Answer:
960,000
Step-by-step explanation:
Every year, the number of blogs doubled.
The first year:60,000
The Second year: 120,000
The third year: 240,000
The fourth year: 480,000
The fifth year: 960,000
Hope this helps! If you found my answer helpful, please consider marking brainliest! If you have any questions, feel free to ask me in the comments!
A national standard requires that public bridges over 20 foot in length must be inspected and rated overy 2 yours. The rating scalo ranges from 0 (poorest rating) to 9 (highost rating). A group of engineers used aprobabilistio model to forecast the inspection ratings of all major bridges in a city. For the year 2020, the enginoors forecast that 8% of all major bridges in that city will have ratings of 4 or below. Comploto parts aand bea. Use tho forecast to find the probability that in a random sample of 8 major bridgos in the city, at least 3 will have an inspection rating of 4 or below in 2020,PIX23) - (Round to five decimal places as needed.)
We can solve the problem by using the probability binomial distribution model. The formula is:
\(P(X=x)=(^n_x)p^xq^{n-x}\)Recall that:
\((^n_x)=^nC_x\)Given:
number of samples(n) = 8
x = 3
8% of all major bridges in that city will have ratings of 4 or below implying that the probability of a bridge having a rating of 4 or below is 0.08.
Hence,
\(\begin{gathered} p\text{ = 0.08} \\ q\text{ = 1-p } \\ q\text{ = 1-0.08} \\ q\text{ = 0.92} \end{gathered}\)The probability that in a random sample of 8 major bridges in the city, at least 3 will have an inspection rating of 4 or below in 2020 would be:
\(\text{Probability of at least 3 = 1 - Probability of at most }2\)Probability of at most 2 can be reduced to:
\(P(x\text{ }<\text{ 3) = P(x =2) + P(x = 1) + P(x = 0)}\)Evaluating the expression, we have:
\(\begin{gathered} P(x\text{ }<3)=^8C_2(0.08)^2(0.92)^{8-2}+^8C_1(0.08)^1(0.92)^{8-1}+^8C_0(0.08)^0(0.92)^{8-0} \\ =\text{ 0.10866 + 0.35702 + }0.51322 \\ =\text{ 0.9789}0 \end{gathered}\)The probability that at least 3 will have a rating of 4 and below:
\(\begin{gathered} P(x\text{ }\ge3)\text{ = 1 - P(x }<\text{ 3)} \\ =\text{ 1 - 0.97890} \\ =\text{ 0.02110} \end{gathered}\)Answer:
0.02110
Write an equivalent expression to m-(8-3m) without parentheses
m - (8 - 3m)
m - 8 + 3m
m + 3m - 8
4m - 8
Answer:
Step-by-step explanation:
m-(8-3m)
m-8 + 3m
=m+3m-8
=4m-8
Calculate the expected value of playing a lottery ticket game where each ticket costs $5, and the chance of having winning ticket is one in one million, and the payout for having a winning ticket is 4.9 billion dollars. Round the expected value to the nearest cent.
Answer:
$4895
Step-by-step explanation:
P(winning) = 1 / 1000000 = 0.000001
P(not winning) = 1 - 1/1000000 = 0.999999
Winning amount = 4,900,000,000 - 5 = 4899999995
Amount lost = - 5
__ X: - 5 _________ 4899999995
P(X) : 0.999999 ___ 0.000001
Expected value E(x) = Σx * p(x)
E(x) = - 5(0.999999) + 4899999995(0.000001)
E(x) = - 4.999995 + 4899.999995
E(x) = 4895
Hence, expected value is 4895
Help I will give crown and brainiest
Answer:
quad then hex then oct then non
Step-by-step explanation:
Exercise 5.2 Suppose you pay 5 to buy a European (K=100, t=1/2 ) put option on a given security. Assuming a nominal annual interest rate of 6 percent, compounded monthly, find the present value of your return from this investment if (a) S(1/2)=102; (b) S(1/2)=98.
In conclusion, the present value of your return from this investment, when the stock price is 98, is approximately $1.965.
To find the present value of your return from the investment, we need to calculate the value of the European put option at time t=1/2 and then discount it back to the present value using the nominal annual interest rate of 6 percent compounded monthly.
