The capacitance of a capacitor is calculated based on 3 values, area of plates, distance between them and epsilon zero, which is the electric permitivity at vacum.
\(\begin{gathered} C=\frac{A}{d}\cdot\xi0 \\ 1.11\cdot10^{-8}F=\frac{8.89\cdot10^{-4}m^2}{d}\cdot8.854188\cdot10^{-12}F/m \\ d=7.091\cdot10^{-7}m \end{gathered}\)A hook of radius 2m weighs 100kg. It rolls along a horizontal floor so that its centre if mass has a speed of 20cm/s. How much work has to be done to stop it?
Answer:
2 J
Explanation:
Work = change in energy
W = ΔKE
W = ½ mv²
W = ½ (100 kg) (0.2 m/s)²
W = 2 J
Answer:
4Nm
Explanation:
Work done is force times distance.
The force is given as mass x (speed )^2 / raduis . Expressed mathematically we have ;
Mv^2/r
Then for the slightest measurable distance r we have: the work done as;
Mv^2/r × r
= Mv^2
= 100 × 0.2 × 0.2= 4Nm
Describe a situation in which these two velocity vectors are different. Use complete sentences.
When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.
Types of velocity
Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.
Acceleration is defined as the rate at which velocity changes with time.
There are two types of velocity which includes:
Average velocity: This is the average rate of change of position of particles with respect to time over an interval.
Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.
The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.
Pls give me the answer asap
Raju's statement is not correct fully as it states that uniform motion is seen only in objects traveling in a straight line while ,Tejas is correct in pointing out that uniform motion can also be observed in objects traveling in circular motion.
Uniform motion refers to the movement of an object at a constant speed in a particular direction. In this type of motion, the object covers equal distances in equal intervals of time. Suppose for example (straight line movement), a car moving on a straight road at a constant speed of 60 km/h. If the car maintains this speed without any change in direction, it exhibits uniform motion. Other example is regarding the object moving in circular path where a race car driving around a circular track with a radius of 100 meters. If the car maintains a constant speed of 40 meters per second and completes each lap in the same amount of time, it exhibits uniform motion. Therefore, Tejas' justification is valid, as he states that uniform motion can indeed be observed in objects traveling in circular paths, in addition to objects moving in straight lines.
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What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 288K?Use the equation 1/2mv^2 =3/2nRTFor m use 0.01000 kg. Remember that R-8.31 J/(mol.K).A. 847 m/sB. 718,000 m/sC. 8.47 m/sD. 71.8 m/s
the Given
*The number of mol of neon is n = 1 mol.
*The temperature of the neon gas is T = 288 K.
*The mass of the neon gas is m = 0.01 kg.
*The gas constant R is R = 8.31 J/(mol.K).
To find: The average velocity of atoms of neon (v).
According to the given equation,
\(\frac{1}{2}mv^2=\frac{3}{2}nRT\)Substitute the known values.
\(\begin{gathered} \frac{1}{2}\times0.01\text{ kg}\times v^2=\frac{3}{2}\times1\text{ mol}\times8.31\text{ J/mol.K}\times288\text{ K} \\ 5\times10^{-3}\text{ kg}\times v^2=\frac{3}{2}\times2393.28\text{ J} \\ 5\times10^{-3}\text{ kg}\times v^2=3589.92\text{ J}\times\frac{1\frac{kg.m^2}{s^2}}{1\text{ J}} \\ v^2=\frac{3589.92\text{ }\frac{kg.m^2}{s^2}}{5\times10^{-3}\text{ kg}} \\ v^2=717984\frac{m^2}{s^2} \\ v=\sqrt[]{717984\frac{m^2}{s^2}} \\ v=847.33\text{ m/s} \\ v\cong847\text{ m/s} \end{gathered}\)The average velocity of atoms of neon is 847.33 m/s. Thus, option (A) is the correct answer.
What are the properties of object located at infinites
Answer:
As the parallel rays coming from the object converge at the principal focus, F of a concave mirror; after reflection through it. Therefore, when the object is at infinity the image will form at F. Properties of the image formed: Point-sized image, highly diminished in size.
At Infinity: At focus (F)
Position of object: Position of image
Between F and C: Beyond C
Beyond C: Between F and C
Explanation:
This is because when the object is at infinity, the incident rays are parallel to the principal axis. Hence the image is formed at the focus. And the image is real and inverted but in diminished size.
