A buffer solution is prepared which is 0.180 M both in propanoic acid (CH3CH2CO2H) and in sodium propanoate (CH3CH2CO2Na).
Ka = 1.3×10-5 for propanoic acid.
What is the pH of this solution?

When 1.46 mL of 0.0800 M HCl is added to 14.0 mL of this buffer solution, what is resulting change in pH?

The unsaturated fatty acid with the formula Ch₃(Ch₂)7ChCh(Ch₂)7Co₂h is more commonly referred to as omega-9 acid.

Omega-9 is a class of monounsaturated fatty acids (MUFA) that are commonly found in vegetable oils, nuts, and seeds. MUFA, or monounsaturated fatty acids, are beneficial fats that can help improve heart health by lowering bad cholesterol levels. MUFA has been shown to reduce the risk of heart disease by reducing low-density lipoprotein (LDL) cholesterol levels while increasing high-density lipoprotein (HDL) cholesterol levels.

These acids are also found in a variety of foods, including avocados, olives, canola oil, peanuts, sesame oil, sunflower seeds, almonds, and peanuts, among others. They're one of the three main types of dietary fats, along with saturated and polyunsaturated fats. Most omega-9 fatty acids are monounsaturated, with a single double bond in the nine-carbon chain that provides its name.

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Answer:

At the Earth's surface, wind blows horizontally from high pressure to low pressure areas. The speed is determined by the rate of air pressure change, or gradient, between the two pressure areas. The greater the pressure difference, the faster the winds.

- sciencing

The Four Forces That Influence Wind Speed & Wind Direction

Explanation:

The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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Answer:

-114.6°C is the new freezing point

Explanation:

The addition of a solute to a pure solvent produce the decreasing in the freezing point (Freezing point depression, Colligative property). The equation to find the new freezing point of the mixture is:

ΔT = Kf*m*i

Where ΔT is the change in the freezing point,

Kf is the freezing point depression constant of the solvent = 1.99°C/m

m is molality of the solution (Moles of solute / kg solvent)

i is Van't Hoff factor = 1 for nonelectrolytes

Molality of the solution is:

Moles glucose -Molar mass: 180.156g/mol-

10.3g * (1mol / 180.156g) = 0.05717 moles

kg of solvent:

250g * (1kg / 1000g) = 0.250kg

Molality = 0.05717 moles / 0.250kg =

0.2287m

ΔT = 1.99°C/m*0.2287m*1

ΔT = 0.46°C

As the freezing point of ethanol is -114.1°C, the freezing point of te solution is:

-114.1°C - 0.46°C

= -114.6°C is the new freezing point

Answers:

Continental Tropical - 2

Maritime Tropical - 3

Continental Polar - 6

Arctic Air - 5

Maritime Polar - 4

Maritime - 1

Hope this helped! :^)

Answer:

Continental Polar = Cold and dry

Maritime polar = Cold and humid

Maritime tropical = Warm and humid

Continental tropical = Warm and dry

Arctic air = Extremely cold and dry

Maritime = of or related to sea

Explanation:

The speed of reaction from fastest to slowest has been 1, 3, 4, 2. Thus, option D is correct.

The chemical reaction has been given as the change in the composition of the reactants, with the formation of product.

The following chemical reactions rate has been given as:

Thus, the speed of reaction from fastest to slowest has been 1, 3, 4, 2. Thus, option D is correct.

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It will take 33 years for a 40-mg sample to decay to a mass of 30.4 mg.

Tο calculate the time it takes fοr a sample οf strοntium-90 tο decay frοm 40 mg tο 30.4 mg, we can use the cοncept οf half-life

Using the half-life formula:

\(\rm A=A_02^{-t/h}\), where

A = resulting amount after time t = 39.6 mg

Ao = initial amount = 90 mg

t = decay time

h = half-life of substance= 28 yrs

Now putting the values into the formula, we get

\($ \rm 39.6=90\times2^{-t/28}\)

\($ \rm 2^{-t/28}=\frac{39.6}{90}=\frac{2.2}{5}\)

Taking logarithm both sides

\($ \rm ln(2^{-t/28})=ln(\frac{2.2}{5})\)

\($ \rm \frac{-t}{28}ln(2)=ln(0.44)\)

\($ \rm t=\frac{-28ln(0.44)}{ln(2)}\)

t = 33.16389

t ≈ 33years

Thus, it will take 33 years for a 40-mg sample to decay to a mass of 30.4 mg.

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Answer:

I think it is C

Explanation:

We have that the reaction and a decrease in the concentration of the reactants will favor the reverse reaction that is the decomposition of the yellow iodine trichloride and the formation of green chlorine gas and brown iodine chloride

Given that some green chlorine gas, which is part of the reactant, will be removed, the reverse reaction will be favored and initial concentration of the yellow iodine trichloride and the green chlorine gas will be reduced while the proportional concentration of the brown iodine chloride will increase and the mixture will become more brown.

Answer:

d because you don't like math or any subject

The third law of thermodynamics describes the entropy of a: solid.

