A bicycle has a momentum of 25.00 kg·m/s and a velocity of 2.5 m/s. What is the bicycle’smass?
Answers
Answer:
10 kg
Explanation:
p=ma
25=2.5m
m=25/2.5
m=10 kg
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Related Questions
What advantage does a machine with a MA of 1 provide? Give an example.
Answers
Answer:
A machine that has a Mechanical Advantage (MA) of 1 offers no benefit. It does not imply that the device is perfect or that there aren't any energy losses, though.
Explanation:
A machine with an MA of 1 produces a force that is exactly equal to the force that is applied to it.
A straightforward screwdriver is an illustration of a machine having an MA of 1. The force needed to spin the screw and the force applied to the handle of the screwdriver are equal when the force is applied to the handle and is passed directly to the screw. Since the distance traveled by the handle and the screw are equal, the Mechanical
Answer:
If the fulcrum is exactly in the middle, then moving one end by 1 meter will move the other end exactly by 1 meter. This is the the machine with Mechanical advantage exactly equal to 1.
Explanation:
whenever something is too heavy to lift, a ramp can be a solution. As long as the slope of the ramp is gentle enough, and the object has something like wheels that roll, heavy weights can be lifted from here to there.
Mechanical advantage is the ratio of output to the input force. It can also be described as the ratio of load to the effort applied.
[04.04] Which best describes the current atomic theory?
Answers
The Internet Engineering Task Force (IETF) sets standards for webpage design.
a) true
b) false
Answers
Calculate the work done when a force of 20N displaces a body by 50 m.
Answers
Answer:
W = ?
F = 20 N
s = 50 m
W = F s
W = 20 × 50
W = 1000 J
The work done when a force of 20N displaces a body by 50m is 1000 joules (J).
The work done (W) by a force (F) on an object that moves a displacement (d) is given by the formula:
W = Fd
Where:
W = Work done
F = Force applied
d = Displacement
In this case, the force applied is 20N and the displacement is 50m. Therefore, the work done is:
W = Fd
W = 20N x 50m
W = 1000 joules (J)
Therefore, the work done in displacing the body by 50 m by applying a force of 20 N is 1000 joules.
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Explain one way organisms with similar niches reduce competition when they are found in the same ecosystem? Give one example.
Answers
One way organisms with similar niches reduce competition when they are found in the same ecosystem is by resource partitioning.
One example of resource partitioning is when two species of birds foraging together feed on different resources; one eats insects on tree trunks while the other eats insects in the outer branches.
What is resource partitioning?Resource partitioning, which helps prevent rivalry in an ecological niche, is the division of scarce resources among species.
Two similar species employ mostly non-overlapping resources as a result of this type of evolution, and as a result, they occupy different niches. Because there is less direct rivalry between the species as a result of this resource partitioning, the species can coexist.
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please help me asdrtyuio
Answers
Answer:
9. The Sun's Gravity
10. The core is the densest layer
An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?
Answers
The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,
F = kx
Therefore,
k = F/x
We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,
K = 50.174/0.25 N/m
K = 200.696 N/m
Therefore, The Spring Constant is 200.696 N/m
On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:
h = \(1/2 kx^{2}\)
We know that k=200.696 N/m and x=0.25 m. Therefore the height is:
h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)
h = 2.5087 m
Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m
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How is thermal energy transferred during conduction? Check all that apply.
Thermal energy is transferred between particles that are not touching each other.
Thermal energy is transferred between particles that are in direct contact with each other.
Thermal energy is transferred between objects of different temperatures.
Thermal energy is transferred between objects of the same temperature.
Thermal energy is transferred from slow-moving particles to fast-moving particles.
Thermal energy is transferred from fast-moving particles to slow-moving particles.
Answers
Answer:
Thermal energy is transferred between particles that are in direct contact with each other.Thermal energy is transferred between objects of different temperatures.Thermal energy is transferred from fast-moving particles to slow-moving particles.Explanation: Correct on Edg 2020/2021 for my school.
28) Refraction results from differences in light's. A) frequency. B) incident angles. C) speed. D) all of the above. E) none of the above.
