A bowling ball and a Ping-Pong ball are rolling at the same speed. Which ball requires more force to stop

Answers

Answer 1

Answer

The bowling ball

Explanation:

due to the bowling ball having a larger mass then the ping pong ball


Related Questions

A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did the kicker apply to the football?

A. 15.5 N
B. 7.5 N
C. 14.5 N
D. 30 N

Answers

Answer:

Explanation:

F = m*a = (0.5)*15 = 7.5 N

A step down transformer with an input voltage of 220V decreases the voltage to half of the input .There is a current flowing of 15A in the primary coil. Find the output current

Answers

The output current for the given step down transformer is 30A.

What is the step down transformer?

A step down transformer is a passive device that converts high voltage power to low voltage power, while the output current is higher than the  input current. They are used in power adaptors and rectifiers to decrease the voltage to the desired level. It works according to Faraday's law of Electromagnetic induction.

The current in the windings of a step down transformer is inversely proportional to the voltage in windings as:

Input voltage / Output voltage = Output current / Input current

220 / 110 = Outout current / 15

Output current = 30A

Hence, the output current (30A) obtained is higher than the given input current (15A).

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What happens to the body’s immune system when attacked by HIV ?

Answers

Answer:

HIV attacks a specific type of immune system cell in the body. It's known as the CD4 helper cell or T cell. When HIV destroys this cell, it becomes harder for the body to fight off other infections.

Explanation:

A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no appreciable air drag. How tall, in meters, is the building?

Answers

Answer:A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no ..

A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50
A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50

How many electrons circulate each second through the cross section of a conductor, which has a current intensity of 4A.

Answers

Answer:

2.5×10¹⁹

Explanation:

4 C/s × (1 electron / 1.60×10⁻¹⁹ C) = 2.5×10¹⁹ electrons/second

If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin​

Answers

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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the energy processed and used by living beings is

Answers

Answer:

Nutrition , heat , wind

Explanation:

Consider an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
1.What is the electric flux through the cylinder due to this infinite line of charge?
2.What is the flux through the cylinder if its radius is increased to r= 0.600 m ?
3.What is the flux through the cylinder if its length is increased to l= 0.990 m ?

Answers

The electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C

Given an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.

Solve for the electric flux through the cylinder due to this infinte line:

As below equation mentions, the electric flux for a uniform electric filed is given by:

Фₓ = EA cosΦ

Φₓ = λLcosΦ)/ε

Φₓ = (3 x 10^(-6) x 0.4 x cos0)/(8.854 x 10^(-12))

Φₓ = 1.355 x 10^(5) Nm²/C

Hence the electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C

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Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom of the hill and car C is at the top. Suppose each car suddenly brakes hard and starts to skid. Assume μk=1.00. What is the x-component of the tangential acceleration (i.e., the acceleration parallel to the road) of car A?

Answers

Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.

How do kinetic and potential energy compare?

The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.

They are being affected by the kinetic frictional force, which is caused by:

f = μk * N

Therefore,

fB = μk * N = μk * mB * g

Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,

fC = μk * N = μk * mC * g

where mC is the mass of Car C.

For Car A, the x-component of the tangential acceleration is given by:

aA = (fB - fC) / mA

where mA is the mass of Car A.

We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:

aA = (μk * mB * g - μk * mC * g) / mA

aA = μk * g * (mB - mC) / mA

Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:

aA = (mB - mC) * 9.81 / mA

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Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom

you're reading from the journal of a European explorer from the early 1600s. In one passage, the explorer describes itting on the Atlantic Ocean with little wind. He describes the area as being quite far north of the equator and having nigh pressure. n which type of global wind was this explorer sailing? doldrums horse latitudes jet stream O polar easterlies ​

Answers

Answer: horse latitudes

Explanation:

Answer:

B

Explanation:

Doldrums are located some 5 degrees away from north while horse latitude is located some thirty degrees away from north latitude and by same degrees from the southern hemisphere. Polar eastariles are cold winds blowing across the Polar Regions and jet stream is fast blowing winds.  

Horse latitude is silent winds and the region has high pressure and very little precipitation.  

Hence, option B is correct

3500 as a power of 10​

Answers

Answer: 3.5 × 10^3

Explanation:

What is the largest known star?

