A boat moving at a constant speed travels 15 meters in 8 seconds. How far does it travel
in 40 seconds?
75 meters
53 meters
335 meters
480 meters
Answers
Related Questions
A ball is launched from inside a cylindrical device that has been set on a frictionless incline and turned loose
What can be determined about where the ball will land ?
The ball will land back in the cylinder.
The ball will land behind the cylinder.
It depends on the mass of the ball.
The ball will land in front of the cylinder.
It cannot be determined.
Answers
The velocity of the ball in the forward direction is the same as the initial velocity with which it was launched.
A ball is launched from inside a cylindrical device that has been set on a frictionless incline and turned loose. What can be determined about where the ball will land?It can be determined that the ball will land in front of the cylinder.
This can be explained with the help of a few concepts of Physics. When an object moves on an incline without friction, then it can be divided into two components, which are: gravity and normal force.
Here, gravity is acting towards the center of the Earth, whereas the normal force is perpendicular to the incline. Let's suppose that the ball is launched with a certain velocity, which makes it move along the incline and get projected in the forward direction.
If we think of the motion of the ball from the observer's point of view who is standing on the incline, then the motion will appear to be parabolic. This is because the observer would see that the ball is moving forward with a constant velocity, but its vertical position keeps changing due to the effect of gravity.
However, from the observer's point of view who is standing in front of the cylinder, the motion of the ball will look like it is a projectile.
The velocity of the ball in the forward direction is the same as the initial velocity with which it was launched.
But, due to the effect of gravity, the vertical component of the velocity would change, which would result in a parabolic path of the ball. Therefore, the ball will land in front of the cylinder.
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The velocity of the ball in the forward direction is the same as the initial velocity with which it was launched. It can be determined that the ball will land in front of the cylinder. The correct option is The ball will land in front of the cylinder.
A ball is launched from inside a cylindrical device that has been set on a frictionless incline and turned loose. What can be determined about where the ball will land?It can be determined that the ball will land in front of the cylinder.
This can be explained with the help of a few concepts of Physics. When an object moves on an incline without friction, then it can be divided into two components, which are: gravity and normal force.
Here, gravity is acting towards the center of the Earth, whereas the normal force is perpendicular to the incline. Let's suppose that the ball is launched with a certain velocity, which makes it move along the incline and get projected in the forward direction.
If we think of the motion of the ball from the observer's point of view who is standing on the incline, then the motion will appear to be parabolic. This is because the observer would see that the ball is moving forward with a constant velocity, but its vertical position keeps changing due to the effect of gravity.
However, from the observer's point of view who is standing in front of the cylinder, the motion of the ball will look like it is a projectile.
The velocity of the ball in the forward direction is the same as the initial velocity with which it was launched.
But, due to the effect of gravity, the vertical component of the velocity would change, which would result in a parabolic path of the ball. Therefore, the ball will land in front of the cylinder.
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What rate of heat input (either electrical or from gas) is required to operate such a unit, assuming that all the heat goes into the water
Answers
To determine the rate of heat input required to operate a unit where all the heat goes into the water, we need additional information such as the specific heat capacity of water and the desired temperature change.
The rate of heat input can be calculated using the formula:
Rate of heat input = (Mass of water) x (Specific heat capacity of water) x (Temperature change per unit time). The mass of water is typically measured in kilograms (kg), the specific heat capacity of water is around 4.186 joules per gram per degree Celsius (J/g°C) or 4,186 joules per kilogram per degree Celsius (J/kg°C), and the temperature change per unit time is measured in degrees Celsius per second or degrees Celsius per hour, depending on the specific scenario. Once we have the desired temperature change and the time period over which the heat input is measured, we can use these values to calculate the required rate of heat input. Please provide the necessary information, such as the mass of water and the desired temperature change, for a more accurate estimation of the rate of heat input.
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According to Jean Piaget, in what stage of cognitive development are children able to understand conservation tasks?
Answers
Answer:
Preoperational
Explanation:
According to Piaget's theory of cognitive development, the preoperational stage is the second stage. This stage includes children between the age group of 2 to 7 years. Children can understand conservation tasks and learn to manipulate various symbols during this stage.
So, the answer is the preoperational stage.
Answer:
B Preoperational
Explanation:
This is the answer the person above is correct!
This is for edge 2021/2022
Hope this helps!!