How did great britian changed the science of forces
Shortage of wood and the abundance of convenient coal deposits and Commercial-minded aristocracy of the great Britain changed the science of forces.
What is the Spread of the Industrial Revolution?Britain attempted to keep its manufacturing processes a secret, but people came to learn about them and brought the knowledge home with them.
Sometimes they used rowboats to smuggle the machines to nearby nations. Belgium, Switzerland, France, and the states that would become Germany were the first nations after Britain to build factories and railroads. Industrialization proven to require the establishment of a national train network. Switzerland's railroads were built in 1847, Belgium's in 1834, France's in 1842, and Germany's in the 1850s.
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What forces are considered when we examine interactions between two objects in a closed, isolated system
Given what we know, we can confirm that when dealing with a closed and isolated system, the forces to be considered in the system are internal forces.
What is a closed system?It is a system that does not interact with the environment or its surroundings.A closed system is described as to not interchange energy of any form. Therefore, all forces present are internal in nature.Therefore, we can confirm that because a closed system is one that does not interact with the environment or its surroundings, any forces to be considered will be internal in nature.
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Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.
Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
How do we explain?In a mixed economy, economic decisions are made by both the government and consumers.
The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.
In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.
The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.
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Show the relation among MA, VR and n.
Answer:
good luck!!! sorry I just needed the points xoxo
Explanation:
umm yeah no sorry I tried
Witch force is represented by arrow at c?
Answer:
did u know there's no such thing as "pear cider."
Explanation:
An engineer carries a set of titanium rods, each with a length of and mass of , up a ladder from the floor of a fabrication facility. He sets them down on an overhead walkway above the floor. Unfortunately, as soon as he does of the rods roll off the walkway and fall to the floor. The engineer climbs back down and brings the fallen rods back up to the walkway. Calculate the change in gravitational potential energy of the engineer's set of rods
Answer:
0.0512 kJ
Explanation:
From the given information, since the values were not given:
Then, Let assume that:
A set of 50 titanium rods is handled by the engineer, with 50cm length and 20g of mass.
The overhead walkway = 5.3 m
In this process, 12 rods roll of the walkway
We are to determine the change in the Gravitational P.E
Change in P.E = final P.E- initial P.E
Change in P.E = (50 mgh) - (0)
Change in P.E = \((50\times \dfrac{20}{1000}\times 9.8 \times 5.3 )-0\)
Change in P.E = 51.94 Joules
Change in P.E = 0.05194 Joules
Change in P.E ≅ 0.0512 kJ
pls help thank youuuu
1. A fluorescent light bulb produces just as much light in the same electrical circuit as an incandescent bulb , but requires much less energy to produce it. Which of the following is the most logical explanation for this?
A. The incandescent bulb produces more forms of energy than just light, like heat.
B. The fluorescent light bulb produces more light than any other bulb.
C. The incandescent bulb has to be connected to another circuit.
D. The fluorescent light bulb generates more current than any other type.
The most logical explanation is the incandescent bulb produces more forms of energy than just light, like heat.
Conservation of energyThe principle of conservation of energy can be used to explain to reason behind the more energy required for an incandescent bulb to produce the same light as a fluorescent light bulb.
Some part of the energy required by the incandescent bulb is used to produce light while some is used to generate heat.
For fluorescent light bulb, all the energy are used to produce light, leading to a better efficiency and less energy required to produce same amout light as incandescent bulb.
Thus, the most logical explanation is the incandescent bulb produces more forms of energy than just light, like heat.
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A wire of length L is made up of two sections of two different materials connected in series. The first section of length L1 = 17.7 m is made of steel and the second section of length L2 = 28.5 m is made of iron. Both wires have the same radius of 5.30 ✕ 10−4 m. If the compound wire is subjected to a tension of 148 N, determine the time taken for a transverse pulse to move from one end of the wire to the other. The density of steel is 7.75 ✕ 103 kg/m3 and the density of iron is 7.86 ✕ 103 kg/m3.
Answer:
Explanation:
velocity of wave in a tense wire is given by the expression
\(v= \sqrt{\frac{T}{m} }\)
v is velocity . T is tension and m is mass per unit length .
for steel wire
m = π r² ρ where r is radius and ρ is density
= 3.14 x (5.3 x 10⁻⁴)²x7.75 x 10³
= 683.57 x 10⁻⁵ kg/m
v = \(\sqrt{\frac{148}{683.57\times 10^{-5}} }\)
= 1.47 x 10² m /s
= 147 m /s
for iron wire
m = π r² ρ where r is radius and ρ is density
= 3.14 x (5.3 x 10⁻⁴)²x7.86 x 10³
= 693.27 x 10⁻⁵ kg/m
\(v = \sqrt{\frac{148}{693.27\times 10^{-5}} }\)
= 146 m /s
Time taken to move from one end to another
= 17.7 / 147 + 28.5 / 146
= .12 + .195
= .315 s .
