1a. The bullet's speed (v_bullet) can be expressed as v_bullet = √[((m + M) * g * μk * d * 2) / m].
1b. The speed of a 8.0 g bullet that, when fired into a 12 kg stationary wood block, causes the block to slide 4.0 cm across a wood table is approximately 616 m/s.
1a. We can use the conservation of momentum and the work-energy principle to find an expression for the bullet's speed. The initial momentum of the system is equal to the final momentum of the system:
m*v_bullet = (m + M)*v_final
We can now use the work-energy principle, which states that the work done on the system is equal to the change in its kinetic energy:
W = ΔK = (1/2)(m + M)*v_final² - (1/2)m*v_bullet²
The work done by friction is:
W = -μk * (m + M) * g * d
Substituting the work done by friction into the work-energy equation and solving for v_bullet:
v_bullet = √[((m + M) * g * μk * d * 2) / m]
1b. We can now plug in the given values to find the speed of the 8.0 g bullet:
m = 0.008 kg (converted from grams to kilograms)
M = 12 kg
μk = 0.20
d = 0.04 m (converted from centimeters to meters)
g = 9.81 m/s² (acceleration due to gravity)
v_bullet = √[((0.008 + 12) * 9.81 * 0.20 * 0.04 * 2) / 0.008]
v_bullet ≈ 616 m/s
The speed of the 8.0 g bullet is approximately 616 m/s.
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the wheel is composted of a 10 kg hoop stiffened by 4 thiin spokes, each with a mass of 2 kg. a horizontal force of 40 n is applied to the wheel initially at rest. calculate the angular velocity of the wheel after its center has moved 3 m
The Angular velocity is 1.165 rad/s.
What is horizontal force?
Horizontal force is defined as a force applied in a direction perpendicular to the horizon. There are two parts to the force applied to a body: a horizontal component as well as a vertical component. The horizontal component of a force, as its name implies, is directed parallel to the surface, while the vertical component is directed perpendicular to a position of the body. In nature, almost all moving things have both vertical and horizontal components of force.
F = 40 N
m= 10 kg = 98.1 N
r= 0.3 m
Circumference of circle = 1.884 m
The Centre of the circle moves 1.884 m then the angle of rotation is 360
Applying the circle arc length formula (s = r θ)
s= 3 -1.884 = 1.116m
θ= 2310
F = m x v2 /r
V = sqrt(F x r/m)
= sqrt(40 x 0.3 / 98.1)
= 0.35 m/s
Angular velocity ω,
= v/r
= 0.35/0.3
=1.165 rad/s
Hence, the angular velocity is 1.165 rad/s
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An object initially at rest accelerates through a distance of 1.5 m at which point the instantaneous velocity of the object is 3.5 m/s.
a) What is the average acceleration of the object?
b) The time it took the object to travel 1.5 meters?
c) The average velocity of the object during this period of motion
The average acceleration is 2.33 m/s². the total distance traveled is 1.5 meters, and the total time taken is 0.84 seconds. The average velocity of the object during this period of motion is approximately 1.79 m/s.
The average acceleration of the object can be calculated by dividing the change in velocity by the distance traveled. In this case, the object started from rest and reached an instantaneous velocity of 3.5 m/s over a distance of 1.5 m. The change in velocity is 3.5 m/s - 0 m/s = 3.5 m/s. Therefore, the average acceleration is 3.5 m/s divided by 1.5 m, which equals 2.33 m/s².
distance = (initial velocity × time) + (0.5 × acceleration × time²). Given that the initial velocity is 0 m/s, the distance is 1.5 m, and the average acceleration is 2.33 m/s², we can solve for time. Rearranging the equation, we have 1.5 m = 0.5 × 2.33 m/s² × time². Solving for time, we find that it took approximately 0.84 seconds for the object to travel 1.5 meters. In this case, the total distance traveled is 1.5 meters, and the total time taken is 0.84 seconds. Therefore, the average velocity is 1.5 m divided by 0.84 s, which equals approximately 1.79 m/s.
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How does the study of light provide knowledge about stars, galaxies, and the universe’s beginning?
Answer in 3 to 4 sentences.
Answer:
from spectral lines astronomers Can determine
A modulo-24 counter circuit needs ( ) D filp-flops at least.