(a) If S(1/2) = 102:
To calculate the value of the European put option at time t=1/2, we need to determine if it is in-the-money or out-of-the-money.
The strike price is K=100, and since the stock price is greater than the strike price (102 > 100), the put option is out-of-the-money. In this case, the put option has no intrinsic value.
The present value of your return from this investment would be $5, as the put option has no value. There is no profit or loss.
(b) If S(1/2) = 98:
Similar to the previous case, we need to determine if the put option is in-the-money or out-of-the-money. Since the stock price is less than the strike price (98 < 100), the put option is in-the-money.
The intrinsic value of the put option is given by the difference between the strike price and the stock price:
K - S(1/2) = 100 - 98 = 2.
To calculate the present value of your return from this investment, we need to discount the intrinsic value of the put option back to the present value. The nominal annual interest rate of 6 percent compounded monthly translates to a monthly interest rate of 6% / 12 = 0.5%.
Using the formula for the present value of a future cash flow:
Present Value = Intrinsic Value / (1 + Monthly Interest Rate)^(Number of Months)
Number of Months = 1/2 years * 12 months/year = 6 months.
Present Value = 2 / (1 + 0.005)^(6)
Present Value ≈ $1.965.
In conclusion, the present value of your return from this investment, when the stock price is 98, is approximately $1.965.
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Write 25 and 13 as equivalent fractions using a common denominator.
Answer:
25/50 + 13/26
Step-by-step explanation:?????Not sure, please have someone else answer i dont want to be the cause of your incorrect answer:(
A company recorded 2 days of accrued salaries of $2,200 for its employees on January 31. On February 9, it paid its employees $8,600 for these accrued salaries and for other salaries earned through February 9. Assuming the company does not prepare reversing entries, the January 31 and February 9 journal entries are:
Solve the following equation:
\(x + \sqrt{x+3} = 3 + 3\sqrt{1-x}\)
Answer:
\(x+\sqrt{x+3}=3+3\sqrt{1-x}\)
\(Remove~ Square ~root\)
\(-36x^3+252x^2-540x+324=\)
\(x^4-32x^3+286x^2-480x+225\)
\(Now ~\mathrm{Switch\:sides}\)
\(x^2-6x\sqrt{-x+1}-15x+18\sqrt{-x+1}+18=x+3\)
\(\mathrm{Subtract\:}x^2-15x\mathrm{\:from\:both\:sides}\)
\(x^2-6x\sqrt{-x+1}-15x+18\sqrt{-x+1}+18-\left(x^2-15x\right)=\)
\(x+3-\left(x^2-15x\right)\)
\(New ~Simplify\)
\(-6x\sqrt{-x+1}+18\sqrt{-x+1}+18=-x^2+16x+3\)
\(Subtract ~18~ from ~ both~ sides\)
\(-6x\sqrt{-x+1}+18\sqrt{-x+1}+18-18=-x^2+16x+3-18\)
\(Simplify\)
\(-6x\sqrt{-x+1}+18\sqrt{-x+1}=-x^2+16x-15\)
\(Now~ factor:\)
\(-6x\sqrt{-x+1}+18\sqrt{-x+1}(-x+3)\)
\(6\sqrt{-x+1}\left(-x+3\right)=-x^2+16x-15\)
\(Solve~~-36x^{3}+252x^{2} -540x+324=x^{4} -32x^{3} +286x^{2} -480x+225=\)
\(x=1,\:x=-3\)
-----------------------hope it helps..have a nice day/nightGiven â³ABC with a 2+ b 2= c 2 , write a two-column proof of the Converse of the Pythagorean Theorem
The converse of the Pythagorean Theorem is that when the sum of the squares of the other two sides square of the length of the longest side of a triangle, then the triangle is a right triangle.
To understand the Pythagorean Theorem let's assume 2 right-angled triangles with the 2 legs = a and b in each case and the longest side = c in one triangle and e in the other.
Pythagoras' Theorem is = \(a^2 + b^2 = c^2\) (Given)
Also in the other triangle \(a^2 + b^2 = e^2\), if it is right-angled.
Therefore a^2 = l^2 and a = e.
So the 2 triangles are congruent by SSS.