Answers

Answer:

UY Scuti is slightly larger than VY Canis Majoris

Explanation:

These stars are millions of miles away and cannot be seen by the naked eye.

Beetlejuice is another large star that can be seen by the eye.

4. A 40.0 kg child swings in a swing supported by two chains, each 3.00 m long. If the tension in each at the lowest point is 350N, find (i) The child’s speed at the lowest point ,

Answers

The child's speed at the lowest point is 5.42 m/s.

At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.

Using the conservation of mechanical energy, we can write:

Potential energy at highest point = Kinetic energy at lowest point

mgh = (1/2)mv²

where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.

First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:

h = (1/2)3.00 m = 1.50 m

Next, we can solve for the child's speed at the lowest point:

mgh = (1/2)mv²

40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²

588 J = 20.0 kg * v²

v² = 29.4 m²/s²

v = 5.42 m/s

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What force acts on a projectile in the horizontal direction?

Answers

The force that acts on a projectile in the horizontal direction is Gravitational force.


A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.


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Rudy plans to conduct an experiment using three rosebushes of the same variety and size. His hypothesis is that the plant
receiving the most sunlight at the end of three months will show the most growth. In his plan below, he has listed how much
water, fertilizer, and sunlight each plant will receive. Why is his experiment flawed?

Answers

Answer: B) He has too many independent variables.

Explanation: Nothing in the experiment is a constant or being measured.

Lawerence kohl berg developed the theory of

Answers

Explanation:

Kohlberg's theory of moral development is a theory that focuses on how children develop morality and moral reasoning. Kohlberg's theory suggests that moral development occurs in a series of six stages. The theory also suggests that moral logic is primarily focused on seeking and maintaining justice.

How do you calculate the maximum angle at which an object will not slip on an incline? I know that it's arctan(μ) but why? Where does that come from? Thank you in advance!

Answers

The maximum angle at which an object will not slip on an incline can be calculated using the coefficient of friction (μ).

Balance of forces on an incline

When an object is on an inclined plane, there are two main forces acting on it: the gravitational force pulling it downward (mg) and the normal force (N) exerted by the inclined plane perpendicular to its surface. Additionally, there is a frictional force (F) acting parallel to the surface of the incline.

To prevent slipping, the frictional force must be equal to or greater than the force component pulling the object down the incline. This force component is given by the equation F = mg sin(θ), where θ is the angle of inclination.

The maximum frictional force that can be exerted between two surfaces is given by the equation F = μN, where μ is the coefficient of friction.

For an object not to slip, the maximum frictional force (F) must be equal to or greater than the force component pulling the object down the incline (mg sin(θ)). Therefore, we have:

F ≥ mg sin(θ)

Substituting F = μN, we get:

μN ≥ mg sin(θ)

Since N = mg cos(θ) (the normal force is equal to the component of the gravitational force perpendicular to the incline):

μmg cos(θ) ≥ mg sin(θ)

μ cos(θ) ≥ sin(θ)

Now, divide both sides of the equation by cos(θ):

μ ≥ tan(θ)

Taking the inverse tangent (arctan) of both sides, we get:

θ ≤ arctan(μ)

Therefore, the maximum angle at which an object will not slip on an incline is given by θ = arctan(μ).

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Mona said, "I think that, when there is no lid, convection is the main way that
energy escapes from the water."
Has she drawn a good conclusion from her results? Explain your ideas

Answers

Mona's conclusion that convection is the main way that energy escapes from the water when there is no lid may or may not be a good conclusion, depending on the context and information provided.

Convection is a process of heat transfer that involves the movement of fluids (in this case, the water) due to differences in temperature. It occurs when warmer portions of the fluid rise and cooler portions sink, creating a circulating flow.

To determine if Mona's conclusion is valid, additional information is needed. Factors such as the presence of other heat transfer mechanisms (such as radiation or evaporation), the specific setup of the experiment, and the conditions under which the observations were made are essential.

If Mona's experiment only considered convection as the primary mechanism for energy escape and excluded other factors, her conclusion might be incomplete or inaccurate. To draw a more comprehensive conclusion, it is necessary to consider other potential heat transfer mechanisms and perform further investigations or provide additional supporting data.

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The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars

Answers

The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.