When discussing Newton's laws of motion which terms do people most likely use when talking about Newton's third law of motion
Answer:
Explanation:
When discussing Newton's laws of motion, the most likely used terms when talking about Newton's third law of motion are action and reaction. According to this law, for every action there is an equal and opposite reaction
Answer: C. "action" and "reaction"
Explanation: Newtons 3rd law of motion: for every action, there is an equal and opposite reaction (action and reaction forces are described by this law).
Have a nice day. :)
HELP PLEASE DUE IN 3 MINUTES
Answer:
tectonic plate movement
Explanation:
Kristen is walking, for about 60 seconds, to her job interview at 1.3 m/sec when she glances at her watch and realizes she is going to be late. She quickens her pace at a rate of 0.090 m/sec2. What is Kristen’s speed after 10 seconds? How far has Kristen traveled in the 70 seconds?
The total distance traveled by Kirsten for the duration of 70 seconds is 92.5 metres and the final velocity is 2.2 m/s.
What is uniform motion?Uniform motion refers to the movement of the body in which it travels equal distance in equal interval of time.
Given:
For 60 seconds Kristen walks at the constant speed of 1.3m/s
For the next 10 seconds she walks with an acceleration of 0.09
Final speed of Kristen can be calculated using Newton's first law of motion
v = u + at
On substituting values we get,
Final speed of Kristen = 1.3+0.09×10
Final speed of Kristen = 2.2m/s
First we will find distance traveled by Kristen for the initial 60 seconds.
Since the motion is uniform we can use the speed distance formula.
Distance = speed × time
Distance traveled by Kristen for the initial 60 seconds = 1.3×60
Distance traveled by Kristen for the initial 60 seconds= 78 metre
Now for the next 10 seconds we will use Newton's third law of motion
Ok substituting values we get
Distance traveled by Kristen for next 10 seconds = 17.5 metre
The total distance traveled by Kirsten for the duration of 70 seconds is 92.5 metres.
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8. Two perpendicular forces, one of 45.0 N directed upward and the other of 60.0 N directed to the
right, act simultaneously on an object with a mass of 35.0 kg. What is the magnitude of the
resultant acceleration of the object?
a) 2.14 m/s
b) 5.25 m/s
c) 3.00 m/s
d) 1.41 m/s
Answer:
\(a=2.14\ m/s^2\)
Explanation:
Force in upward direction = 45 N
Force in right side = 60 N
Mass of the object, m = 35 kg
Net force on the object is given by :
\(F=\sqrt{45^2+60^2} \\F=75\ N\)
We know that,
F = ma
Where
a is acceleration of the object
\(a=\dfrac{F}{m}\\\\a=\dfrac{75\ N}{35\ kg}\\\\a=2.14\ m/s^2\)
So, the acceleration of the object is \(2.14\ m/s^2\).
The motor of a table saw is rotating at 3450 rev/min. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208 m is mounted on the same rotating shaft as the second pulley.
Answer: It should be the answer beginning like this
The linear spread is that
The radial acceleration of locations along the blade's outer edge is approximately 17580 \(m/s^2\).
What is Radial acceleration?Radial acceleration describes the acceleration of an object travelling on a circular path towards the circle's center. It can be defined as the rate of change of tangential velocity with regard to time and is also known as centripetal acceleration.
