A cannonball is shot horizontally off a 10.5 m high castle wall at 47.4 m/s. How far from the base of the wall does the cannonball land?

Answer:

B

Explanation:

A body has kinetic energy that is moving

Answer:

there is no image to go off of. If you could share that I would be happy to help.

Explanation:

Please share the image!

Answer:

its D

Explanation:

The kinetic energy is the energy of motion.

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

An item in motion has energy, which is called kinetic energy. Motion in space, you walking down the street, and the rotation of the planet around the sun are all examples of kinetic energy. Kinetic energy has the following formula: K.E. = 1/2 m*v², where m is the object's mass and v is its square velocity.

Any object in motion is using kinetic energy, so the energy of motion is

kinetic energy.

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Answer:

20 m

Explanation:

1 s = 4 m

5 s = ?

? = (4 x 5) = 20 meters

Answer:

distance = 0.8 m

Explanation:

given:

A bike travels at a constant speed of 4.0 m/s for 5.0s.

find:

How far does it go?

solution:

distance = speed / time

distance = 4.0 m/s

                     5 sec.

distance = 0.8 m

As we know that,

\(\boxed{ \sf \: {v}^{2} - {u}^{2} = 2as }\)

According to the question,

0² - u² = 2(20)(121)

0 - u² = 4840

-u² = 4840

-u = √4840

u = -69.5 m/s

The initial velocity of the stone is -69.5 m/S.

When the child moves from the center to the edge of the rotating platform, the following changes occur in the child-platform system: 1. Angular momentum, 2. Rotational inertia, 3. Angular velocity and 4. Rotational kinetic energy.

1. Angular momentum: Remains constant. Angular momentum is conserved in the absence of external torque, so the total angular momentum of the child-platform system does not change.

2. Rotational inertia: Increases. As the child moves away from the center, the distance between the child and the rotation axis increases, which leads to an increase in the moment of inertia (rotational inertia) of the system.

3. Angular velocity: Decreases. Due to the conservation of angular momentum (L = Iω, where L is angular momentum, I is rotational inertia, and ω is angular velocity), as rotational inertia increases, angular velocity must decrease to keep the product constant.

4. Rotational kinetic energy: Remains constant. Since the total angular momentum is conserved, and rotational kinetic energy is proportional to the square of angular velocity and rotational inertia (K = 1/2 Iω^2), the changes in angular velocity and rotational inertia result in no net change in rotational kinetic energy.

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Answer: 20mm/s

Explanation: Maximum displacement in shortest time....

Answer:

To find the specific gravity of the fluid, we need to compare its density to that of water.

First, we need to find the mass of the water in the bottle:

Mass of water = Mass of filled bottle - Mass of empty bottle

Mass of water = 84.70 g - 10.00 g

Mass of water = 74.70 g

Next, we can calculate the volume of water in the bottle using the density of water, which is 1 g/mL:

Volume of water = Mass of water / Density of water

Volume of water = 74.70 g / 1 g/mL

Volume of water = 74.70 mL

Now we can use the mass of the bottle when it is filled with the other fluid to find the mass of the fluid:

Mass of fluid = Mass of filled bottle - Mass of water - Mass of empty bottle

Mass of fluid = 70.00 g - 74.70 g - 10.00 g

Mass of fluid = -14.70 g

This result is negative, which means that the mass of the fluid is less than the mass of the water. This could be due to a variety of factors, such as air bubbles trapped in the fluid or an error in the measurements.

Assuming that the mass of the fluid should have been greater than the mass of the water, we can still calculate the specific gravity using the volume of water we calculated earlier:

Density of fluid = Mass of fluid / Volume of water

Density of fluid = (70.00 g - 10.00 g - 74.70 g) / 74.70 mL

Density of fluid = -14.70 g / 74.70 mL

Density of fluid = -0.196 g/mL

Again, this result is negative and therefore not physically meaningful. It is possible that there was an error in the measurements or that the assumption about the mass of the fluid being greater than the mass of the water was incorrect. Without additional information, we cannot calculate the specific gravity of the fluid.

Explanation:

The light ray bends away from the normal when passing from water into air at a non-90° angle.

When light passes through a boundary between two different mediums, such as water and air, it undergoes refraction. Refraction is the bending of light as it travels from one medium to another due to a change in its speed.

The direction of refraction depends on the angle of incidence (the angle between the incoming light ray and the normal, which is a line perpendicular to the boundary surface) and the refractive indices of the two mediums involved.

