A bar magnet is broken in half. The magnetic field around one piece is sketched. What is wrong with this sketch

Answer:

C

Explanation:

it's the measure of the force of gravity pulling the object towards the centre of the Earth and this value differs at various locations away from the equator and highest at the poles

The bug will cross the sticky region once in each cycle of its motion, where a cycle is defined as one complete round trip from the top of the bowl to the bottom and back to the top.

To find the number of cycles the bug goes through, we can use conservation of mechanical energy. At the top of the bowl, the bug has only potential energy, which is converted to kinetic energy as it slides down the bowl. At the bottom of the bowl, all of the potential energy has been converted to kinetic energy, and as the bug slides up the other side of the bowl, the kinetic energy is converted back into potential energy. At the top of the bowl again, the bug has only potential energy, and the cycle repeats.

Because there is no friction (except for the sticky patch), the total mechanical energy of the system is conserved. Therefore, the potential energy at the top of the bowl is equal to the potential energy at the bottom of the bowl, and the kinetic energy at the bottom of the bowl is equal to the kinetic energy at the top of the bowl.

We can set the potential energy at the top of the bowl to zero, and use the conservation of energy to find the potential energy at the bottom of the bowl:

mgh = (1/2)mv^2

where m is the mass of the bug, g is the acceleration due to gravity, h is the depth of the bowl, and v is the speed of the bug at the bottom of the bowl.

Solving for v, we get:

v = sqrt(2gh)

Plugging in the numbers, we get:

v = sqrt(29.810.12) = 0.775 m/s

The time it takes for the bug to slide from the top of the bowl to the bottom and back up to the top is twice the time it takes to slide from the top to the bottom:

t = 2sqrt(2h/g) = 2sqrt(2*0.12/9.81) = 0.774 s

Therefore, the frequency of the bug's motion is:

f = 1/t = 1/0.774 = 1.29 Hz

Since the bug completes one cycle in each oscillation, the bug will cross the sticky region 1.29 times per second, or approximately once every 0.78 seconds.

Answer:

To investigate into how the height of a ramp affects the speed of a toy car rolled down a hill or slope because the higher the ramp the more Gravitational potential Energy (GPE), the more kinetic energy converted and the car will go faster. So the ramp increases, the velocity will also increase.

Explanation:

a) The average force with which the woman pushed the man is 210 N.

b.  the woman's recoil speed is still 3.68 m/s

c.  If  she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.

We first calculate  the Momentum  = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)

v = 3.68 m/s

Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s

The average force exerted on the man by the woman is:

Average force =   Δp / Δt

Average force  = 105 kg·m/s / 0.500 s

Average force  = 210 N

b) The woman's recoil speed is :

0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

v = 3.68 m/s

c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.

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Answer:

Explanation:

To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.

Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.

Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.

It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.

It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.

Here are six things that can help save energy or increase energy efficiency in any part of a house:

Install energy-efficient light bulbs: Replace traditional incandescent light bulbs with energy-efficient LED light bulbs. LED bulbs consume less electricity and last much longer.

Use a programmable thermostat: Installing a programmable thermostat can help you control the temperature of your home more efficiently. You can set it to automatically lower the temperature when you're away from home or sleeping.

Air leaks should be sealed with weatherstripping or caulk around windows and doors. By doing so, you can keep your house more pleasant and prevent draughts.

Install ceiling fans: Ceiling fans can help circulate air and keep your home cool in the summer and warm in the winter. They use less energy than air conditioners or heaters.

Upgrade to energy-efficient appliances: When it's time to replace appliances, choose ones with an Energy Star label. These appliances are designed to use less energy and can help you save money on your energy bills.

Use power strips: Plug electronics and appliances into power strips, which can be turned off when not in use. This can prevent phantom energy use, which occurs when electronics and appliances continue to draw power even when turned off.

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An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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Answer:

an owl hunts, catches, and consumes a field mouse for energy

Explanation:

a)The heat transfer coefficient  will be 0.231 .The concept of the Newtons law of cooling is used in the given problem.

The pace at which an item cools is proportional to the temperature differential between the object and its surroundings,

According to Newton's law of cooling. Simply explained, in a cold environment, a glass of hot water will cool down faster than in a hot room.

The given data in the problem is;

T₀ is the initial temperature= 40°

\(\rm T_S\)  is the constant temperature = 70°

T is the final temperature = 55°

From the given equation the Newtons law of cooling;

\(\rm T=T_S+(T_0-T_S)e^{-kt} \\\\ 55=70+(40-70)e^{-3k} \\\\-30 e^{-3k}=-15\\\\ e^{-3k}= -\frac{1}{2} \\\\ ln e^[3k}=ln 2 \\\\ K=\frac{1}{3} ln2 \\\\ K=0.231\)

Hence the heat transfer coefficient  will be 0.231 .

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Sam traveled a total distance of 60 miles, but his displacement is zero, as he ended up back at his starting point after all of his movements.

How to measure the distance?