A modulo-24 counter circuit needs at least five D flip-flops to count up to 24.
A modulo-24 counter circuit needs at least 5 D flip-flops. A D flip-flop, also known as a data or delay flip-flop, is a type of flip-flop that stores the value of the data input.
In a modulo-n counter, the counter's output will change state only when n pulses have been received. In other words, the counter cycles through n states before returning to its original state. For a modulo-24 counter, this implies that there will be 24 states before it repeats the original state.
The state diagram of the modulo-24 counter can be represented as follows:As a result, 24 is equivalent to 11000 in binary. Since there are five digits in 11000, the modulo-24 counter will require at least five D flip-flops.The main answer is that a modulo-24 counter circuit needs at least 5 D flip-flops.
In digital electronics, a counter circuit is used to generate binary numbers using a clock pulse. A counter circuit is a collection of flip-flops that are connected together to form a sequential circuit.
A sequential circuit is a circuit in which the output is dependent on the input and the state of the circuit. There are two types of sequential circuits: synchronous and asynchronous.In synchronous sequential circuits, the output is dependent on the input and the state of the circuit, and the clock is used to synchronize the operation of the flip-flops. The clock pulse controls the operation of the flip-flops.
The flip-flops are triggered at the rising or falling edge of the clock pulse.In asynchronous sequential circuits, the output is dependent on the input and the state of the circuit, but the clock is not used to synchronize the operation of the flip-flops. Instead, the flip-flops are triggered by the output of other flip-flops or external signals.In a counter circuit, the number of flip-flops required depends on the modulus of the counter.
The modulus is the number of states in the counter. For example, a modulus-16 counter has 16 states. A modulus-24 counter has 24 states. A modulus-32 counter has 32 states.A D flip-flop is a type of flip-flop that stores the value of the data input. In a counter circuit, the D flip-flops are used to store the count. The output of the counter is taken from the outputs of the flip-flops.
The conclusion is that a modulo-24 counter circuit needs at least five D flip-flops to count up to 24.
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A hockey puck has a mass of 0.21 kg. If the hockey puck
is moving with 74 J of kinetic energy, what is its speed?
Show all your work.
Answer:
v = 26.54 m/s
Explanation:
Given that,
The mass of a hockey puck, m = 0.21 kg
The kinetic energy of the hockey puck, E= 74 J
We need to find the speed of the hockey puck. Let the speed is v. We know that, the kinetic energy is given by :
\(E=\dfrac{1}{2}mv^2\)
Where
v is the speed
So,
\(v=\sqrt{\dfrac{2E}{m}} \\\\v=\sqrt{\dfrac{2\times 74}{0.21}} \\\\v=26.54\ m/s\)
So, the speed of the hockey puck is 26.54 m/s.
I need help
With this
Answer:
dfvgxbcjnhmv,kbl
Explanation:
fvgbnhjmk
A spring that obeys Hooke's Law has an unstretched length of 10 cm. A load of 20 N is hung from the spring. The new length of the spring is 36 cm. What is the spring constant k of the spring? (a) 0.56 N/cm (b) 0.77 N/cm 8/12/2022 Physics (c) 1.3 N/cm (d) 1.8 N/cm (8) marks
A spring that obeys Hooke's Law has an unstretched length of 10 cm. A load of 20 N is hung from the spring. The new length of the spring is 36 cm, then the spring constant k of the spring would be 0.77 N/ cm.
What is the spring constant?The spring constant is used to define the stiffness of the spring, the greater the value of the spring constant stiffer the spring and it is more difficult to stretch the spring.
Relation between force and the spring constant,
F = - Kx
F= 20 N and
x = 36 -10
= 26 cm
K = F/x
=20/26 N/ cm
=0.77 N / cm
Thus, the spring constant for the spring is 0.77 N/ cm, therefore the correct answer is option B.
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In golf, a club is swung to hit a small ball resting on the ground. Golfer A holds his club a short distance behind the golf ball, swings through a small distance, and hits the ball. The ball travels a small distance. Golfer B holds his club above his shoulder, swings through a large distance, and hits the ball. The ball travels a large distance. Explain why golfer B's golf ball travels a longer distance than golfer A's by using Newton's First Law.