In this case, when a light ray passes at a non-90° angle from water into air, it will bend away from the normal. This means that the angle of refraction (the angle between the refracted light ray and the normal) will be greater than the angle of incidence.

This phenomenon can be explained using Snell's law, which states:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

where n₁ and n₂ are the refractive indices of the initial and final mediums, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.

In the case of water and air, the refractive index of water is higher than that of air, meaning that light travels slower in water than in air. When a light ray passes from water into air at a non-90° angle, it enters a medium (air) with a lower refractive index. As a result, the light ray bends away from the normal, as determined by Snell's law.

When a light ray passes at a non-90° angle from water into air, it bends away from the normal. This bending phenomenon is a result of the change in speed of light as it transitions between the two mediums and can be explained using Snell's law.

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Blurring the background and foreground of the main subjects in photographs can create a calming effect, option D.

This technique is often used in portrait photography to make the subject stand out and appear more prominent. By blurring the surrounding elements, the viewer's focus is drawn towards the subject, creating a sense of serenity and isolation. This effect is particularly effective when the background and foreground are busy or distracting. However, it is important to note that the impact of this technique on the viewer can also depend on the specific composition and context of the photograph. Blurring the background and foreground is not likely to create a monotonous and calming effect (option D), as the blurred elements can still convey a sense of movement or depth, which can be visually engaging.

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1. The Schrödinger equation is a fundamental equation in quantum mechanics that describes the behavior of particles. The general solution represents the wave function of a particle and provides information about its position and momentum.

3.Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically.

1. The Schrödinger equation is a partial differential equation that was developed by Erwin Schrödinger in 1925 as a mathematical formulation of quantum mechanics. It describes how the wave function of a particle evolves over time. The equation takes the form:

Ĥψ = Eψ

Where Ĥ is the Hamiltonian operator, ψ is the wave function, E is the energy of the particle, and Ĥψ represents the operation of the Hamiltonian on the wave function.

The general solution to the Schrödinger equation represents the wave function of a particle. The wave function provides information about the probability distribution of the particle's position and momentum. It contains both real and imaginary components and is typically represented as a complex-valued function.

The wave function, ψ, can be written as a product of a spatial part and a temporal part:

ψ(x, t) = Ψ(x) * Φ(t)

The spatial part, Ψ(x), represents the probability amplitude of finding the particle at position x, while the temporal part, Φ(t), describes how the wave function evolves over time.

The Schrödinger equation and its general solution are essential tools in quantum mechanics, as they allow us to predict the behavior of particles on a microscopic scale. By solving the equation, we can determine the wave function of a particle and calculate probabilities associated with its position and momentum.

2.Case 1: Particle in a Box

In the case of a particle confined to a one-dimensional box, the potential energy is zero within the box and infinite outside of it. This situation can be represented by the following potential function:

V(x) = 0,  0 < x < L

V(x) = ∞,  x ≤ 0 or x ≥ L

To solve the Schrödinger equation for this case, we need to find the wave function (Ψ) and the corresponding energy levels (E). The general form of the wave function inside the box is given by:

Ψ(x) = A * sin(kx)

Where A is a normalization constant, and k = (2π/L).

Applying the boundary conditions, we find that the wave function must go to zero at both ends of the box (x = 0 and x = L). This leads to the quantization of the wave vector k:

k = nπ/L,  where n = 1, 2, 3, ...

The corresponding energy levels are given by:

E = (ħ²π²/2mL²) * n²

Where ħ is the reduced Planck's constant and m is the mass of the particle.

Case 2: Harmonic Oscillator

In the case of a particle in a harmonic oscillator potential, the potential energy can be described by:

V(x) = (1/2)kx²

Where k is the spring constant. To solve the Schrödinger equation for this potential, we use the harmonic oscillator equation:

- (ħ²/2m) * (d²Ψ/dx²) + (1/2)kx²Ψ = EΨ

The solutions to this equation are given by Hermite polynomials, and the corresponding energy levels are quantized. The wave function for the harmonic oscillator potential can be expressed as a product of a Gaussian function and a Hermite polynomial:

Ψ(x) = (A/π)\(^{(1/4)\) * exp(-αx²/2) * Hₙ(√αx)

Where A is a normalization constant, α = (√(mk/ħ)), and Hₙ is the Hermite polynomial of degree n.