Given:
A table saw's engine rotates at 3450 revolutions per minute.A V-belt connects a pulley that's attached to the motor shaft to a second pulley half the diameter.A 0.208 m circular saw blade is installed on the same rotating shaft as the second pulley.We know that the motor is rotating at 3450 rev/min. One revolution is equal to 2π radians, so we can convert the motor speed to radians per minute:
ω₁ = (3450 rev/min) x (2π rad/rev) = 21675π rad/min
The second pulley is half the diameter of the first pulley, so its angular speed, ω₂, is twice that of ω₁:
ω₂ = 2ω₁ = 43350π rad/min
The circular saw blade is mounted on the same shaft as the second pulley, so it also rotates at the same angular speed:
ω = ω₂ = 43350π rad/min
We can now calculate the linear speed of the small piece of wood moving at the same rate as the rim of the circular saw blade, indicated by v. The circumference of the circle is supplied by the rim of the circular saw blade:
C = πd = π(0.208 m) = 0.6548 m
The linear speed of the little piece of wood is equal to the tangential speed of the circular saw blade's rim:
v = ωr
where r is the circular saw blade's radius, given by half its diameter:
r = d/2 = 0.208/2 = 0.104 m
By substituting the values, we obtain:
v = r = (43350 rad/min) x (0.104 m) x (1/60) = approx. 23.0 m/s
As a result, the linear speed of the little piece of wood moving at the same rate as the rim of the circular saw blade is about 23.0 m/s.
Next, compute the radial acceleration of locations on the blade's outer edge, represented by. The radial acceleration is calculated as follows:
α = rω²
By substituting the values, we obtain:
r2 = (0.104 m) x (43350 rad/min)2 x (1/602) = 17580 m/s2 (approximate)
Therefore, the radial acceleration of points on the outer edge of the blade is approximately 17580 m/s². This high radial acceleration explains why sawdust doesn't stick to the teeth of the saw blade.
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Your question is incomplete, most probably the complete question is:
The motor of a table saw is rotating at 3450{\rm rev/min}. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208{\rm m}is mounted on the same rotating shaft as the second pulley.
The operator is careless and the blade catches and throws back a small piece of wood. This piece of wood moves with linear speed equal to the tangential speed of the rim of the blade. What is this speed?
v =_______________________ m/s
Calculate the radial acceleration of points on the outer edge of the blade to see why sawdust doesn't stick to its teeth.
\alpha=______________________m/s2
how do you determine half life
Answer:
T= In(2)/___ =__ In(2)
Explanation:
the equation pices arnt on the keyboard so i put the blanks
sorry
jope it helps some. Have a good day ir night! :)
A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to the wall is 300 m The time delay between clap an echo is 1.5 seconds. Calculate the speed of sound
Explanation:
∆x=300 m×2
∆t=1.5 s
v=∆x/∆t → v=2×300/1.5 = 400 m/s
2. A man in a hot air balloon drops his “five guy's hamburger" over the edge of the basket. The
basket is 19 meters above the ground. How fast is the hamburger moving when it hits the ground?
Answer:
19.3 m/s
Explanation:
Considering that no initial velocity was imparted to the hamburger, then we can use the distance covered formula for motion under constant acceleration (that of gravity) and solve for the time it took to reach the ground.
D = vi * t + (1/2) a * t^2
in our case
19 = 0 + 4.9 t^2
t^2 = 19/4.9
then t is approximately 1.97 seconds
We now use this time information in the equation for velocity under accelerated motion (due to gravity)
Vf = Vi + g * t
For our case:
Vf = 0 + 9.8 * 1.97 = 19.3 m/s
a dog is running around chasing his tail using a force of 30N. The dog has a mass of 5 kg. what is the dogs acceleration?
Answer:
Explanation:
a = F/m
a = 30/5
a = 6 m/s²
Answer:
Acceleration is 6 meters per square seconds.
Explanation:
Data:
Force (F) = 30 NMass (m) = 5kgAcceleration (a) = ?Use formula:
\(\boxed{\bold{a=\frac{F}{m}}}\)Replace:
\(\boxed{\bold{a=\frac{30\ N}{5\ kg}}}\)Solve the division, remember remember that N / kg is equal to m/s²:
\(\boxed{\boxed{\bold{a=6\frac{m}{s^{2}}}}}\)15. Which tectonic boundary would have many normal faults associated
with it?
A. Convergent
B. Divergent
C. Transform
Problem
THE FLIGHT OF A BALL A ball is launched at 5.5 m/s at 76° above
the horizontal. It starts and lands at the same distance from the
ground. What are the maximum height above its launch level and the
flight time of the ball?
1. The maximum height above its launch level is 1.45 m
2. The time of flight of the ball is 1.1 s
1. How do I determine the maximum height?
From the question given above, the following data were obtained:
Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Maximum height (H) =?The maximum height can be obatianed as follow:
H = u²Sine²θ / 2g
H = [5.5² × (Sine 76)²] / (2 × 9.8)
Maximum height = 1.45 m
How do I determine the time of flight?
