A block attached to a horizontal spring of force constant 75N/m undergoes SHM with an amplitude of 0.15m. If the speed of the mass is 1.7 m/s when the displacement is 0.12m from the equilibrium position, what is the mass of the block?

The 21 cm radiation provides information about the gas clouds, including their temperature and density, as well as their magnetic field strength and chemical composition.

The radiation also helps to map out the structure of the Milky Way galaxy and its surrounding regions.21 cm radiation is a type of radio wavelength radiation that is emitted by neutral hydrogen atoms. When these atoms change the direction of their spins, they emit radiation at a wavelength of 21 centimeters. This radiation is able to penetrate dust clouds and other obstacles in space, allowing astronomers to study the gas clouds that make up the Milky Way and other galaxies. The 21 cm radiation provides information about the gas clouds, including their temperature and density, as well as their magnetic field strength and chemical composition. By studying this radiation, astronomers can create detailed maps of the Milky Way galaxy and the regions surrounding it.

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Answer:

2.5

Explanation:

F=m.a

(Force = mass . acceleration)

 5=2.a

a= 5/2 = 2.5

Answer:

Yes

Explanation:

Because the call can evaporate from the water.

Answer:

A centrifuge is utilized to isolated little sums of strong held in suspension from the fluid. For case, chalk from water. The centrifuge contains test-tubes that are spun around at tall speed that causes the strong to sink to the foot of the tube. The fluid is the tapped (poured off) clearing out the strong behind.

The correct statements are b and d. When the donor concentration is much smaller than the acceptor concentration (nd<<na), the donors have a big effect in increasing the conductivity of the material.

Conversely, when the donor concentration is much larger than the acceptor concentration (nd>>na), the donors have little effect on the material's conductivity.This is because in the former case, most of the acceptor sites are filled by the donors, leading to a large number of free electrons and hence high conductivity. In the latter case, most of the donors remain unoccupied as there are not enough acceptor sites available to bind with them, leading to low conductivity.It's important to note that in cases where nd and na are of the same order of magnitude, both donors and acceptors will contribute to the material's conductivity, and their effects will need to be considered together.

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Answer:

The terminal voltage across the battery is 7-13 V.

Explanation:

The terminal voltage of a battery is the voltage measured across its terminals when it is connected to a load. In this case, the battery has a voltage of 8-13 V, and it is connected to a load resistor of 60 Ω.

The terminal voltage of a battery can be affected by various factors, including the internal resistance of the battery and the current flowing through the load. When a load is connected to the battery, the internal resistance of the battery can cause a voltage drop, reducing the terminal voltage.

In this scenario, the terminal voltage across the battery is given as 8-13 V. This range indicates that the terminal voltage can vary between 8 V and 13 V depending on the specific conditions and the load connected to the battery.

To determine the exact terminal voltage across the battery, more information is needed, such as the current flowing through the load or the internal resistance of the battery. Without this additional information, we can only conclude that the terminal voltage across the battery is within the range of 8-13 V.

In summary, the terminal voltage across the battery connected to a load resistor of 60 Ω is 8-13 V. This range indicates the potential voltage values that can be measured across the battery terminals, depending on the specific conditions and factors such as the internal resistance and the current flowing through the load.

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The downward force on the 2.67-cm piston required to lift the 2000 kg mass supported by the 20-cm piston is approximately 346220 dynes.

To calculate the downward force on the smaller piston, we'll use the principle of hydraulic lift, which states that the ratio of forces is equal to the ratio of the areas of the pistons. The formula for the area of a circle is A = πr^2.
First, calculate the areas of the pistons:
A1 = π(2.67 cm)^2 = 22.42 cm² (smaller piston)
A2 = π(20.0 cm)^2 = 1256.64 cm² (larger piston)
Next, calculate the weight of the 2000 kg mass supported by the larger piston using the gravitational force formula F = m*g, where m is the mass and g is the acceleration due to gravity (approximately 9.81 m/s²). Note that 1 kg = 1000 g, and 1 N = 100000 dynes.
F2 = (2000 kg)(9.81 m/s²) = 19620 N = 19620000 dynes
Now, apply the principle of hydraulic lift: (F1/A1) = (F2/A2), where F1 is the downward force on the smaller piston.
F1 = (F2 * A1) / A2
F1 = (19620000 dynes * 22.42 cm²) / 1256.64 cm²
F1 ≈ 346220 dynes

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A) Moving with a constant speed in the positive direction, B) Moving in the negative direction and speeding up, C) Moving in the positive direction, first fast then slow, and D) Moving with negative velocity and negative acceleration.

A) Moving with a constant speed in the positive direction: This indicates a linear motion where the object maintains a constant velocity in the positive direction. The sketch would show a straight line with a constant positive slope, indicating a steady speed.