The energy levels in the harmonic oscillator potential are given by:

E = (n + 1/2)ħω

Where n = 0, 1, 2, ... and ω = (√(k/m)) is the angular frequency of the oscillator.

These solutions provide insights into the behavior of electrons traveling in these potential systems, including the quantization of energy levels and the spatial distribution of the wave functions.

3. Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically. This effect arises from the wave nature of particles, as described by the Schrödinger equation.

Tunneling has important implications in various areas of physics, such as nuclear fusion, quantum computing, and scanning tunneling microscopy. It allows for phenomena such as alpha decay, where alpha particles escape from atomic nuclei, and the operation of tunneling diodes in electronic devices.

Overall, tunneling is a fascinating quantum mechanical phenomenon that challenges our classical intuition and plays a crucial role in understanding the behavior of particles in the presence of potential barriers.

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Answer:

9

Explanation:

Say you had 1 apple, if someone gives you another 8 apples you would have 9 apples total.

Answer:

9

Explanation:

9 is 1 higher than 8, so 8+1 equals 9

Answer:

Waves move through different vmaterials

A:  Waves travel at different speeds through different materials.

Answer:

Two tectonic plates move away from each other

Explanation:

I just did this on AP3X. If this is not what your lookinf for then so sorry

A. The velocity of the object at t = 10.0 s is 78.9 m/s.

B. The time(s) at which the object at rest are 0.33s and 4.10s.

C. The acceleration of the object at t = 0.50 s is 8.3 m/s².

The position of an object as a function of time is given as, x=At³+Bt²+Ct+D. The constants are A=2.10 m/s3, B=1.00 m/s2, C=−4.10 m/s and D=3.00 m.

A.  The velocity of the object is given as, v= dx/dt. So, velocity,v= d(At³+Bt²+Ct+D)/dt = 3At²+2Bt+C. Putting the values of the constants and time t=10.0 secs, velocity=3×2.10×(10)² +2×1.00×10 +(-4.10) =63+20-4.10 =83-4.10 =78.9 m/s.

B. When the object is at rest, the velocity of the object is zero.So, v= 3At²+2Bt+C=0 , 3At²+2Bt=-C, t(3At+2B)=-C, t=-C or 3At+2B=-C. So the time at which it is at rest is 4.10s and 0.33 s.

C. The acceleration of the object is given as, a=dv/dt, a=d( 3At²+2Bt+C)/dt =6At+2B. So acceleration at time t=0.5sec is a=6×2.10×0.5 +2×1.00 =8.3 m/s².

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Answer:

See Below.

Explanation:

I can't transpose the diagram onto Brainly. I'll do my best to describe what is going on.

Now you are ready to develop the equation

Clockwise

There is only 1 force where B is the Balance point that is going clockwise

10 * Force A

The AntiClockwise Moments

Platform: 4*10kg * 9.8 = 392 N m

Physics T: 2 * 75 * 9.8 = 1470 N m

So the Anti Clockwise moments = the clockwise moments.

10 * Force A = 392 NM  + 1470NM   Divide by 10. Remember that is in meters

Force A = 1862 N M / 10 10 M = 186 N

Does that make some sort of sense? It should Student A is the furthest distance from where all the action is at B. Therefore he is carrying the lightest weight.

Now what is the total force?

(75 + 10 ) * 9.8 = 85 * 9.8 = 833

This is one of those strange things that won't make sense until it does. Read the next sentence carefully. B is carrying most of the weight. Remember Newtons measure weight.

Support of A = 186 N

Support of B = x

Total of A+B = 933

186 + x = 833

x = 933 - 186

x = 647

So the forces are

A supports    186

B supports    647

Answer:

Postindustrial

Explanation:

Answer:

Average velocity = 0.375 m/s

Explanation:

Average velocity = net displacement/total time

The penguin swims leftward 9m then dodges rightward another 12m. Let left side is negative and right side is positive.

Average velocity,

\(v=\dfrac{-9+12}{8}\\\\v=\dfrac{3\ m}{8\ s}\\\\v=0.375\ m/s\)

So, the penguin's average velocity during the chase is 0.375 m/s.

Answer:

Velocity=0.38

Speed=2.6

Explanation:

False. Staleness and burnout are often associated with overtraining, which occurs when an individual exceeds their capacity to recover from intense physical training or activity.