Answers
Refraction results from differences in light's speed. The correct answer is C) speed.
Refraction is the term for the bending of light as it passes through transparent materials (it also occurs with sound, water, and other waves). We are able to create lenses, magnifying glasses, prisms, and rainbows because to this bending caused by refraction.
Refraction occurs when light passes through different mediums and changes its speed. This change in speed causes the light to bend, creating the effect of refraction.
This is why objects appear to be in different positions when viewed through water or a lens. The frequency and incident angles of the light do not affect refraction, only the speed of the light does.
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A car starts at rest and accelerates at a constant rate for 12 seconds to speed of 30 m/s. What is the total distance traveled in these 12 seconds
Answers
Answer:
360 meters
Explanation:
1. Set up a formula. Distance = Speed x Time
2. Plug in given information. d (distance) = 30m/s * 12s
3. Multiply numbers AND units. d = 360m
4. Check that units & numbers make sense.
Speed is a measure of how quickly an object moves.
The speed equation can be rearranged to calculate the distance traveled and the time required.
The total distance traveled in these 12 seconds = 360 m.
What is speed ?Speed is a measure of how quickly an object moves. Use the speed equation to calculate speed: speed = distance divided by time. The speed equation can be rearranged to calculate the distance traveled and the time required.Speed is the rate at which an object moves along a path in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar value.The force of impact increases with the square of the increase in speed, according to physical laws. So, doubling the speed of a car increases the force of impact fourfold.The total distance traveled in these 12 seconds = 30 m/s x12 sec
=360 m.
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planets move in elliptical orbits around the sun. as a planet moves away from the sun in its counterclockwise orbit it is suddenly struck head-on by a large asteroid.
Answers
If a planet moving in an elliptical orbit around the sun is suddenly struck head-on by a large asteroid, the impact would cause a disruption to the planet's motion and orbit. The specific consequences would depend on the circumstances of the collision and could include changes in the planet's velocity, direction, orbital shape, eccentricity, and period.
Over time, the planet's orbit would be influenced by gravitational forces and other factors, leading to potential long-term orbital evolution.
Here's a step-by-step explanation of what would happen if a planet moving in an elliptical orbit around the sun is suddenly struck head-on by a large asteroid:
Step 1:
Initial elliptical orbit:
The planet is initially moving in an elliptical orbit around the sun, following the laws of planetary motion, such as Kepler's laws. The elliptical orbit means that the planet's distance from the sun varies throughout its orbit.
Step 2:
Approach of the asteroid:
The large asteroid, traveling in its own trajectory, intersects the planet's path and strikes it head-on. This collision occurs as the planet is moving away from the sun in its counterclockwise orbit.
Step 3:
Disruption of the planet's orbit:
The collision with the asteroid causes a significant disruption to the planet's motion and orbit. The planet may experience a sudden change in velocity, direction, and orbital parameters due to the impact.
Step 4:
Deviation from the original orbit:
The planet's path deviates from its original elliptical orbit due to the asteroid's impact. The exact nature of this deviation depends on the specific circumstances of the collision, such as the mass and velocity of the asteroid, as well as the planet's mass and orbital parameters.
Step 5:
Potential change in orbital shape and eccentricity:
The impact may alter the shape and eccentricity of the planet's orbit. It could become more elongated or circular, depending on the energy and momentum transferred during the collision.
Step 6: Perturbation of orbital period: The collision can perturb the planet's orbital period, causing it to either increase or decrease, depending on the interaction between the planet and the asteroid.
Step 7:
Adjustments due to gravitational forces:
After the collision, the planet will be subject to the gravitational forces exerted by the sun and other celestial bodies. These forces may act to gradually reshape the planet's orbit over time.
Step 8:
Long-term orbital evolution:
The long-term evolution of the planet's orbit will depend on various factors, such as the magnitude of the collision, the planet's interaction with other objects in the solar system, and the influence of tidal forces.
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If the Angle of Incidence is 14º, what is the Angle of Reflection?
Answers
Answer:
Explanation:
The Law of reflection states that angle of incidence equals angle of reflection.
