Answers
Answer:3000
Explanation:
given:u=0v=20m/st= 8sec
thereforea=v-u/t=20-0/8=20/8=5/2 m/som=1200 kg
thereforef=ma=1200*5/2=600*5=3000N
Related Questions
A soldier is tasked with measuring the muzzle velocity of a new rifle. Knowing the principles of
projectile motion, he decides to perform a simple experiment at the indoor firing range. The soldier
hangs a target a distance of d = 109 m from the end of the barrel. The rifle is mounted so that the bullet?
exits moving horizontally at the same height as the bullseye. After six trials, the soldier tabulates the
values he measured for the vertical distance h from the bullseye to the bullet strike.
d
h
What is the most accurate muzzle velocity that the soldier can report to his sergeant?
Answers
Answer:
it could be that there is a big percentage
Explanation:
Help please ............
Answers
Answer:
47c
Explanation:
A 230 g air track glider is connected to a string hanging over a frictionless pulley. A 100g mass hangs from the other end of the string. Find the acceleration of each.
Answers
Answer:
a= 2.97m/s²
Explanation: mg = (M+m)a, with M the mass of the g
a= 100(230+100)g .
Increasing the surfactant concentration above the critical micellar concentration
will result in: Select one:
1.An increase in surface tension
2. A decrease in surface tension
3. No change in surface tension
4.None of the above
Answers
Answer:
Explanation:no change in surface tension
An increase in the surfactant concentration above the critical micellar concentration will result in no change in surface tension.
In water-gas interface, surfactant reduces the surface tension of water by adsorbing at the liquid–gas interface.
Also, in oil-water interface, surfactant reduces the interfacial tension between oil and water by adsorbing at the oil-water interface.
The concentration of the surfactant can increase to a level called critical micellar concentration, which is an important characteristic of a surfactant.
As the concentration of the surfactant increases before critical micellar concentration, the surface tension changes strongly with an increase in the concentration of the surfactant. After reaching the critical micellar concentration, any further increase in the concentration will result in no change of the surface tension, that is the surface tension will be constant.Thus, increasing the surfactant concentration above the critical micellar concentration will result in no change in surface tension.
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ts
An electric light bulb mixer is used for 19.2 seconds. In that time, it transfers 1
536 J of energy.
Calculate the power output of the cake mixer.
A
I DONT KNOW
Answers
Question 9 of 10
According to the law of conservation of momentum, the total initial
momentum equals the total final momentum in a(n)
A. Interacting system
B. System interacting with one other system
C. Isolated system
D. System of balanced forces
Answers
Answer:
The answer is C. Isolated System
Answer:
C. Isolated system
Explanation :
∵According to law of conservation of momentum ,In an isolated system ,the total momentum remains conserved.
Write an expression for the average velocity of an object in the x direction. (Use the following as necessary: x for the displacement of the object during a time interval, and At for the time interval)
Answers
Answer:x=20
Explanation:
PLEASE HELP ME ANSWER THIS QUESTION.
Answers
When the segment is shrunk to one-third of its original length, the ratio of the final linear charge density (?f) to the initial linear charge density (?i) is f/?i = 3
This is because the charge is the same, but the length of the segment has decreased to one-third of its original length. Therefore, the charge density has increased by a factor of 3.
The ratio of the electric force on the proton after the segment is shrunk (Ff) to the force before the segment was shrunk (Fi) is also 3. This is because the electric force is directly proportional to the charge density, so if the charge density increases by a factor of 3, the electric force will also increase by a factor of 3.
If the original segment of wire is stretched to 15 times its original length, the charge density will decrease by a factor of 15. To keep the linear charge density unchanged, we need to add 14 times the original charge to the wire. This is because the original charge will be spread out over 15 times the original length, so we need to add 14 times the original charge to make up for the decrease in charge density.
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A constant acceleration of 0.25 m/s^2, how long would it take to attain a
speed of 45 m/s at which speed it could liftoff?
Answers
Answer:
180 s
Explanation:
a= v-u/t
0.25=45-0/t
t=45/0.25
t=180 s
A woman stands still holding a 350 Newton bag (about 80 pounds) 2 meters off the ground. How much work does the woman do?
Answers
Answer:
700 Joules
Explanation:
What we know:
Force = 350 Newton
Distance = 2 meters
Work = ?
The formula for work is:
Work = force x distance
Plugging values into equation:
Work = 350 Newtons x 2 meters
Work = 700 Joules
I had the same question on the homework assignment with the answers provided:
a) It depends on how long she holds the bag
b) 350 Joules
c) none
d) 350 Newtons
The final answer would be c) none. The work done is 700 Joules. Hope this helps!