So m < e in one triangle = m < e the angles opposite the hypotenuse
Therefore the second triangle is right-angled
The two triangles are said to be congruent by the SSS rule when all three sides of one triangle are equivalent to the corresponding three sides of the second triangle.
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Please help! Will mark brainliest if correct! Use the model attached to answer
Answer:
4 cubes will be shown in the right view of the model and the 1st option is the top view for the model.
What is the formula for calculating the slope m of a line?
The formula or equation used to determine the slope of a straight line is as follows:
m = (Y₂-Y₁)/(X₂-X₁)
What is an equation?An equation is about two expressions, either arithmetic or algebraic, that are related with a "=" sign that indicates equality of expressions.
Equations can be graphed, they are used to model many problems and theories.
The straight lines are characterized by a finite succession of points, when they have an inclination they adopt a slope value different from 0, and to determine that slope it is necessary to know two points of the line and use the following equation:
m = (Y₂-Y₁)/(X₂-X₁)
Where the points are:
P₁ = (X₁,Y₁)P₂ = (X₂,Y₂)Learn more about equations at:
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Please help.
Is algebra.
9514 1404 393
Answer:
6. C multiply the first equation by -7 ...
7. A parallel lines
Step-by-step explanation:
6. The idea of elimination is to create equations that have opposite coefficients for one of the variables. In this set of equations, there are two simple ways to achieve that.
On is to multiply the second equation by -2 (so x-coefficients are 4 in the first equation and -4 in the second equation).
The other is to multiply the first equation by -7 (so y-coefficients are -7 in the first equation and +7 in the second equation).
This latter method is described in answer choice C.
__
7. Equations are more easily compared if they are in the same form. Here, "standard form" is nice. To put the second equation in standard form, we must remove a factor of 3 from all of the numbers:
3(2x) +3(y) = 3(4)
2x +y = 4
We see that this differs from the first equation only in that it has a different right-side constant. That means it describes a parallel line.
Which of the following cannot be in the solution set of w/-2 < 1?
O -1
O 1
O 2
O -2
A patient asks about the purpose of withholding food and fluid before surgery. Which response by the nurse is appropriate?
a)It decreases urine output so that a catheter would not be needed.
b)It prevents overhydration and hypertension.
c)It decreases the risk of elevated blood sugars and slow wound healing.
d)It prevents aspiration and respiratory complications.
Withholding food and fluids before surgery is done to ensure that the patient's stomach is empty. This helps to minimize the risk of aspiration, which occurs when stomach contents enter the lungs. Aspiration can lead to respiratory complications such as pneumonia, which can be dangerous for the patient.
The appropriate response by the nurse is d) It prevents aspiration and respiratory complications. Withholding food and fluid before surgery is important to prevent aspiration, which occurs when stomach contents enter the lungs during surgery, and can cause respiratory complications. It also helps ensure a clear surgical field. However, the patient will still receive necessary fluids and medications through an IV during surgery to prevent dehydration and maintain blood pressure. It is important to follow the healthcare provider's instructions on pre-operative fasting to ensure the safest surgical experience.
d) It prevents aspiration and respiratory complications.
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A certain car is rated to get 26 miles per gallon. How far can it travel on 12.5 gallons of gas?
Our car can do 26 miles with one gallon, so, if we have 12.5 gallons, to find how much we can travel we need to make the product of the amount of gallons we have by the amount of milles we can do with one gallon, wich gives us the expression:
\(12.5\times26=325\)So our car can travel 325 miles with 12.5 gallons of gas.
raina wants to save $900 to buy TV she save $17 each week the amount A (in dollars) that she still needs after W weeks is given by the following function
Answer:
a 19
b 798 dollars
Step-by-step explanation:
a you just plug in a random nuber in
b all you have to do is plug 6 for x
900-17(6)=798
What is the value of the following expression if x = 4, 2x + 3.1
Answer:
11.1
Step-by-step explanation:
x=4
2x+3.1
You need to plug in the 4 into the x in the equation above
2(4)+3.1
8+3.1=11.1
Answer:
11.1
Step-by-step explanation:
here's your solution
=> the value of x = 4
=> the given expression is = (2x + 3.1)
=> putting the value of x in expression
=> 2*4 + 3.1
=> 8 + 3.1
=> 11.1
hope it helps
OA ⊥ OC start overline, O, A, end overline, \perp, start overline, O, C, end overline \qquad m \angle BOC = 6x - 6^\circm∠BOC=6x−6 ∘ m, angle, B, O, C, equals, 6, x, minus, 6, degrees \qquad m \angle AOB = 5x + 8^\circm∠AOB=5x+8 ∘ m, angle, A, O, B, equals, 5, x, plus, 8, degrees Find m\angle BOCm∠BOCm, angle, B, O, C:
Answer:
42 degrees.