Answer:
Golfer B hits his golf ball at a higher rate of speed and with more force. This means that golfer B's ball will travel for a longer period of time and a longer distance due to newtons first law, where it says an object in motion stays in motion, with the same speed and in the same direction.
Explanation:
6. The race car in the previous problem slows from
36 m/s to 15 m/s over 3.0 s. What is its average
acceleration?
Answer:
a_AV - 15 m/s – 36 m/s =-70 m/s2. At. 3.0 s.
Explanation:
The average acceleration of the car as it slows down is -5 m/s².
Given is a race car that slows down from 36 m/s to 15 m/s in 3 seconds.
initial velocity [u] = 36 m/s
final velocity [v] = 15 m/s
time taken [Δt] = 3 s
We can calculate the acceleration as follows -
a = Δv/Δt
a = (v - u) / Δt
a = (15 - 30)/3
a = -15/3
a = -5 m/s²
Therefore, the average acceleration of the car as it slows down is
-5 m/s².
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Demuestre que la función de onda: y(x, t) = A e^−i(kx−ωt+φ) satisface la ecuación de onda lineal. (donde i =√−1).
Answer:
La ecuación de onda lineal para una función f(x, t) se escribe como:
\(\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}\)
Donde c es una constante que depende de la velocidad de propagación de la onda.
En este caso, tenemos:
\(f(x) = A*e^{-i*(k*x - w*t + \phi)}\)
Recordar que la derivada de la exponente es tal que:
\(k(x,y) = A*e^{c*x + n*y}\\dk/dx = c*A*e^{c*x + n*y}\)
Entonces las derivadas de f van a ser:
\(\frac{df}{dt} = (i*w)*f(x)\)
\(\frac{d^2f}{dt^2} = (i*w)^2*f(x) = -(w)^2*f(x)\)
\(\frac{df}{dx} = (-i*k)*f(x)\)
\(\frac{d^2f}{dx^2} = (-i*k)^2*f(x) = -k^2*f(x)\)
Entonces podemos reescribir la ecuación de onda como:
\(\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}\)
\(-(w)^2*f(x) = c^2*(-k^2*f(x))\)
Ahora podemos simplemente definir c^2 = (w/k)^2 y vemos que la ecuación de onda se cumple.
how can seismograms by used to locate an earthquake?
By studying the patterns of seismic waves recorded on seismograms, scientists can learn more about the subsurface structure of the Earth, allowing them to better understand the cause and effects of the earthquake.
Seismograms can be used to locate an earthquake in a variety of ways. Seismograms can be used to measure the arrival times of seismic waves at different locations, allowing scientists to triangulate the source of the earthquake. Seismograms can also be used to measure the magnitude of an earthquake, and to determine the type of faulting that caused the earthquake. By combining all of this information, seismologists can accurately pinpoint the location of an earthquake.
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(a) To calculate the minimum charge magnitude needed on the silk, we can use the equation for the electric force: F = qE. We know that E = 10 n/c and we can assume that the weight of the spider is acting in the opposite direction to the electric force (since it's being lifted by the electric force). Therefore, the net force on the spider is the difference between the two forces, which is equal to the electric force. The weight of the spider can be calculated by multiplying its mass (0.95 mg = 0.00000095 kg) by the acceleration due to gravity (9.81 m/s^2). Therefore, we can write the equation as:
F = qE = mg
q = mg/E
q = (0.00000095 kg)(9.81 m/s^2) / (10 n/c) = 9.5*10^-9 C
(b) To calculate the minimum number of electrons needed, we can use the charge of an electron (1.610^-19 C) and divide the minimum charge magnitude by it.
n = q/e
n = (9.510^-9 C) / (1.610^-19 C) = 5.910^9
Note: The charge is carried through the solution by the ions present in it, which in this case are sodium and chloride ions.
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(d) A force of 30 N is required to accelerate a skateboard at 1.5 m/s². How much force
would accelerate the same skateboard at 6.0 m/s²?
Answer:
\(\huge\boxed{\sf F = 120\ N}\)
Explanation:
Firstly, we need to find the mass of the skateboard.