So Angle of reflection is 14° also.
what is the maximum ma measured electric current that a class 3 pd can use?
Answers
The maximum measured electric current that a Class 3 power-limited circuit can use is 0.5 amperes or 500 milliamperes (ma).
The maximum measured electric current that a Class 3 power-limited circuit or power source can use is typically defined by the relevant electrical safety standards. However, it's important to note that Class 3 refers to the power limitation and signaling levels, and not specifically to a measured electric current.
Class 3 circuits or power sources are characterized by limited power levels, usually lower than those of Class 1 or Class 2 circuits. These circuits are designed to operate at low voltages and limited power levels to reduce the risk of electric shock and fire hazards.
The specific current limit for Class 3 circuits can vary depending on the applicable standards, regulations, and equipment being used. It is crucial to consult the relevant electrical codes and standards specific to your location and the equipment being utilized to determine the maximum current limits for Class 3 circuits accurately.
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I need help with all of these questions
Answers
Answer:
This was my best estimation of the answers
Cellular respiration occurs in every cell of our bodies. Through this process, we obtain the energy we need for life. During cellular respiration, oxygen helps in breaking down sugar molecules into carbon dioxide and water molecules. Which reaction correctly represents the cellular respiration process?(1 point)
carbon dioxide + water → sugar + oxygen + energy
sugar + oxygen → carbon dioxide + water + energy
carbon dioxide + water + energy → sugar + oxygen
sugar + oxygen + energy → carbon dioxide + water
Answers
Answer:
B. sugar + oxygen → carbon dioxide + water + energy
Explanation:
Energy is that which sustains living organisms, so as to perform various activities. One of the processes by which living organisms produce energy is by respiration.
Respiration involves the breathing-in of oxygen and breathing-out of carbon dioxide as a waste. The oxygen helps in breaking down molecules of carbohydrates e.g sugar in the system of living organisms into energy, carbon dioxide and water.
This process is well represented by the equation in option B.
The reaction which correctly represents the cellular respiration process is sugar + oxygen → carbon dioxide + water + energy.
What is Cellular respiration?Cellular respiration involves the conversion of chemical energy from food
into ATP which is needed for the cell's daily activities.
This process is done in the presence of oxygen to form products such as:
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Compare the temperature changes in the stratosphere with those in the troposphere.
Answers
Answer:
the temperature in the troposphere decreases while the temperature in the stratosphere increases because of the density of air molecules.
Explanation:
sorry ima little late
98. In Fig. 24-71, a metal sphere
with charge q = 5.00 uC and radius
r = 3.00 cm is concentric with a
larger metal sphere with charge Q =
15.0 uC and radius R = 6.00 cm. (a)
What is the potential difference be-
tween the spheres? If we connect the
spheres with a wire, what then is the
charge on (b) the smaller sphere and
(c) the larger sphere?
Answers
Answer:
(a) The potential difference between the spheres is 750 kVA
(b) The charge on the smaller sphere is 6.\(\overline 6\) μC
(c) The charge on the smaller sphere, Q₁ = 13.\(\overline 3\) μC
Explanation:
(a) The given parameters are;
The charge on the inner sphere, q = 5.00 μC
The radius of the inner sphere, r = 3.00 cm = 0.03 m
The charge on the larger sphere, Q = 15.0 μμC
The radius of the larger sphere, R = 6.00 cm = 0.06 m