Determine the force of gravitational
attraction between a 12 kg bicycle
that is located 5 meters away from
an 1,240 kg car.
Answers
Answer:
1.12×10^-9N
Explanation:
Determine the force of gravitational
attraction between a 12 kg bicycle
that is located 5 meters away from
an 1,240 kg car.
Gravitational force is expressed as
F = GMm/r²
F = 6.67×10^-11×12×1240/5²
F = 6.67×10^-11×14880/25
F = 6.67×10^-11/595.2
F = 0.0112×10^-11
F = 1.12×10^-9N
Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
Answers
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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a 90.0 g mass is attached to the bottom of a vertical spring and set vibrating. assume that the maximum speed of the mass is 25.0 cm/s and the period is 0.450 s.
Answers
a. Spring constant which has a maximum mass velocity of 25.0 cm/s and a period of 0.450 s = 17.49 N/m.
b. The amplitude of the motion of the spring = 0.0179 m.
c. Frequency of oscillation of the spring = 2.22 Hz.
The angular velocityBriefly, angular velocity is the angular speed accompanied by the direction. The unit of angular speed is rad/s or rad/minute or rad/hour.
Some of the equations that are often used are:
ω = \(\sqrt{\frac{k}{m}}\)
ω = 2π/T
ω = angular velocity (rad/second)
k = the spring constant
m = mass of the object
f = frequency (rev/second)
T = period (second)
The question is incomplete, it should be:
Find the
a. constant of the spring?
b. amplitude of the motion?
c. frequency of oscillation?
We have,
Mass of the object = 90.0 g
The maximum speed = 25.0 m/s
The period = 0.450 s
Determine the angular velocity first,
ω = 2π/T
= 2π/0.450
= 4.44 π rad/s
So,
a. Spring constant:
ω = \(\sqrt{\frac{k}{m}}\)
k = ω²m
= (4.44 π rad/s)² (0.09)
= 17.49 N/m.
b. The amplitude:
vm = (xm) (ω)
So, xm = vm/ω
= 0.25/4.44 π
= 0.0179 m
c. The frequency:
f = 1/T
= 1/0.450
= 2.22 Hz.
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A fast-moving car has 0.5 MJ of kinetic energy.
The driver brakes and the car comes to a halt.
How much work is done by the force provided
by the brakes?
Answers
Answer:
-0.5 MW
Explanation:
For this we can use the principle of work and energy, which states that:
T₁ + ∑U₁₋₂ = T₂
Where T is kinetic energy (in situations one and two) and U is the sum of all work done (between situations one and two).
So, since the car is first moving with a kinetic energy of 0.5 MJ:
T₁ = 0.5 MJ = 0.5 · 10⁶ J
On top of this, we know that the car comes to a halt, using this as situation 2:
T₂ = 0 J
Filling in the equation:
⇒ 0.5 · 10⁶ + U = 0
⇒ U = -0.5· 10⁶ [W] (unit of work is watts)
= -0.5 MW
Thinking about the sign convention, we see that the brake force will point to the back of the car (backward), and the distance the car will travel before stopping will be forward, oposite directions and thus negative work.
How can we show that air can do work?
Answers
Air can do work when it exerts a force on an object and causes it to undergo displacement. The ability of air to do work is evident in various phenomena, such as wind pushing sails, fans moving objects, and air pressure powering pneumatic systems.
Air can do work through its ability to exert a force over a distance. Work is defined as the transfer of energy that occurs when a force is applied to an object and it undergoes displacement in the direction of the force. When air is in motion, it possesses kinetic energy and can exert a force on objects in its path, thus performing work.
To understand how air can do work, we can consider the example of a moving fan. When a fan is turned on, the blades start to rotate, creating a flow of air. As the air moves, it carries kinetic energy. When the moving air encounters an object, such as a piece of paper, the air molecules collide with the paper's surface and exert a force on it. This force causes the paper to move and displaces it from its initial position.
The work done by the air can be calculated using the equation:
Work = Force * Distance * cos(θ)
Where Force is the magnitude of the force exerted by the air, Distance is the displacement of the object, and θ is the angle between the direction of the force and the displacement.
In the case of air doing work on an object, the force exerted by the air is perpendicular to the direction of motion, resulting in θ = 90 degrees. Since cos(90) = 0, the equation simplifies to:
Work = Force * Distance * 0
Therefore, the work done by the air on the object is zero when the force exerted by the air is perpendicular to the displacement.