The distance that Sam has traveled is the total length of the path he took, regardless of the direction. In this case, the distance can be calculated as follows:

Distance = 20 miles (North) + 10 miles (East) + 20 miles (South) + 10 miles (West)

Distance = 60 miles

Therefore, Sam has traveled a total of 60 miles.

The displacement, on the other hand, is the shortest distance between the starting point and the ending point. It is the distance between the initial and final position of an object, measured in a straight line. To calculate the displacement, we need to find the net vector sum of all the individual movements.

Starting from the origin, Sam moved 20 miles to the north and then 20 miles to the south, which means he ended up back at the starting point. Next, he moved 10 miles to the east and then 10 miles to the west, which also means he ended up back at the starting point.

Therefore, the displacement of Sam's journey is zero.

In summary, Sam traveled a total distance of 60 miles, but his displacement is zero, as he ended up back at his starting point after all of his movements.

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Answer:The motion. of the ball will most likely still go up but since the bus is moving the ball will end up at the back of the bus

Explanation:

Answer:

i thik u must ask me

Explanation:

is it maths sum

Answer:

130.7 N

Explanation:

It takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

The formula for radioactive decay is \(A = A0 * (1/2)^{(t/t1/2)}\) where: A is the final activity A0 is the initial activity is the time elapsed t1/2 is the half-life of the sample

In this problem, the initial activity A0 is given as 1.07 x 105 Bq and the final activity A is given as 100 Bq.

The half-life of the sample is given as 5.7 days.

Substituting these values into the formula, we get: \(100 = 1.07 \times 105 * (1/2)^{(t/5.7)}\)

Dividing both sides by 1.07 x 105, we get:

\(0.000934579 = (1/2)^{(t/5.7)}\)

Taking the natural logarithm of both sides, we get:\(-7.072737 = (t/5.7) * ln(1/2)\)

Dividing both sides by ln(1/2), we get:

\(t = -7.072737 \div ln(1/2) * 5.7t \approx 28.3\) days

Therefore, it takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

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The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.

Answer:

x = A cos (w \sqrt{2y_{o}/g})

a) maximun  Ф= \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) minimun     Ф = \(\frac{\pi }{2}\) - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

Explanation:

For this exercise let's use kinematics to find the time it takes for the mass to reach the floor

         y = y₀ + v₀ t - ½ g t²

as the mass is released from rest, its initial velocity is zero (vo = 0) and its height upon reaching the ground is zero (y = 0)

      0 = y₀ - ½ g t²

      t = \(\sqrt{2y_{o}/g}\)

The bucket-spring system has a simple harmonic motion, which is described by

     x = A cos wt

in this expression we assumed that the phase constant (Ф) is zero

let's replace the time

     x = A cos (w \sqrt{2y_{o}/g})

this is the distance where the system must be for the mass to fall into it.

a) The new system has a total mass of m ’= 3.0 kg, so its angular velocity changes

          w = \(\sqrt{k/m}\)

In the initial state

         w = \sqrt{k/2}

When the mass changes

         w ’= \sqrt{k/3}

the displacement in each case is

         x = A cos (wt)

for the new case

        x ’= A cos (w’t + Ф)

the phase constant is included to take into account possible changes due to the collision of the mass.

we see that this maximum expressions when the cosine is maximum

        cos (w´t + Ф) = 1

         w’t + Ф = 0

        Ф = -w ’t

        Ф = - \(\sqrt{k/3}\) \(\sqrt{2y_{o}/g}\)

       \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) the function is minimun if

        cos (w’t + fi) = 0

        w’t + Ф = π / 2

        Ф = π / 2 - w ’t

        Ф = \(\frac{\pi }{2}\) - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

As an ecological resource manager, your initial environmental studies should include investigating whether wetlands include oyster beds and shallow estuaries which are habitats for shrimp, crabs, and fish that support many local industries.

When viewed from an ecological perspective, the main factors to consider are the state of the environment and the living things that live in it.

The relationship between the environment and sustainable development is one indicator of sustainable development which is to minimize environmental damage as a result of development.

Environmentally sound development is a conscious and planned effort to use and manage resources wisely in planned and irrational development to improve the quality of human life.

This question is not written neatly, and this question is a multiple choice

As an ecological resource manager, your preliminary environmental studies should include inquiry into whether                        

The true choice is C

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The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.

Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h

We have to find the magnitude of the angular momentum

Let,

ρ = Density of air = 1.29 kg/m^3

v = Speed of wind = 73.0 mi/h = 0.032 km/s

M = angular momentum of air

Let the volume of air be 1 m^3

Mass = Volume x ρ = 1 x 1.29 = 1.29 kg

Momentum = M = mass x velocity

Momentum = 1.29 x 0.0032

Momentum = 4.128 x 10^(-3) kg·m^2/s

Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

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Sound level in dB of the ultrasound used in medical diagnostics is approximately 99.7 dB.

Ultrasound is an imaging method that uses sound waves to produce images of structures within body.

SIL = 10 log10(I/I0)

where I is sound intensity in watts per square meter, and I0 is reference sound intensity of 1 picowatt per square meter (1 p W/m²).