The potential difference between two concentric spheres is given according to the following equation;
\(V_r - V_R = k \times q \times \left ( \dfrac{1}{r} - \dfrac{1}{R} \right)\)
Where;
R = The radius of the larger sphere = 0.06 m
r = The radius of the inner sphere = 0.03 m
q = The charge of the inner sphere = 5.00 × 10⁻⁶ C
Q = The charge of the outer sphere = 15.00 × 10⁻⁶ C
k = 9 × 10⁹ N·m²/C²
Therefore, by plugging in the value of the variables, we have;
\(V_r - V_R = 9 \times 10^9 \times 5.00 \times 10^{-6} \times \left ( \dfrac{1}{0.03} - \dfrac{1}{0.06} \right) = 750,000\)
The potential difference between the spheres, \(V_r - V_R\) = 750,000 N·m/C = 750 kVA
(b) When the spheres are connected with a wire, the charge, 'q', on the smaller sphere will be added to the charge, 'Q', on the larger sphere which as follows;
\(Q_f\) = Q + q = (5 + 15) × 10⁻⁶ C = 20 × 10⁻⁶ C
\(Q_f\) = 20 × 10⁻⁶ C
From which we have;
Q₁/Q₂ = R/r
Where;
Q₁ = The new charge on the on the larger sphere
Q₂ = The new charge on the on the smaller sphere
\(Q_f\) = 20 × 10⁻⁶ C = Q₁ + Q₂
∴ Q₁ = 20 × 10⁻⁶ C - Q₂ = 20 μC - Q₂
∴ (20 μC - Q₂)/Q₂ = 0.06/(0.03) = 2
20 μC - Q₂ = 2·Q₂
20 μC = 3·Q₂
Q₂ = 20 μC/3
The charge on the smaller sphere, Q₂ = 20 μC/3 = 6.\(\overline 6\) μC
(c) Q₁ = 20 μC - Q₂ = 20 μC - 20 μC/3 = 40 μC/3
The charge on the smaller sphere, Q₁ = 40 μC/3 = 13.\(\overline 3\) μC.
The potential difference is 7.5*10^5V and the charge on the smaller sphere is 6.67uC while the charge on the larger sphere is 13.34uC
Data;
q = 5.0 uCr = 3.0cm= 0.03mQ = 15.0uCR = 6.0cm = 0.06mPotential Difference between the Spheresfor the inner sphere;
\(v_i = \frac{kq}{r} = \frac{(9*10^9)(5*10^-^6)}{0.03} \\v_i = 1.5*10^6V\)
for the outer sphere;
\(v_o = \frac{KQ}{R} = \frac{(9*10^9)(15*10^-^6)}{0.06} = 2.25 * 10^6V\)
The difference in potential is
\(\delta V = v_o - v_i = 2.25*10^6 - 1.5*10^6 = 7.5*10^5V\)
Charge on the Smaller Plate\(q + Q = 5 + 15 = 20 \mu C = 20*10^-^6C ..eq(i)\)
The sharing of charge continues till they attain a point of equal potential
\(v_i = v_o \\\frac{kq}{r} = \frac{kQ}{R} \\\frac{q}{0.03} = \frac{Q}{0.06} \\Q= 2q ...eq(ii)\\\)
let's solve for equation (i) and equation (ii)
\(q+2q = 20\mu C\\q = 6.67 \mu C\)
The charge on the smaller sphere is 6.67uC
The charge on the larger sphereThe charge on the larger sphere is
\(Q = 2q\\q = 6.67 \mu C\\Q = 2 * 6.67 = 13.34 \mu C\)
The charge on the larger sphere is 13.34uC
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Two mechanical waves are traveling through the same medium, and Wave X has an amplitude of 2 cm and Wave Y has an amplitude of 3 cm.How do the two waves' speeds compare?A. Wave X has a greater speed. B. Wave Y has a greater speed. C. Wave X and Wave Y share the same speed. D. The speed of the waves is impossible to compare without more data.Part 2Which best explains the correct answer to Part 1?A. The speed of a wave is always constant. B. The speed of a wave is directly proportional to its amplitude.C. The speed of a wave is determined by its wavelength and frequency.D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.
Answers
ANSWER:
1. C. Wave X and Wave Y share the same speed.
2. D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.
STEP-BY-STEP EXPLANATION:
The amplitude of a wave does not affect the speed at which the wave travels. Both wave A and wave B travel at the same speed. The speed of a wave is only altered by alterations in the properties of the medium through which it travels.
Therefore, in the first art the correct answer is C. Wave X and Wave Y share the same speed.
If the medium is uniform (does not change), the speed of the wave will be constant.
Therefore, the correct answer is: D. The speed of a wave is affected by the properties of the medium it is traveling through, not amplitude.
