warmer air frequently have lower pressure. They are known as low pressure systems. High pressure systems are areas with high air pressure.

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Solution :

Given :

Wavelength of the thin beam of light, λ = 50 μm

Distance of the screen from the slit, D = 3.00 m

Width of the fringe, Δy = ±8.24 mm

Therefore, width of the slit is given by :

\($d=\frac{n \lambda D}{\Delta y}$\)

  \($=\frac{2 \times 50 \times 10^{-9} \times 3}{2 \times 8.24 \times 10^{-3}}$\)

  = 0.000018203 m

  = 0.0182 mm

  = 0.018 mm

The intensity of light is given by :

\($I=I_0\left(\frac{\sin \beta /2}{\beta/ 2}\right)^2$\)   , where \($\beta=\frac{2 \pi D \sin \theta}{\lambda}$\)

\($I=I_0\left(\frac{\sin \frac{\pi d \sin \theta}{\lambda}}{\frac{\pi d \sin \theta}{\lambda}}\right)^2$\)

\($I=I_0\left(\frac{\sin \frac{\pi d y}{D\lambda}}{\frac{\pi d y}{D\lambda}}\right)^2$\)

Now, \($\frac{dy}{D \lambda} = \frac{8.24 \times 10^{-3}\times 0.018 \times 10^{-3}}{4 \times 50\times 10^{-9}\times 4}$\)

               = 0.1854

               ≈ 0.18

\($I=I_0\left(\frac{\sin 0.56}{0.56}\right)^2$\)

  \($=I_0 \times 0.81$\)

  = 2  x0.81

  \($= 1.62 \ W/m^2$\)

Explanation:

distance = speed x time

a- d= 350 m/s x 30s

   d= 10500m

b- 5 mins = 300 sec

    d= 350 m/s x 300s

    d= 105000 m

c-  30 mins = 1800 sec

    d= 350 m/s x 1800 s

   d=  630000 m

Answer:

Option B is correct

Explanation:

acceleration is equal to rate of change of velocity.

Answer: <3

Explanation: ):

Final velocity - Velocity displacement

       Δv            a

2)    -12 m/s        -3 m/s2

3)     5 m/s        2.5 m/s2

What is the final and initial velocity?

1. Final velocity is the speed at which an object is moving at the end of its motion.

2. Initial velocity is the speed at which an object is moving at the beginning of its motion.

3. Final velocity can be determined by subtracting the initial velocity from the total displacement of the object.

4. Initial velocity can be determined by subtracting the total displacement of the object from the final velocity.

2) 0-12 = -12/4 = -3

3) 8-3 = 5/2 = 2.5

4) 46.4-27.3 = 19.1/11 = 1.73

5) 5-15 = -10/5 = -2

Therefore, the above one is the answer for this chart.

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Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.

Hope it helped! :>

Answer:

there are 22 massive, positively charged, fundamental particles in the element's nucleus. Given this, the element is unquestionably titanium.

The nucleus of titanium contains 46 particles in total in which 22 protons and 26 neutrons.

The atomic nucleus can be described as the small and dense region containing of protons and neutrons at the center of an atom. An atom is made of a positively charged nucleus, with electrons surrounding it, bound together by electrostatic force.

Almost all of the mass of an atom is concentrated in the nucleus as the mass of electrons is negligible. Neutrons and Protons are bound together to create a nucleus by the nuclear force.

The diameter of the nucleus is about 1.70 fm for hydrogen to about 11.7 fm for uranium. Protons and neutrons are fermions, are the particles present inside the nucleus.

The titanium has 22 protons and 26 neutrons in its nucleus so it has 46 particles in its atomic nucleus.

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The complete table by using the speed of light is

Time, t (sec)      Distance, d (km)

1                             299,792

2                            599,584

3                             899,377

4                          1,199,169

5                          1,498,961

Now, to complete this table, we need to use the relationship between distance, time, and speed. This relationship is given by the equation:

distance = speed x time

So, if we know the speed of light and the time elapsed, we can use this equation to calculate the distance traveled by a photon of light. Let's use this equation to fill out the table:

Time, t (sec) Distance, d (km)

1 299,792

2 599,584

3 899,377

4 1,199,169

5 1,498,961

As you can see, the distance traveled by a photon of light increases linearly with time, since the speed of light is constant. For example, in one second, a photon of light travels a distance of 299,792 kilometers. In two seconds, it travels twice that distance, or 599,584 kilometers.

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Answer:

The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.

Explanation:

Hope this helps!