The third law of thermodynamics states that the entropy of a pure crystalline substance approaches zero as the temperature approaches absolute zero (0 Kelvin or -273.15 degrees Celsius). This law implies that at absolute zero, a perfectly ordered and pure crystalline solid will have zero entropy.

The third law of thermodynamics is not specific to liquids or gases but applies to solids. In a solid, the molecules are highly ordered and have fixed positions in a regular lattice structure. As the temperature decreases towards absolute zero, the thermal motion of the molecules reduces, and the system becomes more ordered, resulting in a decrease in entropy.

In contrast, liquids and gases have higher entropy compared to solids at absolute zero because their molecules have more freedom of movement and are not as tightly arranged. Therefore, the third law of thermodynamics specifically addresses the entropy of solids and does not apply to liquids or gases.

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The number of moles of NaCl present in 276.50 mL of 1.55 M NaCl solution is 0.429 mol.

To find the number of moles of NaCl in a given solution, we can use the formula: moles of solute = concentration of solution x volume of solution We are given the following information:Concentration of solution = 1.55 MVolume of solution = 276.50 mL

To use this formula, we need to convert the volume of the solution from milliliters (mL) to liters (L).1 L = 1000 mLTherefore, 276.50 mL = 0.27650 LNow, we can substitute the given values in the formula and calculate the number of moles of NaCl present in the solution:moles of solute = concentration of solution x volume of solution= 1.55 M x 0.27650 L= 0.429 molTherefore, there are 0.429 moles of NaCl in 276.50 mL of 1.55 M NaCl solution. Hence, the correct option is 0.429.

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Burning velocity is defined as the rate at which a planar flame moves through a stationary, quiescent flammable mixture of infinite extent.

D is the correct answer.

In relation to the unburned gas, burning velocity is the rate at which a flame front moves. As opposed to flame speed, this. The speed at which an unburned gas mixture in front of a laminar (planar) combustion wave propagates is known as the laminar burning velocity (SL).

The laminarness or turbulentness of a flow system affects the flame speed. The rate at which a fire can spread through the flammable mixture and ultimately throughout the system must be taken into account when calculating flame speed.

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The complete question is:

which of the following terms is defined as the rate at which a planar flame moves through a stationary, quiescent flammable mixture of infinite extent?

A. static velocity

B. Downward velocity

C. Front velocity

D. Burning velocity

Dipole-induced dipole forces must be overcome between br2 when liquid br2 dissolves into ethanol.

In contrast to C2H5OH, which is a very polar molecule, bromine is non-polar and has zero dipole moment. Charges are separated within polar molecules.

When a nonpolar Br2 molecule interacts with a polar C2H5OH molecule, one half of the bromine molecule acquires a charge and the other half acquires an opposing charge. A dipole is created when two adjacent bromine molecules have different charges. Bromine molecules must thus overcome the intermolecular forces—also known as dipole-induced dipole forces—that form in order to dissolve in ethanol.

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Answer:

\(\boxed{It\ will\ shift\ to\ create\ less\ of\ substance\ A}\)

Explanation:

If the concentration of any substance A in a dynamic equilibrium increases, The equilibrium will be  shifted to its opposite side so that Substance A can be created less and the substance opposite to A can be created more so that a "dynamic equilibrium" can again be established.

The complex ion geometry that has the potential to exhibit cis-trans isomerism is octahedral geometry.

Cis-trans isomerism refers to the phenomenon where two or more ligands in a coordination complex can occupy different positions around a central metal ion, resulting in distinct spatial arrangements.

In the context of complex ion geometry, cis refers to ligands located adjacent to each other on the same side of the coordination complex, while trans refers to ligands located opposite to each other across the coordination complex.

Octahedral geometry is a common coordination geometry for complex ions where the central metal ion is surrounded by six ligands, forming an octahedron shape. In an octahedral complex, there are three possible arrangements of ligands: cis-cis, cis-trans, and trans-trans.

The cis-cis arrangement occurs when two sets of ligands are located adjacent to each other on the same side of the octahedron, while the trans-trans arrangement occurs when two sets of ligands are located opposite to each other across the octahedron.

The cis-trans arrangement, as the name suggests, occurs when there is one set of ligands located adjacent to each other on one side of the octahedron and another set of ligands located opposite to each other on the other side.

The potential for cis-trans isomerism in octahedral complexes arises when the ligands attached to the central metal ion are different. This allows for different spatial arrangements of the ligands, leading to the possibility of cis and trans isomers.

It is important to note that not all octahedral complexes exhibit cis-trans isomerism, as it depends on the specific ligands and their arrangement around the central metal ion.

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Answer:

the answer is the third figure from left

Answer:

hi

Explanation:

Answer:

Na (s) + Cl2 (g) → NaCl (s)

Explanation:

A reaction of sodium with chlorine to produce sodium chloride is an example of a combination reaction. 2 Na + Cl 2 → 2 NaCl.

Horner-Wadsworth-Emmons (HWE) reaction is an important synthetic reaction in organic chemistry. It is widely used for synthesizing various compounds. The reaction is between an aldehyde or ketone and a phosphonate or phosphonate ester in the presence of a strong base.