Using formula:
F = maWhere,
Force = f = 30 NAcceleration = a = 1.5 m/s²30 = m (1.5)
Divide 1.5 to both sides
30/1.5 kg = m
20 kg = m
m = 20 kgNow, finding the force:Using the same formula.
F = maWhere,
mass = m = 20 kgAcceleration = a = 6 m/s²F = (20)(6)
F = 120 N\(\rule[225]{225}{2}\)
One year consists of 365 days. this is closest to how many seconds?
If one year consists of 365 days, this is closest to x = 3.15 × 10⁷ seconds.
What is the number of seconds in a year?
Given that;
Number of days in a year = 365Number of seconds in 365 days = ?Note that; there are 24 hours in a day, 1440 minutes in a day and 86400 seconds in a days.
1 day contains 86400 seconds
365 contains x seconds
x = 365 × 86400
x = 3.15 × 10⁷ seconds
Therefore, if one year consists of 365 days, this is closest to x = 3.15 × 10⁷ seconds.
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Stars which never disappear below the horizon are called__stars. A. Polaris B. visible C. constellation D. circumpolar
Answer:
D. circumpolar
Explanation:
A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.
-Wikipedia
A force is 10 and is used to move a box. It is moved a distance of 3 m. What is the work involved in moving the box?
Answer:
Workdone = 30Nm
Explanation:
Given the following data;
Force = 10N
Distance = 3m
To find the workdone;
Workdone = force * distance
Substituting into the equation, we have
Workdone = 10 * 3
Workdone = 30Nm.
Therefore, the work involved in moving the box is 30 Newton-meter.
How to do this question plz answer
Explanation:
(i)An analog signal has some feature that is a continuous function of the program material being transmitted. It may take on any of a range of values.
In radio, amplitude, frequency, or phase are features of the radio signal commonly modulated when transmitting an analog signal.
__
(ii)A digital signal has some feature that is a discrete function of the program material being transmitted. It may take on any of a specific set of values.
A digital radio signal typically uses some combination of amplitude, frequency, and phase to represent a discrete state being transmitted. Only specific values of these are used by the transmitter.
(The receiver generally has to deal with corruption of the signal by the transmission channel, so the received set of values may not correlate well with those intended at the transmitter. This is why error-correcting codes are often used with digital signal transmission.)
_____
Additional comment
Analog radio signals are generally transmitted using a carrier wave at a specific frequency (or in some specific frequency range, in the case of frequency modulation). Processing techniques may be used at the transmitter to limit the bandwidth used in the transmission. One commonly-used technique is to limit the transmitted spectrum to one side of the carrier wave frequency. (This is called "single side-band" radio.)
Digital signals offer the opportunity to transmit different bits of the information at different frequencies. Sometimes, "frequency hopping" is used, so that the transmitted carrier wave jumps around from one frequency to another in a predetermined pattern. The effect of this is to spread out the spectrum of the transmitted signal so that average power in any frequency band is significantly reduced. In fact, it may be indistinguishable from background noise, except by a receiver that tunes to the carrier wave in the predetermined frequency pattern.
Thirty-five (35.0) mL of ozone (O3) is stored at a temperature of 285 K and a pressure of 150.0 Pa. If the pressure is decreased to 125 Pa, what will be the new temperature?
Answer:
Temperature T2 = 237.5 K
Explanation:
Given:
Volume = 35 ml
T1 = 285 k
P1 = 150 pa
P2 = 125 pa
Find:
Temperature T2
Computation:
P1V/T1 = P2V/T2
150(35) / 285 = 125(35) / T2
Temperature T2 = 237.5 K
IF you are in Space and push a bowling what happens to you and the bowling ball?
Answer:
The bowling ball did not change size or shape- the only thing that changed was the amount of gravity that pulls on it. But the mass of the bowling ball would never change. A bowling ball with a mass of 12 pounds on earth will have the mass of 12 pounds on the moon! Mass is the amount of atoms that a space fills.
Explanation:
I hope this helps! :D
a 90-kg fullback, running at 5.0 m/s attempts to dive across the goal line for a touchdown. just as he reaches the goal line, he is met head-on in midair by two 73-kg linebackers, one moving at 3.0 m/s and the other at 4.0 m/s. if they all become entangled as one mass, with what velocity do they travel?