8. Jame's mom slammed on her brakes to avoid a squirrel. The
squirrel is most concerned with?
a. Direction
b. Acceleration
c. Deceleration
d. Speed
I really need help..
Answers
Answer:
c
Explanation:
deceleration
15cm 20cm find area
Answers
I already did part a and the magnitude for all the parts. I need help finding the direction.
Answers
b)
Given that,
A=10 N at 0°
B=20 N at 180°
As we can see these two vectors are in opposite directions.
Thus the resultant vector will be in the direction of the vector with the higher magnitude.
In vector addition we can write,
\(C=10\cos 0^0+20\cos 180^0\)Where C is the resultant vector.
Thus magnitude of R will be equal to,
\(R=-10\text{ N}\)The negative sign indicates that the direction of the C is along the negative x-axis.
Thus the magnitude of C is 10 N and the direction of the C is 180°
a)
Given,
A= 10 N at 0°
B=20 N at 0°
The the vector C is
\(C=10\cos 0^0+20\cos 0^0=30\text{ N}\)The direction of R will be along the direction of these two vectors, as they are in the same direction.
Thus the magnitude of the vector C will be 30 N and the direction of the vector C is 0°
c)
Given,
A=10 N at 180°
B=20 N at 180°
Thus the vector C is
\(C=10\cos 180^0+20\cos 180^0=-30\text{ N}\)The direction of the vector C will be along the direction of the negative x-axis, as these two vectors are along the negative x-axis.
Thus the magnitude of the vector C is 30 N and the direction of the vector C is 180°
d)
Given,
A= 10 N at 0°
B=20 N at 90°
The x-component of the vector C will be,
\(C_x=10\cos 0^0+20\cos 90^0=10\text{ }\hat{\text{i}}\)The y- component of C will be,
\(C_y=10\sin 0^0+20\sin 90^0=20\text{ }\hat{j}\)The magnitude of vector C is given by,
\(\begin{gathered} C=\sqrt[]{C^2_x+C^2_y}_{} \\ =\sqrt[]{10^2+20^2} \\ =22.36\text{ N} \end{gathered}\)The direction of the vector C will be,
\(\begin{gathered} \theta=\tan ^{-1}\frac{C_y}{C_x} \\ =\tan ^{-1}\frac{20}{10} \\ =63.43^0 \end{gathered}\)Thus the magnitude of C will be 22.36 N and the direction of C will be 63.43°
e)
Given that
A= 10 N at 90°
B=20 N at 0°
The x-component of the vector C will be
\(C_x=10\cos 90^0+20\cos 0^0=20\text{ }\hat{\text{i}}\)The y-component of the vector C will be
\(C_y=10\sin 90^0+20\sin 0^0=10\text{ }\hat{j}\)The magnitude of the vector C will be
\(\begin{gathered} C=\sqrt[]{C^2_x+C^2_y}_{} \\ =\sqrt[]{20^2+10^2} \\ =22.36\text{ N} \end{gathered}\)The direction of vector C will be,
\(\begin{gathered} \theta=\tan ^{-1}\frac{C_y}{C_x} \\ =\tan ^{-1}\frac{10}{20} \\ =26.56^0 \end{gathered}\)Thus the magnitude of the vector C will be 22.36 N and the direction of the vector C will be 26.56°
A man is whirling a 0.25 kg ball on a 1.5 m long string at 3 m/s. Find the centripetal acceleration of this ball.
O 13.5 m/s2
0 0.5 m/s2
m.
2 m/s2
6 m/s2
Answers
The centripetal acceleration of the ball been whirled in a circular path is 6m/s².
Hence, Option D) 6m/s² is the
Given the data in the question:
Mass of ball; \(m = 0.25kg\)Length of string or radius; \(r = 1.5m\)Speed; \(v = 3m/s\)Centripetal acceleration is the acceleration of a particle moving in a circular path. It is expressed as:
\(a_c = \frac{v^2}{r}\)
Where \(a_c\) is the Centripetal acceleration, v is the speed of the motion and r is the length of the string or radius of the circular pattern.
We substitute our given values into the equation
\(a_c = \frac{(3m/s)^2}{1.5m}\\\\a_c = \frac{9m^2/s^2}{1.5m}\\\\a_c = 6m/s^2\)
The centripetal acceleration of the ball been whirled in a circular path is 6m/s².
Hence, Option D) 6m/s² is the correct answer.
