Explanation:
f=mg
=200×10
=200N
Now,
work done=df
25×200
=500J
Which activities demonstrate reaction time the most?
Answer:
A goal keepee catering the ball in time is answer
Someone helppppp meee please please!!
Answer:
Explanation:
What is your question? There is multiple questions to answer...
Answer:
what question u want
Explanation:
what is the coefficient of static friction between a mass of 0.75kg and a horizontal surface. if the limiting friction force is 5N and g=10ms
1.47 is the coefficient of static friction between a mass of 0.75kg and a horizontal surface
m=0.75 KG
g=9.8 M/S^2
N=5 N
F=µN
µ=F/N
µ=mg/N
µ=0.75×9.8÷5
µ=1.47
We are physically surrounded with friction. An object moving along a path is resisted by a force known as static friction. Lastly, use an easy example to comprehend it. Think about the activity we perform frequently called walking. We are constantly in contact with the floor while we work. Motion presses against the ground as we move it backward, and we then advance our feet.
One key concept to be aware of in order to minimize friction is the fact that it operates in the opposite direction from relative motion. This phenomena may be useful for reducing the speed of the action until it eventually comes to a stop.
To know more about static friction visit : brainly.com/question/13000653
#SPJ9
A block of mass, m=4.80 kg is placed on the edge of a rough surface of height h = 0.5 2m as shown above. The block is released and moves until it stops momentarily after compressing a horizontal spring (with a spring constant k = 2,000 N/m) by a compression distance x = 12.1 cm. Find the work done by friction.
This question can be easily solved by using the law of conservation of energy.
The work done by the friction is "9.9 J".
The law of conservation of energy applied to this condition gives the following equation:
\(Potential\ Energy\ Lost\ by\ Block = Energy\ Stored\ by\ Spring\ +\ Work\ done\ by\ friction\\\\mgh = \frac{1}{2}kx^2\ +\ W\)where,
W = Work done by friction = ?
m = mass of the block = 4.8 kg
g = acceleration due to gravity = 9.81 m/s²
h = height = 0.52 m
k = spring constant = 2000 N/m
x = compression distance = 12.1 cm = 0.121 m
Therefore,
\((4.8\ kg)(9.81\ m/s^2)(0.52\ m)=\frac{1}{2}(2000\ N/m)(0.121\ m)^2+W\\W = 24.5\ J - 14.6\ J\)
W = 9.9 J
Learn more about the law of conservation of energy here:
brainly.com/question/20971995?referrer=searchResults
The attached picture explains the law of conservation of energy.
Express 6revolutions to radians
Answer:
About 37.70 radians.
Explanation:
1 revolution = 2\(\pi\) radians
∴ 6 revolutions = (6)(2\(\pi\) radians)
6 revolutions = 37.6991 or ≈ 37.70 radians
A bullet is fired horizontally with an initial velocity of 900 m/s at a target located 150 m from the rifle.
a) How much time is required for the bullet to reach the target?
b) Using the approximate value of g = 10 m/s^2, how far does the bullet fall in this time?
If you could show work, that'd be greatly appreciated :) I know the answers, but I'm not sure how they're worked.
Answer:
S = Vx t = 900 t
t = 150 / 900 = 1/6 sec
If the bullet is fired horizontally it will travel 900 m in .167 sec
H = 1/2 g t^2 = 1/2 * 10 * (1/6)^2 = .139 m distance bullet will fall
A low C (f=65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and
its mass density is 5.0 g/m2, determine the tension of the wire.
Answer:
T = 676 N
Explanation:
Given that: f = 65 Hz, L = 2.0 m, and ρ = 5.0 g\(/m^{2}\) = 0.005 kg
A stationary wave that is set up in the string has a frequency of;
f = \(\frac{1}{2L}\)\(\sqrt{\frac{T}{M} }\)
⇒ T = 4\(L^{2}\)\(f^{2}\)M
Where: t is the tension in the wire, L is the length of the wire, f is the frequency of the waves produced by the wire and M is the mass per unit length of the wire.