However, if the force exerted by the air is not perpendicular to the displacement, such as when blowing air at an angle to move an object, then work is performed. The air exerts a force on the object and causes it to move in the direction of the force, resulting in the transfer of energy.
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\Parts of a device that use radio waves. On the left is a box labeled A. On the right is a box labeled B. There is a vector pointing up from Box A and a vector pointing down to Box B. Arrows pointing left from Box A to Box B are labeled Radio waves travel through the air.
Which part, A or B, captures, amplifies, and demodulates radio waves?
Which part , A or B, modulates, amplifies, and sends out radio waves?
Answers
The radio waves travels between the two boxes and they were travelling through air,
Box B captures, amplifies and demodulates radio waves.Box A modulates, amplifies and send out radio waves.What are radio waves?Radio waves are the type of radiation from the electromagnetic spectrum.The radio waves can be used in communication technologies like computer, phones, radios , etc..Radio waves have lower frequencies but longer wavelength.These devices will get signal and then it transmit as mechanical waves through sound.In that way, the radio waves from box A to B through air, the box A will gets the signal, and then modulates, amplifies and then it send out radio waves. Through the air, Box B will captures, amplifies and demodulates radio waves.
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10. Refraction occurs...
A. only with light waves
B. at any, unpredictable time
C. when a wave changes speed
D. only at a wave front
E. All of the above
Answers
if an object sinks in water its density is greater than that of water
Answers
Scott travels north 2 miles and then goes west 5 miles before coming straight back south 7 miles what is his displacement
Answers
Answer:
Displacement is 5√2 miles
Explanation:
From south, Scott travelled 2 miles north and then 5 miles west then he came back south by 7 miles.
I've attached a diagram to indicate Scott's path travelled
Now, displacement is a vector quantity that tells us the overall change in position by Scott i.e distance from his initial position to his current final position while distance is a scalar quantity and tells us how much ground Scott covered in his motion over the entire trip.
Now, from the attached image, the displacement is denoted by "d".
d can be found from pythagoras theorem.
Thus;
d² = 5² + 5²
d = √50
d = 5√2 miles
7. A car stops at a red light. The light turns green
and the car accelerates up to a constant speed. After
several minutes, the car slows down and stops at the
next red light. Which graph shows the car's motion?
Answers
Answer:
Graph C
Explanation:
This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.
Titan is special because
Answers
I need help please only way to put my grade up !!!!!! Would appreciate it !!! Someone who’s good at this
Answers
Answer:
Total energy = 1000J
KE = 500J
PE = 500J
Explanation:
As you may know, the equation for gravitational potential energy is mgh (weight x height)
If the skateboard is halfway down, that means it is at half the height. As the skateboard speeds up (as it goes downward), the potential energy becomes kinetic energy. Since it has 500J of kinetic energy at half way down, it means it had double that amount of Potential energy at the top (1000J). Since half of that became kinetic energy, there is only 500J of PE left.
Total energy = KE + PE = 1000J
KE = 500J
PE = 500J
A deuterium (an isotope of hydrogen) nucleus (mass = 2.01355 amu) is made up of one proton (mass = 1.007276 amu) and one neutron (mass = 1.008665 amu). Which statement best describes what happens when a deuterium nucleus forms?
Answers
Answer: Deuterium is a stable isotope of hydrogen, which, unlike “normal” hydrogen atoms, or protium, also contains a neutron. The isotope deuterium has one proton, one neutron and one electron. One out of 6420 hydrogen atoms, on average, is a deuterium isotope.
Explanation: Deuterium is an isotope of hydrogen that is composed of one proton, one neutron, and one electron. The nucleus of deuterium is composed of a proton and a neutron. The symbol for deuterium is given as 2H. The atomic number of deuterium is 1 and the mass number is 2.
A cinderblock is pulled 0.50 meters to the right in 0.2 seconds. What is the block's
average speed to the nearest tenth of a meter per second (m/s)? Your answer should
only contain numbers (no units).
PLS HELPPP
Answers
The average speed of the block is 2.5 m/s.
What is Speed?Speed is defined as the distance traveled by an object divided by the time it takes to travel that distance.
Equation:The acceleration of the cinderblock can be calculated using the formula:
speed = distance / time
where distance is the distance the block is pulled and time is the time it takes to pull the block.
Adding the given values gives us:
Average speed= 0.50 meters / 0.2 seconds
Simplifying, we get:
Average speed= 2.5 m/s
If we round to the nearest tenth ,average speed of the block is 2.5 m/s.