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What are sport skills sometimes referred to as?
a skill-related fitness
b. performance skills
c. health-related fitness
d. physical fitness
Answers
A simple motor consists of a wire loop that spins in a uniform magnetic field. As the the loop spins, the angle between its pivot axis and the force on the loop changes. At what angle does the torque on the loop change direction?.
Answers
At zero degree the torque on the loop change direction as a record of the loop spins in a uniform magnetic field.
What is torque and how come the angle 0 degree for the loop to change the direction?Simply we can say torque means rotational force because it helps to rotate objects.But actually torque is the product of force and radius distance.The unit of torque is N/m.The initial maximum flux is passing across the loop, when rotates flux decreases.when becomes parallel to the magnetic field the flux becomes zero.To know more about torque visit:
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What happens to the lifetime of stars as they become more massive?.
Answers
You want to have a subject exercise at 125 Watts with an RPM of
60 for 3 minutes. What resistance (in SI units) do you set the
cycle ergometer to (include your units
Answers
To determine the resistance in SI units that you need to set the cycle ergometer to, given that you want to have a subject exercise at 125 watts with an RPM of 60 for 3 minutes, follow the steps below:
Step 1: Determine the energy used in Joules during the 3 minutes at 125 watts.
P = W / tWhere:
P = power (125 watts)t = time (3 minutes converted to seconds
= 3 × 60 = 180 seconds)
W = energy used in Joules (to be determined)
Substituting the given values:
P = W / t125
= W / 180W
= 125 × 180W
= 22,500 Joules
Step 2: Determine the work done (in Joules) per revolution (360 degrees).
Work done per revolution = energy used in Joules / number of revolutions per minute / 60
Where:number of revolutions per minute = RPM / 60
Substituting the given values:
Work done per revolution = 22,500 / (60 / 60) / 360
Work done per revolution = 22,500 / 1 / 360
Work done per revolution = 22,500 × 360
Work done per revolution = 8,100,000 Joules
Step 3: Determine the torque needed to perform one revolution (360 degrees) of the pedals in SI units (N-m).Torque = work done per revolution / (2 × π)
Where:
2 × π = 6.2832
Substituting the given values:Torque = 8,100,000 / 6.2832
Torque = 1,288,684.08 N-m
Step 4:
Determine the resistance (force) needed at the pedals in Newtons (N) to produce the required torque.Resistance = Torque / pedal radius
Where:pedal radius = 0.175 m (average for a cycle ergometer)
Substituting the given values:
Resistance = 1,288,684.08 / 0.175
Resistance = 7,358,971.89 N (Newtons)
Therefore, you would need to set the resistance to 7,358,971.89 N (Newtons) on the cycle ergometer to achieve the desired subject exercise at 125 Watts with an RPM of 60 for 3 minutes.
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VOTING BRAINLIEST FOR ANYONE WHO ANSWERS RIGHT!!
PLS HELP
Answers
Answer:
B
Explanation:
-1 e so the atomic number should increase so,
B. Np
a 4 kg bowling ball videos rolling down a lane at bowling alley at 6 m/s when the ball strikes the pins is moving your 5.1 m/show much energy in the J is lost due to the friction?
Answers
Answer:
19.98Joules
Explanation:
Energy possessed by the body is the kinetic energy
Kinetic Energy = 1/2mv²
m is the mass
v is the velocity
For the 4kg moving at 6m/s
kE = 1/2 * 4 * 6^2
KE = 1/2 * 4 * 36
KE = 72Joules
For the 4kg moving at 5.1m/s
kE = 1/2 * 4 * 5.1^2
KE = 1/2 * 4 *26.01
KE = 52.02Joules
Amount of Energy lost = 72 - 52.02
Amount of Energy lost = 19.98Joules
Hence the amount of Energy lost is 19.98Joules
How does changing the mass of planets change the gravity?
Answers
Problem 08.058-RC op amp circuit with stepped voltage, find voltage expression with time constant If 4-8, obtain an expression for the voltage vy as labeled in the op amp circuit. www 5012 The expression of vis 8 mF www e-TV, where Tis ms.
Answers
The voltage expression for vy in the given RC op amp circuit with a stepped voltage can be obtained by considering the time constant. If the time constant is 4-8, and the expression for the voltage across the resistor R is 8 mF, where T is in ms, the expression for vy can be derived.