Weight of objects on Earth and on Mars

The weight of an object is given by the product of its mass and the gravitational field strength at its location.

On Earth:

Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 N

On Mars:

Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 N

Therefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.

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A student is observing the motion of a bird relative to its nest. It goes from rest to a velocity of 4.0m/s[E] in 8.0s. It
then remains at rest for an additional 3.0s. Finally it reaches a velocity of 3.0m/s [W] in an additional time of 5.0s.
Based on this information create a position time, velocity time, and acceleration time graph. Make sure to include
all the elements of a good graph including a title, axis labels, and an accurate plot. Your d-T graph will have a level
of approximation but the key points should be accurate. 3 grids have been provided for you. Show your
calculations where necessary. [4 marks v-t, 5 marks a-t, 5 marks d-t. 14 marks TOTAL] (PRO TIP - MAKE YOUR V-T
graph first!!)

Answers

The bird remains at rest for 3.0 seconds, so its velocity is 0 m/s and displacement is also 0 m.

What is velocity?

To create the graphs, we need to first calculate the bird's motion parameters:

Initial velocity, u = 0 m/s

Final velocity, v = 4.0 m/s [E]

Time taken, t = 8.0 s

Acceleration, a = (v - u) / t = (4.0 - 0) / 8.0 = 0.5 m/s²

Displacement, d = ut + (1/2)at² = 0 + (1/2)(0.5)(8.0)² = 16.0 m

After this, the bird remains at rest for 3.0 seconds, so its velocity is 0 m/s and displacement is also 0 m.

Then, the bird starts moving again with a velocity of 3.0 m/s [W] and takes 5.0 seconds to reach this velocity. Therefore, its acceleration is:

Initial velocity, u = 0 m/s

Final velocity, v = 3.0 m/s [W]

Time taken, t = 5.0 s

Acceleration, a = (v - u) / t = (3.0 - 0) / 5.0 = 0.6 m/s²

Displacement, d = ut + (1/2)at² = 0 + (1/2)(0.6)(5.0)² = 7.5 m [W]

Using this information, we can create the required graphs:

These graphs are shown in below image.

A Position-time graph shows that the bird starts from the nest, moves 16.0 m to the east, remains there for 3.0 s, and then moves 7.5 m to the west.

The Velocity-time graph shows that the bird starts from rest, reaches a velocity of 4.0 m/s [E] in 8.0 s, remains at rest for 3.0 s, and then reaches a velocity of 3.0 m/s [W] in 5.0 s.

An Acceleration-time graph shows that the bird has an acceleration of 0.5 m/s² [E] from 0 to 8.0 s, no acceleration from 8.0 to 11.0 s (remains at rest), and an acceleration of 0.6 m/s² [W] from 11.0 to 16.0 s.

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A student is observing the motion of a bird relative to its nest. It goes from rest to a velocity of
A student is observing the motion of a bird relative to its nest. It goes from rest to a velocity of
A student is observing the motion of a bird relative to its nest. It goes from rest to a velocity of

PLS HELP!! This question was never fully solved!

An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg

Answers

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

Define invariant transformations

Answers

Answer:

For a given system, there can be particular transformations for which the explicit equations of motion are the same for both the old and new variables. Transformations for which the equations of motion are invariant, are called invariant transformations. It will be shown that if the Lagrangian does not explicitly contain a particular coordinate of displacement  qi, then the corresponding conjugate momentum,  pi, is conserved. This relation is called Noether’s theorem which states “For each symmetry of the Lagrangian, there is a conserved quantity".

What is the solution to this equation?
X- 14 = -9
O A. x = 5
O B. x= -23
O c. x = 23
O D. x= -5

Answers

Answer:

X-14=9

x-14+14=9+14

x=23

Explanation:

Your answer is 23.

An athlete exerts 3000 W of power when he takes 10.2 s to run the race. How much WORK does the athlete do?

Answers

Answer:

30600 J

Explanation:

Work = Power* Time

         =30600 J

A woman 1.2 m tall lies along the axis of a space vehicle traveling at 0.87c. What is her height as measured by a stationary observer?