A point charge produces an electric flux of +305 N⋅m2/C through a gaussian sphere of radius 15.0 cm centered on the charge. a What is the flux through a gaussian sphere with a radius 29.0 cm ?b What is the magnitude of the charge?
Answers
Given
The electric flux is
\(\phi=+305\text{ Nm}^2\text{ /C}\)Radius of the sphere,
\(r=15.0\text{ cm}\)To find
a. The flux through a gaussian sphere with radius of 29.0 cm.
b. The magnitude of the charge
Explanation
a. Since the gaussian sphere covers the same charge so the electric flux through both the sphere will be same.
Thus the required flux is
\(\phi=305\text{ Nm}^2\text{ /C}\)b.
The magnitude of the charge is
\(\begin{gathered} Q=\phi\epsilon_o \\ \Rightarrow Q=305\times8.85\times10^{-12} \\ \Rightarrow Q=30.97\times10^{-12}\text{ C} \end{gathered}\)Conclusion
a. The flux is
\(305\text{ Nm}^2\text{ /C}\)b. The charge is
\(30.97\times10^{-12\text{ }}C\)A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds. What
is the acceleration?
-13 m/s
-6 m/s²
6mis?
13 m/s2
Answers
Acceleration = (change in speed) / (time for the change)
Change in speed = (speed after the change) - (speed before the change)
Change in speed = (65 m/s) - (35 m/s) = 30 m/s
Acceleration = (30 m/s) / (5 s)
Acceleration = 6 m/s²
In an ionic compound, what happens to the electrons that the metal atoms have lost?
Answers
Answer:
metal atoms lose electrons to form positively charged ions. non-metal atoms gain electrons to form negatively charged ions
Explanation:
HELP PLEASE...
Assume you have a 50L barrel full of basketballs and a 50L barrel full of tennis balls. If you dump both barrels full of balls into a 100L barrel, will the barrel be full?
Answers
two buses are moving in the opposite directories with the velocities 36km/hr and 108km/hr .find the distance between them in 20 minutes.
Answers
The distance between the two buses is 48km.
Let us assume that the velocity of the first bus is 36 km/h and that of the second bus is 108 km/h.
To find the distance between them, we will consider that both buses move in opposite directions.
Distance travelled by bus 1 in 20 minutes = 36 km/h × 20 min ÷ 60 min/h = 12 km
Distance travelled by bus 2 in 20 minutes = 108 km/h × 20 min ÷ 60 min/h = 36 km
Total distance between them = distance travelled by bus 1 + distance travelled by bus 2= 12 km + 36 km= 48 km
Therefore, the distance between them in 20 minutes is 48 km.
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3. A force of 380 N is applied to a 38 kg object over a distance of 2.5 meters. What is the speedof the object after it accelerates?
Answers
Given,
Force, F = 380 N
Mass, M = 38 kg
Distance, d = 2.5 m
The work done on the body is equal to the final kinetic energy.
\(F\times d=\frac{1}{2}mv^2\)Put the given values in the formula,
\(\begin{gathered} 380\text{ N}\times2.5\text{ m = }\frac{1}{2}\times38kg\times v^2 \\ v^2=\frac{950\times2}{38} \\ v^2=50 \\ v=\sqrt[]{50} \end{gathered}\)Thus, the speed of the object after it accelerates is
\(v=7.07\text{ m/s}\)Rhonda is looking for a campsite for the night. From her parking spot she walks north for 212 meters, then turns and walks west for 145 m what is the displacement from Rhonda's car to her campsite
Answers
The displacement from Rhonda's car to her campsite 257 m, 34.4° north of west.
Most campgrounds have picnic tables, a place to park your car, and a place to pitch your tent. Bathrooms and taps are often shared. One of the joys of camping is the lack of outdoor gear. But it's also nice to have a comfortable, convenient and cozy campsite. A tent is a small shelter for sleeping while camping.
Camps are areas with tents campfires and surroundings. There are many types of camping but the main methods of camping are backpacking auto-camping and glamping. These top three camping styles have options for every level of camper. Front country camping is also called auto camping because you can drive to the campground. These campsites usually have running water and modern washrooms.