In the given RC op amp circuit, the voltage across the resistor R is given by the expression vy = vis * (1 - e^(-t/RC)), where vis is the input voltage, t is the time, R is the resistance, and C is the capacitance.
Given that the time constant is 4-8, we can assume that the product of R and C is equal to this time constant. Let's assume RC = τ, where τ lies between 4 and 8.
Substituting RC = τ and the given expression for vis as 8 mF (where T is in ms), we can write the voltage expression as vy = 8 * (1 - e^(-t/τ)).
This expression represents the voltage across the resistor R, labeled as vy in the op amp circuit, as a function of time and the time constant τ.
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if the systolic pressures of two patients differ by 10 millimeters, by how much would you predict their diastolic pressures to differ? round the answer to three decimal places.
Answers
Systolic pressure variation is a non-invasive method to assess fluid responsiveness and volume status. In a positive pressure breath, it is the difference between the maximum and minimum systolic blood pressure values.
Thus, A positive pressure breath begins with a brief rise in systolic blood pressure (delta up), which is swiftly followed by a fall in systolic blood pressure (delta down) after four or five beats.
Because of decreased preload to the right ventricle, increased afterload to the right ventricle, and decreased afterload to the left ventricle, increases in intrathoracic pressure during positive pressure ventilation result in a decrease in systolic blood pressure.
When there is hypovolemia, this decline is higher. Hypovolemia has been identified using systolic pressure variations in response to respiratory fluctuation.
Thus, Systolic pressure variation is a non-invasive method to assess fluid responsiveness and volume status. In a positive pressure breath, it is the difference between the maximum and minimum systolic blood pressure values.
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a rigid, hollow sphere is submerged in boiling water in a room where the air pressure is 1.0 atm. the sphere has an open valve with its inlet just above the water level. after a long period of time has elapsed, the valve is closed. what will be the pressure inside the sphere if it is then placed in a mixture of ice and water?
Answers
The pressure inside the sphere will be lower in the ice and water mixture than it was in the boiling water, but the exact value depends on the initial conditions and specific values of the variables in the ideal gas law.
Assuming the rigid, hollow sphere is initially filled with air, the pressure inside the sphere will be equal to the atmospheric pressure of 1.0 atm when it is submerged in boiling water and the valve is open. This is because the air inside the sphere is in equilibrium with the surrounding air pressure.
When the valve is closed, the air inside the sphere is trapped and the pressure inside the sphere will decrease as the temperature of the air decreases due to thermal contraction. When the sphere is placed in a mixture of ice and water, the temperature of the air inside the sphere will decrease further and its pressure will decrease accordingly.
The final pressure inside the sphere in the ice and water mixture will depend on the volume of the sphere and the amount of air trapped inside. Assuming the volume of the sphere remains constant, the pressure inside the sphere will decrease as the temperature decreases according to the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.
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Not
sure if I'm correct.
.bloow The fewer the number of substitutes for a good: (a.) the less elastic the demand. b. the more elastic the demand.easenoni vtitnsu c. the more elastic the supply. sesetoeb yliinau d. the less el
Answers
The fewer the number of substitutes for a good, the less elastic the demand.
The concept of elasticity measures the responsiveness of demand or supply to changes in price. When there are fewer substitutes available for a particular good, consumers have limited alternatives to switch to if the price of that good increases. As a result, the demand for the good becomes less elastic, meaning that the quantity demanded is less responsive to changes in price.
In this scenario, option (a.) is correct. When there are fewer substitutes for a good, consumers have a more limited range of choices, making them less likely to respond strongly to changes in price. On the other hand, if there are many substitutes available, consumers have more flexibility to switch to alternative goods if the price of one particular good increases, resulting in a more elastic demand.
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the complete question is
The fewer the number of substitutes for a good: (a.) the less elastic the demand. b. the more elastic the demand.easenoni vtitnsu c. the more elastic the supply. sesetoeb yliinau d. the less elastic the supply
A car applies a force of 36. 8 newtons for a 668-meter loop; what was the work done?.
Answers
The value of the work that was done on the car is 24.6 J.