Answers

Answer:

L = L0 (1 - v^2/c^2)     where L0 is proper length and L the measured length

L = 1.2 (1 - .87^2)^1/2 m = .59 m

Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

You decide to make one of the world’s largest musical instruments, using long cylindrical steel rods that are clamped tightly at both ends. The speed of longitudinal waves in rods of the type of steel you use is 5068 m/s and the steel has a Young’s modulus of 199 GPa.

Required:
a. What is the density of the steel, in kilograms per cubic meter?
b. When a longitudinal wave is excited in one of the steel rods in your instrument to produce resonance, will the rod’s ends be nodes or antinodes?
c. A standard frequency for tuning musical instruments is 440 Hz for the pitch of A above middle C, denoted A4. What is the length, in meters, of the steel rod that produces the pitch A4 as its fundamental longitudinal resonance?
d. Assume, instead, that you want to create a smaller version of this, using the same kind of construction, with one rod of length 9.5 cm. What would the fundamental longitudinal resonance frequency of that rod be, in hertz, with the same longitudinal wave speed as above, 5149 m/s?

Answers

Answer:

Explanation:

speed of longitudinal wave in a rod = \(\sqrt{\frac{Y}{D} }\)

Where Y is young's modulus of elasticity and D is density .

Putting given data

5068 = \(\sqrt{\frac{199\times 10^{9}}{D} }\)

D = 199 x 10⁹ / .2568 x 10⁸

= 7749 kg / m³

b )

Rod's ends are not to vibrate as they are clamped . So node is produced there .

c )

Frequency = 440 Hz

Note = fundamental

l = λ / 2  , l is length of rod and λ is wavelength

wavelength of 440 Hz note

= velocity of sound / frequency

= 5068 / 440

= 11.518 m

l = 11.518 / 2

= 5.76 m .

Length of rod = 5.76 m

d )

l = .095 m

velocity = 5149 m /s

wavelength = 2l

= 2 x .095 m

= .19 m

frequency = velocity / wavelength

= 5149 / .19

= 27100 Hz .

In this exercise we have to use the density knowledge to calculate the wave speed, like this:

A)\(D=7749 kg/m^3\)

B) Have node.

C) \(L = 5.76 m\)
D) \(f= 27100 Hz\)

So knowing that from the data informed by the statement we find that:

A) First we have to calculate the density as:

\(D = 199 * 10^9 / 0.2568 * 10^8\\D= 7749 kg / m^3\)

B) Rod's ends are not to vibrate as they are clamped.

C) Second we have to calculate the length as:

\(Length= velocity \ of \ sound / frequency\\= 5068 / 440\\= 11.518 m\\L= 11.518 / 2\\L= 5.76 m\)

D) Third  we have to calculate the frequency as:

\(wavelength = 2L\\= 2 * 0.095 m\\=0 .19 m\\frequency = velocity / wavelength\\= 5149 / 0.19\\f= 27100 Hz .\)

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A particle with mass
m = 3.80 kg
accelerates according to
a = (−3.40i + 1.70j) m/s2.
(a) What is the net force acting on the particle? (Express your answer in vector form.)

(b) What is the magnitude of this force?

Answers

The net force acting on the particle would be and the magnitude of the force would be -12.92i + 6.49j and the magnitude of the force would be 14.46 Newtons.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The net force on the particle = mass of the particle × acceleration

                                                =3.80*(−3.40i + 1.70j)

                                                = -12.92i + 6.49j

Thus, the magnitude of the net force on the particle would be 14.46 Newtons.

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A toy car is given an initial velocity of 5.0 m/s and experiences a constant
acceleration of 2.0 m/s/s. What is the final velocity after 6.0 s?

Answers

The final velocity after 6.0 s is

1304.2 .

What is velocity?

velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.

Solution -

As per the given-

Mass of runner m = 74kg

initial velocity of runner u=4.8 m/s

final velocity of runner v =0

Coefficient of friction ¥=0.7

Let's d be the distance moved by runner till the stop.

a- mechanical energy lost due to friction

As friction does negetive work causing the runner to stop.

As we know,

Mechanical energy lost= Kinetic energy of runner

Mechanical energy lost =

1/2 mv^2 = 1/2 ×74×4.8^2=852.2

Distance move by runner-

Work done by friction = mechanical energy lost

-¥×mg×d =852.2 j

-0.7×74×9.8×d = -491.2

Solving the equation we get

1304.2.

