A ball rolls off a flat roof and hits the ground 2 seconds later. The roof is ? meters high

Given data:

* The distance traveled by the air conditioner is,

Solution:

As the air conditioner is falling freely under the action of gravity.

Thus, the acceleration of the air conditioner is equal to the acceleration due to gravity.

As the air conditione ris falling itself from the height.

Thus, the initial velocity of the air conditoner is,

By the kinematics equation, the final velocity of the air conditioner is,

Substituting the known values,

Thus, the final velocity of the air conditioner is 21.69 m/s.

By the kinematics equation, the time taken by the air conditioner,

where t is the time taken by the air conditioner to reach the ground,

Substituting the known values,

Thus, the time taken by the air conditioner ot reach the ground is 2.21 seconds.

41.4 x 104 Nm2/C is the electric flux through the sheet.

The electric flux through a planar area A is calculated as the product of the electric field, the area of the plane, and the cosine of the angle between the electric field and a vector that is perpendicular to the area.

Φ = E A cos θ -----1  

By the question;

E = 4.6 x 10⁴ N/C

A = Area of the square = l²          [l = length of the square]

=> A = (3m)² = 9m²

θ = 0°    [since the electric field is perpendicular to the square sheet, then the area vector is parallel to the field]

Substitute the values in equation 1

Φ = 4.6 x 10⁴ x 9 x cos 0°

Φ = 4.6 x 10⁴ x 9 x 1

Φ = 41.4 x 10⁴ Nm²/C

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Answer:

Explanation:

Scientific modelling is a scientific activity, the aim of which is to make a particular part or feature of the world easier to understand, define, quantify, visualize, or simulate by referencing it to existing and usually commonly accepted knowledge.

True, the magnetic force F' is always perpendicular to the acceleration a of the particle.

True. According to the Lorentz force law, the magnetic force F' experienced by a charged particle moving in a magnetic field is given by F' = q(v × B), where q is the charge of the particle, v is its velocity, and B is the magnetic field.

Since the cross product v × B results in a vector perpendicular to both v and B, the magnetic force F' is always perpendicular to the velocity of the particle. Additionally, Newton's second law states that F' = ma, where m is the mass of the particle and a is its acceleration. Therefore, the magnetic force F' is always perpendicular to the acceleration a of the particle.

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Answer:

C

Explanation:

i belive it's C may i be marked brainleist

The two components of an internal force system are: • Normal force and

• Shear force

Normal force refers to the force that acts perpendicular to the surface of an object or a structural element. It is responsible for counteracting external loads and providing support.

Shear force, on the other hand, acts parallel to the surface of an object or a structural element. It is responsible for causing a deformation or shear stress within the material.

Bending moment, although an important factor in structural analysis, is not one of the two components of an internal force system. Bending moment refers to the internal force that causes a structural element to bend or undergo a moment about an axis.

Therefore, the correct answer is: Normal force, shear force.

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a) the black paper heats up the fastest, and the white paper heats up second fastest, then shiny metallised plastic film and the smooth white plastic film heats up slowest.

b) black paper will cool down slowest and smooth white plastic film will cool down quickest.

BUT! Neither the black paper nor the white paper is in intimate close contact with the steel block underneath each piece of paper - there is a very effective insulating layer of stagnant air between the bottom of the sheets of paper and the steel. BOTH sheets of paper shield the steel block from IR and visible radiation.

The two shields of plastic can be assumed to be closely contacting the top of the steel block, and so they will heat the steel blocks underneath them faster than the paper. The reflective plastic “might” have a greater emissivity than the white plastic - with the actual albedo measurements of both and their emissivities, you cannot make a prediction accurately.

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The time period of the wave is 0.5 seconds.

To find the answer, we have to know more about the time period.

                       \(T=\frac{t}{N} =\frac{0.5}{1}\)

where; t is the time taken to complete one oscillation(from A to H) and N is the number of patterns completed.

Thus, we can conclude that, The time period of the wave is 0.5 seconds.

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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A serial killer is one that goes on from one place to another killing people everywhere.

The information about a serial killer that is documented are;

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Answer:

Mostly with aid of Kohlberg 's moral growth theory, I clarify this answer, which would also be separated into three stages under which this particular problem is illustrated below.

Explanation:

The daughter's father would think about either the penalty during that point if he commits any wrongdoing or breaches laws to save her daughter. But another way to make that happen for surgery is that a person cares about either the legislation and rules as well as the significance of respecting them throughout the pre-conventional process. He will also attempt to establish its insight into solving these problems.