B) Moving in the negative direction and speeding up: This suggests an object that is initially moving in the negative direction and is accelerating, or increasing its speed. The sketch would depict a line with a negative slope that becomes steeper over time, indicating an increase in velocity.

C) Moving in the positive direction, first fast then slow: This implies an object initially moving in the positive direction at a high speed and gradually slowing down. The sketch would show a line with a positive slope that becomes less steep over time, indicating a decrease in velocity.

D) Moving with negative velocity and negative acceleration: This refers to an object moving in the negative direction with decreasing speed, or decelerating. The sketch would display a line with a negative slope that becomes less steep over time, representing a decrease in velocity.

These sketches provide visual representations of the predicted actions/movements, illustrating the changes in velocity over time for each scenario.

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The intensity of the transmitted light is approximately 96.6 W/m².

The intensity of the transmitted light can be found using Malus's Law which states that the intensity of the transmitted light is equal to the incident intensity multiplied by the square of the cosine of the angle between the transmission axis and the polarization direction of the incident light.

Given that the incident light is vertically polarized and has an intensity of 100 W/m2, and the transmission axis of the polarizer is at an angle of 15 degrees with the vertical, we can calculate the intensity of the transmitted light as follows:

cos^2(15) = 0.966

Transmitted intensity = 100 x 0.966 = 96.6 W/m2

Therefore, the intensity of the transmitted light is 96.6 W/m2.

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Answer:

Momento = 170.8 Kgm/s

Explanation:

Dados los siguientes datos;

Masa = 3,05 kg

Velocidad = 56 m/s

Para encontrar el impulso;

El momento se puede definir como la multiplicación (producto) de la masa que posee un objeto y su velocidad. El momento se considera una cantidad vectorial porque tiene magnitud y dirección.

Matemáticamente, el momento viene dado por la fórmula;

\( Momento = masa * velocidad \)

Sustituyendo en la fórmula, tenemos;

\( Momento = 3.05 * 56 \)

Momento = 170.8 Kgm/s

The wavefunction ψ(x) = Axe^(-αx) satisfies the one-dimensional time independent Schrödinger equation with the potential term V(x) = -xq^2, where q = √(αℏ^2/m).

To show that the wavefunction ψ(x) = Axe^(-αx) satisfies the one-dimensional time independent Schrödinger equation, we need to verify if it satisfies the equation:

(-ℏ^2/2m) * (d^2ψ/dx^2) + V(x)ψ = Eψ

where V(x) = -xq^2. Let's substitute the wavefunction and potential term into the equation and simplify:

(-ℏ^2/2m) * (d^2(Axe^(-αx))/dx^2) + (-xq^2)(Axe^(-αx)) = E(Axe^(-αx))

Differentiating ψ(x) twice, we get:

(-ℏ^2/2m) * [(Ae^(-αx))(α^2x - 2α + 2α^2x^2 - 2αx)] + (-xq^2)(Axe^(-αx)) = E(Axe^(-αx))

Simplifying further, we have:

(Ae^(-αx)) * [(-ℏ^2/2m)(α^2x - 2α + 2α^2x^2 - 2αx) - xq^2] = E(Axe^(-αx))

Expanding and rearranging terms, we obtain:

(Ae^(-αx)) * [-ℏ^2α^2x + ℏ^2(2α - α^2x - 2α^2x^2) - 2mαx^2 - mα^2x^3 + xq^2] = E(Axe^(-αx))

Comparing the coefficients of similar powers of x on both sides, we can equate the terms and obtain a relationship between q and α:

-ℏ^2α^2 = Eq^2   ... (1)

By substituting α = ℏ^2/(2mq^2) into equation (1), we can verify that the relationship holds. Therefore, the wavefunction satisfies the one-dimensional time independent Schrödinger equation with the given potential term.

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About 1,360 watts per square meter

At Earth's average distance from the Sun (about 150 million kilometers), the average intensity of solar energy reaching the top of the atmosphere directly facing the Sun is about 1,360 watts per square meter, according to measurements made by the most recent NASA satellite missions.

Answer:

Real Image

Explanation:

Images which are formed on the screen by the actual intersection of light rays are called real images.

Answer:

Explanation:

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Answer:

The importance of international bureau of weights and measures are;

1. to bring unification of measurement system.

2. to establish and preserve fundamental international prototypes.

3. to verify national standards, etc.