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A girl with a mass of 32 kg is playing on a swing. There are three main forces
acting on her at any time: gravity, force due to centripetal acceleration, and
the tension in the swing's chain (ignore the effects of air resistance). At the
instant shown in the image below, she is at the bottom of the swing and is
traveling at a constant speed of 4 m/s. What is the tension in the swing's
chain at this time? (Recall that g = 9.8 m/s²)
Tension
Weight
A. 333.6 N
OB. 817.8 N
C. 562.8 N
D. 441.6 N
4 m/s

A girl with a mass of 32 kg is playing on a swing. There are three main forcesacting on her at any time:

Answers

The tension in the swing's chain at the instant shown in the image is 441.6 N.

option D

What is the tension at bottom swing?

At the bottom of the swing, the girl is traveling at a constant speed, so her acceleration is zero. Therefore, the net force acting on her is also zero.

Thus, we have:

0 = T - mg - mv²/r

where;

T is the tension in the swing's chain, m is the girl's mass, g is the acceleration due to gravity, v is her speed, and r is the radius of the swing.

At the bottom of the swing, the radius is equal to the length of the chain, so we have:

r = L = 4.0 m

Substituting the values we have:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

Solving for T, we get:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

T = 441.6 N.

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Plz help!Why would parents verbally fight in front of their children? The pH of a 1. 00x10-2 M solution of cyanic acid (HOCN)is 2. 77 at 25 degrees celsius. Calculate Ka for HOCNfrom this result The slope of AB is 2/3, A(1,-4) and B(-5,y). Solve for the value of y. as a manager, mark tries to be as clear and direct as possible when asking for something from his employees. what context of communication is mark using? dont get it i just want some answers man Class I viruses, double-stranded (ds)DNA viruses, usually utilize the following polymerases for (i) mRNA synthesis and (ii) DNA replicationA. (i) viral RNA-dependent RNA polymerase and (ii) viral DNA-dependent DNA polymeraseB. (i) viral DNA-dependent RNA polymerase and (ii) viral DNA-dependent DNA polymeraseC. (i) viral RNA-dependent RNA polymerase and (ii) host cell DNA-dependent DNA polymeraseD. (i) host cell DNA-dependent RNA polymerase and (ii) host cell DNA-dependent DNA polymeraseE. (i) host cell RNA-dependent RNA polymerase and (ii) host cell DNA-dependent DNA polymerase 5, 30, 80 find the 7th term A line passes through the points (5,18) and (9,22). Write a linear function rule in terms of c and u for this line. e-waste management is extraordinarily difficult to monitor and track because of the complexity of the modern value chain. 9. What 3 things influence what values arepassed on from parent to child? (p60)This is a child development class Who is Hatchepsut and how did she gain power in Egypt? How did she use art and architecture to display her power and authority? How is stability emphasized within the location and architectural structure of the temple? As a female pharaoh how was Hatchepsut's mortuary statue influenced by previous pharaohs and how in what way did it depart? What is the significance of her position? You are investigating Hooke's law by putting different masses on the end of a spring. What apparatus would you use to measure the force exerted by the mass hanging from the spring? Convert 49 Celsius to degree Fahrenheit using F= 9/5C + 32 Which state lies partially within the mountain time zone? draw a cladogram that depicts the evolutionary relationship among humans, chimpanzees, fruit flies, and mosses definition of computer HELP.. ASAP..HURRY Axons of the cochlear branch sensory neurons extend toA) nuclei in the ponsB) the cerebellumC) nuclei in the medulla oblongataD) the spiral ganglion of the cochlea please help for a brainliest 4.1.13 While checkpoint blockade therapy is effective at treating a variety of cancers and has provided benefits to many patients, adverse effects can arise during or following the treatment. How do anti-PD-L1 antibodies use during checkpoint blockade cause adverse events?A. The antibodies lead to the activation of T cells that recognize and kill normal cells.B. The treatment leads to the massive release of cytokines, leading to a deficiency of these cytokines needed to fight infections that cause inflammation.C. The antibodies bind to antigens on non-malignant cells, leading to the death of those cells.D. The treatment causes the death of both malignant and normal cells that express the checkpoint molecules, leading to loss of function of normal tissues where the tumour arose.