As per the traditional process of the spiritual psychosocial development of Kohlberg, her father would think of civilization because there are conventions that unless he borrows money of his dad again for the procedure of their daughter, culture would label him greedy or prejudice against him to pay the profits of his father despite his consideration.

As per this argument, he might determine for her child as well as father in his philosophy including perspectives, which means that his father is not in the situation of requesting credit, but because he's in a position to give a recommendation, therefore he certainly gives authorization rescue her grandchildren even though she is small and has several activities to do in hers life. And subsequently, with emerging profits, he will take care of his father as well as daughter, and nowadays focus says their daughter wants treatment to recover.

Wavelength is defined by Velocity of the wave by Frequency

Symbolically

\(\\ \ast\bull\rm\longmapsto \lambda=\dfrac{c}{v}\)

Answer:

at rest because time is passing and speed is still at 0

Explanation:

Answer:

Given

mass (m) =5kg

velocity (v) =6m/s

momentum (p) =?

Form

p=mv

5kgx6m/s

p=30kg.m/s

momentum =30kg.m/s

Answer:

10 / 80 amount of potassium-40 remaining

1/8 = 1/2 * 1/2 * 1/2 = 3 half-lives

3 half-lives * 1.3E9 yrs / half-life = 3.9E9 yrrs

After 3.9 billion years the 80 g will have decayed to 10 g

Answer:

3.9 billion years

Explanation:

i took test

Answer:  NOx and VOC combine chemically with oxygen to form ozone

Explanation:

Answer:  a measure of the ratio of output force to input force in a system, used to analyze the forces in simple machines like levers and pulleys.

Explanation:

Answer: the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine
Explanation: a measure of the ratio of output force to input force in a system

! <

Elements heavier than hydrogen (and helium) are made by stars and therefore should be located within galaxies.

So if we see absorption lines from these elements in quasar spectra, they should have the same redshifts as hydrogen lines from intervening galaxies. Absorption lines may not be present at redshifts of protogalactic clouds that are composed of hydrogen and helium only. This means that the redshifts of these elements should be similar to the redshifts of the galaxies they are associated with. However, it is possible that absorption lines may be present at redshifts of protogalactic clouds that are composed of hydrogen and helium only. In these cases, the redshifts of heavier elements would be different than the redshifts of the protogalactic clouds and therefore not be present in the spectrum.

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The ratio of the drag force on the jet to the drag force on the prop-driven transport, Ratio = (0.46 kg/m^3 * (784 * 1000/3600)^2 m^2/s^2) / (0.71 kg/m^3 * ((784 * 1000/3600) / 2)^2 m^2/s^2)

To calculate the ratio of the drag force on the jet to the drag force on the prop-driven transport, we can use the equation for drag force:

Drag Force = (1/2) * density * velocity^2 * A * C

- density is the air density

- velocity is the speed of the aircraft

- A is the effective cross-sectional area

- C is the drag coefficient

Let's denote the drag force on the jet as F_jet and the drag force on the prop-driven transport as F_prop. We are given the following information:

For the jet:

- Velocity_jet = 784 km/h = (784 * 1000) / 3600 m/s (converting from km/h to m/s)

- Altitude_jet = 8.6 km

- Density_jet = 0.46 kg/m^3

For the prop-driven transport:

- Velocity_prop = (1/2) * Velocity_jet = (1/2) * (784 * 1000) / 3600 m/s (half the speed of the jet)

- Altitude_prop = Altitude_jet / 2 = 8.6 km / 2 (half the altitude of the jet)

- Density_prop = 0.71 kg/m^3

The effective cross-sectional area (A) and the drag coefficient (C) are assumed to be the same for both aircraft.

Now, we can calculate the ratio of drag forces:

Ratio = F_jet / F_prop

Using the equation for drag force, we have:

Ratio = [(1/2) * density_jet * velocity_jet^2 * A * C] / [(1/2) * density_prop * velocity_prop^2 * A * C]

The A and C terms cancel out, giving:

Ratio = (density_jet * velocity_jet^2) / (density_prop * velocity_prop^2)

Substituting the given values, we get:

Ratio = (0.46 kg/m^3 * (784 * 1000/3600)^2 m^2/s^2) / (0.71 kg/m^3 * ((784 * 1000/3600) / 2)^2 m^2/s^2)

Calculating this ratio will give us the desired result.