How to calculate how much the work on the car was done?Work is an energy that move from or to one object into another object that might make the object have the displacement, or we can say work is equal to force multiply with displacement in meters. In formula form, it will be written as W = F x s. As per data given F = 36.8 N and s = 668 m. The work will be:
W = F x s
W = 36.8 x 668
W = 24,582J
Let round the work value. So, the work value will be 24.6 J
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Filiberto va a 90m/s en su carri, de repente se distrae por un par de segundos y su velocdad pasa a 40 m/s ¿cual fue su aceleracion de su movimientonto
Answers
Answer:
Filiberto experimenta una deceleración de \(2\,\frac{m}{s^{2}}\).
Explanation:
(The problem was written in Spanish. Hence, explanation will be held in Spanish).
Asúmase que Filiberto se distrae por 2 segundos, puesto que un par equivale a dos, y que el vehículo experimenta un aceleración constante. La deceleración experimentada por el vehículo se deriva de la siguiente fórmula:
\(a = \frac{v-v_{o}}{\Delta t}\)
\(a = \frac{40\,\frac{m}{s}-90\,\frac{m}{s} }{2\,s}\)
\(a = -25\,\frac{m}{s^{2}}\)
Filiberto experimenta una deceleración de \(2\,\frac{m}{s^{2}}\).
Anybody knows this thanks !
Answers
Answer:
225J
Explanation:
1/2mvsq=1/2×50×9
Answer:
b. 225 J
Explanation:
Velocity (v) = 3 m/s
Mass (m) = 50 kg
\(K. E. = \frac{1}{2} m {v}^{2} \\ \\ = \frac{1}{2} \times 50 \times {3}^{2} \\ \\ = 25 \times 9 \\ \\ = 225 \: j \)
A car going around a curve with a radius of 15m experiences a centripetal acceleration of 2.5 m/s2. How fast is the car going?
0.17m/a
38 m/s
6.1 m/s
6.0 m/s
Answers
Answer:
Explanation:
The formula for centripetal acceleration is
\(a_c=\frac{v^2}{r}\) . Filling in:
\(2.5=\frac{v^2}{15}\) and
\(v=\sqrt{2.5(15)}\) so
v = 6.1 m/s
If a body of mass 4 kg moves at a velocity of 25 m/s and has a completely inelastic collision with a body of mass 10 kg, the final velocities of both the bodies is 14 m/s. Calculate the initial velocity of the body of mass 10 kg.
Answers
We are given the following information about an inelastic collision.
Mass of 1st object = 4 kg
Mass of 2nd object = 10 kg
Initial velocity of 1st object = 25 m/s
Final velocity of both objects = 14 m/s
Initial velocity of 2nd object = ?
In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.
Recall that the total momentum is conserved and given by
\(m_1u_1+m_2u_2=(m_1+m_2)v_2\)Let us substitute the given values and solve for initial velocity of the body (u2)
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_2 \\ 4\cdot25+10\cdot u_2=(4+10)\cdot14 \\ 100+10\cdot u_2=196 \\ 10\cdot u_2=196-100 \\ 10\cdot u_2=96 \\ u_2=\frac{96}{10} \\ u_2=9.6\; \frac{m}{s} \end{gathered}\)Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s
You have determined the volume of a sphere to be 4.21 m3 and the radius to be 1.002 m. what is the value of you would determine from this experiment to the proper number of significant digits.
Answers
The value you would determine from this experiment to the proper number of significant digits would be \(4.2 m^3\)
To determine the value with the proper number of significant digits, you need to consider the number of significant figures in the given measurements. The volume of the sphere is given as \(4.21 m^3\), which has three significant figures. The radius is given as \(1.002 m\), which also has four significant figures. When calculating the volume of a sphere using the formula \(V = (4/3)\pi r^3\), you need to use the radius value with the least number of significant figures.
In this case, that would be three significant figures from the volume measurement. Therefore, the value you would determine from this experiment to the proper number of significant digits would be \(4.2 m^3\)
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your task is to build a road joining a ranch to a highway that enables the drivers to reach the city in the shortest time. how should this be done if the speed limit is 40mi/h on the road and 65 mi/h on the highway? the perpendicular distance from the ranch to the highway is 20mi, and the city is 30mi down the highway
Answers
A straight road from the ranch to the highway at a perpendicular angle, with a distance of approximately 36.06 miles.
To minimize the travel time from the ranch to the city, we need to find the shortest distance between the ranch and the highway, and then build a straight road connecting the ranch to the highway.