Step-by-step explanation:
\(\angle BOC+\angle AOB=90^\circ $(Complementary Angles)\\6x - 6^\circ+5x + 8^\circ=90^\circ\\6x+5x-6^\circ+ 8^\circ=90^\circ\\11x+ 2^\circ=90^\circ\\11x=90^\circ-2^\circ\\11x=88^\circ\\$Divide both sides by 11\\x=8^\circ\\$Therefore:\\m\angle BOC=6x - 6^\circ\\=6(8) - 6^\circ\\=48-6\\=42^\circ\)
The measure of angle BOC is 42 degrees.
Answer:
BOC = 42º
Step-by-step explanation:
Angle BOC is equal to 42 degrees, due to these steps -
1. Create the equation which will result to be -
6x - 6 + 5x + 8 = 90
2. Simplify by adding variables and numbers together -
11x + 2 = 90
3. Subtract 2 from both sides to get -
11x = 88
4. Divide by 11 on both sides to get-
x = 8
5. Substitute x in angle BOC as 8 to get this equation -
6(8) - 6
6. Solve
48 - 6 =
42º
Your final answer for angle BOC is 42º!
* This is the correct answer, I have taken the test and am posting the answers in hopes of helping other people :] *
Based on the diagram, what is tanA?
Enter your answer in the boxes.
tanA=
Aw that's really nice of you thanks
thank you <3 appreciate it loads
The function LaTeX: c\left(t\right)=1.75+0.85\left(t-1\right)c ( t ) = 1.75 + 0.85 ( t − 1 ) represents the cost to call China as a function of the time, in minutes, t, on the phone. When will the cost first exceed $57?
Given:
The cost to call China as a function of the time, in minutes, t, on the phone is
\(c(t)=1.75+0.85(t-1)\)
To find:
The time when the cost first exceed $57.
Solution:
The cost first exceed $57 means cost is greater than $57.
\(c(t)>57\)
\(1.75+0.85(t-1)>57\)
\(0.85(t-1)>57-1.75\)
\(0.85(t-1)>55.25\)
Divide both sides by 0.85.
\(t-1>\dfrac{55.25}{0.85}\)
\(t-1>65\)
\(t>65+1\)
\(t>66\)
Therefore, after 66 minutes the cost to call china will exceed $57. It means first at t=67 the cost will exceed $57.
y=-7x+10 in standard form
Answer:
Write in standard form.
7x+y=10
Step-by-step explanation:
A pizza restaurant has 63 and 2/3 cups of flour. Each batch of pizza dough uses 5 and 1/4 cups of flour. About how many batches of pizzas will they be able to make.
Answer:
12
Step-by-step explanation:
Helppppppppppppppppppppp
Answer:
5
Step-by-step explanation:
the square root of 25 is 5, i hope this this the answer you are looking for! brainliest please, and thanks!! have a good day! :)
Answer:
5
Step-by-step explanation:
Graph the solution of the inequality on a number line. 2(x - 3) - 5x < x-2
Answer:
good luck with this, i have got a good mark in this lesson back then and i would gladly like to help you miss gilr
Step-by-step explanation:
Option D is representing the inequality 2(x - 3) - 5x < x-2 on the number line.
What is a number line?A number line in elementary mathematics is a representation of a graduated straight line that serves as an abstraction for real numbers, represented by the symbol R."
It is assumed that every point on a number line corresponds to a real number and that every real number corresponds to a point.