But M = L × ρ = (2 × 0.005) = 0.01 kg/m
T = 4 × \(2^{2}\) ×\(65^{2}\) × 0.01
= 4 × 4 ×4225 × 0.01
= 676 N
Tension of the wire is 676 N.
A rover vehicle weighs 37 N on Mars. How much would the rover weigh on Earth?
The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N
How do determine the weight of the vehicle on earth?We'll begin by obtaining the mass of the rover vehicle. This is shown below:
Weight (W) = 37 NAcceleration due to gravity on Mars (g) = 3.72 m/sMass of rover vehicle =?Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Divide both sides by g
m = W /g
m = 37 / 3.72
m = 9.95 Kg
Now, we shall determin the weight of the rover vehicle on Earth. Details below:
Mass (m) = 9.95 KgAcceleration due to gravity on Earth (g) = 10 m/s² Weight (W) = ?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 9.95 × 10
Weight = 99.5 N
Thus, we can conclude that the weight on Erath is 99.5 N
Learn more about weight:
https://brainly.com/question/22881705
#SPJ1
is Firefly an artificial or natural light source
Answer:
NATURAL
Explanation:
well this is because a firefly isn't man- made it is a firefly it isn't a robot, it is an insect.
under what conditions of temperature and pressure would you expect gases to obey the ideal-gas equation?
Answer:
Gases obey the ideal-gas law at high temperatures and low pressures.
Explanation:
Becoming informed about economics helps a person understand the reasons a command economy is ideal. role of government in regulating production. why consumers receive tax revenue. reasons an economy must always be completely regulated. Mark this and return
Answer:
Role of government in regulating production
Explanation:
The role of government in regulating show , provides the legal and social framework, uphold competition, provides public goods and services.
What is the role of economics in the community?The community's role in conserving and enhancing common-property resources is well known.
In extra, its role in helping market growth by its power to execute trade agreements among transacting parties belonging to the community network is stressed.
Thus, it provides the legal and social framework, maintains competition, and provides public goods and services.
To learn more about economics in community click here:
https://brainly.com/question/1344575
The philosopher Robert Nozick imagined an “experience machine” to show that a core feature of utilitarianism (as conceived by Bentham and Mill) does not conform with most people’s intuitions about “the good life.” Which of these core features of utilitarianism was Nozick’s main target?
Robert Nozick opines that individuals own themselves and hence have a right to own property.
What is utilitarianism?The term utilitarianism refers to the philosophical ideology that in the use of commodities, the best options is that which maximizes utility or satisfaction derived from the commodity.
In the position of Robert Nozick, utilitarianism means that individuals own themselves and hence have a right to own property.
Learn more about utilitarianism : https://brainly.com/question/10548094
A string of a given length and diameter and density is under a tension of 100 N and produces a sound of 200 Hz. How many vibrations per second will be produced if the tension is changed to :A. 900 NB. 25 N
Given,
The length, diameter, and density are given, i.e., the length, diameter and density of the string are constant.
The tension on the string, T₁=100 N
The frequency of the sound, f₁=200 Hz
The tension on the string and the frequency of the sound is related as,
\(T=4ml^2f^2\)Where m is the mass of the string and l is the length of the string.
On rearranging the above equation,
\(\frac{T}{f}=4ml^2\)As the length, diameter, and density of the string is constant,
\(\begin{gathered} \frac{T}{f}=\text{constant} \\ \frac{T_1}{f_1}=\frac{T_2}{f_2} \end{gathered}\)A.
Given,
Tension in the string, T₂=900 N
The frequency of the string after the change in the tension is given by,
\(\begin{gathered} \frac{T_1}{f_1}=\frac{T_2}{f_2} \\ \Rightarrow f_2=\frac{T_2\times f_1}{T_1} \end{gathered}\)On substituting the known values,
\(\begin{gathered} f_2=\frac{900\times200}{100} \\ =1800\text{ Hz} \end{gathered}\)Thus the frequency of the sound after the tension on the string changes to 900 N is 1800 Hz, i.e., 1800 vibrations are produced per second.
B.