Answer:Hetero

Explanation: Honestly, same as the last guy said

Answer:

there very old

Explanation:

Answer:

105,000km or about 65,244mi

Explanation:

If the space shuttle orbits around it 1.4 times every hour then the speed of the space shuttle in km/hour would be 595330.8 Km/hour, and its speed in meters would be 165369.67 m/s.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

Average speed = total distance /Total time

As given in the problem If the circumference of a space shuttle's orbit around Earth is 42,522 km and the space shuttle orbits around it 1.4 times every hour, then we have to find the speed of the space shuttle in km/hour

The total distance covered by the space shuttle in an hour = 42,522×1.4

                                                                                                 = 595330.8 Km

The speed of the space shuttle in meters/second = 595330.8 × 1000/3600

                                                                                   = 165369.67 m/s

Thus, the speed of the space shuttle would be 595330.8 Km/hour, and its speed in meters would be 165369.67 m/s.

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The four components of the physical universe are matter, energy, space, and time.

The four components of which the entire physical universe exists are:

Matter: All the physical substances that make up the universe, including everything from stars and planets to subatomic particles, are made of matter.

Energy: Energy is a property of matter that can be transformed, but cannot be created or destroyed. It comes in many forms, including kinetic energy, thermal energy, and electromagnetic energy.

Space: Space is the three-dimensional framework in which all matter and energy exist. It provides the canvas on which the universe unfolds and shapes the way objects interact and move.

Time: Time is the dimension in which change occurs. It is essential for the universe to exist and for events to unfold in a causal and ordered manner.

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Answer:

OC.Newton's third law of motion which states that,"every action has equal and opposite reaction."

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Answer:

40 hours

Explanation:

in 20 hours, 1/2 will decay

in 40 hours, 1/4 will decay

therefore, 40 hours

Answer:

the following image will make you understand

Explanation:

the distance, in inches, from the wall to the edge of the door is 8.2 inches.

We must utilise the reference angle that makes a right triangle with the wall and the edge of the door in order to determine the distance between them. The reference angle is 90° - (140°/2) = 20° since the door swings open by 140°.

To get the distance from the wall to the edge of the door, let's utilise trigonometry. Let x represent the distance from the door's edge to the wall. Next, we have:

sin(20°) = x/24

When we multiply both sides by 24, we obtain:

x = 24*sin(20°)

Calculating the answer, we discover:

x ≈ 8.2

Therefore, 8.2 inches or so separate the wall from the door's edge. The distance, rounded to the nearest tenth of an inch, is 8.2 inches.

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The correct arrangement of the tiles for the endothermic reaction is shown in the image attached.

A chemical reaction known as an endothermic reaction takes in heat energy from its environment. In an endothermic reaction, energy is transported from the environment into the system to speed up the reaction since the products have more energy than the reactants.

An endothermic process often involves the absorption of heat energy, which results in a drop in the ambient temperature.

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The plumb bob hangs vertically downwards when the railroad car is at rest. However, when the car moves in a circular track of radius 340 m at a speed of 94 km/h, it experiences a centrifugal force that pulls the plumb bob away from the vertical.

To find the angle relative to the vertical at which the plumb bob hangs, we need to use the formula:

tan(theta) = (v^2) / (g * r)

where:
theta = angle relative to the vertical
v = speed of the railroad car = 94 km/h = 26.11 m/s
g = acceleration due to gravity = 9.81 m/s^2
r = radius of the circular track = 340 m

Substituting the given values, we get:

tan(theta) = (26.11^2) / (9.81 * 340)
tan(theta) = 2.146

Taking the inverse tangent of both sides, we get:

theta = tan^-1(2.146)
theta = 64.7 degrees

Therefore, the plumb bob hangs at an angle of 64.7 degrees relative to the vertical when the railroad car rounds a circular track of radius 340 m at a speed of 94 km/h.

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Answer:

C is corret answer okay

Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

\(F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]\)

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

\((m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})\)

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

\((2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]\)

Now using the following equation of kinematics, we can determine the distance traveled.

\(v_{2}^{2} =v_{1}^{2}+2*a*x\)

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

\(1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]\)

Answer:

the size of a typical campus

Explanation:

The eight planets of the solar system cover the size of a typical campus option (B) is correct.

It is defined as the energy that continuously comes from the sun. As we know, the sun is the greatest source of energy. The sun's radiation reaches the earth and can be utilized as heat energy.

It is given that:

Suppose we imagine the sun to be about the size of a grapefruit.

As we know,

Sun is the greatest source of the energy.

Our solar system is around 160 million times smaller than the Milky Way galaxy, notwithstanding how big this figure may seem.

Thus, the eight planets of the solar system cover the size of a typical campus option (B) is correct.

The question is incomplete.

The complete question is:

Suppose we imagine the Sun to be about the size of a grapefruit. How big an area would the orbits of the eight planets of the solar system cover?

A) the size of a typical dorm room

B) the size of a typical campus building

C) the size of a typical campus

D) the size of a small city

E) the size of a western state (e.g., Colorado)

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