The time of flight of the ball can be obtained as follow:
Initial velocity (u) = 5.5 m/sAngle of projection (θ) = 76 °Acceleration due to gravity (g) = 9.8 m/s²Time of flight (T) = ?T = 2uSineθ / g
T = [2 × 5.5 × Sine 76] / 9.8
Time of flight = 1.1 s
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_____is the nitrogen base found only in DNA.
Answer:
thymine
Explanation:
The nitrogen base found only in DNA is known as thymine which is also called 5-methyl uracil as thymine is a derivative of uracil.
A 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head. If one’s exerts a force of 10 N on the string, what speed should the plane have as it rotates
With the use of formula, The plane should rotate at the speed of 3 m/s
Circular MotionWhen a body is moving rotationally at a point, the motion is said to be a circular motion. There are two types of motion in a circle
Vertical circular motionHorizontal circular motionGiven that a 3 kg toy plane is attached to a 1.8 m string that it can be whirled around in a horizontal circle above the users head rotates.
The given parameters are:
mass m = 3 kg
Length L = 1.8 m = radius
Force F = 10 N
Velocity V = ?
If one’s exerts a force of 10 N on the string, The speed the plane should have can be calculated by using the below formula
F = M\(V^{2}\) / r
Substitute all the parameters into the formula
10 = 3 x \(V^{2}\) / 1.8
Cross multiply
18 = 3\(V^{2}\)
\(V^{2}\) = 18/3
\(V^{2}\) = 9
V = \(\sqrt{9}\)
V = 3 m/s
Therefore, The plane should rotate at the speed of 3 m/s
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What happens to the brightness of the lightbulb when its resistance is increased? *
Answer:
It will be dimmer than before
Answer:For parallel connection,the brightness would be dimmer, while for series connection it would be brighter
Explanation:
For parallel connection,resistance and brightness are inversely proportional.meaning as resistance increases, brightness decreases.
For series connection,resistance and brightness are directly proportional. Meaning as the resistance increases, brightness also increases.
Highway safety engineers want to design roadside barriers that will crumple
in the event that a car drives off the road and collides with them, slowing
down the car more gradually. The average person has a mass of 68 kg and
travels on a highway at a velocity of 27 m/s. If the engineers know that the
maximum force that a person can safely withstand is 1650 N, approximately
how much time is required to crumple the barrier to safely slow the person
with this force?
A 1.5s
B. 0.7 s
C. 1.1 s
D. 2.1 s
The time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately C, 1.1 seconds.
How to find time?To determine the time required to crumple the barrier and safely slow down the person with a maximum force of 1650 N, use the equation of motion:
F = m × a
where:
F = force
m = mass
a = acceleration
Given:
m = 68 kg
F = 1650 N
Find the acceleration (a) first. Rearranging the equation:
a = F / m
Substituting the values:
a = 1650 N / 68 kg
a ≈ 24.26 m/s²
Now, use the equation of motion to find the time (t):
v = u + at
where:
v = final velocity (0 m/s as the person comes to a stop)
u = initial velocity (27 m/s)
a = acceleration (24.26 m/s²)
t = time
Rearranging the equation:
t = (v - u) / a
Substituting the values:
t = (0 m/s - 27 m/s) / 24.26 m/s²
t ≈ -27 m/s / 24.26 m/s²
t ≈ -1.11 s
The negative sign indicates that the time is in the opposite direction to the initial velocity. Taking the absolute value, the time required to crumple the barrier and safely slow down the person with a force of 1650 N is approximately 1.11 seconds.
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Why is the sun not the major factor in the tides?
Answer: the moon is closer.
Explanation:
The moon is closer to the earth than the sun, which results in a larger gravitational gradient for the moon even though the sun is considerably more massive and has stronger overall gravity than the moon.
7. Apply Concepts: suppose the dog walked at a constant speed the whole way. What
would the graph look like then? Explain.
If the dog walked at a constant speed the whole way, the graph of the dog's position versus time would be a straight line. This is because the dog's velocity (which is the derivative of position with respect to time) would be constant, and the acceleration (which is the derivative of velocity with respect to time) would be zero.
What is the speed about?A straight line on a position-time graph indicates that the object is moving at a constant velocity. The slope of the line would be equal to the velocity of the dog.
If the graph is a horizontal line, it would indicate that the dog is at rest. If the line slopes upward, the dog is moving in the positive direction (for example, to the right in a position-time graph), and if the line slopes downward, the dog is moving in the negative direction.
In all, A constant speed means a constant velocity and the line is a straight line with a particular slope.
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