Given,
The tension on the string, T₃=25 N
The frequency of the string after the tension changes to 25 N is given by,
\(\begin{gathered} \frac{T_1}{f_1}=\frac{T_3}{f_3}_{} \\ \Rightarrow f_3=\frac{T_3\times f_1}{T_1} \end{gathered}\)On substituting the known values,
\(\begin{gathered} f_3=\frac{25\times200_{}}{100} \\ =50\text{ Hz} \end{gathered}\)Thus the frequency of the sound after the tension changes to 25 N is 50 Hz, i.e., 50 vibrations are produced per second.
The __________ of exercise determines the health and fitness benefit of the exercise. A. frequency B. intensity C. time D. type Please select the best answer from the choices provided. A B C D
Answer:
c- Time
Explanation:
The time will tell depending on the person who is exercising, the rate of time, the workout time. & limits on weights....
Answer:
The guy above me is wrong the real answer is D
Explanation:
Explain how a common housecat gets “worms.”eplain(science)
Answer:
Cats most commonly contract worms after coming into contact with parasite eggs or infected feces. A cat may walk through an area with eggs or infected feces, and since cats are often such fastidious groomers, they will then ingest the eggs or fecal particles as they clean their fur and feet.
Explanation:
this is the only thing in my book hope it helps
Flag question
Consider the pressure and force acting on the
dam retaining a reservoir of water. Suppose the
dam is 500-m wide
and the water is 80.0-m
deep at the dam, as illustrated below. What is
the average pressure on the dam due to the
water?
Answer:
P = density (p) * g * h
P = 1000 kg/m^3 * 9.8 m/s^2 * 40 m = 392,000 N/m^2
since kg m / s^2 = Newtons
The average pressure is 1/2 (pressure at 0m + pressure 80 m) for liquid of uniform density
A 7.9 kg block initially at rest is pulled to the
right along a horizontal, frictionless surface
by a constant, horizontal force of 12.4 N.
Find the speed of the block after it has
moved 3.7 m.
Answer in units of m/s.
Answer:
\(v=3.4081\frac{m}{s}\)
Explanation:
\(F=ma\\F=12.4N\\m=7.9kg\\a=\frac{12.4N}{7.9kg}\\a=1.5696\frac{m}{s^2}\)
\(v^2=v_0^2+2a\Delta x\\v_0=0\frac{m}{s}\\a=1.5696\frac{m}{s^2}\\\Delta x=3.7m\\v^2=(0\frac{m}{s})^2+2(1.5696\frac{m}{s^2})(3.7m)\\v^2=11.6152\frac{m^2}{s^2}\\v=\sqrt(11.6152\frac{m^2}{s^2})\\v=3.4081\frac{m}{s}\)
What is the best flowers
Answer:
What are the best flowers? (My opinion)
Water liliesWhite rosesHydrangeaExplanation:
You're welcome.
Answer:
Tulips,
Lilies,
Lotuses on my opinion...
A hunter on a frozen, essentially frictionless pond uses a rifle that shoots 4.20 gg bullets at 970 m/sm/s. The mass of the hunter (including his gun) is 69.5 kgkg, and the hunter holds tight to the gun after firing it. You may want to review (Page) . For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Collision along a straight line. Part A Find the recoil speed of the hunter if he fires the rifle horizontally.
Answer:
\(0.059\ \text{m/s}\)
Explanation:
\(m_1\) = Mass of bullet = 4.2 g
\(u_1\) = Initial velocity of bullet = 0
\(m_2\) = Mass of hunter with rifle = 69.5 kg
\(u_2\) = Initial velocity of hunter with rifle
\(v_1\) = Final velocity of the bullet = 970 m/s
\(v_2\) = Final velocity of the hunter with the rifle
As the momentum of the system is conserved we have
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}\\\Rightarrow v_2=\dfrac{0-0-0.0042\times 970}{69.5}\\\Rightarrow v_2=-0.059\ \text{m/s}\)
The recoil speed of the hunter is \(0.059\ \text{m/s}\) in the opposite direction of the bullet.