Given that the inequality is 2(x - 3) - 5x < x-2. The inequality will be solved as,
2(x - 3) - 5x < x-2
2x - 6 - 5x < x - 2
-3x - 6 < x - 2
-3x - x < 6 - 2
-4x < 4
x > -1
The number line of the inequality is attached with the answer below.
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Find the derivative:
f(x)=tan\((x^{2} +5)\)
Answer:
\( 2x \sec^2 (x^2 + 5) \)
Step-by-step explanation:
\( f(x) = \tan (x^2 + 5) \)
\( \dfrac{d}{dx} \tan u = \sec^2 u \dfrac{d}{dx} u \)
\( \dfrac{d}{dx} \tan (x^2 + 5) = \sec^2 (x^2 + 5) \dfrac{d}{dx} (x^2 + 5) \)
\( \dfrac{d}{dx} \tan (x^2 + 5) = [\sec^2 (x^2 + 5)]2x \)
\( \dfrac{d}{dx} \tan (x^2 + 5) = 2x \sec^2 (x^2 + 5) \)
PLEASE HELP
ASAP!! i’ve been on it for 2 hrs
C. Two vectors are said to be parallel if they point in the same direction or if they point in
opposite directions.
i. Are the vectors = < 1> and = <--1> parallel? Show your work and explain.
Type your response here:
ii. Are the vectors = <2, 3> and = <-3, -2> parallel? Show your work and explain.
Type your response here:
Answer:
Hey there,
The answer is below!!
Step-by-step explanation:
Knowing that those vectors start at the point (0,0) we can "think" them as lines.
As you may know, two lines are parallel if the slope is the same, then we can find the "slope" of the vectors and see if it is the same.
A) the vectors are: (√3, 1) and (-√3, -1)
You may remember that the way to find the slope of a line that passes through the points (x1, y1) and (x2, y2) is s = (y2 - y1)/(x2 - x1)
Because we know that our vectors also pass through the point (0,0)
then the slopes are:
(√3, 1) -----> s = (1/√3)
(-√3, -1)----> s = (-1/-√3) = (1/√3)
The slope is the same, so the vectors are parallel.
Part B:
The vectors are: (2, 3) and (-3, -2)
the slopes are:
(2, 3) -----> s = 3/2
(-3, -2)----> s = -2/-3 = 2/3
the slopes are different, so the vectors are not parallel.
At McDonald’s, a cheeseburger has 1/10 pound of meat. A
quarter-pounder has 1/4 pound of meat.
a. How much more meat is used for the quarter-pounder?
Answer:
3/20 of more meat is used for a quarter pounder
I think of a number. I double it. I divide the result by 5. My answer is 6. What number did I think of?
The tangent line to the graph of y=h(x) at the point (-1,4) passes through the point (3,6). Find h(-1) and h'(-1).
The value for h(-1) is 4
The value for h'(-1) is 1
Given the tangent line to the graph of y=h(x) at the point (-1,4) passes through (3,6), to get h(-1) and h'(-1), we should calculate the following:
Gradient of the tangent line:
Gradient=change in y axis/change in x axis=Δy/Δx
Using the x and y coordinates (-1,4) and (3,6)
Gradient=(6-4)/(3--1)
=2/4
=1/2
Gradient=1/2 or 0.5
Equation of the tangent line:
This should be in the form of y=mx+c, where m is the gradient of the line
We use the gradient and one of the x and y coordinates get the equation of the tangent line
Gradient=change in y axis/change in x axis=Δy/Δx, and gradient was found as 1/2
Δy/Δx=1/2
(y-4)/(x--1)=1/2
(y-4)/(x+1)=1/2
2y-8=x+1
y=(1/2)x+4.5
Equation of the tangent line is y=(1/2)x+4.5 or y=0.5x+4.5
And y=h(x)
So, h(x)=0.5x+4.5
Calculate h(-1), here x=-1:
h(x)=0.5x+4.5
h(-1)=(0.5*-1)+4.5
=4
h(-1)=4
Calculate h'(-1), x=-1:
Here we get the derivative of the equation of the tangent line h(x)=0.5x+4.5,
h'(x)=0.5x^0+0
h'(-1)=1+0
h'(-1)=1
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the sum or two numbers is -4 and their difference is 12. What are the two numbers?
Answer:
above is the answer to the question