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Calculate the speed for a car that went a distance of 125 miles in 2 hours time.
Answers
Answer:
65 miles per hour
Explanation:
Speed= Distance/Time
Following this formula, we just need to insert the values.
The distance is 125 miles and the time is 2 hours
125=2=65
65 miles per hour
The speed of the car was exactly 125 mi per 2 hours.
In a more familiar unit, 125mi/2hr = 62.5 mi/hr.
. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mass units)? (3) (b) the mass (in kg) of an aspartame molecule?
Answers
The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg
Aspartame has the chemical formula C14H18N2O5
C = 12, H = 1, N = 14, O = 16
(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)
= 168 + 18 + 28 + 80
= 294 amu
(b) Mass of 1 molecule of aspartame = mole x molar mass
= 1 x 294
= 294 g
Converting 294 g to kg = 294/1000
= 0.294 kg
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If you put a 15 kg mass at 2 meters where on the other side do you have to put the
20 kg mass to balance the lever?
0.25 meters
0.5 meters
0.75 meters
1 meter
1.25 meter
1.5 meter
1.75 meter
2 meter
Answers
To balance the lever, the 20kg mass will be positioned at 1.5m
What is equilibrium?When all the forces that act upon an object are balanced, the object is said to be in a state of equilibrium. The forces are considered to be balanced if the rightward forces are balanced by the leftward forces and the upward forces are balanced by the downward forces. This however does not necessarily mean that all the forces are equal to each other.
The product of mass and distance of right hand side should be equal to the product of mass and distance of the left hand side.
m1 x d1 = m2 x d2
where m1 = 15kg
d1 = 2m
m2 = 20kg
m1 x d1 = m2 x d2
Therefore;
d2 = (m1 x d1 )/m2
d2 = (15 x 2)/20
d2 = 30/20
d2 = 1.5m
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A very long straight current-carrying wire produces a magnetic field of 20 mT at a distance d from the wire. To measure a field of 5 mT due to this wire, you would have to go to a distance from the wire of
A- 4d.
B - 16d.
C - d sqrt2
D- 8d.
E- 2d.
Answers
Answer:
A. 4d
Explanation:
Magnetic field strength is inversely proportional to distance. So in order to have a smaller magnetic field, we need to move further out from the wire. How far we go exactly can be determined from the formula: B=(μ₀I)/(2πr)
(That is derived from Ampere's Law, which states ∫B•dl=μ₀I)
With that you can set up a ratio between the magnetic fields in both cases. Because the current is the same for both instances, everything reduces out on one side of the equation and leaves you with something that relates the two distances by a ratio of each magnetic field value.
My work is in the attachment, comment for questions.
i
e. network executives make hasty
When winding an old clock, it is important not to overwind it. Over-
winding occurs when the mainspring is almost fully wound, but the
operator continues to turn the winding key. This causes the main
spring to coil too tight, and might even break it.
110. This paragraph best supports the statement that
a. clocks have changed over the years.
b. old-fashioned clocks become fragile with age.
c. old-fashioned clocks were operated by an internal spring.
d. overwinding clocks used to be a common mistake.
e. time flies when you're having fun.
Answers
The paragraph primarily discusses the concept of overwinding old clocks and its consequences, indicating that overwinding clocks used to be a common mistake. Here option D is the correct answer.
The paragraph explains that overwinding occurs when the mainspring is almost fully wound, but the operator continues to turn the winding key, resulting in the spring coiling too tightly or even breaking.
This suggests that overwinding was a mistake commonly made in the past when operating old-fashioned clocks. The other options, such as clocks changing over the years or clocks becoming fragile with age, are not directly addressed in the paragraph and are therefore less supported.
The option e. "time flies when you're having fun" is unrelated to the paragraph and can be disregarded as an irrelevant answer choice. Hence option D is the correct answer.
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1. A small metal weight is suspended from a spring
scale as shown in this illustration
Spring Scale
N
1.0
2.0
3.0
4.0- The spring is measure here at 4.0 N
5.0
6.0
7.0
8.0
9.0
10.0
• What is the gravitational force acting on the weight? Explain.
• What is the net force acting on the weight? Explain.
Answers
Answer:
a) W = -4N, b) F_net = 0
Explanation:
The suspended weight of the spring ladder is subjected to two forces: the elastic force of the spring directed downwards and the gravitational force directed downwards.
\(F_{e}\) - W = 0
F_{e} = W
F_{e} = W = 4 N
a) the gravitational force is the weight of the body
W = -4N
b) as the system is in equilibrium, the net force is zero
F_net = 0