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Canada’s northern territories experience "midnight sun," meaning what?.
Answers
Canada’s northern territories experience "midnight sun" that refers to a natural phenomenon in which the sun remains visible at midnight or beyond midnight because of the tilt of the Earth’s axis. The sun rises around late May and stays in the sky until late July in the northern hemisphere, particularly in Canada's northern territories.
Canada’s northern territories experience "midnight sun" that refers to a natural phenomenon in which the sun remains visible at midnight or beyond midnight because of the tilt of the Earth’s axis. The sun rises around late May and stays in the sky until late July in the northern hemisphere, particularly in Canada's northern territories. The sun is visible at midnight and beyond midnight because of the tilt of the Earth’s axis. It implies that in the summer season, there is virtually daylight for 24 hours.
Hence, it can be stated that the northern territories of Canada experience "midnight sun," which means the sun remains visible at midnight or beyond midnight due to the tilt of the Earth’s axis. This phenomenon occurs because of the northern hemisphere's tilt during the summer solstice, which directs the Earth's northernmost part toward the sun. Therefore, the sun stays visible at midnight and beyond midnight, resulting in the Midnight Sun in Canada's northern territories.
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A plane at an altitude of 12,000 feet finds the angle of depression for a building ahead of the plane to be 10.4°
. With the building still straight ahead, two minutes later, the angle of depression is 25.6°
. Find the speed of the plane relative to the ground in feet per minute.
Answers
The speed of the plane relative to the ground in feet per minute is 26775 feet per minute (ft/min).
Given : The angle of depression for a building ahead of the plane to be 10.4° and 25.6°.The altitude of the plane at 12000 ft.A plane flying at a constant height of 12000 feet above the ground finds the angle of depression of a building to be 10.4°. Two minutes later the angle of depression of the building is found to be 25.6°.
Let the distance travelled by the plane in two minutes be x.Speed of the plane can be found using distance, speed and time relationship.i.e., speed = distance/time = x/2The vertical distance travelled by the plane in two minutes can be given by:12,000 ft - h = 12000 - 12000cos 10.4°or h = 12,000cos 10.4°Thus the vertical distance travelled by the plane in two minutes will be 12,000 - h - h = 2hAlso, h/(x/2) = tan 10.4° and (h + 2h)/(x/2) = tan 25.6°On solving we get, x = 53550 feetThus the speed of the plane relative to the ground in feet per minute is 53550/2 = 26775 feet per minute (ft/min).Hence, the speed of the plane relative to the ground in feet per minute is 26775 feet per minute (ft/min).
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in an elliptical orbit of a planet around the sun, the sun sits at one focus, what sits at the other?
Answers
In an elliptical orbit of a planet around the sun, the sun sits at one focus and there is nothing at the other focus.
What is the solar system?We know that in the solar system, we have the sun at the focus or the center of a set of concentric circles that is composed of the planets. We know that the planets.
We have to note that in accordance with the Kepler's law, the only thing that we can be able to find at the center of the solar system is the sun and we do not find any other thing at the focus.
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Chapter 3 Newton’s second law force and acceleration
Answers
According to the second motion law, acceleration is created. As a result, the force applied to an item equal its and even times the rate at which its velocity changes over time (acceleration).
What is the second law of Newton? Chapter 6: Force and Acceleration in the Second Law of Newton's of Motion?According to Newton's second law, an object's acceleration is approximately equal to its net force's magnitude, moves in the exact same direction as its net force, and is negatively proportionate to the weight of the thing.
How is the second law of Newton's of acceleration and force is expressed?F = ma, or force, is measured as mass times acceleration. According to the rule, an object's acceleration is influenced by both its mass and the force being applied. The law on kinetic energy and force is another name for Newton's second principle of motion.
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Using the model above, which letter represents the position of the earth when the northern hemisphere is experiencing the shortest hours of daylight
A
B
C
D
Answers
Answer:
At position "B" the northern hemisphere is tilted the most from the earth-sun direction and will experience the shortest hours of daylight, (and also the most indirect sun rays).