A 2 m long rope having a mass of 26 grams is stretched with a tension of 50 N. It is set to periodic
motion with frequency of 30 Hz and amplitude of 3 cm. considering zero amplitude at t = 0 seconds
and wave motion along the +x-axis. Find
a|. amplitude (A).
b|. wave speed (v).
c|. angular frequency().
d|. period (T).
e|. wavelength().
(a) The amplitude of the wave is 3 cm.
(b) The speed of the wave is 19.6 m/s
(c) The angular frequency is 653.72 rad/s.
(d) The period of the wave is 0.0096 s.
(e) The wavelength of the wave is 0.392 m.
Speed of the wave
The speed of the wave is calculated as follows;
\(v = \sqrt{\frac{T}{\mu} }\)
where;
μ is mass per unit length = (0.26 kg)/(2 m) = 0.13 kg/mT is tension\(v = \sqrt{\frac{50}{0.13} } \\\\v = 19.6 \ m/s\)
Angular frequencyω = v/r
ω = v/A
ω = 19.6/0.03
ω = 653.72 rad/s
Period of the wave\(T = \frac{2\pi }{\omega } \\\\T = \frac{2\pi }{653.72} \\\\T = 0.0096 \ s\)
Wavelengthv = fλ
λ = v/f
λ = 19.6/50
λ = 0.392 m
Learn more about wavelength here: https://brainly.com/question/10728818
#SPJ1
A 602-kg elevator starts from rest and moves upward for 2.60 s with constant acceleration until it reaches its cruising speed, 1.72 m/s. Answer parts a and b.
The distance traveled by the elevator is 2.0136 m.
Given values: Mass, m = 602 kg. Initial velocity, u = 0 m/s. Time taken, t = 2.60 s. Final velocity, v = 1.72 m/s.(a) Find the acceleration of the elevator. The formula to calculate the acceleration is given below:
a = (v - u)/t Substitute the given values in the above equation and get the acceleration value.
a = (1.72 - 0)/2.60a = 0.6615 m/s²Therefore, the acceleration of the elevator is 0.6615 m/s².
(b) Find the distance traveled by the elevator. The formula to calculate the distance is given below:
s = ut + 1/2at²Substitute the given values in the above equation and get the distance traveled by the elevator.
s = 0(2.60) + 1/2(0.6615)(2.60)²s = 2.0136 m.
For more question distance
https://brainly.com/question/13771806
#SPJ8
What inductance must be put in series with a 100-kiloohm resistor at 1.0-MHz for a total impedance
of 150 kiloohm
An inductance of 0.0191 H (19.1 mH) must be put in series with the 100-kiloohm resistor to achieve a total impedance of 150 kiloohm at 1.0 MHz.
What is Induction?
Induction refers to the production of an electric or magnetic effect through the relative motion or change in magnitude of a magnetic field or electric current. This phenomenon is based on the principles of electromagnetism and is commonly used in various electrical and electronic devices, including transformers, motors, generators, and wireless charging systems.
The total impedance can be calculated using the following formula:
Z_total = sqrt(\(R^{2}\) X_\(L^{2}\))
where R is the resistance (100 kiloohm) and X_L is the inductive reactance. We can rearrange this formula to solve for X_L:
At 1.0 MHz, the angular frequency is:
w = 2πf = 2π × 1.0 × \(10^{6}\) = 6.28 × \(10^{6}\)ad/s
The inductive reactance can be calculated using the following formula:
X_L = wL
where L is the inductance in henries. We can rearrange this formula to solve for L:
L = X_L / w
Now we can substitute the given values and solve for L:
X_L = sqrt((150 ×\(10^{3}\)) - (100 ×\(10^{3}\))) = 120 × \(10^{3}\) ohm
L = X_L / w = 120 × \(10^{3}\) ohm / 6.28 × \(10^{6}\) rad/s = 0.0191 H
Learn more about Induction from the given link
https://brainly.com/question/30049273
#SPJ1
An average hole drift velocity of 103 cm/sec results when 2 V is applied across a 1 cm long semiconductor bar. What is the hole mobility inside the bar
Answer:
ε = 2 V/cm
Explanation:
To calculate the mobility inside this bar, we just need to apply the expression that let us determine the mobility. This expression is the following:
ε = ΔV / L
Where:
ε: Hole mobility inside the bar
ΔV: voltage applied in the bar
L: Length of the bar
We already have the voltage and the length so replacing in the above expression we have:
ε = 2 V / 1 cm
ε = 2 V/cmThe data of the speed can be used for further calculations, but in this part its not necessary.