SIL = 10 log10(6.87 × 10⁻² W/m² / 1 p W/m²)

= 10 log10(6.87 × 10²) + 10 log10(10¹²)

= 10 log10(6.87 × 10⁻²) + 120

1 p W/m² = 10⁻¹² W/m^2.

SIL = 10 log10(6.87 × 10⁻²) + 120

= 99.7 dB

Therefore, the sound level in dB of the ultrasound used in medical diagnostics is approximately 99.7 dB.

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Tidal energy is the form of energy used to generate electrical energy.

The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.

Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.

After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.

Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.

Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.

Thus, kinetic energy is used to generate electrical energy in a tidal power station.

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When you change the light from green to red, the number of waves remains the same.

Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.

The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.

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Answer:

\(d=11\sqrt2\ km\)

Explanation:

Given that,

Displacement in North = 11 km

Displacement in East = 11 km

We need to find the approximate displacement of the hiker from the camp. It can be calculated by resultant of two displacement as follows :

\(d=\sqrt{11^2+11^2}\\\\= 11\sqrt2\ km\)

Hence, the approximate displacement of the hiker from the camp is \(11\sqrt2\ km\).

Answer:

3300 J

Explanation:
P = Q/t

Q = Pt = 110 * 30 = 3300 J

Answer:Sir haymo knows

Explanation:

he gave as homework

The acceleration of the Saturn is - (2πf)²x(t).

A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. A particle moving in simple harmonic motion accelerates as a(t) = - ω² x (t). Here, ω denotes the particle's angular velocity.

The acceleration of the particle at any position is directly proportional to the displacement from the mean position in simple harmonic motion, which is an oscillatory motion.

Given that:

at any time, the angular position of Saturn is (2πf)t.

the displacement in SHM at that time t is given by x(t)=R cos(2πf)t.

Hence, speed  in SHM at that time t is given by

\(v(t) = \frac{dx(t)}{dt} =R \frac{d }{dt} cos(2\pi f)t = -(2\pi f) sin(2\pi f)t\)

it's acceleration is

\(a(t) = \frac{dv(t)}{dt} =-(2\pi f) R \frac{d }{dt} sin(2\pi f)t = -(2\pi f)^2 Rcos(2\pi f)t = -(2\pi f)^2 x(t)\)

hence, at any time t, the acceleration of the Saturn is - (2πf)²x(t).

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Answer:

Impulse = 1000 Ns

Explanation:

Given the following data;

Force of collision = 1000 kg•m/s.

Time = 1 seconds

To find the impulse;

Mathematically, the impulse experienced by an object or body is given by the formula;

Impulse = force * time

Substituting into the formula, we have;

Impulse = 1000 * 1

Impulse = 1000 Ns

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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From the histogram given, there were at approximately 7 downloads between 3pm and 4pm . This can be derived by counting the rows in that time period.

A histogram is a graph that depicts the frequency distribution of a few data points from a single variable.

Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.

Histograms are frequently used to depict the key properties of data distribution in a handy format. It is especially beneficial when working with huge data sets (more than 100 observations). It can aid in the detection of uncommon observations (outliers) or gaps in the data.2

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The following describes a change to Earth’s surface due to weathering include the following below:

A. plants creating a crack in a rock formation

B. rocks along the beach being reshaped by wave action.

F. glaciers scraping rocks across the land

This is referred to as the process which involves the breaking down of rocks and minerals on Earths surface as a result of certain factors such as rain, glacier etc. They form cracks when they come in contact with rocks afterf a given period of time before they are disintegrated.

Weathering occurs when plants creating a crack in a rock formation and also when the rocks along the beach are being reshaped by wave action.It also involves the  glaciers scraping rocks across the land which is therefore the reason why option A, B and F was chosen as the correct choice.

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The options are:

A. plants creating a crack in a rock formation

B. rocks along the beach being reshaped by wave action

C. sand being blown to a new location by the wind

D. sediments moved from place to place by a river

E. rain washing soil down a steep hill

F. glaciers scraping rocks across the land

The independent variable in this experiment is the act of turning the bulb on and off, while the dependent variable is the behavior of the earthworm in response to changes in light. The scientist can analyze the data collected to determine the impact of light on the earthworm's behavior.

In the experiment where a scientist is turning a bulb on and off to check the behavior of an earthworm, the independent variable is the manipulation performed by the scientist, which is the act of turning the bulb on and off.

The independent variable is the variable that the scientist deliberately changes or controls in order to observe its effect on the dependent variable. In this case, the scientist is interested in investigating how the earthworm responds to changes in light. By turning the bulb on and off, the scientist is manipulating the presence or absence of light in the environment of the earthworm.

The behavior of the earthworm, which is the dependent variable, will be observed and measured in response to the changes in light. The scientist may record various behaviors such as movement, burrowing, or changes in activity level exhibited by the earthworm when the light is turned on and off.

By systematically controlling the independent variable (turning the bulb on and off) and observing the dependent variable (behavior of the earthworm), the scientist can analyze the relationship between light exposure and the earthworm's behavior. This allows for drawing conclusions about how the earthworm responds to light stimuli.

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