Overtraining can lead to physical and psychological symptoms, including decreased performance, fatigue, irritability, and decreased motivation. It is important for individuals to listen to their bodies and take rest and recovery periods to prevent overtraining and associated symptoms.

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This is not a gamma radiation because there is a change in the atomic number of the daughter nucleus. It is rather a beta decay.

We have to note that when we talk about a decay we are talking about the manner that we can be able to break up the atom of a radioactive substance so that we can be able to produce a new substance.

We can see now that what we have here is the loss of a beta ray or an electron from the specie that is shown. This is evidenced by the change in the atomic number of the daughters nucleus.

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Answer:

\(K.E. =1/2mv^2\\6.8*10^4=1/2*175*v^2\\777.14=v^2\\v=27.87 m/s\)

Kinetic energy is the energy possessed by a body due to its motion.

The Doppler effect is the difference in a wave's frequency or wavelength caused by an observer moving in respect to the wave source. As both the elephant and the zookeeper are moving in this situation, their movements will have an impact on the elephant's sound waves.

A sound wave with an airborne wavelength of 0.85 m has a frequency of 340 m/s.

Hence, the distance between neighbouring identical portions of a sound wave is its wavelength. Similar to how the separation between adjacent crests .

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Answer:

Primer can help seal the surface to protect against moisture and allow the paint to properly stick. Cover the area with primer, allowing the surface to dry according to the manufacturer's directions

Explanation:

Answer:

here's the answer to your question hope it helps you

Explanation:

time=distance/speed

=7m/5ms

=1.4s

Answer:

Other than gravity, the most commonly encountered force is what or the force that resists motion.

friction

the ratio of the force necessary to move an object (or keep it moving) and the normal force

coefficient of friction

friction between a solid and a liquid or gas

drag

a force that resists motion

friction

the force that presses two surfaces together and is directed perpendicular to the contact surface; on a level surface, its magnitude is equal to the force of the object's weight but in the opposite direction

normal force

force that opposes a rolling object

rolling friction

force that opposes a sliding object

sliding or kinetic friction

force that opposes the start of motion

starting or static friction

a force that develops when a mass is accelerated by gravity; stated as Fw = mg

weight

Friction is a force that resists what

motion

It occurs when a surface in motion rubs against another what

surface

What acts parallel to the surfaces that are moving against one another and in the direction opposite to the direction of the motion (represented by F).

Friction

riction is caused by the interaction of the what or what of each object sliding over each other.

atom or molecules

he more contact the atoms are able to make, the greater the what

frictional effect

A what surface will produce more friction (resistance) than a smooth surface

rough surface

The high points on one surface interact with the high points on the other surface allowing atoms and molecules to form temporary what

intermolecular bonds

The more bonds that are allowed to form, the greater the what

friction

he force that opposes the start of motion is referred to as what

starting or static friction

This force is caused by the what that form between two surfaces

tiny bonds

The pull required to keep the block moving at a constant speed in the example above is due to what

sliding or kinetic friction

What occurs as tiny intermolecular bonds are constantly being formed and broken.

Sliding friction

Sliding friction is also affected by the weight of the object and another force called the what

normal force

What is the force of the contact surface pressing opposite the weight of the object, as seen in the diagram below.

normal force

The normal force is always perpendicular to the what

contact surface

The ratio between the sliding friction and the perpendicular normal force is called the what of sliding friction

coefficient

What is represented by the Greek letter mu, μ,

coefficient

he third type of friction that can exist between solid surfaces is what or the force that opposes a rolling object

rolling friction

Friction can also exist between what

solids liquids and gases

Gases and liquids, such as air and water, offer what

resistance to motion

the opposing force between a solid and a liquid or gas

drag

Answer:

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt. Speed (or rate, r) is a scalar quantity that measures the distance traveled (d) over the change in time (Δt), represented by the equation r = d/Δt.

Explanation:

The formula for speed is speed = distance ÷ time.

The sensation of colour is seen when light falls on the eye's cones.

The retina, a component of the eye, is what detects light entering our eyes. The pupil is the black hole in the centre of the eye that lets the light into the eye.

Light-sensitive cells can be found in the retina of the eye. It contains two kinds of cells known as rods and cones. Cones are the cells of retina that produce colour sensation. These photoreceptor cells are responsible for colour vision.

Rod cells are photoreceptor cells in the retina that function in dim light better than the other type of visual photoreceptor, cone cells.

Rods are employed in peripheral vision and are often clustered at the borders of the retina.

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