Hope this helps
2. True or false?
Forensic entomology uses the study of insects to help criminal investigations.
Find the terminal velocity of a sphere that has a mass of 600g and a radius of 30cm. Take the density of air 1.2 kg/m^3 . Report the speed in mph.
The terminal velocity of the sphere is approximately 22.68 mph.
The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:
Fd = (1/2) * rho * Cd * A * v²
where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.
The gravitational force pulling the sphere down is given by:
Fg = m * g
where m is the mass of the sphere and g is the acceleration due to gravity.
At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:
Fd = Fg
Substituting the expressions for Fd and Fg and solving for v, we get:
v = √((2 * m * g) / (rho * Cd * A))
where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.
Plugging in the given values, we get:
v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s
To convert this to mph, we multiply by 2.23694:
v ≈ 22.68 mph
To know more about terminal velocity, here
brainly.com/question/2654450
#SPJ1
What is the total amount of force needed to keep a 6.0 kg object moving at speed
of 5.0 m/s? (F=ma)
A. 30 N
B. 60 N
C.ON
D. 10 N
A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all values are accurate to three significant digits. (Assume that the density of air is 1.21 kg/m3 and the drag coefficient of a skydiver in a pike position is 0.7.) If each skydiver has a frontal area of 0.14 m2, calculate their terminal velocities (in m/s). 52 kg skydiver m/s 95 kg skydiver m/s How long will it take (in s) for each skydiver to reach the ground (assuming the time to reach terminal velocity is small)
Answer: 52 kg skydiver: 9.09 m/s and 522.55 s
95 kg skydiver: 12.3 m/s and 386.2 s
Explanation: Drag Force is an opposite force when an object is moving in a fluid.
For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.
Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:
\(F_{G}=F_{D}\)
\(mg=\frac{1}{2}C \rho Av_{T}^{2}\)
\(v_{T}=\sqrt{\frac{2mg}{\rho CA} }\)
where
m is mass in kg
g is acceleration due to gravitational force in m/s²
ρ is density of the fluid in kg/m³
C is drag coefficient
A is area of the object in the fluid in m²
Calculating:
The 52kg skydiver has terminal velocity of:
\(v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 9.09
The 95kg skydiver's terminal velocity is
\(v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }\)
\(v_{T}=\) 12.3
The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.
The time each one will reach the floor will be:
52 kg at 9.09 m/s:
\(t=\frac{4750}{9.09}\)
t = 522.5
95 kg at 12.3 m/s:
\(t=\frac{4750}{12.3}\)
t = 386.2
The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.
in object in motion tend to stay in motion in object in rest tends to stay in rest. "many years before newton wrote this law,__________stated the same idea as the principal of _______.
Many years before newton wrote this law, of motion stated the same idea as the principal of inertia.
What is Newton's first law of motion?
Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Newton's first law of motion is also called law of inertia because it depends on mass of the object.
Thus, many years before newton wrote this law, of motion stated the same idea as the principal of inertia.
Learn more about law of inertia here: https://brainly.com/question/1412777
#SPJ1
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
for such more questions on principle
https://brainly.com/question/26117248
#SPJ8
A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is the end of the ramp from the ground? m
Answer:
The end of the ramp is 38.416 m high
Explanation:
Horizontal Motion
When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)
If the maximum horizontal distance is known, we can solve the above equation for h:
\(\displaystyle h=\frac {d^2g}{2v^2}\)
The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:
\(\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}\)
\(\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}\)
h= 38.416 m
The end of the ramp is 38.416 m high