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Answer:

0.6 ☻︎☻︎☻︎☻︎☻︎☻︎☻︎☻︎☻︎☻︎☻︎

The measurements of sizes of eclipsing binaries depend on data such as light curves, radial velocity curves, and inclination of the orbital plane.

Eclipsing binaries are a type of binary star system in which two stars orbit around each other and periodically pass in front of each other, causing periodic variations in the system's brightness as seen from Earth. These variations are known as light curves and can be used to measure the sizes of the stars.

The analysis of the light curve involves measuring the depth and duration of the eclipses, as well as the shape of the light curve between eclipses. By comparing these measurements to theoretical models of eclipsing binaries, astronomers can determine the sizes and other physical properties of the stars in the system.

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A leftward force of 50 N is applied to an 8 kg object to move it across a rough surface with a leftward acceleration of 5 \(m/s^{2}\) , its

gravitational force = 78.4 N

normal force = 78.4 N

frictional force = 10 N rightward

net force =  40 N leftward

coefficient of friction = 0.128

given

force = 50 N

mass = 8 kg

acceleration = 5 \(m/s^{2}\)

gravitational force = mg = 8 * 9.8 = 78.4 N

normal force = mg = 78.4 N ( as N= mg )

- F (applied) + frictional force  = - F (net )

F (applied)  - fr = F (net )

50 - fr = mass * acceleration

50 - fr = 8 * 5

fr = 10 N

Fnet = ma = 8 * (-5) = -40 N

Frictional force = mu * N

10 = mu * 78.4

mu (coefficient of friction ) = 10 / 78.4 = 0.128

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Answer:

C = 93.4m

Ф₃= 54°

Explanation:

if Ф₁ =21° and Ф₃ = 11°

The new landowner has a triangular piece of flat land, and she wishes to fence. The length and orientation of the third side are 92.3 meters, with an orientation of 53.7°.

Numerous algebraic operations involving vectors are carried out using vector algebra. The Latin word for the carrier is a vector. Points A and B are transported by vectors. The magnitude of the vector is the length of the line connecting the two points A and B, and the vector's direction is the movement from point A to point B. Other names for vectors are Euclidean vectors and spatial vectors. In many different domains, including mathematics, physics, engineering, and others, vectors are used.

Now, according to the question :

Let the given vector is R, and it makes an angle of θ then its components will be :

\(R_x\) = R cos θ

\(R_y\) = R sin θ

As we know that A + B + C =0

A is given as 80 m with direction 21° below the x-axis and,

B is 105 meters, with a direction of 11° counterclockwise from the positive y-axis.

\(A_x\\\) = 80 cos 21°

\(A_y\) = -80 sin 21°

similarly,

\(B_x\\\) = 105 cos 101°

\(B_y\) = -105 sin 101°

C = -(A+B)

C = -( 80 cos 21° + 105 cos 101°) i - (-80 sin 21°+105 sin 101°) j

C = 54.65 i -74.40 j

So the magnitude vector of C will be :

|C| = \(\sqrt{Cx^2+Cy^2}\)

|C| = 92.3 m

Now direction will be :

θ = arc tan (Cy/Cx)

θ = 53.7°

Hence, the orientation of the third side will be 53.7° and the length will be 92.3 meters.

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Answer:

things move quickly through a liquid

Explanation:

Therefore, the density of water would be 28g/48mL.

The density of an object can be calculated by dividing its mass by its volume.

In this case, we have a density bottle filled with water.

The mass of the empty dry density bottle is 25g, while the mass of the bottle filled with water is 53g.

The volume of water in the bottle is given as 48 cm³.

To find the density of water, we can subtract the mass of the empty bottle from the mass of the bottle filled with water to determine the mass of the water alone.

In this case, the mass of the water would be 53g - 25g = 28g.

Next, we divide the mass of the water by its volume to calculate the density.

The density of water is given by the equation density = mass/volume.

So, the density of water would be 28g/48cm³.

To simplify the units, we can convert cm³ to mL (milliliters), as they are equivalent.

Therefore, the density of water would be 28g/48mL.

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Answer:

which statement is true about his walk? he walked 1200m then went back 600m

Explanation:

because he walked 1200m east the 600m west so it adds up to 600

Answer:

See below

Explanation:

x component =  90 cos 45 = 63.6 N

y component =  90 sin 45  = 63.6 N

Answer:

The mineral's hardness is greater than 4 but less than 5.5 on the Mohs hardness scale.