The final velocity of the combined mass of the fullback and the two linebackers is 4.09 m/s.
To find the velocity of the combined mass of the fullback and the two linebackers, we need to use the principle of conservation of momentum. This principle states that the total momentum of an isolated system remains constant if no external forces act on it.
First, we need to find the initial momentum of the fullback by multiplying his mass (90 kg) by his velocity (5.0 m/s):
Initial momentum of fullback = 90 kg * 5.0 m/s = 450 kg m/s
Next, we need to find the initial momentum of the two linebackers by multiplying each of their masses by their velocities:
Initial momentum of first linebacker = 73 kg * 3.0 m/s = 219 kg m/s
Initial momentum of second linebacker = 73 kg * 4.0 m/s = 292 kg m/s
Now, we need to add the initial momentum of the three individuals to find the total initial momentum:
Total initial momentum = 450 kg m/s + 219 kg m/s + 292 kg m/s = 961 kg m/s
Since the final velocity of the combined mass is going to be the same as the initial momentum, we can say:
Final velocity = 961 kg m/s / (90 kg + 73 kg + 73 kg) = 961 kg m/s / 236 kg = 4.09 m/s
Therefore, the final velocity of the combined mass of the fullback and the two linebackers is 4.09 m/s.
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A boy is looking into a plane mirror .His nose is 30 cm in front of the mirror .How far is his nose from where its image appears to be ?
Answer:
60cm
Explanation:
30+30=60
What questions do you still have about supermassive black holes after watching this Ted Talk? Do you feel that you have a deeper understanding of what they are and why they are important, like was asked of you in the third question? Explain and discuss.
After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.
While the speaker did mention that these black holes are responsible for the creation of galaxies, I wanted to know more about how this process works and why it is so important.Despite these questions, I do feel that I have a deeper understanding of supermassive black holes and their importance.From the Ted Talk, I learned that supermassive black holes are some of the largest objects in the universe and are essential for the formation of galaxies. I also learned that these black holes are incredibly powerful and have the ability to affect the trajectory of stars and planets.Overall, I think that the Ted Talk did a great job of explaining supermassive black holes in a way that was easy to understand. While there were still a few questions that I had after watching the video, I feel that I now have a better grasp of what supermassive black holes are and why they are so important.For such more question on supermassive
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Light waves can be easily blocked but ______ waves pass through all substances? ( fill in the blank)
The National Communication Association (NCA) defines several competencies students should exhibit after completing a college-level public speaking. Select all of the following competencies the NCA proposed.
Group of answer choices
A)Students should be able to get past their fears of public speaking.
B) Students should be able to apply critical thinking skills to interpret messages.
C) Students should be able to use communication to embrace difference.
D) Students should be able to influence public discourse.
he competencies proposed by the National Communication Association (NCA) for college-level public speaking include: students being able to apply critical thinking skills to interpret messages, use communication to embrace difference, and influence public discourse.
The National Communication Association (NCA) has defined several competencies that students should exhibit after completing a college-level public speaking course.
These competencies encompass a range of skills and abilities related to effective communication. Firstly, students should be able to apply critical thinking skills to interpret messages.
This means they should be capable of analyzing and evaluating the content, structure, and context of communication, allowing them to form reasoned judgments and interpretations.
This competency enables students to comprehend and engage with diverse messages encountered in various settings. Secondly, students should be able to use communication to embrace difference.
This competency emphasizes the importance of understanding and valuing diverse perspectives, cultures, and identities. It involves developing the ability to communicate effectively with individuals from different backgrounds and fostering inclusivity and respect in interactions.
By embracing difference, students enhance their communication skills and contribute to building a more inclusive and equitable society.Lastly, students should be able to influence public discourse. This competency highlights the power of public speaking to shape conversations, attitudes, and actions.
It involves developing persuasive and influential communication strategies to articulate ideas, advocate for causes, and participate actively in public discussions.
By mastering this competency, students become effective communicators who can contribute meaningfully to public discourse and positively impact society.
In summary, the competencies proposed by the NCA for college-level public speaking encompass the ability to apply critical thinking skills, use communication to embrace difference, and influence public discourse.
These competencies aim to equip students with essential skills for effective communication in diverse contexts and enable them to make a meaningful impact through their speech.