Let's draw a diagram to represent the situation:
R C
\ /
\ /
\ /
\ /
H
In this diagram, R represents the ranch, C represents the city, and H represents the point on the highway that is closest to the ranch. The perpendicular distance between R and H is given as 20 miles, and the distance between H and C is given as 30 miles.
We can use the Pythagorean theorem to find the distance between R and H:
d(R,H) = sqrt(20^2 + x^2)
where x is the distance from H to C that we need to find.
To minimize the travel time, we need to minimize the total time it takes to travel from R to C. This time is given by the equation:
t = t1 + t2
where t1 is the time it takes to travel from R to H, and t2 is the time it takes to travel from H to C.
The time it takes to travel from R to H is given by:
t1 = d(R,H) / 40
The time it takes to travel from H to C is given by:
t2 = (30 - x) / 65
Therefore, the total time it takes to travel from R to C is:
t = d(R,H) / 40 + (30 - x) / 65
We want to minimize this expression with respect to x.
To do this, we can take the derivative of t with respect to x, set it equal to zero, and solve for x:
dt/dx = -1/65
Setting this equal to zero, we get:
-1/65 = 0
This equation has no solution, which means that there is no minimum or maximum value of t. However, we can use our common sense to see that the shortest time is achieved when the road from the ranch is perpendicular to the highway.
Therefore, we should build a road from the ranch to the highway at a right angle. The distance between the ranch and the closest point on the highway is 20 miles, and the distance between this point and the city is 30 miles. Therefore, the length of the road we need to build is:
\(\sqrt{(20^2 + 30^2)\) = \(\sqrt{ (1300)\) = 36.06 miles (approximately)
So, we should build a straight road from the ranch to the highway at a perpendicular angle, with a distance of approximately 36.06 miles.
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The average person can hear sound waves ranging in frequency from about 20 Hz to 20 kHz. Determine the
wavelengths at these limits, taking the speed of sound to be 340 m/s.
Given:
Equation:
Solution:
Answers
The wavelengths at the frequency limits of 20 Hz and 20 kHz are approximately 17 meters and 0.017 meters (or 17 mm), respectively.
To determine the wavelengths at the frequency limits of 20 Hz and 20 kHz, we can use the equation:
Wavelength = Speed of Sound / Frequency
Given:
Speed of Sound = 340 m/s
Frequency:
Lower Limit = 20 Hz
Upper Limit = 20,000 Hz (20 kHz)
For the lower limit:
Wavelength_lower = Speed of Sound / Frequency_lower
= 340 m/s / 20 Hz
= 17 meters
For the upper limit:
Wavelength_upper = Speed of Sound / Frequency_upper
= 340 m/s / 20,000 Hz
= 0.017 meters (or 17 mm)
Therefore, the wavelengths at the frequency limits of 20 Hz and 20 kHz are approximately 17 meters and 0.017 meters (or 17 mm), respectively.
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the molecules in a solid state have _______ energy then molecules in a gas state
Answers
Answer:
less
Explanation:
hope this helps....................:)
How many joules per coulomb are given to charges that flow in a 120-volt circuit?
due tmr!! please help
Answers
The number of joules per coulomb for 120-volt circuit is 120 joules/C.
What is the number of Joules flowing in the circuit?
The amount of energy transferred to each unit of charge is given by the voltage or potential difference between two points.
The unit of potential difference is the volt, which is equivalent to one joule per coulomb.
So if we have a 120-volt circuit, each coulomb of charge that flows between two points receives 120 joules of energy.
Energy per unit charge = Potential difference
= 120 volts
= 120 joules/coulomb
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An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster. If her velocity increases to 5 m/s, what is her change in kinetic energy as a result? J How much work did she perform? J
Answers
Answer:
640 J
Explanation:
ΔKE = KE − KE₀
ΔKE = ½ mv² − ½ mv₀²
ΔKE = ½ m (v² − v₀²)
ΔKE = ½ (80 kg) ((5 m/s)² − (3 m/s)²)
ΔKE = 640 J
Her kinetic energy increases by 640 J, so she does 640 J of work.
It's 640 for both answers. :)
how does Newton's third law of motion give a property of process
Answers
Answer:
Newton's third law explains the generation of thrust by a rocket engine. In a rocket engine, hot exhaust gas is produced through the combustion of a fuel with an oxidizer. The hot exhaust gas flows through the rocket nozzle and is accelerated to the rear of the rocket. In re-action, a thrusting force is produced on the engine mount.
Explanation:
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