The Horner-Wadsworth-Emmons reaction is one of the most convenient and well-known methods of constructing carbon-carbon double bonds. The reaction proceeds via the formation of an ylide intermediate. The HWE reaction is particularly useful for the synthesis of compounds with a Z-configuration.

The mechanism for the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, can be explained in the following steps:

Step 1: Formation of the ylide intermediate

The reaction starts with the formation of an ylide intermediate. This is achieved by the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of a strong base like NaOH or KOH. In this reaction, a deprotonated species called an ylide intermediate is generated.

Step 2: Addition of the ylide intermediate to the aldehyde

The ylide intermediate then attacks the aldehyde, leading to the formation of a betaine intermediate.

Step 3: Formation of the phosphonate ester

The betaine intermediate undergoes elimination to form the final product, 3,4-methylenedioxystilbene, and the by-product phosphonate ester.

The mechanism of the Horner-Wadsworth-Emmons (HWE) reaction between diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, is complete. This reaction is significant in organic chemistry and finds applications in the pharmaceutical industry.

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The carbor-14 (C14) has 8 neutrons.

How to calculate the neutrons?

Neutrons can be calculated by using the mass number and atomic number.

Neutrons = mass number - atomic number.

As given,

Carbon atomic number is 6 and carbon mass number is 14.

Apply formula,

neutrons = mass number - atomic number

neutrons = 14 - 6

               = 8

Therefore, carbor-14 (C14) has 8 neutrons.

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Answer: potassium and rubidium

Explanation:

1) The group 1 of the periodic table contain six elements namely Lithium(Li), Sodium(Na),Potassium(K),Rubidium(Rb),Cesium(Cs) and Francium(Fr). These metals are called alkali metals because they form alkalies( i.e. strong bases capable of neutralizing acids) when they react with water.

2) The heavier alkali metals (K, Rb, and Cs) react so vigorously that they invariably explode.

3) This trend, which is not consistent with the relative magnitudes of the reduction potentials of the elements, serves as another example of the complex interplay of different forces and phenomena—in this case, kinetics and thermodynamics.

The molarity of the solution is 2 M (Option C)

This is simply defined as mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = mass / molar mass

Mole of LiOH = 36 / 24

Mole of LiOH = 1.5 mole

Molarity = mole /Volume

Molarity = 1.5 / 0.75

Molarity = 2 M

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The extremophile that has evolved in conditions of extreme drought is the xerophile, while the extremophile that has evolved in conditions of extreme salt is the halophile.

Extremophiles are organisms that thrive in extreme environments, where most other life forms cannot survive. They have developed unique adaptations to withstand and thrive in these extreme conditions. Two types of extremophiles specifically adapted to different extreme environments are xerophiles and halophiles.

Xerophiles are extremophiles that have evolved to survive in conditions of extreme drought. They are adapted to environments with very low water availability or high water stress. These organisms have developed mechanisms to prevent water loss, such as efficient water retention and protection of cellular structures. Xerophiles can be found in desert environments and other arid regions.

On the other hand, halophiles are extremophiles that have evolved to live in conditions of extreme salt concentration. They are adapted to environments with high salinity, such as salt flats, salt lakes, and hypersaline environments. Halophiles have specialized adaptations to cope with the osmotic stress caused by high salt concentrations. They have enzymes and transport proteins that function in high-salt environments and can maintain osmotic balance within their cells.

In summary, xerophiles have evolved in conditions of extreme drought, while halophiles have evolved in conditions of extreme salt. These extremophiles showcase remarkable adaptations to thrive in their respective harsh environments.

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The molecule (a) is a structural isomer of C₅H₁₂. Hence, A is the correct answer.

Generally a structural isomer, in other words defined as a constitutional isomer and it is specifically one in which two or more organic compounds have the exactly same molecular formulas but different structures. As we can see the two molecules given below have the same chemical formula, but they are different molecules because they differ in the location of their respective methyl group.

Basically Pentane is described as any or one of the organic compounds which have the formula C₅H₁₂. The properties of pentane are similar to the properties of butane and hexane.

Therefore, pentane has three structural isomers they are Normal pentane, Iso pentane and Neo pentane. Hence, A is the correct answer.

The given question is incomplete and the complete question is given below in the image.

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Answer:

An Arrhenius base is a substance that dissociates in water to form hydroxide (OH–) ions. In other words, a base increases the concentration of OH– ions in an aqueous solution.

Some of the properties are:

1. Gamma, γ-rays are not deflected by electric and magnetic fields. It shows that they do not have any charge.

2. Gamma, γ-rays are electromagnetic waves like X-rays. The wavelength of γ-ray photon is smaller than that of X-rays.

3. The rest mass of a Gamma, γ-ray photon is zero. (Photon has mass zero but it has momentum, why?)

4. Gamma, γ-rays travel with the speed of light.

5. Gamma, γ-rays have very large penetrating power. They can pass through several centimeter of iron and lead.

6. Gamma, γ-rays can produce fluorescene in a substance like willimite.