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NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)
Group of answer choices
It does not explain why objects exert gravitational force.
It does not describe the relationship between objects and forces.
It can be changed by new experimentation and investigation.
It can be used to prove that theories on gravity are non-observable.
If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?
The definition of eccentricity allows us to find that the answer for the distance to the focus is
c = 4.6 10⁶ km
The orbit of the plants without ellipses, where the eccentricity is the ratio between the distance to the focus and the major axis
e = \(\frac{c}{a}\)
Where e is the eccentricity, c the distance to the focus and a the major axis
In this case they indicate the value of the eccentricity e = 0.92 and the value of the major axis a = 5 10⁶ km
c = e a
Let's calculate
c = 0.92 5 10⁶
c = 4.6 10⁶ km
In conclusion using the definition of eccentricity we can calculate the distance to the focus is
c = 4.6 10⁶ km
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Answer:
4,600,000 km
Explanation:
I need help with this practice problem solving I believe the subject for this physics practice is complex numbers and vectorsI will send you an additional picture that goes along with this. it is a graph, it asks to use graph to answer this
The head-to-tail method consists of changing the subtraction of vectors into an addition, where the second vector in the addition will be the opposite vector of the second vector in the subraction:
\(a-b=a+(-b)\)If vector b is <1, 4>, vector -b is <-1, -4> (we just need to change every signal).
Now, let's draw vector 'a', and in the head of vector 'a' let's start drawing the tail of vector b:
The red vector, which is the sum of 'a' and '-b', is created at the tail of 'a' and finishes at the head of '-b'.
The initial point is (0, 0), and the terminal point is (-4, -9)
I am going to build a boat. My partner says I cannot put a refrigerator and a television in my boat because that would make it too heavy-and the boat might sink. Then we would be swimming with the sharks!!!!
What would you advise me to tell my friend? Is she right or wrong?
please help me...ill give out brainlyest
Answer:
In mine I said to build the boat accordingly based on what is going to be in it
Explanation:
just remember the density of the boat cannot change but the volume and the mass can
What force holds Mars in its place in the solar system?
Group of answer choices
The gravitational pull caused by the black hole in the center of the Milky Way
The gravitational pull caused by the sun within the solar system
The gravitational pull caused by the asteroid belt that lies beyond its orbit
The gravitational pull caused by the Earth and Jupiter within the solar system
The pull of gravity keeps planets in their orbits around the Sun. Only gravity keeps us on the surface of the Earth. Measurable characteristics of planets include their size, mass, density, and composition.
the solar system's gravitational force brought on by the sun.
The only planet smaller than Mars in the Solar System is Mars, which is the fourth planet from the Sun. Mars bears the name of the Roman god of war in the English language.
Mars, the fourth planet from the Sun, is a cold, arid, dusty place with a tenuous atmosphere. Mars is a dynamic planet as well, with seasons, ice caps, canyons, volcanoes, and indications that it once experienced greater levels of activity.
The Sun, our star, and everything gravitationally attached to it, including the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune; dwarf planets like Pluto; dozens of moons; and millions of asteroids, comets, and meteoroids, make up our solar system.
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of the two premises in the cause and effect argument for god's existence, skeptics are most likely to challenge the second premise. what five points (all from science) back the second premise up (the universe began to exist)?
The five points (all from science) to back the second premise up (The universe began to exist) are:
Einstein's theory of General Relativity
Galaxy seeds
Second Law of Thermodynamics
Expanding universe
Radiation echo
What is thermodynamics?
The four principles of thermodynamics, which give a quantitative description using quantifiable macroscopic physical variables but may be interpreted in terms of microscopic elements by statistical mechanics, regulate how these quantities behave. Physical chemistry, biochemistry, chemical engineering, mechanical engineering, and other complicated subjects like meteorology are just a few of the topics in science and engineering where thermodynamics is relevant.To know more about thermodynamics, click the link given below:
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A 45.2 kg softball player slides across dirt with Uk=0.340. What is her acceleration?
Answer:
The answer is -3.34 m/s^2.
Explanation:
I used another brainly question to help me find the answer. It was pretty similar to this one so yeah. Good luck to you nonetheless.
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